To host an event at a popular convention center, it costs $300 plus $45 per person attending. Step 1 of 3 : Write a rational expression that represents how much you would need to charge each attendee in order to cover the cost of hosting the event. Let x be the number of attendees.

Answer:

Option C. √280

Step-by-step explanation:

From the question given above, the following data were obtained

MN = 19

ML = 9

LN =?

We can obtain the value of LN by using the pythagoras theory as illustrated:

M ² = ML² + LN²

19² = 9² + LN²

361 = 81 + LN²

Collect like terms

361 – 81 = LN²

280 = LN²

Take the square root of both side

LN = √280

Therefore, the length of LN is √280

9514 1404 393

Answer:

  is a polynomial

Step-by-step explanation:

The expression is a sum of products.

Each product involves a numerical value and a product of variables to positive integer powers.

These meet the requirements for an expression to be a polynomial, so ...

  the given expression is a polynomial

Answer:

x = 4[tex]\sqrt{2}[/tex]

Step-by-step explanation:

Pytago:

x[tex]x^{2} +7^{2} = 9^{2} \\\\x = \sqrt{9^{2} - 7^{2} } x = 4\sqrt{2}[/tex]

Answer:

please write this question in English then I give answer

Answer:

√11 cm

Step-by-step explanation:

Pythagorean Thereom

a^2 + b^2= c^2

x^2 +5^2=6^2

x^2 + 25 = 36

subtract 25 from both sides

x^2=11

do the square root

x = √11

Let it be x

Using basic proportionality theorem

[tex]\\ \sf\longmapsto \dfrac{x}{10}=\dfrac{14}{7}[/tex]

[tex]\\ \sf\longmapsto \dfrac{x}{10}=2[/tex]

[tex]\\ \sf\longmapsto x=10(2)[/tex]

[tex]\\ \sf\longmapsto x=20[/tex]

13x - 4[x + (3 - x)] =

= 13x - 4(x + 3 - x) =

= 13x - 4 · 3 = 13x - 12

C.

Answer:

13x -12

Step-by-step explanation:

13 x - 4[ x + (3 - x )].

Combine like terms inside the brackets

13 x - 4[ 3 -0x]

13x - 4[3]

Multiply

13x -12

Answer:

Not very sure what you mean,

But in the provided set, 8 is the greatest number, and 1 is the smallest.

Hope this helps!!

Answer:

72 degrees

Step-by-step explanation:

Area of a sector=(pi*r^2)*(Theta/360)

125*pi=pi*(625)*(theta/360)

(125*360)/625=theta

Theta=72 degrees

The angle theta of the sector of the given circle is 72 degrees.

We have given that,

In the diagram below, the circle has a radius of 25 inches.

The area of the shaded sector is 125π in^2.

[tex]Area \ of \ a \ sector=(pi*r^2)*(\Theta/360)[/tex]

Therefore we get,

[tex]125*pi=pi*(625)*(\theta/360)[/tex]

[tex](125*360)/625=\theta[/tex]

[tex]\theta=72 degrees[/tex]

Therefore we get the angle of the sector of the given circle is 72 degrees.

To learn more about the area of sector visit:

https://brainly.com/question/22972014

#SPJ2

Answer:

Slope = 5

Step-by-step explanation:

To find the slope of a line perpendicular to a given line, take the opposite reciprocal of the given line's slope.

Ex. -1/5 ⇒ 5

Opposite = opposite sign (- ⇒ +)

Reciprocal = numerator and denominator flipped (1/5 ⇒ 5/1 = 5)

Answer:

113.1

Step-by-step explanation:

use the formula to solve for volume

use x^2 when x=0 because the restriction for it is "use x if x is less than or equal to 1"

when x = 0, (0)^2 will make f(x) = 0

the graph of f(x) will just be a dot at 0

Answer:

El capital que prestado al 10% bimestral durante 6 meses y 10 días produce un interés de $1140 es $3,600.

Step-by-step explanation:

Para determinar cuál es el capital que prestado al 10% bimestral durante 6 meses y 10 días produce un interés de $1140 se debe realizar el siguiente cálculo:

6 / 2 = 3

10/60 = 0.16666

10 x 3.1666 = 31.666

31.666 = 1140

100 = x

100 x 1140 / 31.666 = X

114,000 / 31.666 = X

3,600 = X

Por lo tanto, el capital que prestado al 10% bimestral durante 6 meses y 10 días produce un interés de $1140 es $3,600.

Answer:

the answer is 240 degrees

Answer:

A: The distribution is skewed to the left.

Step-by-step explanation:

Skewness:

If the distribution has a long left tail, it is skewed to the left.

If it has a long right tail, it is skewed to the right.

Otherwise, it is approximately symmetrical.

In this question:

Lots of values on the start(left), few on the end(right), so it is skewed to the left, and the correct answer is given by option a.

Answer:

4206 is the answer of this question

Answer:

I think it will help you a lot.

Answer:

0.0733364

Step-by-step explanation:

Given :

Number of vegans = x ;

Sample size, n = 150

Zα/2 ; Zcritical at 95% = 1.96

p = x / n = 45 / 150 = 0.3

Margin of Error :

Zcritical * √(p(1 - p) / n)

1.96 * √(0.3(1 - 0.3) / 150)

Margin of Error :

1.96 * √(0.3 * 0.7) / 150)

1.96 * √0.0014

Margin of Error = 0.0733364

Answer:

Reflection

Step-by-step explanation:

It is the opposite of the first,...

Let a, b, and c be vectors each starting at the origin and terminating at the points (x, x + 1), (x + 2, x + 3), and (x + 3, 2x + 4), respectively.

Then the vectors a - b, a - c, and b - c are vectors that point in directions parallel to each of the legs formed by the triangle with these points as its vertices.

If this triangle is to contain a right angle, then exactly one of these pairs of vectors must be orthogonal. In other words, one of the following must be true:

(a - b) • (a - c) = 0

or

(a - b) • (b - c) = 0

or

(a - c) • (b - c) = 0

We have

a - b = (x, x + 1) - (x + 2, x + 3) = (-2, -2)

a - c = (x, x + 1) - (x + 3, 2x + 4) = (-3, -x - 3)

b - c = (x + 2, x + 3) - (x + 3, 2x + 4) = (-1, -x - 1)

Case 1: If (a - b) • (a - c) = 0, then

(-2, -2) • (-3, -x - 3) = (-2)×(-3) + (-2)×(-x - 3) = 2x + 12 = 0   ==>   x = -6

which would make a - c = (-3, 3) and b - c = (-1, 5), and their dot product is not zero. Then the triangles vertices are at the points (-6, -5), (-4, -3), and (-3, -8).

Case 2: If (a - b) • (b - c) = 0, then

(-2, -2) • (-1, -x - 1) = (-2)×(-1) + (-2)×(-x - 1) = 2x + 4 = 0   ==>   x = -2

which would make a - c = (-3, -1) and b = (-1, 1), and their dot product is also not zero. The vertices are the points (-2, -1), (0, 1), and (1, 0).

Case 3: If (a - c) • (b - c) = 0, then

(-3, -x - 3) • (-1, -x - 1) = (-3)×(-1) + (-x - 3)×(-x - 1) = x ² + 4x + 6 = 0

but the solutions to x here are non-real, so we throw out this case.

So there are two possible values of x that make a right triangle, x = -6 and x = -2.

Answer:

The 99% confidence interval for the difference in two proportions is (0.0456, 0.1944).

Step-by-step explanation:

Before building the confidence interval, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

Western residents:

39% out of 640, so:

[tex]p_1 = 0.39[/tex]

[tex]s_1 = \sqrt{\frac{0.39*0.61}{640}} = 0.0193[/tex]

Eastern residents:

51% out of 540, so:

[tex]p_2 = 0.51[/tex]

[tex]s_2 = \sqrt{\frac{0.51*0.49}{540}} = 0.0215[/tex]

Distribution of the difference:

[tex]p = p_2 - p_1 = 0.51 - 0.39 = 0.12[/tex]

[tex]s = \sqrt{s_2^2+s_1^2} = \sqrt{0.0215^2+0.0193^2} = 0.0289[/tex]

Confidence interval:

[tex]p \pm zs[/tex]

In which

z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].

99% confidence level

So [tex]\alpha = 0.01[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.01}{2} = 0.995[/tex], so [tex]Z = 2.575[/tex].

The lower bound of the interval is:

[tex]p - zs = 0.12 - 2.575*0.0289 = 0.0456[/tex]

The upper bound of the interval is:

[tex]p + zs = 0.12 + 2.575*0.0289 = 0.1944[/tex]

The 99% confidence interval for the difference in two proportions is (0.0456, 0.1944).

Answer:

Quadratic

Step-by-step explanation:

Answer:

Linear

Step-by-step explanation:

for every one unit increase in x, there is a 3 unit increase in y

The slope of the plot line would be 3

The y intercept of the plot line would be -1

y = 3x - 1

Answer:

The minimum sample size is 1,704.

Step-by-step explanation:

We have to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1 - 0.95}{2} = 0.025[/tex]

Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].

That is z with a p-value of [tex]1 - 0.025 = 0.975[/tex], so Z = 1.96.

Now, find the margin of error M as such

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

Standard deviation of 21,059,637 shares

This means that [tex]\sigma = 21059637[/tex]

What is the minimum required sample size if you would like your sampling error to be limited to 1,000,000 shares?

This is n for which [tex]M = 1000000[/tex], so:

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

[tex]1000000 = 1.96\frac{21059637}{\sqrt{n}}[/tex]

[tex]1000000\sqrt{n} = 1.96*21059637[/tex]

[tex]\sqrt{n} = \frac{1.96*21059637}{1000000}[/tex]

[tex](\sqrt{n})^2 = (\frac{1.96*21059637}{1000000})^2[/tex]

[tex]n = 1703.8[/tex]

Rounding up:

The minimum sample size is 1,704.

Answer:

x= (2+ √ 34) /5 , (2- √ 34) /5

decimal form= 1.566

Step-by-step explanation:

Answer:

You'd think its 34% but apparently it's 16%.

I hope this is right. If its not then it must be 34%.

(A) -- or maybe (B). 80% confident it is A.

ED2021

That's a question about quadratic function.

Any quadratic function can be represented by the following form:

[tex]\boxed{f(x)=ax^2+bx+c}[/tex]

Example:

[tex]f(x)= -3x^2-9x+57[/tex] is a function where [tex]a=-3[/tex], [tex]b=-9[/tex] and [tex]c=57[/tex].

Okay, in our problem, we need to find the value of x when [tex]f(x)=0[/tex]. That's mean that the result of our function is equal to zero. Therefore, we have the quadratic equation below:

[tex]x^2+4x-5=0[/tex]

To solve a quadratic equation, we use the Bhaskara's formula. Do you remember the value of a, b and c? They going to be important right now. This is the Bhaskara's formula:

[tex]\boxed{x=\frac{-b\pm \sqrt{b^2-4ac} }{2a} }[/tex]

So, let's see the values of a, b and c in our equation and apply them in the Bhaskara's formula:

In [tex]x^2+4x-5=0[/tex] equation, [tex]a=1[/tex], [tex]b=4[/tex] and [tex]c=-5[/tex]. Let's replace those values:

[tex]x=\frac{-b\pm \sqrt{b^2-4ac} }{2a}[/tex]

[tex]x=\frac{-4\pm \sqrt{4^2-4\times1\times(-5)} }{2\cdot1}[/tex]

[tex]x=\frac{-4\pm \sqrt{16-(-20)} }{2}[/tex]

[tex]x=\frac{-4\pm \sqrt{16 + 20)} }{2}[/tex]

[tex]x=\frac{-4\pm \sqrt{36} }{2}[/tex]

[tex]x=\frac{-4\pm 6 }{2}[/tex]

From now, we have two possibilities:

To add:

[tex]x_1 = \frac{-4+6}{2} \\x_1=\frac{2}{2} \\x_1=1[/tex]

To subtract:

[tex]x_2=\frac{-4-6}{2} \\x_2=\frac{-10}{2} \\x_2=-5[/tex]

Therefore, the result of our problem is: [tex]x_1 = 1[/tex] and [tex]x_2=-5[/tex].

I hope I've helped. ^^

Enjoy your studies.  \o/

Answer:

ask in English then I can help u

Since this is a right triangle, we can use one of the three main trigonometric functions: sine, cosine, or tangent.

Remember: SOH-CAH-TOA

Looking from the given angle, we know the opposite side and want to know the adjacent side. Therefore, we should use the tangent function.

tan(54) = 16/BC

BC = 16/tan(54)

BC = 11.62 units

Hope this helps!

[tex]\\ \sf\longmapsto 3x-4y=-12[/tex]

[tex]\\ \sf\longmapsto 3x+12=4y[/tex]

[tex]\\ \sf\longmapsto y=\dfrac{3x+12}{4}[/tex]

[tex]\\ \sf\longmapsto y=\dfrac{3}{4}x+\dfrac{12}{4)[/tex]

[tex]\\ \sf\longmapsto y=\dfrac{3}{4}+3[/tex]