Answer:
[see below]
Step-by-step explanation:
"Two-Fifths of a number is 48."
(2/5)n = 48
((2/5n)(5/2) = 48 *(5/2)
n = 120
------------------------------------
120 * (3/4) = 90
Hope this helps you.
Convert 7 6/7 into an improper fraction.
Answer:
55/7Explanation:
Step 1
Multiply the denominator by the whole number
7 × 7 = 49
Step 2
Add the answer from Step 1 to the numerator
49 + 6 = 55
Step 3
Write answer from Step 2 over the denominator
Answer = 55/7
I hope you are enjoying your day and that this helps you out! Brainliest would be appreciated :)Answer:
55/7
Step-by-step explanation:
To convert 7 6/7 to an improper fraction
Start by multiplying the whole number with the denominator 7 x 7 = 49Then add the numerator to the number you get 49 + 6 = 55 The 55 will be your numerator for your improper fraction. 55/7 The denominator will remain the sameWhat is the probability of a red on this spinner?
Be sure to reduce.
Answer:
2/8 or 1/4 simplified
Step-by-step explanation:
If you count how many equal sections there are, you will see there are 8, and 2 or those 8 sections are red so that would easily give you your answer, 2/8.
And to simplify it divide both the top and the bottom by 2 and that gives you 1/4.
Hope the helps! :)
The probability of a red on this spinner would be 1/4.
Used the concept of probability that states,
The term probability refers to the likelihood of an event occurring. Probability means possibility.
Given that,
A spinner is shown in the image.
Since there are a total of 8 parts with different colors.
And, the number of red colors on this spinner is 2.
Hence, the probability of a red on this spinner would be,
P = 2 / 8
P = 1 / 4
Therefore, the probability is 1/4.
Learn more about the probability visit:
https://brainly.com/question/13604758
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please help, i don't understand the subject so i need an answer to help me out:) i will give brainliest to a good answer.
To be honest, I don't think it has anything to do with the exponent part at all. Instead, I think it has to do with the fact that integers are inherently easier to grasp compared to fractions (which is exactly what rational numbers are).
For instance, it's much easier to say 2+3 = 5 than it is to say 1/2 + 1/4 = 3/4
So going back to the exponent example, it's easier to say
x^2*x^3 = x^(2+3) = x^5
than it is to say
x^(1/2)*x^(1/4) = x^(1/2+1/4) = x^(3/4)
So that's my opinion as to why rational exponents are more tricky to grasp compared to integer exponents. Of course, everyone learns math differently so maybe some find fractions easier than others.
Please Help Asap Its Pre-Calculus
The point (−2, 2) is a solution to which of the following systems?
y > −2x + 2 and y > x + 5
y < x + 2 and y > x − 1
y < 2x + 8 and y ≥ −x − 3
y < 2x + 3 and y ≥ −2x − 5
The point [tex](-2,2)[/tex] is a solution of the system given by [tex]y<2x+8[/tex] and [tex]y \geq -x-3[/tex]
Given point: [tex](-2,2)[/tex]
Given systems:
[tex]y>-2x+2[/tex] and [tex]y>x+5[/tex] [tex]y<x+2[/tex] and [tex]y>x-1[/tex] [tex]y<2x+8[/tex] and [tex]y \geq -x-3[/tex] [tex]y<2x+3[/tex] and [tex]y \geq -2x-5[/tex]To find: The system to which the given point is a solution
If a point is a solution of a system, then the coordinates of the point satisfies all the equation(s) or inequation(s) of the system. So, we can substitute the x & y coordinates of the given point into the inequalities of each of the given systems and check if the inequalities are satisfied by the coordinates of the point.
(1) [tex]y>-2x+2[/tex] and [tex]y>x+5[/tex]
Substitute the coordinates of the point [tex](-2,2)[/tex] into the inequalities of the system.
Put [tex]x=-2,y=2[/tex] in [tex]y>-2x+2[/tex] to get,
[tex]2>-2(-2)+2[/tex]
[tex]2>4+2[/tex]
[tex]2>6[/tex]
The above inequality is clearly impossible and thus, the coordinates of the given point does not satisfy this inequality.
This implies that the given point is not a solution of this system.
(2) [tex]y<x+2[/tex] and [tex]y>x-1[/tex]
Substitute the coordinates of the point [tex](-2,2)[/tex] into the inequalities of the system.
Put [tex]x=-2,y=2[/tex] in [tex]y<x+2[/tex] to get,
[tex]2<-2+2[/tex]
[tex]2<0[/tex]
The above inequality is clearly impossible and thus, the coordinates of the given point does not satisfy this inequality.
This implies that the given point is not a solution of this system.
(3) [tex]y<2x+8[/tex] and [tex]y \geq -x-3[/tex]
Substitute the coordinates of the point [tex](-2,2)[/tex] into the inequalities of the system.
Put [tex]x=-2,y=2[/tex] in [tex]y<2x+8[/tex] to get,
[tex]2<2(-2)+8[/tex]
[tex]2<-4+8[/tex]
[tex]2<4[/tex]
This is a true inequality. Then, the given point satisfies the first inequality of the system.
We will now check if the point satisfies the second inequality of the system.
Put [tex]x=-2,y=2[/tex] in [tex]y \geq -x-3[/tex] to get,
[tex]2 \geq -(-2)-3[/tex]
[tex]2 \geq 2-3[/tex]
[tex]2 \geq -1[/tex]
This is also a true inequality. Then, the given point also satisfies the second inequality of the system.
Thus, the given point is a solution of this system.
(4) [tex]y<2x+3[/tex] and [tex]y \geq -2x-5[/tex]
Substitute the coordinates of the point [tex](-2,2)[/tex] into the inequalities of the system.
Put [tex]x=-2,y=2[/tex] in [tex]y<2x+3[/tex] to get,
[tex]2<2(-2)+3[/tex]
[tex]2<-4+3[/tex]
[tex]2<-1[/tex]
The above inequality is clearly impossible and thus, the coordinates of the given point does not satisfy this inequality.
This implies that the given point is not a solution of this system.
Thus, we can see that the coordinates of the given point [tex](-2,2)[/tex] satisfies the inequalities of the third system only.
Then, the point [tex](-2,2)[/tex] is a solution of the system given by [tex]y<2x+8[/tex] and [tex]y \geq -x-3[/tex].
Learn more about geometric solutions of system of linear inequalities here:
https://brainly.com/question/17174433
A giant pie is created in an attempt to break a world record for baking. The pie is shown below:
A circle is shown with a central angle marked 45 degrees and the diameter marked 15 feet.
What is the area of the slice of pie that was cut, rounded to the nearest hundredth?
22.08 ft2
24.45 ft2
26.32 ft2
28.97 ft2
Answer:
22.08 ft^2
Step-by-step explanation:
First find the area of the full circle
A = pi r^2
The diameter is 15 so the radius is 1/2 (15) = 7.5
A = (3.14) (7.5)^2
=176.625
45 degrees is a fraction of a circle which is 360 degrees
45/360 = 1/8
Multiply the area of the circle by this fraction
1/8 (176.625) =22.078125
Rounding to the nearest hundredth
22.08
Answer:
22.08 ft2
Step-by-step explanation:
WILL MARK BRAINLIEST!!
Angelica uses the point 4,3 to represent the location of her house and uses the point 10,8 to represent the location of a gas station. Each unit on the graph represents 1 mi. How far is the gas station from Angelica’s house? Show your work.
Answer:
Angelica's house is 11 miles away from the gas station.
Step-by-step explanation:
The most simple path from Angelica's house is 11 blocks away from the gas station and each unit/block is 1 mile. So 11 miles.
(PLEASE ANSWER ASAP I JUST NEED TO SEE IF I GOT THE RIGHT ANSWER PLEASE EXPLAIN ALSO)
Answer:
37.15 pounds left
Step-by-step explanation:
Add the two pound values
1.3+1.75= 3.05
Subtract it from the total number of pounds in the bag
40.2-3.05
=37.15
Will Mark Brainlest Help Please ,,,,
[tex]\\ \sf\longmapsto 2x+y=2[/tex]
[tex]\\ \sf\longmapsto 2x=2-y[/tex]
[tex]\\ \sf\longmapsto x=\dfrac{2-y}{2}\dots(1)[/tex]
And
[tex]\\ \sf\longmapsto x+1=y+2[/tex]
[tex]\\ \sf\longmapsto x=y+2-1[/tex]
[tex]\\ \sf\longmapsto x=y+1[/tex]
Put the value[tex]\\ \sf\longmapsto \dfrac{2-y}{2}=y+1[/tex]
[tex]\\ \sf\longmapsto 2-y=2(y+1)[/tex]
[tex]\\ \sf\longmapsto 2-y=2y+2[/tex]
[tex]\\ \sf\longmapsto 2-2=2y+y[/tex]
[tex]\\ \sf\longmapsto 3y=0[/tex]
[tex]\\ \sf\longmapsto y=\dfrac{0}{3}[/tex]
[tex]\\ \sf\longmapsto y=\infty[/tex]
Put in eq(1)[tex]\\ \sf\longmapsto x=\dfrac{2-y}{2}[/tex]
[tex]\\ \sf\longmapsto x=\dfrac{2-\infty}{2}[/tex]
[tex]\\ \sf\longmapsto x=\dfrac{2}{2}[/tex]
[tex]\\ \sf\longmapsto x=1[/tex]
Answer:
x=1 , y=0
Step-by-step explanation:
2x+y=2.......1
x+1=y+2
x-y=2-1
x-y=1...... 2
from equation 2 we get ,
x-y=1
x=1+y
putting the value of x in equation 1 we get,
2*(1+y) +y=2
2+2y+y=2
2+3y=2
3y=2-2
3y=0
y=0/3
y=0
putting the value of y in equation 2 we get,
x-0=1
x=1+0
x=1
hence x=1 , y=0
helppppppppppppppp me
Answer:
42
Step-by-step explanation:
5²+3(2)+5+6
25+6+5+6
31+11
42
Hope it helps
Find the area of the figure.
we observe that this figure could be divided into a triangle and a rectangle.
for the area of the triangle, bxh/2, we have 15 x 12/2 = 90
and for the rectangle, we have 5 x 12 = 60
so, 90 + 60 = 150
hope it helps :)
express y=2x²+9x+4 in the form a(x+b)²+c . where a ,b,c are constant
Answer:
2(x+9)^2 + 4
Step-by-step explanation:
.............
Given that cos 75 = X, show that cos 105 = −X
Step-by-step explanation:
cos(90) = 0
around this point the cos function "mirrors" with opposite signs. cos(<90) is positive and cos(>90) is negative.
but |cos(90-a)| = |cos(90+a)| for 0 <= a <= 90
75 = 90 - 15
105 = 90 + 15
so, a = 15
and because of
|cos(90-a)| = |cos(90+a)| for 0 <= a <= 90
cos (90-15) = cos(75) = -cos(90+15) = -cos(105)
Find an explicit formula for the geometric sequence \dfrac12\,,-4\,,\,32\,,-256,.. 2 1 ,−4,32,−256,..start fraction, 1, divided by, 2, end fraction, comma, minus, 4, comma, 32, comma, minus, 256, comma, point, point. Note: the first term should be \textit{a(1)}a(1)start text, a, left parenthesis, 1, right parenthesis, end text. a(n)=a(n)=a, left parenthesis, n, right parenthesis, equals
Answer:
a(n)= 1/2 * (-8) n-1
Step-by-step explanation:
In a geometric sequence, the ratio between successive terms is constant. This means that we can move from any term to the next one by multiplying by a constant value. Let's calculate this ratio over the first few terms:
\dfrac{-256}{32}=\dfrac{32}{-4}=\dfrac{-4}{\frac12}=\blue{-8}
32
−256
=
−4
32
=
2
1
−4
=−8start fraction, minus, 256, divided by, 32, end fraction, equals, start fraction, 32, divided by, minus, 4, end fraction, equals, start fraction, minus, 4, divided by, start fraction, 1, divided by, 2, end fraction, end fraction, equals, start color #6495ed, minus, 8, end color #6495ed
We see that the constant ratio between successive terms is \blue{-8}−8start color #6495ed, minus, 8, end color #6495ed. In other words, we can find any term by starting with the first term and multiplying by \blue{-8}−8start color #6495ed, minus, 8, end color #6495ed repeatedly until we get to the desired term.
Let's look at the first few terms expressed as products:
nn 111 222 333 444
h(n)\!\!\!\!\!h(n)h, left parenthesis, n, right parenthesis \red{\dfrac12}\cdot\!\!\!\left(\blue{-8}\right)^{\,\large0}\!\!\!\!\!\!
2
1
⋅(−8)
0
start color #df0030, start fraction, 1, divided by, 2, end fraction, end color #df0030, dot, left parenthesis, start color #6495ed, minus, 8, end color #6495ed, right parenthesis, start superscript, 0, end superscript \red{\dfrac12}\cdot\!\!\!\left(\blue{-8}\right)^{\,\large1}\!\!\!\!\!\!
2
1
⋅(−8)
1
start color #df0030, start fraction, 1, divided by, 2, end fraction, end color #df0030, dot, left parenthesis, start color #6495ed, minus, 8, end color #6495ed, right parenthesis, start superscript, 1, end superscript \red{\dfrac12}\cdot\!\!\!\left(\blue{-8}\right)^{\,\large2}\!\!\!\!\!\!
2
1
⋅(−8)
2
start color #df0030, start fraction, 1, divided by, 2, end fraction, end color #df0030, dot, left parenthesis, start color #6495ed, minus, 8, end color #6495ed, right parenthesis, squared \red{\dfrac12}\cdot\!\!\!\left(\blue{-8}\right)^{\,\large3}
2
1
⋅(−8)
3
start color #df0030, start fraction, 1, divided by, 2, end fraction, end color #df0030, dot, left parenthesis, start color #6495ed, minus, 8, end color #6495ed, right parenthesis, cubed
We can see that every term is the product of the first term, \red{\dfrac12}
2
1
start color #df0030, start fraction, 1, divided by, 2, end fraction, end color #df0030, and a power of the constant ratio, \blue{-8}−8start color #6495ed, minus, 8, end color #6495ed. Note that this power is always one less than the term number nnn. This is because the first term is the product of itself and plainly 111, which is like taking the constant ratio to the zeroth power.
Thus, we arrive at the following explicit formula (Note that \red{\dfrac12}
2
1
start color #df0030, start fraction, 1, divided by, 2, end fraction, end color #df0030 is the first term and \blue{-8}−8start color #6495ed, minus, 8, end color #6495ed is the constant ratio):
a(n)=\red{\dfrac12}\cdot\left(\blue{-8}\right)^{\large{\,n-1}}a(n)=
2
1
⋅(−8)
n−1
a, left parenthesis, n, right parenthesis, equals, start color #df0030, start fraction, 1, divided by, 2, end fraction, end color #df0030, dot, left parenthesis, start color #6495ed, minus, 8, end color #6495ed, right parenthesis, start superscript, n, minus, 1, end superscript
Note that this solution strategy results in this formula; however, an equally correct solution can be written in other equivalent forms as well.
CAN SOMEONE HELP ME PLEASE
heeeellllp...
...
...
...
...
...
...
Answer:
didn't shade all of them
Factor the polynomial
Answer:
(x+8)(x+7)
Step-by-step explanation:
Find two numbers that add to
b
and mulitply to
a*c
so find two numbers that add to
15
and mulitply to
56
Those two numbers are 8 and 7
therefore the answer is
(x+8)(x+7)
The following ordered pairs represent a function: {(-3, 1), (1, -2), (3, 0), (4, 5)}.
True or False
Answer:
false
Step-by-step explanation:
this is because there is no function of an unknown in this set
18
The length of a rectangle is twice as long as the width of the rectangle.
The area of the rectangle is 32 cm.
Draw the rectangle on the centimetre grid.
.
4
54
B2
%
I did it wrong can someone help me
Answer:
Width = 4 cm
Length = 8 cm
Step-by-step explanation:
Hi there!
Let [tex]l[/tex] be equal to the length of the rectangle.
Let [tex]w[/tex] be equal to the width of the rectangle.
1) Determine equations to find the length and width
We're given that the length is two times the length of the width:
[tex]l=2w[/tex]
We're also given that the area of the rectangle is 32 cm². Recall that the area of a rectangle is [tex]A=lw[/tex]:
[tex]A=lw\\32=lw[/tex]
Now, we have our two equations:
[tex]\displaystyle \left \{ {{l=2w} \atop {32=lw}} \right.[/tex]
2) Solve for the width using substitution
[tex]\displaystyle \left \{ {{l=2w} \atop {32=lw}} \right.[/tex]
Replace [tex]l[/tex] in the second equation with [tex]2w[/tex] from the first equation:
[tex]32=(2w)w\\32=2w^2[/tex]
Divide both sides by 2 to isolate w²:
[tex]16=w^2[/tex]
Take the square root of both sides to isolate w:
[tex]\pm4=w[/tex]
Because width cannot be negative, w=4. Therefore, the width of the rectangle is 4 cm.
3) Solve for the length
[tex]\displaystyle \left \{ {{l=2w} \atop {32=lw}} \right.[/tex]
Now, that we have the width (4 cm), we can solve for the length by plugging it back into one of the equations. Either of the equations work, but we can use the first:
[tex]l=2w\\l=2(4)\\l=8[/tex]
Therefore, the length of the rectangle is 8 cm.
3) Draw the rectangle
We can use what you had before as a foundation. You drew a rectangle with width 4 cm and length 7 cm. To draw the correct rectangle, add another row on top to make it 4 cm by 8 cm.
I hope this helps!
Question 10 The hypotenuse of a right triangle is I m longer than the longer leg. The other leg is 7 m shorter than the longer leg. Determine the lengths of the three sides of the triangle. (3 marks)
Answer:
5, 12, 13
Step-by-step explanation:
let x be the longer leg then x + 1 is the hypotenuse and x - 7 the shorter leg
Using Pythagoras' identity in the right triangle
x² + (x - 7)² = (x + 1)² ← expand using FOIL
x² + x² - 14x + 49 = x² + 2x + 1
2x² - 14x + 49 = x² + 2x + 1 ( subtract x² + 2x + 1 from both sides )
x² - 16x + 48 = 0 ← in standard form
(x - 4)(x - 12) = 0 ← in factored form
Equate each factor to zero and solve for x
x - 4 = 0 ⇒ x = 4
x - 12 = 0 ⇒ x = 12
x = 4 , then x - 7 = 4 - 7 = - 3 ← not possible
x = 12, then x - 7 = 12 - 7 = 5 and x + 1 = 12 + 1 = 13
The lengths of the 3 sides are
longer leg = 12 m , shorter leg = 5 m and hypotenuse = 13 m
Type the equation for the graph
below.
Answer:
Step-by-step explanation:
This is a "regular" sin graph that's "taller" than the original. The amplitude is 3; other than that, its period is the same and it has not shifted to the right or left, so the equation, judging from the graph, is
[tex]y=3sin(x)[/tex]
ILL GIVE POINTS!! PLS HELP !!!
Which set of polar coordinates describes the same location as the
rectangular coordinates (1. - 1)?
A. (sqrt2,315°)
B. (-1,135°) C. (sqrt2,225°)
D. (1,45°)
Answer:
The polar coordinates appear in the form (r, θ), where r is the the radius from the center and θ is the angle. To get the radius, do the following.
[tex]r = \sqrt{x^2 + y^2} = \sqrt{1^2 + (-1)^2} = \sqrt{2}\\[/tex]
You can get the angle visually by drawing a point (1, -1) on a graph and seeing that it is 45 degrees from the top right quadrant (you can tell its 45 because both x and y have the same magnitude). Since there are 360 degrees, 360 - 45 = 315.
If you would like to find it mathematically, this is the way to do it
[tex]\theta = atan(y/x) = -45[/tex]
Notice that -45 degrees is just 360 - 45 = 315
Your answer would be
[tex](\sqrt{2}, 315)[/tex]
Find the 6th term of each geometric sequence. 9, 45, 225, 1125
Answer:
28125
Step-by-step explanation:
Refer to the image below.
Can someone help me with this please !!
Step-by-step explanation:
I need help to...
I keep putting it in and no one has ever answered it and I'm struggling and getting stressed.
Answer pls……………………….
Answer:
D
Step-by-step explanation:
x^2=y^3
Then x^6=y^9 but x^3z=z^9 so 3z=6, z=2
Answer:
z = 2
Step-by-step explanation:
[tex]x^{3z} = y^{9}\\\\x^{3z} =y^{3*3} \\\\x^{3z}= (y^{3})^{3}\\\\x^{3z}=(x^{2})^{3}\\\\x^{3z} = x^{6}[/tex]
As bases are same, compare the powers
3z = 6
z = 6/3
z = 2
A pendulum's height is modeled by the function h(t) = 4 cos(pi/4*t) + 8 where h is the
measure of the pendulum's height in feet and t is the number of seconds since the
maximum height. How many seconds does it take the pendulum to complete one
full swing?
===========================================================
Explanation:
The general cosine template is
y = A*cos(B(t - C)) + D
where in this case
A = 4B = pi/4C = 0D = 8We only really need to worry about the B value. To get the period T, we do the following
T = 2pi/B
T = (2pi)/(pi/4)
T = 2pi * (4/pi)
T = 8
Note how the pi terms canceled. The period is 8 seconds, which is the length of one full cycle. This is the time it takes for the pendulum to do one full swing (eg: start at the right, swing to the left all the way, then swing back to the right again).
The result of 8 we got has nothing to do with the D = 8 value (this D value could be any other number and T = 8 would still be the case as long as B doesn't change of course).
Please help will give brainliest, pls don’t just guess
Answer:
B = multiply both sides by 2y+1
Step-by-step explanation:
Answer:
B. multiply both sides by the equation 2y + 1
Find: (6m5 + 3 – m3 – 4m) – (–m5 + 2m3 – 4m + 6)
Answer: 7m⁵ -3m³ - 3
Working:
= (6m⁵ + 3 - m³ - 4m) -(-m⁵ + 2m³- 4m +6)
= 6m⁵ + 3 - m³ - 4m +m⁵-2m³+4m - 6
= 6m⁵ + m⁵-m³ -2m³ -4m + 4m - 6 +3
= 7m⁵ -3m³ - 3
Answered by Gauthmath must click thanks and mark brainliest
f(x)=square root 2x and g(x)=square root 50x find (f/g)(x)
Answer:
1/5
Step-by-step explanation:
(f/g)(x) = f(x)/g(x) = sqrt(2x)/sqrt(50x) = 1/5
solve for x.
solve for x.
solve for x.
Answer:
x = 10
Step-by-step explanation:
7(x+1+7)=6(x+5+6)
or, 7(x+8)=6(x+11)
or, 7x+56=6x+66
or, 7x-6x=66-56
or, x=10
Answered by GAUTHMATH
An equilateral triangle has a perimeter of 18 feet. If a square whose sides have the same length as one side of the triangle is built, what will be the area of the square?
Answer:
36 ft²
Step-by-step explanation:
equilateral means all sides are equally long.
a triangle has 3 sides.
in our case they are all equally long.
and their sum (all 3 sides together) is the perimeter
P = 18 = 3 × side length
side length = 18/3 = 6 ft
a square with the same side length (6) had then an area of
side length × side length = 6×6 = 6² = 36 ft²
it is important to remember : a length is measured e.g. in feet (ft). an area is then meshed in square-feet (ft²). it is important to add this to the calculated numbers to express the right dimension of these numbers.