The perimeter of the Canadian Flag is 192 cm. Its length is twice the width.
If x = the length of the flag and y = the width of the flag, the linear system of
equations that could be used to model this situations is,
ax + 2y = b
A cx = dy
The value of a is:?
The value of b is:?
The value of c is:?
The value of d is:?

Answer: C

Step-by-step explanation:

The center is at (1,0). This eliminates all the options except for C.

Answer:2/pi

Step-by-step explanation:

First, name the points. Top Left will be A, Top Right will be B, Bottom Right will be C, and Bottom Left will be D. Now, the area of ABCD is 4. Then, we have to find the area of the circle. The center to the midpoint of AB is 1. The length of the midpoint of AB to B is 1. So, using the Pythagorean Theorem, it will be 1^2 + 1^2 = 2, then it will be sqrt2. Finding the area of the circle will be easy now that we have the radius. sqrt2*sqrt2*pi = 2pi. So, it will be 4/2pi, and simplified, it will be 2/pi.

Answer:

7.393691004

Step-by-step explanation:

7.4 is the standard deviation from the following set of observation 20, 25, 30, 36, 32, 43​

Statistics is the discipline that concerns the collection, organization, analysis, interpretation, and presentation of data.

The given data set is 20, 25, 30, 36, 32, 43​

Firstly we have to find the mean

Mean=20+25+30+36+32+43/6

=186/6

=31

The deviations from the mean are 20-31=-11

25-31=-6

30-31=-1

36-31=5

32-31=1

43-31=12

Using the definition of standard deviation (σ) , we have:

σ=√121+36+1+25+1+144/6

σ=√328/6

σ=√54.66=7.4

Hence, 7.4 is the standard deviation from the following set of observation 20, 25, 30, 36, 32, 43​

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Find the least common multiple.

List the multiples of each number:

6, 12, 18, 24, 30, 36, 42

10, 20, 30, 40

15, 30, 45

The least common multiple is 30.

The answer is 30

Answer:

3196 to the 8th power

Step-by-step explanation:

the difference is that -24 is just an integer and (-2)4 is asking you to multiply -2 by positive 4

Answer:

The answer is A. 54 (sqrt)2

Step-by-step explanation:

Answer:

soy de ecuador p-by-step e

Answer:

m∠ADC = 90°

5x-5 = 90

x = 19

Step-by-step explanation:

"reassessed" has a total of 10 characters, one of which (e) occurs 3 times and another (s) which occurs 4 times.

Taking each character to be distinct, there would be a total of 10! permutations. But we don't want to do that, and instead want, for instance,

rEassessEd

and

rEassessEd

to count as the same permutation. So we divide the previous total by the number of ways we can permute each set of repeated characters. For example, 3 e's can be rearranged in 3! ways.

So the total number of distinguishable permutations would be

10!/(3! × 4!) = 25,200

The fraction of packages that weigh less than 30kg is 3/8 for the given histogram.

To find the fraction of packages that weigh less than 30kg, we need to look at the histogram and count the number of packages that fall in the bins to the left of the 30kg mark.

Let's assume that w is weight.

As per the histogram, we have

0 ≤ w ≤10 : 0.55

10 < w ≤ 20 : 0.55

20 < w ≤ 30 : 1.9

So, 0 ≤ w ≤ 30.

0.55 × 2 + 1.9 = 3.

The total can be calculated as:

0.55+0.55+1.9+0.2+0.75+0.75+1.65+1.65 = 8

This means there are 8 packages that weigh less than 30kg.

Here, fraction = 3/8

Therefore, the fraction of packages that weigh less than 30kg is 3/8.

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The missing histogram is attached below.

Answer:

answer is

4ft * 5ft

= 20ft^2

Answer: 17/28

Step-by-step explanation:

Since there is a total profit of 6/7 million dollars and the spinning department gave a profit of 1/4 million, then the profit gotten from other departments will be the fraction of profit from the spinning department subtracted from the total profit. This will be:

= 6/7 - 1/4

= 24/28 - 7/28

= 17/28

The fraction of profit from other department is 17/28.

Answer: 6.633 Feet

Step-by-step explanation:

Answer:

14

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan theta = opp side /adj side

tan theta = 8/33

taking the inverse tan of each side

tan^-1 (tan theta) =tan^-1 (8/33)

theta = tan ^-1 (8/33)

theta =13.62699486

To the nearest degree

theta = 14

We simply add the two subtotals to get the grand total. If we knew the value of b, then we'd be able to find an actual numeric result.

For example, let's say b = 100 pies were baked last year. That would mean b+158 = 100+158 = 258 pies were made over the two year period. However, since we don't know what b is, we just leave b+158 as is.

============================================================

Explanation:

If we plug in x = -3, then we get

y = (1/3)*x + 2

y = (1/3)*(-3) + 2

y = -1 + 2

y = 1

So the point (-3, 1) is on the line instead of (-3, 2). This rules out choice A.

Now let's try x = 3

y = (1/3)*x + 2

y = (1/3)*(3) + 2

y = 1 + 2

y = 3

We can see that (3,3) is on the line. That directs us to choice C as the final answer.

For the sake of completeness, let's try x = 6 to see what we get

y = (1/3)*x + 2

y = (1/3)*(6) + 2

y = 2 + 2

y = 4

So the point (6,4) is on the line instead of (6,8), which allows us to rule out choice D.

Answer:

Option B

Step-by-step explanation:

The function is in the form A cos (bx)+c where A is the amplitude and B is the period. The amplitude of this function is 3 so that rules out option D. The formula for finding the period is 2pi/b so 2pi/pi/2 is 4 so that makes the period 4. The equation that matches the description is B

Answer: [tex]25.9\%[/tex]

Step-by-step explanation:

Given

Shopkeeper allows 15% discount on the marked price and still manages a profit of 7%

Suppose the marked price is [tex]x[/tex]

So, the selling price is [tex](1-0.15)x=0.85x[/tex]

Suppose the cost price is [tex]y[/tex]

[tex]\Rightarrow \dfrac{0.85x-y}{y}=7\%\\\\\Rightarrow \dfrac{0.85x}{y}-1=0.07\\\\\Rightarrow \dfrac{0.85x}{y}=1.07\\\\\Rightarrow y=\dfrac{0.85x}{1.07}\\\\\Rightarrow y=0.794x[/tex]

So, the percentage the shopkeeper marked his goods above cost price

[tex]\Rightarrow \dfrac{x-y}{y}\times 100\\\\\Rightarrow \dfrac{x-0.794x}{0.794}\times 100\\\\\Rightarrow \dfrac{0.2056}{0.794x}\times 100\\\\\Rightarrow 25.89\%\approx 25.9\%[/tex]

Answer:

[tex]{ \tt{f(x) = (x + 2)(x + 2.2i)(x - 2.2i)}}[/tex]

Answer:

f the mean of this set is equal to 20, we can write down the below equation,

20 = (x1 + x2 +x3 + .... + x10)/10

x1 + x2 + x3 + ... x10 = 200

Then we can also write an equation for the mean of the given numbers as below,

Mean  = [(x1+4) + (x2+8) + (x3+12) + .... + (x10+40)]/10

          = (x1 + x2 + x3 + ... + x10 + 4 + 8 + 12 + ... + 40)/10

Then we can use above equation (1) to replace x1 + x2 + x3 + ... + x10 by 200

Mean = (200 + 4 + 8 +12 + 16 + 20 + 24 + 28 + 32 + 36 + 40)/10

        = 420/10

        = 42

If you remember Arithmetic Progressions you can simply add together the above number set.

If you closely look above, you can find that there is an Arithmetic Progression : 4, 8, 12, ... , 40

Here we want the addition of 10 terms. So we can use,

Sn = n/2(a+l)

S10 = 10/2(4+40)

      = 220

Then you can easily get the answer,

Mean = (200 + 220)/10

         = 42

Answer:

D. A straight line segment can be drawn between any two points.

Step-by-step explanation:

Euclid of Alexandria was famously known and regarded as the founder of geometry, as well as the father of geometry. He was born in the Mid-fourth century, BC and he specialized in the field of Mathematics. Some of his popular works in the field of Mathematics were Euclid's Elements, Euclidean algorithm and Euclidean geometry.

One of the basic postulate of Euclidean geometry is that a straight line segment can be drawn between any two points.

Others include;

I. All right angles are congruent.

II. All straight line segment is indefinitely extendable in a straight line.

Answer:

-6

Step-by-step explanation:

3*2=6

so the opposite of 6 is -6

Also a negetive times a positive is always a negetive number

Answer:

I assume that we want to find the inverse of the function:

f(x) = 2*x + 10

Remember that the inverse of a function f(x), is a function g(x) such that:

f( g(x) ) = g( f(x) ) = x

Because f(x) is a linear function, we can assume that g(x) will also be a linear function:

g(x) = a*x + b

let's find the values of a and b.

We will have that:

f( g(x) ) = 2*g(x) + 10 = 2*(a*x + b)  + 10

And that must be equal to x, then we need to solve:

2*(a*x + b)  + 10 = x

2*a*x + 2*b + 10 = x

this must be true for all values of x, so we can separate it as:

(2*a*x) + (2*b + 10) = x + 0

2*a*x = x    (one equation for the terms with x)

2*b + 10 = 0

Solving these two equations we get:

2*b = -10

b = -10/2 = -5

2*a*x = x

2*a = 1

a = 1/2

Then the inverse function is:

g(x) = (1/2)*x - 5

when x= 11

or,y= 35x +y/7

or,y= 35×11+y/7

or,y=(385×7+y)/7

or,7y=2695+y

or,7y-y =2695

or,y=2695/6

or, y = 449.167

Answer:

Forth term = x + 6

Fifth term = x + 8

Sixth term = x + 10

Formular for nth term:

[tex]{ \tt{n _{th} = a + (n - 1)d}} \\ { \tt{{n _{th} = x + (n - 1) \times 2}}} \\ { \tt{{n _{th} =x + 2n - 2 }}}[/tex]

Answer:

Hello,

Step-by-step explanation:

First term of this aritmetical sequence is x+0*2

[tex]U_1=x+0*2\\U_2=x+2=x+1*2\\U_3=x+4=x+2*2\\U_4=x+6=x+3*2\\\\n^{th}\ term\ is\ U_n=x+(n-1)*2\\[/tex]

Answer:

x is 90° I hope it will help you please follow me

Answer:

My answer came 78°

Step-by-step explanation:

First, B and C are alternate angles so,

71°= y (let) + 29°

Y= 42°

Then, X + 42 + 60 = 180°

X = 180 - 102

X = 78 °

Hope this helps. :)

[tex]\\ \sf\longmapsto 3\dfrac{1}{3}+4\dfrac{1}{6}+5\dfrac{1}{2}[/tex]

[tex]\\ \sf\longmapsto \dfrac{10}{3}+\dfrac{25}{6}+\dfrac{11}{2}[/tex]

[tex]\\ \sf\longmapsto \dfrac{40+50+66}{12}[/tex]

[tex]\\ \sf\longmapsto \dfrac{156}{12}[/tex]

[tex]\\ \sf\longmapsto Perimeter=11in[/tex]

Answer:

13 in.

Step-by-step explanation:

3 + 5 + 4 = 12

1/3 + 1/6 + 1/2 = 1

12 + 1 = 13

Answer:

if im not mistaken its 121

Step-by-step explanation:

Answer:

99°

Step-by-step explanation:

The interior angle sum of any 5 sided polygon is 540°.

540-53 = 487 - 137 = 350 - 105 = 245- 146 = 99°

Answer:

Rational numbers can be written as a fraction where p and q are integers and q is not equal to zero