Answer:
p = 1.25
Step-by-step explanation:
varies inversely
p (q + 2)² = k
-----------------------
Find k
p=5 when q = 3
5(3 + 2)² = k
5(25) = k
125 = k
----------------------
Find p when q = 8
p(8 + 2)² = 125
p(100) = 125
divide both sides by 100
p = 1.25
Find the area of the triangle. Round your answer to the nearest tenth.
B
37 cm
410
А
37 cm
с
a. 449.1 cm2
b. 684.5 cm
C. 898.1 cm2
d. 595 cm
The answer would be A. 449.1 cm2.
What is the result if -8ײ +24× divided by -4×
Answer:
2x-6
Step-by-step explanation:
( -8ײ +24×) ÷ (-4×) =
2x-6
25=125^k find the value of k
Answer:
2/3
Step-by-step explanation:
25=125^k
5^2=5^3k
2=3k
k=2/3
The value of k is k = 2/3.
What is an exponent?The number of times a number is multiplied by itself is referred to as an exponent.
Given that, [tex]25 = 125^k[/tex].
Follow the steps to find the value of k:
[tex]25 = 125^k\\\\5^2=(5^3)^k\\\\5^2=5^{3k}[/tex]
Since the base of the exponents is the same, it follows:
2 = 3k
k = 2/3
Hence, the value of k is k = 2/3.
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Find angle C!!!!! See the image below! I need this answer fast
Answer:
55
Angle C is a inscribed angle of the of Arc Ba.
CA is the diameter so that means Arc BA equal 110 becuase
110+70=180.
Angle C is half of Arc BA so Angle C is
[tex]55[/tex]
y-5 = -3 (x+2) in standard form
Answer:
maybe y - -3x = -11?
Step-by-step explanation:
im rushing so i may have did it wrong sorry
plz answer fast i need the answers thank u
Answer:
Step-by-step explanation:
(-5 , 2) here -5 is x coordinate and 2 is y coordinate since x coordinate is negative and y coordinate is positive it lies in II quadrant.
(2 , -5) here 2 is x coordinate whereas -5 is y coordinate and siince x coordiante is positive and y coordinate is negative it lies in IV quadrant.
(x^3 - 2)(x^2 + 11)
to find the degree of polynomial first u need to factor this out
x^3(x^2 + 11) -2(x^2 + 11)
x^3 * x^2 + x^3 * 11 - 2 * x^2 - 2 * 11
x^3+2 + 11x^3 - 2x^2 - 22
x^5 + 11x^3 - 2x^2 - 22
since the highest degree is 5 the degree of the polynomial is also 5.
Step-by-step explanation:
MARK ME BRAINLIEST THANKS MY ANSWER PLEASE
Which formula gives the coordinates of the midpoint of the segment connecting points (u, v) and (s, 6,t),
Answer:
[tex](\frac{u+s}{2} , \frac{v+t}{2} )[/tex] (the first option)
Step-by-step explanation:
The midpoint of a segment connecting two points [tex](x_1, y_1)[/tex] and [tex](x_2,y_2)[/tex] can be described by the following formula: [tex]\frac{x_1 + x_2}{2} = x_{mid}[/tex] and [tex]\frac{y_1 + y_2}{2} = y_{mid}[/tex]. As you can see, the formula essentially takes the average of the x- and y-coordinates to find the point in the middle.
With points (u, v) and (s, t), the midpoint becomes [tex](\frac{u+s}{2} , \frac{v+t}{2} )[/tex] (the first option).
(15 POINTS) please please help out if you can!! I Will mark you brain list!! I also have other things on my account for a lot of points! If you could help that would help so so much!!
Answer:
(2w+2)(w+8) ≤ 100
Step-by-step explanation:
A = l x w
we want less than or equal to 100
100 ≥ length (2w +2) x width (w+8)
flip around to look like answer
can somebody help me with this question please!
fig 3 would take 18 triangle
fig 4 would take 30 small triangles
if its wrong i am sorry
Answer:
the answer is 33the answer is 18Jodi has two bank accounts. Her parents started Account A for her. It currently has $100 in it, and Jodi deposits $20 into it each month. Jodi's grandparents started Account B for her. It currently has $300 in it, and her grandparents deposit $40 into it each month.
Answer:
(f+g)(x) = 60x + 400
Step-by-step explanation:
Given :
Amount in account A:
f(x) = 20x + 100
Amount in account B :
g(x) = 40x + 300
Total amount in Account A and B:
f(x) + g(x) = (20x + 100) + (40x + 300)
(f+g)(x) = (20x + 40x) + (100 + 300)
(f+g)(x) = 60x + 400
Name the polygon with seven sides_____
a polygon with seven sides is called a heptagon
Answer:
Hyptagon
Step-by-step explanation:
In geometry, a heptagon is a seven-sided polygon or 7-gon.
The heptagon is sometimes referred to as the septagon, using "sept-" (an elision of septua-, a Latin-derived numerical prefix, rather than hepta-, a Greek-derived numerical prefix; both are cognate) together with the Greek suffix "-agon" meaning angle.
SOMEBODY PLEASE HELP I DON’T HAVE MUCH TIME
Find the volume of this sphere.
Use 3 for TT.
V
V [?]cm
V = 713
12cm
Answer:
904.78
Step-by-step explanation:
I hope this is correct, if it isn't please feel free to let me know and I can fix it. I'm sorry in advance if it is incorrect.
The sum of squares of two
numbers is 80 and the square of
difference between the two numbers
is 36. Find the product of two
numbers .
Answer:
the product of the 2 numbers is 22
Step-by-step explanation:
x² + y² = 80
(x - y)² = 36
=>
x - y = 6
or y - x = 6
let's start with the first one x-y=6
x = 6 + y
=>
(6+y)² + y² = 80
y² + 6y +6y + 36 + y² = 80
2y² + 12y + 36 = 80
2y² + 12y - 44 = 0
y² + 6y - 22 = 0
the solution of a quadratic equation
x = (-b ± sqrt(b² - 4ac))/(2a)
in our case here we have an squadron in y.
a=1
b=6
c=-22
(-6 ± sqrt(36 + 4×22))/2 = (-6 ± sqrt(36+88))/2 =
= (-6 ± sqrt(124))/2 = (-6 ± sqrt(4×31))/2 =
= (-6 ± 2×sqrt(31))/2 = -3 ± sqrt(31)
y1 = -3 + sqrt(31)
y2 = -3 - sqrt(31)
=>
x1 = 6 + -3 + sqrt(31) = 3 + sqrt(31)
x2 = 3 - sqrt(31)
control :
(-3 + sqrt(31))² + (3 + sqrt(31))² = 80
9 - 3 sqrt(31) - 3 sqrt(31) + 31 + 9 +3 sqrt(31) + 3 sqrt(31) + 31 = 80
9 + 31 + 9 +31 = 80
18 + 62 = 80
80 = 80 correct
solving now for y-x=6
delivers exactly the same calculations, just with x and y trading places.
so, the resulting 2 number pairs are the same.
the product of the 2 numbers :
(3 + sqrt(31))(-3 + sqrt(31)) = -9 - 3 sqrt(31) + 3 sqrt(31) + 31 =
= -9 + 31 = 22
(3 - sqrt(31))(-3 - sqrt(31)) = -9 + 3 sqrt(31) - 3 sqrt(31) + 31 =
= 22
so, the product is the same in both cases.
WILL GIVE BRAINLIEST AND 20 POINTS!
Find the equation of the line which passes through the point (11,8) and is parallel to the given line. Express your answer in slope-intercept form. Simplify your answer.
6x+8y=15
Step By Step Explanation:
y = - 3/4× + 15/8Step 1Swap sides so that all variable terms are on the left hand side.[tex] - \frac{3}{4} x + \frac{15}{8} = y[/tex]Step 2Subtract [tex]\frac{15}{8}[/tex] from both sides.[tex] - \frac{3}{4} \times = y - \frac{15}{8} [/tex]Step 3Divide both sides of the equation by -[tex]\frac{3}{4}[/tex] which is the same as multiplying both sides by the reciprocal of the fraction.[tex] \frac{ - \frac{3}{4} \times}{- \frac{3}{4} } = \frac{y - \frac{15}{8} }{ - \frac{3}{4} } [/tex]Step 4Dividing by [tex]-\frac{3}{4}[/tex] undoes the multiplication by [tex]-\frac{2}{4}[/tex][tex]x = \frac{y - \frac{15}{8} }{ - \frac{3}{4} } [/tex]Step 5Divide [tex]y-\frac{15}{8}[/tex] by -\frac{3}{4} by multiplying [tex]y-\frac{15}{8}[/tex] by the reciprocal of [tex]-\frac{3}{4}[/tex][tex]\color{Green}x = \frac{ - 4y}{3} + \frac{5}{2} [/tex]A bungee jumper leaps off a cliff 122 meters from the ground. Her cord, when fully stretched, is 72 meters long, and it takes 6 seconds after the jump for it to extend fully. The distance between e jumper and the ground as a function of time can be modeled as a quadratic function. Which equation represents her distance from the ground as a function of time?
Answer:
Answer is B.
Step-by-step explanation:
You can solve this by recognizing the vertex and the y-intercept of the quadratic equation based on the information provided.
The vertex occurs 6 seconds into the jump, when the cord is fully stretched to 72m, before it starts to contract again. This is when the jumper is closest to the ground, 122-72 = 50m above the ground. Notice the jumper never reaches the ground because the cord is only 72m long - it can't make it the full 122m - so there will not be an x-intercept (or t-intercept in this case). Anyway - the vertex is (6,50) using this information.
The y-intercept is the point at which t=0, the beginning of the jump. At the beginning of the jump, the jump is still on top of the cliff, 122m up. So the coordinates of the y-intercept are (0,122).
Now plug these values into the vertex form of the quadratic formula and solve for a:
[tex]f(t) = a(t-h)^2+k\\122=a(0-6)^2+50\\72 = 36a\\a=2[/tex]
This means our general equation (in vertex form) for this scenario is:
[tex]f(t)=2(t-6)^2+50[/tex]
Our answer options are in standard form, so just expand the vertex form of the equation to finish:
[tex]f(t)=2(t-6)^2+50\\f(t)=2(t^2-12t+36)+50\\f(t)=2t^2-24t+72+50\\f(t)=2t^2-24t+122[/tex]
Help me on this pls!!!!!!
Step-by-step explanation:
bla bla bla bla123222222333333
please please please help
Answer:
a S(-3) = 2(-3)(-3)+5(-3)-12
=18-15-12
=-9
b 2x2+5x-12=0
2x2+8x-3x-12=0
2x(x-4)-3(x+4)=0
(2x-3)(x+4)=0
2x-3=0
x=3/2
x=-4
sorry I couldn't answer the other question
Let $z$ and $w$ be complex numbers satisfying $|z| = 5, |w| = 2,$ and $z\overline{w} = 6+8i.$ Then enter in the numbers \[|z+w|^2, |zw|^2, |z-w|^2, \left| \dfrac{z}{w} \right|^2 \]below, in the order listed above. If any of these cannot be uniquely determined from the information given, enter in a question mark. Don't even know where to start.
I got 49 for the first one, 100 for the second one, 9 for the 3rd one, and 6.25 for the 4th one. But it was wrong, so I don't know how to do this question.
Answer:
1st entry: 41
3rd entry: 17
Step-by-step explanation:
The 1st and 3rd entry are incorrect.
We will use the following for the 1st and 3rd:
[tex]|z+w|=|z|^2+|w|^2+2R(z\overline{w})[/tex]
[tex]|z-w|=|z|^2+|w|^2-2R(z\overline{w})[/tex]
where [tex]R(z\overline{w})[/tex] means 'real part of [tex]z\overline{w}[/tex]'.
Let's do part 1 now)
25+4+2(6)
29+12
41
Let's do part 3 now)
25+4-2(6)
29-12
17
Which of these is the lowest unit price for apples? $8.00 per 10-pound bag $21.40 per 3-pound bag $4.10 per 5-pound bag $.79 per pound Click on the correct answer.
Answer:
.79 cents a pound is the lowest unit price for apples
Step-by-step explanation:
FIRST ANSWER GETS BRAINLIEST !!!!
16.
What is the solution of the equation 56 = 2.8y ?
a. y = 156.8
b. y = 58.8
c. y = 2
d. y = 20
Answer:
When you solve for y, you get y = 20.
Step-by-step explanation:
You isolate the variable by dividing each side of the equation by the number with the variable, therefore getting 20.
[tex]\longrightarrow{\green{d.\:y\:=\:20}}[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]
➝[tex]\:56 = 2.8y[/tex]
➝[tex]\:y = \frac{56}{2.8} [/tex]
➝[tex]\:y = 20[/tex]
Therefore, the value of [tex]y[/tex] is 20.
[tex]\large\mathfrak{{\pmb{\underline{\blue{To\:verify}}{\blue{:}}}}}[/tex]
➝[tex]\:56 = 2.8y[/tex]
➝[tex]\:56 = 2.8 \times 20[/tex]
➝[tex]\:56 = 56[/tex]
➝[tex]\:L.H.S.=R. H. S[/tex]
Hence verified.
[tex]\bold{ \green{ \star{ \orange{Mystique35}}}}⋆[/tex]
In the given figure alongside,prove that
Triangle ABC is simalar to Triangle SRT
Find the length of AC
Answer:
let's use Pythagoras theorem,
h²=b²+l²
so,
ad²=ac²+dc²
6²=ac²+3²
36-9=ac²=27
√27 can be written as 3√3,
hence ac= 3√3
if f( x )3 X + 4 and g(x)= X + 1 find the value of x given that F - 1g( x) = 2
Answer:
The answer for the question is -1.5
Where is Point B on the number line
Answer:
the answer is the second option
Step-by-step explanation:
it is
The two triangles are similar. What is the value of x? Enter your answer in the box. x = Two right triangles, one smaller than the other, back to back, so that their right angles form a straight angle. The two acute angles along the straight angle are congruent to each other. The overlapping part of the legs is labeled 12. The part of the overlapping side that extends above the smaller triangle is labeled 3. The leg of the smaller triangle that is a ray of the straight angle is labeled 3 x plus 1. The leg of the larger angle that is a ray of the straight angle is labeled 4 x.
Answer:
The two triangles are similar.
What is the value of x?
Enter your answer in the box.
x=
The value of x is 7 units.
What is Similarity of Triangles?Two triangles are said to be comparable if their two sides are in the same ratio as the two sides of another triangle and their two sides' angles inscribed in both triangles are equal.
Given :
AD = 6 units , BD = 8 units, m∠ABC = m∠DBE = 90° and
∠DEB ≅ ∠ACB
Now, AB = AD + BD
= 8 + 6 = 14 units
Now, In ΔABC and ΔDBE,
∠DBE = ∠ABC ( Each of 90° )
∠DEB = ∠ACB ( given )
So, By using AA postulate of similarity of triangles , ΔABC ~ ΔDBE
Now, proportion of the corresponding sides will be equal.
AD/ DB= BC/ BE
14/8 = 3x/ 2x-2
4x= 28
x= 7
Hence, the value of x is 7 units.
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Put these numbers in order from least to greatest.
1/8,1/2,0.13, and 7/8
Answer: 1/8, 0.13, 1/2, 7/8
Step-by-step explanation: Mental Math
Step-by-step explanation:
0.13,1/2,1/8,and 7/8
hope it is helpful to you
Cedarburg's zoo has two elephants. The male elephant weighs 3 3/4 tons and the female
elephant weighs 7/12 of a ton. How much more does the male weigh than the female?
Answer:
the male weigh than the female
Step-by-step explanation:
[tex]\frac{19}{6}[/tex]=[tex]3\frac{1}{6}[/tex]
1. Find the value of x, rounded to the nearest tenth
A. 3.7
B. 4.4
C. 8.9
D. 4.2
Answer:
C 8.9
Step-by-step explanation:
all these lines (from the same point of origin, cutting into and through a circle, ending at the far end of the circle they are cutting into) have the same relation of their lengths :
a×(a+b) is the same for all these lines.
with a being the first segment from the point of origin to touching the outside of the circle, and b being the length of the line inside the circle.
so,
4×(4+16) = 8×(8+2) = 80
this is correct for these two lines.
now, the line with the length x is a special case, as it does not really go through a circle, it only touches them.
but the length relation applies also to this line. it is just that the length inside the circle is 0.
so,
x×(x+0) = 80 (the same value as for the other lines)
must be true here too.
=>
x² = 80
x = sqrt(80) ≈ 8.9
A side of the triangle below has been extended to form an exterior angle of 129°. Find the value of x.
129° + x = 180°. [Linear pair]
=> x = 180° - 129°
=> x = 51°
Which is a solution to the equation |10-5y|=20
Identify the least common multiple of:
(x + 1), (x - 1), & (x^2 - 1)
Given:
The expressions are [tex](x+1),\ (x-1)[/tex] and [tex](x^2-1)[/tex].
To find:
The least common multiple of given expressions.
Solution:
The expressions are [tex](x+1),\ (x-1)[/tex] and [tex](x^2-1)[/tex]. The factor forms of these expressions are:
[tex](x+1)=1\times (x+1)[/tex]
[tex](x-1)=1\times (x-1)[/tex]
[tex](x^2-1)=(x-1)(x+1)[/tex] [tex][\because a^2-b^2=(a-b)(a+b)][/tex]
The least common multiple is the product of all distinct factors with its highest degree. So,
[tex]L.C.M.=1\times (x+1)\times (x-1)[/tex]
[tex]L.C.M.=(x+1)(x-1)[/tex]
[tex]L.C.M.=x^2-1^2[/tex] [tex][\because a^2-b^2=(a-b)(a+b)][/tex]
[tex]L.C.M.=x^2-1[/tex]
Therefore, the least common multiple of given expressions is [tex]x^2-1[/tex].
