three friends, akira,bruno and carmela pooled thier money to start a lemonade stand. akria contributes $25, bruno contributed $20 and carmela contributed $35. after a month, thier lemoneade stand had earned 2000, and they want to distribute this money in the same ratio as the money that was invested. how many dollars will brouno recieve
plz explian

Answers

Answer 1

9514 1404 393

Answer:

  $500

Step-by-step explanation:

Bruno's fraction of the total contribution was ...

  Bruno / Total = $20/($25 +20 +35) = 20/80 = 1/4

Then Bruno's share of the earnings is this same fraction, so is ...

  (1/4) × ($2000) = $500


Related Questions

If X is a normal random variable with mean 6 and standard deviation 2.0, then find the value x such that P(X > x) is equal to .7054. Group of answer choices5.28

5.46

4.92

7.28

Answers

Answer:

Step-by-step explanation:

If X is a normal random variable with a mean of 6 and a standard deviation of 3.0, then find the value x such that P(Z>x)is equal to .7054.

-----

Find the z-value with a right tail of 0.7054

z = invNorm(1-0.7054) = -0.5400

x = zs+u

x = -5400*3+6 = 4.38

The product of -3x and (2x+5) is …​

Answers

[tex]\huge{\boxed{\boxed{ Solution ⎇}}} \ [/tex]

[tex] - 3x \times (2x + 5) \\ = - 3x \times 2x + - 3x \times 5 \\ = - 6x ^{2} - 15x[/tex]

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ ツ

꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐

[tex] \huge\boxed{\mathfrak{Answer}}[/tex]

[tex] - 3x \times (2x + 5) \\ = - 3x \times 2x + - 3x \times 5 \\ = - 6x ^{2} - 15x [/tex]

Answer ⟶ - 6 - 15x

Can someone help me with this question an my other work?

Answers

The gradient of the line is -2/3 so A is incorrect
The line is solid so is part of the solution set so the equation needs >= so C and D are incorrect.

The correct answer is B y >= -2/3x + 1

You could have tested the labelled points and any point off the line (say (0,0)) by substituting into each option.

Hello, please help me!!​

Answers

Answer:

0.14

Step-by-step explanation:

P(A|B) asks for the probability of A, given that B has happened. This is equal to the probability of A and B over the probability of B (see picture)

Here, the question is asking if someone is taking the bus given that they are a senior.

The probability of someone being a senior and taking the bus is 5/100, or 0.05 . The probability of someone being a senior is 35/100, or 0.35

Our answer is then 0.05/0.35 = 1/7 = 0.14

please help to solve this in written format

Answers

Answer:

50 dozen total

Step-by-step explanation:

8/12 & 10/12.... average 9/12

11/12 - 9/12 =

2/12x = 100

2x = 1200

x = 600/12

50 dozen total

Sarah ordered 39 shirts that cost $8 each. She can sell each shirt for $16.19. She sold 32 shirts to customers. She had to return 7 shirts and pay a $1.4 charge for each returned shirt. Find Sarah's profit.

Answers

Answer:

$196.28

Step-by-step explanation:

Original cost: 39 × $8 = $312

Revenue: 32 × $16.19 = $518.08

Return charge: 7 × $1.4 = $9.8

$312 + $9.8 = total cost, which is $321.8

$518.08 - $321.8 = profit

Profit = $196.28

Solve for X.
-6x + 14 < -28
AND 3x + 28 < 25

Answers

Answer:

1. -6x + 14 < -28

6x<42

x<7

2.  3x + 28 < 25

3x < -3

x<-1

Hope This Helps!!!

Paul writes newspaper articles. He earns a base rate of $500 per month and an additional $100 per article he writes. Last month he earned $2000.

Write an equation to determine the number of articles (a) he sold last month.

Answers

Answer:

Total earning last month with x articles is:

x*100 + 500

This is same amount as 2000

The equation is:

100x + 500 = 2000

Is it possible to have a relation on the set {a, b, c} that is both symmetric and transitive but not reflexive

Answers

Answer:

Yes, it is possible to have  a relation on the set {a, b, c} that is both symmetric and transitive but not reflexive

Step-by-step explanation:

Let

Set A={a,b,c}

Now, define a relation R on set A is given by

R={(a,a),(a,b),(b,a),(b,b)}

For reflexive

A relation is called reflexive if (a,a)[tex]\in R[/tex] for every element a[tex]\in A[/tex]

[tex](c,c)\notin R[/tex]

Therefore, the relation R is  not reflexive.

For symmetric

If [tex](a,b)\in R[/tex] then [tex](b,a)\in R[/tex]

We have

[tex](a,b)\in R[/tex] and [tex](b,a)\in R[/tex]

Hence, R is symmetric.

For transitive

If (a,b)[tex]\in R[/tex] and (b,c)[tex]\in R[/tex] then (a,c)[tex]\in R[/tex]

Here,

[tex](a,a)\in R[/tex] and [tex](a,b)\in R[/tex]

[tex]\implies (a,b)\in R[/tex]

[tex](a,b)\in R[/tex] and [tex](b,a)\in R[/tex]

[tex]\implies (a,a)\in R[/tex]

Therefore, R is transitive.

Yes, it is possible to have  a relation on the set {a, b, c} that is both symmetric and transitive but not reflexive.

Which of the following is the intersection of the line AD and line DE?

Answers

Answer:

Point D

Step-by-step explanation:

The intersection(s) of lines represents where they cross or intersect. We can see that lines AD and DE cross or intersect as Point D, hence the answer being Point D.

Answer: Point D

Step-by-step explanation: The intersection of two figures is the set of points that is contained in both figures. In the diagram shown, D is the intersection of lines AD and DE because D is the point contained by both line AD and DE.

If 19,200 cm2 of material is available to make a box with a square base and an open top, find the largest possible volume of the box.

Answers

Step-by-step explanation:

√19200cm²

=138.56cm

then the highest possible volume

=(138.56)³

=2660195.926cm³

The largest possible volume of the box is; V = 25600 cm³

Let us denote the following of the square box;

Length = x

Width = y

height = h

Formula for volume of a box is;

V = length * width * height

Thus; V = xyh

but we are dealing with a square box and as such, the base sides are all equal and so; x = y. Thus;

V = x²h

The box has an open top and as such, the surface are of the box is;

S = x² + 4xh

We are given S = 19200 cm². Thus;

19200 = x² + 4xh

h = (19200 - x²)/4x

Put (19200 - x²)/4x for h in volume equation to get;

V = x²(19200 - x²)/4x

V = 4800x - 0.25x³

To get largest possible volume, it will be dimensions when dV/dx = 0. Thus;

dV/dx = 4800 - 0.75x²

At dV/dx = 0, we have;

4800 - 0.75x² = 0

0.75x² = 4800

x² = 4800/0.75

x² = 6400

x = √6400

x = 80 cm

From h = (19200 - x²)/4x;

h = (19200 - 80²)/(4 × 80)

h = (19200 - 6400)/3200

h = 4 cm

Largest possible volume = 80² × 4

Largest possible volume = 25600 cm³

Read more at; https://brainly.com/question/19053087

The principle of redundancy is used when system reliability is improved through redundant or backup components. Assume that a​ student's alarm clock has a 15.3​% daily failure rate. Complete parts​ (a) through​ (d) below. a. What is the probability that the​ student's alarm clock will not work on the morning of an important final​ exam?

Answers

Answer:

[tex]Pr = 0.153[/tex]

Step-by-step explanation:

Given

[tex]p = 15.3\%[/tex]

Required

Probability of alarm not working

[tex]p = 15.3\%[/tex] implies that the alarm has a probability of not working on a given day.

So, the probability that the alarm will not work on an exam date is:

[tex]Pr = 15.3\%[/tex]

Express as decimal

[tex]Pr = 0.153[/tex]

The sum of 5 consecutive integers is 505. What is the second number in this sequence?

Answers

Answer:

The second number is 100.

Step-by-step explanation:

Let the first integer be x.

Then since the five integers are consecutive, the second integer will be (x + 1), the third (x + 2), fourth (x + 3), and the fifth (x + 4).

They total 505. Hence:

[tex]\displaystyle x+(x+1)+(x+2)+(x+3)+(x+4)=505[/tex]

Solve for x. Combine like terms:

[tex]5x+10=505[/tex]

Subtract 10 from both sides:

[tex]5x=495[/tex]

And divide both sides by five. Hence:

[tex]x=99[/tex]

Thus, our sequence is 99, 100, 101, 102, and 103.

The second number is 100.

Using law of sines please show process!!!

Answers

Let the <C=x

We know in a triangle

☆Sum of angles=180°

[tex]\\ \sf\longmapsto 51+26+x=180[/tex]

[tex]\\ \sf\longmapsto 77+x=180[/tex]

[tex]\\ \sf\longmapsto x=180-77[/tex]

[tex]\\ \sf\longmapsto x=103°[/tex]

PLS HELP please give an explanation if you don’t have one pls still give answer

Answers

I think a and b is the answer mate
The correct answers are Line A and Line B

Since you are looking for a -2 you start by finding the negative lines which narrows it down to A and B. The you check the rise over run of both lines and you should get -2/1 which simplifies to -2

(a) The heights of male students in a college are thought to be normally distributed with mean 170 cm and standard deviation 7.
The heights of 5 male students from this college are measured and the sample mean was 174 cm.
Determine, at 5% level of significance, whether there is evidence that the mean height of the male students of this college is higher than 170 cm.
[6]
(b) (i) The result of a fitness trial is a random variable X which is normally distributed with mean μ and standard deviation 2.4 . A researcher uses the results from a random sample of 90 trials to calculate a
98% confidence interval for μ . What is the width of this interval?
[4]
(ii) Packets of fish food have weights that are distributed with standard deviation 2.3 g. A random sample of 200 packets is taken. The mean weight of this sample is found to be 99.2 g. Calculate a 99% confidence interval for the population mean weight.
[4]
(c) (i) Explain the difference between a point estimate and an interval
Estimate. [2]
(ii) The daily takings, $ x, for a shop were noted on 30 randomly chosen days. The takings are summarized by Σ x=31 500 and
Σ x2=33 141 816 .
Calculate unbiased estimates of the population mean and variance of the shop’s daily taking. [4

Answers

Answer:

the answer is 50 but I don't know if

In a given region, the number of tornadoes in a one-week period is modeled by a Poisson distribution with mean 2. The numbers of tornadoes in different weeks are mutually independent. Calculate the probability that fewer than four tornadoes occur in a three-week period.

Answers

Answer:

0.1512 = 15.12% probability that fewer than four tornadoes occur in a three-week period.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

In which

x is the number of sucesses

e = 2.71828 is the Euler number

[tex]\mu[/tex] is the mean in the given interval.

In a given region, the number of tornadoes in a one-week period is modeled by a Poisson distribution with mean 2

Three weeks, so [tex]\mu = 2*3 = 6[/tex]

Calculate the probability that fewer than four tornadoes occur in a three-week period.

This is:

[tex]P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)[/tex]

In which

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

[tex]P(X = 0) = \frac{e^{-6}*6^{0}}{(0)!} = 0.0025[/tex]

[tex]P(X = 1) = \frac{e^{-6}*6^{1}}{(1)!} = 0.0149[/tex]

[tex]P(X = 2) = \frac{e^{-6}*6^{2}}{(2)!} = 0.0446[/tex]

[tex]P(X = 3) = \frac{e^{-6}*6^{3}}{(3)!} = 0.0892[/tex]

Then

[tex]P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0025 + 0.0149 + 0.0446 + 0.0892 = 0.1512[/tex]

0.1512 = 15.12% probability that fewer than four tornadoes occur in a three-week period.

a woman bought some large frames for 
$12 each and some small frames for $5
each. If she bought 20 frames for $156
find how many of each type she bought.

Answers

Answer:

8 pairs of large glasses and 12 pairs of small ones

Step-by-step explanation:

Let's say the number of large frames she buys is l, and the number of small frames is s. She buys 20 frames of assorted sizes, but they can only be small or large. Therefore, s + l = 20.

Next, the total cost of large frames is 12 dollars for each frame. Therefore, the total cost for the large frames is equal to 12 * l. Similarly, the total cost for the small frames is equal to 5 * s. The total cost of all frames is equal to 156, so

12* l + 5 * s = 156

s + l = 20

In the second equation, we can subtract l from both sides to get

s = 20 - l

We can then plug that into the first equation to get

12 * l + 5 * (20-l) = 156

12 * l + 100 - 5*l = 156

subtract both sides by 100 to isolate the variable and its coefficient

12 * l  -  5 * l = 56

7 * l = 56

divide both sides by 7 to isolate the l

l = 8

The woman buys 8 pairs of large glasses. The number of small glasses is equal to 20-l=20-8=12

You buy a six pack of Gatorade for $9.00. What is the unit price or the price per bottle?
$1.50/bottle
$2/bottle
$1.75 per bottle

Answers

Answer:

The answer is $1.50/bottle.

Step-by-step explanation:

To get the unit price, you need to divide the total by the amount of bottles.

[tex]9.00/6=1.50[/tex]

Translate the sentence into an inequality. The product of w and 2 is less than 23.​

Answers

Answer:

2w<23

Step-by-step explanation:

The product of w and 2 mean that w multiplied by 2

If 2(x + 3) - 27 = 3[7 - 2(x + 19)], what is 2x - 5?

Answers

Answer:

D = -23

Step-by-step explanation:

Answer:

D) -23

Step-by-step explanation:

Definitely

The cost of 5 gallons of ice cream has a variance of 64 with a mean of 34 dollars during the summer. What is the probability that the sample mean would differ from the true mean by less than 1.1 dollars if a sample of 38 5-gallon pails is randomly selected

Answers

Answer:

0.5587 = 55.87% probability that the sample mean would differ from the true mean by less than 1.1 dollars.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The cost of 5 gallons of ice cream has a variance of 64 with a mean of 34 dollars during the summer.

This means that [tex]\sigma = \sqrt{64} = 8, \mu = 34[/tex]

Sample of 38

This means that [tex]n = 38, s = \frac{8}{\sqrt{38}}[/tex]

What is the probability that the sample mean would differ from the true mean by less than 1.1 dollars ?

P-value of Z when X = 34 + 1.1 = 35.1 subtracted by the p-value of Z when X = 34 - 1.1 = 32.9. So

X = 35.1

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{35.1 - 34}{\frac{8}{\sqrt{38}}}[/tex]

[tex]Z = 0.77[/tex]

[tex]Z = 0.77[/tex] has a p-value of 0.77935

X = 32.9

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{32.9 - 34}{\frac{8}{\sqrt{38}}}[/tex]

[tex]Z = -0.77[/tex]

[tex]Z = -0.77[/tex] has a p-value of 0.22065

0.77935 - 0.22065 = 0.5587

0.5587 = 55.87% probability that the sample mean would differ from the true mean by less than 1.1 dollars.

Pls help this is rlly important!! You’ll get branliest bc this is hard and I’m stuck.

Answers

the median of restaurant b's cleanliness ratings is 2.

the median of restaurant b's food quality ratings is 4.

the median of restaurant b's service ratings is 3.

:))

Consider this linear function:
y = 1/2x + 1
Plot all ordered pairs for the values in the domain.
D: {-8, -4,0, 2, 6)

Answers

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

The attachment shows the ordered pairs (x, f(x)) and their graph.

A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between 47.0 and 57.0 minutes. Find the probability that a given class period runs between 51.25 and 51.5 minutes.

Answers

Answer:

0.025 = 2.5% probability that a given class period runs between 51.25 and 51.5 minutes.

Step-by-step explanation:

Uniform probability distribution:

An uniform distribution has two bounds, a and b.

The probability of finding a value between c and d is:

[tex]P(c \leq X \leq d) = \frac{d - c}{b - a}[/tex]

Uniformly distributed between 47.0 and 57.0 minutes.

This means that [tex]a = 47, b = 57[/tex]

Find the probability that a given class period runs between 51.25 and 51.5 minutes.

[tex]P(c \leq X \leq d) = \frac{51.5 - 51.25}{57 - 47} = 0.025[/tex]

0.025 = 2.5% probability that a given class period runs between 51.25 and 51.5 minutes.

answer quick it's urgent

Expand : (5xy+7)(5xy-7)

Answers

Answer:

[tex](5xy + 7)(5xy-7) = 25x^2 y^2 - 49[/tex]

Step-by-step explanation:

[tex](a - b)(a +b ) = a^2 - b^2 \\\\From \ given \ expression \ a = 5xy \ , \ b = 7\\\\Therefore , (5xy + 7 )(5xy - 7 ) = ( 5xy)^2 - ( 7)^2 \\[/tex]

                                             [tex]= 25x^2 y^2 - 49[/tex]

Answer:

25x²y² - 49

Step-by-step explanation:

We can do this by using the a+b formula:

(a+b)(a-b)= a² - b²

So,

(5xy+7)(5xy-7)

=(5xy)² - 7²

= 25x²y² - 49

Another way we can do this by expanding the algebraic expression:

(5xy+7)(5xy-7)

= 5xy(5xy-7) + 7(5xy-7)

= 25x²y² - 35xy + 35xy - 49

= 25x²y²- 49

Find the slope of the line that passes through the two points 2,-4 & 4,-1

Answers

Answer:

Step-by-step explanation:

I have this saved on my computer in notepad b/c this type of question get asked sooo often :/

point P1 (-4,-2)  in the form (x1,y1)

point P2(3,1)  in the form (x2,y2)

slope = m

m = (y2-y1) / (x2-x1)

My suggestion is copy that above and save it on your computer for questions like this

now use it

Point 1  , P1 = (2,-4)   in the form (x1,y1)

Point 2 , P2 = (4,-1)  in the form (x2,y2)

m = [ -1-(-4) ]  /  [ 4-2]

m =  (-1+4) / 2

m = 3 / 2

so now we know the slope is  3/2  :)  

Calculate the pH of a buffer solution made by mixing 300 mL of 0.2 M acetic acid, CH3COOH, and 200 mL of 0.3 M of its salt sodium acetate, CH3COONa, to make 500 mL of solution. Ka for CH3COOH = 1.76×10–5

Answers

Answer:

Approximately [tex]4.75[/tex].

Step-by-step explanation:

Remark: this approach make use of the fact that in the original solution, the concentration of  [tex]\rm CH_3COOH[/tex] and [tex]\rm CH_3COO^{-}[/tex] are equal.

[tex]{\rm CH_3COOH} \rightleftharpoons {\rm CH_3COO^{-}} + {\rm H^{+}}[/tex]

Since [tex]\rm CH_3COONa[/tex] is a salt soluble in water. Once in water, it would readily ionize to give [tex]\rm CH_3COO^{-}[/tex] and [tex]\rm Na^{+}[/tex] ions.

Assume that the [tex]\rm CH_3COOH[/tex] and [tex]\rm CH_3COO^{-}[/tex] ions in this solution did not disintegrate at all. The solution would contain:

[tex]0.3\; \rm L \times 0.2\; \rm mol \cdot L^{-1} = 0.06\; \rm mol[/tex] of [tex]\rm CH_3COOH[/tex], and

[tex]0.06\; \rm mol[/tex] of [tex]\rm CH_3COO^{-}[/tex] from [tex]0.2\; \rm L \times 0.3\; \rm mol \cdot L^{-1} = 0.06\; \rm mol[/tex] of [tex]\rm CH_3COONa[/tex].

Accordingly, the concentration of [tex]\rm CH_3COOH[/tex] and [tex]\rm CH_3COO^{-}[/tex] would be:

[tex]\begin{aligned} & c({\rm CH_3COOH}) \\ &= \frac{n({\rm CH_3COOH})}{V} \\ &= \frac{0.06\; \rm mol}{0.5\; \rm L} = 0.12\; \rm mol \cdot L^{-1} \end{aligned}[/tex].

[tex]\begin{aligned} & c({\rm CH_3COO^{-}}) \\ &= \frac{n({\rm CH_3COO^{-}})}{V} \\ &= \frac{0.06\; \rm mol}{0.5\; \rm L} = 0.12\; \rm mol \cdot L^{-1} \end{aligned}[/tex].

In other words, in this buffer solution, the initial concentration of the weak acid [tex]\rm CH_3COOH[/tex] is the same as that of its conjugate base, [tex]\rm CH_3COO^{-}[/tex].

Hence, once in equilibrium, the [tex]\rm pH[/tex] of this buffer solution would be the same as the [tex]{\rm pK}_{a}[/tex] of [tex]\rm CH_3COOH[/tex].

Calculate the [tex]{\rm pK}_{a}[/tex] of [tex]\rm CH_3COOH[/tex] from its [tex]{\rm K}_{a}[/tex]:

[tex]\begin{aligned} & {\rm pH}(\text{solution}) \\ &= {\rm pK}_{a} \\ &= -\log_{10}({\rm K}_{a}) \\ &= -\log_{10} (1.76 \times 10^{-5}) \\ &\approx 4.75\end{aligned}[/tex].

help? haha
solve the equation below:)
3x - 5 = 10 + 2x

Answers

Step-by-step explanation:

3x-2x=5+10 [taking variables on one side and constant on other]

x=15

soln:

3x-5= 2x+10

3x -5+5=2x+10+5 [ adding 5 on both side]

3x=2x+15

3x-2x=2x+15-2x [subtracting 2x on both side]

x=15

Ans=15

Answer:

[tex]x = 15[/tex]

Step-by-step explanation:

[tex]3x - 5 = 10 + 2x[/tex]

[tex]3x - 2x = 10 + 5[/tex]

[tex]1x = 15[/tex]

[tex]x = 15[/tex]

Hope it is helpful.....

using the 1 to 9 at the most time each, fill in the boxes to make a true statement

Answers

Answer:

2

Step-by-step explanation:

8*8 is 64

Since it looks like the empty box is an exponent, and there are 2 8s being multiplied, the answer is 2

Other Questions
Fre point[tex] \: \: \: \: \: \: [/tex] Which of the following are stages in the life cycle of a mosquito?tap the photo Prior to recording adjusting entries, the Office Supplies account had a $490 debit balance. A physical count of the supplies showed $175 of unused supplies available. The required adjusting entry is: debit/credit [ Select ] to [ Select ] account for [ Select ] debit/credit [ Select ] to [ Select ] account for [ Select ] Life, Inc. experienced the following events in Year 1, its first year of operation: Performed counseling services for $22,000 cash. On February 1, Year 1, paid $15,000 cash to rent office space for the coming year. Adjusted the accounts to reflect the amount of rent used during the year.RequiredBased on this information alone:a. Record the events under an accounting equation.TABLE PROVIDED BELOWa.Life, Inc.Effect of Events on the Accounting Equation Assets = Stockholders EquityEventCashPrepaid Rent =Retained Earnings1. Performed Services 36,000 36,0002. Prepaid Rent (18,000) 18,000 NA3. Used Rent (18,000) (18,000) Totals 18,000 0 = 18,000b. Prepare an income statement, balance sheet, and statement of cash flows for the 2016 accounting period.Life, Inc.Income StatementFor the Year Ended December 31, 2016 Revenue 36,000 Expense 18,000 Net Income 18,000 list few points on the importance of sun in power supply. Team Dramoine or Team Drarry? Dramoine= Draco and Hermoine, Drarry= Draco and Harry Why do only certain cells respond to particular signaling molecules that are sent throughout the body PLEASE HELP!!!Verify sin(180- ) = sin SHOW WORK!!! Help and explain !!!!!!!!!!!!! The tools shown in the diagram are used for gardening Each tool is made upof two levers that are attached to each other. The handles are the input arms,and the cutting blades are the output armoHand shearsLopperWhich tool has a greater mechanical advantage, and why?A. The lopper, because the input work is the same as the output workB. The hand shears, because their shorter handles transfer forcemore quickly to the cutting bladeC. The hand shears, because you can apply less total force to thehandles with one handD. The lopper, because its longer handles can produce more outputforce with less input force simplify 3xy + x 2 - 4xy + 2xupper2y The amount of potential energy, P, an object has is equal to the product of its mass, m, its height off the ground, h, and the gravitational constant, g. This can be modeled by the equation P = mgh.What is the equivalent equation solved for h?StartFraction StartFraction p Over m EndFraction Over g EndFraction equals h. = hStartFraction p Over m g EndFraction equals h.= hPmg = hStartFraction p Over StartFraction m Over p EndFraction EndFraction equals h. = h During a basketball practice, Steph Curry made 234 three point shots in 45 minutes,In the same practice, his teammate Klay Thompson made 168 three point shots in 34 minutes.1) Find the unit rates of both players of shots made per each minute2) Which player was making more shots at a higher rate?I needsdd helppppp pleaseeeee The function f(x) is shown below.-6-3f(x)1253Coon0If g(x) is the inverse of f(x), what is the value of f(g(2))?-65 Two functions, A and B, are described as follows: Function A y = 9x + 4 Function B The rate of change is 3 and the y-intercept is 4. How much more is the rate of change of function A than the rate of change of function B? 2369 Required: Monson sells 15 units for $20 each on December 15. Assume the periodic inventory system is used. Determine the costs assigned to ending inventory when costs are assigned based on the weighted average method. (Amounts to be deducted should be indicated with a minus sign. Round cost per units to 2 decimals.) How do I find the area for this shape The concept of professionalism includes the following values EXCEPTA commitment communication and AltruismB commitment life long learning and altruism C Commitment accountability and altruismD commitment community and altruismE commitment accountability and dignity What is the 7th term in the sequence below? 5, 25, 125, 625, A. 78,125 B. 15,625 C. 3,125 D. 825 Here are two steps from the derivation of the quadratic formula.What took place between the first step and the second step?