This is my question:

Answer:

i have no idea that's why I need ur help

Answer:

8

Step-by-step explanation:

6x+5=53

6x=48

6x/6=48/6

x=8

48..................

Answer:

10 inches

Step-by-step explanation:

radius = 5 inches

Diameter = radius x 2 = 5 x 2 = 10 inches

Answer:

63

Step-by-step explanation:

6x + 3y - 9

x = 6

y = 9

6(6) + 3(9)

36 + 27

= 63

[tex]\\ \rm\Rrightarrow 11+7x=-17[/tex]

[tex]\\ \rm\Rrightarrow 7x=-7-11[/tex]

[tex]\\ \rm\Rrightarrow 7x=-28[/tex]

[tex]\\ \rm\Rrightarrow x=\dfrac{-28}{7}[/tex]

[tex]\\ \rm\Rrightarrow x=-4[/tex]

Answer: x = -4

Step-by-step explanation:

Given equation

11 + 7x = -17

Subtract 11 on both sides

11 + 7x - 11 = -17 - 11

7x = -28

Divide 7 on both sides

7x / 7 = -28 / 7

[tex]\boxed{x=-4}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Answer:

Im not certain but I think 7.5% If you get another answer which is different trust them not me if u get one which is the same it should be correct

The interest rate was 7.5% when borrowing $600 for one year and paying $45.00 interest.

Simple interest is defined as interest paid on the original principal and calculated with the following formula:

S.I. = P × R × T, where P = Principal, R = Rate of Interest in % per annum, and T = Time, usually calculated as the number of years. The rate of interest is in percentage r% and is to be written as r/100.

We have been given data as:

Principal (P) = $600

Time (T) = 1 year

Simple interest = $45.00

⇒ Simple interest = P × R × T

Substitute the value of P, and T in the above formula, and solve for R

⇒ 45.00 = 600 × R × 1

⇒ 45.00 = 600R

⇒ R = 45.00/600

⇒ R = 0.075

⇒ R = 7.5/100

⇒ R = 7.5%

Therefore, the interest rate was 7.5%.

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Answer:

Step-by-step explanation:

x-intercept(s):  

( − 4 , 0 ) , ( 6 , 0 )

y-intercept(s):  

( 0 , − 24 )

Answer:1 and 2

Step-by-step explanation:right on edge

Answer:

[tex]2(a + 1) \times (3a + 5)[/tex]

Step-by-step explanation:

[tex]6(a + 1 {)}^{2} + 4(a + 1)[/tex]

➡️ [tex]2(a + 1) \times (3(a + 1) + 2)[/tex]

➡️ [tex]2(a + 1) \times (3a + 3 + 2)[/tex]

➡️ [tex]2(a + 1) \times (3a + 5)[/tex]

Answer:

[tex]tan(\theta)=\frac{\sqrt{21}}{3}[/tex]

Step-by-step explanation:

1. Approach

One is given the following information:

[tex]cos(2\theta)=-\frac{2}{5}[/tex]

One can rewrite this as:

[tex]cos(2\theta)=-0.4[/tex]

Also note, the problem says that the angle ([tex]2\theta[/tex]) is found in the third quadrant.

Using the trigonometric identities ([tex]cos(2\theta)=2(cos^2(\theta))-1[/tex]) and ([tex]cos(2\theta)=1-2(sin^2(\theta))[/tex]) one can solve for the values of ([tex]cos(\theta)[/tex]) and ([tex]sin(\theta)[/tex]). After doing so one can use another trigonometric identity ([tex]tan(\theta)=\frac{sin(\theta)}{cos(\theta)}[/tex]).  Substitute the given information into the ratio and simplify.

2. Solve for [tex](cos(\theta))[/tex]

Use the following identity to solve for ([tex]cos(\theta)[/tex]) when given the value ([tex]cos(2\theta)[/tex]).

[tex]cos(2\theta)=2(cos^2(\theta))-1[/tex]

Substitute the given information in and solve for ([tex]cos(\theta)[/tex]).

[tex]cos(2\theta)=2(cos^2(\theta))-1[/tex]

[tex]-0.4=2(cos^2(\theta))-1[/tex]

Inverse operations,

[tex]-0.4=2(cos^2(\theta))-1[/tex]

[tex]0.6=2(cos^2(\theta))[/tex]

[tex]0.3=cos^2(\theta)[/tex]

[tex]\sqrt{0.3}=cos(\theta)[/tex]

Since this angle is found in the third quadrant its value is actually:

[tex]cos(\theta)=-\sqrt{0.3}[/tex]

3. Solve for [tex](sin(\theta))[/tex]

Use the other identity to solve for the value of ([tex]sin(\theta)[/tex]) when given the value of ([tex]cos(2\theta)[/tex]).

[tex]cos(2\theta)=1-2(sin^2(\theta))[/tex]

Substitute the given information in and solve for ([tex]sin(\theta)[/tex]).

[tex]cos(2\theta)=1-2(sin^2(\theta))[/tex]

[tex]-0.4=1-2(sin^2(\theta))[/tex]

Inverse operations,

[tex]-0.4=1-2(sin^2(\theta))[/tex]

[tex]-1.4=-2(sin^2(\theta))[/tex]

[tex]0.7=sin^2(\theta)[/tex]

[tex]\sqrt{0.7}=sin(\theta)[/tex]

Since this angle is found in the third quadrant, its value is actually:

[tex]sin(\theta)=-\sqrt{0.7}[/tex]

4. Solve for [tex](tan(\theta))[/tex]

One can use the following identity to solve for [tex](tan(\theta))[/tex];

[tex]tan(\theta)=\frac{sin(\theta)}{cos(\theta)}[/tex]

Substitute the values on just solved for and simplify,

[tex]tan(\theta)=\frac{sin(\theta)}{cos(\theta)}[/tex]

[tex]tan(\theta)=\frac{-\sqrt{0.7}}{-\sqrt{0.3}}[/tex]

[tex]tan(\theta)=\frac{\sqrt{0.7}}{\sqrt{0.3}}[/tex]

[tex]tan(\theta)=\frac{\sqrt{\frac{7}{10}}}{\sqrt{\frac{3}{10}}}[/tex]

Rationalize the denominator,

[tex]tan(\theta)=\frac{\sqrt{\frac{7}{10}}}{\sqrt{\frac{3}{10}}}[/tex]

[tex]tan(\theta)=\frac{\sqrt{\frac{7}{10}}}{\sqrt{\frac{3}{10}}}*\frac{\sqrt{\frac{3}{`0}}}{\sqrt{\frac{3}{10}}}[/tex]

[tex]tan(\theta)=\frac{\sqrt{\frac{7}{10}*\frac{3}{10}}}{\sqrt{\frac{3}{10}*\frac{3}{10}}}[/tex]

[tex]tan(\theta)=\frac{\sqrt{\frac{21}{100}}}{\frac{3}{10}}[/tex]

[tex]tan(\theta)=\frac{\frac{\sqrt{21}}{10}}{\frac{3}{10}}[/tex]

[tex]tan(\theta)=\frac{\sqrt{21}}{10}*\frac{10}{3}[/tex]

[tex]tan(\theta)=\frac{\sqrt{21}}{3}[/tex]

Answer:

The united nations flag the translation can be any of the blue triangles and the reflection if the flag itself as it is symmetrical

Step-by-step explanation:

The united nations flag the translation can be any of blue triangles and the reflection if the flag itself as it is symmetrical.

When a graph is reflected along an axis, say x axis, then that leads the graph to go just in opposite side of the axis as if we're seeing it in a mirror.

If we study it more, you will find that its symmetric, thus each point is equidistant from the axis of reflection as that of the image of that point.

If you're reflecting a point (x,y) along x axis, then its abscissa will stay same but ordinates will negate. Thus (x,y) turns to (x, -y)

Similarly, if you're reflecting a point (x,y) along y axis, the resultant image of the point will be (-x,y)

Therefore, The united nations flag the translation can be any of blue triangles and the reflection if the flag itself as it is symmetrical.

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Answer:

2400

which is not having any remainder as 2400÷60=40

Step-by-step explanation:

I believe this is the expression:

[tex] \displaystyle \large \boxed{ - 8 {y}^{2} }[/tex]

Since we want to evaluate it when y = -2, simply substitute y = -2 in the expression.

[tex] \displaystyle \large{ - 8 {( - 2)}^{2} }[/tex]

Any negative number squared will result in positive, refer below:

[tex] \displaystyle \large{ {( - a)}^{2} = {a}^{2} } \\ \displaystyle \large{ {( - 2)}^{2} = {2}^{2} } \longrightarrow \boxed{4} \\ [/tex]

Hence,

[tex] \displaystyle \large{ - 8(4) = - 8 \times 4} \\ \displaystyle \large \boxed{ -32}[/tex]

Answer:

-32

Step-by-step explanation:

Replace the variable y with -2 in the expression giving -8(-2)^2

Then, square -2 giving us (positive) 4

Lastly, multiply -8 with 4 and get -32 as our answer

(Hopefully this helped you! Feel free to ask again if you need more help. Tell me if the solution is unclear to you)

Answer:

hahaaaaaaaaaaaaaaaaa

Step-by-step explanation:

Answer:

IF the signs ARE same the result is a POSITIVE, if the signs are NOT the same the result is NEGATIVE

Step-by-step explanation:

Answer:

5(x+4)

Step-by-step explanation:

It's basically asking for the sum of a number and four to be multiplied by 5. Since the sum is made up of the unknown number and four, you'd put four and the unknown number in parenthesis while putting five on the outside, making it 5(x+4).

Answer:

y = 1/3mx + b

Step-by-step explanation:

x = 3(y - b)/m

~Multiply m to both sides

mx = -3b + 3y

~Add 3b to both sides

mx + 3b = 3y

~Divide everything by 3

1/3mx + b = y

y = 1/3mx + b

Best of Luck!

[tex]\\ \rm\longmapsto x=\dfrac{3(y-b)}{m}[/tex]

[tex]\\ \rm\longmapsto mx=3(y-b)[/tex]

[tex]\\ \rm\longmapsto mx=3y-3b[/tex]

[tex]\\ \rm\longmapsto 3y=mx+3b[/tex]

[tex]\\ \rm\longmapsto y=\dfrac{1}{3}mx+b[/tex]

Answer:

17/30 (0.56)

Step-by-step explanation:

18/20-4/12

Reduce the fraction with 2 and 4: 9/10-1/3

Write all numerators above the least commmon denominator 30: 27-10/30

Subtract: 27-10/30 = 17/30

Answer:

[tex]\frac{(a+b)}{a^{2} -b^{2} }[/tex] + [tex]\frac{(a-b)}{a^{2} -b^{2} }[/tex] = [tex]\frac{2a}{a^{2} -b^{2} }[/tex]

Step-by-step explanation:

Step-by-step explanation:

[tex] \frac{ \sqrt{a + b} }{ \sqrt{a - b} } + \frac{ \sqrt{a - b} }{ \sqrt{a + b} } \\ squaring \: on \: both \: sides \\ \frac{a + b}{a - b} + \frac{a - b}{a + b} \\ \frac{(a + b) \times (a + b) + (a - b)(a - b)}{(a - b)(a + b)} \\ \frac{ {(a + b)}^{2} + {(a - b)}^{2} }{ {a}^{2} - {b}^{2} } \\ remaining \: in \: attachment[/tex]

[tex]thank \: you[/tex]

Answer:

This will plot as an upward  "V" with the vertex at x = 4/3, y = 5

Step-by-step explanation:

The absolute value will mean that y can only be positive. y will be at a minimin when the absolute value is zero. To determine that find the x that makes it zero, so

-3x + 4 = 0

-3x = -4

x = 4/3

which makes y = 5 (the minimin)

Answer:

$17.25

Step-by-step explanation:

The tip is 15% of $15.00, or 0.15 * 15 = $2.25

We add that to the meal's cost, which is $15.00

15.00 + 2.25 = 17.25

Answer:

semoga jawapan ini dapat membantu

Answer:

153*10^3

Step-by-step explanation:

I assumed the first exponential number as 1

[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\boxed{\mathsf{(3.4 \times 10^4)(4.5 \times 10^3)}}\\\huge\boxed{\mathsf{\rightarrow 3.4\times10^4 \times 4.5 \times 10^3}}[/tex]

[tex]\huge\boxed{\mathsf{10^4}}\\\huge\boxed{= 10\times10\times10\times10}\\\huge\boxed{= 100\times100}\\\huge\boxed{= 10,000}\\\\\\\huge\boxed{\mathsf{10^3}}\\\huge\boxed{=10\times10\times10}\\\huge\boxed{= 100\times10}\\\huge\boxed{= 1,000}[/tex]

[tex]\huge\boxed{\rightarrow\mathsf{3.4\times \bold{10,000} \times 4.5 \times \bold{1,000}}}}[/tex]

[tex]\huge\boxed{\mathsf{3.4\times10,000}}\\\huge\boxed{= 34,000}\\\\\\\huge\boxed{\mathsf{4.5\times1,000}}\\\huge\boxed{{= 4,500}}}[/tex]

[tex]\huge\boxed{\mathsf{\rightarrow\bf 34,000\times4,500}}\\\huge\boxed{\rightarrow\mathsf{ORIGINAL \ ANSWER: \frak {153,000,000}}}}[/tex]

[tex]\huge\boxed{\textsf{Your answer: }\mathsf{153\times10^6}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\huge\boxed{\frak{Amphitrite1040:)}}[/tex]

Answer:

purple.orang.blue.yellow and green

purple.orang.blue.yellow and green

Answer:

43.4 yd

Step-by-step explanation:

[tex]45^{2}[/tex]-[tex]12^{2}[/tex]

2025-144=1881

[tex]\sqrt{1881}[/tex]

43.37049

43.4

Answer:

hope it helps, appreciate if you can give brainliests

Answer:

Below,...

Step-by-step explanation:

Your equation:

[tex]\frac{63}{7-(2*3)} =\frac{63}{7-6} =\frac{63}{1}=63[/tex]

Hope it helps,... Chow,...!

AB = AD [Given]

BC = CD [Given]

AC = AC [Same line segment]

So, ΔABC ≅ ΔADC [By SSS congruence criteria]

So, ∠ABC = ∠ADC [CPCT (Corresponding parts of congruent triangles)]

Hence, proved.

Answer:

I hope it will help U.

Answer:

After 5 seconds

Step-by-step explanation:

One is given the following expression to model to the flight path of a ball:

[tex]h=-16t^2+80t[/tex]

In this problem, one is asked to find the time at which the ball lands on the ground. The easiest way to do so is to factor the expression. Take out factors that both terms have in common. The one will set the equation equal to zero, as this is the height at which one wants to find the time for. Finally, use the zero product property to solve. The zero product property states that any number times zero equals zero. Apply these ideas to the given function:

[tex]h=-16t^2+80t[/tex]

Factor the expression; both terms have a common factor of (-16t):

[tex]h=-16t^2+80t[/tex]

[tex]h=-16t(t-5)[/tex]

Set the equation equal to zero to solve for when the ball has a height of zero or rather lands on the ground:

[tex]h=-16t(t-5)[/tex]

[tex]0=-16t(t-5)[/tex]

Now use the zero product property, this states that any number times zero equals zero. Set each of the factors equal to zero, and solve to find the value of (t) for which the factor will equal zero:

[tex]0=-16t(t-5)[/tex]

[tex]0=-16t[/tex]                          [tex]t - 5 =0[/tex]

Solve for the value (t) using inverse operations,

[tex]0=-16t[/tex]                            [tex]t - 5 =0[/tex]

(divide by (-16)                   (add (5))

[tex]0=t[/tex]                                     [tex]t=5[/tex]

As one can see, the ball started on the ground, therefore at (0) seconds, its height was (0). Then, after (5) seconds the ball landed on the ground, therefore, after (5) seconds its height was again (0).