The square root of 30

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Explanation:

The center is at (0,2). So (h,k) = (0,2) leads to h = 0 and k = 2.

The radius is 2 units, meaning r = 2.

Plug h = 0, k = 2, r = 2 into the formula below and simplify

[tex](x-h)^2 + (y-k)^2 = r^2\\\\(x-0)^2 + (y-2)^2 = 2^2\\\\x^2 + (y-2)^2 = 4[/tex]

Answer:

Step-by-step explanation:

Let the price for children and adults package be represented with x and y respectively.

For the first week the sum of the package will be as follows:

3x+8y = 126

For the two weeks after:

6x+4y= 108

So, we will be having two equations

3x+8y = 126..... (1)

6x+4y= 108.......(2)

These are simultaneous equations

From equation 1

3x+8y = 126

3x = 126-8y

X = 126-8y/3 ............. (3)

Put equation 3 into 2

6 ( 126-8y)/3 +4y = 108

756-48y/3 +4y = 108

756-48y+12y/3 = 108

Cross multiplying

756-48y+12y= 108×3

756-48y+ 12y = 324

Collecting like terms

756-324 = 48y-12y

432= 36y

Divide both sides by 36

432/36 = 36y/36

y= 12

Substituting y into equation 1

3x+8= 126

3x+96=126

3x= 126-96

3x= 30

Divide both sides by 3

3x/3 = 30/3

x = 10

Hence for each of the packages for children and adults. It will be 10 and 12 respectively.

Answer:

X=25

Step-by-step explanation:

Since these 2 angles are vertically opposite angles so they are equal. (rule)

75°=(4x-25°)

75° + 25° = 4x

100=4x

X=100/4 = 25

___________

Hope this helps...

Answer:

4.5 feet

Step-by-step explanation:

Here, we are concerned with calculating the actual height in feet of the door given the scale used in the maps drawing.

In the scale, scale to actual is 1 inch to 2.5 feet

let 1.8 inch scale = x actual feet

Thus mathematically, by cross multiplying; we have;

x = 2.5 * 1.8 = 4.5 feet

Answer:

No she won't

Step-by-step explanation:

200(0.30)=60

60(0.06)=3.6

60+3.6=63.6

75(0.06)=4.5

75+4.5=79.5

79.5+63.6=143.1

200-143.1=56.9

56.9<60

Answer:

h ≈ 2.64ft

Step-by-step explanation:

A = 2πrh + 2πr2

h= A /2πr﹣r = 240 /2·π·5﹣5 ≈ 2.63944ft

Kono Dio Da!!

Answer:

Step-by-step explanation:

Guven two prime numbers to be 31/x and 71/x, if their sum is 10 as given;

3x + 71/x = 10 then to find the value of x, the following steps must be taken;

Step 1

Find the LCM of the given equation;

3x + 71/x = 10

[tex]\frac{3x^{2}+71 }{x} =10\\[/tex]

Step 2:

Cross multiplying;

[tex]3x^{2} +71=10x\\3x^{2} -10x+71 =0\\[/tex]

Using the general formula to get the value of x;

x = -b±√b²-4ac/2a

a=3, b=-10, c=71

= 10±√(-10)²-4(3)(71)/2(3)

= 10±√100-852/6

= 10±√-752/6

= 10±27.4i/6

= 10+27.4i/6 or 10-27.4i/6

x = 5/3+27.4i/6 or 5/3-27.4i/6

Since the values of x are real values then, our answer will be the real part of the complex number gotten.

x = 5/3

Answer: 16

Step-by-step explanation:

[tex]x^2-8x+c[/tex]

Let's complete the square.

[tex]c=(\frac{b}{2})^2[/tex]

[tex]c=(\frac{-8}{2})^2[/tex]

[tex]c=(-4)^2\\ c=16[/tex]

The value c that completes the square for x²-8x+c is,

c = 4

We have to give that,

An equation is,

⇒ x² - 8x + c

Now, Complete the quadratic equation to square,

⇒ x² - 8x + c

⇒ x² - 2×2²×x + 4

⇒ x² - 8x + 4

⇒ (x - 2)²

Hence, The value c that completes the square for x²-8x+c is,

c = 4

Learn more about the quadratic equation visit:

brainly.com/question/1214333

#SPJ6

Answer:

Step-by-step explanation:

Nick's age = x years

Lina's age =3*x = 3x

After 6 years,

Lina's age = 3x + 6

Nick's age = x + 6

3x + 6 = 2*(x+6)

3x + 6 = 2*x + 2*6

3x + 6 = 2x + 12      {Subtract 6 form both sides}

3x +6 - 6 = 2x + 12 - 6

3x  = 2x + 6    {subtract 2x from both sides}

3x - 2x = 2x + 6 - 2x

x = 6

Nick's age = 6 years

Lina's age =3*6 = 18 years

Answer:

Lina is 18 and Nick is 6

Step-by-step explanation:

Answer: C. There is evidence that teachers at Woodlands Middle may prefer the aquarium more than students.

Step-by-step explanation:

The results of the poll showed that 50% of teachers preferred to go to the aquarium whilst only 20% of students prefer to go to the aquarium.

With 5 in every 10 teachers preferring to go to the aquarium and only 2 in every 10 students preferring the aquarium that is clear evidence that there are is a higher proportion of teachers wanting the aquarium than the students. This shows therefore that relatively speaking, teachers prefer the Aquarium more than students do.

The Answer is C. There is evidence that teachers at Woodlands Middle may prefer the aquarium more than students.

Step-by-step explanation:

I just did it

Answer:

30x2010x943

Step-by-step explanation:

219x29192

Answer:

0.007

Step-by-step explanation:

Answer:

A=2x^2+5x

Step-by-step explanation:

length of frame = 2x+5

width of frame = x

A=lw

A=(2x+5)x

A=2x^2+5x

Answer:

q < 5

Step-by-step explanation:

Answer:45

Step-by-step explanation:

Sin^-1= 5÷7

Answer:

8.66 meters

Step-by-step explanation:

Assuming that the building is completely straight, a right angle is formed and therefore a right triangle.

Thanks to this we can calculate the height at which the ladder reaches the wall using the Pythagorean theorem, this height being one of the legs.

We have to:

c ^ 2 = a ^ 2 + b ^ 2

c = 10

a = 5

replacing

b ^ 2 = 10 ^ 2 - 5 ^ 2

b ^ 2 = 75

b = 8.66

that is to say that the height at which the ladder reaches the wall is 8.66 meters

Answer:

50.32 I think

Step-by-step explanation:

52,13+50,32=102.45

Answer:

C

Step-by-step explanation:

Answer:

BGC

Step-by-step explanation:

They are both on a straight line and add up to 180 degrees.

Answer:

the correct answer is 9

A polynomial's degree is the highest total exponent in the polynomial.

Example: 5xy^2 has a degree of 3.

x has a exponent of 1 and y had a exponent of 2 so in total it is 3.

Answer:

144 (If multiplying)

Step-by-step explanation:

18x8=144.

Answer:

The position marked x is shown in the diagram/attachment

Step-by-step explanation:

So the university position is gotten relative to the the position of the stadium and hospital .

We go about this because if the given bearing.

The university is 50° from the stadium then 350° from the hospital.

I.e it is N 50° E from stadium and

N 60° W from hospital.

The angle It forms is 50+60 = 110°

The position is shown in the diagram.

Answer:

In the books of Wirtz, the selling party, the required entries are

Debit Accounts receivable $780

Credit Revenue $780

Being entries to recognize sales revenue on account

Debit Cost of sales $470

Credit Inventory  $470

Being entries to recognize the cost of items sold

In the books of Cha Company

Debit Inventory $780

Credit Accounts payable  $780

Being entries to record cost of inventory purchased

Step-by-step explanation:

When a company makes a sale, the effect of such sale is dual in the books of the company being that the company would first recognize revenue and then recognize the cost of items sold.

To recognize revenue,

Debit Cash/Accounts receivable

Credit Revenue

To record the cost of the item sold

Debit Cost of sales

Credit Inventory

For the party that makes the purchase

Debit Inventory

Credit Cash/Accounts payable

creo que la respuesta el 10 minutos, porque dice "horas" pero no dice a cuantas horas equivale :)      espero que te aya adudado auque sea un poquito

Answer:

Tim has $50. 15+15=30-35=5

Tim has $5 left

Answer:

1. (5·sin(A) - 3·cos(A)/(4·cos(A) + 5·sin(A))  = 1/8

2. θ = 30°

3. tan(θ) - cot(θ) = (2·sin²(θ) -1)/((cos(θ)×sin(θ))

from tan(θ) - 1/tan(θ) = sin(θ)/cos(θ) - cos(θ)/sin(θ) and sin²(θ) +  cos²(θ) = 1

4. tan10°·tan15°·tan75°·tan80°= 1 from;

sin(α)·sin(β) = 1/2[cos(α - β) - cos(α + β)]

cos(α)·cos(β) = 1/2[cos(α - β) + cos(α + β)]

5. x² + y² = a² + b² where x = a·cosθ - b·sinθ and y = a·sinθ + b·cosθ from;

cos²θ + sin²θ = 1

Step-by-step explanation:

1. Here we have 5·tan(A) = 5·sin(A)/cos(A) = 4

∴ 5·sin(A) = 4·cos(A)

Hence to find the value of (5·sin(A) - 3·cos(A)/(4·cos(A) + 5·sin(A)) we have;

Substituting the value for 5·sin(A) = 4·cos(A) into the above equation in both the numerator and denominator we have;

(4·cos(A) - 3·cos(A)/(4·cos(A) + 4·cos(A)) = cos(A)/(8·cos(A)) = 1/8

Therefore, (5·sin(A) - 3·cos(A)/(4·cos(A) + 5·sin(A)) = 1/8

2. For the equation as follows, we have

[tex]\frac{sin \theta}{1 + cos \theta} + \frac{1 + cos \theta}{sin \theta} = 4[/tex] this gives

[tex]\frac{2sin (\theta/2) cos (\theta/2) }{2 cos^2 (\theta/2)} + \frac{2 cos^2 (\theta/2)}{2sin (\theta/2) cos (\theta/2) } = 4[/tex]

[tex]tan\frac{\theta}{2} + \frac{1}{tan\frac{\theta}{2} } = 4[/tex]

[tex]tan^2\frac{\theta}{2} + 1 = 4\times tan\frac{\theta}{2}[/tex]

[tex]tan^2\frac{\theta}{2} - 4\cdot tan\frac{\theta}{2} + 1 = 0[/tex]

We place;

[tex]tan\frac{\theta}{2} = x[/tex]

∴ x² - 4·x + 1 = 0

Factorizing we have

(x - (2 - √3))·(x - (2 + √3))

Therefore, tan(θ/2) = (2 - √3) or (2 + √3)

Solving, we have;

θ/2 = tan⁻¹(2 - √3) or tan⁻¹(2 + √3)

Which gives, θ/2 = 15° or 75°

Hence, θ = 30° or 150°

Since 0° < θ < 90°, therefore, θ = 30°

3. We have tan(θ) - cot(θ) = tan(θ) - 1/tan(θ)

Hence, tan(θ) - 1/tan(θ) = sin(θ)/cos(θ) - cos(θ)/sin(θ)

∴  tan(θ) - 1/tan(θ) = (sin²(θ) -  cos²(θ))/(cos(θ)×sin(θ))...........(1)

From sin²(θ) +  cos²(θ) = 1, we have;

cos²(θ) = 1 - sin²(θ), substituting the value of sin²(θ) in the equation (1) above, we have;

(sin²(θ) -  (1 - sin²(θ)))/(cos(θ)×sin(θ)) = (2·sin²(θ) -1)/((cos(θ)×sin(θ))

Therefore;

tan(θ) - cot(θ) = (2·sin²(θ) -1)/((cos(θ)×sin(θ))

4. tan10°·tan15°·tan75°·tan80°= 1

Here we have since;

sin(α)·sin(β) = 1/2[cos(α - β) - cos(α + β)]

cos(α)·cos(β) = 1/2[cos(α - β) + cos(α + β)]

Then;

tan 10°·tan15°·tan75°·tan80° = tan 10°·tan80°·tan15°·tan75°

tan 10°·tan80°·tan15°·tan75° = [tex]\frac{sin(10^{\circ})}{cos(10^{\circ})} \times \frac{sin(80^{\circ})}{cos(80^{\circ})} \times \frac{sin(15^{\circ})}{cos(15^{\circ})} \times \frac{sin(75^{\circ})}{cos(75^{\circ})}[/tex]

Which gives;

[tex]\frac{sin(10^{\circ}) \cdot sin(80^{\circ})}{cos(10^{\circ})\cdot cos(80^{\circ})} \times \frac{sin(15^{\circ}) \cdot sin(75^{\circ})}{cos(15^{\circ})\cdot cos(75^{\circ})}[/tex]

[tex]=\frac{1/2[cos(80 - 10) - cos(80 + 10)]}{1/2[cos(80 - 10) + cos(80 + 10)]} \times \frac{1/2[cos(75 - 15) - cos(75 + 15)]}{1/2[cos(75 - 15) + cos(75 + 15)]}[/tex]

[tex]=\frac{1/2[cos(70) - cos(90)]}{1/2[cos(70) + cos(90)]} \times \frac{1/2[cos(60) - cos(90)]}{1/2[cos(60) + cos(90)]}[/tex]

[tex]=\frac{[cos(70)]}{[cos(70) ]} \times \frac{[cos(60)]}{[cos(60) ]} =1[/tex]

5. If x = a·cosθ - b·sinθ and y = a·sinθ + b·cosθ

∴ x² + y² = (a·cosθ - b·sinθ)² + (a·sinθ + b·cosθ)²

= a²·cos²θ - 2·a·cosθ·b·sinθ +b²·sin²θ + a²·sin²θ + 2·a·sinθ·b·cosθ + b²·cos²θ

= a²·cos²θ + b²·sin²θ + a²·sin²θ + b²·cos²θ

= a²·cos²θ + b²·cos²θ + b²·sin²θ + a²·sin²θ

= (a² + b²)·cos²θ + (a² + b²)·sin²θ

= (a² + b²)·(cos²θ + sin²θ) since cos²θ + sin²θ = 1, we have

= (a² + b²)×1 = a² + b²

Answer:

a

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

Answer:

-0.954(rounded)

Step-by-step explanation:

first write it in number form

√2(3)-√27

the exact form will be 3√2-3√27 = -0.954(rounded)

Answer:

55% probability of getting a purple marble if you take a marble out of the bag

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

In this question, we have that:

20 marbles.

6 are red.

3 are green

The rest(x) are purple.

So

6 + 3 + x = 20

x = 11

20 marbles, of which 11 are purple.

11/20 = 0.55

55% probability of getting a purple marble if you take a marble out of the bag

Answer:

distance = sqrt((x2-x1)^2 + (y2-y1))

distance = sqrt((7-13)^2 + (10-2)^2)

distance = sqrt( -6^2 + 8^2)

distance = sqrt(36+64)

distance = 10

Step-by-step explanation:

Answer:

10 units

Step-by-step explanation:

d = [tex]\sqrt{(x2 - x1)^2 + (y2 - y1)^2}[/tex]

d = [tex]\sqrt{(13 - 7)^2 + (2 - 10)^2}[/tex]

d = [tex]\sqrt{(6)^2 + (-8)^2}[/tex]

d = [tex]\sqrt{36 + 64}[/tex]

d = [tex]\sqrt{100}[/tex]

d = 10 units