Answer:
length of BC = 5 1/4 feet
Step-by-step explanation:
Area of a triangle = 1/2×base×height
Area = 4 3/8 square feet
Base = AC= 1 2/3 feet
Height = BC = ?
Area of a triangle = 1/2×base×height
4 3/8 = 1/2 × 1 2/3 × height
35/8 = 1/2 × 5/3 × height
35/8 = 5/6 × height
Height = 35/8 ÷ 5/6
= 35/8 × 6/5
= (35 × 6) / (8 × 5)
= 210 / 40
= 5 1/4 feet
Height = BC = 5 1/4 feet
length of BC = 5 1/4 feet
The ratio of Seema's age to the age of her mother is 5:12. The age difference is 21 years. What will be the ratio of Seema's age and her mother's age after three years?
Let ages of Seema and her mother be “5x” years and “12x” years respectively.
Difference between ages is 21 years
Hence,
12x - 5x = 21
7x = 21
x = 3
Therefore,
Age of Seema = 5 × 3 = 15 years
Age of her mother = 12 × 3 = 36 years
Ratio of ages after three years = ( 15+3 ) / (36+3 )
= 18 / 39
= 6 / 13
= 6 : 13
Answer the following questions using 125 words or more:
Write about the similarity of the original comic to the enlargement. How similar are they and how can you tell? What would cause differences in the two pictures? If you drew another comic using a grid, is there anything you would do differently?
What would happen if you reduced the comic's size rather than enlarged it? Would the process be the same? What would you do differently?
Link to video 2min https://media-release.glynlyon.com/g_mat08_ccss_2016/4/media/html5/anm_scale_drawing_comic_project/media/video.mp4
Answer:
given in a triangle rst and another triangle ratOn a coordinate plane, triangle R S T has points (0, 0), (negative 2, 3), (negative 3, 1). Triangle R prime S prime T prime has points (2, ...
9 votes
A rectangle has a perimeter of 150 feet and a base of 45 feet. What is the height?
PLZ help i will give brainly to whoever wants it.
Answer:
30
Step-by-step explanation:
45+45 = 90
150-90 = 60
60/2 = 30
I think...
PLEASE HELP WILL MARK BRAINLIEST
Answer:
I believe its negative nonlinear association
Step-by-step explanation:
The line is going down so its definitely negative
And the line is not straight so its not linear
Therefore, its negative nonlinear association
Christian has 1/2 of a foot of tape. His friend gives him 3/10 of a foot of tape. How much tape does Christian have now?
Answer:
4/5 foot
Step-by-step explanation:
Add the lengths together
1/2 +3/10
Get a common denominator
1/2 *5/5 + 3/10
5/10 + 3/10
8/10
Simplify the fraction by dividing the top and bottom by 2
4/5
[tex]\rm \implies \: Total \: \: length \: \: of \: \: tape \: = \: \frac{1}{2} \: + \: \frac{3}{10} \\ [/tex]
Now , we take LCM of denominators.LCM of 2 and 10 is 10.[tex]\bf \large \rightarrow \: \: \frac{5 \: + \: 3}{10} \: = \: \frac{8}{10} \\ [/tex]
Now , simplifying the fraction in simplest form.
[tex]\bf \large \rightarrow \: \: \cancel\frac{8 \: \: ^{4} }{10 \: \: ^{5} } \: = \frac{4}{5} \\ [/tex]
Christian have 4/5 foot of tape have now.
This is my question. These are the options below, does anyone know the simplest form?
Answer:
B. [tex]2ab^5\sqrt{2ab}[/tex]
Step-by-step explanation:
To simplify, first, simplify the integers. The integers include the number 8. To simplify 8, find out what is the largest perfect square that is a factor of 8. In this case, that is 4. Then, divide 8 by that number. This equals [tex]\sqrt{4} *\sqrt{2}[/tex]. Since the square root of 4 is 2, it can be taken out of under the radical. So, the new expression is [tex]2\sqrt{2a^3b^11}[/tex].
Next, simplify the exponents. To simplify exponents under a radical divide the exponent by the root. For example, 3 divided by 2 is 1 with a remainder of 1. So, take the answer out from under the radical and then leave the remainder in the radical. This looks like[tex]\sqrt{a^3} = a\sqrt{a}[/tex]. Then, do this for the other variable, [tex]\sqrt{b^11} = b^5\sqrt{b}[/tex]. Finally, put everything for the final answer, [tex]2ab^5\sqrt{2ab}[/tex].
Which ratio represents $20 for every 4 cups of lemonade sold?
4/1 or 4,
1/5,
5/1 or 5
Answer:
5/1 or 5
Step-by-step explanation:
4 cup of lemonade is $20
then,
1 cup of lemonade is 20 ÷4 =5
PLEASE HELP URGENT!!! QUESTION IS IN PICTURE PLEASE
Angle 3 and Angle 5 are corresponding angles. Corresponding angles lie in the same relative position. As such, they are congruent.
50x - 100 = 25x + 25
25x - 100 = 25
25x = 125
x = 5
Angle 3 = 50(5) - 100 = 250 - 100 = 150
Angle 5 = 25(5) + 25 = 125 + 25 = 150
Hope this helps!
what is 5cd when c = 3 and d = 4
[tex] \sf \: c = 3 \\ \sf \: d = 4 \\ \\ \sf \: 5cd \: = \: ?\\ \\ \sf \:5 cd \hookrightarrow \\ \sf = 5 \times (3) \times (4) \\ \sf = 5 \times 12 \\ = \underline{ \bf \: 60}[/tex]
-> Just substitute the values given for variables c & d in the equation 5cd & you'll get the answer.
What is the solution of x + 1/5 (x - 1) = 1?
Answer:
1
Step-by-step explanation:
x-1+ 1 /5*( x-1)=0
(x-1)*6/5=0
x=1
square of 5x+1 by 5x
Answer:
5x(5x+1)^2
= 5x(25x^2+10x+1)
= 125x^3+50x^2+5x
40) what is the area of a rectangular porch measuring 8 ft x 12/f
45) Create a stem and leaf plot to represent this set of data.
30, 62, 32, 63, 43, 77, 48, 78, 49, 82, 51, 84, 60,
please make sure to answer both questions
please help (picture) 25 points
Answer:
1) perimeter = sum of all the sides = 3y+9+2y+4+y+3+2y+4 = 8y+20
2) P = 4(5x-2) = 20x-8
Simplify the expression.
7(5 +t) - 4(t + 4)
7(5 + t) - 4(t + 4) = [
7(5 + t) - 4(t + 4) =
= 35 + 7t - 4t - 16 =
= 7t - 4t + 35 - 16 = 3t + 19
what is the value of x in a decagon
Answer:
x = 54
y = 144
Step-by-step explanation:
y = (10-2)×180/10 = 144
x = 180-90-(180-144) = 54
Answered by GAUTHMATH
Yeah uh I have no idea how to do this.....
Use exponent laws to simplify this :
9√(a^-5 b^2)
The answer is 9b / a^5/2 I just don't know how so please show steps! Thank you
Answer:
9b /a^5/2
Step-by-step explanation:
9√(a^-5 b^2)
9 sqrt( a^ -5 b^2)
Rewriting sqrt as ^1/2
9 ( a^ -5 b^2)^1/2
9 ( a^ -5) ^1/2 ( b^2)^1/2
we know that an exponent to an exponent means multiply
9 a^ (-5*1/2) b^(2*1/2)
9 a^-5/2 b^1
9b a^ -5/2
We know that x^-y = 1/x^y
9b /a^5/2
Answer:
[tex]\frac{9b}{a^{2} }[/tex][tex]\sqrt{\frac{1}{a} }[/tex] should be the answer of the problem that you posted
if you try to solve using [tex]\sqrt{x}[/tex] as as [tex]x^{\frac{1}{2} }[/tex]
then [tex](a^{-5)} ^{\frac{1}{2} } \\[/tex] = [tex](a^{-5/2)}[/tex] = [tex]\frac{1}{a^{\frac{5}{2} } }[/tex]
[tex]\frac{1}{a^{\frac{5}{2} } }[/tex] * 9b = [tex]\frac{9b}{a^{\frac{5}{2 } } }[/tex]
Step-by-step explanation:
[tex]9 \sqrt{(a^-5 b^2)}[/tex]
[tex]x^{-1} = \frac{1}{x}[/tex]
[tex]a^{-5} = \frac{1}{a^{5} }[/tex]
[tex]\sqrt{b^{2} } = b[/tex]
[tex]a^{4}[/tex] a's can be removed from the radicle (one will be left in because you have a^5)
[tex]\frac{9b}{a^{2} }[/tex][tex]\sqrt{\frac{1}{a} }[/tex]
james cuts 2 of his neighbor's lawn the first is 1000 m long and 100 m wide what is the area
Step-by-step explanation:
The formula for area is l x b. This stands for length and breadth. I can multiply 1000(100) to get 100,000m. The area of the lawn is 100,000 m.
HOPE IT HELPS YOU
MARK ME BRAINLIEST
The volume of a rectangular prism with a cone shaped hole in it is approximately 163.22cm³ (as shown below).
✏️ What is the height of the cone?
Answer:
Height of the cone = 5 cm
Step-by-step explanation:
Volume of the rectangular prism with a cone shaped hole = Volume of the rectangular prism - Volume of the cone
Volume of the rectangular prism = Length × Width × Height
= 5 × 5 × 7
= 175 cm³
Volume of the cone = [tex]\frac{1}{3}\pi r^{2}h[/tex]
Here, r = Radius of the cone
h = Height of the cone
Volume of the cone = [tex]\frac{1}{3}\pi (\frac{3}{2})^{2}(h)[/tex]
= 0.75πh cm³
Volume of the rectangular prism with a hole = 163.22 cm³
175 - 0.75πh = 163.22
0.75πh = 175 - 163.22
0.75πh = 11.78
h = 5 cm
HELLLPPPPP!!!!!!!!!!!!!!!!!!
Answer:
1}6 times
Step-by-step explanation:
The highest number of president born in Virginia minus the highest number of president born in Texas2}Yes.New York and Mast has the same number of president which is four
3}Yes,this can be done using piechart.
4}I am still working on this question
I’ve been stuck on this for 3 days today is the last day please help me guys
y = x^2 - 2x - 3
Factored Form: y = (x - 3)(x + 1)
X-Intercepts: (3, 0) and (-1, 0)
Axis of Symmetry: x = 1
Vertex: (1, -4)
Domain: All Real Numbers (or negative infinity to infinity)
Range: y > -4
Hope this helps!
I need help I don't understand this.
9514 1404 393
Answer:
∠4 = 108°
Step-by-step explanation:
Angles 2 and 4 together form a "linear pair". That is, the sum of them is 180°, a "straight angle." They are supplementary.
∠4 = 180° -∠2 = 180° -72°
∠4 = 108°
Can someone help me out
Answer: V=9.4 cm^3
Step-by-step explanation:
[tex]V=\pi r^2h\\V=\pi (1)^2(3)\\V=9.4cm^3[/tex]
The inequalities x < -5 and -X > -5 are the same.
True
False
QUESTION-:
The inequalities x < -5 and -X > -5 are the same.
True
False
ANSWER-:
FALSE
!! HOPE ITS HELP U !!
30 points PLEASE HELP!!!!
Find the volume of the pyramid.
76.34 ft3
458.06 ft3
916.11 ft3
305.37 ft3
Answer:
916.11 ft³
Step-by-step explanation:
(9×6)×7.83/2×13/3
= 211.41×13/3
= 916.11 ft³
Answered by GAUTHMATH
Answer:
916.11 ft³
Step-by-step explanation:
3000 dollars is invested in a bank account at an interest rate of 7 percent per year, compounded continuously. Meanwhile, 20000 dollars is invested in a bank account at an interest rate of 5 percent compounded annually.
To the nearest year, when will the two accounts have the same balance?
9514 1404 393
Answer:
after 89 years
Step-by-step explanation:
For principal p, interest rate r, and number of years t, the two account balances are ...
a = p·e^(rt) . . . . continuous compounding
a = p(1+r)^t . . . . annual compounding
Using the given values, we have
3000·e^(0.07t) . . . . . compounded continuously
20000·1.05^t . . . . . . compounded annually
We want to find t so these are equal.
3000·e^(0.07t) = 20000·1.05^t
0.15e^(0.07t) = 1.05^t . . . . divide by 20,000
ln(0.15) +0.07t = t·ln(1.05) . . . . take natural logarithms
ln(0.15) = t·(ln(1.05) -0.07) . . . . subtract 0.07t
t = ln(0.15)/(ln(1.05) -0.07) ≈ -1.8971/-0.02121 . . . . . divide by the coefficient of t
t ≈ 89.4 ≈ 89
The two accounts will have the same balance after 89 years.
Can someone plz tell me what’s 9% of 41
Answer:
3.69
Step-by-step explanation:
9% of 41 is (9/100)*41=369/100=3.69
A circle has a circumference of 1{,}133.541,133.541, comma, 133, point, 54 units.
What is the diameter of the circle?
Answer: Radius is 21.2537 units, to 6 sig figs
Step-by-step explanation:
I'll assume the circumference is simply 133.541 units^2. Circumference (C) is C = 2*pi*R, where R is the radius. Thus, R = C/(2*pi),
R = (133.541/2*(3.14159) to 6 sig figs
R = 21.2537 units
1_tanA/1+tanA=cotA_1/cotA+1
Answer:
here,
L.H.S;
1-tanA / 1+tanA
=1-1/cotA / 1+1/cotA
= cotA-1/cotA / cotA+1/cotA
=cotA-1 / cotA+1
= R.H.S
proved
Answer:
if it's a math proof, i will think this is answer
Step-by-step explanation:
PLS HELP ME ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST IF YOU KNOW THE ANSWER PLS GIVE ME A STEP BY STEP EXPLANATION!!
Which ratio is not equivalent to the others?
A. 1:3
B. 36
C. 7 to 14
D. 816
Answer:
a. 1:3
Step-by-step explanation:
theres a pattern of x^2 but 1:3 is 1x3
The frequency table represents the job status of a number of high school students. A 4-column table with 3 rows titled job status. The first column has no label with entries currently employed, not currently employed, total. The second column is labeled looking for job with entries 12, 38, 50. The third column is labeled not looking for a job with entries 28, 72, 100. The fourth column is labeled total with entries 40, 110, 150. Which shows the conditional relative frequency table by column? A 4-column table with 3 rows titled job status. The first column has no label with entries currently employed, not currently employed, total. The second column is labeled looking for a job with entries 0.3, nearly equal to 0.33, 1.0. The third column is labeled not looking for job with entries 0.7, nearly equal to 0.65, 1.0. the fourth column is labeled total with entries nearly equal to 0.27, nearly equal to 0.73, 1.0. A 4-column table with 3 rows titled job status. The first column is blank with entries currently employed, not currently employed, total. The second column is labeled Looking for a job with entries 0.12, 0.38, 050. The third column is labeled not looking for a job with entries 0.28, 0.72, 1.00. The fourth column is labeled total with entries 0.4, 1.1, 1.5. A 4-column table with 3 rows titled job status. The first column has no label with entries currently employed, not currently employed, total. The second column is labeled looking for a job with entries 0.24, 0.76, 1.0. The third column is labeled not looking for a job with entries 0.28, 0.72, 1.0. The fourth column is labeled total with entries nearly equal to 0.27, nearly equal to 0.73, 1.0. A 4-column table with 3 rows titled job status. The first column has no label with entries currently employed, not currently employed, total. The second column is labeled looking for job with entries 0.08, nearly equal to 0.25, nearly equal to 0.33. The third column is labeled not looking for a job with entries nearly equal to 0.19, 0.48, nearly equal to 0.67. The f
Answer:
[tex]\begin{array}{cccc}{} & {Looking\ for\ job} & {Not\ looking} & {Total} & {Employed} & {0.24} & {0.28} & {0.27} & {Not\ Employed} & {0.76} & {0.72} & {0.73}& {Total} & {1} & {1} & {1} \ \end{array}[/tex]
Step-by-step explanation:
The question is not properly formatted (see attachment for the frequency table and the options)
Required
The conditional relative frequency table by column
We have:
[tex]\begin{array}{cccc}{} & {Looking\ for\ job} & {Not\ looking} & {Total} & {Employed} & {12} & {28} & {40} & {Not\ Employed} & {38} & {72} & {110}& {Total} & {50} & {100} & {150} \ \end{array}[/tex]
To get the conditional frequency by column, we simply divide each cell by the corresponding total value (on the last row)
So, we have:
[tex]\begin{array}{cccc}{} & {Looking\ for\ job} & {Not\ looking} & {Total} & {Employed} & {12/50} & {28/100} & {40/150} & {Not\ Employed} & {38/50} & {72/100} & {110/150}& {Total} & {50/50} & {100/100} & {150/150} \ \end{array}[/tex]
[tex]\begin{array}{cccc}{} & {Looking\ for\ job} & {Not\ looking} & {Total} & {Employed} & {0.24} & {0.28} & {0.27} & {Not\ Employed} & {0.76} & {0.72} & {0.73}& {Total} & {1} & {1} & {1} \ \end{array}[/tex]