Answer:
The view factor for radiation emitted by surface 2 to surface 1 is 0.1
Explanation:
Given
[tex]F_{12} = 0.4[/tex]
[tex]A_1 = 0.01m^2[/tex]
[tex]A_2 = 0.04m^2[/tex]
Required
Determine [tex]F_{21}[/tex]
To do this, we make use of the following equivalent ratio
[tex]A_1 * F_{12} = A_2 * F_{21}[/tex]
Make [tex]F_{21[/tex] the subject
[tex]F_{21} = \frac{A_1 * F_{12}}{ A_2}[/tex]
Substitute values into the equation
[tex]F_{21} = \frac{0.01m^2 * 0.4}{0.04m^2}[/tex]
[tex]F_{21} = \frac{0.01 * 0.4}{0.04}[/tex]
[tex]F_{21} = \frac{0.004}{0.04}[/tex]
[tex]F_{21} = 0.1[/tex]