the points 9a b,3 lie on the line y=2 out of 3 x-7

Answer:

Step-by-step explanation:

m1 = 300

m2= 300(1+.05) = 300(1.05)

m3 = 300(1.05)(1.05)

m4= 300(1.05)(1.05)(1.05)

each subsequent month is the previous month times "1 + .05"

the "one" preserving the running total, and the extra ".05" adding the 5%

the repeating (1.05)(1.05)(1.05) is notational simplified using exponents

(1.05)(1.05)(1.05) = [tex](1.05)^{3}[/tex]

Answer:

-$87

Step-by-step explanation:

SEE THE IMAGE FOR SOLUTION

HOPE IT HELPS

HAVE A GREAT DAY

Answer:

or, -4a - 2a -7 = 11

or, -4a -2a =11 +7

or, - 6a = 18

or, a= 18÷ -6

a= -3

Answer:

Step-by-step explanation:

If the function is f(x), then shift 8 units left and 3 units down will result in:

Apply to the given function to get:

Correct choice is A

Answer:

C

Step-by-step explanation:

f(x) = x-8 when x>3, f(7)=7-8=-1

Answer:

Ascending- 10%, 0.2, 1/4, 30%

Descending- 30%, 1/4, 0.2, 10%

Step-by-step explanation:

0.2 = 2/10 = 4/20

1/4 = 5/20

30% = 30/100 = 6/20

10% = 10/100 = 2/20

Ascending

-2/20, 4/20, 5/20, 6/20

- 10%, 0.2, 1/4, 30%

Descending

- 6/20, 5/20, 4/20, 2/20

- 30%, 1/4, 0.2, 10%

Answer: 804 is divisible by 1, 2, 3, 4, 6, 12 ,67 ,134 ,201, 268, 402 ,804

Answer:

The factors of 804 are: 1, 2, 3, 4, 6, 12, 67, 134, 201, 268, 402,804.

Step-by-step explanation:

Answer:

i think you have to count till you get to 4 or 3 then the remaining you plus with the 3

Answer:

[tex]d=5[/tex]

Step-by-step explanation:

you have to use the distance formula, making the origin (0,0) the 1st point and (4,0) the second point.

[tex]d=\sqrt{(x_{2} -x_{1})^{2} + (y_{2} -y_{1})^{2} }[/tex]

[tex]d=\sqrt{(4-0)^{2}+(3-0)^2 }[/tex]

[tex]d=\sqrt{(4)^2+(3)^2}[/tex]

[tex]d=\sqrt{16+9}[/tex]

[tex]d=\sqrt{25}[/tex]

[tex]d=5[/tex]

Answer:

[tex]2(x^{2} -2x+4)[/tex]

Step-by-step explanation:

[tex]2x^{2} -4x+8[/tex]

= [tex]2x^{2} -2*2x+2*4[/tex]

= [tex]2(x^{2} -2x+4)[/tex]

Answer:

Step-by-step explanation:

[tex]\frac{9}{11}=0 .818181....[/tex]

     __  

= 0.81

Answer:

21 letters

Step-by-step explanation:

A, B, C, D, E, F, G, H, I, J, K, L, M, NO, P, Q, R, S, T, U

Answer:Hey I'm sorry I didn't get to answer your question it's just that I need the points because I don't have enough to get help with my question. I hope you get the answer that you need for you question. Good Luck :)

Step-by-step explanation:

Answer:

20.53 minutes

Step-by-step explanation:

Speed = Distance/Time = 30/7

Time = Distance / Speed

= 5280/30/7

= 1232 seconds / 60 = 20.53 minutes

Answered by Gauthmath

Answer:

The answer is B (4, 8) and (0, -8)

Answer:

4500

Step-by-step explanation:

The first digit can't be 0. so it will be a number from 1000 to 9999. That's a total of 9000 numbers (9999-1000+1=9000). Since the last digit must be an even number that is one half of the 9000 numbers which is 4500.

Given:

The equation is:

[tex]y=\sqrt[3]{x}[/tex]

To find:

The graph of the given equation.

Solution:

We have,

[tex]y=\sqrt[3]{x}[/tex]

The table of values is:

x                 y

-8              -2

-1                -1

0               0

1                 1

8                8

Plot these points on a coordinate plane and connect them by a free hand curve as shown in the below graph.

Answer:

D

Step-by-step explanation:

edge 2020

Answer:

C is the answer

Step-by-step explanation:

Quadratic equations have at most 2 solution, and linear equations only have 1 solution, and since y is equal to both of them, it can only have 1 or 2 solutions.

The correct answer is option D.  The system may have no, 1, or 2 solutions

A quadratic equation is a second-order polynomial equation in a single variable x , ax²+bx+c=0. with a ≠ 0 .

f(x) is a quadratic function and g(x) is linear function

y=f(x)

y=g(x)

Quadratic equations have at most 2 solution

linear equations only have 1 solution,

f(x)=g(x)=y

y is equal to both of them, it can only have 1 or 2 solutions.

A line and a parabola can intersect zero, one, or two times

Therefore, a linear and quadratic system can have zero, one, or two solutions

Hence, the correct answer is option D.  The system may have no, 1, or 2 solutions

To learn more on Quadratic equation click:

https://brainly.com/question/17177510

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Answer:

if the diameter is 11, them the answer is 47.52275cm

Answer:

M<C = 20°

Step-by-step explanation:

Because they’re vertical angles, that means they’re equal to each other so:

m<C = m<D

x = -3x + 80

x + 3x = 80

4x = 80

x = 20

Since m<C equals x, that means m<C is 20°

Answer:

P = 1,-10

Q=1,-1

R=7,-1

S=7,-10

Answer:

bạn cực ngu

Step-by-step explanation:

bạn cực kì ngu

Answer:

Step-by-step explanation:

This requires some serious work before we even begin. First off, we will convert the km to meters:

32 km = .032 m

46 km = .046 m

And then we have to deal with the angle given as 40 degrees west of north. An angle 40 degrees west of north "starts" at the north end of the compass and moves towards the west (towards the left in a counterclockwise manner) 40 degrees. That means that the angle that is made with the negative x axis is a 50 degree angle. BUT the way angles are measured in standard form are from the positive x-axis, therefore:

40 degrees west of north = 50 degrees with the negative x axis = 130 degrees with the positive x axis. 130 is the angle measure we use. Phew! Now we're ready to start. Adding vectors requires us to use the x and y components of vectors in order to add them.

[tex]A_x=.032cos90.0[/tex] so

[tex]A_x=0[/tex] (the 90 degrees comes from "due north")

[tex]B_x=.046cos130[/tex] so

[tex]B_x=-.030[/tex] and if we add those to get the x component of the resultant vector, C:

[tex]C_x=-.030[/tex]   And onto the y components:

[tex]A_y=.032sin90.0[/tex] so

[tex]A_y=.032[/tex]

[tex]B_y=.046sin130[/tex] so

[tex]B_y=.035[/tex] and if we add those together to get the y component of the resultant vector, C:

[tex]C_y=.067[/tex]  Note that since [tex]C_x[/tex] is negative and [tex]C_y[/tex] is positive, the resultant angle (the direction) will put us into QII.

We find the magnitude of C:

[tex]C_{mag}=\sqrt{(-.030)^2+(.067)^2}[/tex]

We will round this after we take the square root to the thousandths place.

[tex]C_{mag}=.073m[/tex] and now for the angle:

[tex]\theta=tan^{-1}(\frac{.067}{-.030})[/tex] which gives us an angle measure of -67, but since we are in QII, we add 180 to that to get that, in sum:

The magnitude of the resultant vector is .073 m at 113°

Answer:

Step-by-step explanation:

We need to create a system of equations here, one for the NUMBER of tickets sold and one for the COST of the tickets. They are very much NOT the same thing.

We have that the total number of tickets is 5, and that that total is made up of adult tickets and child tickets. The equation for the NUMBER of tickets, then, is:

a + c = 5

Now for the money.

If a child ticket costs Rc 500, the expression that represents that that is in fact the cost of the child ticket is 500c;

likewise for the adult ticket. If the adult ticket costs Rc 700, the expression that represents that is 700a.

And we know that a total of Rs 1300 was spent on the tickets. The equation for the COST is

700a + 500c = 1300

Now go back to the first equation and solve it for either a or c, it doesn't matter which. I solved for a:

a = 5 - c  and we will sub that into the second equation for a:

700(5 - c) + 500c = 1300 and

3500 - 700c + 500c = 1300 and

-200c = -400 so

c = 2 tickets. That means that there were

a = 3 tickets sold for the adults.

Answer:

equation of the line would be y=-3x+7

Step-by-step explanation:

because the line goes 3 up and 1 behind for the next point ad the line is not y intercept 7

Answer:

A

Step-by-step explanation:

Recall that the sum of an arithmetic series is given by:

[tex]\displaystyle S = \frac{n}{2}\left(a + x_n\right)[/tex]

Where n is the number of terms, a is the first term, and x_n is the last term.

We know that the initial term a is 13, the common difference is 7, and the total sum is 2613. Since we want to find the number of terms, we want to find n.

First, find the last term. Recall that the direct formula for an arithmetic sequence is given by:

[tex]x_n=a+d(n-1)[/tex]

Since the initial term is 13 and the common difference is 7:

[tex]x_n=13+7(n-1)[/tex]

Substitute:

[tex]\displaystyle S = \frac{n}{2}\left(a + (13+7(n-1)\right)[/tex]

We are given that the initial term is 13 and the sum is 2613. Substitute:

[tex]\displaystyle (2613)=\frac{n}{2}((13)+(13+7(n-1)))[/tex]

Solve for n. Multiply both sides by two and combine like terms:

[tex]5226 = n(26+7(n-1))[/tex]

Distribute:

[tex]5226 = n (26+7n-7)[/tex]

Simplify:

[tex]5226 = 7n^2+19n[/tex]

Isolate the equation:

[tex]7n^2+19n-5226=0[/tex]

We can use the quadratic formula:

[tex]\displaystyle x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

In this case, a = 7, b = 19, and c = -5226. Substitute:

[tex]\displaystyle x =\frac{-(19)\pm\sqrt{(19)^2-4(7)(-5226)}}{2(7)}[/tex]

Evaluate:

[tex]\displaystyle x = \frac{-19\pm\sqrt{146689}}{14} = \frac{-19\pm 383}{14}[/tex]

Evaluate for each case:

[tex]\displaystyle x _ 1 = \frac{-19+383}{14} = 26\text{ or } x _ 2 = \frac{-19-383}{14}=-\frac{201}{7}[/tex]

We can ignore the second solution since it is negative and non-natural.

Therefore, there are 26 terms in the arithmetic series.

Our answer is A.

Step-by-step explanation:

the answer is -1. I have a picture, take a lot at it

Answer: 3x+3

Step-by-step explanation:

4x+3-x

= (4x-x) + 3

= 3x+3

Given:

The probability of drawing a red candy at random from a bag of 25 candies is [tex]\dfrac{2}{5}[/tex].

To find:

The probability of randomly drawing a red candy from the bag after removing 5 candies from the bag.

Solution:

Let n be the number of red candies in the bag. Then, the probability of getting a red candy is:

[tex]P(Red)=\dfrac{\text{Number of red candies}}{\text{Total candies}}[/tex]

[tex]\dfrac{2}{5}=\dfrac{n}{25}[/tex]

[tex]\dfrac{2}{5}\times 25=n[/tex]

[tex]10=n[/tex]

After removing the 5 candies from the bag, the number of remaining candies is [tex]25-5=20[/tex] and the number of remaining red candies is [tex]10-5=5[/tex].

Now, the probability of randomly drawing a red candy from the bag is:

[tex]P(Red)=\dfrac{5}{20}[/tex]

[tex]P(Red)=\dfrac{1}{4}[/tex]

Therefore, the required probability is [tex]\dfrac{1}{4}[/tex].