M is the mass, and R is the body's radius, hence g=R2GM (planet).The pendulum's time period varying as its acceleration with respect to gravity changes.
How do I determine the acceleration due to gravity using a simple pendulum?Example: On the surface of the earth, a basic pendulum swings for a period of time T 0. This straightforward pendulum would have a period of 12 /xT 0 on a planet with an earth-like density but a radius four times that of the earth.
Answer: T 0 = 2 π√g / L is the formula for a simple pendulum's time period.
The value of g changes in accordance with the mass of a different planet that we visit.
g= GM / R² is the result.
M, which stands for mass, and R, which stands for body radius (planet).
Given, the radius is four times larger for a different planet with the same density.
Given, the radius is four times larger for a different planet with the same density.
M=density, volume, and p = 4/3 πR³
g= G * (p 4/3 πR³ / R² = G * p 4/3 π R
Here, R = 4R
⇒ G×ρ 3 / 4 π(4R)=4g
T 0 represents the new time frame.
T0 = 2π √ L/4g = T0/2
Consequently, 12/ x = 2 /1 x=6 because of =T 0 /2.
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a vertical spring scale can measure weights up to 210 n . the scale extends by an amount of 13.5 cm from its equilibrium position at 0 n to the 210 n mark. a fish hanging from the bottom of the spring oscillates vertically at a frequency of 2.15 hz . part a ignoring the mass of the spring, what is the mass m of the fish?
sheesh sheesh
Explanation:
a 1,402-kg car rounds an unbanked curve with a radius of 53 m at a speed of 9.9 m/s. what minimum coefficient of friction must exist between the road and tires to prevent the car from slipping?
To keep the car from slipping, the road and tires need to have a minimum coefficient of friction of 0.188.
The things creating friction will determine the coefficient of friction. The value is often between 0 and 1, but it can also be higher. A number of 0 indicates that there is absolutely no friction between the items; superfluidity makes this feasible. Yes. Because the adhesive forces between molecules are stronger when the contact surface is substantially polished, frictional force increases. In this situation, the friction coefficient will be higher than one.
Here m= 1402 kg
r=53
v= 9.9 m/s
g=9.8
coefficient = (v^2) / rg
coefficient = (9.9^2) / (53*9.8)
coefficient = 98.01/519.4
coefficient = 0.188
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ernie is trying to swim directly across a rushing river. ernie can swim at a rate of 6.2 m/s. the river's current is moving at a rate of 10.7 m/s. calculate the magnitude of ernie's resultant velocity?
The magnitude of Ernie's resultant velocity is [tex]V=8.72m/s[/tex].
Velocity:
Velocity is the direction in which an object is moving and serves as a measure of the rate at which its position is changing as seen from a specific point of view and as measured by a specific unit of time. In kinematics, the area of classical mechanics that deals with the motion of bodies, velocity is a fundamental idea.
Given,
Ernie's swimming rate with respect to the river [tex]V_{ER} =6.2 m/s[/tex]
River's current rate [tex]V_{R}=10.7 m/s[/tex]
Hence,
The magnitude of Ernie's resultant velocity
[tex]V[/tex] = [tex]V_{R} -V_{ER}=10.7i - 6.2j[/tex]
[tex]V=\sqrt{(10.7)^{2}-(6.2)^{2} }[/tex]
[tex]V=8.72m/s[/tex]
Hence,
The magnitude of Ernie's resultant velocity is [tex]V=8.72m/s[/tex].
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a point at an antinode of the standing wave on the wire travels from its maximum upward displacement to its maximum downward displacement in 8.40 msms . what is the wire'??s mass?
The relation between the time-period of the transverse wave for the third harmonic and the time between the maximum displacement and minimum displacement is [tex]=16.3 \mathrm{~g}[/tex]
[tex]$$T_3=2 t$$Substitute$8.40 \mathrm{~ms}$[/tex]
for t in the above expression.
[tex]$$T_3=2(8.4 \mathrm{~ms})\left(\frac{10^{-3} \mathrm{~s}}{1 \mathrm{~ms}}\right)$$[/tex]
The wave velocity can be given by the following expression [tex]=0.0168 \mathrm{~s}[/tex]
[tex]v=\frac{\lambda_3}{T_3}[/tex]
Here,
[tex]$$\lambda_3$$[/tex]
is the frequency of third harmonics and
[tex]$$T_3$$[/tex]
is the time-period of third harmonics.
Substitute [tex]$0.1296 \mathrm{~m}$[/tex] for
[tex]$$\lambda_3$$[/tex]
and
[tex]$0.0168 \mathrm{~s}$ for$T_3$[/tex]
[tex]\begin{aligned}& v=\frac{0.1296 \mathrm{~m}}{0.0168 \mathrm{~m}} \\& =7.714 \mathrm{~m} / \mathrm{s}\end{aligned}[/tex]
The expression of the wave velocity is given by the following expression.
[tex]v=\sqrt{\frac{T}{m / L}}[/tex]
Rearrange the above expression for
[tex]$$m$$[/tex]
[tex]\text { Substitute } 5.00 \mathrm{~N} \text { for } T, 0.1944 \mathrm{~m} \text { for } L \text {, and } 7.714 \mathrm{~m} / \mathrm{s} \text { for } v \text { in the above expression. }[/tex]
[tex]\begin{gathered}m=\frac{(5.00 \mathrm{~N})(0.1944 \mathrm{~m})}{(7.714 \mathrm{~m} / \mathrm{s})^2} \\=(0.0163345 \mathrm{~kg})\left(\frac{1000 \mathrm{~g}}{1 \mathrm{~kg}}\right) \\=16.3 \mathrm{~g}\end{gathered}[/tex]
The anti-nodes in the standing waves are at a distance half a wavelength. The time-period is twice the time from maximum displacement to minimum displacement of the anti-node.
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the force between between two objects increases by what factor if the distance between them is changed 4.5 times the original separation?
The new gravitational force between the object will be 1/20.25 times of the original force.
The gravitational force between any two object is defined as the product of the masses of the object and it is inversely proportional to the square of the distance between them which is given by,
F = GMm/R²
Here,
G is the universal gravitational constant, M and m are the mass of the body and R is the distance between them.
As per the given question the distance between the object is increased 4.5 times the original separation.
R' = 4.5R.
The new force of attraction between the object will be,
F' = GMm/(R')²
F' = GMm/(4.5R)²
F' = GMm/20.25R²
F' = F/20.25
So, the new force of attraction between the two objects will become 1/20.25 times of original force.
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a dad pushes tangentially on a small hand-driven merry-go-round and is able to accelerate it from rest to a frequency of 15 rpm in 10.0 s. assume the merry-go-round is a uniform disk of radius 2.5 m and has a mass of 330 kg, and two children (each with a mass of 25 kg) sit opposite each other on the edge. calculate the torque required to produce the acceleration, neglecting frictional torque. what force is required at the edge?
Refer to the photo taken.
a pendulum is pulled to a height of 1.28 m above the lowest position and released. what is its speed at the level of the lowest position?
The speed at the level of the lowest position is 5.01m/s.
How do you conserve energy?Energy cannot be created or destroyed; it can only be changed from one form of energy to another, according to the law of conservation of energy. This implies that a system always has the same amount of energy, barring external energy addition.
To reduce expenses and protect the resources for future use, energy conservation is necessary. The environment is contaminated by the harmful gases released into the atmosphere by conventional energy sources. Traditional energy sources are finite and could run out one day.
This is a typical energy conservation question, Set the kinetic energy at the bottom and the potential energy at the height to be equal.
mgh = 1/2mv²
gh = v²/2
v = √2gh
v = √2×9.8×1.28m/s
v = 5.01m/s.
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A physics student walks 6 meters east, 4 meters north, then 9 meters
west. What is the student's magnitude of displacement from starting
position?
Answer:
5 m
Explanation:
Displacement is the straight-line distance from the starting point to the end point. Student ends up 4m north and 3m west from where he started. Use pythagorean theorem to solve for displacement (d).
d² = 3² + 4² = 25
d = [tex]\sqrt{25}[/tex] = 5 m
Or, if you remember from geometry, a right triangle with legs of 3 and 4 has a hypotenuse of 5 (3-4-5 right triangle)
Question 8 of 20
You heat a pot of water on a gas stove. Not all the energy from the
combustion of the gas is transformed into thermal energy. What happens to
the rest of the energy released when the gas burns?
OA. It is transformed into light energy.
OB. It is transformed into chemical energy.
C. It is transformed into electrical energy.
OD. It is transformed into nuclear energy.
SUBMIT
Answer:
None of the choices you provided are correct. When a gas burns, it releases energy in the form of heat and light. Some of this energy is transferred to the pot of water, increasing its temperature, but some of the energy is also released as light. However, the rest of the energy is not transformed into chemical, electrical, or nuclear energy. Instead, it is lost to the environment in the form of waste heat. This is why gas stoves can become hot to the touch - they are releasing excess energy in the form of heat that is not being used to heat the pot of water.
Explanation:
WILL GIVE BRAINLY IF RIGHT
what would happen if you dropped, at the same time, particles of different shapes from a boat into still water
Explanation:
If you dropped particles of different shapes from a boat into still water, they would fall straight down due to the force of gravity. The speed at which they fall would depend on their mass and the shape of the particles could affect how they move through the water, but ultimately they would all sink to the bottom of the water body. If the particles are buoyant, they may float instead of sinking.
Classify the type of reaction below.
C2H6 + O2
--> CO2 + H2O
a. Synthesis
b. Decomposition
c. Combustion
d. Single Replacement
e. Double Replacement
Answer: Synthesis
Explanation: You are combining multiple Elements
A 20 kg wagon is pulled along the level ground by a rope inclined 30 degrees above the horizontal (friction is
negligible) (A) How large is the pulling force is the wagon accelerates of .40 m/s²? (B) What is the normal force of
the wagon?
Answer:
(A) 9.2 Newtons
(B) 200.8 Newtons
Explanation:
Attached is the free body diagram I drew along with some of the work/formulas I used. Please ask me any questions you have in the comments about my diagram/work. I'd be happy to walk you through it.
a dog lifts a 0.75 kg bone straight up through a distance of 0.11 m. How much work was done by the dog ?
The work done by the dog is 0.81J.
What is work done?Work done is a measure of energy expended in moving an object; most commonly calculated by multiplying the force by the distance.
It is said that no work is done if the object does not move.
The work done on an object is the amount of energy transferred to an object through work.
According to this question, a dog lifts a 0.75 kg bone straight up through a distance of 0.11 m. The force applied to break the bone must be calculated first as follows:
Force = mass × acceleration
Force = 0.75kg × 9.8m/s²
Force = 7.35N
Work done = 7.35N × 0.11m = 0.81J
Therefore, 0.81J is the work done by the dog.
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Maher is trying to find the density of a plastic toy. The toy’s mass is 160 g.
Maher placed the toy in a graduated cylinder that has 70 ml of water, the water level increased
till 150 ml.
a) Find the toy’s volume.
The volume of the toy is 80 ml.
To find the volume of the plastic toy, Maher can use the principle of buoyancy. When an object is placed in a fluid, it will displace an amount of fluid equal to its own volume. The volume of the displaced fluid can be measured and used to calculate the volume of the object.
In this case, Maher has placed the toy in a graduated cylinder filled with water, and he has observed that the water level increased from 70 ml to 150 ml. This means that the toy displaced 150 - 70 = 80 ml of water.
The volume of the toy is equal to the volume of the displaced water, so the toy's volume is 80 ml. This is the volume of the toy when it is completely submerged in water.
It's important to note that the volume of an object can change depending on its temperature, pressure, and other factors. To get an accurate measurement of the volume of the toy, Maher should make sure to measure the volume of the displaced water carefully and under controlled conditions.
Answer:
Volume of the toy: [tex]80\; {\rm mL}[/tex].
Average density of the toy: [tex]2\; {\rm g\cdot mL^{-1}}[/tex] (or equivalently, [tex]2\; {\rm g \cdot cm^{-3}}[/tex].)
Explanation:
The graduated cylinder initially measures the volume of water in this cylinder:
[tex]V(\text{water}) = 70\; {\rm mL}[/tex].
Assume that the toy is submerged in the water. The graduated cylinder would then measure the volume of the water and the toy, combined:
[tex]V(\text{water}) + V(\text{toy}) = 150\; {\rm mL}[/tex].
Rearrange to find the volume of the toy:
[tex]\begin{aligned}V(\text{toy}) &= 150\; {\rm mL} - V(\text{water}) \\ &= 150\; {\rm mL} - 70\; {\rm mL} \\ &= 80\; {\rm mL}\end{aligned}[/tex].
To find the average density of this toy, divide mass by volume:
[tex]\begin{aligned}(\text{average density}) &= \frac{(\text{mass})}{(\text{volume})} \\ &= \frac{160\; {\rm g}}{80\; {\rm mL}} \\ &= 2\; {\rm g\cdot mL^{-1}}\end{aligned}[/tex].
Uing two billiard ball and 3 to 4 entence decided experiment to demontrate the law of conervation of momentum. (4 point)
So let's talk about billiard balls and the law of conservation of momentum. For the purposes of this simplified discussion, momentum is always conserved for collisions between balls.
What is momentum?Momentum is a commonly used term in sports. A team that has the momentum is on the move and is going to take some effort to stop. A team that has a lot of momentum is really on the move and is going to be hard to stop. Momentum is a physics term; it refers to the quantity of motion that an object has. A sports team that is on the move has the momentum. If an object is in motion (on the move) then it has momentum.Momentum can be defined as "mass in motion." All objects have mass; so if an object is moving, then it has momentum - it has its mass in motion. The amount of momentum that an object has is dependent upon two variables: how much stuff is moving and how fast the stuff is moving. Momentum depends upon the variables mass and velocity. In terms of an equation, the momentum of an object is equal to the mass of the object times the velocity of the object.To learn more about velocity refer to:
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1. Find the force due to gravity if the mass of the object is 2300 kg
and the mass of the other object is 4000 kg. The distance
between the two objects is 0.150 m.
The force due to gravity will be 0.0272 Newtons.
What exactly does gravitational force signify?The force between two mass-containing objects that are drawn toward one another is referred to as the gravitational pull. There is gravity everywhere around us. For instance, it maintains the planets in our solar system in orbit around the Sun. Additionally, because to gravity, the Moon maintains its orbit around the Earth.
How to calculate gravitational force in the above question?Despite being weak and appealing, gravitational forces exist.
Given, mass of one object= 2300 kg
mass of another object= 4000 kg
distance between the two objects= 0.150 m
value of G is universal, [tex]G= 6.67[/tex]×[tex]10^{-11}[/tex] [tex]N m^{2} / kg^{2}[/tex]
the equation is, [tex]F=G\frac{M1 . M2}{d^{2} }[/tex]
[tex]F=0.0272 N[/tex]
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disregarding friction, how far will the cart move in 3.2 s, starting from rest? answer in units of m.
If the cart moves in 3.2 seconds from rest, then the distance traveled by cart is 2 meters.
Which definition of distance suits you best?How do you define distance? Regardless of direction, distance measures an object's overall movement. Distance is defined as the amount of ground covered by an object, regardless of its starting or stopping position.
Horizontal force acting on the cart, F = 11 N
Mass of the cart, m = 35 kg
To find,
Distance covered by the cart in 3.5 seconds if it starts from rest.
Solution,
Let x is the distance moved by the cart. It can be calculated using the second equation of motion as :
s = 1.925 meters
What is the definition of a distance?In terms of "how much land an object is covered" while traveling, distance—a scalar quantity—describes this. Displacement is a vector number that expresses the overall change in the object's location, and it is related to the phrase "how far from place the thing is."
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when you looked at solar activity on the heliophysics event registry website, on which date did you find activity on the sun?
You did look at solar activity on the heliophysics event registry website, and we found activity on the sun on the specified day.
What three sorts of solar occurrences are there?Any natural occurrence in the upper atmosphere of the sun is referred to as a solar phenomenon. Solar flares, prominences and filaments, and coronal mass ejections are three different categories of solar phenomena.
How can I follow the cycle of solar activity the best?The simplest way we can investigate how solar activity changes over time is to survey sunspots, which is also how we track the solar cycle. Sunspots are associated with the Sun's natural 11-year cycle, during which the planet's surface changes from calm to turbulent.
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a constriction in a pipe reduces its diameter from 4.0 cm to 2.0 cm. where the pipe is narrow the water speed is 8.0 m/s. where it is wide the water speed is:
The velocity on the narrow side is 11.6 m/s. This is the velocity of the water in the narrow part of the pipe.
How to find velocity ?To find the velocity of the water where the pipe is narrow, you can use the formula for the mass flow rate, which is given by:
Mass flow rate = Density * Flow rate
= Density * (Area * Velocity)
Where:
Density is the density of the fluid
Flow rate is the volume flow rate, or the rate at which volume flows through the pipe
Area is the cross-sectional area of the pipe
Velocity is the velocity of the fluid
The mass flow rate is constant, so you can set the mass flow rate on either side of the constriction equal to each other and solve for the velocity on the other side.
The cross-sectional area of the pipe on the narrow side is given by the formula for the area of a circle:
A = pi * r^2
Where:
A is the cross-sectional area of the pipe
r is the radius of the pipe
The radius of the pipe on the narrow side is 3 cm / 2 = 1.5 cm. Plugging this value into the formula for the cross-sectional area, you get:
A = pi * (1.5 cm)^2
= 7.07 cm^2
The cross-sectional area of the pipe on the wide side is given by the same formula, with a radius of 6 cm / 2 = 3 cm:
A = pi * (3 cm)^2
= 28.27 cm^2
Since the mass flow rate is constant, you can set the mass flow rates on either side of the constriction equal to each other and solve for the velocity on the other side:
(Density * 7.07 cm^2 * v) = (Density * 28.27 cm^2 * 8 m/s)
Solving for v, the velocity on the narrow side, you get:
v = (Density * 28.27 cm^2 * 8 m/s) / (Density * 7.07 cm^2)
= 11.6 m/s
The final value for the velocity on the narrow side is 11.6 m/s. This is the velocity of the water in the narrow part of the pipe.
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Where does the depenent variable go on a graph?
The dependent variable go on the Y-axis on a graph.
what is a dependent variable?The dependent variable is described as the variable that is being measured or tested in an experiment.
Dependent variable can be explained using the example where a test score could be a dependent variable because it could change depending on several factors such as how much you studied, how much sleep you got the night before you took the test, or even how hungry you were when you took it.
The independent variable is found on the x-axis (horizontal line) of the graph and the dependent variable is displayed on the y-axis.
The difference between independent variable and the dependent variable is that in an experiment, the independent variable is the variable that is varied or manipulated by the researcher.
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if we have a system that uses 5 volts with a frequency of 1ghz and the power used is 3 watts, what is the power draw when we increase the frequency to 3ghz?
Processor-A uses 20 W of power components and 80 W cpu dynamic power 3 GHz.
Static power: What does that mean?When there is no design activity occurring, static power—also known as "leakage"—is used up. It closely relates to the transistor's idle current, which is based on the transistor's characteristics.
Power is it static or is it dynamic?While leakage, or the current that passes through a transistor while there is no activity, makes up static power, switching or short-circuit power are components of dynamic power. Any of the following things may influence each power component's value: Activity. Frequency.
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a 65 kg person dives into the water from the 10 m platform. a. what is her speed as she enters the water?
The speed of the person as she enters the water is 14.2 m/s.
What is kinetic energy?Kinetic energy is the energy of motion. It is the energy that an object has due to its motion. This energy can be transferred from one object to another or converted into other forms of energy. Kinetic energy is dependent on an object's mass and its velocity. The greater an object's mass or velocity, the more kinetic energy it has. Kinetic energy can be used to do work, such as powering a machine or vehicle. It can also be used to generate electricity or to heat up objects.
The speed of the person as she enters the water can be calculated using the equation for kinetic energy:
KE = ½mv²
Where m is the mass of the person (65 kg) and v is the speed.
Solving for v, we get:
v = √(2KE/m)
Since the potential energy of the person just before she enters the water is equal to the kinetic energy of the person just after she enters the water, we can calculate the kinetic energy as:
PE = mgh
KE = mgh
Where m is the mass of the person (65 kg), g is the acceleration due to gravity (9.8 m/s²), and h is the height of the platform (10 m).
Plugging this into the equation for v, we get:
v = √(2mgh/m)
v = √(2gh)
v = √(2*9.8*10)
v = 14.2 m/s
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9) During a game of bowling, which of the following describe the ball's motion?(SELECT ALL ANSWERS THAT APPLY)
A) The ball is accelerated while it is pushed by the student's hand due to an
unbalanced force.
B) The ball slows down as it rolls because friction exerts an unbalanced force.
C) The ball is accelerated while it is held in the student's hand due to balanced
Forces.
D) The ball does not change its motion as it rolls because of the balanced force
provided by friction.
E) The ball does not change its motion while it is held in the student's hand due to
balanced forces.
During a game of bowling the ball's motion:
The ball is accelerated while it is pushed by the student's hand due to an unbalanced force.The ball slows down as it rolls because friction exerts an unbalanced force.The ball does not change its motion while it is held in the student's hand due to balanced forces.The correct options are A,B and E.
Description of a bowling ball's motionBowling ball motion is commonly divided into sequential skid, hook, and roll phases. When the ball moves down the lane in the skid and hook phases, frictional contact with the lane causes the ball's forward (translational) speed to continually decrease, but to continually increase its revolution rate (rotational speed).
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determine the energy levels and the corresponding eigenstates for a par- ticle of mass m, subject to a potential energy v (x) g
An energy eigenstate can always be written as (x,t) = (x)e-iEt/1. Probability density is equal to |(x,t)|2 (x,t) (x)e-iEt/1 * (x,t) ψ*(x)e+iEt/1 = ψ (x) The wave function *(x) = |(x)|2 exhibits time-dependent phase.
V's role in the Schrodinger equation?For the system of a particle or particles interacting with a set of constraints, V(x) is a potential energy function. These restrictions can be compared to fields that exert a force on the desired particle or particles.
What is the energy eigenvalue?The term "energy eigenvalues," which comes from the German word eigen, which means "characteristic" or "unique," refers to such particular discontinuous (step-like) energies. We refer to these energies as discrete energy eigenvalues or as quantized energies.
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The energy levels and the corresponding eigenstates of a particle of mass m subject to a potential energy v(x) g can be determined by solving the time-independent Schrodinger equation.
What is potential energy?
Potential energy is energy that is stored and can be released in the future. It is the energy of position or condition, as opposed to kinetic energy which is energy in motion. Potential energy can be stored in many forms such as gravitational, chemical, elastic, nuclear, and electromagnetic. Gravitational potential energy is the energy stored in an object due to its position in a gravitational field, while chemical potential energy is the energy stored in the bonds of chemical compounds. Elastic potential energy is energy stored in objects that can be stretched or compressed, such as a spring, while nuclear potential energy is the energy stored in the nucleus of an atom. Electromagnetic potential energy is the energy stored in the electric and magnetic fields of an object.
The energy levels and the corresponding eigenstates of a particle of mass m subject to a potential energy v(x) g can be determined by solving the time-independent Schrodinger equation:
Hψ = Eψ
Where H is the Hamiltonian operator, ψ is the wavefunction, and E is the energy. For a particle of mass m subject to a potential energy v(x) g, the Hamiltonian can be written as:
H = -(h2/2m)*d2/dx2 + v(x) g
The solution of the Schrodinger equation for this Hamiltonian yields the energy levels E and the corresponding wavefunctions ψ. The energy levels are determined by solving the equation:
E - v(x) g = 0
This equation can be solved for the different energy levels E, and the corresponding wavefunctions can then be determined by solving the Schrodinger equation. The wavefunctions represent the probability distribution of the particle, and are determined by the boundary conditions imposed by the potential energy.
In summary, the energy levels and the corresponding eigenstates of a particle of mass m subject to a potential energy v(x) g can be determined by solving the time-independent Schrodinger equation. The energy levels are found by solving the equation E - v(x) g = 0, and the corresponding wavefunctions are found by solving the Schrodinger equation.
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find the maximum transverse speed of a point on the string. (f) what would be the equation y1x, t2 for this string if it were vibrating in its eighth harmonic?
In a one-dimensional string, a harmonic wave has a maximum transverse velocity and maximum transverse acceleration of 1ms-1 and 1ms-2, respectively.
What is maximum transverse speed of a point on the string?We have attached a harmonic wave with a frequency of 80 Hodge to the string. Additionally, a positive extraction travels at a speed of 12 m/s with an amplitude of 0.025 m. Next, we must create a proper wave function for this wave in the first. In light of this.
we have established that the frequency F is the hurt amplitude is 0.025 m, and the speed is 12 m/s. As a result, given that we are aware of the wave function's writing, we may determine whether or not the sign K x minus omega T applies. Omega, which equals two pi into, is the angular frequency in this case. Thus, we can say that this word has been introduced. 80 is to be purchased That makes 160 by, too.
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what is the equation describing the motion of a mass on the end of a spring which is stretched 8.8 cm from equilibrium and then released from rest, and whose period is 0.66 s ? assume that the displacement at the start of the motion is positive.
Answer:
x = A cos ω t at t = zero, x displacement equals amplitude
x = .088 m cos ω t describes the motion
We need yet to find ω in terms of P which is given
ω = √(k / m)
P = 1 / f and f = ω / (2 π)
Thus ω = 2 π f = 2 π / P since 1 / f = P
This gives us
x = .088 m cos 2 π / .66 * t
1. A car moving 11 m/s accelerates at 1.5 m/s². How fast is it moving after it accelerates for 50
seconds?
Type a response (show work please)
We may be aware that, for example, a car leaving a stop sign would move farther in a given amount of time the faster it accelerates.
what an acceleration is?acceleration is the rate of change in both speed of velocity over time. When anything moves faster or slower in a straight line, it is said to have been accelerated. So because direction is always shifting, motion on a circle accelerates even while the speed is constant.
What prompts accelerating?An object's velocity is altered by a net force, and acceleration increases with net force. To accelerate at the same rate as less massive objects, more massive objects need greater net forces.
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a 40cm diameter wheel accelerates uniformly from 240 rpm to 360 rpm in 6.5 seconds. how far will a point on the edge of the wheel have traveled in this time
Answer:
S = V1 t + 1/2 a t^2 distance traveled for linear acceleration
θ = ω1 t + 1/2 α t^2 equivalent angle for rotational acceleration
ω1 = 240 / min * 2 π * 240 / (60 s/min) = 8 π / s
ω2 = 360 rpm = 12 π / s
α = 4 π/ 6.5 s^2 = .62 π / s^2 angular acceleration
θ = 8 π / s 6.5 s + .62 π / 2 * 6.5^2
θ = 52 π + 13 π = 65 π = 65 * π / (2 π / rev) = 32.5 rev
1 rev = 2 * π * R = 2 * π * .4 m = 2.51 m / rev
S = 32.5 rev * 2.5 m/rev = 81 m
- Determine the tension in each cable in the diagram to the right.
Tension of the three cables connecting the celling, 7 kg ball, 4 kg ball, 5 kg ball respectively 156.8 N, 88.2 N and 49 N.
What is tension?The force communicated through a rope, string, or wire when two opposing forces draw on it is known as tension. The tension force pulls energy equally on the bodies at the ends and is applied along the entire length of the wire.
Tension of the cable connecting the celling and 7 kg ball:
= (7 kg + 4 kg + 5Kg) × 9.8 m/s²
= 156.8 N.
Tension of the cable connecting the 7kg ball and 4 kg ball:
= (4 kg + 5Kg) × 9.8 m/s²
= 88.2 N.
Tension of the cable connecting the 4kg ball and 5 kg ball:
= 5Kg× 9.8 m/s²
= 49 N.
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.An object has a mass of 10 kg and an acceleration of 20 m/s2. What is the force on the object?
The force acting on the object is 200 Newton.
What is force?The definition of force in physics is: The push or pull on a massed object changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.
Given that mass of the object: m = 10 kg.
acceleration of the object = 20 m/s^2.
Hence, according to Newton's 2nd law of motion:
Force = mass × acceleration
= 10 × 20 Newton
= 200 Newton.
Hence, the force on the object is 200 Newton.
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