In linear equation, 48720 is the tread life covered under the warranty.
What in mathematics is a linear equation?
An algebraic equation with simply a constant and a first-order (linear) term, such as y=mx+b, where m is the slope and b is the y-intercept, is known as a linear equation. Sometimes, the aforementioned is referred to as a "linear equation of two variables," where x and y are the variables.
1) µ = 60,000 and σ = 6000 miles.
P ( X >= 55000 ) = 1 - P ( X < 55000 )
Standardizing the value
Z = ( X - μ)/σ
Z = ( 55000 - 60000 ) / 6000
Z = -0.83
P((X - μ)/σ > ( 55000 - 60000)/6000
P ( Z > -0.83 )
P ( X >= 55000 ) = 1 - P ( Z < -0.83 )
P ( X >= 55000 ) = 1 - 0.2033
P ( X >= 55000 ) = 0.7967
Part v) What proportion of the tires will need to be replaced under warranty?
X ~ N ( μ = 60000 , σ = 6000 )
P ( X < 52000 )
Standardizing the value
Z = ( X - μ)/σ
Z = ( 52000 - 60000 ) / 6000
Z = -1.33
P((X - μ)/σ > ( 55000 - 60000)/6000
P ( X < 52000 ) = P ( Z < -1.33 )
P ( X < 52000 ) = 0.0918
Part c) If you buy 36 tires, what is the probability that the average life of your 36 tires will exceed 61,000?
X ~ N ( μ = 60000 , σ = 6000 )
P ( X > 61000 ) = 1 - P ( X < 61000 )
Standardizing the value
Z = ( X - μ)/(σ/√n)
Z = (61000 - 60000)/(6000/√36)
Z = 1
P(( X - μ)/(σ/√n) > (61000 - 60000)/(6000/√36)
P ( Z > 1 )
P ( X > 61000 ) = 1 - P ( Z < 1 )
P ( X > 61000 ) = 1 - 0.8413
P ( X > 61000 ) = 0.1587
Part d) The manufacturer is willing to replace only 3% of its tires under a warranty program involving tread life. Find the tread life covered under the warranty.
P ( Z < ? ) = 3% = 0.03
Looking for the probability 0.03 in standard normal table to find the critical value Z
Z = - 1.88
Z = (X - μ)/σ
- 1.88 = ( X - 60000)/6000
X = 48720
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Prove the following using a direct proof:
The sum of the squares of 4 consecutive integers is an even integer
It ahs been proved by mathematical induction that the sum of the squares of 4 consecutive integers is an even integer.
How to solve Mathematical Induction?To prove that the sum of the squares of 4 consecutive integers is an even integer.
Let x, (x + 1), (x + 2), (x + 3) be the four consecutive integers.
The sum of the squares of these integers are:
S = x² + (x + 1)² + (x + 2)² + (x + 3)²
Expanding this gives us:
S = 4x² + 12x + 14
Simplifying this gives:
S = 2(2x² + 6x + 7)
The number 2x² + 6x + 7 is either even number or odd number.
However, since it is multiplied by 2x² + 6x + 7, the sum will always be an even number.
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Se depositan $ 8.000 en un banco que reconoce una tasa de interés del 36% anual, capitalizable mensualmente. ¿Cuál será el monto acumulado en cuatro años?
Answer:
Se depositan $ 8.000 en un banco que reconoce una tasa de interés del 36% anual, capitalizable mensualmente. ¿Cuál será el monto acumulado en cuatro años?
Step-by-step explanation:
Para resolver este problema, podemos utilizar la fórmula del interés compuesto:
A = P*(1 + r/n)^(n*t)
Donde:
A: el monto acumulado después de t años
P: el capital inicial
r: la tasa de interés anual
n: el número de veces que se capitaliza el interés por año
t: el tiempo en años
En este caso, tenemos:
P = $8.000
r = 36% = 0.36
n = 12 (ya que la tasa de interés se capitaliza mensualmente)
t = 4 años
Sustituyendo estos valores en la fórmula, obtenemos:
A = $8.000*(1 + 0.36/12)^(124)
A = $8.000(1 + 0.03)^48
A = $8.000*(1.03)^48
A = $16.751,83
Por lo tanto, el monto acumulado en cuatro años será de $16.751,83.
in a batch of 10,000 clock radios 500 are defective. A sample of 10 clock radios is randomly selected without replacement from the 10,000 and tested. The entire batch will be rejected if at least one of those tested is defective. what is the probability that the entire batch will be rejected?
Answer:
Step-by-step explanation:
This is an example of a hypergeometric distribution problem, where we have a population of 10,000 clock radios with 500 defective ones, and we want to calculate the probability of getting at least one defective radio in a random sample of 10 without replacement.
The probability of getting no defective radios in the sample is:
(9500/10000) * (9499/9999) * (9498/9998) * ... * (9491/9992)
This is because, for the first radio, there are 9500 good radios out of 10,000, and for the second radio, there are 9499 good radios out of 9,999, and so on.
The probability of getting at least one defective radio in the sample is then:
1 - (9500/10000) * (9499/9999) * (9498/9998) * ... * (9491/9992)
which is approximately equal to 0.401.
Therefore, the probability that the entire batch will be rejected is 0.401.
PLEASE HELP !
Use the figure below to answer the questions
From the figure 1. Two line segments are LA and EP. 2. Two rays are EC and AH. 3. Two lines are b and AP.
What are rays, line segment and line?A line segment having a single endpoint and an infinite length in one direction is known as a ray. A ray's length cannot be determined.
There are two endpoints to a line segment. Every point on the line connecting these endpoints to one another is also included. The length of a line cannot be measured, but the length of a segment can.
An eternally long and thin line is a group of points that stretches in two opposite directions.
From the given figure we observe that,
1. Two line segments are LA and EP.
2. Two rays are EC and AH.
3. Two lines are b and AP.
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Use the equation f=d–5 to find the value of f when d=7.
Answer:
2
Step-by-step explanation:
since d=7 and the equation is d-5 in the place of d we'll put 7 therefore 7-5=2
Jonathan says that the function represented by the graph is always decreasing. Is he correct? fI not, where is the function decreasing?
Explain your reasoning.
If the slope of the graph is increasing from positive x-axis to negative x-axis, then the function is not that decreasing. Therefore, Jonathan's statement is incorrect.
What is the graph function about?The function is decreasing on intervals where the slope is negative. In this case, since the slope is increasing from positive x-axis to negative x-axis, the function is decreasing on the interval where x is negative.
To determine this interval more precisely, we would need to find the x-value(s) where the slope changes sign from positive to negative. These x-values correspond to critical points, such as local maximums or minimums. The function is decreasing before a local maximum and after a local minimum.
Therefore, Jonathan's statement is not correct, and the function represented by the graph is decreasing on the interval where x is negative.
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What is 1 2/3 as an improper fraction
Answer:
5/3
Step-by-step explanation:
1×3=3
3+2=5
So answer is 5/3
A normal distribution is informally described as a probability distribution that is "bell-shaped" when graphed. Draw a rough sketch of a curve having the bell shape that is characteristic of a normal distribution.
Choose the correct answer below.
A.
A symmetric curve is plotted over a horizontal scale. From left to right, the curve starts on the horizontal scale and rises at a decreasing rate to a central peak before falling at an increasing rate to the horizontal scale.
B.
A symmetric curve is plotted over a horizontal scale. From left to right, the curve starts above the horizontal scale, falls from the horizontal at an increasing rate, then falls at a decreasing rate to a central minimum before rising at an increasing rate, then rising at a decreasing rate, and finally becoming nearly horizontal.
C.
A symmetric curve is plotted over a horizontal scale. From left to right, the curve starts on the horizontal scale, rises from horizontal at an increasing rate, then rises at a decreasing rate to a central peak before falling at an increasing rate, then falling at a decreasing rate, and finally approaches the horizontal scale.
The correct answer is C. A normal distribution is a symmetric probability distribution that is bell-shaped when graphed. When plotted on a horizontal scale, the curve starts on the horizontal axis, rises to a central peak, and then falls back to the horizontal axis.
The curve is symmetric, meaning that the left and right halves of the curve are mirror images of each other. The curve approaches the horizontal axis but never touches it, which indicates that there is a non-zero probability of observing values at any distance from the mean, although the probability decreases as the distance from the mean increases.
Normal distribution is a type of probability distribution that is commonly found in natural and social phenomena, where the majority of the observations tend to cluster around the mean, with fewer observations further away from the mean.
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A pond in the shape of a right-angled triangle is shown below. Calculate the perimeter of the pond. Give your answer in metres to 1 d.p. 1.46 m 100 73°
The perimeter of the pond is 2.92 meters.
What s a right-angle triangle:
A right-angled triangle is a triangle in which one of the angles measures exactly 90 degrees, also known as a right angle.
The side opposite the right angle is called the hypotenuse, and the other two sides are called the legs.
The perimeter of a right-angled triangle is the sum of the lengths of its three sides.
Here we have
The Hypotenuse of the triangle is 1.46 m
The angle between hypotenuse and perpendicular height = 73°
From triagonometric ratios,
=> cos A = Perpendicular height/ Hypotenuse.
=> cos (73) = Perpendicular height/1.46
=> Perpendicular height = 1.46 × 0.29 = 0.42 m
As we know from Pythagoras' theorem,
Hypotenuse² = side² + side²
Side = √Hypotenuse² - side²
= √[(1.46)²- (0.42)²] = 1.04
Therefore, the sides of the pond are 1.46 m, 0.42 m, and 1.04
Hence, perimeter of the pond = 1.46 + 0.42 + 1.04 = 2.92 meters
Therefore,
The perimeter of the pond is 2.92 meters.
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The complete Question is given below
(b) a dy integral that represents the surface area of the solid formed when c is rotated about the (x or y)-axis
The surface area of the surface generated by rotating the curve y = x² about the y-axis, and we found that the surface area is approximately 54.33 square units.
In this case, the curve we want to rotate is y = x², and we want to rotate it about the y-axis. To use the formula above, we need to express the equation of the curve in terms of x. Therefore, we need to rewrite y = x² as x = √y.
Next, we need to find the derivative of x = √y with respect to y, which is:
dx/dy = 1/2√y
Substituting this into the formula for the surface area, we get:
Surface Area = 2π ∫[0,4] √y √(1+(1/2√y)²) dy
Simplifying the expression inside the square root, we get:
Surface Area = 2π ∫[0,4] √(y+(1/4)) dy
We can evaluate this integral using the power rule of integration, which gives:
Surface Area = 2π [2/3(y+(1/4))^(3/2)]₀⁴
Simplifying further, we get:
Surface Area = 2π [2/3(17/4)^(3/2)]
Surface Area ≈ 54.33 square units
Therefore, the surface area of the surface generated by rotating the curve y = x² about the y-axis is approximately 54.33 square units.
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Complete Question:
How do you find the area of the surface generated by rotating the curve about the y-axis y = x^2 , 0 ≤ x ≤ 2 ?
A scuba diver was 30 feet below sea level when he ascended f feet to a depth of 16 feet below sea level to see a school of fish.
In order to see the school of fish, the scuba diver descended to a depth of 14 feet below sea level.
What dοes "depth" mean?Hοw far sοmething stretches is described by the cοncept οf depth. The pοοl has a six-fοοt depth. Unknοwn is the well's depth. We can use the fοllοwing equatiοn tο determine the scuba diver's initial depth:
Initial depth = Final depth + Depth Change The scuba diver's change in depth is positive because he rose f feet (positive because he went up) and ended up 16 feet below the surface. Therefοre:
initial depth = 16 + f - 30 initial depth.
Simplifying the phrase:
Original depth = -14 + f
The scuba diver reached his initial depth there after descended another 14 feet below sea level to observe the school of fish.
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Questions-
A scuba diver was 30 feet below sea level when he ascended f feet to a depth of 16 feet below sea level to see a school of fish. what is her new elevation now?
Uri paid a landscaping company to mow his lawn. The company charged $74 for the service plus
5% tax. After tax, Uri also included a 10% tip with his payment. How much did he pay in all?
Uri paid a total of $85.47 for the landscaping service including tax and tip.
What is tax?Taxes are compulsory payments made by a government organisation, whether local, regional, or federal, to people or businesses. Tax revenues are used to fund a variety of government initiatives, such as Social Security and Medicare as well as public infrastructure and services like roads and schools. Taxes are borne by whoever bears the cost of the tax in economics, whether this is the entity being taxed, such as a business, or the final users of the items produced by the firm. Taxes should be taken into consideration from an accounting standpoint, including payroll taxes, federal and state income taxes, and sales taxes.
Given that company charged $74 for the service plus 5% tax.
The tax is 5%, that is:
Tax = 5% of $74 = 0.05 x $74 = $3.70
Cost after tax = $74 + $3.70 = $77.70
Now, tip is 10%:
Tip = 10% of $77.70 = 0.10 x $77.70 = $7.77
Total cost = $77.70 + $7.77 = $85.47
Hence, Uri paid a total of $85.47 for the landscaping service including tax and tip.
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12. Nora and Sara both worked to make some money and earned a total of $95. If Sara earned $15
more than Nora, how much did they both earn? Step by Step Please!!
Answers:
Nora = $40
Sara = $55
=========================================================
Work Shown:
n = amount Nora earned
s = amount Sara earned
n+s = 95 .... total amount earned
s = n+15 .... since Sara earned $15 more than Nora
--------------
I'll use the substitution method to solve.
n+s = 95
n+n+15 = 95 ....... replaced "s" with n+15
2n+15 = 95
2n = 95-15
2n = 80
n = 80/2
n = 40 dollars is the amount Nora earned
s = n+15
s = 40+15
s = 55 dollars is the amount Sara earned
--------------
Check:
Nora+Sara = 40+55 = 95 dollars total earned
This confirms the answer. Also, we can see that Sara earned $15 more than Nora to help further confirm the answer.
Solve the given initial-value problem. y''' − 2y'' + y' = 2 − 24ex + 40e5x, y(0) = 1 2 , y'(0) = 5 2 , y''(0) = − 11 2
Answer:
Step-by-step explanation:
To solve the initial-value problem y''' − 2y'' + y' = 2 − 24ex + 40e5x, y(0) = 1/2, y'(0) = 5/2, y''(0) = −11/2, we first find the characteristic equation by assuming that y = e^(rt):
r^3 - 2r^2 + r = 0
r(r^2 - 2r + 1) = 0
r(r-1)^2 = 0
r = 0, 1, 1
Therefore, the general solution to the homogeneous equation y''' − 2y'' + y' = 0 is:
y_h = c1 + c2e^x + c3xe^x
To find the particular solution to the non-homogeneous equation y''' − 2y'' + y' = 2 − 24ex + 40e5x, we guess a particular solution of the form:
y_p = Ax^2e^5x + Be^x
y_p' = (2Ax + 5Ax^2)e^5x + Be^x
y_p'' = (10Ax^2 + 4Ax + 25Ax^2)e^5x + Be^x
y_p''' = (70Ax^2 + 60Ax + 10A + 25Ax^2)e^5x + Be^x
Substituting these expressions into the original equation, we get:
(70Ax^2 + 60Ax + 10A + 25Ax^2)e^5x + Be^x − 2[(10Ax^2 + 4Ax + 25Ax^2)e^5x + Be^x] + [(2Ax + 5Ax^2)e^5x + Be^x] = 2 − 24ex + 40e5x
Simplifying, we get:
(45Ax^2 + 2Ax − 2)e^5x + Be^x = 2 − 24ex + 40e5x
Equating the coefficients of the like terms on both sides, we get:
45A = 40
2A − 2 = 0
B = 2
Therefore, the particular solution is:
y_p = 8/9 x^2e^5x + 2e^x
The general solution to the non-homogeneous equation is therefore:
y = c1 + c2e^x + c3xe^x + 8/9 x^2e^5x + 2e^x
Using the initial conditions y(0) = 1/2, y'(0) = 5/2, y''(0) = −11/2, we get:
c1 + c2 + 2 = 1/2
c2 + 2c3 + 5/2 = 5/2
2c2 + 10/9 + 10 = -11/2
Solving this system of equations, we get:
c1 = 1/9
c2 = -25/18
c3 = 0
Therefore, the solution to the initial-value problem y''' − 2y'' + y' = 2 − 24ex + 40e5x, y(0) = 1/2, y'(0) = 5/2, y''(0) = −11/2 is:
y = 1/9 - 25/18e^x + 8/9
The roots of a quadratic equation a x +b x +c =0 are (2+i √2)/3 and (2−i √2)/3 . Find the values of b and c if a = −1.
[tex]\begin{cases} x=\frac{2+i\sqrt{2}}{3}\implies 3x=2+i\sqrt{2}\implies 3x-2-i\sqrt{2}=0\\\\ x=\frac{2-i\sqrt{2}}{3}\implies 3x=2-i\sqrt{2}\implies 3x-2+i\sqrt{2}=0 \end{cases} \\\\\\ \stackrel{ \textit{original polynomial} }{a(3x-2-i\sqrt{2})(3x-2+i\sqrt{2})=\stackrel{ 0 }{y}} \\\\[-0.35em] ~\dotfill[/tex]
[tex]\stackrel{ \textit{difference of squares} }{[(3x-2)-(i\sqrt{2})][(3x-2)+(i\sqrt{2})]}\implies (3x-2)^2-(i\sqrt{2})^2 \\\\\\ (9x^2-12x+4)-(2i^2)\implies 9x^2-12x+4-(2(-1)) \\\\\\ 9x^2-12x+4+2\implies 9x^2-12x+6 \\\\[-0.35em] ~\dotfill\\\\ a(9x^2-12x+6)=y\hspace{5em}\stackrel{\textit{now let's make}}{a=-\frac{1}{9}} \\\\\\ -\cfrac{1}{9}(9x^2-12x+6)=y\implies \boxed{-x^2+\cfrac{4}{3}x-\cfrac{2}{3}=y}[/tex]
find the two numbers whose ratio is 3:7 and their difference is 20
Answer:
the two numbers are 15 and 35, and their ratio is 3:7, and their difference is 20.
Step-by-step explanation:
Bokomo produced 300 Granola megapacks for the Mogoditshane market. Bokomo’s marginal cost equation is as follows: MC=2x-100. Find the cost of producing an additional 200 items due to increased demand.
The cost of producing an additional 200 items due to increased demand is 180,000 Botswana Pula.
What is marginal cost?Marginal cost is the additional cost incurred by producing one additional unit of a good or service. In other words, it is the cost of producing one more unit of output.
According to question:The marginal cost (MC) equation given is MC = 2x - 100, where x is the number of units produced.
To find the cost of producing an additional 200 items due to increased demand, we need to calculate the marginal cost of producing these 200 items and then multiply that by 200.
The marginal cost of producing 200 additional items is given by:
MC(200) = 2(300 + 200) - 100
MC(200) = 2(500) - 100
MC(200) = 900
So the marginal cost of producing 200 additional items is 900. To find the total cost of producing these 200 items, we can simply multiply the marginal cost by the number of units produced, which in this case is 200:
Total cost = MC(200) × 200
Total cost = 900 × 200
Total cost = 180,000
Therefore, the cost of producing an additional 200 items due to increased demand is 180,000 Botswana Pula.
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7. Jada walks up to a tank of water that can hold up to 10 gallons. When it is active, a
drain empties water from the tank at a constant rate. When Jada first sees the tank, it
contains 7 gallons of water. Three minutes later, the tank contains 5 gallons of water.
a. At what rate is the amount of water in the tank changing? Use a signed number, and
include the unit of measurement in your answer.
b. How many more minutes will it take for the tank to drain completely? Explain or
show your reasoning.
c. How many minutes before Jada arrived was the water tank completely full? Explain
or show your reasoning.
In the word problem,
a)Gallons per minute change is -2/3 gallons per minute
b) 7.5 minutes to drain the other 5 gallons
c)The tank was full 4 1/2 minutes before Jada arrived.
What is word problem?
Word problems are often described verbally as instances where a problem exists and one or more questions are posed, the solutions to which can be found by applying mathematical operations to the numerical information provided in the problem statement. Determining whether two provided statements are equal with respect to a collection of rewritings is known as a word problem in computational mathematics.
a) Gallons per minute change is -2/3 gallons per minute since it decreases by 2 gallons in 3 minutes.
b) we have 5 gallons and lose 2/3 gallons per minute
=> (2/3 gal/minute)(x minutes) = 5 gallons
=> x = 5(3/2) = 15/2 = 7.5 minutes to drain the other 5 gallons
c) There was 10 gallons when the tank is full . That is 3 gallons more than the 7 gals there when Jada arrived.
=> (2/3)(x) = 3
=> x = 3(3/2) = 9/2 = 4 1/2 minutes
The tank was full 4 1/2 minutes before Jada arrived.
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Which graph represents this equation?
= 3/2x^2 - 6x
The parabola is passing through (0, 0) and (9, 0).
What is the parabola?The locus of a moving point is the location that maintains a constant distance between a stationary point and a predetermined line.
The directrix is a non-moving line, while the focus is a non-moving point.
As you can see, the quadratic variable is not, which modifies the figure's orientation.
This parabola doesn't actually represent a function because it will open horizontally, specifically toward negative infinity, as the graphic linked illustrates.
The vertical line test will reveal that the vertical line in question intercepts the figure in two places, proving that it is not a function.
According to our question-
The equation of the parabola is given below.
y = (3/2)x² - 6x
Then the factor of the equation will be
y = 3x (x / 2 - 3)
Then the zeroes of the function will be
y = 0
x = 0, 9
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For the graph, find the average rate of change on the intervals given
See attached picture
The average rate of change on the intervals [0, 3], [3, 5], [5, 7], and [7, 9] are 2, -1.5, 1, and -1.5, respectively.
What is the average rate in math?It expresses how much the function changed per unit on average during that time period. It is computed by taking the slope of the straight line connecting the interval's endpoints on the function's graph.
To calculate the average rate of change for the intervals shown in the graph, we must first determine the slope of the line connecting the endpoints of each interval.
0-3 interval:
Because the interval's endpoints are (0, 1) and (3, 7), the slope of the line connecting them is:
slope = (y change) / (x change) = (7 - 1) / (3 - 0) = 2
pauses [3, 5]:
Because the interval's endpoints are (3, 7) and (5, 4), the slope of the line connecting them is:
slope = (y change) / (x change) = (4 - 7) / (5 - 3) = -1.5
[5–7] Interval:
Because the interval's endpoints are (5, 4) and (7, 6), the slope of the line connecting them is:
slope = (y change) / (x change) = (6 - 4) / (7 - 5) = 1
Interval 7 and 9:
Because the interval's endpoints are (7, 6) and (9, 3), the slope of the line connecting them is:
slope = (y change) / (x change) = (3 - 6) / (9 - 7) = -1.5
As a result, the average rate of change on the intervals [0, 3], [3, 5], [5, 7], and [7, 9] is 2, -1.5, 1, and -1.5.
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How this app works? Why I can’t find any answers? I need pay for points when I ask questions? I subscribe this app and when I’m lucky to the answers almost the answers are wrong
I need your help to buy a door for my house. I have a scale drawing for the door I want but I am not sure of the true size. In the scale drawing the length is 4 in and the width as 7in. The scale for the door is 1 in = 1.5 ft. What are the actual measurements of the door?
Answer:
According to the scale, 1 inch on the drawing represents 1.5 feet in real life. So, to find the actual length of the door, we need to multiply the length on the drawing by the scale factor:
4 inches x 1.5 feet/inch = 6 feet
Similarly, to find the actual width of the door, we need to multiply the width on the drawing by the scale factor:
7 inches x 1.5 feet/inch = 10.5 feet
Therefore, the actual measurements of the door are 6 feet by 10.5 feet.
6x+16=8x-18 i need x
Answer:
x = 17
Step-by-step explanation:
Subtract 6x from both sides:
2x - 18 = 16
Add 18 on both sides to isolate the variable:
2x = 18 + 16
2x = 34
Divide by 2: x = 17
Please help me to solve question 12 asap
The height of the pole is approximately 17.75 meters.
Describe Trigonometry?The main trigonometric functions are sine, cosine, and tangent, which are abbreviated as sin, cos, and tan, respectively. They are used to relate the angles of a right triangle to the lengths of its sides. The sine function gives the ratio of the length of the side opposite an angle to the length of the hypotenuse of the triangle. The cosine function gives the ratio of the length of the adjacent side to the length of the hypotenuse. The tangent function gives the ratio of the length of the opposite side to the length of the adjacent side.
Let's denote the height of the pole as h, and let's denote the distance between the pole and the student's original position (due west of the pole) as x.
From the student's original position, we have a right triangle with the pole being the hypotenuse. The angle opposite to the height of the pole is 40°. So, we have:
tan(40°) = h/x
From the student's new position (10 m due south of the original position), we have another right triangle with the pole being the hypotenuse. The angle opposite to the height of the pole is 35°. The distance between the pole and the student's new position is (x+10) meters (the student moved 10 m south). So, we have:
tan(35°) = h/(x+10)
Now we have two equations with two unknowns (h and x). We can solve for x in terms of h from the first equation:
x = h/tan(40°)
Substitute this expression for x into the second equation:
tan(35°) = h/((h/tan(40°))+10)
Simplify and solve for h:
h = (10 tan(35°) tan(40°)) / (tan(40°) - tan(35°)) ≈ 17.75 m
Therefore, the height of the pole is approximately 17.75 meters.
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If A = [ 1 2 4 0 5 6 ] and B= [ 7 3 2 5 1 9] find C= A+B and D=A-B
Step 1: Arrange the arrays so that A and B are in the same order: A = [ 1 2 4 0 5 6 ], B = [ 7 3 2 5 1 9]
Step 2: To find C = A+B, add each element of A and B together.
C = [1+7, 2+3, 4+2, 0+5, 5+1, 6+9]
C = [8, 5, 6, 5, 6, 15]
Step 3: To find D = A-B, subtract each element of B from A.
D = [1-7, 2-3, 4-2, 0-5, 5-1, 6-9]
D = [-6, -1, 2, -5, 4, -3]
According to a poll, about % of adults in a country bet on professional sports. Data indicates that % of the adult population in this country is male. Complete parts (a) through (e).
(b) Assuming that betting is independent of gender, compute the probability that an adult from this country selected at random is a male and bets on professional sports.
P(male and bets on professional sports)
0.0568
(c) Using the result in part (b), compute the probability that an adult from this country selected at random is male or bets on professional sports.
P(male or bets on professional sports)
0.5362
(d) The poll data indicated that 7.3% of adults in this country are males and bet on professional sports. What does this indicate about the assumption in part (b)?
A.
The assumption was incorrect and the events are not independent.
Part 5
(e) How will the information in part (d) affect the probability you computed in part (c)? Select the correct choice below and fill in any answer boxes within your choice.
A.
P(males or bets on professional sports) = ?
a) D. No. A person can be both male and bet on professional sports at the same time
How to solveb) If the events A and B are independent, P(A&B) = P(A) x P(B)
P(male and also bets on professional sports) = 0.484x0.13 = 0.0629
c) P(male or bets in professional sports) = P(male) + P(bets in professional sports) - P(male and also bets on professional sports)
= 0.484 + 0.13 - 0.0629
= 0.5511
d) A. The assumption was incorrect and the events are not independent
(if the were independent, the percentage would have been 6.29)
e) A. P(male or bets on professional sports = 0.484 + 0.13 - 0.081
= 0.5330
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PLEASE HELP ME ON THIS QUESTION
The frequency table is completed as follows
Number of books frequency
0 - 9 1
10 - 19 10
20 - 29 9
What is frequency table?
A frequency table is a way of organizing data in a table that shows the number of times each value or category appears in a dataset.
The table lists the unique values or categories in one column, and the frequency (or count) of occurrences of each value or category in the dataset in another column.
In the table attached, the solution is achieved by examining the tally column
Each item in the tally column is counted to get the numbers in place of l
A B C and D
Examining the table, we can say that
A = 1
B = 5 + 5 = 10
C = 5 + 4 = 9
D = 3
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93. Electricity Usage The graph shows
the daily megawatts of electricity used
on a record-breaking summer day in
Sacramento, California.
(a) Is this the graph of a function?
(b) What is the domain?
(c) Estimate the number of megawatts
used at 8 A.M.
(d) At what time was the most electric-
ity used? the least electricity?
(e) Call this function f. What is f(12)?
Interpret this answer.
(f) During what time intervals is usage
increasing? decreasing?
Sacramento, California's electricity demand on a scorching summer day is depicted in a function graph. The domain is 24 hours of a day.
The site is available around-the-clock.
One thousand two hundred megawatts are consumed at eight in the morning.
The hours between 4:00 and 6:00 pm saw the highest electricity use, while 4:00 am saw the lowest use.
It would be 1,900 megawatts for f (12).
From 4 am to 5 pm, usage rises, and from 5 pm to 4 am, it falls.
What is displayed by the graph?Because each point on the graph reflects a different megawatt usage, the graph is a function. As this graph of electricity usage illustrates, the domain would be available throughout the entire day.
At 8 a.m., these megawatts are used:
= 1, 300 - ( 200 / 2 )
equal to 1,200 megawatts
As people get ready for work and leave for work, we can observe an increase in power demand from 4 am to 5 pm, but a reduction from 5 pm to 4 am.
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3. Each sample of water from a river has a 10% chance of contamination by a particular heavy metal. Find the probability that in 18 independent samples taken from the same river, only two samples were contaminated. [3 marks]
The probability that, out of 18 independent samples received from one river, just two were contaminated is 0.8438.
Explain about the independent samples?Randomly chosen samples are known as independent samples since their results are independent of other observations' values. The premise that sampling are independent underlies many statistical analysis.When each trial possesses the same probability of achieving a given value, the number of trials or observations is represented using the binomial distribution.In the following 18 samples to be evaluated,
Let X = the number of samples that now the pollutant is present in.
Thus, with p = 0.10 and n = 18, X is a binomial random variable.
Using the binomial theorem:
[tex](^{n} _{r} ) p^{x} q^{n-x}[/tex]
p = 0.10
q = 1 - 0.10 = 0.9
n = 18
The likelihood that only two samples out of 18 obtained in different ways from the same river were polluted
P(x = 2) = [tex](^{18} _{2} ) (0.1)^{2} (0.9)^{18-2}[/tex]
= [tex](^{18} _{2} ) (0.1)^{2} (0.9)^{16}[/tex]
= 153 x 0.01 x 0.1853
= 0.8438
Thus, the probability that, out of 18 separate samples received from one river, just two were contaminated is 0.8438.
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can’t seem to get this any help
A. 27.4
B. 37.3
C. 40.0
D. 42.0
Answer:
Step-by-step explanation:
In the boys triangle:
[tex]tanx=\frac{56}{48}[/tex]
[tex]x=tan^{-1}(\frac{56}{48} )=49.4\textdegree[/tex]
Because triangles are similar:
[tex]tan 49.8=\frac{h}{32}[/tex]
[tex]h=32tan49.8 = 37.3[/tex]
