TIMED HELP ASAP

19.11 g of MgSO₄ is placed into 100.0 mL of water. The water's temperature increases by 6.70°C. Calculate ∆H, in kJ/mol, for the dissolution of MgSO₄. (The specific heat of water is 4.184 J/g・°C and the density of the water is 1.00 g/mL). You can assume that the specific heat of the solution is the same as that of water.

Answers

Answer 1

Answer:

TIMED HELP ASAP

19.11 g of MgSO₄ is placed into 100.0 mL of water. The water's temperature increases by 6.70°C. Calculate ∆H, in kJ/mol, for the dissolution of MgSO₄. (The specific heat of water is 4.184 J/g・°C and the density of the water is 1.00 g/mL). You can assume that the specific heat of the solution is the same as that of water.

Answer 2

Answer:

-21.03 kJ/mol

Explanation:

∆H is enthalpy. Enthalpy is the total heat content of a system.

So we can establish that ∆H = q (heat)

The formula for heat (q)

q = cm∆T

c = specific heat capacity

m = mass of substance

∆T= change of temperature

Since we are calculating the enthalpy of the SOLUTION. We must account for both the mass of water and the mass of MgSO₄ in our q formula.

All you gotta do is plug and chug at this stage.

∆H = q     = cm∆T = (4.184)(19.11+100.0)(6.70) = 3338.986808 Joules

We have now calculated the heat (aka enthalpy) of the solution.

BUT

Remember! The problem asked for enthalpy in kj....

Use this conversion factor.

1000 J = 1 kJ

3338.986808 Joules * 1kJ/1000 J = 3.338986808 kJ

We were asked to find ∆H for the dissolution of MgSO4  in units of kj/mol so we are not finished.

Take the grams of MgSO4 in the problem  and convert it into moles using its molar mass.

MgSO4 molar mass = 120.3676 g

1 mol = 120.3676 g MgSO4   <---- Use this as a conversion factor

19.11 g MgSO4 * 1 mol MgSO4/120.3676 g = 0.15876365 mol MgSO4

Now that you've calculated the moles of MgSO4 in this solution. You can divide your heat by it.

q dissolution = 3.338.986808 kJ/ 0.15876365 mol =  21.03 kj/mol

Note that the problem tells us that the temperature of water increases.

This means that the water is experiencing an endothermic process (heat is being absorbed from MgSO4) . Mathematically, this would be indicated by a positive sign. ---> +q

We can assume MgSO4 is losing heat as it is placed into the water. It is experiencing an exothermic process (heat is being lost).  Mathematically, this would be indicated by a negative sign. ----> -q

So if we're calculating the enthalpy for the dissolution of MgSO₄ ....the value we've arrived at must be negative.

Answer

∆H = 21.03 kj/mol :)))))

I hope that helped...I feel like my explanation was a bit convoluted.

TIMED HELP ASAP19.11 G Of MgSO Is Placed Into 100.0 ML Of Water. The Water's Temperature Increases By

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Answer:

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What is the chemical formula for carbon tetrafluoride?
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Answer:

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Explanation:

hope it helps you

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Answers

Answer:

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Answer:

Age. ...

Residency. ...

Residence and Physical Presence.

Good Moral Character.

Attachment to the Constitution.

Language.

U.S. Government and History Knowledge.

Oath of Allegiance.

These are some requirements for obtaining citizenship .

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Culture
Race
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Answer:

1;1, 2;1, 3;1, 1;2, 1;1, 3;2, 1;3, 2;3, 1;1.

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Answer:

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Answers

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Answers

The final temperature of the water, T2 = 38.57°C

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Answers

The Sun radiates sunlight (visible)  photons

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Explanation:

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Answer:

bete is your answer.

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Answer:

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Karma is saying to add water to acid.By which acid will be diluted and become less hazardous.Sonam is saying to add an indicator .She is advising wrong .Indicator won't absorb much acid.For which this is uneffective unless it changes a colour.Sangay's idea is also fluff.Salt won't react with acid to neutralise. Because both contains halogens.Like Sodium chloride is a salt and Hydrochloric acid is also a salt.Yes,Tshering's idea is quite good.by this acid will be neutralized some.Thsomo's idea is also good .Its better to call teacher but we should solve it by ourselves.I think karma's suggestion is best .It is better to dilute the acid .But we should add water while mixing acid with spoon .

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1 Anomalous Pairs. The rest of the  pairs of elements don't follow the follow Mendeleev's Principles . they are :

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career in chemistry list ten

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Explanation:

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Analytical Chemist.
Chemical Engineer.
Chemistry Teacher.
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C. 4M
D. 1 M

Answers

Answer:

[tex]\boxed {\boxed {\sf B. \ 0.5 \ M}}[/tex]

Explanation:

Molarity is a measure of concentration in moles per liter. The formula for calculating molarity is:

[tex]molarity= \frac{moles \ of \ solute}{ liters \ of \ solution}[/tex]

There are 2 moles of a compound or the solute. There are 4 liters of water or the solution.

moles of solute= 2 mol liters of solution = 4 L

Substitute the values into the formula.

[tex]molarity = \frac{ 2 \ mol}{ 4 \ L}[/tex]

Divide.

[tex]molarity= 0.5 \ mol /L[/tex]

1 mole per liter is equal to 1 Molar, so the solution's molarity of 0.5 mol/L is equal to 0.5 M.

[tex]molarity = 0.5 \ M[/tex]

The molarity of the solution is 0.5 Molar and choice B is correct.

WM "Please write the molecular formula for the following by criss cross method. 1. Calcium nitrate 2. Sodium bicarbonate 3. Magnesium nitrite 4. Sodium chloride 5. Hydrogen sulphate 6. Hydrogen chloride T-Aluminium bisulphate 8 Aluminium chloride 9. Aluminium sulphate 10. Hydrogen Nitrate​

Answers

Answer:

1 Ca(NO3)2

Calcium- Ca, Valency 2

Nitrate- NO3, Valency 1

AFTER CRISS CROSS:

Ca1(NO3)2

Ca(NO3)2

2 sodium bicarbonate = NaHCO3

Na = Sodium = (Na)+

HCO3 = bicarbonate = (HCO3) -

Na HCO3

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    +1    _1

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5 hydrogen         sulphide  

H                       SO4

+1                       _2

formula H2SO4

6  H    Cl

  +1     _1

HCl

7 AL2     HSO4

  +2        -2

AL2(HSO4)3

8  NH4   Cl

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