Answer:
[tex] x = \frac {30}{r} + 2 [/tex]
Step-by-step explanation:
Given the following data;
S.A of cylinder = 30πr + 2πr²Area of circle = πr²To find how many times greater is the S.A compared to the area, we would have to divide the surface area (S.A) of the cylinder by the area of circle.
Let the unknown variable be x.
[tex] x = \frac {30 \pi r + 2 \pi r^{2}}{\pi r^{2}} [/tex]
Factorizing the numerator, we have;
[tex] x = \frac {\pi r(30 + 2r)}{\pi r^{2}} [/tex]
Dividing both sides by πr, we have;
[tex] x = \frac {30 + 2r}{r} [/tex]
Simplifying further, we would have;
[tex] x = \frac {30}{r} + 2 [/tex]
josh is standing on the top of a building that is 425 feet tall. He throws a penny up into the air with an initial of 32 ft/sec. How long does it take for the penny to hit the ground?
Y = -4.9x^2 + 32x + 425
A. 10 seconds
B. 6.25
C. 400
D. 0 seconds
Answer:
A
Step-by-step explanation:
cause it will be more faster just because it is in a solid phase or it is solid
The time taken to hit the ground is 6.25 sec.(Option B)
How to calculate time?
It is given that penny follows the trajectory:
[tex]y = -4.9x^2 + 32x + 425[/tex]
Differentiating it we get:
[tex]\dfrac{dy}{dx} =-9.8x+32[/tex]
At y=425, it is obvious that x=0
So dy/dx at x=0 is 32.
Now the vertical component of the velocity is 32sinФ (where Ф is the angle at which penny is thrown).
Ф[tex]=\tan^{-1}(32)[/tex]
Vertical component=[tex]32*\sin(\tan^{-1}(32))[/tex]=31.98 ft/sec
Now applying the equation of motion: acceleration=-32ft/sec^(2)
u=31.98ft/sec s=-425 t=?
[tex]s=ut+\frac{1}{2} at^{2}[/tex]
[tex]-425=31.98t-16t^2[/tex]
[tex]16t^2-31.98t-425=0[/tex]
Solving the quadratic equation we get:
t=6.249 sec≅6.25 sec
Therefore, the time taken is 6.25 sec.
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The chance of solving a problem by A and B is and 1/3 and 2/5 respectively. What is the probability the problem will be solved?
a)2/15
b)1
c)9/15
d)11/15
Books shows "c" as the answer.. I am confused..
We want to compute the probability P(A or B) because we could either solve it following path A, path B, or doing both paths.
P(A) = 1/3
P(B) = 2/5
P(A and B) = P(A)*P(B) assuming A,B are independent
P(A and B) = (1/3)*(2/5)
P(A and B) = 2/15
--------
P(A or B) = P(A) + P(B) - P(A and B)
P(A or B) = 1/3 + 2/5 - 2/15
P(A or B) = 5/15 + 6/15 - 2/15
P(A or B) = (5 + 6 - 2)/15
P(A or B) = 9/15
We could reduce this to 3/5, but it appears your teacher has chosen not to.
I need help please. The question is already there. Tysm. 20 points.
Answer:
$109 and 35%
Step-by-step explanation:
49.05 is the sale price and the discount is 55%. What’s the original price?
price/ 1- discount
49.05/ 1 - 0.55
49.05/ 0.45
109
for the other part
to find the discount subtract final price from original price
94 - 61.10 = 32.9
Which would be 35% in percent form.
Find the missing side. Round it to the nearest tenth
The following formula gives the area A of a trapezoid, where b and c are the bases of the trapezoid and h
is the height:
A=
(6+c)h
Rearrange the formula to highlight the height.
h
Answer:
[tex]h = \frac{2A}{b + c}[/tex]
Step-by-step explanation:
Given
[tex]A = \frac{1}{2}(b + c)h[/tex]
Required
Solve for h
We have:
[tex]A = \frac{1}{2}(b + c)h[/tex]
Multiply sides by 2
[tex]2A = (b + c)h[/tex]
Make h the subject
[tex]h = \frac{2A}{b + c}[/tex]
2 square5 + 5 square5
Answer:
=2^5+5^5
=32+3125
=3157
Find the difference quotient for f(x) = x2 + 4.
I am trying to simplify a difference quotient with the form
f(x+h)−f(h)/h
if f(x)=2/x2 I have attempted to cancel out the denominator of the numerator by the least common denominator method. I know that I can solve this using implicit differentiation, but am trying to use the difference quotient to get the partial derivative
Here is my work so far:
f(x+h)−f(x)(h)
=f(2/(x+h)2)−f(2/x2)h
=(2/(x+h)2)−(2/x2)h
here I multiply by the LCD
=(2(x2)−2(x+h)2)/(x2(x+h)2)h
Here I expand out the top and cancel out 2x2
=(2x2−(2x2+4xh+2h2))/(x2(x+h)2)h
=−(4xh+2h2)/(x2(x+h)2))h
Here I think I should multiply by 1/h to get rid of the h on the bottom
I end up with:
=4xh+2h2hx2(x+h)2
factor out an h
=−4x+2hx2(x+h)2
David bought a used Dodge Challenger for $14,000. The value of the car depreciates 11% per year from the time he bought the car. Write a function that represents the value of David's car, V(t), after t years.
Answer:
V(t) = 14,000(0.89)^t
Step-by-step explanation:
Present value of the Dodge Challenger = $14,000
Present percentage value = 100%
Depreciation value = 11%
Number of years = t
Future value = V(t)
V(t) = Present value of the Dodge Challenger(Present percentage value - Depreciation value)^t
= 14,000(100% - 11%)^t
= 14,000(89%)^t
= 14,000(0.89)^t
V(t) = 14,000(0.89)^t
Help me! thank you so much
Answer:
Step-by-step explanation:
[tex]\frac{sinxcos^3x-cos xsin^3x}{cos^42x-sin^42x} \\=\frac{sin x cos x(cos^2x-sin ^2 x)}{(cis^2 2x+sin^2 2x)(cos^2 2x-sin ^22x)} \\=\frac{2sin x cos x cos 2x}{2(1)(cos 4x)} \\=\frac{sin 2x cos 2x}{2 cos 4x} \\=\frac{2 sin 2x cos 2x}{4 cos 4x} \\=\frac{sin 4x}{4 cos 4x} \\=\frac{1}{4} tan 4x[/tex]
What is the area of a circle with a diameter of 20 inches if
[tex]\pi[/tex]
=3.1415
$\sf\underline\bold\blue{Information\:given\:in\:the\:question:}$
π =[tex]\sf{ 3.1415}[/tex]$\sf{Diameter = 20inches}$$\space$
$\sf\underline\bold\blue{What\:we\:have\:to\:find?}$
$\sf{Area\:of\:the\:circle.}$$\space$
$\sf\underline\bold\blue{Answer:}$
$\sf\small{Area\:of\:the\:circle\:is : 314.15}$$\space$
$\sf\underline\bold\blue{Calculations:}$
Here we have the value of the circle's diameter that is 20inches. So, first we have to calculate the radius of the circle using the formula :
$\mapsto$ $\sf\bold{Radius=}$ $\sf\dfrac{Diameter}{2}$
$\space$
$\sf\underline\bold\blue{Calculating\:the\:required\:values:}$
$\mapsto$ $\sf\bold{Radius=}$ $\sf\dfrac{20}{2}$
$\sf{Convert \: to \: the\:lowest\:term(Divide),}$
$\mapsto$ $\sf\underline\bold{Radius=10}$
☆Now we know the value of the radius . So now let's calculate the area of the circle.
$\space$
$\sf\bold{Area\:of\:circle:}$ π$\sf{ r \: ^{2} }$
$\sf\bold{Evaluating \: the\:required\:values:}$
$\sf\bold{Area\:of\:circle=3.1415(10)^2}$
$\space$
$\sf\bold{Area\:of\:the\:circle=3.1415\times10\times10}$
$\sf\bold{Now,}$
$\sf\bold{Area\:of\:the\:circle:3.1415\times100}$
$\space$
$\sf\underline\bold\green{Thus,Area\:of\:the\:circle\: is \: 314.15}$
____________________________
Select the best answer to describe the parabola
Positive parabola that has a minimum.
It’s positive if it opens upward, negative if it opens downward. It has a minimum if it opens upward, and maximum when it opens downward.
For the function F defined by F(x)=x2−2x+4, find F(|−4|).
A. 8
B. 4
C. 12
D. 28
Answer:
12
Step-by-step explanation:
F(x)=x^2−2x+4
Let x = |-4| = 4
F(|-4|)=4^2−2(4)+4
= 16 -8+4
= 8+4
= 12
please please please help asap
Answer:
1,3,5
Step-by-step explanation:
81 is a perfect square so it can be written as an integer
11.8 is rational because it can be written as a fraction (107/9)
sqrt(6) isn't a perfect square so it is irrational
3/7 is a fraction so it is rational
8.57 is a terminating decimal so it is rational
May somebody help with this and show how you solved these 4 problems??
Answer:
x=27
y=25
c=12
n=70
Step-by-step explanation:
a- x-10=17
isolate the x by adding 10 to both sides
x=27
b- y+7=32
isolate the y by subtracting 7 from both sides
y=25
c- 4c=48
isolate c by dividing both sides by 4
c=12
d- n/5=14
isolate the n by multiplying both sides by 5
n=70
Answer:
a) [tex]x-10=17[/tex]
Add 10 to both sides:-
[tex]x-10+10=17+10[/tex][tex]x=27[/tex]----------
b) [tex]y+7=32[/tex]
Subtract 7 from both sides
[tex]y+7-7=32-7[/tex][tex]y=25[/tex]------------
c) [tex]4c=48[/tex]
Divide both sides by 4
[tex]\frac{4c}{4}=\frac{48}{4}[/tex][tex]c=12[/tex]------------
d) [tex]\frac{n}{5}=14[/tex]
Multiply both sides by 5
[tex]\frac{5n}{5}=14\cdot \:5[/tex][tex]n=70[/tex]OAmalOHopeO
what is the degree of the polynomial below
Answer:
d
Step-by-step explanation:
trust me gang
Answer:
the degree is the value of the highest exponent... 4x^3 the exponent is a three
answer "D"
Step-by-step explanation:
In Circle H with m<GKJ=38, Find the m<GHJ
Answer:
the angle GHJ would be 76 because the central angle is always double the measurement of the inscribed angle
YOU HAVE A GARDEN HOSE AND A 0.5 LITER CONTAINER AND A 0.3 LITER CONTAINER. YOU NEED TO MEASURE OUT 0.1 LITER OF WATER. HOW DO YOU DO IT
Answer:
Fill up the .3 container and then pour it into the .5
fill up the .3 again and fill up the .5 ... if all is poured in the .5 will overflow over the top.
stop when the .5 is totally full... only .3 will fit... the liquid left in the .3 will be .1
Step-by-step explanation:
pleeaseeee help me !!!
Answer 3. -7.5 is located to the left of 6.5 on a number line oriented from left to right.
graph shown here is the graph of which of the following rational
functions?
Answer:
B) f(x) = 1/x-1
Step-by-step explanation:
You can type it into desmos graphing calculator- hope this helps
Option (B) is correct.
What is a graphing function?"Graphing functions is drawing the curve that represents the function on the coordinate plane. If a curve (graph) represents a function, then every point on the curve satisfies the function equation"
For the given graph,
The functions are
(A) [tex]f(x)=\frac{1}{x}[/tex]
(B) [tex]f(x)=\frac{1}{x-1}[/tex]
(C) [tex]f(x)=\frac{1}{x+1}[/tex]
Plot all these functions in the graph. We can obtain the graph as shown for option (B).
Hence we can conclude that option (B) is correct.
Learn more about graphing functions here
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PLS HELP ME ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST IF YOU KNOW THE ANSWER!!
You can visualize data sets using ______________.
A. dot charts
B. dotgrams
C. dot graphs
D. dot plots
Answer:
Adrenaline: A stress hormone produced within the adrenal gland that quickens the heart beat, strengthens the force of the heart's contraction, and opens up the bronchioles in the lungs, among other effects. The secretion of adrenaline is part of the human 'fight or flight' response to fear, panic, or perceived threat.
Step-by-step explanation:
What is the distance from point N to LM in the figure below?
Answer:
It is 7.5
Step-by-step explanation:
Solve the following equation for b. Be sure to take into account whether a letter is capitalized or not.
t+1/2b=Y
Answer:
b = 2(Y - t)Step-by-step explanation:
Given:
t + 1/2b = YIsolate b:
1/2b = Y - tFind b:
b = 2(Y - t)[tex]\\ \sf\longmapsto t+\dfrac{1}{2}b=Y[/tex]
take t right side[tex]\\ \sf\longmapsto \dfrac{1}{2}b=Y-t[/tex]
[tex]\\ \sf\longmapsto \dfrac{b}{2}=Y-t[/tex]
[tex]\\ \sf\longmapsto b=2(Y-t)[/tex]
[tex]\\ \sf\longmapsto b=2Y-2t[/tex]
A Triangular Park ABC has sides 120 m, 80m and 50m. a gardener has to put a fence all around it and also plant grass inside. How much area does she need to plant? Find the cost of fencing it with barbed wire at the rate of of Rs. 20 per metre leaving a space 3m wide for a gate on one side?
The perimeter = sum of all sides
= 120 + 80 + 50
= 250
So 250 - 3
247
Left space for gate
Now cost of fencing = Rs 20/per meter
= 247 × 20
= Rs 4,940
Now the area of the triangular park can be found using heron's formula
S = (a+b+c)/2
S = (120+80+50)/2
S = 250/2
S = 125
Now
Herons formula = √s(s-a)(s-b)(s-c)
√125(125-120)(125-80)(120-50)
√125(5)(45)(70)
√5×5×5×5×5×3×3×5×14
After Making pairs
5×5×5×3√14
375√14
Therefore 375√14m is the area of the triangular park
Must click thanks and mark brainliest
$\sf\underline\bold{Answer:}$
$\sf\small\underline{\underline{Area\: planted\: by\: the\: gardener : 1452.36m^2}}$$\sf\small\underline{\underline{The\:cost\:of\:fencing\:the\:park:Rs.4940}}$$\space$
$\sf\underline\bold{Step-by-Step:}$
$\space$
$\sf\bold{Given(In \:the\:Q):}$
Sides of the triangular park are 120m,80m and 50m.$\space$
$\sf\bold{To \: find:}$
How much area of the park does she need to plant?The cost of fencing the park ?$\space$
$\sf\small{☆Area\:to\:be\:planted=Area \: of \: ∆ABC}$
$\space$
$\sf\underline\bold{Calculating\:area\:of\:∆ABC:}$
$\space$
Use heron's formula to find the area of the triangle.
$\space$
$\mapsto$ $\sf\small{Heron's\:formula=}$
[tex]\sf\sqrt{s(s-a)(s-b)(s-c)}[/tex]
$\sf{Where\:s=semi\:perimeter}$$\sf{a,b,c\: = side\:of\:the\:∆}$$\sf\small{Here\:a=120,b=80 \:and\: c=50}$$\space$
$\sf\bold{Now,find\:semi\:parameter:-}$
$\sf\small{Perimeter\:of\:the\:∆=120+80+50=250}$
$\sf\small{Semi-Perimeter:}$ $\sf\dfrac{250}{2}$ $\sf\small{=125m}$
$\space$
$\sf\small{Substitute \: the\:values\:in\:heron's\:formula:}$
$\sf{Area\:of\:the\:∆:-}$
$\mapsto$ [tex]\sf\sqrt{125(125-120)(125-80)(125-50)}[/tex]
$\space$
$\mapsto$ $\sf\sqrt{125\times(5)\times(45)\times(75)}$
$\space$
$\mapsto$ $\sf\small\sqrt{2109375}$ $\sf\small{=375}$ $\sf\small\sqrt{15}$
$\space$
$\longmapsto$ $\sf\underline\bold\purple{1452.56m^2}$
______________________________
$\sf\underline\bold{Now,find\:the\:cost\:of\:fencing:}$
$\sf{Cost\:of\:fencing-}$
$\sf{Rate = Rs.20 per \:meter}$ $\sf{Left\:space=3m}$$\space$
$\sf\underline{Hence,the\:gardener\:has\:to\:fence:}$
$\sf{= 250-3=247m.}$$\space$
So,total cost of fencing at the rate of Rs.20 per m:-
$\sf\underline\bold\purple{=247\times20=4940}$___________________________________
-4 = -2/u solve for U
PLSSSS HELP ME I NWWD THIS OR ELSE I FAIL
Answer:
-4= -2/u
or, -4u= -2
or, u= -2/-4
u=1/2
Here is a list of fractions 18/45 14/30 10/25 8/20 16/40 one of these fractions are not equivalent to 2/5 write down this fractions
Answer:
14/30Step-by-step explanation:
How to simplify: • divide both numerator and denominator by their GCF.18/45= 18 ÷ 9 / 45 ÷ 9= 2/514/30= 14 ÷ 2 / 30 ÷ 2= 7/1510/25= 10 ÷ 5 / 25 ÷ 5= 2/58/20= 8 ÷ 4 / 20 ÷ 4= 2/516/40= 16 ÷ 8 / 40 ÷ 8= 2/5[tex]\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}[/tex]
[tex]\frac{14}{30}[/tex] is not equivalent to [tex]\frac{2}{5}[/tex] in the list of fractions [tex]\frac{18}{45}, \frac{14}{30} , \frac{x}{y} \frac{10}{25}, \frac{8}{20}, \frac{16}{40}[/tex].
Equivalent FractionsEquivalent fractions represent the same value even though they look different.
How to determine the Equivalent fractions?We know we can find an equivalent fraction of a given fraction by or dividing both the numerator and denominator of the given fraction with the same number (maybe LCM or HCF of the numerator or denominator).
[tex]\frac{18}{45}=\frac{18/9}{45/9}=\frac{2}{5}[/tex] (since [tex]9[/tex] is HCF of [tex]18, 45[/tex])
[tex]\frac{14}{30}=\frac{14/2}{30/2}=\frac{7}{15}[/tex] (since [tex]2[/tex] is HCF of [tex]7, 15[/tex])
[tex]\frac{10}{25} =\frac{10/5}{25/5} =\frac{2}{5}[/tex] (since [tex]5[/tex] is HCF of [tex]10, 25[/tex])
[tex]\frac{8}{20} =\frac{8/4}{20/4} =\frac{2}{5}[/tex] (since [tex]4[/tex] is HCF of [tex]8, 20[/tex])
[tex]\frac{16}{40} =\frac{16/8}{40/8} =\frac{2}{5}[/tex] (since [tex]8[/tex] is HCF of [tex]16, 40[/tex])
Thus, [tex]\frac{14}{30}[/tex] is not equivalent to [tex]\frac{2}{5}[/tex].
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Find the measures of angles 1, 2, and 3.
Two perpendicular lines cross each other. Another line rises from left to right intersecting the perpendicular lines where they both intersect. Angles labeled 1, 2, 3 and 57 degrees are shown. Angle 1 is opposite of angle 3. Angle two is opposite to a right angle. Angle 57 degrees plus angle 1 is a right angle. Angle 3 plus the angle opposite of angle 57 degrees is a right angle.
a piece of work can be done by 24 men in 15 days.in how many days can 18 men do the same work?
18 people is 25% less people so will take 25% longer
25% of 15 is 3.75
3.75+ 15 = 18.75 days ?
help lol i forgot everything of the summer time
fill in the table using this function rule
Answer:
hope it help you
Step-by-step explanation:
mark me brailiest answer
3(x-5)=5x-(3-x) solve for x
Answer:
x = -4
Step-by-step explanation:
[tex]3(x-5)=5x-(3-x)\\\\3x-15=5x-3+x\\\\3x-15=6x-3\\\\-15=3x-3\\\\-12=3x\\\\-4=x[/tex]
Step-by-step explanation:
[tex]3(x - 5) = 5x - (3 - x) \\ 3x - 15 = 5x - 3 + x \\ 3x - 5x - x = - 3 + 15 \\ - 3x = 12 \\ x = \frac{12}{ - 3} \\ x = - 4[/tex]
I hope it helped U
stay safe stay happy
What is the quotient?
(-3)
(-3)²
O-9
1
o
1
9
100
O 9
Answer:
(-3)
Step-by-step explanation:
follow me if you want