Two drums of the same size and same height are taken.
i)what will be the difference in liquid pressure on their bases if A of them is completely filled and B is half filled and kept at the same place.
ii) what will be the difference in liquid pressure on their bases if both A and B are filled with water completely but one of them is kept at nepal and another in india?why?
iii) what will be the difference in liquid pressure on their bases if A is filled with water and B is filled with salty water and kept at delhi in the same position?why?​

Answers

Answer 1

Answer:

i) The pressure acting on the base of B will be half the pressure acting on the base of A

ii) The pressure acting on the base of B will be the same as the pressure acting on the base of A

iii) The pressure on the base of drum A will be slightly less than the pressure on the base of drum B

Explanation:

The pressure acting on the base of the drum, P = h·ρ·g

Where;

h = The level of the liquid in the drum

[tex]h_{max}[/tex] = The height of the drums

ρ = The density of the liquid in the drum

g = The acceleration due to gravity ≈ 9.81 m/s²

i) If A is completely filled, we have [tex]h_A[/tex] = [tex]h_{max}[/tex]

Therefore, [tex]P_A[/tex] = [tex]h_{max}[/tex]×[tex]\rho_{liquid}[/tex]×g

If B is half filled, we have, [tex]h_B[/tex] =  (1/2)·[tex]h_{max}[/tex]

[tex]P_B[/tex] = (1/2) × [tex]h_{max}[/tex]×[tex]\rho_{liquid}[/tex]×g

Therefore, [tex]P_B[/tex] = (1/2) × [tex]P_A[/tex]

The pressure acting on the base of B will be half the pressure acting on the base of A

ii) If both A and B are each filled with water (the same liquid), then the pressure on their bases will be [tex]P_A[/tex] = [tex]h_{max}[/tex]×[tex]\rho_{water}[/tex]×g = [tex]P_B[/tex], the same, given that the acceleration due to gravity, g, is constant and the same in Nepal and India

iii) If A is filled with water, and B is filled with salty water, we have that, the density of salty water is slightly higher than water, therefore, we get;

[tex]P_A[/tex] = [tex]h_{max}[/tex]×[tex]\rho_{water}[/tex]×g <  [tex]P_B[/tex] =

The pressure on the base of drum A will be less than the pressure on the base of drum B.


Related Questions

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Answer:

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hello dost timi kasto cha

If a force of 1250 N acts on an area of 25 metres squared, what will be the pressure acting on the surface? Show your working as well.

Answers

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Explanation:

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Answer:

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Answers

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Explanation:

1. rearrange equation p = mv to find v

2. v = p/m - then convert 800 g into kg (= 0.8 kg)

3. plug in p and m - v = 20 / 0.8 = 25 m/s

Answer:

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Explanation:

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Answer:

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I hope this help you!:)

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Answer:

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Answer:

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Answer:

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Answer:c

Explanation:

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Answer:

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Answer:

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Answers

Pressing a lever in the box's corner is the sole method to get rid of the shocks. The rat picks up pressing the lever quite quickly. This is an illustration of negative reinforcement.

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have a higher intensity in the red part of the spectrum

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Answers

Answer:

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Explanation:

Wool which is mixed with certain substances, conducts electricity in a manner similar to the wool-water system that give rise to centers of impurities where electrical conduction takes place

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Answers

Answer:

the magnitude of the momentum of the two-ball system immediately after collision is 32.31 kg.m/s

Explanation:

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mass of the first ball, m₁ = 1.0 kg

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initial velocity of the first ball, v₁ = 30 m/s due west

initial velocity of the second ball, v₂ = 6 m/s due north

From the principle of conservation of linear momentum;

the total momentum before collision = total momentum after collision

The westward momentum of the first ball, = m₁v₁ = 1 x 30 = 30 kg.m/s

The northward momentum of the second ball = m₂v₂ = 2 x 6 = 12 kg.m/s

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R = 32.31 kg.m/s

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Answers

Answer:

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a body starts moving from rest and attains the acceleration of 2 metre square calculate the velocity at the end of 310 minutes and also find the distance traveled by it during that time​

Answers

Answer:

Here, we have

Initial velocity, u = 0 m/s (As starts from rest)

Acceleration, a = 2 m/s².

Time taken, t= 310 min = 310 × 60 = 18600 seconds

To Find,

Final velocity, v and,

Distance covered, s

Formula to be used,

1st and 3rd equation of motion,

v = u + at and v² - u² = 2as

So, putting all the values, we get

V = u + at

v = 0 + 2 x 18600

v = 2 x 18600 → v = 37200 m/s.

Hence, the final velocity is 37200 m/s.

Now, Distance covered,

v² - u²= 2as

(37200 )² - (0)² = 2 x 2 x s

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Answers

Answer:

• Initial velocity (u) = 0 m/s

• Final velocity (v) = 40 m/s

• time (t) = 8s

Acceleration :

[tex]\implies \sf a = \dfrac{\Delta v}{ t} \\ [/tex]

[tex]\implies \sf a = \dfrac{v - u}{ t} [/tex]

[tex]\implies \sf a = \dfrac{40 - 0}{ 8} [/tex]

[tex]\implies \sf a = \dfrac{40}{ 8} [/tex]

[tex]\implies \bf a = 5 \: {ms}^{ - 2} [/tex]

• Distance travelled by the motorcycle:

[tex] \longrightarrow \sf {v}^{2} - {u}^{2} = 2as \\ [/tex]

[tex]\longrightarrow \sf {(40)}^{2} - {(0)}^{2} = 2 \times5 \times s \\ [/tex]

[tex] \longrightarrow \sf 1600 = 10s[/tex]

[tex]\longrightarrow \sf s = \dfrac{1600}{10} [/tex]

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A 45.0 kg student runs at a constant velocity up the incline 6 metres high. If the power output of the student is 1.50 x 103 W, how long does it take the student to run the 9.0 m along the incline?

Answers

Answer:

The time taken is 1.76 s.

Explanation:

mass of student, m = 45 kg

height, h = 6 m

power, P = 1500 W

Power is defined as the rate of doing work.

Work done in moving height is

W = m g h

Let the time is t.

P = m g h / t

1500 = 45 x 9.8 x 6 / t

t = 1.76 s

Write down the role played by four digestive juices in digestion and the
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Answer:

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How is the potential difference same in capacitors arranged in parallel combination?​

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Answer:

Potential difference across capacitors in parallel

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A glass rod acquires charge by rubbing silk cloth. The charge on the glass is due to:
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(b) Conduction
(c) Induction
(d) Radiation

Answers

Answer:

(a)Friction

Explanation:

It is due to friction as you are rubbing the glass rod with silk cloth  

as friction occurs when 2 surfaces are rubbed against each other

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