The slope of a d vs t graph represents velocity. Describe 3 ways you know this to be true.

Answers

Answer 1

Answer:

Look at explanation

Explanation:

I only know 1 way, there is another way you can rephrase this using derivatives but that's pretty much the same thing.

The slope is calculated by Δy/Δx so the slope of distance vs time graph is Δd/Δt which is the velocity


Related Questions

A smooth circular hoop with a radius of 0.400 m is placed flat on the floor. A 0.325-kg particle slides around the inside edge of the hoop. The particle is given an initial speed of 8.50 m/s. After one revolution, its speed has dropped to 5.50 m/s because of friction with the floor.
(a) Find the energy transformed from mechanical to internal in the particle "hoop" floor system as a result of friction in one revolution.
(b) What is the total number of revolutions the particle makes before stopping? Assume the friction force remains constant during the entire motion.

Answers

Answer:

a)  W = - 6.825 J,  b) θ = 1.72 revolution

Explanation:

a) In this exercise the work of the friction force is negative and is equal to the variation of the kinetic energy of the particle

         W = ΔK

         W = K_f - K₀

          W = ½ m v_f² - ½ m v₀²

         W = ½ 0.325 (5.5² - 8.5²)

         W = - 6.825 J

b) find us the coefficient of friction

Let's use Newton's second law

            fr = μ N

y-axis (vertical)   N-W = 0

            fr = μ W

work is defined by

             W = F d

the distance traveled in a revolution is

             d₀ = 2π r

             W = μ mg d₀ = -6.825

            μ = [tex]\frac{ -6.825}{d_o \ mg}[/tex]

               

The total work as the object stops the final velocity is zero v_f = 0

         W = 0 - ½ m v₀²

          W = - ½ 0.325 8.5²

          W = - 11.74 J

           μ mg d = -11.74

           

we subtitle the friction coefficient value

           ( [tex]\frac{-6.8525 }{d_o mg}[/tex]) m g d = -11.74

               6.825  [tex]\frac{d}{d_o}[/tex] = 11.74

               d = 11.74/6.825  d₀

               d = 1.7201  2π 0.400

               d = 4.32 m

this is the total distance traveled, the distance and the angle are related

              θ = d / r

              θ = 4.32 / 0.40

              θ = 10.808 rad

we reduce to revolutions

              θ = 10.808 rad (1rev / 2π rad)

              θ = 1.72 revolution

During the data transmission there are chances that the data bits in the frame might get corrupted. This will require the sender to re-transmit the frame and hence it will increase the re-transmission overhead. By considering the scenarios given below, you have to choose whether the packets should be encapsulated in a single frame or multiple frames in order to minimize the re-transmission overhead.


Justify your answer with one valid reason for both the scenarios given below.


Scenario A: Suppose you are using a network which is very prone to errors.


Scenario B: Suppose you are using a network with high reliability and accuracy.

Answers

1. Based on Scenario A, multiple frames will minimize re-transmission overhead and should be preferred in the encapsulation of packets.

2. Based on Scenario B, the encapsulation of packets should be in a single frame because of the high level of network reliability and accuracy.

 

Justification:

There will not be further need to re-transmit the packets in a highly reliable and accurate network environment, unlike in an environment that is very prone to errors.  The reliable and accurate network environment makes a single frame economically better.

Encapsulation involves the process of wrapping code and data together within a class so that data is protected and access to code is restricted.

With encapsulation, each layer:

provides a service to the layer above itcommunicates with a corresponding receiving node

Thus, in a reliable and accurate network environment, single frames should be used to enhance transmission and minimize re-transmission overhead.  This is unlike in an environment that is very prone to errors, where multiple frames should rather be used to minimize re-transmission overhead.

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Consider two closely spaced and oppositely charged parallel metal plates. The plates are square with sides of length L and carry charges Q and -Q on their facing surfaces. What is the magnitude of the electric field in the region between the plates

Answers

Answer:

  E_ {total} = [tex]\frac{Q }{L^2 \epsilon_o}[/tex]

Explanation:

In this exercise you are asked to calculate the electric field between two plates, the electric field is a vector

         E_ {total} = E₁ + E₂

         E_ {total} = 2 E

where E₁ and E₂ are the fields of each plate, we have used that for the positively charged plate the field is outgoing and for the negatively charged plate the field is incoming, therefore in the space between the plates for a test charge the two fields point in the same direction

to calculate the field created by a plate let's use Gauss's law

          Ф = ∫ E . dA = q_{int} /ε₀

As a Gaussian surface we use a cylinder with the base parallel to the plate, therefore the direction of the electric field and the normal to the surface are parallel, therefore the scalar product is reduced to the algebraic product.

           E 2A = q_{int} / ε₀

where the 2 is due to the surface has two faces

indicate that the surface has a uniform charge for which we can define a surface density

           σ = q_{int} / A

           q_{int} = σ A

we substitute

           E 2A = σ A /ε₀

           E = σ / 2ε₀  

therefore the total field is

           E_ {total} = σ /ε₀

let's substitute the density for the charge of the whole plate

           σ= Q / L²

           

            E_ {total} = [tex]\frac{Q }{L^2 \epsilon_o}[/tex]

A single force acts on a particle situated on the positive x axis. The torque about the origin is in the negative z direction. The force might be:_______.
A. in the positive y direction
B. in the negative y direction
C. in the positive x direction
D. in the negative x direction

Answers

C maybe don’t count on it 100%

A single force acts on a particle situated on the positive x axis. The torque about the origin is in the negative z direction. The force might be in the negative y direction. Thus, option B is correct.

To determine the force that could generate a torque in the negative z direction, we need to consider the right-hand rule for cross products. The torque vector, denoted by τ, is given by the cross product of the position vector, r, and the force vector, F:

[tex]τ = r × F[/tex]

In this case, the position vector, r, points along the positive x-axis. The negative z-direction torque indicates that the force vector must be perpendicular to both the position vector and the negative z-axis.

Using the right-hand rule, we can determine that the force vector must be in the negative y-direction, which is option B.

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calculate horizontal distance travelled by a ball travelling with a speed of 20root2 mper sec without hitting ceiling of height 20 m per sec​

Answers

Calculate the horizontal distance travelled by a ball throw with a velcoity 20 sqrt 2 ms^(-1) without hitting the ceiling of an anditorium of heith 20 m. Use g= 10 ms^(-2). =(20√2)2sin2×45∘10=9800×1)10=80m .

HOPE SO IT HELPS YOU

The mass flow rate through a centrifugal compressor is 1 kg/s. If air enters at 1 bar and 288k and leaves at 200 kN/m² and 370k, determine the power of the compressor. Take Cp = 1.103 kJ (kg.K), R = 287 kJ (kg.k)​

Answers

We have that the power of the compressor is

[tex]H_p=24.242hp[/tex]

From the question we are told that:

Flow rate [tex]W=1kg/s[/tex]

inlet Pressure [tex]P_1=1 bar[/tex]

inlet Temperature [tex]T_1= 288k[/tex]

Outlet Temperature [tex]T_2= 370k[/tex]

Outlet Pressure [tex]P_2=200 kN/m^2=2bars[/tex]

[tex]Cp = 1.103 kJ[/tex]

[tex]R = 287 kJ (kg.k)​[/tex]

Generally, the equation for Adiabatic head  is mathematically given by

[tex]H=\frac{ZRT_1}{Cp-1/K}[\frac{P_2}{P_1}^{(Cp-1)/Cp}-1][/tex]

Where

[tex]Z=Compressibility\ factor[/tex]

[tex]Z=0.99[/tex]

Therefore

[tex]H=\frac{(0.99)(287)(288)}{(1.103)-1/(1.103)}[\frac{(200)}{(1)}^{((1.103)-1)/(1.103)}-1][/tex]

[tex]H=560925.5958 J/kg[/tex]

[tex]H=5.6*10^5J/kg[/tex]

Generally, the equation for centrifugal compressor power  is mathematically given by

[tex]H_p=\frac{WH}{E*33000}[/tex]

Where

E is efficiency (adiabatic)

[tex]E=70\%=0.7[/tex]

Therefore

[tex]H_p=\frac{(1)(5.6*10^5)}{0.7*33000}[/tex]

[tex]H_p=24.242hp[/tex]

In conclusion

The power of the compressor is

[tex]H_p=24.242hp[/tex]

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27. The part of the Earth where life exists .

Mesosphere
Stratosphere
Troposphere
Biosphere

Answers

Answer:

Biosphere is the part of the earth where life exists.

The resistance of the light bulb changed as the voltage (and current) changed. Why does this resistance change occur?

Answers

This resistance current is directly proportional to voltage and inversely proportional to resistance. In other words, as the voltage increases, so does the current. Hope this helps !!

The magnetic flux that passes through one turn of a 8-turn coil of wire changes to 5.0 Wb from 8.0 Wb in a time of 0.098 s. The average induced current in the coil is 140 A. What is the resistance of the wire

Answers

Answer:

Resistance is 1.75 ohms

Explanation:

Magnetic flux:

[tex]{ \phi{ = NBA}}[/tex]

N is number of turns, N = 8

B is magnetic flux

A is area of projection.

From faradays law:

[tex]E = - \frac{ \triangle \phi}{t} [/tex]

where E is the Electro motive force.

But E = IR

where I is current and R is resistance:

[tex]IR = \frac{( \phi_{1} - \phi _{2}) }{t} \\ \\ 140 \times R = \frac{8 \times (8 - 5)}{0.098} \\ \\ R = \frac{24}{0.098 \times 140} \\ \\ resistance = 1.75 \: ohms[/tex]

If a body travels 6km in 30 minutes in a fixed direction, calculate it's velocity.
Plz show me the process too.

Answers

Distance=6kmTime=30min=1/2h

We know

[tex]\boxed{\large{\sf Velocity=\dfrac{Distance}{Time}}}[/tex]

[tex]\\ \Large\sf\longmapsto Velocity=\dfrac{6}{\dfrac{1}{2}}[/tex]

[tex]\\ \Large\sf\longmapsto Velocity=6\times 2[/tex]

[tex]\\ \Large\sf\longmapsto Velocity=12km/h[/tex]

Is this the right answer??

We should keep km and min in smallest SI unit

An electron is moving through a magnetic field whose magnitude is 83 x 10-5 T. The electron experiences only a magnetic force and has an acceleration of magnitude 34 x 10+13 m/s2. At a certain instant, it has a speed of 72 x 10+5 m/s. Determine the angle (less than 90°) between the electron's velocity and the magnetic field.

Answers

Answer:

the angle between the electron's velocity and the magnetic field is 19⁰

Explanation:

Given;

magnitude of the magnetic field, B = 83 x 10⁻⁵ T

acceleration of the electron, a = 34 x 10¹³ m/s²

speed of the electron, v = 72 x 10⁵ m/s

mass of electron, m = 9.11 x 10⁻³¹ kg

The magnetic force experienced by the electron is calculated as;

F = ma = qvB sinθ

where;

q is charge of electron = 1.602 x 10⁻¹⁹ C

θ is the angle between the electron's velocity and the magnetic field.

[tex]sin(\theta ) = \frac{ma}{qvB} \\\\sin(\theta ) = \frac{(9.11\times 10^{-31})(34\times 10^{13})}{(1.602\times 10^{-19})\times (72\times 10^5) \times (83 \times 10^{-5})} \\\\sin(\theta ) = 0.3235\\\\\theta =sin^{-1}(0.3235)\\\\\theta =18.9^0[/tex]

[tex]\theta \approx 19^ 0[/tex]

Therefore, the angle between the electron's velocity and the magnetic field is 19⁰

A 80 kg bungee jumper is on a bridge that is 100 meters above a river. Attached to the jumper is a bungee cord that is 50 meters long. After jumping off of the bridge, the jumper reaches a position that is 10 meters above the river when the bungee cord is at its maximum stretch.

Required:
a. How much energy is stored in the bungee cord at that maximum stretch?
b. What is the spring force constant of the bungee cord?

Answers

Answer:

a) 70,560 J

b) 88.2 N/m

Explanation:

The spring potential will equal the change in gravity potential

PS = PE = mgh = 80(9.8)(100 - 10) = 70,560 J

PS = ½kx²

k = 2PS/x² = 2(70560)/(100 - 50 - 10)² = 88.2 N/m

A racing car going a 20 m/s stops in a distance of 20 m.What is its acceleration?​

Answers

step by step

formular v^2 = u^2+2as

stop v = 0

0 = 400+2a(20)

-400=40a

a = -10 m/s^2

ans affect acceleration is 10 m/s^2

Tay quay OB quay đều quanh trục cố định đi qua O với vận tốc góc không đổi ω. Con lăn A chuyển động trong rãnh thẳng đứng. Tại vị trí trên hình vẽ thì thanh OB thẳng đứng, OA có phương nằm ngang. Hãy xác định vận tốc góc thanh AB, vận tốc của con lăn A; gia tốc góc của thanh AB, gia tốc của con lăn A. Cho ω = 1,5 rad/s, r = 1 m.

Answers

sorry don’t understand your language.

Liquid plastic is frozen in a physical change that increases its volume. What can be known about the plastic after the change?
(A) Its mass will increase.
(B) Its density will increase.
(C) Its mass will remain the same.
(D) Its density will remain the same.

Answers

Answer:

c

Explanation:

Liquid plastic is frozen in a physical change that increases its volume,it can be known about the plastic that Its mass will remain the same, therefore the correct answer is option C.

What is the matter?

Anything which has mass and occupies space is known as matter ,mainly there are four states of matter solid liquid gases, and plasma.

These different states of matter have different characteristics according to which they vary their volume and shape.

It is known about plastic that its mass will remain the same when liquid plastic is frozen, by increasing its volume.

Liquid plastic is frozen in a physical change that increases its volume,it can be known about the plastic that Its mass will remain the same,  therefore the correct answer is C.

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Calculate the potential energy stored in a metal ball of a mass of 80 kg kept at a height of 15m from the earth surface.What will be the potential energy when the metal ball is kept on the earth surface.​

Answers

Answer:

39200 joules

the potential energy will be zero

Explanation:

we know that potential energy is found by multiplying mass, acceleration due to gravity and height from the Earth's surface

so it will be

potential energy= mgh

80x9.8x15

= 39200 joules

the potential energy of the mental ball will be zero when kept on the Earth's surface because the height from the Earth's surface will be zero and zero multiplied to any number is zero only

I have a doubt with the second one, this is what I think it is. Consult your teacher if you think my answer for the second one is wrong

Answer:

392000 joules

Explanation:

hope it helpsss

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Use base units to check whether the following equations are balance
(a) pressure = depth x density gravitational field strength,
(b) energy = mass x (speed of light).
dod to molt solid

Answers

Answer:

In a column of fluid, pressure increases with depth as a result of the weight of the overlying fluid. Thus a column of fluid, or an object submerged in the fluid, experiences greater pressure at the bottom of the column than at the top. This difference in pressure results in a net force that tends to accelerate an object upwards.

The pressure at a depth in a fluid of constant density is equal to the pressure of the atmosphere plus the pressure due to the weight of the fluid, or p = p 0 + ρ h g , p = p 0 + ρ h g , 14.4

Granite: 2.70 × 10 32.70 × 10 3

Lead: 1.13 × 10 41.13 × 10 4

Iron: 7.86 × 10 37.86 × 10 3

Oak: 7.10 × 10 27.10 × 10 2

A 10 n force is applied horizontally on a box to move it 10 m across a frictionless surface. How much work was done to move the box?

Answers

Given from question
Force = 10 N
Displacement = 10 m
Work done = ?
We know that
Work done = force X displacement
So 10 X 10
100
Work done = 100J answer

Answer:

[tex]\boxed {\boxed {\sf 100 \ J}}[/tex]

Explanation:

We are asked to calculate the work done to move a box.

Work is the product of force and distance or displacement.

[tex]W= F*d[/tex]

A 10 Newton force is applied horizontally on the box. Since the surface is frictionless, there is no force of friction, and the net force is 10 Newtons. The force moves the box 10 meters.

F= 10  N d= 10 m

Substitute the values into the formula.

[tex]W= 10 \ N * 10 \ m[/tex]

Multiply.

[tex]W= 100 \ N*m[/tex]

Let's convert the units. 1 Newton meter is equal to 1 Joule, therefore our answer of 100 Newton meters is equal to 100 Joules.

[tex]W= 100 \ J[/tex]

100 Joules of work was done to move the box.

1 hallar el trabajo mecanico de un cuerpo que tiene una fuerza de 250 newton y recorre 750 metros

2 hallar la potencia necesaria para levantar un transformador de masa 2500kg,una altura de 4 metros en un tiempo de 30 segundos
porfa es para hoy

Answers

Answer: TRACK

Explanation:

Need help with this one! Thank you xoxo!

Answers

Answer:

it's electron attraction

The answer is Electron Attraction

what is liquid pressure? and tell me its si unit please ​

Answers

The SI unit of pressure is the pascal: 1Pa=1N/m2 1 Pa = 1 N/m 2 . Pressure due to the weight of a liquid of constant density is given by p=ρgh p = ρ g h , where p is the pressure, h is the depth of the liquid, ρ is the density of the liquid, and g is the acceleration due to gravity.

Katie swings a ball around her head at constant speed in a horizontal circle with circumference 2.1 m. What is the work done on the ball by the 34.4 N tension force in the string during one half-revolution of the ball

Answers

Answer:

the work done on the ball is 0

Explanation:

Given the data in the question;

Katie swings a ball around her head at constant speed in a horizontal circle with circumference 2.1 m.

circle circumference = 2πr = 2.1 m

radius r will be; r = 2.1 m / 2π = 0.33 m

Tension force = 34.4 N

one half revolution means, displacement of the ball is;

d = 2r = 2 × 0.33 = 0.66 m

Now, Work done = force × displacement × cosθ

we know that, the angle between the tension force on string and displacement of object is always 90.

so we substitute

Work done = 34.4 N × 0.66 m × cos(90)

Work done = 34.4 N × 0.66 m × 0

Work done = 0 J

Therefore,  the work done on the ball is 0

A rectangular loop of wire with sides 0.129 and 0.402 m lies in a plane perpendicular to a constant magnetic field (see part a of the drawing). The magnetic field has a magnitude of 0.888 T and is directed parallel to the normal of the loop's surface. In a time of 0.172 s, one-half of the loop is then folded back onto the other half, as indicated in part b of the drawing. Determine the magnitude of the average emf induced in the loop.

Answers

Answer:

[tex]0.2677\ \text{V/m}[/tex]

Explanation:

A = Area of loop = [tex]0.129\times0.402[/tex]

B = Magnetic field = [tex]0.888\ \text{T}[/tex]

t = Time taken = [tex]0.172\ \text{s}[/tex]

Electric field is given by

[tex]E=B\dfrac{dA}{dt}\\\Rightarrow E=0.888\times\dfrac{0.129\times 0.402}{0.172}\\\Rightarrow E=0.2677\ \text{V/m}[/tex]

The emf induced is [tex]0.2677\ \text{V/m}[/tex].


In the diagram, the amplitude of the wave is shown by:

A
B
C
D

Answers

Answer:

A.

Explanation:

Amplitude measures how much a wave rises or falls. This is illustrated by A.

In the diagram, the amplitude of the wave is shown by A.

What is Amplitude?The amplitude of a periodic variable is a measure of its change in a single period. The amplitude of a non-periodic signal is its magnitude compared with a reference value.

There are various definitions of amplitude, which are all functions of the magnitude of the differences between the variable's extreme values.

The amplitude of a variable is simply a measure of change relative to its central position. In contrast, magnitude is a measure of the distance or quantity of a variable irrespective of its direction.

Amplitude is a property that is unique to waves and oscillations.

Therefore, in the diagram, the amplitude of a wave is shown by A.

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A conductor is placed in a steady external electric field. Which of the following is FALSE?
a) All excess charge is distributed on the surface of the conductor
b) The electric field inside the conductor is the same as the external electric field
c) The electric field is zero inside the conductor
d) the electric field just outside the surface of the conductor is perpendicular to the surface

Answers

Answer:

a

Explanation:

because the electric field doesn't effect the conductor and its goes into storage for later

(b) State the unit of volume in S.I. system and define it. 4.​

Answers

Answer:

the cubic meter (m3)

Explanation:

Volume is the measure of the 3-dimensional space occupied by matter, or enclosed by a surface, measured in cubic units. The SI unit of volume is the cubic meter (m3),

Answer:

please answer all  component's

Explanation:

please answer all  component's

Who should you invite to the meeting?

—-

Answers

Answer

Irma

Explanation:

You should invite Irma to the meeting because she is in Charlotte and she also visited after 10/24/20

You attach a 2.30 kg weight to a horizontal spring that is fixed at one end. You pull the weight until the spring is stretched by 0.500 m and release it from rest. Assume the weight slides on a horizontal surface with negligible friction. The weight reaches a speed of zero again 0.400 s after release (for the first time after release). What is the maximum speed of the weight (in m/s)

Answers

Answer: [tex]3.92\ m/s[/tex]

Explanation:

Given

Mass of the attached object is [tex]m=2.3\ kg[/tex]

Spring is stretched by [tex]A=0.5\ m[/tex]

Speed reaches zero after [tex]t=0.4\ s[/tex]

Speed is zero at the extremities of the S.H.M motion that is

[tex]\Rightarrow \dfrac{T}{2}=0.4\\\\\Rightarrow T=0.8\ s[/tex]

Time period of motion is [tex]0.8\ s[/tex] which can also be given by

[tex]\Rightarrow \omega T=2\pi\\\\\Rightarrow \omega=\dfrac{2\pi }{T}\\\\\Rightarrow \omega =\dfrac{2\pi }{0.8}\\\\\Rightarrow \omega=\dfrac{5\pi }{2}[/tex]

Maximum speed for S.H.M. is [tex]v_{max}=A\omega[/tex]

[tex]\Rightarrow v_{max}=0.5\times 2.5\pi\\\Rightarrow v_{max}=3.92\ m/s[/tex]

Although human beings have been able to fly hundreds of thousands of miles into outer space, getting inside the earth has proven much more difficult. The deepest mines ever drilled are only about 10 miles deep. To illustrate the difficulties associated with such drilling, consider the following: The density of steel is about 7900 kilograms per cubic meter, and its breaking stress, defined as the maximum stress the material can bear without deteriorating, is about 2.0×1092.0×109 pascals. What is the maximum length of a steel cable that can be lowered into a mine? Assume that the magnitude of the acceleration due to gravity remains constant at 9.8 meters per second per second.
Use two significant figures in your answer, expressed in kilometers.

Answers

Answer:

26 km

Explanation:

Let's say our "cable" has a cross section of 1 m²

Then each meter of cable would weight 7900(9.8) = 77420 N

A Pascal is a Newton per square meter

2 x 10⁹ / 77420 = 25840 m or about 26 km or about 16 miles

A chair of weight 85.0 N lies atop a horizontal floor; the floor is not frictionless. You push on the chair with a force of F = 40.0 N directed at an angle of 35.0deg below the horizontal and the chair slides along the floor.
Using Newton's laws, calculate n, the magnitude of the normal force that the floor exerts on the chair.

Answers

Answer:

 N = 107.94 N

Explanation:

For this exercise we must use Newton's second law.

Let's set a reference system with the x-axis parallel to the ground and the y-axis vertical

X axis

        Fₓ = ma

ej and

       N -F_y - W = 0

let's use trigonometry to decompose the applied force

     cos -35 = Fₓ / F

     sin -35 = F_y / F

     Fₓ = F cos -35

     F_y = F sin -35

     Fₓ = 40.0 cos -35 = 32.766 N

     F_y = 40.0 sin -35 = -22.94 N

we substitute

     N = Fy + W

     N = 22.94 + 85

     N = 107.94 N

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In cats, orange vs black fur is controlled by a single x-linked gene. The orange and black alleles are codominant; the intermediate phenotype is tortoiseshell.-------------------------------------------------------------------------------------------------------------------A mother and father cat have 6 kittens: two orange females, two tortoiseshell females, and two black males.a. What is the mother cat's phenotype? a) blackb) orangec) tortoise shelld) impossibleb. What is the father cat's phenotype? a) blackb) orangec) tortoise shelld) impossiblec. What is the fourth possible phenotype for their offspring?a) black femaleb) orange male c) tortoise shell maled) they already had all the offspring with possible phenotypes Find the imagine of (x-1 ,y -8 ) The mass of a single tantalum atom is 3.0110-22 grams. How many tantalum atoms would there be in 37.1 milligrams of tantalum? explain water cycle with the help of diagram Help pls!!! For groups 13 through 18, the number of valence electrons is equal to the group numbera. minus 10b. minus the period number c. plus 1d. plus the period number The driving distance between Manchester and London is 195 miles. Farris wants to travel from Manchester to London on coach. The coach will leave Manchester at 3:30pm. Farris assumes the coach will travel at an average speed of 50mph. work out Farris's arrival time in London? A bricklayer needs to order 6 300 kg of building sand.a) Write 6 300 kg in grams, giving your answer in standard form.One grain of this sand approximately weighs 7 x 10g.b) How many grains of sand are there in 6 300 kg of sand? Give your answer in standard from. You work at Happy Joe's family restaurant and want to see if customer meal satisfaction and gender are related to one another. You take a sample of customers and ask them if they were satisfied with their meal and note their gender. To determine if Satisfaction and Gender are dependent, what are the appropriate hypotheses Describe the thickness of the uterus lining duringmenstruation process. A sweater is on sale for $45.00, down from $75.00. What is the percent of discount of the sweater?A. 50%B. 30%C. 55%D. 40% which of the following is most likely the next step in the series? What is the primary languagespoken in West African nations?A. SwahiliB. YorubaC. Zulu If anyone can assist with a step by step Ron has a family history of high blood pressure. He has studied the causes, signs, and possible outcomes of the disease. What kind of strategy has he used to improve his health?A. He has found immediate and cumulative risks.B. He has set long-term and short-term goals.C. He has incorporated risk reduction into his life.D. He has increased his knowledge. How much money would be in an account that starts with $125 and earns 2% interest a year over 3 years LOOKING FOR A GOOD UNDERSTANDING EXPLAINING PLEASE Prepare journal entries for each transaction and identify the financial statement impact of each entry.The financial statements are automatically generated based on the journal entries recorded.Assume Adams Services began the year with the following balances: Cash, $41,000;Accounts receivable, $11,200; and Common stock, $52,200.Jan. 1 Leslie Adams invested $21,200 cash in the company in exchange for common stock.Jan. 2 The company provided services to a client and immediately received $4,500 cash.Jan. 3 The company received $11,200 cash from a client in payment for services to be provided next year.Jan. 4 The company received $5,900 cash from a client in partial payment of accounts receivable.Jan. 5 The company borrowed $11,000 cash from the bank by signing a note payable. THE VOYAGES OF DOCTOR DOLITTLEBy Hugh LoftingChapter 1: The Cobbler's SonMy name was Tommy Stubbins, son of Jacob Stubbins, the cobbler of Puddleby-on-the-Marsh; and I was nine and a half years old. At that time Puddleby was only quite a small town. A river ran through the middle of it; and over this river there was a very old stone bridge, called Kingsbridge, which led you from the market-place on one side to the churchyard on the other.Sailing-ships came up this river from the sea and anchored near the bridge. I used to go down and watch the sailors unloading the ships upon the river-wall. The sailors sang strange songs as they pulled upon the ropes; and I learned these songs by heart. And I would sit on the river-wall with my feet dangling over the water and sing with the men, pretending to myself that I too was a sailor.For I longed always to sail away with those brave ships when they turned their backs on Puddleby Church and went creeping down the river again, across the wide lonely marshes to the sea. I longed to go with them out into the world to seek my fortune in foreign landsAfrica, India, China and Peru! When they got round the bend in the river and the water was hidden from view, you could still see their huge brown sails towering over the roofs of the town, moving onward slowlylike some gentle giants that walked among the houses without noise. What strange things would they have seen, I wondered, when next they came back to anchor at Kingsbridge! And, dreaming of the lands I had never seen, I'd sit on there, watching till they were out of sight.Which of the following best summarizes the main point of the plot as presented in the excerpt of "The Cobbler's Son"? (6 points)Tommy had little hope of escaping his quiet life.Tommy learned strange songs from sailors in his youth.Tommy hoped to live a life of adventure in his youth.Tommy lived in a quaint, small village in his youth. Write the balanced half-equations for silver + oxygen= silver oxide: V. Rewrite the sentences with the same meaning as the original ones.1. She is the fastest runner in this group.=No one...................2. This is the most moving sight I have ever seen.=I have never...............=I have..............=I have................=I have.............3. She spends half an hour a day reading novels.=It takes...........4. They started selling flowers sixteen years ago.=They............=They...........=They...........5. I offer to make some coffee.=Would..........=would.........=Do.......=Do.......=Shall.........6. Why don't we take a short break?=How...........=What..........=Why..........=Let's.......=Shall.........7. How much are the spoons?=What.........3. She likes skiing.=She is.......=She is.........=She is...........9. She didn't find it hard to run 100 meters in 10 seconds.=She .......... An investor has an account with stock from two different companies. Last year, herstock in Company A was worth $1850 and her stock in Company B was worth $2280.The stock in Company A has decreased 2% since last year and the stock in CompanyB has decreased 25%. What was the total percentage decrease in the investor's stockaccount? Round your answer to the nearest tenth (if necessary).