True or false, the two triangles are congruent by ASA
O true
false

Answer: 12 x 8

Step-by-step explanation: The other three are not the basic multiplication facts from 0 - 12.

Using the t-distribution, it is found that the 99% confidence interval for the difference is (0.058, 3.462).

We are given the standard deviation for the samples, hence, the t-distribution is used to solve this question.

The standard errors are given by:

[tex]s_A = \frac{1.79}{\sqrt{18}} = 0.4219[/tex]

[tex]s_B = \frac{1.95}{\sqrt{18}} = 0.4596[/tex]

For the distribution of differences, the mean and the standard error are given by:

[tex]\overline{x} = \mu_A - \mu_B = 23.95 - 22.19 = 1.76[/tex]

[tex]s = \sqrt{0.4219^2 + 0.4596^2} = 0.6239[/tex]

The interval is given by:

[tex]\overline{x} \pm ts[/tex]

The critical value for a two-tailed 99% confidence interval with 18 + 18 - 2 = 34 df is t = 2.7284.

Then:

[tex]\overline{x} - ts = 1.76 - 2.7284(0.6239) = 0.058[/tex]

[tex]\overline{x} + ts = 1.76 + 2.7284(0.6239) = 3.462[/tex]

The 99% confidence interval for the difference is (0.058, 3.462).

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Answer:

32 qt = 8 gal

Step-by-step explanation:

1 qt x 32 = 1/4 gal x 32

32 qt = 32/4 gal

32 qt = 8 gal

Answer:

[tex]t_4 = 20[/tex]

Step-by-step explanation:

The base case in the recursive function are:

[tex]t_1 = 1[/tex]

[tex]t_2 = 2[/tex]

The recursive case is equal to:

[tex]t_n = 2t_{n-1} + 3t_{n-2}[/tex]

So replace [tex]t_n[/tex] for [tex]t_4[/tex]:

[tex]t_4 = 2t_{3} + 3t_{2}[/tex]

In the new expression [tex]t_2[/tex] is a base case so you don't have to worry for that part, but [tex]t_3[/tex] is still the recursive case so evaluate again in [tex]t_n[/tex]

[tex]t_3 = 2t_{2} + 3t_{1}[/tex]

[tex]t_2[/tex] and [tex]t_1\\[/tex] are define as base cases so you replace for it's numbers:

[tex]t_3 = 2(2) + 3(1) = 7[/tex]

Now return to [tex]t_4[/tex] and replace for the new values:

[tex]t_4 = 2(7) + 3(2) = 14 + 6 = 20[/tex]

So the final answer is 20

Answer:

9 mm

Step-by-step explanation:

90*0.1=9

The area of the rectangular field is 0.07 square kilometers (km²).To find the area of the rectangular field in square kilometers, we need to convert the given dimensions from meters to kilometers.

To find the area of the rectangular field in square kilometers, we need to convert the given dimensions from meters to kilometers and then calculate the area.

Given:

Length of the field = 350 meters

Width of the field = 200 meters

To convert from meters to kilometers, we divide the measurements by 1000, since there are 1000 meters in a kilometer.

Length in kilometers = 350 meters / 1000 = 0.35 kilometers

Width in kilometers = 200 meters / 1000 = 0.2 kilometers

Now that we have the dimensions of the field in kilometers, we can calculate the area.

Area of the field = Length in kilometers * Width in kilometers

Area of the field = 0.35 kilometers * 0.2 kilometers

Multiplying the values, we get:

Area of the field = 0.07 square kilometers

Therefore, the area of the rectangular field is 0.07 square kilometers.

It's important to include the correct unit in the answer, which is "square kilometers" (km²). This represents the unit for measuring the two-dimensional area. In this case, the area of the field is 0.07 km².

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The project in her Geometric class is an illustration of equivalent ratios

The approximated height of the flagpole is 13.19 meters

The given parameters are:

Distance from flagpole (D) = 14.25

Distance to the other side of the mirror (d) = 1.35

Kylie's height (h) = 1.25

To calculate the height (H) of the flagpole, we make use of the following equivalent ratios

[tex]\mathbf{D :d = H :h}[/tex]

Substitute known values

[tex]\mathbf{14.25 :1.35 = H :1.25}[/tex]

Express as fraction

[tex]\mathbf{\frac{14.25 }{1.35 }= \frac{H }{1.25}}[/tex]

Multiply both sides by 1.25

[tex]\mathbf{H = 1.25 \times \frac{14.25 }{1.35 }}[/tex]

Multiply

[tex]\mathbf{H = 13.19 }[/tex]

Hence, the approximated height of the flagpole is 13.19 meters

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Answer:

she would have 3ft. 10 inches of board

Step-by-step explanation:

Answer:

3ft and 10inches

Step-by-step explanation:

so 6ft 8 in minus 10in is 5ft 10 in

then 5ft minus 2ft is 2ft the rest is a piece of cake

Answer:

Step-by-step explanation:

55.345 is rounded off two places therefore, the hundreths place

the number next to 4 is 5 in the thousandths place. 5 is high and therefore 4 is changed to 5 and makes it 53.35

Answer:

7 boys to 10 all children

Answer:

Step-by-step explanation:

So at 38mph you are roughly traveling .6333 miles a minute. So 13 miles would take you roughly 8.2 minutes. How does one figure out this?

We know that there are 60minutes in an hour. We know you’re driving 38miles per hour. Dividing 38 by 60 gives you the miles per minute. Multiple that by how many miles you’re driving to get an estimate of the minutes it takes to drive those miles.

Answer:

∠b = 95°

Step-by-step explanation:

Assuming these angles are Supplementary, it would look something like this:

                                       /

                          ∠b      /    ∠a

  _______________/__________________

If this is true, and ∠a = 85°, then this means that ∠b must equal 95° because being supplementary angles means all angles add to 180°, so 180 - 85 = 95

Answer:

90° − 85° = 5°

Answer:

x= - 3/5y +4/5

Step-by-step explanation:

isolate x:

5x+ 3y= 4

5x= -3y+ 4

x= -3/5y +4/5

Answer:

Step-by-step explanation:

the answer is 1.1324

[tex] \red{ \rule{40pt}{555555pt}}[/tex]

[tex](\stackrel{x_1}{-4}~,~\stackrel{y_1}{6})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{5}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{5}-\stackrel{y1}{6}}}{\underset{run} {\underset{x_2}{-2}-\underset{x_1}{(-4)}}}\implies \cfrac{-1}{-2+4}\implies \cfrac{-1}{2}\implies -\cfrac{1}{2}[/tex]

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{6}=\stackrel{m}{-\cfrac{1}{2}}[x-\stackrel{x_1}{(-4)}] \\\\\\ y-6=-\cfrac{1}{2}(x+4)\implies y-6=-\cfrac{1}{2}x-2\implies \underset{\textit{slope-intercept form}}{y=-\cfrac{1}{2}x+4}[/tex]

Answer:

The correct answer is 66,045

Answer:

-2.65

Step-by-step explanation:

Answer:

Step-by-step explanation:

Initial class size = 30 students

Class size now is 40% larger:

First let's find larged amount

[tex]\\ \sf\longmapsto 40\%\:of\:30[/tex]

[tex]\\ \sf\longmapsto 0.4(30)[/tex]

[tex]\\ \sf\longmapsto 12[/tex]

Class size=30+12=42students

Answer:

It'll be B.10

Step-by-step explanation:

Rectangles always have 2 side lower than the other2 . BC and AD are same length so they are both 13. BA and CB are the same length to It has to be 10.

Hope this helps :)

cyclist a speed is d = v × t

so you can find velocity of a and b.

then compare them both.

Step-by-step explanation:

(10+5)³-1 = 3375-1 = 3374.

Answer:

6+x=15 (x=9)

Step-by-step explanation:

6 cookies + the newly baked ones = 15 cookies

we know there was 6 cookies and we knew that the result is 15, which means that we "don't know" how many cookies are baked. So the answer is 6+x=15

5 bombas deben trabajar durante 4 dias para llenar la piscina.

Cada bomba trabaja a un rate (razon de trabajo) R.

Sabemos que 3 bombas, trabajando 5 horas diarias por 10 días (un total de 50 horas), llena una piscina, entonces:

(3R)*50 horas= 1 piscina.

R = (1 piscina)/(150 horas).

Es decir, una sola bomba tarda 150 horas en llenar una piscina.

En el caso de que 5 bombas trabajen, tenemos que para llenar una piscina tienen que trabajar un tiempo T.

5*((1 piscina)/(150 horas))*T = 1 piscina.

(1 piscina)/(30 horas)

Resolviendo para T, obtenemos:

T = 1 piscina*(30 horas)/(1 piscina) = 30 horas.

Y sabemos que trabajan 8 horas diarias, es decir, las bombas deben trabajar durante:

30/8 = 3.75 ≈ 4 días.

5 bombas deben trabajar durante 4 dias para llenar la piscina.

Sí quieres aprender más sobre razones de trabajo.

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[tex] \frac{1}{2} \: to \: the \: power \: of \: 5 \: is \: \frac{1}{32} or \: 0.03125 [/tex]

Answer:

[tex] \ {\boxed{ \tt ( \frac{1}{2}) ^{5} = \frac{1}{32} }}[/tex]

Step-by-step explanation:

[tex] \\ \tt( \frac{1}{2} )^{5} [/tex]

[tex] \\ \tt= \frac{ {1}^{5} }{ {2}^{5} } [/tex]

[tex] \\ \tt = \frac{1 \times 1 \times 1 \times 1 \times 1}{2 \times 2 \times 2 \times 2 \times 2} [/tex]

[tex] \\ \tt = \frac{1}{32} [/tex]

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

The correct Choice is ~ D

a || b by the converse of the same side interior angles

Answer: [tex]x^{2/5}[/tex][tex]y[/tex]

Step-by-step explanation:

([tex]x^{2}[/tex][tex]y^{5}[/tex])^[tex]^{1/5}[/tex]

= [tex]x^{2/5}[/tex][tex]y[/tex]

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

A. " Certain " is shown by letter E

B. " Even " is shown by letter C

C. " Impossible " is shown by letter A

Step-by-step explanation:

10 1

20 miles car travel 65t hb

Answer:

Hello!

Judging by the link you provided I have come up with the correct solution:

x= 61°

y= 29°

Step-by-step explanation:

I will link my work below:

The first step to finding the two solutions it to first identify one of them.

I chose to identify x first.

To identify the value of x in this problem you have to notice that the x value corresponds with the value "29°" to form a perfect right angle, being 90°.

Thus you can simply find the value of x by doing this formula:

x+29°=90°

You then subtract 29° from both sides to simplify, and you come up with the solution

x=61°

Now we need to find the value of y.

To find the value of y I noticed that again, like x, y corresponds with another variable (being x) to form a perfect right angle (90°).

The way I realized this is a perfect right angle is because, as you can see in the picture you provided, the y+x angle are alternate exterior angles with another angle that is 90°.

Thus you can assume that:

x+y=90°

x= 61°

61°+y=90°

You then subtract 61° from both sides to get:

y=29°