Answer:
A 2:1
B 1:2
Step-by-step explanation:
If there is 24 students and 8 are girls, then 24 - 8 tells you how many are boys.
24 - 8 = 16.
There are 16 boys.
If there is 16 boys and 8 girls, the ratio would be 2 : 1 or 2/1 or 2 because 16 and 8 have a common factor of 8, so both sides can be divided by 8.
Hence the 8 : 2.
Ratios are commonly expressed with a colon, so that is going to be the symbol I'm using to differenciate the numbers.
We can just reverse the ratio since the original was boys to girls, but it is now girls to boys.
1:2
Question is in photo.
Thanks
Answer:
what do you mean for this question. What do you need help on?
What is the slope of the line formed by (7,1) and (-3,3)?
Answer:
JMK
Step-by-step explanation:
Answer:
[tex]-\frac{1}{5}[/tex] is the slope of the line.
Step-by-step explanation:
(7 , 1) = (x1 , y1)
(-3 , 3) = (x2 , y2)
slope = y2 - y1/x2 - x1
=3 - 1/-3 - 7
=2/-10
=1/-5
=[tex]-\frac{1}{5}[/tex]
Question 7
1. Calculate and write your answer as a mixed number
1 4/5 + 2 2/3 - 16/15
Answer:
3 7/15
Step-by-step explanation:
1 4/5 + 2 2/3 - 16/15
9/5 + 8/3 - 16/15
27/15 + 40/15 - 16/15
52/15 = 3 7/15
Answer:
3 2/5
Step-by-step explanation:
STEP 1: Convert all fractions into improper fractions
9/5 + 8/3 - 16/15
Step 2: pass denominators
(9x3 + 8x5 - 16) / 15
=51/15
Step it into proper mixed number
3 2/5
Keller performed the work below to express the polynomial in factored form:
r(x) = x4 – 8x2 – 9
r(x) = (x2 + 1)(x2 – 9)
(x) = (x + 1)(x – 1)(x + 3)(x – 3)
Explain the error he made and complete the factorization correctly.
Answer:
He made the following mistake, he assumed that polynomial [tex](x^{2}+1) = (x^{2}-1)[/tex], having for granted that [tex]x^{2}+1[/tex] has two real roots, instead of two complex roots.
Step-by-step explanation:
He made the following mistake, he assumed that polynomial [tex](x^{2}+1) = (x^{2}-1)[/tex], having for granted that [tex]x^{2}+1[/tex] has two real roots, instead of two complex roots. The true factorized form of the fourth grade polynomial is:
[tex]r(x) = (x^{2}+1)\cdot (x^{2}-9)[/tex]
[tex]r(x) = (x- i)\cdot (x+i)\cdot (x+3)\cdot (x-3)[/tex]
i need help like asap!!!!
Answer:
to do this lets first solve this so
5*5*5*5=625
5^-3=0.008
0.008^2=0.000064
0.000064*625=0.4
so all equations that are equal to 0.4 are right which is C
Solve x2 + 10x + 7 = 0 by completing the square.
Which equation is used in the process?
( x + 5) 2 = 32
( x + 5) 2 = 18
( x + 10) 2 = 93
**PLEASE HELP**The frequency table below represents the 30 best battling averages for a semi pro baseball league. Which ranges of battling averages were least common among the players
The lower the frequency the least common the average.
There are two frequencies that are 1, which would be the least common.
The answer is C. 0.320-0.329 and 0.360 -0.369
Answer:
option C
Step-by-step explanation:
option c is contains the two batting averages which have a frequency of 1, this means that they both only occurred once which is the least amount of times any of the batting averages has occurred.
Un capital de S/. 42.000 colocado a una tasa de interés del 7% capitalizable anualmente, ¿en cuántos meses produce un interés de S/. 8 700?
Answer:
Se requiere 34 meses para producir un interés de 8700 soles.
Step-by-step explanation:
Asumamos que el capital aumenta conforme a una tasa de interés compuesto, cuya fórmula se describe aquí abajo:
[tex]C = C_{o}\cdot \left(1 + \frac{r}{100} \right)^{t}[/tex] (1)
Donde:
[tex]C_{o}[/tex] - Capital inicial, en soles.
[tex]C[/tex] - Capital actual, en soles.
[tex]r[/tex] - Tasa de interés mensual, en [tex]\frac{1}{a}[/tex].
[tex]t[/tex] - Período de capitalización, en años.
Si sabemos que [tex]C_{o} = 42000[/tex], [tex]C = 50700[/tex] y [tex]r = 7\,\frac{\%}{a}[/tex], entonces el período de capitalización es:
[tex]C = C_{o}\cdot \left(1 + \frac{r}{100} \right)^{t}[/tex]
[tex]\frac{C}{C_{o}} = \left(1 + \frac{r}{100}\right)^{t}[/tex]
[tex]\ln \frac{C}{C_{o}} = t\cdot \ln \left(1 + \frac{r}{100}\right)[/tex]
[tex]t = \frac{\ln C - \ln C_{o}}{\ln \left(1+\frac{r}{100} \right)}[/tex]
[tex]t = \frac{\ln 50700 - \ln 42000}{\ln \left(1+\frac{7}{100} \right)}[/tex]
[tex]t = 2.782\,yr[/tex]
Es decir, se requiere 34 meses para producir un interés de 8700 soles.
Math help please show work thanks
Answer:
600.4 cm^2
Step-by-step explanation:
first we should find the base of samller triangle
hypotenuse = 35 cm
one side = 30 cm whereas other has be be find
using pythagoras theorem
a^2 + b^2 = c^2
30^2 + b^2 = 35^2
900 + b^2 = 1225
b^2 = 1225 - 900
b^2 = 325
b = [tex]\sqrt{325}[/tex]
b = [tex]5\sqrt{13}[/tex]
area of big triangle
base = 22 + [tex]5\sqrt{13}[/tex]
area of a triangle = base * height / 2
= 30 (22 + [tex]5\sqrt{13}[/tex] ) /2
=30*22 + 30*[tex]5\sqrt{13}[/tex] / 2
=660 + 540.83 / 2
=1200.83 / 2
=600.415
=600.4 cm^2
9514 1404 393
Answer:
330 cm²
Step-by-step explanation:
The formula for the area of a triangle is ...
A = 1/2bh
where b is the base length and h is the height measured perpendicular to the base.
Here, the base length is 22 cm, and the height is 30 cm. The area is ...
A = 1/2(22 cm)(30 cm) = 330 cm²
__
Additional comment
As is often the case with "overspecified" geometrical figures, the given dimensions are inconsistent. If the side lengths are taken as true, the height is closer to 33.1 cm, and the area is about 364.1 cm².
We assume the intended solution method is the one used above, as all it requires is to make use of a simple formula, and the calculation can be done mentally.
A cube of sides 10cm was cut across to obtain a prism. Calculate the surface area of the prism and the volume of the prism
[tex] \frac{1}{2} bh \times h[/tex]
Answer:
Part A
The volume of the triangular prism is 500 cm³
Part B
The total surface area of the prism is approximately 441.42 cm²
Step-by-step explanation:
The given details are;
The dimensions of the side length of the cube, s = 10 cm
The shape the cube was cut across to obtain = A prism
Part A
Whereby the prism obtained is a triangular prism, we have;
The cube can be cut in half to form a triangular prism
The volume of each triangular prism obtained = (1/2) × The volume of the cube
∴ The volume of the triangular prism = (1/2) × (10 cm)³ = 500 cm³
Part B
The height of the prism, h = 10 cm × sin(45°) = 5·√2 cm = (1/2) × The base width of the prism
The triangular cross sectional area of the prism, A₁ = 5·√2 × 5·√2 = 50
The square cross sectional area, A₂ = 10 × 10 = 100
The cross sectional area of the base, A₃ = 10·√2 × 10 = 100·√2
The total surface area of the prism, A = 2·A₁ + 2·A₂ + A₃
∴ A = 2×50 + 2×100 + 100·√2 = 300 + 100·√2 ≈ 441.42
The total surface area of the prism, A ≈ 441.42 cm²
Please help I’ll give brainliest
Answer:
v = 27,000 mm³
Step-by-step explanation:
v = s³
v = 30³
v = 27,000 mm³
Find the sum difference 104 - (-92)
Answer:
12
Step-by-step explanation:
if cos A= 9\13 find csc A
Answer:
13[tex]\sqrt{22}[/tex] / 44
Step-by-step explanation:
cos A = 9/13
here adjacent = 9 and hypotenuse = 13 opposite = ?
using pythagoras theorem to find opposite
a^2 + b^2 = c^2
9^2 + b^2 = 13^2
81 + b^2 = 169
b^2 = 169 - 81
b^2 = 88
b = [tex]\sqrt{88}[/tex]
b = [tex]2\sqrt{22}[/tex]
therefore opposite = [tex]2\sqrt{22}[/tex]
cosec A = hypotenuse/opposite
= 13/[tex]2\sqrt{22}[/tex]
rationalizing the denominator
=13/ [tex]2\sqrt{22}[/tex] * [tex]2\sqrt{22}[/tex] / [tex]2\sqrt{22}[/tex]
=13 *[tex]2\sqrt{22}[/tex] /( [tex]2\sqrt{22}[/tex] )^2
=26 [tex]\sqrt{22}[/tex] / 4*22
=26 [tex]\sqrt{22}[/tex] / 88
=13[tex]\sqrt{22}[/tex] / 44
Answer:
[tex]cosec A = \frac{13}{\sqrt{88}}[/tex]
OR
[tex]cosec A = \frac{13 \sqrt{22}}{44}[/tex]
Step-by-step explanation:
Formulas used:
[tex]cos^2 A = 1 - sin^2 A\\\\cosec A = \frac{1}{sin A}[/tex]
Given :
[tex]cos A = \frac{9}{13}[/tex]
Find cosec A
[tex]sin ^2 A = 1 - cos^2 A[/tex]
[tex]= 1 - (\frac{9}{13})^2\\\\= 1 - \frac{81}{169}\\\\=\frac{169 - 81}{169}\\\\=\frac{88}{169}[/tex]
[tex]sin A = \sqrt{\frac{88}{169}} = \frac{\sqrt{88}}{13}[/tex]
Therefore,
[tex]cosec A = \frac{1}{sin A} = \frac{1}{ \frac{\sqrt{88}}{13}} = \frac{13}{ \sqrt{88}}[/tex]
OR In a simplified form :
[tex]cosec A = \frac{13}{\sqrt{88}} \times \frac{\sqrt{88}}{\sqrt{88}} = \frac {13 \times \sqrt{4 \times 22}}{88} = \frac{13 \times 2 \sqrt{22}} {88} = \frac{13 \sqrt{22}}{44}[/tex]
$125 to the markup rate of 80% what is the final price?
Answer:
$225
Step-by-step explanation:
mark rate = 80%
original price = $125
mark amount = 80% of $125
=80/100 *125
=10000/100
=$100
final price = $125 + $100
=$225
Evaluate 5 x3 - 2 + 7 when x = -2.
Answer:
57
Step-by-step explanation:
5|x^³-2|+7
let x=-2
5|(-2)^3-2|+7
work inside the absolute value first
5|-8-2|+7
5|-10|+7
Take the absolute value, which make it positive
5 *10+7
multiply
50+7
=57
nakita ko lng po yan but hope that helpsツ
What is the perimeter of this rectangle?
i need the answer plz
Answer:
see explanation
Step-by-step explanation:
If (x - 1) is a factor then f(1) = 0
Given
f(x) = x³ - 13x² + 32x - 20 , then
f(1) = 1³ - 13(1)² + 32(1) - 20
= 1 - 13 + 32 - 20
= 0
Since f(1) = 0 then (x - 1) is a factor
Using Synthetic division
1 | 1 - 13 32 - 20
↓ 1 - 12 20
-----------------------------
1 - 12 20 0 ← remainder
quotient = x² - 12x + 20 = (x - 2)(x - 10)
Then
x³ - 13x² + 32x - 20 = (x - 1)(x - 2)(x - 10) ← in factored form
The scores from Dr. Wilhelm's students science fair project are shown below .
Dr wilhelm made a histogram for the data.
answer choices :
50
65
70
71
plsss help I appreciate it thank you so much
Answer:
See Explanation
Step-by-step explanation:
You posted an incomplete question with little and unclear details.
I will answer this question with a more complete version (see attachment)
Given that:
[tex]Scores: 100\ 95\ 88\ 62\ 76\ 90\ 100\ 58\ 72\ 60\ 85\ 90\ 70\ 72\ 54\ 100\ 60\ 80\ 75\ 51[/tex]
Required
The fraction that passed the test
Rearrange the score in ascending order:
[tex]Scores: 51\ 54\ 58\ 60\ 60\ 62\ 70\ 72\ 72\ 75\ 76\ 80\ 85\ 88\ 90\ 90\ 95\ 100\ 100\ 100[/tex]
The total number of students is:
[tex]n =20[/tex]
Extract the students that passed (scored 70 and above)
[tex]Passed: 70\ 72\ 72\ 75\ 76\ 80\ 85\ 88\ 90\ 90\ 95\ 100\ 100\ 100[/tex]
Their numbers are:
[tex]Passed: 14[/tex]
So, the fraction of those that passed is:
[tex]Fraction = \frac{Passed}{n}[/tex]
[tex]Fraction = \frac{14}{20}[/tex]
Reduce fraction
[tex]Fraction = \frac{7}{10}[/tex]
31/24 menos 5/8 cuanto es?
Answer:
31/24 menos 5/8 cuanto es 2/3
Step-by-step explanation:
=31/24- 5/8
=31-15/24
= 16/24
=2/3
Hence the final answer is 2/3
Carol wants to tile her utility room. Each tile is 1 square foot. She draws the shape of her room on a grid. Each square unit on the grid represents 1 square foot. How many tiles will she need?
Answer:
1
Step-by-step explanation:
that's a very vague question
need help w this onee thankss!!
Step-by-step explanation:
if you draw an imaginary perpendicular line across the figure from the vertex which joins the line of 2 cm with the line that is making an angle of X then you can see that this figure is made up of two figures that is a triangle and a rectangle.
now from the angle given i.e X.
perpendicular= 5 cm
base = 14 -2= 12 cm
hypotenuse= ?
we know that,
h² = p²+b²
= 5²+12²=169
h= √169
h= 13
again,
cos X = b/h
= 12/13
Help is very much appreciated
Answer:
Options : B & D
Step-by-step explanation:
E(x) = 10x - 30 , where x is the number of doors she knocks
Given she has to pay her own expense.
So whatever she earns $30 is reduced from it ,for her expense.
Option A: She can earn $10 even if she does not knock
any doors - False
That is, x = 0
When x = 0 , E (x) = 10 ( 0 ) - 30 = - 30
=> she loses $30.
Option B :Her expenses are $ 30 per week - True
E(x) = 10x - 30
Expenses are reduced from her earnings.
Option C: She will lose $10 per week if she does not knock
any doors - False.
Already checked on option A that if she does not knock
on any door, means x = 0 , then loses $30.
Option D : If she does not knock on any doors at all during
the week , she will lose $30 - True
For what values of b will F(x) = logo x be a decreasing function?
A. b>0
B. 0
C. b< 0
D. O >b>-1
[tex]f(x) = \log_b(x)[/tex] is a decreasing function when [tex]0 < b < 1[/tex]
This is because we can use the change of base formula to say
[tex]\log_b(x) = \frac{\log(x)}{\log(b)}[/tex]
If b is between 0 and 1, not including either endpoint, notice how the log(b) term is negative.
For example, if b = 0.5, then log(b) = log(0.5) = -0.301 approximately. I'm using log base 10 to get log(0.5) = -0.301
So for b = 0.5, we have,
[tex]\log_{0.5}(x) = \frac{\log(x)}{\log(0.5)} \approx \frac{\log(x)}{-0.301} \approx -3.322\log(x)[/tex]
The log(x) part on its own is always increasing. The negative coefficient out front flips it to always decreasing.
By applying the behavior rules we notice that the expression [tex]F(x) = \log_{b} x[/tex]decreasing function if the base of the logarithm is 0 < b < 1. (Correct choice: D) #SPJ5
How to define the behavior of a logarithmLogarithms are trascendent functions whose form is defined by the following expression:
[tex]\log _{b} x[/tex] such that [tex]x = b^{a}[/tex], where b > 0.
Where b is the base of the power.
Whose rules are described below:
The logarithm is an increasing function if its base is less than 1.The logarithm is a decreasing function if its base is greater than 1.By applying the behavior rules we notice that the expression [tex]F(x) = \log_{b} x[/tex] is a decreasing function if the base of the logarithm is 0 < b < 1. (Correct choice: D)
RemarkThe statement is poorly formatted and reports several mistakes. Correct form is shown below:
For what values of b will [tex]F(x) = \log_{b} x[/tex] be a decreasing function?
A. b > 0
B. 0
C. b < 0
D. 0 < b < 1
To learn more on logarithms, we kindly invite to check this: https://brainly.com/question/20785664 #SPJ5
Use the diagram right above
AB=?
m
Stationary points. Help ASAP please. Thanks
You can use the power rule for derivatives for each problem (though you could also use the product rule for the fourth curve).
y = x ² + 6x - 1 ==> dy/dx = 2x + 6
y = x ² - 5x + 1 ==> dy/dx = 2x - 5
y = 2 - 4x - x ² ==> dy/dx = -4 - 2x
y = (1 + x) (7 - x) = 7 + 6x - x ² ==> dy/dx = 6 - 2x
--
or, using the product rule,
dy/dx = (1 + x) (-1) + 1 (7 - x) = -1 - x + 7 - x = 6 - 2x
--
Now, stationary points occur where the derivative is zero. We have
2x + 6 = 0 ==> x = -3
2x - 5 = 0 ==> x = 5/2
-4 - 2x = 0 ==> x = -2
6 - 2x = 0 ==> x = 3
Find the area of the figure
Will
Give
Brainlist
Answer: 52x+4
Step-by-step explanation: Do 16(2x-1)+4(5x+5) and get 52x+4.
The area of a wall that needs to be papered is 84sqft. The wallpaper that needs to be papered is 18in wide and 33ft long. Rolls of solid color wallpaper will be used, so patterns do not have to match up.
Answer:
The answer is below
Step-by-step explanation:
The area of the wall is 84 ft².
The width of the wallpaper is 18 in.
1 ft. = 12 in
Hence; 18 in = 18 in * 1 ft. per 12 in = 1.5 ft
The length of the wallpaper is 33 ft.
Therefore, the area of the wallpaper = length * width = 1.5 ft. * 33 ft. = 49.5 ft². This means that each roll of wallpaper has an area of 49.5 ft²
Therefore, the minimum amount of rolls of wallpaper needed = area of wall / area of wallpaper
Amount of wallpaper = 84 ft² / 49.5 ft² = 1.7 rolls
Analyze the diagram below and complete the statement that follows.
The perimeter of the square is
A. 42
B. 60
C. 110.25
D. 112.5
Answer:
A: 42
Step-by-step explanation: 10.5x4=42
Answer:
your answer is A 42
Step-by-step explanation:
make me brainliest
Help please giving brainly and points! :)
Answer:
(8,5):
8 is x-axis
5 is y-axis
A rectangular garden has length and width as given by the expressions below.
Length: 4 - 7(3x + 4y)
Width: 3x(-2y)
Write a simplified expression for the perimeter of the rectangle.
y
ху
Answer:
8 - 42x - 56y - 12xy
Step-by-step explanation:
Length = 4 - 7(3x + 4y)
= 4 - 21x - 28y
Width = 3x(-2y)
= -6xy
Perimeter of the rectangle = 2(length + width)
= 2{(4 - 21x - 28y) + ( -6xy)}
= 2(4 - 21x - 28y - 6xy)
= 8 - 42x - 56y - 12xy
Perimeter of the rectangle = 8 - 42x - 56y - 12xy