The volume of a cylinder varies jointly with the square of its radius and with its height: V=kr2h

Cylinder A has a volume of 254.34 cubic inches and has a radius of 3 inches and a height of 9 inches. What is the volume of cylinder B, which has a radius of 4 inches and a height of 5 inches?

Answer:

its the 4 one

Step-by-step explanation:

9514 1404 393

Answer:

  (d)  2

Step-by-step explanation:

The parallel lines divide the transversals proportionally, so we have ...

  3y/3 = 2y/y

  y = 2 . . . . . . . . . simplify (assuming y ≠ 0)

Answer:

Option C (25%) is the correct answer.

Step-by-step explanation:

Given:

Number of students,

= 120

Students responded high interest,

= 30

Students responded medium interest,

= 50

Students responded low interest,

= 40

Now,

The relative frequency will be:

= [tex]\frac{30}{120}[/tex]

= [tex]0.25[/tex]

or,

= [tex]25[/tex]%

Answer:

the right answer would be C

Answer:

Step-by-step explanation:

You first need to find the surface area of a completely open cylinder. That formula is

[tex]SA=2\pi rh[/tex] Using 3.14 for π, we find the area of the material that is needed to make this pipe:

SA = 2(3.14)(1)(30)

SA = 188.49 square feet.

If it costs $3.50 per square foot and you have 188.9 square feet, we multiply the cost per square foot times the number of square feet:

188.49(3.50) = $659.40, choice B.

The expression cos240 degrees is equivalent to cos120 degrees

Answer: B. cos240°

Step-by-step explanation:

Took the Test/Exam on Edge

Answer:

There are 75 ways to form the committee.

Step-by-step explanation:

The order in which the people are chosen is not important, which means that the combinations formula is used to solve this question.

Combinations formula:

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

In this question:

Considering the eldest has to be there, 2 men from a set of 6 and 4 boys from a set of 5(excluding the youngest), so:

[tex]T = C_{6,2}C_{5,4} = \frac{6!}{2!4!} \times \frac{5!}{1!4!} = 3*5*5 = 75[/tex]

There are 75 ways to form the committee.

Answer:

See below

Step-by-step explanation:

-3x+2y = -6 [1]

-2x + y = 6 [2]

For [1], solve for X.

-3x + 2y = -6

-3x = -6 - 2y

3x = 6 + 2y

x = 2 + (2/3)y

Plug x into [2]

-2(2+(2/3)y) + y = 6

-4 - 4/3y + y= 6

-4/3y + y= 10

-1/3y = 10

y = -30

9514 1404 393

Answer:

  (x, y) = (-18, -30)

Step-by-step explanation:

When choosing to solve by substitution, it is convenient if one of the variables has a coefficient of 1 or -1. Here, y has a coefficient of 1 in the second equation, making it easy to rearrange that equation to give an expression for y:

  y = 2x +6 . . . . . add 2x to the second equation

Using this expression, we can substitute for y in the first equation:

  -3x +2(2x +6) = -6

  x + 12 = -6 . . . . . . . . . simplify

  x = -18 . . . . . . . . . . . subtract 12

  y = 2(-18) +6 = -30 . . . . substitute into the equation for y

The solution is (x, y) = (-18, -30).

Answer:

Joe: 18 years old

Tim: 14 years old

Answer: correct answer is B.

Step-by-step explanation:

in the small triangle

taking 60 as reference angle

b = [tex]10\sqrt{3}[/tex]

so

tan 60 = p/b

[tex]\sqrt{3}[/tex] = p/([tex]10\sqrt{3}[/tex])

30 = p

so

[tex]h^2 = p^2 + b^2\\ = 30^2 + (10\sqrt{3} )^2\\\\ = 900 + 300\\ = 1200\\so h^2 = 1200\\then, h = \sqrt{1200} \\ = 20\sqrt{3} \\so\\in bigger triangle\\\\h = x[/tex](taking 45 as reference angle)

so

in bigger triangle

b = 20[tex]\sqrt{3}[/tex]

so

tan 45 = p/b

1 = p/(20[tex]\sqrt{3}[/tex])

p = 20[tex]\sqrt{3}[/tex]

so h^2 = p^2 + b^2

so

h^2 = (20[tex]\sqrt{3}[/tex])^2 +( 20[tex]\sqrt{3}[/tex])^2

= 1200 + 1200

h^2 = 2400

h =[tex]\sqrt{2400}[/tex]

=20[tex]\sqrt{6}[/tex]

so x = 20[tex]\sqrt{6}[/tex]

Answer:

0% probability that a customer will be exactly 7.50 minutes in the record store.

Step-by-step explanation:

Uniform probability distribution:

An uniform distribution has two bounds, a and b.  

The probability of finding a value of at lower than x is:

[tex]P(X < x) = \frac{x - a}{b - a}[/tex]

The probability of finding a value between c and d is:

[tex]P(c \leq X \leq d) = \frac{d - c}{b - a}[/tex]

The probability of finding a value above x is:

[tex]P(X > x) = \frac{b - x}{b - a}[/tex]

The uniform distribution is a continuous distribution, which means that the probability of an exact outcome is zero.

Uniformly distributed between 3 and 12 minutes.

This means that [tex]a = 3, b = 12[/tex]

What is the probability that a customer will be exactly 7.50 minutes in the record store?

Continuous distribution, so:

0% probability that a customer will be exactly 7.50 minutes in the record store.

Answer:

x = - [tex]\frac{2}{3}[/tex]

Step-by-step explanation:

Given

6x + 3 = - 1 ( subtract 3 from both sides )

6x = - 4 ( divide both sides by 6 )

x = [tex]\frac{-4}{6}[/tex] = - [tex]\frac{2}{3}[/tex]

Answer: 43.988

Step-by-step explanation: The formula for the circumference of a circle is the diameter multiplied by pi. Since the diameter is 14 and it is telling us to use 3.142 as pi, we can multiply the two and get the answer.

Answer:

Step-by-step explanation:

If (8,2) and (0,0) are points on the line, the slope of the line is (2-0)/(8-0) = ¼.

y = ¼x

y = 1/4x is the equation of the  line passing through points (0, 0) and (8, 2)

The slope of line passing through two points (x₁, y₁) and (x₂, y₂) is

m=y₂-y₁/x₂-x₁

slope of line passing through (0, 0) and (8, 2)

m=2/8

=1/4

Now let us find the y intercept in the equation.

2=1/4(8)+b

2=2+b

b=0

So equation will be y=1/4x.

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Answer:

Sorry I can't help you. I can't see the problem.

Step-by-step explanation:

Answer:

28 are in the larger class.

Step-by-step explanation:

50/2 = 25 xy

25+ 3 = 28 larger

25-3 = 22 smaller

x = 28

The larger class has 28 students, and the correct option is 28.

Let's assume the number of students in one class is x.

According to the given information, the other class has 6 more students than this class, which means the number of students in the other class is x + 6.

To find the total number of students, we add the number of students in both classes: x + (x + 6) = 50.

Combining like terms, we have: 2x + 6 = 50.

Next, we subtract 6 from both sides of the equation: 2x = 44.

Finally, we divide both sides of the equation by 2 to solve for x: x = 22.

So, there are 22 students in one class, and the other class has 22 + 6 = 28 students.

Therefore, the larger class has 28 students, and the correct option is 28.

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Answer: 12 x 6

Step-by-step explanation:

36/2=18

3x=18

x equal 6

6x2=12 as it is two times

Answer:

A.

Step-by-step explanation:

Each mark is worth two. We are inbetween the first mark and 0 on the left. Half of two is one. and since we are in the left quadrant we know it to be negative. Looking down, we see that we are exactly one mark down. As a mark is two, ans that we are going down, this will be a negative two. That leaves us with the answer of (-1, -2)

Answer:

A. (-1,-2)

Step-by-step explanation:

just trust me...I promise it right

Answer:

I guess this is the correct answer

Answer:

1. >

2. <

3. =

4. <

Step-by-step explanation:

23.197 > 23.179

3 2/10 which is the same as,

3.2 < 3.243

30.423 = 30 423/1000

18.546 < 18 56/100

Answer:

90 numbers

Step-by-step explanation:

Considering the stipulations from the question, the layout for the 3-digit number is:

[tex]\underline{x}\:\underline{2}\:\underline{y}[/tex]

The hundreds digit, [tex]x[/tex], can be any number from 1-9 inclusive, which contains 9 numbers.

The tens digit, 2, is fixed, as stipulated from the problem, and therefore may only be one number, 2.

The ones digit, [tex]y[/tex], can be any number from 0-9 inclusive which gives 10 options.

Therefore, there are [tex]9\cdot 1\cdot 10=\boxed{90}[/tex] three digit numbers that have 2 as a tens digit.

Answer:

0.81 = 81% probability that at most 1 watch in the sample is defective.

Step-by-step explanation:

For each watch, there are only two possible outcomes. Either it is defective, or it is not. The probability of a watch being defective is independent of any other watch, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

4% of watches produced at a particular factory are defective.

This means that [tex]p = 0.04[/tex]

20 watches made at this factory are randomly selected

This means that [tex]n = 20[/tex]

What is the probability that at most 1 watch in the same sample is found to be defective?

This is:

[tex]P(X \leq 1) = P(X = 0) + P(X = 1)[/tex]

In which

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{20,0}.(0.04)^{0}.(0.96)^{20} = 0.442[/tex]

[tex]P(X = 1) = C_{20,1}.(0.04)^{1}.(0.96)^{19} = 0.368[/tex]

Then

[tex]P(X \leq 1) = P(X = 0) + P(X = 1) = 0.442 + 0.368 = 0.81[/tex]

0.81 = 81% probability that at most 1 watch in the sample is defective.

[tex] \underline{ \huge \mathcal{ Ànswér} } \huge: - [/tex]

Average of b and c is 8, that is

[tex]➢ \: \: \dfrac{b + c}{2} = 8[/tex]

[tex]➢ \: \: b + c = 16[/tex]

[tex]➢ \: \: c = 16 - b[/tex]

now let's solve for average of c and d :

[tex]➢ \: \: \dfrac{c + d}{2} [/tex]

[tex]➢ \: \: \dfrac{16 - b + 3b - 4}{2} [/tex]

[tex]➢ \: \: \dfrac{12 + 2b}{2} [/tex]

[tex]➢ \: \: \dfrac{2(6 + b)}{2} [/tex]

[tex]➢ \: \: b + 6[/tex]

Therefore, the average of c and d, in terms of b is : -

[tex] \large \boxed{ \boxed{b + 6}}[/tex]

[tex]\mathrm{✌TeeNForeveR✌}[/tex]

Answer:

b+6

Problem:

If the average of b and c is 8, and d=3b-4, what is the average of c and d in terms of b?

Step-by-step explanation:

We are given (b+c)/2=8 and d=3b-4.

We are asked to find (c+d)/2 in terms of variable, b.

We need to first solve (b+c)/2=8 for c.

Multiply both sides by 2: b+c=16.

Subtract b on both sides: c=16-b

Now let's plug in c=16-b and d=3b-4 into (c+d)/2:

([16-b]+[3b-4])/2

Combine like terms:

(12+2b)/2

Divide top and bottom by 2:

(6+1b)/1

Multiplicative identity property applied:

(6+b)/1

Anything divided by 1 is that anything:

(6+b)

6+b

b+6

Answer:

The marked price was $ 7,777.77, and the selling price of it with VAT was $ 7,910.

Step-by-step explanation:

Given that 13% VAT is levied on a handicraft after 10% discount, if the VAT amount is $ 910, to find the marked price and selling price of it with VAT the following calculations must be performed:

13 = 910

100 = X

100 x 910/13 = X

91,000 / 13 = X

7000 = X

0.9 = 7000

1 = X

7000 / 0.9 = X

7,777.77 = X

Therefore, the marked price was $ 7,777.77, and the selling price of it with VAT was $ 7,910.

Answer:

14.8%

Step-by-step explanation:

53/100*53/100*53/100

Answer:

28.0125 cm^2 rounded to 28.0 cm^2

Step-by-step explanation:

Area = a*b*sin(c)*1/2

Area = 7 * 13 * sin(38) * 1/2

Area = 91/2 * 0.61566...

Area = 28.0125...

Answer:

no solution?

Step-by-step explanation:

2(5)-5=5(5)+7+3(5)        <-- plug in 5

10−5=25+7+15

5=32+15

5=47

Answer:

−2√85/85

Step-by-step explanation:

The required value of the cosθ is −2√85/85. Option D is correct.

Given that,
The value of cosθ given that (−2, 9) is a point on the terminal side of θ is to be determined.

These are the equation that contains trigonometric operators such as sin, cos.. etc.. In algebraic operations.

here,
horizontal run b = -2, vertical rise p = 9
Slant height,
h = √ -[2]² + [9]²
h = √4 + 81
h = √85
Now,
cosθ = b / h
cosθ = -2 / √85
cosθ = -2 √85/85

Thus, the required value of the cosθ is −2√85/85. Option D is correct.

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Answer:

  B.  x ≤ 1 or x > 6

Step-by-step explanation:

Subtract 8 and divide by 2. (Same steps for both inequalities.)

  2x +8 ≤ 10

  2x ≤ 2

  x ≤ 1

__

  2x +8 > 20

  2x > 12

  x > 6

The solution is x ≤ 1 or x > 6.