Answer:
57 x 1 =57
Step-by-step explanation:
Please remember identity property of multiplication says
An integer * 1 = the same integer
Using this property
57 x 1 = 57
Determine the value of x.
8 2
8 3
4
8
Answer:
Step-by-step explanation:
please someone help I know the answer but I don't know how to place it on the scales below. (15 Points)
Given:
a. 35% of 150 g
b. 113% of $55
To find:
The correct values for the given blanks.
Solution:
a. 35% of 150 g
Here, the percent part is 35% and percent whole is 100%.
35% of 150 g is:
[tex]\dfrac{35}{100}\times 150=52.5[/tex]
So, the number part is 52.5 g and the whole number is 150 g.
Therefore, the percent part is 35%, number part is 52.5 g and the whole number is 150 g.
b. 113% of $55 g
Here, the percent part is 113% and percent whole is 100%.
113% of $55 is:
[tex]\dfrac{113}{100}\times 55=62.15[/tex]
So, the number part is $62.15 and the whole number is $55.
Therefore, the percent part is 113%, number part is $62.15 and the whole number is $55.
what is the maximum value of y=-x^2-x+6 ?
Answer:
[tex]{ \tt{y = - {x}^{2} - x + 6 }} \\ { \tt{ \frac{dy}{dx} = - 2x - 1}} \\ f {}^{'} (x) = - 2x - 1 \\ f {}^{'}(1) = - 2 - 1 \\ = - 3 [/tex]
What is the common difference between successive terms in the sequence 0.36, 0.26,0.16,0.06,-0.04,-0.14
Answer:
- 0.1
Step-by-step explanation:
a drinks company use 76.8 kg of sugar in April .How much sugar the day use each day?
Answer:
2.56 kgs
Step-by-step explanation:
76.8kg ÷ 30 days = 2.56 kgs
Amount of sugar used - 76.8 kg
No. Of Days in Month of April - 30 days
∴ Sugar used each day is = 76.8 ÷ 30
[tex]76.8 \div 30 \\ \\ = \frac{76.8}{30} \\ \\ = \frac{768}{30 \times 10} \\ \\ = \frac{ \cancel{768}}{ \cancel{30} \times 10} \fbox{cancelling by 3} \\ \\ = \frac{256}{10 \times 10} \\ \\ = \frac{256}{100} \\ \\ = 2.56 \: kg[/tex]
So 2.56 kg is used everyday.Hope This Helps YouTo the nearest square metre, calculate the curved surface area of the half pipe if it is 9m long? (With a radius of 2.5m)
Answer:
70.686 [tex]m^{2}[/tex]
Step-by-step explanation:
A=2πrh (area of cylinder without top or bottom)
A = 2[tex]\pi[/tex](2.5)(9)
A = 141.372
divide by two for half of pipe.
A = 70.686
Which option correctly shows one row of a stem-and-leaf plot that displays this data set? 24,35,10,32,19,26,24,30,17,19,20,35
Answer:
STEM ___ LEAF
1 _______0_ 7 _ 9 _ 9
2_______0 _ 4 _ 4 _ 6
3_______0 _ 2 _ 5 _ 5
Step-by-step explanation:
Given the ordered version of the data:
10, 17, 19, 19, 20, 24, 24, 26, 30, 32, 35, 35
. The stem is the tens digit and leaf is the unit digit of each data.
STEM ___ LEAF
1 _______0_ 7 _ 9 _ 9
2_______0 _ 4 _ 4 _ 6
3_______0 _ 2 _ 5 _ 5
Since there isn't any option given, then the row could be any of row values above.
HELP ME ASAP NO LINKS
Which student's expression results in a quotient of 12.5?
KWAN
VERA
16.25 : 1.3
- 11.25 = (-9)
Mark only one oval.
0000
a. Kwan's only
b. Vera's only
c. Both Kwan and Vera's
d. Neither Kwan nor Vera's
Answer:
I wanna say its B. Vera's only
The table below represents a linear function f(x), and the equation represents a function g(x): X) -1, 0, 1 F(x) -5, -1, 3 G(x)=4x+3
Part A. Write a sentence to compare the slope of the two functions and shows the steps you used to determine the slope of f(x) and g(x)
Part B which functions has greater y-intercept. Justify
Answer:
(a) g(x) has a greater slope
(b) g(x) has a greater y intercept
Step-by-step explanation:
Given
[tex]x \to -1,0,1[/tex]
[tex]f(x) \to -5,-1,3[/tex]
[tex]g(x) = 4x + 3[/tex]
Solving (a): Compare the slopes
Slope (m) is calculated as:
[tex]m =\frac{y_2 - y_1}{x_2 - x_1}[/tex]
So, for f(x), we have:
[tex]m =\frac{-1- 0}{-5- -1}[/tex]
[tex]m =\frac{-1}{-4}[/tex]
[tex]m =\frac{1}{4}[/tex]
For g(x), we have:
Assume [tex]g(x) = mx + c[/tex] then the slope is m
Compare the above to [tex]g(x) = 4x + 3[/tex]
Then the slope of g(x) is 4
g(x) has a greater slope
Solving (b): Function with greater y intercept
Here we set [tex]x= 0[/tex]
From the table of f(x)
[tex]f(x) = -1[/tex] when [tex]x = 0[/tex]
From [tex]g(x) = 4x + 3[/tex]
[tex]g(0) = 4 * 0 + 3[/tex]
[tex]g(0) = 3[/tex]
Hence:
g(x) has a greater y intercept
Grayson is 1.25 meters tall. At 12 noon, he measures the length of a tree's shadow to be 22.75 meters. He stands 17.6 meters away from the tree, so that the tip of his shadow meets the tip of the tree's shadow . Find the height of the tree to the nearest hundredth of a meter.
Answer:
5.52m
Step-by-step explanation:
First, we can see that two similar triangles are formed. One similar triangle is the big triangle, with the base being 22.75m and the height being the tree's height. Another triangle is formed with Grayson's height as the height and the and the difference between where he is standing and the edge of the tree's shadow (the red outline in the picture) . We know that these are similar triangles because both the bases are parallel, as well as the heights and hypotenuses.
The base length for the triangle with Grayson as the height is 22.75-17.6 = 5.15 .
For similar triangles, we know that the ratios between sides are the same. For example, base₁/base₂ = height₁/height₂ . We can apply this here, making 5.15 base₁ and 1.25 height₁ (note that the same triangle's sides should be on top)
If we make the tree's height t, we thus have
5.15/22.75 = 1.25/t (height 2 is the tree's height
multiply both sides by t to remove one denominator
5.15 * t / 22.75 = 1.25
multiply both sides by 22.75 to remove the other denominator
5.15 * t = 1.25 * 22.75
= 28.4375
divide both sides by 5.15 to isolate the t
t = 5.52m
the lateral surface area of right circular cylinder is 120 pi cm squared and the circumference is 12 cm find the height
Answer:
h=31.4 cm
Step-by-step explanation:
A=lateral surface area
c=circumference
h=height
A= c*h
solving for h we get:
h=A/c=120pi/12=10pi
question is in the pucture
Answer:
Aiden earned less money for his 8th than he earned for his 4th drive.
[tex]ANSWER:C[/tex]
-------------------------------
HOPE IT HELPS
HAVE A GREAT DAY!!
can you help me do this Question if you can?
Answer:
A
Step-by-step explanation:
In a triangle ABC, b=13cm c=17cm A=86 degree. Find B,C and a
Step-by-step explanation:
went to a calculator
it said
Side a = 20.66803
Side b = 13
Side c = 17
Angle ∠A = 86°
Angle ∠B = 38.863°
Angle ∠C = 55.137°
solve for
(6x + 9)/3 =
Hello!
(6x + 9)/3 =
= 3(2x + 3)/3 =
= 2x + 3
Good luck! :)
Can you help with 7-10
Answer:
7.Mean=Ex/n
= 88+96+92+84+86+92+98/7
=90
(b). Median = {84,86,88},92,{92,96,98}
=92
(C).Mode=92 ; it is the number with the highest frequency
9.Mean=Ex/n
=28+26+32+24+27+32+29/7
=28
(b).Median={24,26,27},28,{29,32,32}
=28
(c).Mode=32;it is the number with the highest frequency.
8.Mean=Ex/n
=3.5+5.7+9.8+7+12.4+10.2/6
=8.1
(b).Median={3.5,5.7},7,9.8,{10.2,12.4}
=7+9.8/2
=8.4
(c).Mode=no mode
10.Mean=Ex/n
=2+6+9+8+8+2+8+7+5+4/10
=5.9
(b).Median={2,2,4,5},6,7,{8,8,8,9}
=6+7/2
=6.5
(c).Mode= 8;it is the number with the highest frequency.
I hope this helps.
Maths Aryabhatta
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Solve the following pair of linear equations using substitution method :-
2x+3y + 5 = 0 ; 5x-3y+9=0
Answer:
(- 2, - [tex]\frac{1}{3}[/tex] )
Step-by-step explanation:
Given the 2 equations
2x + 3y + 5 = 0 → (1)
5x - 3y + 9 = 0 → (2)
Rearrange (1) expressing 3y in terms of x by subtracting 2x + 5 from both sides
3y = - 2x - 5
Substitute 3y = - 2x - 5 into (2)
5x - (- 2x - 5) + 9 = 0 ← distribute parenthesis on left side and simplify
5x + 2x + 5 + 9 = 0
7x + 14 = 0 ( subtract 14 from both sides )
7x = - 14 ( divide both sides by 7 )
x = - 2
Substitute x = - 2 into either of the 2 equations and solve for y
Substituting into (1)
2(- 2) + 3y + 5 = 0
- 4 + 3y + 5 = 0
1 + 3y = 0 ( subtract 1 from both sides )
3y = - 1 ( divide both sides by 3 )
y = - [tex]\frac{1}{3}[/tex]
solution is (- 2, - [tex]\frac{1}{3}[/tex] )
someone help me please with this algebra problem
Answer:
x=44-y
Step-by-step explanation:
In this problem, there are 44 glasses in total. Additionally, we want to know how many ice teas she can have; therefore, we must find x. The problem tells us that when x and y are added together they should equal 44. One way to solve this is to write the equation, x+y=44, because we know it is true and then solve for x. To find x subtract y from both sides. This equals x=44-y, the final answer.
Which of the following graphs represents the equation y=3x+2? A.Graph B. Graph B C. Graph C D. Graph D
HELP PLEASE
how do i put this into a piecewise function?
Answer:
Step-by-step explanation:
2 functions start by making a domain
Function 1: -3≤x<1
Function 2: -1≤x≤1
Now come up with equations
Function 1= x+3
Function 2= 5
Now put it all together
f(x)= x+3 for -3≤x<1 and 5 for -1≤x≤1
If a car is moving on a straight line with a velocity of 40 m/s and it changes its velocity to 60 m/s in 4 seconds, calculate its acceleration.
Answer:
5m/s²
Step-by-step explanation:
Given :-
Initial Velocity = 40m/s Final velocity = 60 m/sTime = 4sTo Find :-
The acceleration .Solution :-
We know that the rate of change of velocity is called acceleration. Therefore ,
[tex]\sf\implies a = v - u / t \\ [/tex]
[tex]\sf\implies a = 60m/s - 40m/s/ 4 \\ [/tex]
[tex]\sf\implies a = 20m/s \div 4 \\[/tex]
[tex]\bf\implies a = 5m/s^2[/tex]
what is the quotient of 3/4 ÷ 5/12
Answer:
1 4/5
Step-by-step explanation:
3/4 ÷ 5 /12
Copy dot flip
3/4 * 12/5
Rewriting
3/5 * 12/4
3/5 * 3
9/5
1 4/5
Which of the following quadratic regression equations best fits the data
shown below?
Х
-4
-3
-2
-1
0
1
N
3
4
y
35
20
10
5
00
10
15
30
48
O A. y = 0.98x2 +3.06x+ 6.02
O B. y = 2.23x2 + 1.62x+ 5.26
O c. y = 3.72x2 + 2.94x + 3.21
O D. y = 4.63x2 + 0.84x+ 4.14
Answer:
C
Step-by-step explanation:
The method that is not used on graphs to lead the reader to misinterpret the graph is - Comparing two sets of related data on the same graph for the sake of comparison.
What is graph?A graph is a intersection of {x} and {y} axis. On the graph, the coordinate points can be plotted in the form (x, y). In this, {x} represents the horizontal distance along the {x} axis and {y} is the vertical distance along the {y} axis.
Given is to identify the methods that are not used on graphs to lead the reader to misinterpret the graph.
The method that is not used on graphs to lead the reader to misinterpret the graph is - Comparing two sets of related data on the same graph for the sake of comparison.
Therefore, the method that is not used on graphs to lead the reader to misinterpret the graph is - Comparing two sets of related data on the same graph for the sake of comparison.
To solve more questions on graphs, visit the link below-
https://brainly.com/question/17267403
#SPJ7
What is the value of this exspession when c=-4 and d=-10 1/4(c^3+d^2)
Answer:
2
Step-by-step explanation:
1/4(-4×3 + 10×2)
1/4(-12 + 20)
THERE ARE 2 WAYS YOU COULD SOLVE THIS!
1. 1/4( -12) + 1/4( 20) = -3 + 5 = 2
2. 1/4 ( -12+20) = 1/4(8) = 2
Answer:
[tex]9[/tex]
Step-by-step explanation:
Given:-
Expression: [tex]\frac{1}{4} (c^3+d^2)[/tex]
Value of c = [tex]-4[/tex]
Value of d = [tex]-10[/tex]
Solution:-
Add the given values in the expression, writing them inside the bracket:
[tex]\frac{1}{4} ((-4)^3+(-10)^2)[/tex]
[tex](\frac{1}{4}) ((-4)^3)+(\frac{1}{4} )((-10)^2)[/tex]
[tex]-16+25[/tex]
[tex]9[/tex]
A claim is reviewed for MOHS surgery on the foot that was performed in 1 stage with 6 tissue blocks. The claim was reported with 17311, 17312-51, 17312-51. Is this correct
Answer:
17311, 17315
Step-by-step explanation:
Explanation,
Mohs surgery, also known as chemosurgery, created by a general surgeon, Dr. Frederic E. Mohs, is performed to remove complex or ill-defined cutaneous malignancy.List Of CPT Codes For Mohs Surgery
CPT Code 17311 and CPT Code 17313 are the base codes for the range of this surgery. CPT Code 17312, CPT Code 17314, and CPT Code 17315 are the add-on codes for this range.
Description Of CPT Code 17311
Moh’s micrographic technique, including removal of all gross tumor, surgical excision to tissue specimens, mapping, color coding of specimens, microscopic examination of specimens by the surgeon, and histopathologic preparation including routine stain(s) (eg. Hematoxylin and eosin, toluidine blue), head, neck, hands, feet genitalia, or any location with surgery directly involving muscle, cartilage, bone, tendon, major nerves, or vessels; first stage, up to 5 tissue blocksDescription Of CPT Code 17315 (addon)
CPT Code 17315 may be used to report each block after the first 5 blocks for any single-stage.
Moh’s micrographic technique, including removal of all gross tumor, surgical excision of tissue specimens, mapping color coding of specimens, microscopic examination of specimens by the surgeon, and histopathologic preparation including routine stains(s) (eg. Hematoxylin and eosin, toluidine blue), each additional block after the first 5 tissue blocks, any stage (List separately in addition to code for primary procedure)Extras
Description Of CPT Code 17312 (addon)
Each additional stage after the first stage, up to 5 tissue blocks (List separately in addition to code for primary procedure)
Description of CPT Code 17313
Moh’s micrographic technique, including removal of all gross tumor, surgical excision of tissue specimens, mapping, color coding of specimens, microscopic examination of specimens by the surgeon, and histopathologic preparation including routine stains(s) (eg. Hematoxylin and eosin, toluidine blue), of the trunk, arms, or legs; first stage, up to 5 tissue blocks
Description Of CPT Code 17314 (addon)
Each additional stage after the first stage, up to 5 tissue blocks (List separately in addition to code for primary procedure).
Multiply the following rational expressions and simplify the result
Answer:
Step-by-step explanation:
We have to solve the given expression,
[tex]\frac{9y-33y^2-3y^4}{100-49y^2}.\frac{7y^2+17y+10}{14y^2+28y}[/tex]
[tex]\frac{9y-33y^2-3y^4}{100-49y^2}.\frac{7y^2+17y+10}{14y^2+28y}[/tex] = [tex]\frac{-y(-9+33y+3y^3)}{100-49y^2}.\frac{7y^2+17y+10}{14y(y+2)}[/tex]
= [tex]\frac{-y(-9+33y+3y^3)}{(10-7y)(10+7y)}.\frac{7y^2+10y+7y+10}{14y(y+2)}[/tex]
= [tex]\frac{-y(-9+33y+3y^3)}{(10-7y)(10+7y)}.\frac{y(7y+10)+1(7y+10)}{14y(y+2)}[/tex]
= [tex]\frac{-y(-9+33y+3y^3)}{(10-7y)(10+7y)}.\frac{(y+1)(7y+10)}{14y(y+2)}[/tex]
= [tex]\frac{-3y(-3+11y+y^3)}{(10-7y)}.\frac{(y+1)}{14y(y+2)}[/tex]
= [tex]\frac{-3(-3+11y+y^3)}{(10-7y)}.\frac{(y+1)}{14(y+2)}[/tex]
= [tex]\frac{3(3-11y-y^3)(y+1)}{(10-7y)(14(y+2)}[/tex]
Hi guys can please help me
using a calculator or otherwise evaluate each of the following giving Your answer to two decimal place .
(i) 73.18-5.23×90
Answer: 26.11
Step-by-step explanation:
73.18 - 5.23 × 90 = 73.18 - 47.07 = 26.11
given g(x) = square root of x - 4 and h(x) = 2x - 8 What is g(h10))?
Step-by-step explanation:
First find h(10)
h(10)=2(10)-8
h(10)=12
Now plug in 12 as the value of x in g(x) ie.g(12)
So g(12)=√12-4=√8=2√2
A discount site decreases the price of cell phones by . Select the two expressions that represent the discounted price of a phone costing dollars.
A
0.40ddd
B
0.60ddd
C
d−d-d−0.60
D
d−d-d−0.60ddd
E
1−-−0.60ddd
The percentage discount given on the prove is not supplied ; Assume the percentage discount given on the phone is 60%
Answer:
0.4d
d - 0.6d
Step-by-step explanation:
Given that :
Percentage Discount given on phone = 60%
The discounted pice :
Initial percentage = 100%
Discount percentage = 60%
(100% - 60%) of price
(100% - 60%) * d
40%*d
0.4d
Also ;
(100% - 60%) * d
100%*d - 60%d
d - 0.6d
-3 raised to the power 0=
Given:
The statement is "-3 raised to the power 0".
To find:
The value of the given expression.
Solution:
We know that [tex]a[/tex] raised to the power [tex]b[/tex] can be written as [tex]a^b[/tex].
Any non zero number raised to the power 0 is always 1. It means,
[tex]a^0=1[/tex], where [tex]a\neq 0[/tex].
-3 raised to the power 0 [tex]=(-3)^0[/tex]
[tex]=1[/tex]
Therefore, the value of the given statement is 1.