Answer:
D)
DF = 52
AB = 48
Step-by-step explanation:
Use the two lengths of sides already given.
Divide to find the scale factor:
20 / 5 = 4
Scale factor: 4
Now multiply to find the unknown sides:
13 × 4 = 52
12 × 4 = 48
DF = 52
AB = 48
Hope this helped.
PLS SOMEONE HELP ASAP IT'S DUE TONIGHT TY AND ILYSM <3
if the trends in yearly median earnings continues for both men and women. how many years after 1960 will women have a median yearly eating that is greater than the men's? In what year will this occur?
Step-by-step explanation:
yes because women where making the food for the men so they where eating the most food(a) Express the prime number 3 as the difference of two squares? 3=
Answer:
2^2 - 1^2
Step-by-step explanation:
1^1 = 1
2^2 = 4
4-1 =3
2^2 - 1^1 = 3
Hoa mua 2 con gà . Lan mua 4 con gà. Hỏi cả 2 bạn mua bao nhiêu con gà
Answer: 6 con ga
Step-by-step explanation:
So ga ca 2 ban mua la:
2+4=6 (con ga)
13 is subtracted from the product of 4 and a certain number. The result is equal to the sum of 5 and the original number. Find the number.
Answer:
Step-by-step explanation:
4x - 13 = x + 5 Add 13 to both sides
4x = x + 18 Subtract x
3x = 18 Divide by 3
x = 6
heSellsSeaShells is an ocean boutique offering shells and handmade shell crafts on Sanibel Island in Florida. Find the price SheSellsSeaShells should charge to maximize revenue if p(x)=160−2xp(x)=160−2x, where p(x)p(x) is the price in dollars at which xx shells will be sold per day.
Answer:
it's too much for me im a child u know
Figure
А A
Figure B
How many squar
w many square are in
tigne
this
Answer:
7 square are 0resent on aaaaaa
write the first 10 multiples of 2 and 3 and find LCM.
Answer:
multiples of 2 2,4,6,8,10,12,14,16,18,20
multiples of 3 3,6,9,12,15,,18,21,24,27,30
Step-by-step explanation:
Lcm is 6
pls help Describe how to find the product of the two terms 3x^2y^5 and 4x^3y^7
Answer:
12 x^5y^12
Step-by-step explanation:
3x^2y^5 * 4x^3y^7
Multiply the constants
3*4 = 12
Multiply the x terms
x^2 * x^3
We know a^b* a^c = a^(b+c)
x^(2+3) = x^5
Multiply the y terms
y^6 * y^7 = y&(5+7) = y^12
Put them back together
12 x^5y^12
Due the end of the week pls help.
This problem seems like a lot when you read through it, but when you start to analyze the problem, the whole first line is extra information that we don't actually need. The part we really need to pay attention to is:
"p = qr - f, write the equation with q solved in terms of p, r, and f."
So, all we are doing here is some manipulating of the equation to get what we want. So, if p = qr - f, we can isolate the variable (q), to get p + f = qr. Now all we have to do is divide both sides by r to isolate the variable (q) even further, and we get [tex]$\frac{p+f}{r}=q$[/tex] or [tex]$r=\frac{p+f}{r}$[tex]
Which of the binomials below is a factor of this expression?
16x2 + 40xy + 25y2
16x²+40xy + 25y²
(4x+5y) (4x+5y)
(4x+5y)²
I hope I helped you^_^
look at the image below
Answer:
117.8
Step-by-step explanation:
Surface area = πr²+πrl (whee r = radius and l = slant height)
= π×3²+π×3×9.5
= 75π/2
= 117.8
The difference between the greatest and the smallest 5-digit numbers formed by using each of the digits 2, 0, 4 and 6 at least once is
Answer:
46374
Step-by-step explanation:
The smallest 5-digit number is 20046
While the greatest is 66420
So 66420-20046=46374
Help me please and thank you
Answer:
D. 3
Step-by-step explanation:
Answer:
3
step by step explanitation
write your answer in simplest radical form
Answer:
a = 4[tex]\sqrt{3}[/tex]
Step-by-step explanation:
Using the cosine ratio in the right triangle and the exact value
cos60° = [tex]\frac{1}{2}[/tex] , then
cos60° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{2\sqrt{3} }{a}[/tex] = [tex]\frac{1}{2}[/tex] ( cross- multiply )
a = 4[tex]\sqrt{3}[/tex]
For each kilogram of a persons weight 2.5 milligrams of a drug is to be given. what dosage should be given to a child who weighs 84 pounds? Use the fact that 1 lb = 0.45 kg
Answer:
A child who weighs 84 pounds should be given 94.5 milligrams of the drug.
Step-by-step explanation:
Givens:
1kg=2.5 milligrams of dosage
Weight of child = 84 pounds
1 pound = 0.45 kg
Solution:
Convert pounds to kilograms --> 84lbs*0.45kg = 37.8 kg
Convert weight to dosage --> 37.8kg * 2.5 mg = 94.5 mg of dosage.
a cycle travel 1st km at therateof 10 km per hour the second km at the rate of 3 per hour and third at therate of 6 km.find the average speed of cyclea cycle travel 1st km at therateof 10 km per hour the second km at the rate of 3 per hour
Answer:
18 kilometers 120 kilometers
Given the function f(x) = -5x + 2, find the range ofly for x = -1, 0, 1.
O 7, 2, -3
O 7, 2, 3
O-7, -2, 3
0-7, -2, -3
Answer:
A
Step-by-step explanation:
f(-1)=7, f(0)=2, f(1)=-3
what is the lub and glb of the following sets, in the set of real numbe if exists E={ 0.2,0.23,0.234,0.2343,0.23434,0.23434,...}
Answer:
Hello,
Step-by-step explanation:
[tex]LUB(E)=0.2=\dfrac{1}{5} \\\\GUB(E)=0.2 34 34 34 ....=0.2+\dfrac{1}{10} *0.343434....\\\\=\dfrac{1}{5} +\dfrac{1}{10} *\dfrac{34}{99} \\\\=\dfrac{198+34}{990} \\\\=\dfrac{116}{495}[/tex]
Point g is located at (3,6) on the coordinate plane. Point G is reflected over the x-axis to create point G'. Point G' is then reflected over the y-axis to create point G''. What ordered pair describes the location of G''.
-Answer:
(-3. -6)
Step-by-step explanation:
G (3,6)
x axis reflect
G' (3, -6)
y axis reflect
G'' (-3. -6)
Emily, Yani and Joyce have a total of 3209 stickers. Yani has 2 times
as many stickers as Joyce. Emily has 279 more stickers than Yani. How
many more stickers does Emily have than Joyce?
Answer:
279+x
Step-by-step explanation:
Emily + Yani + Joyce=3209 stickers
if Yani has 2 times as many stickers as Joyce:this statement states that Joyce has x stickers and Yani has 2x stickers because x multiplied by 2"Emily has 279 more stickers than Yani":therefore the equation for Emily will be ;279+2xhow many stickers does Emily have than Joyce:
(279+2x)-(x)
279+2x-x
=279+x
3 log2 (x+1) - 2 = 13
Answer:
Hello,
Answer 31
Step-by-step explanation:
[tex]3*log_2(x+1)-2=13\\\\3*log_2(x+1)=13+2\\\\log_2(x+1)=5\\\\\\x+1=2^5\\\\x=32-1\\\\\boxed{x=31}\\[/tex]
Please help me with this on the image
Answer:
a) Obtuse angle b) Reflex anglethe age of furaha is 1/2 of the age of her aunt if the sum of their ages is 54 years. find the age of her aunt
Answer:
I think it is twenty seven
Use the point-slope formula to determine the equation of the line that has a slope of 1⁄2 and passes through point (0, 0).
Answer:
y-0 = 1/2(x-0)
y = 1/2(x)
Step-by-step explanation:
Point slope form is
y-y1 = m(x-x1)
where m is the slope and (x1,y1) is a point on the line
y-0 = 1/2(x-0)
y = 1/2(x)
Two sides of a triangle have lengths 13 m and 19 m. The angle between them is increasing at a rate of 2°/min. How fast is the length of the third side increasing when the angle between the sides of fixed length is 60°? (Round your answer to three decimal places.)
Answer:
The third side is increasing at an approximate rate of about 0.444 meters per minute.
Step-by-step explanation:
We are given a triangle with two sides having constant lengths of 13 m and 19 m. The angle between them is increasing at a rate of 2° per minute and we want to find the rate at which the third side of the triangle is increasing when the angle is 60°.
Let the angle between the two given sides be θ and let the third side be c.
Essentially, given dθ/dt = 2°/min and θ = 60°, we want to find dc/dt.
First, convert the degrees into radians:
[tex]\displaystyle 2^\circ \cdot \frac{\pi \text{ rad}}{180^\circ} = \frac{\pi}{90}\text{ rad}[/tex]
Hence, dθ/dt = π/90.
From the Law of Cosines:
[tex]\displaystyle c^2 = a^2 + b^2 - 2ab\cos \theta[/tex]
Since a = 13 and b = 19:
[tex]\displaystyle c^2 = (13)^2 + (19)^2 - 2(13)(19)\cos \theta[/tex]
Simplify:
[tex]\displaystyle c^2 = 530 - 494\cos \theta[/tex]
Take the derivative of both sides with respect to t:
[tex]\displaystyle \frac{d}{dt}\left[c^2\right] = \frac{d}{dt}\left[ 530 - 494\cos \theta\right][/tex]
Implicitly differentiate:
[tex]\displaystyle 2c\frac{dc}{dt} = 494\sin\theta \frac{d\theta}{dt}[/tex]
We want to find dc/dt given that dθ/dt = π/90 and when θ = 60° or π/3. First, find c:
[tex]\displaystyle \begin{aligned} c &= \sqrt{530 - 494\cos \theta}\\ \\ &=\sqrt{530 -494\cos \frac{\pi}{3} \\ \\ &= \sqrt{530 - 494\left(\frac{1}{2}\right)} \\ \\&= \sqrt{283\end{aligned}[/tex]
Substitute:
[tex]\displaystyle 2\left(\sqrt{283}\right) \frac{dc}{dt} = 494\sin\left(\frac{\pi}{3}\right)\left(\frac{\pi}{90}\right)[/tex]
Solve for dc/dt:
[tex]\displaystyle \frac{dc}{dt} = \frac{494\sin \dfrac{\pi}{3} \cdot \dfrac{\pi}{90}}{2\sqrt{283}}[/tex]
Evaluate. Hence:
[tex]\displaystyle \begin{aligned} \frac{dc}{dt} &= \frac{494\left(\dfrac{\sqrt{3}}{2} \right)\cdot \dfrac{\pi}{90}}{2\sqrt{283}}\\ \\ &= \frac{\dfrac{247\sqrt{3}\pi}{90}}{2\sqrt{283}}\\ \\ &= \frac{247\sqrt{3}\pi}{180\sqrt{283}} \\ \\ &\approx 0.444\text{ m/min}\end{aligned}[/tex]
The third side is increasing at an approximate rate of about 0.444 meters per minute.
9514 1404 393
Answer:
0.444 m/min
Step-by-step explanation:
I find this kind of question to be answered easily by a graphing calculator.
The length of the third side can be found using the law of cosines. If the angle of interest is C, the two given sides 'a' and 'b', then the third side is ...
c = √(a² +b² -2ab·cos(C))
Since C is a function of time, its value in degrees can be written ...
C = 60° +2t° . . . . . where t is in minutes, and t=0 is the time of interest
Using a=13, and b=19, the length of the third side is ...
c(t) = √(13² +19² -2·13·19·cos(60° +2t°))
Most graphing calculators are able to compute a numerical value of the derivative of a function. Here, we use the Desmos calculator for that. (Angles are set to degrees.) It tells us the rate of change of side 'c' is ...
0.443855627418 m/min ≈ 0.444 m/min
_____
Additional comment
At that time, the length of the third side is about 16.823 m.
__
c(t) reduces to √(530 -494cos(π/90·t +π/3))
Then the derivative is ...
[tex]c'(t)=\dfrac{494\sin{\left(\dfrac{\pi}{90}t+\dfrac{\pi}{3}\right)}\cdot\dfrac{\pi}{90}}{2\sqrt{530-494\cos{\left(\dfrac{\pi}{90}t+\dfrac{\pi}{3}}}\right)}}}\\\\c'(0)=\dfrac{247\pi\sqrt{3}}{180\sqrt{283}}\approx0.443855...\ \text{m/min}[/tex]
Did any one know this?
Answer:
x sqrt(2)
Step-by-step explanation:
sqrt(a) / sqrt(b) = sqrt(a/b)
sqrt( 14 x^3) / sqrt(7x)
sqrt(14x^3/7x)
sqrt(2x^2)
sqrt(ab) = sqrt(a)sqrt(b)
sqrt(x^2) sqrt(2)
x sqrt(2)
Five students want to play dodgeball and they all want to be a team captain. To be fair, the gym coach decides to place the names of all five students into a hat, mix well, and select two names at random without replacement. The names chosen will be the team captains. Each outcome in the sample space for the random selection of two team captains is equally likely. What is the probability of each outcome in the sample space?
1/25
1/20
1/10
1/5
WARNING! PEOPLE HAVE BEEN PUTTING THE FOLLOWING WRONG ANSWERS:
1/10 AND 1/5 --> THESE TWO ARE WRONG.
I THINK IT IS 1/20. CAN SOMEONE CONFIRM?
Answer:
1/25
Step-by-step explanation:
There are five students. They all have a 1/5 chance. You have to include the chance of all five students, so each student has a 1/25 chance.
5 Cece draws these two figures to prove there is more
than one parallelogram with a 40° angle between a
2-cm side and a 6-cm side. Is Cece correct? Explain.
2 cm
40
4.
2 cm
Answer:
chash greatly ta 45uerywryrsyrsyrs
The manager of a juice bottling factory is considering installing a new juice bottling machine which she hopes will reduce the amount of variation in the volumes of juice dispensed into 8-fluid-ounce bottles. Random samples of 10 bottles filled by the old machine and 9 bottles filled by the new machine yielded the following volumes of juice (in fluid ounces).
Old machine: 8.2, 8.0, 7.9, 7.9, 8.5, 7.9, 8.1,8.1, 8.2, 7.9
New machine: 8.0, 8.1, 8.0, 8.1, 7.9, 8.0, 7.9, 8.0, 8.1
Required:
Use a 0.05 significance level to test the claim that the volumes of juice filled by the old machine vary more than the volumes of juice filled by the new machine
Answer:
Reject H0 and conclude that volume filled by old machine varies more than volume filled by new machine
Step-by-step explanation:
Given the data:
Old machine: 8.2, 8.0, 7.9, 7.9, 8.5, 7.9, 8.1,8.1, 8.2, 7.9
New machine: 8.0, 8.1, 8.0, 8.1, 7.9, 8.0, 7.9, 8.0, 8.1
To test if volume filled by old machine varies more than volume filled by new machine :
Hypothesis :
H0 : s1² = s2²
H1 : s1² > s2²
Using calculator :
Sample size, n and variance of each machine is :
Old machine :
s1² = 0.37889
n = 10
New machine :
s2² = 0.006111
n = 9
Using the Ftest :
Ftest statistic = larger sample variance / smaller sample variance
Ftest statistic = 0.37889 / 0.006111
Ftest statistic = 62.001
Decision region :
Reject H0 ; If Test statistic > Critical value
The FCritical value at 0.05
DFnumerator = 10 - 1 = 9
DFdenominator = 9 - 1 = 8
Fcritical(0.05, 9, 8) = 3.388
Since 62 > 3.388 ; Reject H0 and conclude that volume filled by old machine varies more than volume filled by new machine
gaurrik had 15 marbles lakhima had 22 marbles and kairuv had 30 marbles how many marbles did they have altogether?
Answer:
67 marbles
Step-by-step explanation:
15+30=45
45+22=67
Step-by-step explanation:
you cannot add some simple numbers ? you don't know how to use a calculator ?
to solve this yourself is way shorter than putting this in here.
15 + 22 + 30 = 67