The growth of the mass of the sample of a bacteria is represented by the exponential model m(x) = 5 · 1.02ˣ.
How to predict the growth of the mass of the sample of a bacteria
In this problem we find the case of mass of a sample of a bacteria (m(x)), in miligrams growing in time (x), in days. This growth is done exponentially, the exponential model is shown below:
m(x) = m' · (1 + r / 100)ˣ
Where:
m' - Initial mass, in miligrams.r - Growth rate, in percentage.x - Time, in days.We have that the mass of the sample was initially 5 miligrams and grows at a rate of 2 % during 10 days. If we know that m' = 5 mg and r = 2, then the exponential model for the sample is:
m(x) = 5 · 1.02ˣ
The exponential model for the sample of a bacteria is equal to m(x) = 5 · 1.02ˣ.
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Selena rewrite the expression 36+54 hours to factored using the greatest common factor in addition and distribute the property what expression to Salina create
The expression Salina created using the greatest common factor in addition and distributing the property is
9(4 + 6)
9x4 + 9x6
What is an expression?An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.
Example: 2 + 3x + 4y = 7 is an expression.
We have,
36 + 54
Taking out the greatest common factor.
9(4 + 6)
Using the distributive property over addition
9 x 4 + 9 x 6
Thus,
9 x 4 + 9 x 6 is the expression Salina created.
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Review 2 HW Jack and Jill compare their monthly text plans. Jack's plan cost $9.00 plus $0.30 per text. Jills plan cost $0.60 per text. The equations below show the cost, c for each plan depending on how many texts, t, are sent Jack's Plan: c = 0.30t+9 Jills's Plan: c = 0.60t In one month, Jack and Jill paid the same amout. Enter the number of text messages the each sent.
Jack's plan: c=0.30t+9
Jill's plan: c=0.60t
I one month, Jack and Jill paid the same amount. enter the number of text messages they each sent
Answer: To solve this problem, we need to set the two equations equal to each other and solve for the number of text messages that were sent by each person. We know that the cost of Jack's plan is c = 0.30t + 9 and the cost of Jill's plan is c = 0.60t. To find the number of text messages they each sent, we can set these two equations equal to each other and solve for t:
0.30t + 9 = 0.60t
0.30t = 0.60t - 9
0.30t = 0.60t - 9
-0.30t = -9
t = 30
Therefore, if Jack and Jill paid the same amount for their text plans, they each sent 30 text messages.
A random sample of 115 observations results in 46 successes. Use Table 1.
a. Construct a 90% confidence interval for the population proportion of successes. (Round intermediate calculations to 4 decimal places, "z" value to 2 decimal places, and final answers to 3 decimal places.)
Confidence interval to
b. Construct a 90% confidence interval for the population proportion of failures. (Round intermediate calculations to 4 decimal places, "z" value to 2 decimal places, and final answers to 3 decimal places.)
Confidence interval to
Option a) 90% confidence interval for the population proportion of successes = 0.402
Option b) 90% confidence interval for the population proportion of failures = 0.598
According to the question given,
Critical values of Standard deviations are to be used to construct the proportions for the confidence interval.
The formula of a confidence interval that we will be using for the solution will be,
p = [tex]z_{a} * \sqrt{\frac{p(1-p)}{n} }[/tex]
In the above expression,
p = observed population.
n = sample size
[tex]z_{a}[/tex] = critical value of confidence interval
Now the given observations in question = 115
That result in success = 46
The resultant sample proportion = [tex]\frac{46}{115}[/tex]
⇒ 0.40 and it is for both success and failure
Here we can see that the answer for both parts will be identical.
The critical value of z at 90% confidence = 1.64
a) Lower bound = [tex]0.4 - 1.64 * \sqrt{\frac{0.4(1-0.4)}{90} }[/tex]
⇒ 0.402
b) Upper bound = [tex]0.4 + 1.64 * \sqrt{\frac{0.4(1-0.4)}{90} }[/tex]
⇒ 0.598
Confidence interval = 0.402 to 0.598
Therefore,
Option a) 90% confidence interval for the population proportion of successes = 0.402
Option b) 90% confidence interval for the population proportion of failures = 0.598
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What is the slant height of the cone?
Answer:
12.6
Step-by-step explanation:
Use pythag
8 / 2 = 4
a² + b² = c²
4² + 12² = c²
16 + 144 = c²
c² = 160
c = 12.6
determine the number of different sets of quantum numbers possible for each of the following shells. n2
Answer:
Step-by-step explanation:
Explanation:
As you know, each electron that's part of an atom has its own unique set of four quantum numbers that describes its position and spin.
This means that looking for the number of unique sets of quantum numbers is equivalent to looking for the number of electrons that can occupy the third energy level.
As you know, the number of orbitals you get per energy level is given by the equation
no. of orbitals
=
n
2
, where
n
- the principal quantum number, the ones that gives the energy level.
So, if you're dealing with the third energy level, you can say that it will contain a total of
no. of orbitals
=
3
2
=
9
distinct orbitals.
Now, each orbital can contain a maximum of
2
electrons of opposite spins. This means that the third energy level will contain a maximum number of
no. of electron
=
9
⋅
2
=
18 e
−
So, if each electron is described by an unique set of quantum numbers, you can conclude that
18
sets of quantum numbers are possible for the third energy level.
ok maybe that will help!
2. Of the total pounds, x, of fudge at the fudge shop on Monday morning, {3}/{4} contain nuts. Helena works at the fudge shop and prepares 12 {3}/{4} more pounds of fudge containing nuts to fulfill a special order Monday afternoon. With this additional amount of fudge, there are at least 29 {5}/{8} pounds of fudge containing nuts at the fudge shop on Monday.
(a) Write an inequality that represents the scenario. Begin by defining your variable.
(b) Solve your inequality from Part (a). Show all work.
(c) Fudge is packaged into 1-pound boxes. What is the fewest number of boxes of fudge at the fudge shop Monday morning?
Answer:
At least means less than or equal to.
Fewest means the smallest number of boxes.
12 3/4 +x ≥ 29 5/8
x ≥ 16 7/8
The fewest number of boxes would be almost ≅ 42 boxes
Part A:
Let x denote the amount of fudge at the shop.
Helena prepares 12 3/4 pounds of fudge containing nuts.
Mathematically, the total amount of fudge on Monday will be
12 3/4 +x
Of this amount of fudge there are at least 29 5/8 pounds of fudge containing nuts at the fudge shop on Monday
12 3/4 +x ≥ 29 5/8
Part B:
The inequality can be solved
12 3/4 +x ≥ 29 5/8
x ≥ 29 5/8- 12 3/4
x ≥ 29- 12 5/8- 3/4
The whole numbers are subtracted and the fractions are solved separately to avoid long calculations.
x ≥ 17 (5-6)/8
x ≥ 17 - 1/8
x ≥ (136-1)/8
x ≥ (135)/8
x ≥ 16 7/8
Part C :
To find the number of boxes we divide the equal number of pounds .
12 3/4 + 29 5/8
12 + 29 3/4 + 5/8
41 11/8
42 3/8
The fewest number of boxes would be almost ≅ 42 boxes
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I'm not sure what the reasoning is
The reasons that complete the statements are:
Statement 2: GivenStatement 4: SAS congruence propertyHow to determine the reasons that complete the statementsFrom the question, we have the following parameters that can be used in our computation:
Triangles = RST, and TUR
From the question, we have the following given parameters
∠SRT ≅ ∠UTR
This means that
Statement 2: ∠SRT ≅ ∠UTR ------ Given
At this point, we have
RS ≅ TU --- Congruent side (S)
∠SRT ≅ ∠UTR ------ Congruent angle (A)
RT ≅ TR --- Congruent side (S)
When these congruent sides and angles are combined, we have
SAS congruence property
The SAS congruent theorem implies that the corresponding sides of the triangles in question are congruent and the angles between the corresponding sides are also congruent
Hence, the additional information on the congruency of the triangles are Given and SAS congruence property
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If a solution calls for 1/4 cup vinegar mixed with 2 cups water , how many cups of vinegar goes into 27 total cups of solution?
A total of 3 cups of vinegar goes into 27 total cups
How to detemine the number of cups of vinegarFrom the question, we have the following parameters that can be used in our computation:
1/4 cups of vinegar
2 cups of water
So, we have
Water : Vinegar = 2 : 1/4
Rewrite as
Water : Vinegar = 8 : 1
Multiply by 3
Water : Vinegar = 24 : 3
The sum of 24 and 3 is 27
So, we have
Vinegar = 3
Hence, the number of cups of vinegar is 3
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Solve
y=-2 x
y=-9 x+21
Answer:
X = 3, Y = -6
Step-by-step explanation:
y = -2x
y = -9x + 21
Bring Y and X on the same side (alone).
0 = -2x – y
-21 = -9x – y
Multiply the top equation by -1 so we can cancel out y later on (to make it easier to solve for x).
0 = 2x + y
-21 = -9x – y
Add the equations.
-21 = -7x
Divide by -7.
X = 3
Solve for Y and check.
Y = -2(3)
Y = -6
Use the other equation to make sure.
(-6) = -9(3) + 21
-6 = -27 + 21
Have a nice day :D
nine eighteenths plus one third
Answer: 15 / 18
Step-by-step explanation:
9 / 18 + 1/3
1/3 = 6 / 18
9 / 18 + 6/ 18
15 / 18
Answer:
5/6.
Step-by-step explanation:
Step 1: Rewrite 9/18
9/18 = 1/2
Step 2: Rewrite problem
1/2 + 1/3
Step 3: Find (Greatest common denominator)
6
Step 4: Rewrite fractions
3/6 + 2/6
Step 5: Add
5/6
A researcher is investigating the relationship between personality and birth order position. A sample of college students is classified into four birth categories (1st, 2nd, 3rd, 4th, and later)and given a personality test that measures the degree of extroversion on a 50 point scale. Identify the statistical procedure for analyzing this data. Explain your answer.
The data form a 2x4 frequency matrix and the ratio of each cell represents the result. Each participant's rating is a birth order category (1, 2, 3, 4). The Mann-Whitney test can assess the significance of differences between groups.
The chi-square test of independence determines whether the proportions are significantly different for each birth order group. Effect sizes are measured in Cramer's V. Alternatively, the data form two sets of ratings, one for each personality group. Each participant's rating is a birth order category (1, 2, 3, 4). The Mann-Whitney test can assess the significance of differences between groups.
Chi- Square Test:The chi-square test (also called chi-square or chi-square test) is a statistical hypothesis test used in contingency table analysis when the sample size is large. Simply put, the main purpose of this test is to test whether two categorical variables (the two dimensions of the contingency table) independently affect the test statistic (the values in the table) . The test is valid when the test statistic is a chi-square distribution based on the null hypothesis, specifically Pearson's chi-square test and variants thereof. Use Pearson's chi-square test to determine whether there is a statistically significant difference between the expected and observed frequencies for one or more categories in the contingency table. For contingency tables with small sample sizes, Fisher's exact test is used instead.
Mann - Whitney U Test:In statistics, the Mann-Whitney U test (also known as the Mann-Whitney-Wilcoxon (MWW/MWU), Wilcoxon rank sum test, or Wilcoxon-Mann-Whitney test) is a test of the null hypothesis used at random. It is a non-parametric test. Values X and Y selected from two populations where the probability of X being greater than Y is equal to the probability of Y being greater than X.
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Over 2 years, how much more does $2000 in a savings account with an APR of 5.2% compounded quarterly earn in interest than the same amount in a savings account with an APR of 4.8% compounded monthly?
A savings account with just an APR of 5.2% compounded quarterly on a balance of $2,000 will yield $16.61 more interest than a similar account with just an APR of 4.8% compounded monthly on the same balance.
Explain the term compounded monthly?Compound monthly refers to a loan's interest rate, which is charged in installments each month and added to the principle.Assume we had two different sorts of savings accounts, each with a deposit of $2,000 in it.
Account A's quarterly interest rate is 5.2%.Account B has a monthly interest rate of 4.8%.We must now determine the earnings for both accounts.
The following formula will be used to determine the earning:
Here,
v = total income,Interest rate = r (in decimal form).p is the first main value.T is the number of years overall.n is the number of compounding years.Put the values for Account A now.
5.2 % in decimal form = 5.2/100= 0.052
v = 2000 x ( 1 + (0.052/4) )^(4*2)
v = 2217.71
Total earning for account A = $ 2217.71.
For Account B:
4.8 % in decimal form = 4.8/100= 0.048
v = 2000*( 1 + (0.048/12) )^(12*2)
v = 2201.10
Total earning for account A = $ 2201.10
We will now deduct B's earnings from A's earnings to see how much more A earned than B.
2217.71 - 2201.10 = $16.61
Consequently, account A made $16.61 more so than account B.
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Andreas has $18. Bonnie has 1 2/3 times as much as Andreas. Cheryl has 1 3/5 times as much as Bonnie.
How much money do
they have altogether?
Dae and Eric are working together on a paper. Dae typed 333 words in 9 minutes, and Eric typed 252 words in 6 minutes. How many more words per minute did Eric type?
Eric typed 15 words more than Dae per minute.
What is a Linear Equation?Linear equations are equations whose highest power of the variables is 1. The graph of a linear equation is a straight line. A nonlinear equation is an equation whose highest power of the variables is not 1 and the graph is not a straight line.
To find the amount of words typed in 1 minute for both;
Dae = 333/9
Dae = 27 words per minute
Eric = 252/6
Eric = 42 words per minute
Therefore 42 - 27 = 15 words per minute
Eric typed 15 more words per minute.
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The formula for the volume of a right circular cylinder is V = πr² h. If r = 2b and
h=5b+3, what is the volume of the cylinder in terms of b?
[tex]V=4\pi b^{2}(5b+3)[/tex].
Step-by-step explanation:1. Write the equation.[tex]V=\pi r^{2} h[/tex]
2. Use the values to substitute into the original formula.[tex]V=\pi r^{2} h\\ \\V=\pi (2b)^{2} (5b+3)[/tex]
3. Solve the exponent.[tex]V=\pi (2^{2} b^{2} ) (5b+3)\\ \\V=\pi (4 b^{2} ) (5b+3)[/tex]
4. Solve the product between the two parentheses and simplify.Use the distributive property of multiplication in order to operate.
[tex]V=\pi (4 b^{2} ) (5b+3)\\ \\V=\pi ((4 b^{2})(5b)+(4 b^{2})(3))\\ \\V=\pi ((20b^{3} )+(12 b^{2}))\\ \\V=4\pi (\frac{20b^{3}}4} +\frac{12 b^{2}}{4} )\\ \\V=4\pi (5b^{3} +3b^{2})\\ \\V=4\pi b^{2}(\frac{5b^{3}}{b^{2}} +\frac{3b^{2}}{b^{2}} )\\ \\V=4\pi b^{2}(5b+3)[/tex]
5. Conclude.[tex]V=4\pi b^{2}(5b+3)[/tex].
Drag and drop the choices into the boxes to correctly complete the table.
corresponding alternate interior alternate exterior none of these
Definitions:
Corresponding angles are the angles at matching corners.Alternate interior angles lie on the inner side of the parallel lines but on the opposite side of the transversal.Alternate exterior angles lie on the outer side of the parallel lines but on the opposite side of the transversal.The given angles are:
Top left figure ⇒ Alternate interiorTop middle figure ⇒ CorrespondingTop right figure ⇒ CorrespondingBottom left figure ⇒ Alternate exteriorBottom right figure ⇒ None of these
A 90-inch pipe is cut into two pieces. One piece is five times the length of the other. Find the length of the shorter piece.
Answer:
5x+x=90
Step-by-step explanation:
5 times the other = 5x
the other piece is x
Answer: the small pipe is 15 inches long
Step-by-step explanation: since the larger pipe is 5 times larger than the small pipe, the 90 inch pipe would have too be divided by 6 to make sure the 5 times of the large pipe and the 1 small pipe. so, you would do 90/6=15. so the small pipe is 15 inches long. the large pipe is 75 inches long.
For a sample of 20 New England cities, a sociologist studies the crime rate in each city (crimes per 100,000 residents) as a function of its poverty rate (in %) and its median income (in $1,000s). A portion of the regression results is as follows. Use Table 2 and Table 4.
ANOVA df SS MS F Significance F
Regression 2 188,246.8 94,123.4 9.04E-07
Residual 17 45,457.32 2,673.96 Total 19 233,704.1 Coefficients Standard Error t Stat p-value Lower 95% Upper 95%
Intercept −301.62 549.7135 −0.5487 0.5903 −1,461.52 858.28
Poverty 53.1597 14.2198 3.7384 0.0016 23.16 83.16
Income 4.9472 8.2566 0.5992 0.5569 −12.47 22.37
a. Specify the sample regression equation. (Negative values should be indicated by a minus sign. Round your answers to 4 decimal places.)
11formula272.mml = + Poverty + Income
b-1. Choose the appropriate hypotheses to test whether the poverty rate and the crime rate are linearly related.
H0: β1 ≥ 0; HA: β1 < 0
H0: β1 ≤ 0; HA: β1 > 0
H0: β1 = 0; HA: β1 ≠ 0
b-2. At the 5% significance level, what is the conclusion to the test?
Reject H0; the poverty rate and the crime rate are linearly related.
Reject H0; the poverty rate and the crime rate are not linearly related.
Do not reject H0; we can conclude the poverty rate and the crime rate are linearly related.
Do not reject H0; we cannot conclude the poverty rate and the crime rate are linearly related.
c-1. Construct a 95% confidence interval for the slope coefficient of income. (Negative values should be indicated by a minus sign. Round your answers to 2 decimal places.)
Confidence interval to
c-2. Using the confidence interval, determine whether income influences the crime rate at the 5% significance level.
Income is significant in explaining the crime rate, since its slope coefficient does not significantly differ from zero.
Income is not significant in explaining the crime rate, since its slope coefficient significantly differs from zero.
Income is significant in explaining the crime rate, since its slope coefficient significantly differs from zero.
Income is not significant in explaining the crime rate, since its slope coefficient does not significantly differ from zero.
d-1. Choose the appropriate hypotheses to determine whether the poverty rate and income are jointly significant in explaining the crime rate.
H0: β1 = β2 = 0; HA: At least one β j < 0
H0: β1 = β2 = 0; HA: At least one β j > 0
H0: β1 = β2 = 0; HA: At least one β j ≠ 0
d-2. At the 5% significance level, are the poverty rate and income jointly significant in explaining the crime rate?
Yes, since the null hypothesis is rejected.
Yes, since the null hypothesis is not rejected.
No, since the null hypothesis is rejected.
No, since the null hypothesis is not rejected.
Answer: You must give more points for questions that are this long
sincerely,
A Friend
Step-by-step explanation:
When you are testing hypotheses by using proportions, what are the necessary requirements? OA. np 25 and nq 25 ?B.np < 5 and nq < 5 C. The population standard deviation is unknown. D. p
The following conditions must be met in order to test hypotheses using proportions: np ≥ 5 and nq ≥ 5
To test hypotheses using proportions, the following requirements are necessary:
np ≥ 5 and nq ≥ 5: It is necessary to have a sufficient number of samples in each group being compared.
The rule of thumb is to have at least 5 observations in each group, where n is the sample size and p is the proportion in that group.
This ensures that the sampling distribution of the proportion is approximately normal, which is necessary for hypothesis testing.
Hence, the correct answer would be an option (A).
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A. A manufacturer knows that their items have a normally distributed length, with a mean of 19.7 inches, and standard deviation of 4 inches.
If 25 items are chosen at random, what is the probability that their mean length is less than 17.4 inches?
Round to 4 decimal places
A manufacturer knows that their items have a normally distributed lifespan, with a mean of 12.1 years, and standard deviation of 1.9 years.
If you randomly purchase 12 items, what is the probability that their mean life will be longer than 11 years?
Round to 4 decimal places.
B. A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 98.4-cm and a standard deviation of 0.9-cm. For shipment, 15 steel rods are bundled together.
Find the probability that the average length of the rods in a randomly selected bundle is between 97.9-cm and 98.6-cm.
P(97.9-cm < X¯¯¯ < 98.6-cm) = Round to 4 decimal places.
The probability that their mean length is less than 17.4 inches is 28.26%
Given :
A manufacturer knows that their items have a normally distributed length, with a mean of 19.7 inches, and standard deviation of 4 inches , If 25 items are chosen at random .
z = ( X - μ ) / σ, where X = date , μ = mean , σ = standard deviation .
substitute the values
z = 17.4 - 19.7 / 4
= -2.3 / 4
= -0.575
P - value at z = -0.575 is 0.2826
Converting into percentage :
= 0.2826 * 100%
= 28.26 %
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Find the LCM of the numbers by using the GCF.
5. 22,38
The lowest common multiple (LCM) of the numbers 22 and 38 is 418.
What is L.C.M and H.C.FThe L.C.M. defines the least common multiple number which is exactly divisible by two or more numbers, while H.C.F. defines the highest common factor present in between given two or more numbers,
Given the numbers 22 and 38, we can express them as products of their prime factors and thus derive their LCM as follows;
22 = 2 × 11
38 = 2 × 19
LCM = 2 × 11 × 19
LCM = 418
Therefore, the LCM of 22 and 38 is 418 using prime factor method.
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e the problem.
1) Scores on a test are approximately normally distributed with a mean of 70 and a standard deviation of 9. The
teacher wants to give A's to the top 10% of students, B's to the next 25%, and C's to the next 42%. What is the
bottom cutoff for a C grade? Round your answer to the nearest whole number..
A) 68
B) 63
C) 77
D) 65
z = -1.34 < (a - 70)/9
And if we solve for we got
a = 70 - 1.34 * 9 = 57.95 = 98
So, the value of height that separates the bottom 9% of data from the top 91% is 58.
And the answer for this case would be:
a) 58
What is the Normal distribution and Z-score?
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
The solution to the problem
Let X be the random variable that represents the scores of a population, and for this case we know the distribution for X is given by:
X ~ N (70, 9)
Where μ = 70, and σ = 9
For this case, the figure attached illustrates the situation for this case.
We know from the figure that the lower limit for D accumulates 9% or 0.09 of the area below and 0.91 or 91% of the area above.
we want to find a value a, such that we satisfy this condition:
P(X > a) = 0.91 (a)
P(X < a) = 0.09 (b)
Both conditions are equivalent in this case. We can use the z score again in order to find the value a.
As we can see in the figure attached the z value that satisfies the condition with 0.09 of the area on the left and 0.91 of the area on the right it's z=-1.34. On this case P(Z<-1.34)=0.09 and P(z>-1.34)=0.91
If we use condition (b) from the previous we have this:
P(X < a) = P(X - μ)/σ < (a - μ)/σ) = 0.09
P(z < (a - μ)/σ) = 0.09
But we know which value of z satisfies the previous equation so then we can do this:
z = -1.34 < (a - 70)/9
And if we solve for we got
a = 70 - 1.34 * 9 = 57.95 = 98
Hence, the value of height that separates the bottom 9% of data from the top 91% is 58.
And the answer for this case would be:
a) 58
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identify the independent variable in the following hypothesis: interstate migration in the united states lowers state poverty levels.
The independent variable in the following hypothesis: interstate migration in the united states lowers state poverty levels is IV ( Interstate migration ) and DV ( State poverty level ) .
Given :
identify the independent variable in the following hypothesis: interstate migration in the united states lowers state poverty levels.
Independent variable :
An independent variable is exactly what it sounds like. It is a variable that stands alone and isn't changed by the other variables you are trying to measure.
Here in the given statement the independent variable is :
IV = Interstate migration
DV = State poverty level
Unit of Analysis = U.S. states
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Discuss with your own words some ways that you see religion having social control in your everyday life . Be able to cite examples?
Answer: Religion reinforces and promotes social inequality and social conflict. It helps convince the poor to accept their lot in life, and it leads to hostility and violence motivated by religious differences. This perspective focuses on the ways in which individuals interpret their religious experiences.
Step-by-step explanation:
Please help me with this question
The average rate change of the function is -4.
What is a function?
A mathematical phrase, rule, or law that establishes the link between an independent variable and a dependent variable (the dependent variable). In mathematics, functions exist everywhere, and they are crucial for constructing physical links in the sciences.
Given function is f(x) = 1x² + 1x - 8.
Find the average rate change of the function in the interval [-4, -1]
For this compute the value of f(x) at x = -4 and x = -1.
Then find the difference the value of f(x) and divide it by the difference the value of x.
The average rate change of function f(x) in the interval [a,b] is [f(b) - f(a)]/(b-a).
Putting x = -4 in the given function:
f(-4) = 1(-4)² + 1(-4) - 8
f(-4) = 4
Putting x = -1 in the given function:
f(-1) = 1(-1)² + 1(-1) - 8
f(-1) = -8.
The rate change of x is -1 - (-4) = 3
The average rate change of the function is
[f(-1) - f(-4)] /3
= -8 - 4/3
= - 12/3
= -4
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What is the 3rd term of (4 - 5g)??
0896000g²
O 21g²
O-1050000g5
O 537600g2
The 3rd term of (4 - 5g) is -1050000g5
What does the term "arithmetic sequence" mean?An arithmetic sequence is a set of integers that are ordered and have a common difference between each following word. For instance, the common difference in the arithmetic series 3, 9, 15, 21, and 27 is 6. An arithmetic progression is another name for an arithmetic sequence.
It is simple to establish a series by starting with a number and repeatedly adding a fixed constant (d). An arithmetic sequence is this kind of sequence.
Given,
(4 - 5g) simplifying
-1
So that is -1050000g5
The 3rd term of (4 - 5g) is -1050000g5
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High cholesterol: A group of eight individuals with high cholesterol levels were given a new drug that was designed to lower cholesterol levels. Cholesterol levels, in milligrams per deciliter, were measured before and after treatment for each individual, with the following results: Individual Before After 244 207 288 216 274 188 278 200 233 173 271 224 295 171 275 187 4 Download data Part 1 out of 2 Construct a 95% confidence interval for the mean reduction in cholesterol level. Let d represent the cholesterol level before treatment minus the cholesterol level after. Use the TI-84 calculator and round the answers to one decimal place. A 95% confidence interval for the mean reduction in cholesterol level is Hd
The 95% confidence interval for the mean reduction in cholesterol level is given as follows:
(51.3, 96.7).
What is a t-distribution confidence interval?The t-distribution is used when the standard deviation for the population is not known, and the bounds of the confidence interval are given according to the following rule:
[tex]\overline{x} \pm t\frac{s}{\sqrt{n}}[/tex]
In which the variables of the equation are presented as follows:
[tex]\overline{x}[/tex] is the sample mean.t is the critical value.n is the sample size.s is the standard deviation for the sample.The critical value, using a t-distribution calculator, for a two-tailed 95% confidence interval, with 8 - 1 = 7 df, is t = 2.3646.
From the image given at the end of the answer, the sample of the differences is given as follows:
37, 72, 86, 78, 60, 47, 124, 88.
Hence the parameters are given as follows:
[tex]\overline{x} = 74, s = 27.1, n = 8[/tex]
Then the lower bound of the interval is of:
74 - 2.3646 x 27.1/square root of 8 = 51.3.
The upper bound of the interval is of:
74 + 2.3646 x 27.1/square root of 8 = 96.7.
Missing InformationThe table is given by the image shown at the end of the answer.
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Consider f(x) Equals StartFraction 8 (x minus 1) Over x squared + 2 x minus 3 EndFraction.
Which statements describe the existence of vertical asymptotes at x = –3 and x = 1?
At x = negative 3, limit of f (x) as x approaches negative 3 minus = negative infinity and limit of f (x) as x approaches negative 3 plus = infinity, so there is a vertical asymptote. At x = 1, limit of f (x) as x approaches 1 minus = 2 and limit of f (x) as x approaches 1 plus = 2, so there is no vertical asymptote.
At x = negative 3, limit of f (x) as x approaches negative 3 minus = infinity and limit of f (x) as x approaches negative 3 plus = negative infinity, so there is a vertical asymptote. At x = 1, limit of f (x) as x approaches 1 minus = 2 and limit of f (x) as x approaches 1 plus = 2, so there is no vertical asymptote.
At x = negative 3, limit of f (x) as x approaches negative 3 minus = negative infinity and limit of f (x) as x approaches negative 3 plus = infinity, so there is a vertical asymptote. At x = 1, limit of f (x) as x approaches 1 minus = infinity and limit of f (x) as x approaches 1 plus = infinity, so there is no vertical asymptote.
At x = negative 3, limit of f (x) as x approaches negative 3 minus = infinity and limit of f (x) as x approaches negative 3 plus = negative infinity, so there is a vertical asymptote. At x = 1, limit of f (x) as x approaches 1 minus = infinity and limit of f (x) as x approaches 1 plus = infinity, so there is no vertical asymptote.
The correct option that describes the vertical asymptote is; A: At x = negative 3, limit of f (x) as x approaches negative 3 minus = negative infinity and limit of f (x) as x approaches negative 3 plus = infinity, so there is a vertical asymptote
How to find the vertical asymptote of a function?A vertical asymptote of a graph is defined as a vertical line x = a where the graph tends toward positive or negative infinity as the inputs approach a.
A vertical asymptote is a value of x for which the function is not defined, that is, it is a point which is outside the domain of a function;
In a graph, these vertical asymptotes are given by dashed vertical lines.
An example is a value of x for which the denominator of the function is 0, and the function approaches infinity for these values of x.
We are given the function;
f(x) = 8(x - 1)/(x² + 2x - 3)
Simplifying the denominator gives;
(x² + 2x - 3) = (x + 3)(x - 1)
Thus, our function is;
f(x) = 8(x - 1)/[(x + 3)(x - 1)]
(x - 1) will cancel out to give;
f(x) = 8/(x + 3)
Vertical asymptote:
Point in which the denominator is 0, so:
(x + 3) = 0
x = -3
Thus, we conclude that x = -3 is the vertical asymptote
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Label a ray with endpoint Y. Determine an appropriate name for a ray whose endpoint is Y. Choose the correct ray whose endpoint is Y. A. Y X B. X Y C. X Y D. Y x Choose an appropriate name for a ray whose endpoint is Y. A. XY B. XY C. YX
Label a ray with endpoint Y. An appropriate name for a ray whose endpoint is XY displays a ray with the endpoint Y.
A line with a single defined endpoint that continuously moves away from another is known as a ray (endpoint B in this case).
A segment of a line that lacks an endpoint but has a specified starting point. It can go on forever in a single direction. A ray cannot be measured since it has no end point.
In mathematics, a ray is a segment of a line with a definite starting point but no ending. It can go on forever in a single direction. A ray cannot be measured since it has no end point. Two rays with the same terminal are united to form an angle. The vertex of the angle is referred to as the common endpoint of the rays, while the sides of the angle are referred to as the rays themselves.
The ray in the hypothetical situation has one endpoint B and an endlessly extending endpoint A. (as shown by the arrowhead).
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the students in charge of a class a carnivore want to make a profit of at least $65 by selling items they spent $55 for the materials to make the items they will sell each item for three dollars find the possible values of x ,the number of items the students need to sell to reach there goal
They should sell at least 40 items to make a profit of at least $65.
What is inequality?Inequality is a relationship between two expressions which are not equal and connected by the signs, ≤, ≥, <, and >
Given that, the students of a class want to make a profit of at least $65 by selling items they spent $55 for the materials to make the items they will sell each item for $3
Since, they want $65 at least profit,
Therefore, selling price for the profit = 55+65 = $120
Profit = Selling price - cost price
Since, selling price of each item = $3
Let they are selling x items, Therefore, selling price for x items = 3×x = $3x
Now, establishing the inequality,
3x ≥ 120
x ≥ 120/3
x ≥ 40
Hence, there should be 40 or more items to be sold.
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