To determine the organic material in a dried lake bed, the percent carbon by mass is measured at two different locations. To compare the means of the two different locations, it must first be determined whether the standard deviations of the two locations are different. For each location, calculate the standard deviation and report it with two significant figures.

Answers

Answer 1

Answer:

[tex]\sigma_1 = 0.08[/tex] --- Location 1

[tex]\sigma_2 = 0.34[/tex] --- Location 2

Step-by-step explanation:

Given

See attachment for the given data

Required

The standard deviation of each location

For location 1

First, calculate the mean

[tex]\bar x_1 =\frac{\sum x}{n}[/tex]

So, we have:

[tex]\bar x_1 =\frac{30.40+30.20+30.30+30.40+30.30}{5}[/tex]

[tex]\bar x_1 =\frac{151.60}{5}[/tex]

[tex]\bar x_1 =30.32[/tex]

The standard deviation is calculated as:

[tex]\sigma_1 = \sqrt{\frac{\sum(x - \bar x_1)^2}{n-1}}[/tex]

[tex]\sigma_1 = \sqrt{\frac{(30.40 - 30.32)^2+(30.20 - 30.32)^2+(30.30 - 30.32)^2+(30.40 - 30.32)^2+(30.30 - 30.32)^2}{5-1}}[/tex]

[tex]\sigma_1 = \sqrt{\frac{0.028}{4}}[/tex]

[tex]\sigma_1 = \sqrt{0.007}[/tex]

[tex]\sigma_1 = 0.08[/tex]

For location 2

First, calculate the mean

[tex]\bar x_2 =\frac{\sum x}{n}[/tex]

So, we have:

[tex]\bar x_2 =\frac{30.10+30.90+30.20+30.70+30.30}{5}[/tex]

[tex]\bar x_2 =\frac{152.2}{5}[/tex]

[tex]\bar x_2 =30.44[/tex]

The standard deviation is calculated as:

[tex]\sigma_2 = \sqrt{\frac{\sum(x - \bar x_2)^2}{n-1}}[/tex]

[tex]\sigma_2 = \sqrt{\frac{(30.10-30.44)^2+(30.90-30.44)^2+(30.20-30.44)^2+(30.70-30.44)^2+(30.30-30.44)^2}{5-1}}[/tex]

[tex]\sigma_2 = \sqrt{\frac{0.472}{4}}[/tex]

[tex]\sigma_2 = \sqrt{0.118}[/tex]

[tex]\sigma_2 = 0.34[/tex]

To Determine The Organic Material In A Dried Lake Bed, The Percent Carbon By Mass Is Measured At Two

Related Questions

What is the slope of the line that passes through the points (10,8) and (-15,18)?
Write your answer in simplest form.

Answers

Answer:

I believe it is 2/5 fraction

Answer:

-2/5

Step-by-step explanation:

We can use the slope formula

m = ( y2-y1)/(x2-x1)

   = ( 18-8)/(-15-10)

    = 10/-25

   = -2/5

A few more problems and then I’m done

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Answer:

((c)).g(x) = 3 × 2^x +2..

if a,b,c,d,e are in continued proportion then a/c is equal to what ?​

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Answer:

huh

Step-by-step explanation:

that don't make no sense

If a,b,c,d,e are in continued proportion then a/c =  a²/b²

What is Ratio?

Ratio is defined as a relationship between two quantities, it is expressed one divided by the other.

It is given that

a,b,c,d,e are in continued proportion

We can write it as

a/b = b/c = c/d = d/e = k

d=ek, c=ek², b=ek³ and a=ek⁴

Here a/c

Substitute the values of a and c

⇒ ek⁴/ek²

⇒ k²    [ k = a/b ]

a²/b²

Learn more about Ratio here:

brainly.com/question/1504221

#SPJ2

The sum of a number x and
eleven

Answers

Answer:

what is the sum.

Step-by-step explanation:

Take the sum - 11 =x

Geometry please help me need help I don’t know how to do it

Answers

Answer:

A'(0,-8) B'(5,-7) C'(3,0) D'(2,-5)

A''(0,8) B''(-5,7) C''(-3,0) D''(-2,5)

Step-by-step explanation:

first everything is shifted down 8 units (x,y-8), so we get A'(0,-8) B'(5,-7) C'(3,0) D'(2,-5)

then you multiply by -1 A''(0,8) B''(-5,7) C''(-3,0) D''(-2,5)

The lifetimes of light bulbs of a particular type are normally distributed with a mean of 350 hours and a standard deviation of 6 hours. What percentage of the bulbs have lifetimes that lie within 1 standard deviation to either side of the mean?

Answers

Answer:

By the Empirical Rule, approximately 68% of the bulbs have lifetimes that lie within 1 standard deviation to either side of the mean.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

What percentage of the bulbs have lifetimes that lie within 1 standard deviation to either side of the mean?

By the Empirical Rule, approximately 68% of the bulbs have lifetimes that lie within 1 standard deviation to either side of the mean.

The minimum point of the graph y = 2x^2 + 2x +1 is located at:

Answers

Answer:

A

Step-by-step explanation:

By completing the square, y = 2x^2 + 2x +1 will be y=2(x+1/2)^2+(1/2) the minimum point is the vertex of the parabola which is (-1/2, 1/2)

Pls helppppp,,,,,.....

Answers

Answer:

yall do school right now???and i forgot how to do these sorry

Answer:

18 = 2x-14

or, 2x =18+14

or, 2x =32

or, x=32/2

x=16

2(6x-7)=10

or, 12x-14=10

or, 12x=10+14

or, x=24/12

x=2

Question 2 of 10
Which pair of functions are inverses of each other?
O A. f(x) = i +15 and g(x) = 12x - 15
O B. f(x) = - 10 and g(x) = 2410
O C. f(x) = y3x and g(x) = (3) 3
O D. f(x) = 11x- 4 and g(x) = 4
SUBMIT

Answers

Answer:

option c f(x)=-10and g(x)=2410

One year, Alex bought an antique car for his birthday. During the first year he owned it, the
value of the car gained 10%. During the second year, the value of the car gained another
15% from the previous year. If the value of the car is now $37,950.00, how much did Alex
originally pay for his car?

Answers

Answer:

28462.5

Step-by-step explanation:

During the first year it gained 10% and during his second year he gained 15% so you first add those and you get 25%.

Then you multiply 25% with 37,950.

25/100 * 37950 = 948,750/100

= 9487.5

To get the original amount you subtract 9487.5 from 37,950

37,950 - 9487.5 = 28462.5

So the original amount was 28462.5

Four seconds pass between the first and third flash of a strobe light. The rate at which the strobe flashes is constant. How many seconds will pass between the first and the twelfth flash of the same light?

Answers

Answer:

t = 22 s

Step-by-step explanation:

If n is the number of strobe pulses

The first strobe pulse occurs at t = 0

t = 2(n - 1)

t = 2(12 - 1)

t = 2(11)

t = 22 s

If you have 2 distinct black playing cards and 2 distinct red playing cards, how many ways can you arrange the four cards given that the red cards can never be next to each other

Answers

Answer:

I'm not 100% on the interoperation of this question...

are the two red cars out of a 52 card deck and you can try all the combinations of two red and black cards ????

for this answer i will assume that you have 4 coins two nickels and 2 quarters

and the question is " how many ways can you arrange the four coins given that the nickels can not be next to the quarters"

in that case I think the answer is 8

Step-by-step explanation:

1- N1 Q1 N2 Q2

2- N1 Q2 N2 Q1

3- N2 Q1 N1 Q2

4- N2 Q2 N1 Q1

5- Q1 N2 Q2 N1

6- Q2 N2 Q1 N1

7- Q1 N1 Q2 N2

8- Q2 N1 Q1 N2

[tex]2\cdot \left(\left(2\:choose\:1\right)\:\cdot \:\left(2\:choose\:1\right)\right)[/tex]

Find the area of the figure.

A =

Is it m, m2, or m3

Answers

Answer:

348 m^2

Step-by-step explanation:

The figure is made up of a rectangle 24 m by 12 m, and a triangle with a 24 m base and a 5 m height.

A = LW + bh/2

A = 24 m * 12 m + (24 m)(5 m)/2

A = 288 m^2 + 60 m^2

A = 348 m^2

Find the first, second, third and fourth order Maclaurin polynomials of f(x) =

arctan(x). Draw the graph of f(x) and the four polynomials on the same

diagram. (Sketch by hand or use software.)

#urgent please give me this answer and help me#

Answers

The first, second, third and fourth order Maclaurin polynomials of f(x)=arctan(x) are:

The first order Maclaurin polynomial is f(x)=xThe second order Maclaurin polynomial is also f(x)=xThe third order Maclaurin polynomial is [tex]f(x)=x-\frac{1}{3}x^{3}[/tex]The fourth order Maclaurin polynomial is also [tex]f(x)=x-\frac{1}{3}x^{3}[/tex]You can see the graph on the attached picture.

So let's start by finding the first order maclaurin polynomial:

f(x)=f(0)+f'(0)x

so let's find each part of the function:

f(0)=arctan(0)

f(0)=0

now, let's find the first derivative of f(x)

f(x)=arctan(x)

This is a usual derivative so there is a rule we can use here:

[tex]f'(x)=\frac{1}{x^{2}+1}[/tex]

so now we can find f'(0)

[tex]f'(0)=\frac{1}{(0)^{2}+1}[/tex]

f'(0)=1

So we can now complete the first order Maclaurin Polynomial:

f(x)=0+1x

which simplifies to:

f(x)=x

Now let's find the second order polynomial, for which we will need to get the second derivative of the function:

[tex]f(x)=f(0)+f'(0)x+\frac{f''(0)}{2!}x^{2}[/tex]

so:

[tex]f'(x)=\frac{1}{x^{2}+1}[/tex]

we can rewrite this derivative as:

[tex]f'(x)=(x^{2}+1)^{-1}[/tex]

and use the chain rule to get:

[tex]f''(x)=-1(x^{2}+1)^{-2}(2x)[/tex]

which simplifies to:

[tex]f''(x)=-\frac{2x}{(x^{2}+1)^{2}}[/tex]

now, we can find f''(0):

[tex]f''(0)=-\frac{2(0)}{((0)^{2}+1)^{2}}[/tex]

which yields:

f''(0)=0

so now we can complete the second order Maclaurin polynomial:

[tex]f(x)=0+1x+\frac{0}{2!}x^{2}[/tex]

which simplifies to:

f(x)=x

Now let's find the third order polynomial, for which we will need to get the third derivative of the function:

[tex]f(x)=f(0)+f'(0)x+\frac{f''(0)}{2!}x^{2}+\frac{f'''(0)}{3!}x^{3}[/tex]

so:

[tex]f''(x)=-\frac{2x}{(x^{2}+1)^{2}}[/tex]

In this case we can use the quotient rule to solve this:

Quotient rule: Whenever you have a function in the form , then it's derivative is:

[tex]f'(x)=\frac{p'q-pq'}{q^{2}}[/tex]

in this case:

p=2x

p'=2

[tex]q=(x^{2}+1)^{2}[/tex]

[tex]q'=2(x^{2}+1)(2x)[/tex]

[tex]q'=4x(x^{2}+1)[/tex]

So when using the quotient rule we get:

[tex]f'(x)=\frac{p'q-pq'}{q^{2}}[/tex]

[tex]f'''(x)=\frac{(2)(x^{2}+1)^{2}-(2x)(4x)(x^{2}+1)}{((x^{2}+1)^{2})^{2}}[/tex]

which simplifies to:

[tex]f'''(x)=\frac{-2x^{2}-2+8x^{2}}{(x^{2}+1)^{3}}[/tex]

[tex]f'''(x)=\frac{6x^{2}-2}{(x^{2}+1)^{3}}[/tex]

now, we can find f'''(0):

[tex]f'''(0)=\frac{6(0)^{2}-2}{((0)^{2}+1)^{3}}[/tex]

which yields:

f'''(0)=-2

so now we can complete the third order Maclaurin polynomial:

[tex]f(x)=0+1x+\frac{0}{2!}x^{2}-\frac{2}{3!}x^{3}[/tex]

which simplifies to:

[tex]f(x)=x-\frac{1}{3}x^{3}[/tex]

Now let's find the fourth order polynomial, for which we will need to get the fourth derivative of the function:

[tex]f(x)=f(0)+f'(0)x+\frac{f''(0)}{2!}x^{2}+\frac{f'''(0)}{3!}x^{3}+\frac{f^{(4)}(0)}{4!}x^{4}[/tex]

so:

[tex]f'''(x)=\frac{6x^{2}-2}{(x^{2}+1)^{3}}[/tex]

In this case we can use the quotient rule to solve this:

[tex]f'(x)=\frac{p'q-pq'}{q^{2}}[/tex]

in this case:

[tex]p=6x^{2}-2[/tex]

p'=12x

[tex]q=(x^{2}+1)^{3}[/tex]

[tex]q'=3(x^{2}+1)^{2}(2x)[/tex]

[tex]q'=6x(x^{2}+1)^{2}[/tex]

So when using the quotient rule we get:

[tex]f'(x)=\frac{p'q-pq'}{q^{2}}[/tex]

[tex]f^{4}(x)=\frac{(12x)(x^{2}+1)^{3}-(6x^{2}-2)(6x)(x^{2}+1)^{2}}{((x^{2}+1)^{3})^{2}}[/tex]

which simplifies to:

[tex]f^{4}(x)=\frac{12x^{3}+12x-6x^{3}+12x}{(x^{2}+1)^{4}}[/tex]

[tex]f^{4}(x)=\frac{6x^{3}+24x}{(x^{2}+1)^{4}}[/tex]

now, we can find f^{4}(0):

[tex]f^{4}(x)=\frac{6(0)^{3}+24(0)}{((0)^{2}+1)^{4}}[/tex]

which yields:

[tex]f^{4}(0)=0[/tex]

so now we can complete the fourth order Maclaurin polynomial:

[tex]f(x)=0+1x+\frac{0}{2!}x^{2}-\frac{2}{3!}x^{3}+\frac{0}{4!}x^{4}[/tex]

which simplifies to:

[tex]f(x)=x-\frac{1}{3}x^{3}[/tex]

you can find the graph of the four polynomials in the attached picture.

So the first, second, third and fourth order Maclaurin polynomials of f(x)=arctan(x) are:

The first order Maclaurin polynomial is f(x)=xThe second order Maclaurin polynomial is also f(x)=xThe third order Maclaurin polynomial is [tex]f(x)=x-\frac{1}{3}x^{3}[/tex]The fourth order Maclaurin polynomial is also [tex]f(x)=x-\frac{1}{3}x^{3}[/tex]

You can find further information on the following link:

https://brainly.com/question/17440012?referrer=searchResults

What is the slope of a line that is perpendicular to the line whose equation is ax+by=c?
A. c/b
B. b/a
C. −b/a
D. a/b

Answers

Answer:

b/a

Step-by-step explanation:

ax+by=c

To find the slope solve for y

by = -ax+c

Divide by b

y = -a/b x + c/b

The slope intercept form is y = mx+b where m is the slope

The slope is -a/b

A perpendicular line has a slope that is the negative reciprocal

-1/ (-a/b)

-1 * -b/a

b/a

Find median of given data : 6,6,7,8,11,19,6​

Answers

Answer:

Median =7

Mean = 9

Mode = 6

Step-by-step explanation:

Have a gr8 day!

Answer:

the median is 7

Step-by-step explanation:

6,6,6,7,8,11,19

7 is the middle number

Find the area of the circle. Use 3.14 for tt. d = 6 ft A = [?] ft2 A=Tr2​

Answers

I know that the diameter is double of the radius, so I can divide 6 by 2 to get 3. 3.14(3)^2 gives me 28.26.

d=6ft

According to formula A=πr²

first we need 'r'

Hence,

as, r=d/2

r=6ft/2

r=3ft

A=πr²

A=3.14(3ft)²

A=3.14×9ft²

A=28.26ft²

I need help completing this answer are you available

Answers

Answer:

Step-by-step explanation:

Write C=5/9(F-32) in standard form

Answers

Answer:

f360 is the ans

Step-by-step explanation:

What are the possible degrees for the polynomial function?

Answers

Degrees of 6 or higher

Answer: Option 1

Degrees of 6 or greater

Answered by Gauthmath must click thanks and mark brainliest

What is the area of this figure?

Answers

Answer:

22

Step-by-step explanation:

(5x2) + (3x2) + (3x2)

22 square units

Answer from Gauthmath

04.10 Which statement about the graph is true? CO 7 E 5 4 3 2 1 2 3 4 5 6 7 8 x The graph shows a proportional relationship because it is a line, and the difference between each point is the same. The graph shows a proportional relationship because it is a line, and each x-value is a multiple of 2. The graph does not show a proportional relationship because each point written as a ratio gives a different value. O The graph does not show a proportional relationship because a line that increases by 1 in the y-value cannot have a constant of proportionality.​

Answers

Answer:

c

Step-by-step explanation:

cheese is rotten milk

I need help ASAP thank you

Answers

9514 1404 393

Answer:

  C

Step-by-step explanation:

The graph shows two vertical asymptotes, so the relevant function will be zero in the denominator for two different x-values. The only possibility is ...

  [tex]F(x)=\dfrac{1}{(x-1)(x+1)}[/tex]

A small boat can travel at 28 per hour how many hours will it take to go across the bay that is 56 miles wide

Answers

Answer:

2 hours

Remember that time = distance/rate

The distance you need to cover is 56 miles, while you go 28 miles per hour. Using these, we get this:

time=56/28

time=2

So it will take two hours to go across a 56 mile wide bay at 28 mph.

Step-by-step explanation:

Complete the function table.

Answers

Answer:

B

Step-by-step explanation:

The function given is f(n) = n-3. Plug in n=0 and you will get an output - 3. Plug in n=2 and you will get an output - 1. Hence table B is the answer .


I need help answering this question asap

Answers

Answer:

Step-by-step explanation:

What is the common difference for this arithmetic sequence?
-6,-1,4,9,14,...
A. 6
B. 4
C. 5
D. 3
SUBMIT

Answers

Answer:

5 is the answer to your question

Step-by-step explanation:

the numbers are increasing by +5

There is a circle with a center of 0,0 on a coordinate plane. There is one point on the circle's circumference in which the x:y ratio is 3:1. What is a possible coordinate?

Answers

Answer:

Step-by-step explanation:

Suppose the radius is 1. The parametric equations for the circle are

x = cosθ

y = sinθ

x:y = 3:1

tanθ = ⅓

cosθ = 3/√(1²+3²) =  3/√10

sinθ = 1/√10

The solutions are (3/√10, 1/√10) and (-3/√10, -1/√10).

Find the solutions of the quadratic equation x2 + 7x + 10 = 0.
Question 13 options:

A)

x = 2, 5

B)

x = –2, –5

C)

x = –7, –3

D)

x = 7, 3

Answers

Answer:

Step-by-step explanation:

x² + 7x + 10 = 0

x = [-7 ± √(7² - 4·1·10)]/(2·1) = [-7 ± √9[/2 = [-7 ± 3]/2 = -2, -5

what is the area of the trapezoid?

Answers

Answer:

A = 70 mm²

Step-by-step explanation:

The area (A) of a trapezoid is calculated as

A = [tex]\frac{1}{2}[/tex] h (b₁ + b₂)

where h is the perpendicular height and b₁, b₂ the parallel bases

Here h = 10, b₁ = 10, b₂ = 4 , then

A = [tex]\frac{1}{2}[/tex] × 10 × (10 + 4) = 5 × 14 = 70 mm²

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