Two objects, one with a mass of and the other with a force of 30.0kg experience a gravitational force of attraction of 7.50 * 10^- 8 N how far apart are centers of mass?

Answer:

The second throw shows both accuracy and precision.

Explanation:

The second throw shows both accuracy and precision because he knew in which degree and the amount of force that can be applied to the dart so that it hits the center of the bullseye or close to it. Due to knowing of these two things the Carlos is able to hit the dart close to the target at the second time so in this way he got both accuracy and precision at the second turn of throwing darts.

Answer:

B-The second throw shows accuracy but poor precision.

Explanation:

Answer:

b

Explanation:

bc

Answer:

horizontal velocity remaing constan thorough out the motion but the vertical motion's velocity changes due to the gravity acting on it.

for everl 1 second the velocity decreases by 9.8 that is the gravity

Answer:

The correct alternative is Option b (are influenced by social trends).

Explanation:

There is no connection between the other three choices. Thus, the answer is right.

Answer:

Option 1 & 2

Explanation:

The area of mathematics known as Boolean algebra concerns with operations on logical quantities with binary variables. To express truths, Boolean features are transformed as binary numbers: 1 = true and 0 = false. Boolean algebra concerns with logistical processes, whereas fundamental algebra deals with machine based.

Answer:

an inverse relationship

Answer:

B

Explanation:

The writers are from a trusted source that is considered impartial. The message is backed up by scientific investigation, and the writers have no monetary gain from their message.

Answer:

A

Explanation:

The process by which molten materials add new oceanic crust to the ocean floor.

9514 1404 393

Answer:

  A1 = 3A, A2 = 1.5A

  Effective resistance = 2Ω

Explanation:

When the switch is closed, the voltage across each resistor is 6V, so the current through it (A2) is ...

  A2 = 6V/(4Ω) = 1.5A

There are two parallel paths, each with that current, so the current from the battery is ...

  A1 = A2 +A2 = 1.5A +1.5A = 3.0A

Then the effective resistance is ...

  Reff = 6V/(3.0A) = 2.0Ω

The solution to the circuit is ...

  A1 = 3A, A2 = 1.5A

  Effective resistance = 2Ω

Answer:

below

Explanation:

that is the procedure above

Answer: 2.43 s

Explanation:

Initial velocity is [tex]u=15.2\ m/s[/tex]

Final velocity [tex]v=23\ m/s[/tex]

Average acceleration is [tex]a_{avg}=3.2\ m/s[/tex]

Average acceleration is change in velocity in the given amount of time

[tex]\therefore a_{avg}=\dfrac{v-u}{t}\\\\\Rightarrow 3.2=\dfrac{23-15.2}{t}\\\\\Rightarrow t=\dfrac{7.8}{3.2}\\\\\Rightarrow t=2.43\ s[/tex]

Thus, 2.43 s is required to acquire that average acceleration with 23 m/s velocity .

Answer:

the answer to this would be D.

Answer: Its D but it might swap to another letter so keep your eye out bud pass this test good luck

Explanation:

Dark matter and dark energy described as dark because of its no interaction with electromagnetic field.

Dark matter is called "dark" because it does not interact with the electromagnetic field. This means that it does not absorb, reflect, or emit electromagnetic radiation and therefore, it is difficult to detect.

So we can conclude that dark matter and dark energy described as dark because of its no interaction with electromagnetic field like dark substances.

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Dark matter and dark energy are described as dark because it doesn't seem to interact with the electromagnetic field.

The matter is a material that fills space and has inertia. Modern physics states that matter is made up of several kinds of particles, each of which has a mass and size.

The electron, proton, and neutron are three of the most well-known instances of material particles. Atoms are made up of combinations of these particles.

Dark matter is so-called because it doesn't seem to interact with the electromagnetic field.

This means it doesn't generate electromagnetic radiation like light or absorb electromagnetic radiation as it does. As a result, it is hard to detect.

Hence, dark matter and dark energy are described as dark.

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Answer:

9.78 m/s^2

Explanation:

Acceleration due to gravity at equator is 9.78m/s^2

Answer:

40

Explanation:

vi=0

a=2

vf=?

d=400

vf^2=vi^2+2ad

vf^2=0+2×2×400=1600

vf=√1600=40m/s

Answer:

if these gases existed in Titan, this n in solid form, by which its absence in the atmosphere is understood.

Explanation:

Each gas and chemical compound has a defined temperature for changes of state, specifically for the change from gaseous to liquid and from liquid to solid state we have

gas                gas → liquid              liquid → solid

                         (ºC)                            (ºC)

H₂0 (Water)      100                                0

CO₂                 -56.6 (P> = 5.2 bar)     <-56.6

The temperature of the Titan satellite is - 180ºC

From the above, if these gases existed in Titan, this n in solid form, by which its absence in the atmosphere is understood.

Answer:

[tex]\mu=0.39[/tex]

Explanation:

From the question we are told that:

Angle [tex]\theta=28[/tex]

Acceleration [tex]a=1.25m/s^2[/tex]

Generally the equation for Frictional force  is mathematically given by

[tex]F=\muN[/tex]

Where

[tex]N=mgcos \theta[/tex]

[tex]N=mgcos 28[/tex]

Since

Friction force is acting against move of box

Therefore

[tex]mgsin(28) - 1.25m = \mu mgcos(28)[/tex]

[tex]\mu=\frac{gsin(28) - 1.25}{gcos(28)}[/tex]

[tex]\mu=0.39[/tex]

Answer:

Tangential speed = R * w  where w is the angular speed

For a wheel   v = .114 m * 6.53 / sec = .744 m/s

Note that this is the tangential speed - If the wheel were moving at speed V then as viewed from the ground you have

top V + v

bottom   V - v

That is the wheel also has speed due to the speed of the axle (axis of rotation)

Answer:

second lag

Explanation:

If in a cup game, a specified time limit is assigned to both teams to score high. If both teams are unable to score or if score of both the teams is equal then there is another second lag played where each team tries to score high. Even if in second lag both teams fail to score higher than other the last third lag is played or else game is declared draw.

Answer:

A vector can be written as:

(R, θ)

Where R is the magnitude, in this case, we know that the magnitude of the displacement is 5m

Then:

R = 5m

and θ defines the direction, it's an angle measured from the positive x-axis.

(In the image, θ would be the angle located at the point A)

Now, if you look at the image, you can see a triangle rectangle.

Where the adjacent cathetus has a length of 4,

the opposite cathetus has a length of 3 units

the hypotenuse has a length of 5 units.

So we can use any trigonometric rule to find the value of θ, like:

sin(θ) = (opposite cathetus)/hypotenuse

Then:

sin(θ) = 3m/5m

Now we can use the inverse sin function, Asin(x), in both sides

Asin( sin(θ)) = θ = Asin( 3/5) = 36.87°

then the vector is:

(5m, 36.87°)

Now, if we define the positive y-axis as the North, and the positive x-axis as the East.

This vector would point at 36.87° North of East.

(or almost Northeast)

Answer:

1. 12 V

2a. R₁ = 4 Ω

2b. V₁ = 4 V

3a. A = 1.5 A

3b. R₂ = 4 Ω

4. Diagram is not complete

Explanation:

1. Determination of V

Current (I) = 2 A

Resistor (R) = 6 Ω

Voltage (V) =?

V = IR

V = 2 × 6

V = 12 V

2. We'll begin by calculating the equivalent resistance. This can be obtained as follow:

Voltage (V) = 12 V

Current (I) = 1 A

Equivalent resistance (R) =?

V = IR

12 = 1 × R

R = 12 Ω

a. Determination of R₁

Equivalent resistance (R) = 12 Ω

Resistor 2 (R₂) = 8 Ω

Resistor 1 (R₁) =?

R = R₁ + R₂ (series arrangement)

12 = R₁ + 8

Collect like terms

12 – 8 =

4 = R₁

R₁ = 4 Ω

b. Determination of V₁

Current (I) = 1 A

Resistor 1 (R₁) = 4 Ω

Voltage 1 (V₁) =?

V₁ = IR₁

V₁ = 1 × 4

V₁ = 4 V

3a. Determination of the current.

Since the connections are in series arrangement, the same current will flow through each resistor. Thus, the ammeter reading can be obtained as follow:

Resistor 1 (R₁) = 4 Ω

Voltage 1 (V₁) = 6 V

Current (I) =?

V₁ = IR₁

6 = 4 × I

Divide both side by 4

I = 6 / 4

I = 1.5 A

Thus, the ammeter (A) reading is 1.5 A

b. Determination of R₂

We'll begin by calculating the voltage cross R₂. This can be obtained as follow:

Total voltage (V) = 12 V

Voltage 1 (V₁) = 6 V

Voltage 2 (V₂) =?

V = V₁ + V₂ (series arrangement)

12 = 6 + V₂

Collect like terms

12 – 6 = V₂

6 = V₂

V₂ = 6 V

Finally, we shall determine R₂. This can be obtained as follow:

Voltage 2 (V₂) = 6 V

Current (I) = 1.5 A

Resistor 2 (R₂) =?

V₂ = IR₂

6 = 1.5 × R₂

Divide both side by 1.5

R₂ = 6 / 1.5

R₂ = 4 Ω

4. The diagram is not complete

Answer:

MKS stands for Meter, Kilogram and second. In this system of unit mass is given in Kilogram, length in meter and time in second. ... CGS system stands for Centimeter- Gram- Second system. In CGS system, length is measured in centimeters mass is measured in grams and time is in seconds.

Answer:

The amplitude of the subsequent oscillations is 13.3 cm

Explanation:

Given;

mass of the block, m = 1.25 kg

spring constant, k = 17 N/m

speed of the block, v = 49 cm/s = 0.49 m/s

To determine the amplitude of the oscillation.

Apply the principle of conservation of energy;

maximum kinetic energy of the stone when hit = maximum potential energy of spring when displaced

[tex]K.E_{max} = U_{max}\\\\\frac{1}{2} mv^2 = \frac{1}{2} kA^2\\\\where;\\\\A \ is \ the \ maximum \ displacement = amplitude \\\\mv^2 = kA^2\\\\A^2 = \frac{mv^2}{k} \\\\A = \sqrt{\frac{mv^2}{k}} \\\\A = \sqrt{\frac{1.25\ \times \ 0.49^2}{17}} \\\\A = 0.133 \ m\\\\A = 13.3 \ cm[/tex]

Therefore, the amplitude of the subsequent oscillations is 13.3 cm

When the temperature of the blocks is the same as the temperature of your hand, you feel neither hot nor cold to the touch. Hence, option ( 3) is correct.

Temperature is a unit used to describe hotness or coldness. It can be stated in terms of any number of arbitrary scales and shows the direction in which heat energy will naturally flow, i.e., from a hotter body to a colder body (one at a lower temperature).

Temperature is not the same as the energy of a thermodynamic system; for instance, an iceberg has a significantly larger total heat energy than a match, despite the fact that a match is burning at a much higher temperature.

If you touch a block that is at higher than or  at lower than  the temperature of your hand, you feel hot or cold respectively. But,  when the temperature of the blocks is the same as the temperature of your hand, you feel neither hot nor cold to the touch.

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Answer:

1. 100 J

2. 225 J

Explanation:

We'll begin by calculating the mass of the object. This can be obtained as follow:

Velocity (v) = 5 ms¯¹

Kinetic energy (KE) = 25 J

Mass (m) =?

KE = ½mv²

25 = ½ × m × 5²

25 = ½ × m × 25

25 = 25m / 2

Cross multiply

25m = 25 × 2

25m = 50

Divide both side by 25

m = 50 / 25

m = 2 Kg

1. Determination of the kinetic energy when the velocity is doubled.

Mass (m) = 2 Kg

Velocity (v) = double the initial velocity

= 2 × 5 ms¯¹

= 10 ms¯¹

Kinetic energy (KE) =?

KE = ½mv²

KE = ½ × 2 × 10²

KE = ½ × 2 × 100

KE = 100 J

2. Determination of the kinetic energy when the velocity increased three times.

Mass (m) = 2 Kg

Velocity (v) = three times the initial velocity

= 3 × 5 ms¯¹

= 15 ms¯¹

Kinetic energy (KE) =?

KE = ½mv²

KE = ½ × 2 × 15²

KE = ½ × 2 × 225

KE = 225 J

Answer:

The strain will come to rest after traveling some distance.

distance traveled = 2500 m

Explanation:

The strain will come to rest after traveling some distance.

Applying,

s = ut+at²/2................... Equation 1

Given: u = initial velocity, a = deceleration, t = time, s = distance

From the question,

Given: u = 50 m/s, t = 100s, a = -0.5 m/s²(deceleration)

Substitute these values into equation 1

s = 50(100)+(-0.5)(100²)/2

s = 5000-2500

s = 2500 m

Hence the distance traveled is 2500 m

Answer:

Explanation:

[tex]KE=\frac{1}{2}mv^2[/tex] so filling in:

[tex]KE=\frac{1}{2}(1000)(30)^2[/tex] so to 2 sig figs (which is actually not accurate, but oh well...)

KE = 450000 J

If we want to find out how high it will have to travel up a hill so that its PE is the same as the KE at this speed, we set the value for KE = to PE:

450000 = (1000)(9.8)h so

[tex]h=\frac{450000}{(1000)(9.8)}=45.9m[/tex]

[tex]option \: (a) \: is \: correct.[/tex]

Explanation:

Yes, I was wrong. Pressure increases as the area decreases.

As per the Figure A, the truck is so heavy and having a greater mass. So, the area of contact between the tyres and the road increases and decreases it's pressure on the road due to the increase in area.

As per the Figure B, You know the nature of Tomato that it is soft and smooth to touch and also lighter mass when it's compared with the truck. As it having a lighter mass, it can be cut through the sharp knife. The area of contact decreases and pressure increases on the vegetables.

Answer:

Option number B

Explanation:

The pressure is indirectly proportional to the area therefore pressure decreases when the area increases, and pressure increases when the area decreases

As per the details given, Priya's total distance traveled is 950 meters, displacement is approximately 410.52, speed is 95 meters per minute, and velocity is 41.05 meters per minute.

To calculate Priya's total distance:

Total distance = 300 m + 500 m + 150 m = 950 m

So, Priya's total distance traveled is 950 meters.

To calculate Priya's displacement, we need to find the straight-line distance and direction from her starting point to her ending point.

Displacement = √((Δx)² + (Δy)²)

For Δx:

Δx = 500 m - 150 m × cos(45°)

Δx = 500 m - 150 m × 0.707

Δx = 500 m - 106.05 m

Δx = 393.95 m

For Δy:

Δy = 150 m × sin(45°)

Δy = 150 m × 0.707

Δy = 106.05 m

Displacement = √((393.95 m)² + (106.05 m)²)

Displacement ≈ 410.52 m

So, Priya's displacement is approximately 410.52 meters in a direction of approximately N36°W.

To calculate Priya's speed, we use the formula:

Speed = Total distance ÷ Time

Speed = 950 m ÷ 10 min

Speed = 95 m/min

So, Priya's speed is 95 meters per minute.

To calculate Priya's velocity:

Velocity = Displacement ÷ Time

Velocity = 410.52 m ÷ 10 min

Velocity = 41.05 m/min

Thus, Priya's velocity is 41.05 meters per minute in a direction of N36°W.

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The length and density of the aluminum cube​ is 15.46 cm and 1,081.1 kg/m³ respectively

The volume of the aluminum is equal to the weight of the kerosene displaced.

V = 0.05 kg / 13.5 kg/m³

V = 3.7 x 10⁻³ m³

density = mass/volume

density = 4 kg / 3.7 x 10⁻³ m³

density = 1,081.1 kg/m³

V = L³

L = ∛V

L = ∛(3.7 x 10⁻³)

L = 0.1546 m

L = 15.46 cm

Thus, the length and density of the aluminum cube​ is 15.46 cm and 1,081.1 kg/m³ respectively.

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