Two boats leave the same port at the same time. One travels at a speed of 28 mi/h in the direction N 50° E, and the other travels at a speed of 26 mi/h in a direction S 70° E (see the figure). How far apart are the two boats after 1 h? (Round your answer to the nearest mile.)

Two Boats Leave The Same Port At The Same Time. One Travels At A Speed Of 28 Mi/h In The Direction N

Answers

Answer 1

Answer:

  27 miles

Step-by-step explanation:

The law of cosines can be used to find the distance between the boats. In 1 hour, one has traveled 28 miles, and the other has traveled 26 miles. The angle between their directions of travel is ...

  180° -50° -70° = 60°

Then the distance c can be found from ...

  c^2 = a^2 +b^2 -2ab·cos(C)

  c^2 = 28^2 +26^2 -2·28·26·cos(60°) = 732

  c = √732 ≈ 27.055

The boats are 27 miles apart after 1 hour.

Two Boats Leave The Same Port At The Same Time. One Travels At A Speed Of 28 Mi/h In The Direction N

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Answer:

S=2

Step-by-step explanation:

the answer can not be higher than 2 because the inequality shows 9 is bigger than what is being added.

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Let's simpify the inequality ~

[tex]9 \geqslant s + 7[/tex]

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

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Answer:

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answer:

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