Answer:
see below
Step-by-step explanation:
For the first question, you should multiply the scale dimension by 30 to get the actual dimension. This is because the scale is 1:30 where the scale dimension is the 1 and the actual dimension is 30, so therefore, the scale dimension is 1/30th of the actual dimension, so to get the actual dimension, we can multiply the scale dimension by 30. I'm not totally sure how to attach pictures from my phone on my computer (sorry) but an example of a drawing could be two rectangles, the first (this is the scale drawing) having dimensions of 1 by 2 units and the second (this is the actual drawing) having dimensions of 30 by 60 units. I hope this helps!
Suppose that the function g is defined, for all real numbers, as follows.
find g(-5) g(1) g(4)
=================================================
Explanation:
The piecewise function shows that we have two cases. Either x = 1 or [tex]x \ne 1[/tex].
If x = 1, then g(x) = 3 as shown in the bottom row. This is why g(1) = 3.
If [tex]x \ne 1[/tex], then g(x) = (1/4)x^2-4
Plug x = -5 into this second definition
g(x) = (1/4)x^2-4
g(-5) = (1/4)(-5)^2-4
g(-5) = (1/4)(25)-4
g(-5) = 25/4 - 4
g(-5) = 25/4 - 16/4
g(-5) = 9/4
Repeat for x = 4
g(x) = (1/4)x^2-4
g(4) = (1/4)(4)^2-4
g(4) = (1/4)(16)-4
g(4) = 4-4
g(4) = 0
The value of the function at x = -5, x = 1, and x = 4 will be 2.25, 3, and 0, respectively.
What is a function?A function is an assertion, concept, or principle that establishes an association between two variables. Functions may be found throughout mathematics and are essential for the development of significant links.
The functions are given below.
g(x) = (1/4)x² - 4, x ≠ 1
g(x) = 3, x = 1
The value of the function at x = -5 will be given as,
g(-5) = (1/4)(-5)² - 4
g(-5) = 25 / 4 - 4
g(-5) = 6.25 - 4
g(-5) = 2.25
The value of the function at x = 4 will be given as,
g(4) = (1/4)(4)² - 4
g(4) = 16 / 4 - 4
g(4) = 4 - 4
g(4) = 0
The value of the function at x = 1 will be given as,
g(1) = 3
The value of the function at x = -5, x = 1, and x = 4 will be 2.25, 3, and 0, respectively.
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Convert the following:
4 quarts is equivalent to
ao liters (rounded to the hundredth)
Answer: 3.79 litres
Step-by-step explanation:
1 litre is equivalent to about 1.05668821 American quarts.
4 quarts would therefore be;
= 4/1.05668821
= 3.78541178
= 3.79 litres
Algebra Review
Write an algebraic expression for each verbal expression.
1. the sum of one-third of a number and 27
2. the product of a number squared and 4
3. Write a verbal expression for 5n^3 +9.
Answer:
Step-by-step explanation:
1. The sum of one-third of a number and 27
= [tex]\frac{1}{3}\times x +27\\= 1/3x +27[/tex]
2. The product of a number squared and 4
[tex]Let\:the\:unknown\: number\: be \:x\\\\x^2\times4\\\\= 4x^2[/tex]
3.Write a verbal expression for 5n^3 +9.
The sum of the product and of 5 and a cubed number and 9
If 2 x 2 + 13 x − 7 = 0 , then x could equal which of the following?
Hi there! :)
Answer:
x = 1/2 or -7.
Step-by-step explanation:
(I'm assuming the expression is 2x² + 13x - 7 = 0)
Factor the equation to solve for the possible values of "x":
2x² + 13x - 7 = 0
When factored, we get:
(2x - 1) ( x + 7) = 0
Use the Zero-Product property to solve for the roots:
2x - 1 = 0
2x = 1
x = 1/2.
-----------
x + 7 = 0
x = -7.
Therefore, possible values of x are x = -1/2, 7.
Answer:
x = 1/2 x=-7
Step-by-step explanation:
2 x^2 + 13 x − 7 = 0
Factor
(2x-1)(x+7)=0
Using the zero product property
2x-1 =0 x+7=0
2x=1 x =-7
x = 1/2 x=-7
4. The general population (Population 2) has a mean of 30 and a standard deviation of 5, and the cutoff Z score for significance in a study involving one participant is 1.96. If the raw score obtained by the participant is 45, what decisions should be made about the null and research hypotheses?
Answer:
The null hypothesis is rejected and research hypotheses is supported
Step-by-step explanation:
From the question we are told that
The population mean is [tex]\mu = 30[/tex]
The standard deviation is [tex]\sigma = 5[/tex]
The sample size is n = 1
The cutoff Z score for significance is [tex]Z_{\alpha } = 1.96[/tex]
The mean score is [tex]\= x = 45[/tex]
Generally the test hypothesis is mathematically represented as
[tex]t = \frac{\= x - \mu }{ \frac{ \sigma }{\sqrt{n} } }[/tex]
=> [tex]t = \frac{45 - 30 }{ \frac{ 5}{\sqrt{1} } }[/tex]
=> [tex]t = 3[/tex]
From the obtained value we can see that [tex]t > Z_{\alpha }[/tex]
Hence the null hypothesis is rejected and research hypotheses is supported
Evaluate the expression for q = -2. 8q=
Answer:
-16
Step-by-step explanation:
8q
Let q = -2
8*-2
-16
A soda bottling company’s manufacturing process is calibrated so that 99% of bottles are filled to within specifications, while 1% is not within specification. Every hour, 12 random bottles are taken from the assembly line and tested. If 2 or more bottles in the sample are not within specification, the assembly line is shut down for recalibration. What is the probability that the assembly line will be shut down, given that it is actually calibrated correctly? Use Excel to find the probability. Round your answer to three decimal places.
Answer:
The probability that the assembly line will be shut down is 0.00617.
Step-by-step explanation:
We are given that a soda bottling company’s manufacturing process is calibrated so that 99% of bottles are filled to within specifications, while 1% is not within specification.
Every hour, 12 random bottles are taken from the assembly line and tested. If 2 or more bottles in the sample are not within specification, the assembly line is shut down for recalibration.
Let X = Number of bottles in the sample that are not within specification.
The above situation can be represented through binomial distribution;
[tex]P(X=r)=\binom{n}{r} \times p^{r}\times (1-p)^{n-r};x=0,1,2,3,.....[/tex]
where, n = number of trials (samples) taken = 12 bottles
x = number of success = 2 or more bottles
p = probabilitiy of success which in our question is probability that
bottles are not within specification, i.e. p = 0.01
So, X ~ Binom (n = 12, p = 0.01)
Now, the probability that the assembly line will be shut down is given by = P(X [tex]\geq[/tex] 2)
P(X [tex]\geq[/tex] 2) = 1 - P(X = 0) - P(X = 1)
= [tex]1-\binom{12}{0} \times 0.01^{0}\times (1-0.01)^{12-0}-\binom{12}{1} \times 0.01^{1}\times (1-0.01)^{12-1}[/tex]
= [tex]1-(1 \times 1\times 0.99^{12})-(12 \times 0.01^{1}\times 0.99^{11})[/tex]
= 0.00617
Express as a trinomial (3x+8) (x+10)
Answer:
[tex]3x^{2} +38x+80[/tex]
Step-by-step explanation:
Hello!
A trinomial is a expression consisting of three different terms
To turn this into a trinomial we multiply everything to each other
3x
3x * x = [tex]3x^{2}[/tex]
3x * 10 = 30x
8
8 * x = 8x
8 * 10 = 80
Now we put them all together in an equation
[tex]3x^{2} +30x+8x+80[/tex]
Combine like terms
[tex]3x^{2} +38x+80[/tex]
The answer is [tex]3x^{2} +38x+80[/tex]
Hope this helps!
An architect is designing a gym for a new elementary
school. The gym will be 116 feet long and have an area of
6,960 square feet. What will be the width of the gym?
The width of the gym will be W=60 feet for the area of 6,960 square feet.
What is area?Area is defines as the space covered by a surface in the two dimensional plane.
It is given that
Area of the gym =6960 square feet
Width of the gym = ?
Length of the gym=116 feet
The width of the gym will be calculated as
[tex]A=\L\times W\\\\\\6960=116\times W\\\\\\w=\dfrac{6960}{116}=60\ \ Feet[/tex]
hence the width of the gym will be W=60 feet for the area of 6,960 square feet.
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Show that the set of functions from the positive integers to the set {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} is uncountable. [Hint: First set up a one-to-one correspondence between the set of real numbers between 0 and 1 and a subset of these functions. Do this by associating to the real number 0.d1d2 . . . dn . . . the function f with f(n).
Answer:
since the set of functions expressed are uncountable and they are a subset of real numbers starting from N therefore the set {0,1,2,3,4,5,6,7,8,9} is uncountable as well as its off functions
Step-by-step explanation:
set = {0,1,2,3,4,5,6,7,8,9}
setting up a one-to-one correspondence between the set of real numbers between 0 and 1
The function : F(n)= {0,1} is equivalent to the subset (sf) of (n) , this condition is met if n belongs to the subset (sf) when f(n) = 1
hence The power set of (n) is uncountable and is equivalent to the set of real numbers given
since the set of functions expressed are uncountable and they are a subset of real numbers starting from N therefore the set {0,1,2,3,4,5,6,7,8,9} is uncountable as well as its offfunctions
classify the following triangle
23.24 divided by 2.8
Answer:
It's 8.3
Step-by-step explanation:
Answer:
8.3
Step-by-step explanation:
Please answer this correctly without making mistakes
Answer:
so first convert to fraction so
9 3/4 = 39/4
so it was spread among 3
so this is division so you do 39/4 divided by 3
so you keep switch flip
which is 39/4 *1/3
answer is 13/4
Answer:
3 1/4 bagsStep-by-step explanation:
[tex]9\frac{3}{4}= \frac{(4 \times 9)+3}{4}= \frac{39}{4} \\\\\frac{39}{4} = 3 \:vegetable \: beds\\x \:\:\:= 1 \: vegetable \:bed\\\\3x = \frac{39}{4} \\\\\frac{3x}{3} = \frac{\frac{39}{4} }{3} \\\\x = \frac{13}{4} \\\\x = 3\frac{1}{4}[/tex]
To the nearest tenth, what is the value of P(C|Y)? 0.4 0.5 0.7 0.8
Answer:
P(C|Y) = 0.5.
Step-by-step explanation:
We are given the following table below;
X Y Z Total
A 32 10 28 70
B 6 5 25 36
C 18 15 7 40
Total 56 30 60 146
Now, we have to find the probability of P(C/Y).
As we know that the conditional probability formula of P(A/B) is given by;
P(A/B) = [tex]\frac{P(A \bigcap B)}{P(B)}[/tex]
So, according to our question;
P(C/Y) = [tex]\frac{P(C \bigcap Y)}{P(Y)}[/tex]
Here, P(Y) = [tex]\frac{30}{146}[/tex] and P(C [tex]\bigcap[/tex] Y) = [tex]\frac{15}{146}[/tex] {by seeing third row and second column}
Hence, P(C/Y) = [tex]\frac{\frac{15}{146} }{\frac{30}{146} }[/tex]
= [tex]\frac{15}{30}[/tex] = 0.5.
Answer: 0.5
Step-by-step explanation:
edge
Write the function in terms of unit step functions. Find the Laplace transform of the given function. f(t) = 5, 0 ≤ t < 7 −3, t ≥ 7
Rewrite f in terms of the unit step function:
[tex]f(t)=\begin{cases}5&\text{for }0\le t<7\\-3&\text{for }t\ge7\end{cases}[/tex]
[tex]\implies f(t)=5(u(t)-u(t-7))-3u(t-7)=5u(t)-8u(t-7)[/tex]
where
[tex]u(t)=\begin{cases}1&\text{for }t\ge0\\0&\text{for }t<0\end{cases}[/tex]
Recall the time-shifting property of the Laplace transform:
[tex]L[u(t-c)f(t-c)]=e^{-cs}L[f(t)][/tex]
and the Laplace transform of a constant function,
[tex]L[k]=\dfrac ks[/tex]
So we have
[tex]L[f(t)]=L[5u(t)-8u(t-7)]=5L[1]-8e^{-7s}L[1]=\boxed{\dfrac{5-8e^{-7s}}s}[/tex]
In this exercise you have to find the laplace transform:
[tex]L[f(t)]=\frac{5-8e^{-7s}}{s}[/tex]
Rewrite f in terms of the unit step function:
[tex]f(t)=\left \{ {{5, for 0\leq t\leq 7} \atop {-3, for t\geq 7}} \right. \\f(t)= 5(u(t)-u(t-7)-3u(t-7)=5u(t)-8u(t-7)[/tex]
Where:
[tex]u(t)= \left \{ {{1, t\geq 0} \atop {0, t<0}} \right.[/tex]
Recall the time-shifting property of the Laplace transform:
[tex]L[u(t-c)f(t-c)]= e^{-cs}L[f(t)][/tex]
and the Laplace transform of a constant function,
[tex]L[k]=\frac{k}{s}[/tex]
So we have:
[tex]L[f(t)]= L[5u(t)-8u(t-7)]= 5L[1]-8e^{-7s}L[1]= \frac{5-8e^{-7s}}{s}[/tex]
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In triangle ABC, ∠ABC=70° and ∠ACB=50°. Points M and N lie on sides AB and AC respectively such that ∠MCB=40° and ∠NBC=50°. Find m∠NMC.
Answer:
∠NMC = 50°
Step-by-step explanation:
The interpretation of the information given in the question can be seen in the attached images below.
In ΔABC;
∠ A + ∠ B + ∠ C = 180° (sum of angles in a triangle)
∠ A + 70° + 50° = 180°
∠ A = 180° - 70° - 50°
∠ A = 180° - 120°
∠ A = 60°
In ΔAMN ; the base angle are equal , let the base angles be x and y
So; x = y (base angle of an equilateral triangle)
Then;
x + x + 60° = 180°
2x + 60° = 180°
2x = 180° - 60°
2x = 120°
x = 120°/2
x = 60°
∴ x = 60° , y = 60°
In ΔBQC
∠a + ∠e + ∠b = 180°
50° + ∠e + 40° = 180°
∠e = 180° - 50° - 40°
∠e = 180° - 90°
∠e = 90°
At point Q , ∠e = ∠f = ∠g = ∠h = 90° (angles at a point)
∠i = 50° - 40° = 10°
In ΔNQC
∠f + ∠i + ∠j = 180°
90° + 10° + ∠j = 180°
∠j = 180° - 90°-10°
∠j = 180° - 100°
∠j = 80°
From line AC , at point N , ∠y + ∠c + ∠j = 180° (sum of angles on a straight line)
60° + ∠c + ∠80° = 180°
∠c = 180° - 60°-80°
∠c = 180° - 140°
∠c = 40°
Recall that :
At point Q , ∠e = ∠f = ∠g = ∠h = 90° (angles at a point)
Then In Δ NMC ;
∠d + ∠h + ∠c = 180° (sum of angles in a triangle)
∠d + 90° + 40° = 180°
∠d = 180° - 90° -40°
∠d = 180° - 130°
∠d = 50°
Therefore, ∠NMC = ∠d = 50°
if the sin 30 = 1/2, then which statement is true?
Answer:
cos 60° = 1/2 because the angles are complements.
Step-by-step explanation:
Use the following recursive formula to answer the question.
A1=-3/2
an=an-1+1/2
what’s is a9?
Step-by-step explanation:
a2=a1+1/2=-1
a3=a2+1/2=-1/2, then we have common difference 0.5
a9=a1+(n-1)d
a9=-3/2+(8)0.5=5/2
The ages of some lectures are 42,54,50,54,50,42,46,46,48 and 48.Calculate the:
(a)Mean Age.
(b)Standard deviation.
Answer:
The mean age is 48
The standard deviation is 4
Step-by-step explanation:
The answer is, (a) mean age is 48.
(b) standard deviation is 4.
What is a mean age?Average age of the population calculated as the arithmetic mean.Another parameter determining the average age of the population is the median age.What does standard deviation of age mean?In general, the standard deviation tells us how far from the average the rest of the numbers tend to be, and it will have the same units as the numbers themselves. If, for example, the group {0, 6, 8, 14} is the ages of a group of four brothers in years, the average is 7 years and the standard deviation is 5 years.How do you find the mean age?To find the mean add all the ages together and divide by the total number of children.
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HELP ASAP ROCKY!!! will get branliest.
Answer:
y = 8x + 70
Step-by-step explanation:
Start with the third line.
x = 3, y = 94
Subtract 1 from x and 8 from y:
x = 2, y = 86; this is the second line
Subtract 1 from x and 8 from y:
x = 1, y = 78; this is the first line
Subtract 1 from x and 8 from y:
x = 0; y = 70
For selling 0 games, she earns $70.
y = mx + b
y = mx + 70
For each game she sells, her commission is $8.
y = 8x + 70
What number should both sides of the following equation be multiplied by to solve for g? g divided by 2 = 4
Answer: Multiply both sides by 2.
Step-by-step explanation:
g divided by 2 is equal to 4 .
We could represent that with the equation :
[tex]\frac{g}{2} = 4[/tex] To solve for g in this case multiply both sides by 2.
[tex]\frac{g}{2} * 2 = 4(2)[/tex] 2 cancels out on the left side so we will be left with g. On the right side will be left with 8 after multiplying.
g = 8
Sarah knows how important it is to budget her monthly expenses. She earns $3,120 every month and her monthly expenses total to $2,130. Sarah has summarized her monthly expenses using the pie chart below. What percent of Sarah's monthly income is left over after she pays her monthly bills? Round to the dollar
Answer: 37.1%
Step-by-step explanation:
2130/3120×100% = 68.3%
100% - 68.3%
=31.7%
37.1%
which makes that $460
May I have brainliest please? :)
Also, the person above me smells like how a diaper tastes
The lower edge of a 5 foot tall painting is 5 feet above your eye level. At what distance should you stand from the wall so your viewing angle of the painting is maximized?
Answer:
x = sqrt(50) = 5sqrt(2) = 7.071 ft (to 3 decimals)
Step-by-step explanation:
referring to the diagram
theta (x) = atan(10/x) - atan(5/x)
differentiate with respect to x
theta'(x) = 5/(x^2+25) - 10/(x^2+100)
For x to have an extremum (max. or min)
theta'(x) = 0 ="
5/(x^2+25) - 10/(x^2+100) = 0
transpose and cross multiply
10(x^2+25) -5(x^2+100) = 0
expand and simplify
10x^2+250 - 5x^2-500 = 0
5x^2 = 250
x^2=50
x = sqrt(50) = 5sqrt(2) = 7.071 ft (to 3 decimals)
Since we know that if x becomes large, theta will decrease, so
x = 5sqrt(2) is a maximum.
Construct a polynomial function with the following properties: fifth degree, 4 is a zero of multiplicity 3, −2 is the only other zero, leading coefficient is 2.
Answer:
[tex]\Large \boxed{\sf \bf \ \ 2(x-4)^3(x+2)^2 \ \ }[/tex]
Step-by-step explanation:
Hello, please consider the following.
Construct a polynomial function with the following properties...
... fifth degree
It means that the polynomial can be written as below.
[tex]a_5x^5+a_4x^4+a_3x^3+a_2x^2+a_1x+a_0 \ \text{ with }a_5\text{ different from 0}\\\\\text{ or } k(x-x_1)(x-x_2)(x-x_3)(x-x_4)(x-x_5) \\\\ \text{ with k different from 0 and } (x_i)_{1\leqi\leq 5 } \text { are the roots.}[/tex]
... 4 is a zero of multiplicity 3
We can write the polynomial as below.
[tex]k(x-4)(x-4)(x-4)(x-x_4)(x-x_5)=k(x-4)^3(x-x_4)(x-x_5)[/tex]
... −2 is the only other zero
Because this is the only other zero, we can deduce that -2 is a zero of multiplicity 2.
[tex]k(x-4)(x-4)(x-4)(x-x_4)(x-x_5)\\\\=k(x-4)^3(x-(-2))(x-(-2))\\\\=k(x-4)^3(x+2)^2[/tex]
... leading coefficient is 2.
Finally, it means that k = 2 and then the polynomial function is:
[tex]\large \boxed{2(x-4)^3(x+2)^2}[/tex]
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
Which of the functions below could have created this graph?
O A. F(x) = -x' +5x° +7
O B. F(x) = 2x2 - 4x2 +4
O C. F(x)=x2+x+3
O D. F(x) = -5x – 2x+5
Answer:
[tex] \boxed{f(x) = 2 {x}^{9} - 4 {x}^{2} + 4}[/tex]
Option B is the correct option
Step-by-step explanation:
By looking at the end behavior , we can say that the degree of the polynomial must be odd and leading coefficient will be positive.
Thus , the correct choice is B.
Hope I helped!
Best regards!
The polynomial function that could have created the given curve on the xy-plane is [tex]f(x)= 2x^9-4x^2+4[/tex]
What are polynomial function?Polynomial functions aree function having a leading degrees of 3 and greater.
The nature of the curve on the xy-plane depends on its end behaviour. From the given graph, the end behaviour shows that the equivalnt function has a positive leading coefficient and an odd degree.
From the listed option, the function that satisfies both criteria is [tex]f(x)=2x^9-4x^2+4[/tex].
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i will rate you brainliest// What is the interquartile range (IQR) of {5.8, 8.5, 9.9, -0.8, -1.3, 2.3, 7.4, -1.9}?
Answer
arrange the element in increasing order
-1.9, -1.3, -0.8, 2.3, 5.8, 7.4, 8.5, 9.9
interquatile = Q3 - Q1
[tex] = \frac{7.4 + 8.5}{2} - \frac{ - 1.3 - 0.8}{2} [/tex]
[tex] = 7.95 + 1.05[/tex]
[tex] = 9[/tex]
Answer:
9.0
Step-by-step explanation:
i took the quiz
A baseball player has a batting average of 0.26. What is the probability that he has exactly 6 hits in his next 7 at bats
Answer:
0.0016
Step-by-step explanation:
Batting average, p = 0.26
n = 7
x = 6
With p = 0.26 as success rate
1-p is equal to failure rate which is = 0.74
We have to solve this by using the binomial distribution formula.
P(X= x)
= nCx * p^x * (1-p)^(n-x)
P(X = 6)
=7C6 × 0.26^6 ×(1-0.26)^(7-6)
= 7 × 0.0003089 × 0..74¹
= 0.0016
So probability that he has exactly 6 hits in his next 7 bats is equal to 0.0016.
Which of the following best represents the average rate at which the human hair grows?
Answer:
1/2 inch per month
Step-by-step explanation:
The average rate hair grows is about half an inch per month which is 6 inches per year.
The one-sample z ‑statistic for Thomas' statistical test has a value of −1.73346 , and Thomas calculates a P-value of 0.0830 . Should Thomas conclude that telephone surveys provide adequate coverage with respect to p ? Why or why not? Select all correct statements about his decision and conclusion.
Answer:
Thomas should not reject the null hypothesis.
Step-by-step explanation:
The null hypothesis is rejected or accepted on the basis of level of significance. When the p-value is greater than level of significance we fail to reject the null hypothesis and null hypothesis is then accepted. It is not necessary that all null hypothesis will be rejected at 10% level of significance. To determine the criteria for accepting or rejecting a null hypothesis we should also consider p-value. Here in this question the test value is -1.73346 and p-value is 0.0830. The p value is greater than the test value therefore the null hypothesis should be accepted.
Evaluate 3h(2) + 2k(3) =
Answer:
6h + 6kStep-by-step explanation:
[tex]3h\left(2\right)+2k\left(3\right)\\\\\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\\\\=3h\times \:2+2k\times \:3\\\\\mathrm{Multiply\:the\:numbers:}\:3\times \:2=6\\\\=6h+2\times \:3k\\\\\mathrm{Multiply\:the\:numbers:}\:2\times \:3=6\\\\=6h+6k[/tex]
Answer:
Answers for E-dge-nuityyy
Step-by-step explanation:
(h + k)(2) = 5
(h – k)(3) = 9
Evaluate 3h(2) + 2k(3) = 17