Answer:
Set two equations:
Number #1 = xNumber #2 = y[tex]\left \{ {{x+y=50} \atop {\frac{x}{y}=\frac{7}{11} }} \right.[/tex]
Rearrange one of the equations to find the value of a variable:
[tex]x+y=50\\x=50-y[/tex]
Substitute in that value into the other equation:
[tex]\frac{50-y}{y}=\frac{7}{11}[/tex]
Cross-multiply & solve for y:
[tex]7y=11(50-y) \\7y=550-11y\\7y+11y=550\\18y=550\\y=\frac{550}{18}=\frac{275}{9}[/tex]
Substitute in the value to the original equation to find x:
[tex]\frac{x}{\frac{275}{9}}=\frac{7}{11} \\\frac{9x}{275}=\frac{7}{11} \\9(11)x=275(7)\\99x=1925\\x=\frac{1925}{99} =\frac{175}{9}[/tex]
Therefore, the answer will be:
x = [tex]\frac{175}{9}[/tex]y = [tex]\frac{275}{9}[/tex]You can check your answers by:
[tex]\frac{175}{9} +\frac{275}{9} =\frac{450}{9} =50[/tex]
[tex]\frac{\frac{175}{9} }{\frac{275}{9} } =\frac{175}{9} *\frac{9}{275} =\frac{175}{275}=\frac{7}{11}[/tex]
Answer:
x = 175/9
y = 275/9
Step-by-step explanation:
Let the larger number be 'x' and smaller number be 'y'
sum of two numbers is 50.
x +y = 50 --------(I)
x = 50 - y -------------(II)
The larger number is divided by the smaller number we get 7/11.
[tex]\frac{x}{y}=\frac{7}{11}\\\\[/tex]
Cross multiply,
11x = 7y
11x - 7y = 0 ------------(III)
Substitute x = 50 -y in equation (III)
11*(50-y) - 7y = 0
11*50 - 11*y - 7y = 0 {Distributive property}
550 - 11y - 7y = 0
550 - 18 y = 0 {Combine like terms}
Subtract 550 from both sides
- 18y = -550
Divide both sides by (-18)
y = -550/-18
y = 275/9
substitute y = 275/9 in equation (III)
[tex]11x - 7*(\frac{275}{9})=0\\\\11x-\frac{1925}{9}=0\\\\11x =\frac{1925}{9}\\\\x=\frac{1925}{9*11}\\\\x=\frac{175}{9}[/tex]
Help please, I need with the question
Answer: [tex]\frac{4}{3}[/tex]
Step-by-step explanation:
tangent of ∠PLM = [tex]\frac{opposite}{adjacent} =\frac{4}{3}[/tex]
Answer:
PLM=4/3
Step-by-step explanation:
The curve y=(k-6)x^2-8x+k cuts the x-axis at two points and has a minimum point. Find the range of values of k.
Answer:
Hello,
answer: -2 < k < 8
Step-by-step explanation:
As there are 2 roots: Δ>0
As there is a mininum, k-6 <0 ==> k<6,
minimum :y'=0 ==> (k-6)*2x-8=0 ==> x=4/(k-6)
[tex]\Delta=8^2-4*k*(k-6)\\=64-4k^2+24k\\=-4(k^2-6k+9)+36+64\\=100-4(k-3)^2\\=4(8-k)(k+2)\\\\\Delta\ is\ positive\ for\ -2 < k < 8[/tex]
I need help solving this
Answer:
E. 248
Step-by-step explanation:
1 to 500 in set A, 250 to 750 in set B
500 - 250 = 250
100 and 200 are divisible by 100.
250 - 2 = 248
tìm kiếm x y z
x-1/y =1
y-1/z =1
z-1/x =1
y - 1/z = 1 ==> y = 1 + 1/z
z - 1/x = 1 ==> z = 1 + 1/x
==> y = 1 + 1/(1 + 1/x) = 1 + x/(x + 1) = (2x + 1)/(x + 1)
x - 1/y = x - (x + 1)/(2x + 1) = (2x ² - 1)/(2x + 1) = 1
==> 2x ² - 1 = 2x + 1
==> 2x ² - 2x - 2 = 0
==> x ² - x - 1 = 0
==> x = (1 ± √5)/2
If you start solving for z, then for x, then for y, you would get the same equation as above (with y in place of x), and the same thing happens if you solve for x, then y, then z. So it turns out that x = y = z.
Chocolate beans are packed in 250 g and 750 g packages. The number of 250 g packages and 750 g packages are in the ratio 1 : 2. If two of the 750 g packages are replaced into 250 g packages, then the ratio becomes 5 : 3. Find
a) the original number of 250 g packages,
b) the total mass of the chocolate beans.
Answer:
a) 4 packages
b) 7000 g or 7 kg
Step-by-step explanation:
x is the number of 250g packages and y is the number of 750g packages.
2x = y
3(x + 2 x (750 : 250)) = 5(y - 2)
3(x + 6) = 5(y - 2)
3(x + 6) = 5(2x - 2)
3(x + 6) = 5(2(x - 1))
3(x + 6) = 5 * 2 * (x - 1)
3(x + 6) = 10(x - 1)
3x + 18 = 10x - 10
(3x + 18) + 10 = (10x - 10) + 10
3x + 28 = 10x
28 = 10x - 3x
28 = 7x
x = 28/7
x = 4
y = 2 * 4 = 8
(250 * 4) + (750 * 8) = 7000 g
Helpppp Please! Please!
Simplify for me please
dilations geometry!
Answer:
A' (0,20)
B' (30,-20)
C' (-10,-40)
Answered by GAUTHMATH
PLEASE HELP! URGENT. the law of cosines is a2+b2-2abcosC=c2. Find the value of 2abccosC.
Answer:
D
Step-by-step explanation:
2ab*cos(C)=a^2+b^2-c^2
2ab*cos(C)=5^2+4^2-2^2=25+12=37
Answer:
The answer is 37
Step-by-step explanation:
Thank you so much thank y’all
If f(1) = 4 and f(n) = f(n − 1) + 5 then find the value of f(5).
Answer:
25
Step-by-step explanation:
f(5)=5(5-1)+5
f(5)=5(4)+5
f(5)=20+5
f(5)=25
Answer:
f(5) = 24
Step-by-step explanation:
f(1) = 4
f(n) = f(n − 1) + 5
Let n = 2
f(2) = f(2 − 1) + 5 = 4+5 = 9
Let n = 3
f(3) = f(3 − 1) + 5 = f(2)+5 = 9+5 = 14
Let n = 4
f(4) = f(4 − 1) + 5 = f(3)+5 = 14+5 = 19
Let n = 5
f(5) = f(5 − 1) + 5 = f(4)+5 = 19+5 = 24
Solve the following equation using
distribution.
2 (4x – 12) = 5
(3) (4x) – (*) (12) = 5
2x - 6 = 5
+6
+6
2x = 11
.. i need help asap look at pics please i need this class done completely in two hours
Answer: 5.5
Step-by-step explanation: It is basically already solved the only thing I did was isolate x by itself my moving the 2 over and doing 11 divided by 2 which equals 5.5. This means that x equals 5.5
can i get some help please
The sum of the interior angles in a triangle is 180 degrees.
72 + 35 + <1 = 180
107 + <1 = 180
<1 = 73 degrees
Hope this helps!
Answer:
<1 = 73
Step-by-step explanation:
The sum of the angles of a triangle is 180 degrees
72+ 35+ <1 = 180
Combine like terms
107 + <1 =180
Subtract 107 from each side
<1 = 180-107
<1 = 73
if the hypotenuse of an isosceles right triangle has a length of 5 centimeters what is the length of one of the legs
Answer:
a =b = [tex]\frac{5\sqrt{5} }{5}[/tex]
Step-by-step explanation:
[tex]a^{2} +b^{2} = 5 ^{2}[/tex]
a = b
[tex]2a^{2} = 5 ^{2}[/tex]
[tex]2a^{2} = 25\\[/tex]
[tex]a^{2} = \frac{25}{5}[/tex]
a = [tex]\frac{5}{\sqrt{5} }[/tex]
must rationalize...
a =b = [tex]\frac{5\sqrt{5} }{5}[/tex]
f(x) = x2 – 12x – 29
f(3) = (x+ ?)+ ?
Answer:
-6 and - 65
Step-by-step explanation:
X-12x-29, by completing the square we get (x-6)^2-65
Given that the point (-2,8) is on the graph of an equation that is symmetric with respect to the x-axis, what other point is on the graph?
(Type an ordered pair)
The table below shows the results from a study that compared speed (in miles per hour) and average fuel economy (in miler per gallon) for cars. Find a quadratic model for the data.
0.008
y=13.472x
2
+0.746x−0.008
y
=
25.836
x
+
0.049
y=25.836x+0.049
y
=
−
.
008
x
2
+
0.746
x
+
13.472
y=−.008x
2
+0.746x+13.472
y
=
0.049
x
+
25.836
y=0.049x+25.836
Note that the quadratic model for the data is y = -0.008x² + 0.75x + 13.47.
How is this so ?
Here are the steps on how to find a quadratic model for the data.
Make a scatter plot of the data. The points should form an inverted U-shape. This suggests a quadratic model.Use the quadratic regression feature on your graphing calculator to find an equation of the model.Here is the output of the quadratic regression feature on my graphing calculator
y = -0.008x² + 0.75x + 13.47.
where -
x is the speed in miles per hour
y is the fuel economy in miles per gallon.
Learn more about Quadratic equation at:
https://brainly.com/question/1214333
#SPJ1
Manish writes the functions g(x) = ^3 sqrt - x - 72 and h(x) = -(x+72)^3
Which pair of expressions could Manish use to show that g(x) and h(x) are inverse functions?
Here we want to find the expressions we need to use to see if the functions g(x) and h(x) are inverses of each other.
The correct option is the last one, counting from the top.
∛((x + 72)^3) - 72 and -(∛(-x) - 72 + 72)^3
Two functions f(x) and g(x) are inverses if:
f( g(x) ) = x
g( f(x) ) = x
In this case, we have the functions:
g(x) = ∛(-x) - 72
h(x) = -(x + 72)^3
Then the expressions we need to check are:
g( h(x) ) = ∛(-h(x)) - 72 = ∛(+(x + 72)^3) - 72 = (x + 72) - 72 = x
h( g(x) ) = -(g(x) + 72)^3 = -(∛(-x) - 72 + 72)^3 = -(∛(-x) )^3 = x
So we found that the two expressions needed are:
∛((x + 72)^3) - 72 and -(∛(-x) - 72 + 72)^3
Then the correct option is the last one, counting from the top.
If you want to learn more, you can read:
https://brainly.com/question/10300045
Answer:
GUYS ITS C THAT IS THE ANSWER
Which equation represents a parabola that has a focus of (0,0) and a directix of y = 2?
Answer: D
Step-by-step explanation:
[tex]a=0,\ b=0,\ k=2\\equation\ of\ the\ parabola:\\\\y=\dfrac{(x-a)^2}{2(b-k)} +\dfrac{b+k}{2} \\\\\\y=-\dfrac{x^2}{4}+1 \\\\x^2=-4(y-1)\\\\Answer\ D[/tex]
Is student is reading a book about 370 words per minute convert this rate to words per hour
Answer: 22,200 words per hour.
Step-by-step explanation:
You can set up a proportion for this: 370 words/per 1 min= x words/ per 60 mins. Cross multiply and you get 22,200=1x which basically equals to 22,200 words per hour or 60 mins.
Based on the graph of the trigonometric function,
what is the period?
Answer:
[tex]\displaystyle 4[/tex]
Explanation:
[tex]\displaystyle y = 3sin\:(\frac{\pi}{2}x + \frac{\pi}{2}) \\ y = 3cos\:\frac{\pi}{2}x[/tex]
[tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{4} \hookrightarrow \frac{2}{\frac{\pi}{2}}\pi[/tex]
OR
[tex]\displaystyle y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{4} \hookrightarrow \frac{2}{\frac{\pi}{2}}\pi[/tex]
You will need the above information to help you interpret the graph. So, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph hits [tex]\displaystyle [-5, 0],[/tex] from there to [tex]\displaystyle [-1, 0],[/tex] they are obviously [tex]\displaystyle 4\:units[/tex] apart, telling you that the period of the graph is [tex]\displaystyle 4.[/tex] Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = 0,[/tex] in which each crest is extended three units beyond the midline, hence, your amplitude. So, no matter how far the graph shifts vertically, the midline will ALWAYS follow.
I am delighted to assist you at any time.
I just need the numbers can anyone help me with this ??
Step-by-step explanation:
Hello!
In order to graph this, a point would have to go through (-6, 1). Then, since it says it needs a slope of 5 (or, to make things a bit easer, we could see it as 5/1) we'd need the next point to be 5 up and 1 across.
One possible solution:
(-6, 1) -> (-5, 6)
Please help explanation if possible
Answer:
Hello,
Step-by-step explanation:
slope of the line=3/7
slope of the perpendicular = -7/3
equation of the perpendicular:
y-3=(x-3)*(-7/3)
or
y=-7/3*x +7+3
or
y=-7/3*x+10
please answer this!!
The solution of this equation has an error. Which of the following steps has an error?
Step 1: -2x + 8 - 3x = 7
Step2:–5x+8=7
Step3:-5x = 15
Step4:
x = -3
O Step 2
O Step 1
O Step 3
3rd step
Solution:-
[tex]\\ \sf\longmapsto -2x+8-3x=7[/tex]
[tex]\\ \sf\longmapsto -2x-3x+8=7[/tex]
[tex]\\ \sf\longmapsto -5x+8=7[/tex]
[tex]\\ \sf\longmapsto -5x=7-8[/tex]
[tex]\\ \sf\longmapsto -5x=-1[/tex]
[tex]\\ \sf\longmapsto x=\dfrac{-1}{-5}[/tex]
[tex]\\ \sf\longmapsto x=\dfrac{1}{5}[/tex]
A boy is flying a kite from the terrace of his house. The kite is 175 m above the terrace. If the terrace is 80 m from the ground floor, findthe distance between the kite and the basement which is 8 m below the ground level.
175 m above the terrace + 80 m from terrace to ground + 8m from ground to basement:
175 + 80 + 8 = 263 meters
if the cost of 2:dozen copies is Rs 720 , find the cost of 72 copies .
Answer:
Rs 2160
Step-by-step explanation:
1 dozen = 12 copies
2 dozen = 24 copies ( 2*12)
72÷12 = 6 dozen
72 copies = 6 dozen
1 dozen = Rs 720÷2
1 dozen Rs 360
6 dozen = 360*6
6 dozen = 72 copies = Rs 2160
find the 10 degree value can u help me on it
Solution:-10
As <AGQ and <EQG are corresponding interior angles
[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow 60°+a=180[/tex]
[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow a=180-60[/tex]
[tex]\\ \qquad\quad\boxed{\sf{:}\twoheadrightarrow a=120}[/tex]
<AGQ=<PQR=60°<BHF=<PRQ=75°[tex]\\ \qquad\quad\boxed{\sf{:}\twoheadrightarrow b=75°}[/tex]
According to angle sum property
[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow b+c+<PQR=180[/tex]
[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow c+75+60=180[/tex]
[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow c+135=180[/tex]
[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow c=180-135[/tex]
[tex]\\ \qquad\quad\boxed{\sf{:}\twoheadrightarrow c=45°}[/tex]
Please help!!!.......thx
Step-by-step explanation:
sin and tan are the only ones with p positive valued
[tex]2 |3 \sqrt{2} - 2 \sqrt{3} | + |3 \sqrt{8} - 8 \sqrt{3} | + 2 \sqrt{12} [/tex]
.......................
Answer:
hope it helps
Step-by-step explanation:
Answer:
SEE THE IMAGE FOR SOLUTION..