There are 3 boxes of coins. There are 4 times as many coins in Box A as in Box B. There are 180 fewer coins in Box C than Box A. The number 2 of coins in Box B is of the total number of coins in the three boxes. 13 What is the total number of coins in the three boxes?​

Answers

Answer 1

Answer:

Step-by-step explanation:

The answer b


Related Questions

f(x,y)=x10-3xy2then fz=

A. 10 x9 - 3y2
B. 20 x9 - 3y2
C. 2y2
D. 10x10 + xy2
which option is correct please

Answers

Given:

The function is:

[tex]f(x,y)=x^{10}-3xy^2[/tex]

To find:

The value of [tex]f_x[/tex].

Solution:

We need to find the value of [tex]f_x[/tex]. So, we have to find the first order partial derivative of the given function with respect to x.

We have,

[tex]f(x,y)=x^{10}-3xy^2[/tex]

Differentiate partially with respect to x.

[tex]f(x,y)=\dfrac{\partial}{\partial x}x^{10}-3y^2\dfrac{\partial}{\partial x}x[/tex]

[tex]f_x=10x^{10-1}-3y^2(1)[/tex]

[tex]f_x=10x^{9}-3y^2[/tex]

Therefore, the correct option is A.

When Claire chooses a piece of fruit from a fruit bowl, there is a 22% chance that it will be a plum, an 18%
chance that it will be an orange, and a 60% chance that it will be an apple. Which type of fruit is she least likely
to choose?

Answers

Answer:

Orange

Step-by-step explanation:

As the chance of choosing orange is 18% which is the least.


Domain and range

O Function
O Not a function

Answers

Answer:

Radiation 1- Function

Radiation 2- Not a function

Radiation 3- function

Radiation 4- function

Answer:

1 - Function  

2 - Not a function

3 - function

4 - function

Step-by-step explanation:

The Sureset Concrete Company produces concrete. Two ingredients in concrete are sand (costs $6 per ton) and gravel (costs $8 per ton). Sand and gravel together must make up exactly 75% of the weight of the concrete. Also, no more than 40% of the concrete can be sand and at least 30% of the concrete be gravel. Each day 2000 tons of concrete are produced. To minimize costs, how many tons of gravel and sand should be purchased each day

Answers

Answer:

The Sureset Concrete Company

The tons of gravel and sand that should be purchased each day are:

Sand = 800 tons

Gravel = 700 tons

Step-by-step explanation:

Two ingredients for producing concrete = sand and gravel

Cost of sand per ton = $6

Cost of gravel per ton = $8

Sand and gravel = 75% of the concrete

Therefore 25% (100 - 75%) will be made up of cement and water

Tons of concrete produced each day = 2,000

Sand and gravel = 1,500 (2,000 * 75%)

Sand <= 40% of 2,000 = 800 tons

Gravel => 30% of 2,000 = 700 (1,500 - 800) tons

To minimize costs,  800 tons of gravel and 700 tons of sand should be purchased each day.

Total cost incurred daily for both sand and gravel = $10,400 (800 * $6 + 700 * $8)

The number of runners in the London Marathon on 25th April, 2010 was 37 527.

Work out an estimate for the number of these runners whose birthday was on that day.

Answers

Answer:

Hi 34

Step-by-step explanation:

Hi

Work out the area of the shape,show working out
help me and I think I did the sides wrong

Answers

25 x 10 = 250
11 x 6 = 66
250 - 66 = 184 cm

determine lcm and HCF of 24 and 26 using prime factors​

Answers

Answer:

WHAT IS THE FACTOR?

Step-by-step explanation:

At a bake sale, pies cost $8 each. One customer buys $64 worth of pies.

Answers

The customer bought 8 pies.

To find the total amount of pies the customer bought, simply divide 64 by 8 to recieve your answer of 8 pies.

I hope this is correct and helps!

Eight pies would be the answer

HELP PLEASE!!! So for this problem is got 0.48 however I just wanted to confirm that my answer is correct. Can someone please help me if the answer is wrong and how to solve it. Thank your for your time

Answers

Answer:

ur answer is correct

A =xy

A = 1.6×0.3 = 0.48

If f(x) = 4^x-8 and g(x) = 5x+6, find (f + g)(x)
A. (F+g)(x) = -4^x - 5x + 2
B.(F+g)(x) = 4^x + 5x - 2
C.(F+g)(x) = 4^x - 3x + 6
D.(F+g)(x) = 9x - 2

Answers

Hey there!

We are given two functions - one is Exponential while the another one is Linear.

[tex] \large{ \begin{cases} f(x) = {4}^{x} - 8 \\ g(x) = 5x + 6 \end{cases}}[/tex]

1. Operation of Function

(f+g)(x) is a factored form of f(x)+g(x). We can common factor out x. Therefore:

[tex] \large{(f + g)(x) = f(x) + g(x)}[/tex]

2. Substitution

Next, we substitute f(x) = 4^x+8 and g(x) = 5x+6.

[tex] \large{(f + g)(x) = ( {4}^{x} - 8) + (5x + 6)}[/tex]

3. Evaluate/Simplify

Cancel out the brackets and combine like terms.

[tex] \large{(f + g)(x) = {4}^{x} - 8 + 5x + 6} \\ \large{(f + g)(x) = {4}^{x} + 5x - 8 + 6} \\ \large{(f + g)(x) = {4}^{x} + 5x - 2}[/tex]

4. Final Answer

(f+g)(x) = 4^x+5x-2

Please help, I’m running out of time. Please.

Answers

Answer:

which standard questions is it

Help and explain explain !!!!!!!!!!

Answers

Answer:

[tex]x=-1\text{ or }x=11[/tex]

Step-by-step explanation:

For [tex]a=|b|[/tex], we have two cases:

[tex]\begin{cases}a=b,\\a=-b\end{cases}[/tex]

Therefore, for [tex]18=|15-3x|[/tex], we have the following cases:

[tex]\begin{cases}18=15-3x,\\18=-(15-3x)\end{cases}[/tex]

Solving, we have:

[tex]\begin{cases}18=15-3x, -3x=3, x=\boxed{-1},\\18=-(15-3x), 18=-15+3x, 33=3x, x=\boxed{11}\end{cases}[/tex].

Therefore,

[tex]\implies \boxed{x=-1\text{ or }x=11}[/tex]

How high up the wall can a 12-foot ladder reach if its base is 4 feet from the wall? Round your answer to the nearest tenth of a foot if necessary.

Answers

Answer: 24 ft I think

Step-by-step explanation:

every student from different schools planted as many plants of their number if they planted 4225 plants how many students were there

Answers

Answer:

65 students.

Step-by-step explanation:

Given that :

Every student planted as many plant as their number ;

Then let the number of student = x

Then the number of plant planted by each student will also = x

The total number of plants planted by all the students = 4225

The Number of students can be obtained thus ;

Total number of plants = Number of plants * number of plants per student

4225 = x * x

4225 = x²

√4225 = x

65 = x

Hence, there are 65 students

A loan of £1000 has a compound interest rate of 2.7% charged monthly. Express the original loan as a percentage of the total amount awed after 2 months if no payment are made

Answers

Answer:

£1054.729

Step-by-step explanation:

To find compound interest you need to use the equation 1000(1.027)^x.

To find the interest rate (1.027):

100 + 2.7 = 102.7

102.7 / 100 = 1.027

The value of x is the amount of months if no payment is made in this situation, so 2 would be the x value for this problem.

Hope this helps!  

1 cm = 5km scale ratio

Answers

Answer: Definition: Ratio of the size of the map to its subject: Scale ... so scale = 1 cm / 100,000 cm = 1/100,000. - Scale ... STEP 1: - 2 cm represents 5 km

Step-by-step explanation:

STEP 1: - 2 cm represents 5 km - (write in full)

- STEP 2: - 1 cm represents 2.5 km - (divide so left side = 1)

- STEP 3: - 1 cm represents 250,000 cm - (convert to same units)

- STEP 4: - scale is 1 : 250,000 - (express as a representative fraction)

y.y3 write without exponts

Answers

Answer:

Y x Y x Y x Y

Step-by-step explanation:

The exponent tells how many times that number is multiplied.

So, x^3 is the same as multiplying x 3 times.

A family has 5 children. Compute the probabilities of the following events:
All five are born on Friday.
Each one is born on a different day of the week.

Answers

I think the answer is 10% and 90%

Answer:

1/16,807 chance that they all will be born on Friday

Probably 5/7, but don't take my word for it.

Step-by-step explanation:

There are 7 days of the week.

There is a 1/7 chance for one kid to be born on a certain day of the week.

We can attach an exponent of 5 since the 1/7 is a constant, and I'm not going to bother typing the same thing over and over again.

(1/7)^5 = 1/16,807.

The probability of all of them being born on Friday or anyday is 1/16,807.

The probability of each person being born on a different day of the week is  probabily going to be 5/7, but it could be different, because you need to factor in the requirement that they are not born on the same day.

I can guarantee that the first question is probably correct, but not the second.

The following data were collected from a simple random sample from an infinite population.
13 15 14 16 12
The point estimate of the population standard deviation is _____.
a. 1.581
b. 2.500
c. 2.000
d. 1.414

Answers

Answer:

1.581

Step-by-step explanation:

Given the data:

13 15 14 16 12

The point estimate of the standard deviation will be :

√Σ(x - mean)²/n-1

Mean = Σx / n = 70 / 5 = 14

√[(13 - 14)² + (15 - 14)² + (14 - 14)² + (16 - 14)² + (12 - 14)² / (5 - 1)]

The point estimate of standard deviation is :

1.581

One number is 2/3 of another number. The sum of the two numbers is 40. Find
the two numbers.

Answers

Answer:

5353454

Step-by-step explanation:

Answer: 16 and 24

Step-by-step explanation:

2x+3x= 40

5x = 40

x=8

that means 2x8 equal 16 and 3x8 equals 24 which leads us to the answer

Which of the following is a secant on the circle below?
Н
G
13-
125
K
o
A.
B. JK
C. HG
D. K

Answers

Answer:

D. KI

Step-by-step explanation:

KI intersects a minimum of two points meaning it is the definition of a secant.

The sum of the first ten terms of an arithmetic progression consisting of

positive integer terms is equal to the sum of the 20th, 21st and 22nd term.

If the first term is less than 20, find how many terms are required to give

a sum of 960.

Answers

Answer: [tex]n=13[/tex]

Step-by-step explanation:

Given

Sum of the first 10 terms is equal to sum of 20, 21, and 22 term

[tex]\Rightarrow \dfrac{10}{2}[2a+(10-1)d]=[a+19d]+[a+20d]+[a+21d]\\\\\Rightarrow 5[2a+9d]=3a+60d\\\Rightarrow 10a+45d=3a+60d\\\Rightarrow 7a=15d[/tex]

No of terms to give a sum of 960

[tex]\Rightarrow 960=\dfrac{n}{2}[2a+(n-1)d]\\\\\Rightarrow 1920=n[2a+(n-1)\cdot \dfrac{7}{15}a]\\\\\Rightarrow 28,800=n[30a+7a(n-1)]\\\\\Rightarrow a=\dfrac{28,800}{n[30+7n-7]}\\\\\Rightarrow a=\dfrac{28,800}{n[23+7n]}[/tex]

Value of first term is less than 20

[tex]\therefore \dfrac{28,800}{n[23+7n]}<20\\\\\Rightarrow 28,800<20n[23+7n]\\\Rightarrow 0<460n+140n^2-28,800\\\Rightarrow 140n^2+460n-28,800>0\\\\\Rightarrow n>12.79\\\\\text{For integer value }\\\Rightarrow n=13[/tex]

Answer:

15

Step-by-step explanation:

In the previous answer halfway through they used the equation: 960 = (n÷2)×(2a+(n-1)×(7a÷15))

Using this equation we can substitute an number to replace n, the higher the number is the smaller a would be.

When we substitute 15 into a, then it leaves us with the answer to be a = 15 which is a positive integer and also is smaller than 20, this then let’s us know that 15 is how many terms can be summed up to make 960.

To double check this answer you can find that d = 7 by changing the a into 15 in the formula 7a/15 (found in the previous answer.

Then in the expression: (n÷2)×(2a+(n-1)×d)

substitute:

n = 14 (must be an even number for the equation to work)

a = 15

d = 7

This will give you an answer of 847, but this is only 14 terms as we changed n into 14. To add the final term you need to complete the following equation: 847+(a+(n-1)×d)

substituting:

n = 15

a = 15

d = 7

This will give you the answer of 960, again proving that it takes 15 terms to sum together to make the number 960.

I hope this has helped you.

P.S. Everything in the previous solution was right apart from the start of the last section and the answer

If $3000 is invested at 3% interest, find the value of the investment at the end of 7 years if the interest is compounded as follows. (Round your answers to the nearest cent.)
(i) annually
(ii) semiannually
(iii) monthly
(iv) weekly
(v) daily
(vi) continuously

Answers

Answer:

annualy=$3689.62

semiannually=$3695.27

monthly=$3700.06

weekly=$3700.81

daily=$3701.00

Continuously=$3701.03

Step-by-step explanation:

Given:

P=3000

r=3%

t=7 years

Formula used:

Where,

A represents Accumulated amount

P represents (or) invested amount

r represents interest rate

t represents time in years

n represents accumulated or compounded number of times per year

Solution:

(i)annually

n=1 time per year

[tex]A=3000[1+\frac{0.03}{1} ]^1^(^7^)\\ =3000(1.03)^7\\ =3689.621596\\[/tex]

On approximating the values,

A=$3689.62

(ii)semiannually

n=2 times per year

[tex]A=3000[1+\frac{0.03}{2}^{2(4)} ]\\ =3000[1+0.815]^14\\ =3695.267192[/tex]

On approximating the values,

A=$3695.27

(iii)monthly

n=12 times per year

[tex]A=3000[1+\frac{0.03}{12}^{12(7)} \\ =3000[1+0.0025]^84\\ =3700.0644[/tex]

On approximating,

A=$3700.06

(iv) weekly

n=52 times per year

[tex]A=3000[1+\frac{0.03}{52}]^3^6 \\ =3000(1.23360336)\\ =3700.81003[/tex]

On approximating,

A=$3700.81

(v) daily

n=365 time per year

[tex]A=3000[1+\frac{0.03}{365}]^{365(7)} \\ =3000[1.000082192]^{2555}\\ =3701.002234[/tex]

On approximating the values,

A=$3701.00

(vi) Continuously

[tex]A=Pe^r^t\\ =3000e^{\frac{0.03}{1}(7) }\\ =3000e^{0.21} \\ =3000(1.23367806)\\ =3701.03418\\[/tex]

On approximating the value,

A=$3701.03

what is the value of digit 6 in9.78265.​

Answers

Answer: uhh I think 60?

Step-by-step explanation:

the answer is 6p because after any value place is zero hoped I helped

Learning Task No. 1 Randy, Manny and Jan put 3 As, 4 Bs and 5 Cs in the box. They will take turns in getting a letter from the box. They are trying to test the probability of getting their favourite letter.

Randy - A
Manny-B
Jan-C

1. What is the probability of getting each boy's favourite letter? a. Randy b. Manny c. Jan
2. If you are next to Jan to pick up a letter and your favourite letter is A , What is the probability of getting your favourite letter?
3. Who is most unlikely to get his favourite letter.​

Answers

Answer:

1. A = 3/12

B= 4/12

C = 5/12

2......

3. Randy

Step-by-step explanation:

3+4+5 = 12

therefore there are 12 letters in the box

we can say that there are 3/12 A's in the box and do the same for the remaining letters

question two does not make sense

3. the person who has the lowest fraction in value which is A


A driver must decide whether to buy a new car for $24,000 or lease the same car over a four-year period. Under the terms of the lease, she can make a down payment
of $3000 and have monthly payments of $150. At the end of the four years, the leased car has a residual value (the amount she pays if she chooses to buy the car at
the end of the lease period) of $11,000. Assume she can sell the new car at the end of the four years at the same residual value. Is it less expensive to buy or
to lease?

Answers

Answer:

3000 is the answer this question.

The head of maintenance at XYZ Rent-A-Car believes that the mean number of miles between services is 4959 miles, with a standard deviation of 448 miles. If he is correct, what is the probability that the mean of a sample of 43 cars would differ from the population mean by less than 111 miles

Answers

Answer:

0.8948 = 89.48% probability that the mean of a sample of 43 cars would differ from the population mean by less than 111 miles

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The mean number of miles between services is 4959 miles, with a standard deviation of 448 miles

This means that [tex]\mu = 4959, \sigma = 448[/tex]

Sample of 43:

This means that [tex]n = 43, s = \frac{448}{\sqrt{43}}[/tex]

What is the probability that the mean of a sample of 43 cars would differ from the population mean by less than 111 miles?

p-value of Z when X = 4959 + 111 = 5070 subtracted by the p-value of Z when X = 4959 - 111 = 4848, that is, probability the sample mean is between these two values.

X = 5070

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{5070 - 4959}{\frac{448}{\sqrt{43}}}[/tex]

[tex]Z = 1.62[/tex]

[tex]Z = 1.62[/tex] has a p-value of 0.9474

X = 4848

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{4848 - 4959}{\frac{448}{\sqrt{43}}}[/tex]

[tex]Z = -1.62[/tex]

[tex]Z = -1.62[/tex] has a p-value of 0.0526

0.9474 - 0.0526 = 0.8948

0.8948 = 89.48% probability that the mean of a sample of 43 cars would differ from the population mean by less than 111 miles

Find the length of an arc of a circle with a 8-cm radius associated with a central angle of 240 degrees. Give your answer in exact and approximate form to the nearest hundredth.

Answers

Answer:

l = 1920 cm

Step-by-step explanation:

Given that,

The radius of circle, r = 8 cm

The central angle is 240 degrees

We need to find the length of the arc. We know that,

[tex]l=r\theta[/tex]

Where

l is the length of the arc

So,

[tex]l=8\times 240[/tex]

[tex]\implies l=1920\ cm[/tex]

so, the length of the arc is equal to 1920 cm.

If you spin two times, what is the probability of landing on
green both times? (leave answer in fraction form in lowest
terms)
Red
Green
Yellow
Red
1/9
1/30
1/6
1/360

Answers

i think the answer is 1/36 because 1/6 times 1/6

FastForward has net income of $19,090 and assets at the beginning of the year of $209,000. Its assets at the end of the year total $264,000. Compute its return on assets.

Answers

Given:

Net income = $19,090

Assets at the beginning of the year = $209,000.

Assets at the end of the year total = $264,000.

To find:

The return on assets.

Solution:

Formula used:

[tex]\text{Return of assets}=\dfrac{\text{Net income}}{\text{Average of assets at the beginning and at the end}}[/tex]

Using the above formula, we get

[tex]\text{Return of assets}=\dfrac{19090}{\dfrac{20900+264000}{2}}[/tex]

[tex]\text{Return of assets}=\dfrac{19090}{\dfrac{473000}{2}}[/tex]

[tex]\text{Return of assets}=\dfrac{19090}{236500}[/tex]

[tex]\text{Return of assets}\approx 0.0807[/tex]

The percentage form of 0.0807 is 8.07%.

Therefore, the return on assets is 8.07%.

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