Answer:
0.9029 = 90.29% probability that the mean of the sample would differ from the population mean by less than 3.8 points if 76 exams are sampled
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
The mean points obtained in an aptitude examination is 167 points with a standard deviation of 20 points
This means that [tex]\mu = 167, \sigma = 20[/tex]
Sample of 76:
This means that [tex]n = 76, s = \frac{20}{\sqrt{76}}[/tex]
What is the probability that the mean of the sample would differ from the population mean by less than 3.8 points?
P-value of Z when X = 167 + 3.8 = 170.8 subtracted by the p-value of Z when X = 167 - 3.8 = 163.2. So
X = 170.8
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{170.8 - 167}{\frac{20}{\sqrt{76}}}[/tex]
[tex]Z = 1.66[/tex]
[tex]Z = 1.66[/tex] has a p-value of 0.9515
X = 163.2
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{163.2 - 167}{\frac{20}{\sqrt{76}}}[/tex]
[tex]Z = -1.66[/tex]
[tex]Z = -1.66[/tex] has a p-value of 0.0485
0.9514 - 0.0485 = 0.9029
0.9029 = 90.29% probability that the mean of the sample would differ from the population mean by less than 3.8 points if 76 exams are sampled
The A&M Hobby Shop carries a line of radio-controlled model racing cars. Demand for the cars is assumed to be constant at a rate of 60 cars per month. The cars cost $70 each, and ordering costs are approximately $15 per order, regardless of the order size. The annual holding cost rate is 20%.
Required:
a. Determine the economic order quantity and total annual cost under the assumption that no backorders are permitted.
b. Using a $45 per-unit per-year backorder cost, determine the minimum cost inventory policy and total annual cost for the model racing cars.
c. What is the maximum number of days a customer would have to wait for a backorder under the policy in part (b)? Assume that the Hobby Shop is open for business 300 days per year.
d. Would you recommend a no-backorder or a backorder inventory policy for this product? Explain.
Answer:
Step-by-step explanation:
A) Demand per month= 40 cars
Annual Demand (D)= 12*40 = 480
Fixed Cost per order (K)= 15
Holding Cost= 20% of cost= 60 *0.2 = 12
a. Economic Order Quantity=
Q^{*}={\sqrt {{\frac {2DK}{h}}}}
= √(2*480*15)/12
=34.64 ~ 35
Total Cost =P*D+K(D/EOQ)+h(EOQ/2) P= Cost per unit
= 60*480+ 15(480/35) + 12(35/2)
= 28800+ 205.71+ 210
=$29215.71
B). Backorder Cost (b)= $45
Qbo= Q* × √( b+h/ h)
= 35*√(12+45/ 45)
= 35* 1.12
=39.28 ~ 39
Shortage (S)= Qbo * (K/K+b)
= 39* (15/15+45)
= 39* 0.25
= 9.75
Total Cost Minimum=( bS2/ 2Qbo) + P (Qbo- S)2/2Qbo + K(D/Qbo)
=45* 9.752 / 2* 392 + 60 (39-9.75)2/ 2* 392 + 15 ( 480/39)
= 1.40+ 21.9.+ 184.61
=$207.91
C)Length of backorder days (d) = Demand ÷ amount of working days
d = 480 ÷ 300
d = 1.6
Calculate the backorders as the maximum number of backorders divided by the demand per day
s/d = 9.75/1.6 = 6.09 days (answer)
D) Calculate the difference in total between not using backorder:
$207.85 + $207.85 - 207.91 = $207.79
The saving in using backorder is $207.79.
Therefore I would recommend using a backorder
Using stoke theorem evaluate integral F.dr given that F(x,y,z) = z^2i + 2xj + y^2k and the normal surface is given by s: z = 1-x^2-y^2
Your description of the surface is incomplete. But it looks like you're considering some subset of the paraboloid z = 1 - x ² - y ², so I'll go ahead and assume it's the part of said paraboloid above the x,y-plane, so that the boundary is a circle centered at the origin with radius 1.
By Stokes' theorem, the line integral of F along this boundary (∂S) is equal to the surface integral of curl(F ) over the surface itself (S). We have
F(x, y, z) = z ² i + 2x j + y ² k
which has curl
curl(F ) = (∂(y ²)/∂y - ∂(2x)/∂z) i - (∂(y ²)/∂x - ∂(z ²)/∂z) j + (∂(2x)/∂x - ∂(z ²)/∂y) k
curl(F ) = 2y i + 2z j + 2k
Parameterize S by the vector function,
r(u, v) = u cos(v) i + u sin(v) j + (1 - u ²) k
with 0 ≤ u ≤ 1 and 0 ≤ v ≤ 2π.
Take the upward-pointing normal vector to S to be
n = ∂r/∂v × ∂r/∂u
n = (-u sin(v) i + u cos(v) j ) × (cos(v) i + sin(v) j - 2u k)
n = 2u ² cos(v) i + 2u ² sin(v) j + u k
Then the integral of curl(F ) over S - and hence the line integral of F over ∂S - is
[tex]\displaystyle \iint_S \mathrm{curl}(\mathbf F(x,y,z))\cdot\mathbf S \\\\ = \iint_S \mathrm{curl}(\mathbf F(\mathbf r(u,v)))\cdot\mathbf n\,\mathrm du\,\mathrm dv \\\\ = \int_0^{2\pi}\int_0^1 \left(2u\sin(v)\,\mathbf i + 2(1-u^2)\,\mathbf j + 2\,\mathbf k\right)\cdot\left(2u^2\cos(v)\,\mathbf i+2u^2\sin(v)\,\mathbf j+u\,\mathbf k\right)\,\mathrm du\,\mathrm dv \\\\ = \int_0^{2\pi}\int_0^1 \left(4u^3\sin(v)\cos(v)+4(1-u^2)u^2\sin(v)+2u\right)\,\mathrm du\,\mathrm dv \\\\ = \int_0^{2\pi}\left(\sin(v)\cos(v)+\frac8{15}\sin(v)+1\right)\,\mathrm dv \\\\ = \boxed{2\pi}[/tex]
Just to confirm this result, we can compute the line integral directly, since it's not so difficult to deal with. Parameterize ∂S by the vector function
r(t) = cos(t ) i + sin(t ) j
with 0 ≤ t ≤ 2π. (Note that there is a k component, but its coefficient is 0.) Then
dr/dt = -sin(t ) i + cos(t ) j
and the line integral is again
[tex]\displaystyle \int_{\partial S}\mathbf F(x,y,z)\cdot\mathrm d\mathbf r \\\\ = \int_{\partial S} \mathbf F(\mathbf r(t))\cdot\frac{\mathrm d\mathbf r}{\mathrm dt}\,\mathrm dt \\\\= \int_0^{2\pi} (\cos(t)\,\mathbf i+\sin(t)\,\mathbf j)\cdot(-\sin(t)\,\mathbf i+\cos(t)\,\mathbf j)\,\mathrm dt \\\\ = \int_0^{2\pi}2\cos^2(t)\,\mathrm dt \\\\ = \boxed{2\pi}[/tex]
Find the numerical value of the area under the normal curve given the following information:
to the right of z = 2.28
enter your answer as a decimal (NOT percentage) and lead with a zero...for example: 0.1234
Answer:
1 - 0.9887 = 0.0113
Step-by-step explanation:
The profits for video game companies depend on what game platform the game runs on, which can either be a portible system with a built in screen, or a standard system that you have to hook up to a television. The profit off of a portible game system is $72, while the profit from a standard game system is $90. The store manager has to make at least $360 per day in order to keep the store open. Which graph represents this inequality? Write the inequality that represents the number of games that must be sold everyday to meet or beat the sales goal.
Step-by-step explanation:
The BBQ club meets every Thursday. The meetings last 2 1/2 hours. There were 5 Thursdays in
September. How many hours did the BBQ club meet in September?
A.2 1/2 hours
B.5 hours
C.12 1/2 hours
D.10 hours
Answer:
12 1/2
Step-by-step explanation:
2 x 5 = 10
1/2 x 5 = 2 1/2
10 + 2 1/2 = 12 1/2
f(10)
calculate the indicated function value
Solve for the length of the unknown side in the following right triangle. (Side AC is the hypotenuse.)
Round your answer to two places, where applicable.
Side AB 3 Side BC 4 Side AC ?
Answer:
side AC is 5
Step-by-step explanation:
by using th pythagorean theorm you would square both sides add them together and the square root the sum to get you answer.
AB =3 BC=4
9+16=25
25 square root is 5
makeing AC=5
During a test period, an experimental group of 10 vehicles using an 85 percent ethanol-gasoline mixture showed mean CO2 emissions of 667 pounds per 1000 miles, with a standard deviation of 20 pounds. A control group of 14 vehicles using regular gasoline showed mean CO2 emissions of 679 pounds per 1000 miles with a standard deviation of 15 pounds. At α = 0.05, in a left-tailed test (assuming equal variances) the test statistic is:______.
A. 1.321.
B. -2.508.
C. -2.074.
D. -1.717.
Answer:
-1.683
Step-by-step explanation:
Given :
Group 1 :
x1 = 667 ; n1 = 10 ; s1 = 20
Group 2 :
x2 = 679 ; n2 = 14 ; s2 = 15
The test statistic assuming equal variance :
x1 - x2 / √[Sp² * (1/n1 + 1/n2)]
sp² = [(n1 - 1)*s1² + (n2 - 1)*s2²] ÷ (n1 + n2 - 2)
Sp² = [(10 - 1)*20² + (14 - 1)*15²] = 296.59
Test statistic =
(667 - 679)/ √[296.59 * (1/10 + 1/14)]
-12 / 7.1304978
Test statistic = - 1.682
An advertising firm wanting to target people with strong desires for success conducted a study to see if such people differed in the types of television shows they watched. Randomly selected participants recorded the shows they watched for a week, then their desire for success was assessed, and finally they were divided into two groups. Low Success seekers watched 8 comedies, 15 romances, 6 documentaries, 13 dramas, and 3 news shows. High Success seekers watched 3 comedies, 3 romances, 9 documentaries, 7 dramas, and 8 news shows.
1. Use the five steps of hypothesis testing.
2. Sketch the chi-square distribution. Be sure your sketch gives a rough indication of its shape and shows the cutoff score and the sample's score.
3. Explain the logic of what you have done to a person who is familiar with the logic and steps of hypothesis testing for the t test and analysis of variance, but who knows nothing about chi-square tests.
4. Figure a measure of effect size and indicate whether it is small, medium, or large.
Answer:
Blablabla
Step-by-step explanation:
Bababa
Please help me with this on the picture
Answer:
this is the chapter of linear equations in one variable?
I need help please guys thank you
Answer:
Option A, the parent function has been translated up
Option B, the parent function has been compressed
Option C, the parent function has been translated to the right
If a < 0 and b > 0, then which of the following is true?
Select one:
a. a + b > 0
b. a + b < 0
c.
a + b = 0
d.
The relationship between a and b cannot be determined.
Answer:
d. The relationship between a and b cannot be determined.
Step-by-step explanation:
Given
[tex]a < 0[/tex]
[tex]b > 0[/tex]
Required
Which is true
To do this, we test each of the options using assumed values
[tex]a + b > 0[/tex]
Let:
[tex]a = -5[/tex] [tex]b= 1[/tex]
So:
[tex]-5 + 1 > 0[/tex]
[tex]-4 > 0[/tex] --- false
[tex]a + b < 0[/tex]
Let:
[tex]a = -5[/tex] [tex]b= 7[/tex]
So:
[tex]-5 + 7 < 0[/tex]
[tex]2 < 0[/tex] --- false
[tex]a + b = 0[/tex]
Let:
[tex]a = -5[/tex] [tex]b= 7[/tex]
So:
[tex]-5 + 7 = 0[/tex]
[tex]2 = 0[/tex] --- false
Hence, the relationship is not specific and cannot be determined
Solve the following system of equations for x to the nearest hundredth : y + 2x + 1 = 0; 4y - 4x ^ 2 - 12x = - 7
Answer:
+3.464; -3.464
Step-by-step explanation:
call A = y + 2x + 1 = 0 => y = (1 - 2x)
call B: 4y - 4(x^2) - 12x = -7
=> replace y from A to B =>
4(1 - 2x) - 4(x^2) - 12x = -74 - 8x - 4(x ^ 2) - 12x = -7-8x - 4(x ^ 2) - 12x = -7 - 4 = -11-4(x^2) - (8x - 12x) = -11-4(x^2) + 4x = -11-4(x^2) + 4x + 11 = 0=> get delta Δ = (-4^2) - 4*(-4 * 11) = 192
=> Δ > 0 => got 2 No
=> x1 = [tex]\frac{-4 + \sqrt{192} }{2 * -4}[/tex] = [tex]\frac{1 - 2\sqrt{3} }{2}[/tex] = -1.232
=> x2 = [tex]\frac{-4 - \sqrt{192} }{2 * -4}[/tex]=[tex]\frac{1 + 2\sqrt{3} }{2}[/tex]= 2.232
=> replace x from B into A
=> y1 = (1 - 2x) = (1 - 2 * -1.232) = 3.464
=> y2 = (1 - 2x) = (1 - 2 * 2.232) = - 3.464
Keith may need some help from his manager. A customer is on the phone and she is really angry. She is threatening to post nasty comments on her blog. What should Keith say to his manager? O a) "She's angry. You deal with it." b) "So she's really angry. Her product never arrived. I think we should offer to send her a replacement product free of charge, but wanted your input." "So l'll tell her to calm down. I think she's overreacting. I doubt she'll post c) anything online." "She's really angry; she ordered the product last Wednesday, Don in customer d) service said it would arrive a week later. It was a dollhouse for her niece, Can you take it from here?"
Answer:
"She's really angry; she ordered the product last Wednesday, Don in customer service said it would arrive a week later. It was a dollhouse for her niece, Can you take it from here?" is the best option
Step-by-step explanation:
if 405 is to be divided among three persons A, B, C in the ratio of 3:5:7, how much money does each one get? Express them in percentages.
Step-by-step explanation:
Pls Mark me
Brainliest!!!!Which of the following rational functions is graphed below?
10
- 10
10
tho
A. F(x) =
3
X-7
B. F(x) = x + 3
X-7
C. F(x) =
(x+3)(x-7)
(x+3)(x-7)
D. F(X)
1
(x + 7(x-3)
7\x-
Check the picture out and please help me lol
Vertical asymptote:
A vertical asymptote is a value of x for which the function is not defined, that is, it is a point which is outside the domain of a function;
In a graphic, these vertical asymptotes are given by dashed vertical lines.
An example is a value of x for which the denominator of the function is 0.
In this graphic:
Dashed vertical lines at: [tex]x = -3, x = 7[/tex], thus, for [tex]x - (-3) = x+3[/tex] and [tex]x - 7[/tex] the denominator is zero.
Thus, the function graphed is:
[tex]F(x) = \frac{1}{(x+3)(x-7)}[/tex]
And the correct answer is given by option C.
To take a look at a problem with asymptote, you can check this item https://brainly.com/question/4084552.
The graph is for the rational function f(x) = 1/(x + 3)(x - 7).
Option C is the correct answer.
We have,
To understand the graph of the function f(x) = 1/((x + 3)(x - 7)).
Vertical Asymptotes:
The function has vertical asymptotes at the values of x for which the denominator becomes zero.
The denominator is (x + 3)(x - 7), so the vertical asymptotes occur at
x = -3 and x = 7.
Horizontal Asymptote:
The highest power of x in the denominator is x², and there is no x² term in the numerator, the function approaches 0 as x goes to positive or negative infinity.
The horizontal asymptote is y = 0.
x-Intercept:
To find the x-intercept, we set y = 0 and solve for x:
0 = 1/((x + 3)(x - 7))
Since the numerator can never be zero, the only way the fraction can be zero is if the denominator is zero:
(x + 3)(x - 7) = 0
Solving for x:
x + 3 = 0
x = -3
x - 7 = 0
x = 7
So, the x-intercepts are (-3, 0) and (7, 0).
y-Intercept:
To find the y-intercept, we set x = 0:
f(0) = 1/((0 + 3)(0 - 7)) = 1/(-3 * -7) = 1/21
The y-intercept is (0, 1/21).
Thus,
The graph is for the rational function f(x) = 1/(x + 3)(x - 7).
Learn more about functions here:
https://brainly.com/question/28533782
#SPJ6
if x=2 and y=3. What is x*y/xy+x*y
Answer
its uhhhhh i dont know
Step-by-step explanation:
Are the ratios 6:3 and 2:1 equivalent?
15% of 80 is 60% of what number? There were no answer choices please help!
Answer:
80
Step-by-step explanation:
15 percent of 80 is 12
and 12 is 60 percent of 80!
hope this helps :)
Jessica works 5 days a week at a factory 7.5 miles from her home.
She travels to and from work in her car which has a fuel consumption of 30 miles per gallon.
Fuel costs £1.14 per litre and there are 4.55 litres in a gallon.
It costs £2.50 to park her car each day.
Rounded to the nearest £1, how much does it cost Jessica to travel to work in her car for a week?
Answer:
£25
Step-by-step explanation:
total distance travelled per week = 2 * 7.5 * 5 = 75
amount of fuel used = 75/30 = 2.5 gallons = 11.375 litre
cost of fuel = 11.375 * 1.14 = 12.9675
total cost = 5(2.5) + 12.9675 = 25.4675 ~~ 25
number
5. Thesum of a two-digit number a
(CBSE 2002]
Find the numbers.
If the two digits differ by 2, find the number. I
6. The sum of two numbers is 1000 and the difference between their squares is 256000.
7. The sum of a two digit number and the number obtained by reversing the order of its
digits is 99. If the digits differ by 3, find the number.
8. A two-digit number is 4 times the sum of its digits. If 18 is added to the number, the digits
are reversed. Find the number.
(CBSE 2001C]
[CBSE 2001C]
9. A two-digit number is 3 more than 4 times the sum of its digits. If 18 is added to the
(CBSE 2001C]
number, the digits are reversed. Find the number.
10. A two-digit number is 4 more than 6 times the sum of its digits. If 18 is subtracted from
the number, the digits are reversed. Find the number.
11. A two-digit number is 4 times the sum of its digits and twice the product of the digits.
[CBSE 2005]
Find the number.
[CBSE 2005]
12. A two-digit number is such that the product of its digits is 20. If 9 is added to the number,
the digits interchange their places. Find the number.
13. The difference between two numbers is 26 and one number is three times the other. Find
them.
14. The sum of the digits of a two-digit number is 9. Also, nine times this number is twice the
Let the numbers are x and y
According to the question
⇒x+y=1000.....eq1⇒x 2 −y 2
=256000∵x 2 −y 2
=(x+y)(x−y)
⇒1000∗(x−y)=256000
⇒x−y=256.....eq2
Adding eq1 and eq2
⇒2x=1256⇒x=628
Put the value of x in eq1
⇒628+y=1000⇒y=372
The numbers are 628 and 372
Hi I'm From PHILIPPINES
I'm here to help USA users like you
WORTH 30 POINTS PLEASE HELP!!!!! WILL GIVE POINTS
Answer:
2/3 and 4/6
Step-by-step explanation:
Solve this inequality: 14 <-7x
Answer:
-2 > x
Step-by-step explanation:
14 <-7x
Divide each side by -7, remembering to flip the inequality
14/ -7 > -7x/-7
-2 > x
A (5,3) and B (2,-1) are two verticles of a square ABCD and D is on the x axis. Find the coordinate of C and D
Answer:
1) D(1,0), C(-2,-4) or 2) D(9,0), C(6,-4)
Step-by-step explanation:
The vector AB is (2-5, -1-3)= (-3,-4)
The modul of the vector is equal to sqrt (3squared+4squared)=5 (the length of the side AB of square)
Explore the point D (the coordinates of the point is (x,0), y=o, because it is an axis x). AD (x-5, -3)
The modul of AD is sqrt ((x-5)^2+(-3)^2)= sqrt (x^2-10x+25+9), it is equal to the side AD which is equal to AB
sqrt(x^2-10x+34)= 5
x^2-10x+34=25
x^2-10x+9=0
x=1, x=9
D is (1,0) or D is (9,0),
find C, (for D1(1,0))
Find the midpoint of BD (O)
xo= (2+1)/2= 1.5
y0=(-1+0)/2= -0.5
It is the midpoint of Ac too
x0= (xa+xc)/2 1.5 = (5+xc)/2 xc= -2
y0=(ya+yc)/2 -0.5= (3+yc)/2 yc=-4
c(-2,-4)
Find C2 (for D(9,0))
Find the midpoint of BD (O)
x0= (2+9)/2=5.5
y0= (-1+0)/2=-0.5
o(5.5, -0.5)
It is the midpoint of Ac too
x0= (xa+xc)/2 5.5= (5+x)/2 x=6
y0=(ya+yc)/2 -0.5= (3+x)/2 y=-4
Word problems ! Please help
Answer:
19- 2(xy+yz+xz)
20- 16t(5-t)
Step-by-step explanation:
19) factor 2xy+2yz+2xz
2xy+2yz+2xz
=2(xy+yz+xz)
20) factor -16t^2 +80t
=80t-16t^2
=16(5t-t^2)
=16t(5-t)
What are Julie’s taxable wages as a data-entry operator if her withholding allowances total $1,500 and her annual gross pay is $24,500?
Julie's Taxable Wages:
Julie's taxable wages as a data-entry operator is:
= $23,000.
Data and Calculations:
a) Annual gross pay = $24,500
Total withholding allowances = 1,500
Taxable wages (income) = $23,000 ($24,500 - $1,500)
b) Julie's total withholding allowance of $1,500 is the total exemption that reduces how much income tax her employer can deduct from Julie's paycheck. This means that $1,500 will be deducted from $24,500, the gross pay, before arriving at her taxable income.
Thus, Julie's taxable wages represent the difference between her annual gross pay and her total withholding allowances.
Learn more about taxable income here: https://brainly.com/question/8653999
Find the cash value of the lottery jackpot (to the nearest dollar). Yearly jackpot payments begin immediately (26 for Mega Millions and 30 for Powerball). Assume the lottery can invest at the given interest rate. Powerball: $360 million; 5.4% interest
a. $188,347,953
b. $282,573,702
c. $185,870,742
d. $298,386,685
Answer:
The right response is Option c ($185,870,742).
Step-by-step explanation:
Given:
n = 30
r = 5.4%
or,
= 0.054
Periodic payment will be:
[tex]R = \frac{360000000}{30}[/tex]
[tex]=12000000[/tex] ($)
Now,
The present value will be:
= [tex]R+R(\frac{1-(1+r)^{-n+1}}{r} )[/tex]
By substituting the values, we get
= [tex]12000000+12000000(\frac{1-(1+0.054)^{-30 + 1}}{0.054} )[/tex]
= [tex]12000000+12000000\times 14.4892[/tex]
= [tex]185,870,742[/tex] ($)
Find the simple interest. The rate is an annual rate unless otherwise noted. Assume 365 days in a year and 30 days per month Round to the nearest cent $600 at 3% for 1 year
9514 1404 393
Answer:
$18
Step-by-step explanation:
The interest is computed using the formula ...
I = Prt
where P is the principal, r is the annual rate, and t is the number of years. The interest is ...
I = $600×0.03×1 = $18
At the Olympic games, many events have several rounds of competition. One of these events is the men's 100100100-meter backstroke. The upper dot plot shows the times (in seconds) of the top 888 finishers in the semifinal round at the 201220122012 Olympics. The lower dot plot shows the times of the same 888 swimmers in the final round. A dot plot is divided into 2 parts labeled, Semifinal Round and Final Round. The horizontal axis is labeled, Time, in seconds, from 52 to 54, in increments of 0.10 second. The portion of the dot plot dedicated to Final Round has dots above the following points; 52.2, 52.3, 52.8, 53.1, 53.2, 53.3, 53.5, and 53.8. The portion of the dot plot dedicated to Semifinal Round has dots above the following points; 52.7, 53, 53.3, 53.3, 53.5, 53.5, 53.5, and 53.7. Which pieces of information can be gathered from these dot plots? (Remember that lower swim times are faster.)
Answer: None of the above.
Step-by-step explanation:
I got it right on khan. I’ll explain a little though. Semifinals median=47.05. Finals median=53.05. Therefore A is not and option and B is DEFINITLEY not an option. Sorry I’m not good at explaining
Answer:
None of the above
Step-by-step explanation:
Got it right on test
what should be the rate of simpe interest such that the interest is double of the sun at 10 years
Answer:
you never showed the chocies
Step-by-step explanation:
