The time it takes for a dragster to cross the finish line is unknown. The dragster accelerates from rest at 26 m/s2 for a quarter-mile (402 m). What is the final velocity of the dragster?

Answers

Answer 1

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[tex] {v}^{2} - {v(0)}^{2} = 2.a.∆x[/tex]

[tex]v = final \: \: velocity[/tex]

[tex]v(0) = the \: \: velocity \: \: in \: \: the \: \: rest \: \: which \: \: is \: \: zero \\ [/tex]

[tex]a = acceleration[/tex]

[tex]∆x = covered \: \: distance[/tex]

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[tex] {v}^{2} - ({0})^{2} = 2 \times 26 \times 402 [/tex]

[tex] v = \sqrt{2 \times 26 \times 402} [/tex]

[tex]v = \sqrt{20904} [/tex]

[tex]v = 144.58 \: \: \frac{m}{s} [/tex]

Done...

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Related Questions

Which statement is supported by the information in the diagram and table below?

Answers

Answer:

a

Explanation:

a

You are taking an image of a patient who is in extreme discomfort while participating in the CT scanning process. Which of the following qualities must you exhibit to obtain a clear and accurate image? O communication skills O interpersonal skills o detail oriented physical endurance​

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Answer:

Interpersonal skills

Explanation:

Answer:

The right answer is interpersonal skills

Explanation:

give the other person brainliest they deserve it

the faster particles move the less kinetic energy they have true or false

Answers

Answer:

False

Explanation:

You get more kinetic energy the more the particles and less kinetic energy with less particles

hey pls help with this HDJSJDH im rlly bad at this kinda stuff :,) i'll mark the correct answer brainliest

Answers

I am pretty sure it’s A
The cue exerts force onto the white ball which pushes the blue ball into the direction of the hole.

Answer:

A. Cue, White Ball, Blue Ball

Explanation:

Visualize in which order things are being hit

When the energy of a wave increases, what happens to the amplitude?

Answers

Answer:

The energy transported by a wave is directly proportional to the square of the amplitude. So whatever change occurs in the amplitude, the square of that effect impacts the energy. This means that a doubling of the amplitude results in a quadrupling of the energy.

Explanation:

When the energy of a wave increases, the amplitude also increases. This is because the amplitude of the wave is directly proportional to the energy of a wave.

What is the amplitude of a wave?

The amplitude of a wave may be defined as the maximum displacement or distance moved by a point on a vibrating body or wave measured from its equilibrium position. It is equal to one-half the length of the vibration path.

It is the principle of physics that when the amplitude of the wave is higher, the energy also gets higher. To summarise, waves carry energy. The amount of energy they carry is related to their frequency and their amplitude. The higher the frequency, the more energy, and the higher the amplitude, the more energy.

Therefore, when the energy of a wave increases, the amplitude also increases. This is because the amplitude of the wave is directly proportional to the energy of a wave.

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What happens to the gravitational force between two objects as the bodies become closer to each other? A. The gravitational force begins to repel the objects. B. The gravitational force increases. C. The gravitational force decreases. D. The gravitational force stays the same.

Answers

Answer:

Explanation:

The gravitational force between two objects becomes weaker if the two objects are moved apart and stronger if they are brought closer together; that is, the force depends on the distance between the objects.

The gravitational force between two objects as the bodies become closer to each other increases.

Gravitational force is force of attraction between two masses. Gravitational force(F) between two bodies is directly proportion to the product of masses(m₁,m₂) of two bodies and inversely proportional to square of distance(r) between them. mathematically it is written as,

F ∝ m₁.m₂

F ∝ 1/r²

F = G m₁,m₂÷r²

where G is gravitational constant, whose value is 6.6743 × 10⁻¹¹ m³ kg-1s⁻².

Force is expressed in Newton N in SI unit. its dimensions are [M¹L¹T⁻²].

As distance decreases the Force increases

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NEED HELP IS THERE SOMEONE CAN HELP ME PLS :)

Answers

if you climb the hill you will be tired also it will be 4.00 meters per second

Write an equation of the line in slope-intercept form.

Answers

the answer would be y=1/3x+2

1. Which elements would likely have similar properties: two elements in the same group, or two elements in the same period?

2. Fill in the table below with the correct classification of element.

Left side:
Right side:
Zigzag line:

3. Use the periodic table to answer this question: Are the properties of rubidium (Rb) more like those of cesium (Cs) or those of strontium (Sr)? Explain your answer.

4. Use the periodic table at the bottom of the page to identify the elements in the following compounds:
PBS:

KBr:

Rao:

5. Use the periodic table to determine whether each element is a metal or a nonmetal:

Sodium (Na):

Krypton (Kr):

Phosphorus (P):

Answers

Answer:

3. Cs, they are in the same group, mainly sharing characteristics.

Explanation:

The elements in the same group have similar properties. The properties of rubidium is similar to those of strontium because, both are in second group.

What are groups in  periodic table ?

In periodic table, all elements are classified into different periods and groups. The vertical columns in the table is called groups and the horizontal rows are called periods.

The elements in a group have same number of valence electrons and similar chemical and physical properties. For example rubidium and strontium are second group elements and they show similarity in properties.

The elements in the compound, PbS are lead and sulphur and that in KBr are potassium and bromine. Elements in RaO are radium and oxygen. Among the given elements sodium is a metal and krypton and phosphorus are non metals or gases.

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Two students are discussing gravity. One student says that there is a gravitational attraction between the two
of them. The other student thinks this cannot be true, because he cannot feel any gravitational attraction to
the other student. Which student is correct, and why?

Answers

The first student is correct, even though the force of gravity between them is not noticeable at all. All masses in the universe have a gravitational force of attraction- we feel the gravitational force of the earth because the earth has a very large amount of mass. The gravitational force between the two students is there, but it is a very very very small amount of force. Just because you can’t feel it doesn’t mean it’s not there. Hope that explanation helps! :)

The student says that there is a gravitational attraction between the two of them. This student is correct.

What is gravitational force?

The force of attraction between any two bodies is directly proportional to the product of their masses and is inversely proportional to the square of the distance between them, according to Newton's universal law of gravitation.

The gravitational force is weak unless there are massive masses involved. As compared to Earth, humans have relatively low masses, which results in a very small and negligible gravitational force. As a result, although it is tiny and imperceptible, gravitational force exists between two people seated near to one another.

Hence, the student, who says that there is a gravitational attraction between the two of them, is correct.

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Marlene loves astronomy and has enrolled in an online course to learn more about space. The course gives Marlene access to a digital classroom.

What does this enable her to do? Check all that apply.

discuss the solar system with others in the class
attend a field trip to a planetarium at a local college
upload an amateur video of a shooting star
make a presentation about her favorite planet
take notes, tests, and quizzes
watch instructional videos made by a teacher

Answers

Answer:

A E and F are the correct answers

Explanation:

Answer:

A E F are correct

Explanation:

What is the mass of a falling rock if it produces a force of 147 N with an acceleration of 9.8 m/s2? ​

Answers

Answer:

15 kg

Explanation:

The mass of the object can be found by using the formula

[tex]m = \frac{f}{a} \\ [/tex]

f is the force

a is the acceleration

From the question we have

[tex]m = \frac{147}{9.8} \\ [/tex]

We have the final answer as

15 kg

Hope this helps you

What role does a resistor play in an electrical circuit

Answers

Answer: It opposes the flow of electrons.

Explanation: just did the quiz on

Answer:

It transforms the electrical energy of the electrons into other forms of energy

Explanation:

did quiz

Space-shuttle astronauts experience accelerations of about 35 m/s2 during takeoff. What force does a 75 kg astronaut experience during an acceleration of this magnitude?

Answers

Answer:

The answer is 2625 N

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 75 × 35

We have the final answer as

2625 N

Hope this helps you

A rubber-wheeled 50 kg cart rolls down a 35 degree concrete incline. Coefficient of rolling friction between rubber and concrete is = 0.02. (a) What is the cart's acceleration if rolling friction is neglected? (b) What is the cart's acceleration if rolling friction is included?

Answers

Answer:

(a) 5.62 m/s²

(b) 5.46 m/s²

Explanation:

The given values are:

mass,

m = 50 kg

angle

= 35°

(a)

If friction neglected,

⇒ [tex]F_x=mgSin \theta=ma[/tex]

⇒ [tex]a_x=gSin \theta[/tex]

       [tex]=9.8 \ Sin35^{\circ}[/tex]

       [tex]=5.62 \ m/s^2[/tex]

(b)

If friction present,

⇒ [tex]F_x=mgCos \theta[/tex]

⇒ [tex]F_x=mgSin \theta-\mu_r mgCos \theta[/tex]

⇒ [tex]a=gSin \theta-\mu_rgCos \theta[/tex]

      [tex]=9.8 \ Sin35^{\circ}-0.02\times 9.8 \ Cos30^{\circ}[/tex]

      [tex]=5.46 \ m/s^2[/tex]

Annie has 100 mL of honey. The honey has a mass of 145 g. What is the density of the honey?

Answers

Answer:

The answer is 1.45 g/mL

Explanation:

The density of a substance can be found by using the formula

[tex]density = \frac{mass}{volume} \\ [/tex]

From the question we have

[tex]density = \frac{145}{100} \\ [/tex]

We have the final answer as

1.45 g/mL

Hope this helps you

What is one physical benefit that can be obtained from participating in field events?

A) strengthen balance
B) better sleep pattern
C) increase capacity for learning
D) all of the above

Answers

Answer:

D

Explanation:

It does all three

What is thought to make the earth behave as if it contained a huge bar magnet?

Answers

A large amount of molten magnetic material containing Iron is believed to rotate (as a liquid) in the Earth’s core.

În ce raport de mase trebuie amestecate două cantități din același lichid, având temperaturile t1=10 grade Celsius, respectiv t2=65 grade Celsius, pentru a obține o temperatură de echilibru t=45 grade Celsius?

Answers

Răspuns:

7: 4

Explicaţie:

Formula pentru calcularea cantității de căldură absorbită este exprimată ca;

Q = mc∆t

m este masa substanței

c este capacitatea termică specifică

∆t este schimbarea temperaturii

Conform legii calorimetriei, căldura pierdută de substanța rece = căldura câștigată de substanța fierbinte.

Folosind formula

(mc∆t) rece = (mc∆t) fierbinte

McCw∆tc = MhCw∆th

Deoarece au aceeași capacitate de căldură specifică, se vor anula. Ecuația devine;

Mc∆tc = Mh∆th ...... 1

Pentru apa rece;

∆tc = 45 ° C - 10 ° C

∆tc = 35 ° C

Pentru apa fierbinte:

∆th = 65 ° C - 45 ° C

∆th = 20 ° C

Înlocuiți în ecuația 1;

Mc (35) = Mh (20)

35Mc = 20Mh

Luând raportul dintre masa apei reci și cea fierbinte:

Mh / Mc = 35/20

Mh / Mc = 7/4

Prin urmare, lichidul trebuie amestecat împreună în raportul 7: 4

An unknown substance from planet X has a density of 10 g/mL. It occupies a volume of 80 mL. What is the mass of this unknown substance?

Answers

Answer:

800 mL

Explanation:

D*V=M

You pick out the numbers as well as what it is they represent from the word problem/explanation, then from there plug them in to the equations. Once you do that, you get your product and have the answer.

10*80= 800

A train is travelling at 15 m/s. It accelerates at 3 m/s² for 20 seconds. How far does the train travel in this time?

Answers

The distance traveled by the train is 900 m.

The given parameters:

Initial velocity of the train, u = 15 m/sAcceleration of the train, a = 3 m/s²Time of motion, t = 20 s

What is distance?Distance is a scalar quantity that shows the total path covered by an object.

The distance traveled by the train is calculated as follows;

[tex]s = ut + \frac{1}{2} at^2\\\\s = (15 \times 20) + (0.5 \times 3 \times 20^2)\\\\s = 900 \ m[/tex]

Thus, the distance traveled by the train is 900 m.

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Answer:

900m

Explanation:

Use the equation: acceleration (a) = change in velocity (v – u) / time taken (t)

Rearrange to solve for the final velocity (v):

v = u + at

Substitute in values and solve:

v = 15 m/s + 3 m/s2 × 20 s = 75 m/s

Rearrange the equation for uniform acceleration (v2 – u2 = 2as) to solve for distance (s):

s = (v2 – u2) / 2a

s = ((75 m/s)2 – (15 m/s)2) / (2 × 3 m/s2)

s = (5,625 m2/s2 – 225 m2/s2) / 6 m/s2

s = 5400 m2/s2 / 6 m/s2

s = 900 m

A player kicks a football from ground level with a velocity of
magnitude 27.0 m/s at an angle of 30° above the horizontal.
What is the horizontal distance the ball travels?
(hint: d= 1/2 at^2)

Answers

Answer:

37.33m

Explanation:

To calculate the distance using d= 1/2 at², the time taken for this projectile object (ball) must be calculated.

Time of a projectile = 2u sinθ/ g

Where u = velocity = 27m/s

g = 9.8m/s²

θ = 30°

T = 2usinθ/ g

T = 2 × 27 × sin 30°/9.8

T = 54sin30°/9.8

T = 27/9.8

T = 2.755

T = 2.76s

If the time taken for the ball to move is 2.76s, the distance travelled is:

D = 1/2at²

D = 1/2 × 9.8 × 2.76²

D = 1/2 × 9.8 × 7.6176

D = 74.65248/2

D = 37.33m

The horizontal distance the ball travels is 37.33m

The horizontal distance travel by ball is 37.32 meters.

First we have to calculate time of projectile,

               [tex]Time=\frac{2usin\theta}{g}[/tex]

Where g is acceleration due to gravity and u is velocity.

Given that, [tex]u=27m/s, \theta=30[/tex]

Substitute values in above relation.

       [tex]Time=\frac{2*27*sin30}{9.8}=\frac{2*27*0.5}{9.8}=2.76s[/tex]

The horizontal distance is given by,

              [tex]d=\frac{1}{2}gt^{2}\\ \\ d=\frac{1}{2}*9.8*(2.76)^{2} \\\\d=37.32m[/tex]    

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Answers

Answer:

Right direction (i.e towards B).

Explanation:

From the question given above, we can see that the car is accelerating in the left direction (i.e towards D).

Friction is the force that tends to oppose the motion of an object. Since the car is moving in the left direction (i.e towards D) then, the frictional force acting on the wheel will be in the opposite direction i.e right direction (i.e towards B).

PLEASE HELP THE question on picture

Answers

Vertical:

(20 m/s) sin(25º) ≈ 8.45 m/s

Horizontal:

(20 m/s) cos(25º) ≈ 18.1 m/s

A skydiver jumps from a plane and falls for 5 seconds before reaching his terminal velocity. During this 5 seconds interval, describe his acceleration before reaching terminal velocity?

Answers

Answer:

His acceleration during the first five seconds before reaching terminal velocity = (W - D)/m

Explanation:

The terminal velocity is the maximum steady velocity attained by a body falling freely with increasing velocity from rest in a fluid, such as air or water

The net force, F acting on the body falling through the fluid is given as follows;

F = Weight force, W, from gravity - Drag force, D, from the fluid

F = W - D

Given that F = Mass, m × Acceleration, a, we have;

F = m × a

The acceleration, a = F/m = (W - D)/m

His acceleration during the first five seconds before reaching terminal velocity = (W - D)/m.

Jen had an average speed of 2.5 m/s when hopping on one foot. If she hopped for 5.0 seconds, for what distance was she hopping?

Answers

Explanation:

distance

speed =_________

time

distance = speed × time

= 2.5 × 5.0

distance = 12.5 m


20. Show that an acceleration of 0.67 m/s/s is the result if a force of 1000N is exerted on a 1500 kg
car.

Answers

Explanation:

Given parameters:

Mass of the car = 1500kg

Force applied  = 1000N

Acceleration  = 0.67m/s²

Unknown:

Proof that the acceleration will result from the applied force on the car

Solution:

According to newton's second law of motion,

       Force  = mass x acceleration

 So;

 Acceleration  = [tex]\frac{Force }{mass}[/tex]

Now insert the parameters and solve;

 Acceleration = [tex]\frac{1000}{1500}[/tex]   = 0.67m/s²

We have shown that the acceleration is 0.67m/s²

can someone help rn please!! thank you sm!!

Answers

I think it’s weight
Mass is the measure of its resistance to acceleration when net force is applied
Pounds and Kilograms definitely cannot be the answer
So the only logical answer is weight
Hope this helps

The unit of force is the newton (N). One newton is the force required to accelerate a 1-kg object at a rate of 1 m/s2. Suppose each fan supplies a force of 2 N.

Answers

Answer:

Explanation:

According to Newton's second law of lmotion

Force = mass × acceleration

Given

Mass = 1kg

Force = 2N

Required

Acceleration of the 2N body

From the formula

Acceleration = Force/mass

Acceleration = 2N/1

Acceleration = 2m/s²

Los satélites de televisión giran alrededor de la Tierra en una órbita de 42370 km de radio. a) ¿Cuánto vale la aceleración de la gravedad en esa órbita? (Resultado: g = 0,22 m/s2 ) b) ¿Cuánto pesará allí un satélite de 1200 kg? (Resultado: P = 264 N) Datos: G = 6,67 10-11 Nm2 /kg masa de la Tierra: 6 1024 kg

Answers

Answer:

(a) La aceleración de la gravedad en esa órbita es 0.22 [tex]\frac{m}{s^{2} }[/tex]

(b) Un satélite de 1,200 kg pesará allí 264 N.

Explanation:

(a) Cada punto del espacio tiene un  valor del campo proporcional a la función, siguiendo el modelo de gravitación de Newton:

[tex]g=G*\frac{m}{r^{2} }[/tex]

donde m será masa, r  la distancia entre los objetos y G la constante de gravitación universal, cuyo valor es [tex]G=6.672*10^{-11}\frac{N*m^{2} }{kg }[/tex]

En este caso:

m= 6*10²⁴ kgr=42,370 km= 42,370,000 m

Reemplazando:

[tex]g=6.672*10^{-11}\frac{N*m^{2} }{kg }*\frac{6*10^{24}kg }{(42,370,000 m)^{2} }[/tex]

Resolviendo, obtenes:

g= 0.22 [tex]\frac{m}{s^{2} }[/tex]

La aceleración de la gravedad en esa órbita es 0.22 [tex]\frac{m}{s^{2} }[/tex]

(b) La ley fundamental de la dinámica o segunda ley de Newton expresa que la fuerza neta que es aplicada sobre un cuerpo es proporcional a la aceleración que adquiere en su trayectoria.  Esto se expresa matemáticamente como:

F= m*a

en donde  F es fuerza neta , m la masa y a la aceleración.

El peso es la fuerza que ejerce la gravedad sobre una masa, por lo que se obtiene de manera análoga a la fuerza:

P=m*g

En este caso la masa m tiene un valor de 1,200 kg y la gravedad g un valor de 0.22 [tex]\frac{m}{s^{2} }[/tex].

Reemplazando:

P=1,200 kg*0.22 [tex]\frac{m}{s^{2} }[/tex]

Resolviendo:

P= 264 N

Un satélite de 1,200 kg pesará allí 264 N.

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