Answer:
The current through R2 is 0.078125 amperes.
Explanation:
Ohm's law is the relationship between electrical conductors and their resistance, which establishes that the current that passes through the conductors is proportional to the voltage applied to them.
Ohm's Law relates the magnitudes of voltage, resistance, and intensity as follows:
V=I*R
where V is the electric potential in volts, I is the current in amperes, and R is the resistance in ohms.
R1 has a 0.200 amperes current flowing through it and a resistante of 25 ohms.
So:
V=0.200 amperes* 25 ohms
Solving:
V=5 volts
Now, for resistance R2 you know the value of the voltage (5 volts) and the value of its resistance R2 = 64 ohms. So:
5 volts= I* 64 ohms
Solving:
[tex]I=\frac{5 volts}{64 ohms}[/tex]
I= 0.078125 amperes
The current through R2 is 0.078125 amperes.
Answer:
the current through R₂ is 0.078 A
Explanation:
Given;
resistance of the first resistor, r₁ = 25 ohms
resistance of the second resistor, r₂ = 64 ohms
current through the first resistor, I₁ = 0.2 A
The voltage passing through each resistor is constant since they are connected parallel to each other.
V = I₁R₁ = I₂R₂
[tex]I_2 = \frac{I_1R_1}{R_2} \\\\I_2 = \frac{0.2 \times 25}{64} \\\\I_2 = 0.078 \ A[/tex]
Therefore, the current through R₂ is 0.078 A
What is the frequency of a wave that passes a given point 412 times in 4.0
seconds?
O A. 0.0097 s
OB. 103 Hz
O C. 408 S
O D. 1650 Hz
SUBMIT
Answer: A.0,0097s
Mas a unidade aí deveria ser Hertz (Hz)
Explanation:
Answer:
103 hz
Explanation:
Alexis is a scientist who is studying solid-state physics. Which activity would she most likely do as a part of this research? O identifying the optimal vessel for containing carbon dioxide O studying the atomic structure of solid carbon dioxide O determining the effect of pressure on the volume of carbon dioxide O observing the natural state of carbon dioxide
Answer:
pretty sure its studying the atomic structure of a solid carbon dioxide. so c
Explanation:
Answer:
B. Studying the atomic structure of solid carbon dioxide
Explanation:
This is known as crystallography, the study of the arrangement of atoms in a solid, and it is a popular branch of solid-state physics.
Hope this helps :)
An object is placed closer to the lens than f for a diverging lens. The image will be located:
a) between f and 2f
b) between the lens and f
c) A or B or C
d) farther than 2f
The motor of a battery-powered scooter can maintain a speed of 5.3 m/s by providing a force of 280 N. What is the power output of the motor? *
Answer:
the power output P = 1484 W
Explanation:
Power P = Force× speed
Given that motor of a battery-powered scooter can maintain a speed of 5.3 m/s by providing a force of 280 N.
Therefore,the power output of the motor P = 280×5.3 = 1484 W
Hence, the power output P = 1484 W
I need help
please help me with this
What is speed in a specific direction called
Answer:
my brainly answer got deleted for no reason but its velocity thats the name of speed in 1 direction
Explanation:
50N force accelerated a body at a rateof 8 metres per second square. Calculate the mass of the body
Answer:
m=6.25kg
Explanation:
Force= mass × acceleration
50=m×8
make m subject of the formula...
m=50/8
m=6.25kg
Answer:
[tex]\boxed {\boxed {\sf 6.25 \ kilograms}}[/tex]
Explanation:
According to Newton's Second Law of Motion, force is the product of mass and acceleration.
[tex]F= m \times a[/tex]
We know the force is 50 Newtons and the acceleration is 8 meters per second squared. Let's convert the units to make the problem and unit cancellation easier.
1 Newton is equal to 1 kilogram meter per square second (1 kg*m/s²), so the force of 50 N is equal to 50 kg*m/s².
Now we know 2 values:
F= 50 kg*m/s²a= 8 m/s²Substitute the values into the formula.
[tex]50 \ kg *m/s^2= m \times 8 \ m/s^2[/tex]
Since we are solving for the mass, we must isolate the variable, m. It is being multiplied by 8 meters per square second and the inverse of multiplication is division. Divide both sides by 8 m/s².
[tex]\frac {50 \ kg *m/s^2}{8 \ m/s^2}= \frac{m \times 8 \ m/s^2}{8 \ m/s^2}[/tex]
[tex]\frac {50 \ kg *m/s^2}{8 \ m/s^2}= m[/tex]
The units of meters per square second (m/s²) cancel.
[tex]\frac {50 \ kg }{8 }=m[/tex]
[tex]6.25 \ kg =m[/tex]
The mass is 6.25 kilograms.
Which wave shows the loudest sound below?
Answer:
I think C
Explanation:
If im right give brainliest :)
Find equivalent resistance.
Answer asap and please, please don't spam.
Answer:
R = 4.77 ohms
Explanation:
Four resistors are given such that,
R₁ = 2 ohms
R₂ = 3 ohms
R₃ = 5 ohms
R₄ = 10 ohms
Here, R₁ and R₂ in series. The equivalent is given by :
R₁₂ = R₁ + R₂
= 2 + 5
R₁₂ = 7 ohms
Similarly, R₃ and R₄ are in series. so,
R₃₄ = R₃ + R₄
= 10+5
R₃₄ = 15 ohms
Now, R₁₂ and R₃₄ are in parallel. So,
[tex]\dfrac{1}{R}=\dfrac{1}{R_{12}}+\dfrac{1}{R_{34}}\\\\\dfrac{1}{R}=\dfrac{1}{7}+\dfrac{1}{15}\\\\R=4.77\ \Omega[/tex]
So, the equivalent resistance s 4.77 ohms.
(b) How much energy must be supplied to boil 2kg of water? providing that the specific latent heat of vaporization of water is 330 kJ/kg.
Complete question:
(b) How much energy must be supplied to boil 2kg of water? providing that the specific latent heat of vaporization of water is 330 kJ/kg. The initial temperature of the water is 20 ⁰C
Answer:
The energy that must be supplied to boil the given mass of the water is 672,000 J
Explanation:
Given;
mass of water, m = 2 kg
heat of vaporization of water, L = 330 kJ/kg
initial temperature of water, t = 20 ⁰C
specific heat capacity of water, c = 4200 J/kg⁰C
Assuming no mass of the water is lost through vaporization, the energy needed to boil the given water is calculated as;
Q = mc(100 - 20)
Q = 2 x 4200 x (80)
Q = 672,000 J
Q = 672,000 J
Q = 672,000 J
Therefore, the energy that must be supplied to boil the given mass of the water is 672,000 J
The length of an aluminium rod is 1m and the speed of sound along the rod is 5000 m per second .Find the values of f1 ad f2
Answer:
i. 2.5 kHz ii. 5 kHz
Explanation:
The frequency of the wave in the rod is given by f = nv/2L where n = harmonic, v = speed of sound in rod = 5000 m/s and L = length of rod = 1 m
i. f1
For f1, n = 1
f1 = 1 × v/2L
= v/2L
Substituting the values of the variables into the equation, we have
= 5000 m/s ÷ (2 × 1 m)
= 5000 m/s ÷ 2 m
= 2500 /s
= 2500 Hz
= 2.5 kHz
ii. f2
For f2, n = 2
f2 = 2 × v/2L
= v/L
Substituting the values of the variables into the equation, we have
= 5000 m/s ÷ 1 m
= 5000 /s
= 5000 Hz
= 5 kHz
If a train traveled 400 miles north and traveled back 275 miles south and the total trip took 5 hours to complete, what was the average velocity of the train in mph?
The average velocity is 25 mph north.
Average velocity = displacement/time
Displacement =
(400 mi north) + (275 mi south)
Displacement = 125 mi north
Average V = (125 mi north) / 5 hours.
Average V = 25 mph north
The rate at which electric
charges flow through a
circuit
Answer:
The answer is Current.
A 5L container has a
Answer:a gas at pressure of 0.8 m column of H g
Explanation:I thinkA person weighs 60 kg. The area under the foot of the person is 150 cm2. Find the pressure exerted on the ground by the person. (Take g 10m/s2)
Answer:
40000 N/m²
Explanation:
Applying,
P = F/A................... Equation 1
Where P = Pressure, F = Force, A = Area.
From the question,
The force(F) exerted by the person's foot is thesame as it's weight.
F = W = mg............ Equation 2
Where m = mass of the person, g = acceleration due to gravity.
Substitute equation 2 into equation 1
P = mg/A................ Equation 3
Given: m = 60 kg, g = 10 m/s², A = 150 cm² = (150/10000) m² = 0.015 m²
Substitute these values into equation 3
P = (60×10)/0.015
P = 600/0.015
P = 40000 N/m²
A man exerts more pressure while standing on one foot than by two foot
Answer:While walking, one foot is in contact with the ground at a time. The surface area of one foot is less than two feet. Therefore, the pressure is more than the pressure exerted while standing, as the surface area of both feet is more.
A person weighs 60 kg. The area under the foot of the person is 150 cm2. Find the pressure exerted on the ground by the person.
Answer:
Pressure = 39200 N/m²
Explanation:
Given the following data;
Mass = 60 kg
Area = 150 cm²
Conversion:
1 centimeter square = 0.0001 meter square
150 centimeter square = 150 * 0.0001 = 0.015 m²
To find the pressure exerted on the ground by the person;
Mathematically, pressure is given by the formula;
[tex] Pressure = \frac {Force}{area} [/tex]
First of all, we would determine the force exerted by the person.
Force = mass * acceleration due to gravity.
We know that acceleration due to gravity is equal to 9.8 m/s².
Substituting into the formula, we have;
Force = 60 * 9.8
Force = 588 Newton
Next, find the pressure;
[tex] Pressure = \frac {Force}{area} [/tex]
Substituting into the formula, we have;
[tex] Pressure = \frac {588}{0.015} [/tex]
Pressure = 39200 N/m²
HELP ME ILL MARK YOU THE BRAINLIEST
Option C: Later in the day, less power is developed in lifting each box
Answer:
Later in the day, less power is developed in lifting each box.
power= workdone÷time
You can do only number 1 only
For 1000 seconds , a current of 0.1 A flows so as to transfer charge of 100C
A student uses an indicator to measure the pH of a solution. The indicator shows a pH of 7. What must be true of this solution?
Answer:
The solution is neither acidic or basic,
PH < 7 acidic
PH = 7 neutral
PH > 7 basic
It is a measure of the (H+) hydronium concentration.
(I have 2 questions which are very similar)
Which of the chemical reactions above stores energy?
A. Cellular respiration
B. Photosynthesis
C. Both cellular respiration and photosynthesis
D. Neither cellular respiration nor photosynthesis
15 Which of the chemical reactions above releases energy?
A. Cellular respiration
B. Photosynthesis
C. Both cellular respiration and photosynthesis
D. Neither cellular respiration nor photosynthesis
(help!!!) SCIENCE
Answer:
B
A
Explanation:
please mark as brainliest :)
can someone please help me with this question... thank u ❤️
Answer:
Which of the following... : constant velocity horizontal motion
A ball is thrown at certain... : 0 m/s
Wire B has twice the length and twice the radius of wire A. both wires are made from the same material. if wire A has a resistance R, what is the resistance of wire B?
Answer:
Hello There!!
Explanation:
1/2R because wire B has twice the radius,it has four times the cross-sectional area of wire A.
hope this helps,have a great day!!
~Pinky~
A mass hanging from a pendulum at the end of a string of negligible mass. The string has a length of 0.84 m. With the string hanging vertically, the object is given an initial velocity of 1.4 m/s parallel to the ground and swings upward on a circular arc. Eventually, the object comes to a momentary halt at a point where the string makes an angle θ with its initial vertical orientation and then swings back downward. Find the angle θ.
Explanation:
tan(theta)=(v^2)/(length of string × g)
=(1.4^2)/(0.84 × 9.8m/s )
=1.96/(8.232)
=0.2380952381
theta=arctan(0.2380952381)
=13.4°
in what ways water helps in germination?
Answer:
Water can spread germs through bacteria.
Explanation:
Bacteria can live in water and can spread to new locations when water is moved.
HELP PLEASE ?? can u answer this multiple choice for me please?
Answer:
.04 kg m/s
Explanation:
Momentum is simply mass multiplied by velocity given by p = mv. You can consider momentum as mass in motion.
Before the collision, the data given for the toy train:
v = 0.5m/s
m = 75g
We need to convert grams into the SI unit of mass, kg.
75g / 1000g * 1kg = 0.075kg
Using p = mv, we can determine:
p = 0.075kg * 0.5m/s = 0.0375 kg m/s
Rounding to the value of 1 sig-fig, it comes out to be 0.04 kg m/s.
A hot cube of iron was heated up using 1500 J of thermal energy and was placed in a beaker of water. Before it was heated, the iron cube was 20.0 ˚C. The cube of iron raised the temperature of the water to 45.0 ˚C. If the iron cube has a mass of 133 g, what is the specific heat capacity of iron?
Answer:
451.13 J/kg.°C
Explanation:
Applying,
Q = cm(t₂-t₁)............... Equation 1
Where Q = Heat, c = specific heat capacity of iron, m = mass of iron, t₂= Final temperature, t₁ = initial temperature.
Make c the subject of the equation
c = Q/m(t₂-t₁).............. Equation 2
From the question,
Given: Q = 1500 J, m = 133 g = 0.113 kg, t₁ = 20 °C, t₂ = 45 °C
Substitute these values into equation 2
c = 1500/[0.133(45-20)]
c = 1500/(0.133×25)
c = 1500/3.325
c = 451.13 J/kg.°C
When should a bar graph be used?
A. When the independent variable is composed of categories and does not show a
relationship
B. When the independent variable is continuous and does not show a relationship to the
dependent variable.
C. When the independent variable is continuous and shows a causal link to the
dependent variable,
D. When there is no independent variable.
Answer:
B. When the independent variable composed of categories and does not show a relationship to the dependent variable
Explanation:
A bar graph, is a graph used for presenting data grouped into categories, which are the independent variables of the graph, and the measurement of each category, which are represented as rectangular bars having lengths proportional to the value of the category, on a chart
In the bar graph or chart, there is no direct relationship between the categories, which are the x-values and the dependent variables , which are the length of the bars, the y-values, as the length of the rectangular bar in one category, cannot be obtained from another category through a relationship
Therefore, the correct option is option is when the independent variable composed of categories and does not show a relationship to the dependent variable
Multiple Choice Identify the letter of the choice that best completes the statement or answers the question. The best type of graph to illustrate the change in air temperature over a period of time would be a _________ graph. a. circle b. line c. bar d. all of these Please select the best answer from the choices provided A B C D
Answer:
B line graph
Explanation:
sorry if I am wrong
Answer:
b
Explanation:
A Stone of mass 40kg is released from
A Catapult whose rubber has been stretched
through 5mm. If the stiffness of the rubber
is 20 Nm^1 CALCULATE the velocity with which
the stone Leaves the Catapult!
Answer:
v = 3.53x10⁻³ m/s.
Explanation:
We can find the velocity of the rock by energy conservation:
[tex] \Sigma E_{i} = \Sigma E_{f} [/tex]
[tex] \frac{1}{2}kx^{2} = \frac{1}{2}mv^{2} [/tex]
Where:
i is for initial and f is for final
k: is the stiffness of the rubber = 20 N/m
x: is the distance of the rubber compression = 5 mm = 0.005 m
m: is the mass of the stone = 40 kg
v: is the velocity =?
Hence, the velocity is:
[tex]v = \sqrt{\frac{kx^{2}}{m}} = \sqrt{\frac{20 N/m(0.005 m)^{2}}{40 kg}} = 3.53 \cdot 10^{-3} m/s[/tex]
Therefore, the velocity with which the stone leaves the catapult is 3.53x10⁻³ m/s.
I hope it helps you!