The medians of ATUV are TX, UY, and VW. They meet at a single point Z.
(In other words, Z is the centroid of ATUV.)
Suppose UY=27, TZ=24, and ZW = 10.
Find the following lengths.
Note that the figure is not drawn
to scale..
7
U
X
VW =
UZ = 0
ZX = 0

It is true that when difference on dependent variable is attributed to effect of that variable through statistical hypothesis testing then it is unlikely that the difference would occur by chance alone

A formal assertion about the nature of a phenomenon made within the constraints of a statistical model is known as a statistical hypothesis.

Statistical hypothesis is a description of the makeup of a population. A population parameter is frequently used to express it.

There are two statistical hypotheses used in hypothesis testing. The above-described null hypothesis (H0) is the first.

If it turns out that the null hypothesis is statistically invalid, an alternative hypothesis (Ha) for each H0 will be given preference. Depending on the research hypothesis, the Ha may be directed or nondirectional.

About the statement in the question,

It is improbable that an observed difference between two groups on the dependent variable would occur by chance alone when the difference is explained by the effect of the dependent variable through statistical hypothesis testing.

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The probability that the first success occurs on trial number n = 3 is 0.032

Given:

probability of success on a single trial p = 0.80

trial number, n = 3

Recall the formula for the Geometric Probability Distribution

P(n) = p(1 - p)ⁿ⁻¹

where n is the number of the binomial trial on which the first success occurs and p is the probability of success on each trial

P(n) = p(1 - p)ⁿ⁻¹

P(3) = 0.8(1-0.8)³⁻¹

P(3) = 0.8(0.2)²

P(3) = 0.032

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Answer:

[tex]2x^2+7x+C[/tex]

Step-by-step explanation:

Find the antiderivative of f'(x)=4x+7

[tex]\frac{4x^{1+1} }{1+1}+7x+C\\\frac{4x^2}{2}+7x+C\\ 2x^2+7x+C\\[/tex]

The statement of the problem has already made a lot of decisions for us. We are told to use three global variables of type int[]. The variables must be static, and I have chosen to make them private, so the declarations become:

private static int[] firstNumbers;  // The first numbers in all ten questions.

private static int[] secondNumbers; // The second numbers in all ten questions.

private static int[] user answers;   // The user's answers to the ten questions.

Note that these declarations are not in any subroutine. These statements only create variables, not arrays. We still need to create three arrays of length 10. The arrays can be created using the new operator. This initialization could in fact be combined with the declaration of the variables:

private static int[] firstNumbers = new int[10];

private static int[] secondNumbers = new int[10];

private static int[] userAnswers = new int[10];

Another possibility would be to create the three arrays at the beginning of the main() routine. In fact, I chose to create them in the subroutines where they are first used.

The program has three stages -- create the problems, administer the quiz, and grade the quiz -- and we are told to write a subroutine to do each stage. The main program simply has to call the subroutines:

public static void main(String[] args) {

   createQuiz();

   administerQuiz();

   gradeQuiz();

}

This is an example of using subroutines to break up a large task into several simpler subtasks, so that programming each subtask becomes a separate problem. The subroutines are short and not too hard to write. Looking at administerQuiz() as an example, note that the user's answers have to be stored in the array, the user answers so that they can be used when grading the quiz. I create the array itself before asking any questions and then store the user's responses in the array as they are read by the user. On the other hand, the arrays that hold the numbers that occur in the questions have already been created and filled before administerQuiz() is called. Here's the subroutine:

private static void administerQuiz() {

   userAnswers = new int[10];

   for (int i = 0; i < 10; i++) {

       int questionNum = i + 1;

       System.out.printf("Question %2d:  What is %2d + %2d  ? ",

                     questionNum, firstNumbers[i], secondNumbers[i]);

       userAnswers[i] = TextIO.getlnInt();

   }

}

A couple notes about the output: I wanted to number the questions 1, 2, ..., 10, but the elements of the arrays are numbered 0, 1, ..., 9. This means that the question number that I output has to be one more than the array index. Also, all the numbers that occur in my program are either one or two digits. By allowing exactly two digits for each number in the output, I can get everything to line up neatly. Here's the I/O for a sample run of the program:

Welcome to the addition quiz!

Question  1:  What is 40 + 14  ? 54

Question  2:  What is 18 + 38  ? 46

Question  3:  What is 21 + 31  ? 52

Question  4:  What is 18 + 36  ? 54

Question  5:  What is 43 + 12  ? 55

Question  6:  What is 21 + 17  ? 38

Question  7:  What is 33 + 25  ? 58

Question  8:  What is 39 + 21  ? 70

Question  9:  What is  1 + 25  ? 26

Question 10:  What is 39 + 26  ? 65

Here are the correct answers:

  Question  1:  40 + 14  =  54.  You were CORRECT.

  Question  2:  18 + 38  =  56.  You said 46, which is INCORRECT.

  Question  3:  21 + 31  =  52.  You were CORRECT.

  Question  4:  18 + 36  =  54.  You were CORRECT.

  Question  5:  43 + 12  =  55.  You were CORRECT.

  Question  6:  21 + 17  =  38.  You were CORRECT.

  Question  7:  33 + 25  =  58.  You were CORRECT.

  Question  8:  39 + 21  =  60.  You said 70, which is INCORRECT.

  Question  9:   1 + 25  =  26.  You were CORRECT.

  Question 10:  39 + 26  =  65.  You were CORRECT.

You got 8 questions correct.

Your grade on the quiz is 80.

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Answer:

Step-by-step explanation:

log base (2) of (x^2 +5) = (3) can also be described as 2^3 = x^2 + 5

simplify: 8 = x^2+5

Subtract 5 from each side: 3 = x^2

square root: x = sqrt(3)

Answer:

Step-by-step explanation:

[tex]log(2)^{(x^2+5)}=3\\[/tex]

[tex]2^3 =x^2+5\\8-5=x^2\\x^2=3\\x=\pm\sqrt{3}[/tex]

Answer:

Dan has 42 quarters and 25 dimes.

Step-by-step explanation:

The total interest paid on the loan repayable over three months weekly at 2.85% per week is $3,584.96.

The total interest can be computed using an online finance calculator.

The result is then added to the late payment fees.  The default payment fee is the product of $600 and 5.

N (# of periods) = 14 weeks (3 x 4 + 2)

I/Y (Interest per year) = 2.85%

PV (Present Value) = $50,000

PMT (Periodic Payment) = $4,000

Results:

Sum of all periodic payments = $56,000.00

Total Interest = $584.96

Late payment charge = $3,000 ($600 x 5)

Total interest and late charge = $3,584.96

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Assume that the borrower repays $4,000 weekly.

Answer:

x- intercept = - 8 , y- intercept = 6

Step-by-step explanation:

to find the x- intercept let y = 0 in the equation and solve for x

3x - 4(0) = - 24

3x = - 24 ( divide both sides by 3 )

x = - 8 ← x- intercept

to find the y- intercept let x = 0 in the equation and solve for y

3(0) - 4y = - 24

- 4y = - 24 ( divide both sides by - 4 )

y = 6 ← y- intercept

The beginning balance of the cash account = $23075

A cash account is a type of brokerage account that requires that all transactions be settled in full on the settlement date using available cash.

In order to ensure that there is sufficient cash on hand to fulfill the buy order when buying stocks in a cash account, the investor must either make a deposit of enough money to cover the transaction or sell other securities on the same trading day.

Contrary to margin accounts, cash accounts do not allow short selling or margin trading.

According to the given question, cash payments were 80% of collections. So, The cash payment or Disbursement are as follows:-

Disbursements = 80% of collections

Disbursements = $115,375 * 0.8

Disbursements = $92,300

The opening balance is computed by using the following formula:-

Opening Balance = Collections - Disbursements

= $115,375 - $92,300

= $23075

Therefore,

The beginning balance of the cash account = $23075

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(a) There are 36 ways to select 8 apartments randomly by cluster sampling method.

(b) Throughout this process, we obtain floors 3, 4, 6, or 3, 6, which do not have sample flats with children, and as a result, the sample will not accurately reflect the population.

(a) Given the building has 9 floors which are taken as N=9 clusters.

Each floor has 4 apartments.

It is to select 8 apartments by cluster sampling method.

That is to select a sample of size any n=2 floors(clusters) by cluster sampling method out of the population of N=9 clusters.

By simple random sampling without replacement, there are NCn = 9C2 =36 ways to select 2 clusters.

Hence, there are 36 ways to select 8 apartments randomly by cluster sampling method.

(b) The main benefit of stratified sampling over cluster sampling is that the sample obtained using this method will unquestionably include representations of both features, i.e., apartments with and without children as a full representative of the population.

In contrast, there is no guarantee that the sample of flats with and without children from the cluster sampling approach will accurately reflect both qualities. Sometimes throughout this process, we obtain floors 3, 4, 6, or 3, 6, which do not have sample flats with children, and as a result, the sample will not accurately reflect the population.

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The right question is given beow:

If the price of a latte is $4 and the price of a muffin is $2, then we can conclude that Julia can buy 5 lattes or 10 muffins ($20) if she chooses to buy only one of the two goods.

A price is the sum of money that one party pays or receives in exchange for another's goods or services. The cost of production may go by another name in certain circumstances. If the item is a "good" in a commercial transaction, the cost of the item will probably be referred to as its "price."

In this case, Allie receives a $20 gift card for the local coffee shop, where she only buys lattes and muffins. Here, we can conclude that Julia can buy 5 lattes. This will be 5 × $4 = $20 or 10 muffins which will be:

= 10 × $2

= $20

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The total fixed cost must be B . $2,500 .

Given :

Average variable cost ( AVC ) = $50

Average total cost ( ATC ) = $75

Output ( Q ) = 100

Since Average fixed cost is the difference between the average total cost and the average Variable cost. This will be:

Average fixed cost = average total cost -  average Variable cost

Average fixed cost = $75 - $50

Average fixed cost = $25

We know that :

AFC = TFC / Q

TFC = AFC × Q

TFC = $25 × 100

TFC = $2500

Therefore, total fixed cost is $2500

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The simplified expression of the fraction in its simplest form is -12a¹¹r⁻³

From the question, we have the following parameters that can be used in our computation:

\frac{3a^9r^{-3}}{-4(a^2)^{-1}}

Rewrite the above expression properly

So, we have the following representation

3a⁹r⁻³/(-4a²)⁻¹

Evaluate the expression in bracket

So, we have the following representation

3a⁹r⁻³/(-4a²)⁻¹ = 3a⁹r⁻³ * (-4a²)

Remove the brackets

This gives

3a⁹r⁻³/(-4a²)⁻¹ = 3a⁹r⁻³ * -4a²

Evaluate the products

So, we have the following representation

3a⁹r⁻³/(-4a²)⁻¹ = -12a¹¹r⁻³

Hence, the the fraction expression in its simplest form is -12a¹¹r⁻³

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The following statements are true are more than 40% of the students at the school are freshmen or sophomores who plan to attend college.

Given :

emily surveyed all the students at her school to find out if they plan to attend college. the results are shown in the two-way frequency table. emily knows that the student body at her high school is distributed as follows: freshmen: 28 % sophomores: 26 % juniors: 24 % seniors: 22 %  .

Freshmen = 0.85

sophomores = 0.80

it is clearly visible that the freshmen or sophomores is greater than the 40 % .

Hence , more than 40% of the students at the school are freshmen or sophomores who plan to attend college.

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Conditional problems are problems that involve one or more conditions that must be met in order for a certain action to be taken or a certain result to be obtained. The temperature of the solution in degrees Fahrenheit after x hours, is y = 1.5x - 100.

The required details for Conditional problems in given paragraph

This function models the temperature of the solution as it decreases at a constant rate of 1.5 °F per hour. The initial temperature of the solution is 100 °F, and the temperature decreases by 1.5 °F for each hour that passes. Therefore, the temperature of the solution after x hours can be found by subtracting 1.5x degrees from the initial temperature of 100 degrees.

For example, if we plug in x = 2 into the function, we get y = 1.5 * 2 - 100 = 3 - 100 = -97, which means that the temperature of the solution after 2 hours is -97 °F.

The other options listed are not correct because they do not correctly model the temperature of the solution as it decreases at a constant rate of 1.5 °F per hour. Option A is incorrect because it adds 1.5x degrees to the initial temperature, rather than subtracting it. Option B is incorrect because it adds 100 degrees to the temperature, rather than subtracting it. Option C is incorrect because it multiplies the initial temperature by 1.5x, rather than subtracting 1.5x degrees from it. Option D is incorrect because it adds 1.5 to the temperature, rather than subtracting 1.5x degrees from it.

what are conditional problems?

Conditional problems are often expressed using words like "if," "then," or "when." For example, a conditional problem might involve finding the value of a variable x if it satisfies a certain condition, such as "If x is greater than 5, then x is even." In this case, the problem specifies that x must be greater than 5 in order for it to be even.

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Reason:

The horizontal width spans from 8 to 20. This is a distance of 20-8 = 12 units.

The height is some unknown, which I'll call x. We multiply the width and height to get the area. This area must be 1 to represent 100%. You can think of it like a pie chart. This applies to any probability distribution.

area = base*height

1 = 12*x

x = 1/12

Therefore, the height of this rectangle must be 1/12 so that the area of this rectangle is 1.

The maximum area of the tile to contain both grounds is 12x²y²

From the question, we have the following parameters that can be used in our computation:

Area of ground A = 12x^2y sq. units

Area of ground B = 6xy^2sq units

Rewrite these areas properly

So, we have the following representation

Area of ground A = 12x²y sq. units

Area of ground B = 6xy² sq units

Express the areas as the products of their prime factors

This gives

Area of ground A = 2 * 2 * 3 * x * x * y

Area of ground B = 2 * 3 * x * y * y

From the above products, we have

Least common multiple = 2 * 2 * 3 * x * x *y * y

Evaluate the products

Least common multiple = 12x²y²

This represents the greatest area

Hence, the greatest area is 12x²y²

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Answer:

Step-by-step explanation:

When any value of x, other than 0, is multiplied by itself the result will ALWAYS be a POSITIVE value. Therefore, equations in the form x square =p, where p is GREATER THAN 0, will have 2 SOLUTIONS.

Answer:

Step-by-step explanation:

so a(x+4)(x-3)is total form after putting the point you will have 4(x+4)(x-3)=y

so answer is 4x^2+4x-48=y

The dimensions of the rectangular box with largest volume if the total surface area is given as 100 cm2: x = y = z = 2.449 cm.

Given that:

Total surface area of the rectangular box or cuboid = 100 cm²

A rectangular box with largest volume is a cube.

The total surface area of a cube = 6 times square of one edge length.

Let the edge length = given dimensions; x, y, z

So,

x = y = z

6x^2 = 100

x^2 = 100 / 6

x = √ 100 / 6

x = 10 / √ 6 cm

x = 2.449 cm

Hence, dimensions of the rectangular box with largest volume if the total surface area is given as 100 cm2: x = y = z = 2.449 cm.

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The complete answer: A domain is a set of input data in a relationship.

The collection of all conceivable independent values that a function or relation may take is known as its domain.

An input value and an output value are matched in a relation.

A relation is a function where each input value yields one and only one output value.

Graphs, tables, and ordered pairs can all be used to represent functions. The domain is the set of input values,

while the range is the set of output values.

The domain of a function or relation is the set of all possible independent values that it can have.

Therefore,  a domain is a set of input data in a relationship.

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Step-by-step explanation:

[tex]1. \: \: 3x +4 y = 8.50[/tex]

[tex]2. \: \: 5x + 8y = 14.50[/tex]

times equation 1 by 2

[tex]3. \: \: 6x + 8y = 17[/tex]

3-2 eliminates y variable

[tex]x =2.50[/tex]

[tex]y = 0.25[/tex]

By using the well ordering principle we can easily prove that the equation

4a³ + 2b³ = c³ does not have any solution for positive integers.

Let (a, b, c) be a positive integer solution with c the smallest possible.

Then c³ is even as the sum of a factor of 4 and factor of 2 is always even .

hence c itself is even.

Let us consider  c = 2c₀ ;

4a³ + 2b³ = (2c₀)³

or, 4a³ + 2b³ = 8c₀³

then 2a³+b³ = 4c₀³

This time, we see that b must be even. using the same principle as above .

Put b = 2b₀ ;

2a³ + 8b₀³ = 4c₀³

then a³ + 4b₀³ = 2c₀³

thus a = 2a₀ must be even,

and 4a₀³+2b₀³=c₀³,

i.e. (a₀, b₀, c₀) is another solution. But c₀ = c/2<c.

And we have taken c to be the smallest of the solutions.

hence we get a contradiction.

Therefore our assumption is not valid.

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The whole Python code is included below as an image, and it sets the base and height of triangles 1 and 2, then calculates the bigger area.

The code for determining the area of the triangle is:

class Triangle:

def __init__(A):

A.base = 0

A.height = 0

def set_base(A, user_base):

A.base = user_base

def set_height(A, user_height):

A.height = user_height

def get_area(A):

area = 0.5 * A.base * A.height

return area

def print_info(A):

print('Base: {:.2f}'.format(A.base))

print('Height: {:.2f}'.format(A.height))

print('Area: {:.2f}'.format(A.get_area()))

if __name__ == "__main__":

triangle1 = Triangle()

triangle2 = Triangle()

# TODO: Read and set base and height for triangle1 (use set_base() and set_height())

# TODO: Read and set base and height for triangle2 (use set_base() and set_height())

# TODO: Determine smaller triangle (use get_area())

print('Triangle with smaller area:')

# TODO: Output smaller triangle's info (use print_info())

Traingle is a type of polygon, the name itself days, tri means three, angles.

So, in a triangle, there will be three vertices, three sides and three angles.

The vertex of a triangle is a point where any two of the sides of a triangle meet.

The altitude of a triangle is the perpendicular length of the triangle, it is also called as height of the triangle. It is drawn perpendicular on the base of the triangle to the apex.

Base of a triangle is that particular side of the triangle on which an altitude is drawn.

For writing the code, we will put the input like only values, like 6.0, 7.0, 11.0 etc.

The first value will denote base of first triangle, second will denote height  of first triangle and third will denote base of second triangle and fourth value denotes height of second triangle/

Let us assume that,

Triangle with smaller area:

Base: 4.00

Height: 5.00 = [4.00*5.00]2 = 10.00

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Answer:

To find the difference between the elevations of City A and City B, we need to subtract the elevation of City A from the elevation of City B. Since City A is located 15 meters below sea level, and City B is located 43 meters above sea level, the difference between their elevations is $43 - (-15) = 43 + 15 = 58 meters. Therefore, the difference between the elevations of City A and City B is 58 meters.

The Slope intercept form of equation passing through points ( 1 , 3 ) and having slope 3 is y = 3x

In mathematics, formulating an equation for a line in the form y = mx + b is known as slope intercept form. The m stands for the line's slope, and the b for the y-intercept. When you need to find a point on a line or solve for y given x, you utilize the slope intercept form.

According to the given information

Form of the slope intercept: y = mx + b

It goes through some points ( 1 , 3 )

Slope of the line given m = 3

Put x = 1 and y = 3 and m = 3 in slope intercept form equation

3 = 3( 1 ) + b

b = 0

Hence

Put the value of b = 0 in y = mx + c

y = 3x

The Slope intercept form of equation passing through points ( 1 , 3 ) and having slope 3 is y = 3x

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All the real numbers except 1 make the two expressions equal. Then the correct option is A.

The equivalent is the expression that is in different forms but is equal to the same value.

The definition of simplicity is making something simpler to achieve or grasp while also making it a little less difficult.

The expressions are given below.

[(x - 1)(x - 6)] / [4(x - 1)] and (x - 6) / 4

Simplify the expression [(x - 1)(x - 6)] / [4(x - 1)], then we have

⇒ [(x - 1)(x - 6)] / [4(x - 1)]

⇒ (x - 6) / 4

But at x = 1, the expression [(x - 1)(x - 6)] / [4(x - 1)] is not defined.

All the real numbers except 1 make the two expressions equal. Then the correct option is A.

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The two linear equations have the same slope, -2/3, and different y-intercepts, thus, the lines are parallel.

A general linear equation is written as:

y = a*x +b

Where a is the slope and b is the y-intercept.

Two linear equations are parallel if both lines have the same slope and different y-intercepts.

And two lines are perpendicular if the product between the slopes is equal to -1.

In this case, we have the two linear equations:

y= -(2/3)*x - 3

y= -(2/3)*x + 6

So you can see that both linear equations have the same slope -2/3 and different y-intercepts, thus, the lines are parallel.

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We have evidence that this is not a symmetrical die, the standardized residuals is 9.5689

The die is tossed 1000 times

Given the observed value

x1 = 163

x2=178

x3=142

x4= 150

x5 = 183

x6 = 184

The mean = 163 + 178 + 142 + 150 + 183 + 184 / 6

= 1000 /6

= 166.67

Next we have to find the value of (observed value - Expected value)^2 / Expected value

x1 = (163-166.67)^2 / 166.67 = 0.081

x2 = (178-166.67)^2 / 166.67 = 0.7659

x3 = (142-166.67)^2 / 166.67 = 3.6598

x4 = (160 -166.67)^2 / 166.67 = 1.673

x5 = (183 - 166.67)^2 /  166.67 =  1.5938

x6 = (184-166.67)^2 / 166.67 =   1.7954

The standardized residuals = 0.081 + 0.7659 + 3.6598 +1.673 +1.5938 +1.7954 = 9.5689

Therefore, this is not a symmetrical die

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