The length of a rectangle is 6 inches more than the width. The perimeter is 28 inches. Find the length and the width (in inches).

Answers

Answer 1

Answer:

The length of the rectangle is 10 inches, and the width is 4 inches.

Step-by-step explanation:

Given that the length of a rectangle is 6 inches more than the width, and the perimeter is 28 inches, the following calculation must be performed to find the length and the width:

(X + X + 6) x 2 = 28

2X + 2X + 12 = 28

4X = 28 - 12

X = 16/4

X = 4

Therefore, the length of the rectangle is 10 inches, and the width is 4 inches.


Related Questions

Which of the following shows the graph of y = 4^x + 3?

Answers

The images of the graphs are missing and so i have attached them.

Answer:

Graph in option A

Step-by-step explanation:

y = 4^(x) + 3

Let's input some values of x and find the corresponding value of y and see if any of the graph matches the coordinates we get.

At x = 0;

y = 4^(0) + 3

y = 4

At x = 1;

y = 4^(1) + 3

y = 7

At x = 2;

y = 4^(2) + 3

y = 19

Looking at all the graphs, the only one with y = 4 when x = 0 is graph A

Gloria received a 4 percent raise and is now making $24,960 a year, what was her salary before the raise?

Answers

She gets a 4% raise so her new pay is 100% + 4% of her previous pay.

104% = 1.04 as a decimal.

Divide her new pay by 1.04:

24,960 / 1.04 = 24,000

Her previous pay was $24,000

Write a rational function that meets the following criteria:

Vertical asymptote at x = 1

Horizontal asymptote at y = 2

and a hole at x = 3​

Answers

You can get a vertical asymptote at x=1 using y = 1/(x-1)
You can generate a hole at x=3 by multiplying by (x - 3/(x - 3) which is undefined at x=3 but otherwise equals 1
You can move the horizontal asymptote up to y=2 by adding 2

y = (x - 3)/((x - 1)(x - 3)) + 2

Help Me! Fake Answers will be reported.

How many triangles are there in this picture?

Answers

Im sorry if you get this wrong but im going with 14 only because i did this question with my class in school and a boy said 14 and got it right.

Answer:

28

Step-by-step explanation:

there are bigger triangles in the triangles pls dont remove

A few years ago, people tended to have relatively large CD collections. For students at a large university in the midwest, the mean number of CDs owned was 78 with a standard deviation of 90. To confirm these numbers, a random sample of 120 students from this university was collected and the size of their CD collections recorded. These particular 120 students had a mean CD collection size of 80 CDs. Select the correct description of the population in this study.

Answers

Complete Question

A few years ago, people tended to have relatively large CD collections. For students at a large university in the midwest, the mean number of CDs owned was 78 with a standard deviation of 90. To confirm these numbers, a random sample of 120 students from this university was collected and the size of their CD collections recorded. These particular 120 students had a mean CD collection size of 80 CDs. What is the numerical value of the sample mean?

Answer:

Sample Mean [tex]\=x=80[/tex]

Step-by-step explanation:

From the question we are told that:

Population Mean [tex]\mu=78[/tex]

Standard deviation [tex]\sigma=90[/tex]

Sample size [tex]n=120[/tex]

Sample Mean [tex]\=x=80[/tex]

Therefore

The numerical value of the sample mean is

Sample Mean [tex]\=x=80[/tex]

Helppp more points 20 math

Answers

Answer:

root(250)

answer choice C

Step-by-step explanation:

explanation in the pic above.

Name some real-life situations where graphing could be useful. Discuss your ideas. Name some real-life situations where finding the coordinates of the midpoint of a line segment could be useful.

Answers

Answer:

mapping an area

Step-by-step explanation:

One situation and probably the most common is mapping an area. Graphs are great for dividing a geographical location into various sections and creating a model representation of the area. The graph itself allows for specific directions to be shared using the x and y coordinates on the graph. The same applies for finding the midpoint of a line segment. For example, this is useful if you were trying to find a place to meetup with a friend that is an equal distance from where you are and from where your friend is currently located. Therefore, allowing you to meetup at the midpoint.

Help me pls
I put the picture in the attach file below
(Sorry i'm in secondary school but i have a problem with my settings)

Answers

Step-by-step explanation:

0 is the ans my guy

dngjdjvkdkckgkdkgkskfkfkv

2.7.2 : Checkup - Practice Problems

Answers

the answer is 47 lol trust

stuck on this problem​

Answers

Answer:

B

Step-by-step explanation:

When we reflect something across the y axis, the y axis stays the same but the x values change by a factor of -1.

B is the Answer

Answer:

c. switch the x-values and y-values in the table

Step-by-step explanation:

For any table or graph reflection over the line y=x

The rule is (x,y) ----> (y,x)

f(x) is reflected over the line y=x, so the coordinates of f(x) becomes

(-2,-31) becomes (-31,-2)

(-1,0) becomes (0,-1)

(1,2) becomes (2,1)

(2,33) becomes (33,2)

As per the rule, we switch the x-values and y-values in the table

For reflection over the line y=x , the coordinate becomes

(-31,-2)

(0,-1)

(2,1)

(33,2)

what is the value of x

Answers

FOR Y
opposite angles - equal
angles in a quadrilateral are 360 degrees
68 + 68 = 136
360 - 136 = 224
224/2 = 112 degrees
angles on a straight line = 180 degrees
180 - 112 = 68
Y = 68
FOR X
angles on a straight line are 180 degrees
180 - 68 = 112 degrees
X=112 degrees

Side CA of the right triangle CAT is 3cm long. The hypotenuse is 5cm long. How many
square centimeters is the area of CAT?

Answers

Answer:

8

Step-by-step explanation:

By taking the number "3" and plus together with the number 5

If one side of the triangle is 3 cm, and the hypotenuse is 5cm, then the other side is 4cm because of Pythagorean triples. Or you can use the Pythagorean theorem which is a^2+b^2=c^2. In this case, c=5, a=3. So it would be 9+b^2=25. b^2=16, and b=4. Then you find the area of the triangle. The formula for area of any triangle is height times base divided by two. (h times b)/2. So the height and the base are 3 and 4. 3 times 4=12, and 12 divided by 2 is 6.
So the area of CAT is 6 cm squared.

Find the value of x in each case:

Answers

Answer:

36

Step-by-step explanation:

2x is an exterior angle

Exterior angles = the sum of the two remote (unconnected - non supplementary interior angles).

Put symbolically

<LEG = <EGF + <EFG

<EFG = 180 - 4x           In this case you need to find the supplemtnt

<LEG = x + 180 - 4x

2x = 180 - 3x                Add 3x to both sides

5x = 180                       Divide by 5

x = 36

Merci de m'aider rapidement !

Answers

Answer:

I will answer in English.

We can prove that the angle APS is a triangle rectangle.

Remember that for a triangle rectangle of catheti A and B, and hypotenuse H, the Pythagorean's theorem says that:

A^2 + B^2 = H^2

In this case, we can assume that the hypotenuse is the longer side, AS, and the other two sides are the catheti.

Then we have:

H = 5x + 10

A = 3x + 6

B = 4x + 8

Now let's write the equation from the theorem, and let's see if its true.

A^2 + B^2 = H^2

( 3x + 6 )^2 + (4x + 8)^2 = (5x + 10)^2

So we can start with:

( 3x + 6 )^2 + (4x + 8)^2

And try to "transform" this into:

(5x + 10)^2

First, let's expand it:

((3x)^2 + 2*(3x)*6 + 6^2) + ( (4x)^2 + 2*(4x)*8 + 8^2)

9x^2 + 24x + 36 + 16x^2 + 64x + 64

25x^2 + 40x + 100

Now we can complete squares on the left side, by writing:

(5x)^2 + 2*10*(5x) + 10^2

(5x + 10)^2

Then we saw that the equation is true for every value of x, then we just prove that the triangle fulfills the theorem, thus, the triangle is a triangle rectangle.

Find domain of (x^2+3)+[tex]\sqrt{x} 3x-1[/tex]

Answers

Answer:

= x^2 + 3 + √3x^2 - 1

Step-by-step explanation:

Remove parentheses: (a) = a

= x^2 + 3 + √x . 3x - 1

x . 3x = 3x^2

= x^2 + 3 + √3x^2 - 1

Matthew participates in a study that is looking at how confident students at SUNY Albany are. The mean score on the scale is 50. The distribution has a standard deviation of 10 and is normally distributed. Matthew scores a 65. What percentage of people could be expected to score the same as Matthew or higher on this scale

Answers

Answer:

The percentage of people that could be expected to score the same as Matthew or higher on this scale is:

= 93.3%.

Step-by-step explanation:

a) Data and Calculations:

Mean score on the scale, μ = 50

Distribution's standard deviation, σ = 10

Matthew scores, x = 65

Calculating the Z-score:

Z-score = (x – μ) / σ

= (65-50)/10

= 1.5

The probability based on a Z-score of 1.5 is 0.93319

Therefore, the percentage of people that could be expected to score the same as Matthew or higher on this scale is 93.3%.

Find m angle QSRIf m angle TSQ=15x , m angle TSR=173^ , and m angle QSR=10x-2

Answers

[tex]{\color{red}{\huge{\underbrace{\overbrace{\mathfrak{\:\:\:\:\:\:\:꧁"Answer"꧂\:\:\: }}}}}}[/tex]

[tex]\small\color{blak}{{\underline{\bold{ Find \:a X } } } }[/tex]

[tex]\small\color{black}{{\underline{\bold{173°=15z+10x-2 } } } } \\ = 173 = 25x - 2 \\ = - 25x = - 2 - 173 \\ = - 25x - 175 \\ = \small\color{blue}{{{\boxed{\tt\red{} \:\:\:\:\:\:\:\:\:\: x=7\:\:\:\: }}}}[/tex]

[tex]\small\color{blak}{{\underline{\bold{ Find\:a\:m<QSR } } } }[/tex]

[tex]\small\color{blak}{{\underline{\bold{ 10(7)-2 } } } }\\=70-2\\=\small\color{red}{{{\boxed{\tt\red{} \:\:\:\:\:\:\:\:\:\: m<QSR=68°\:\:\:\: }}}}[/tex]

[tex]\Large\color{red}{{\underline{\mathfrak {{꧁"Carry\:on\: learning"꧂ }}}}}[/tex]

The measure of angle QSR is 68 degrees.

What is substitution?

Substitution means putting numbers in place of letters to calculate the value of an expression.

According to the given question.

m ∠TSQ = 15x

m ∠TSR = 173 degrees

m ∠QSR = 10x -2

Since,

m ∠TSR = m ∠TSQ + ∠QSR

Substitute the value of m ∠TSR, m ∠TSQ and m ∠QSR in the above expression.

⇒ [tex]173 = 15x + 10x - 2[/tex]

⇒ [tex]173 = 25x - 2[/tex]

⇒ [tex]175 = 25x[/tex]

⇒ [tex]x = \frac{175}{25}[/tex]

⇒ [tex]x = 7[/tex]

Again, for finding the value of angle QSR substitute the value of x in 10x - 2.

Therefore,

m ∠QSR = 10(7) - 2

⇒ m ∠QSR = 70 - 2

⇒ m ∠QSR = 68 degrees

Hence, the measure of angle QSR is 68 degrees.

Fid out more information about substitution here:

brainly.com/question/27810586

#SPJ3

Tim Hortons is hiring and offers $200 every week plus $5 per hour. McDonalds offers $300 every week plus $2 per hour. State the conditions under which Tim Hortons is the better employer

Answers

Answer:

Assuming you want better payment each week, any number of hours above 33.333 or 33 hours and 20 minutes per week

Step-by-step explanation:

There are several ways we could do this.  We could say we want to have Tim Hortons be the better employer on the first week, or after so many weeks by adjusting the hours.  I am going to assume we are saying we want it to be a better employer on the first week, so the profit will be the amount made every week plus the money made per hour times the number of hours.

Let's say number of hours is H

So Tim Hortons winds up as 200 + 5H for one week and  Mcdonalds will be 300 + 2H.

If you set the two expressions equal to each other you will find where they intersect, which means at that number of hours they will give the same amount of money while any amount before one of the companies will give more and after that many hours the other will.  Let's go ahead and solve.

200 + 5H = 300 + 2H

3H = 100

H = 100/3

So H is about 33.333.  let's check.

200 + 5(33.333) = 366.665 which rounds to 366.67 dollars

300 + 2(33.333) = 366.666 which also rounds to 366.67 dollars

So at 33.333 hours both give 366.67 dollars.  Let's look at a value below it, say 32.

200 + 5(32) = 360

300 + 2(32) = 364

So you can see here Tim Hortons  pays less.  Now we will try 34 as a value above 33.333

200 + 5(32) = 370

300 + 2(32) = 368

Here Mcdonalds pays less.  This was to show that values below 33.333 make Tim Hortonspay less and values above 33.333 make Mcdonalds pay less.  In other words any value above 33.333 hours will have Tim Hortons be the better employer.  And this is per week

I want to repeat, you can expand this to be multiple weeks and see which of the two becomes better in that epriod of time.  This was, I think, the simplest way to answer though.  

So the conditions where Tim Horton pays more isif you work more than 33.333 hours per week.  This will make them pay more every single week.  

prove that

[tex]2 \tan30 \div 1 + tan ^{2} 30 = sin60[/tex]
prove that

.

Answers

Step-by-step explanation:

2tan 30° / 1 + tan² 30° =

2(⅓√3) /1 + (⅓√3)² =

⅔√3 / 1+ ⅓ =

⅔√3 / 4/3 =

2/4 √3 =

½3 = sin 60° (proven)

Which expression gives the best estimate of 30 percent of 61?

The answers are below:

Hurry, please!

Answers

Answer:

it would be 1/4(60)

Step-by-step explanation:

30 percent of 61 is 18.3 and 1/4 of 60 is 15 which is closest to 18.3

Determine the measure of the interior angle at vertex C.

Answers

Answer:

The ANSWER is 18*3= 54

Step-by-step explanation:

total angle inside pentagon = 540 degrees so 3(8x)+2(3x)=540 and that is 30x=540

Answer:

C = 144

Step-by-step explanation:

A 5 sided figure has the interior angle sum of 540 degrees

8x+8x+8x+3x+3x = 540

Combine like terms

30x= 540

30x/30 = 540/30

x = 18

<C = 8*18 = 144

Let T be the event that an adult admits to texting while driving and N be the event an adult does not admit to texting while driving. We previously determined
P(T) = 0.61
and
P(N) = 0.39.
Since three adults are chosen randomly, we have the following simple events.
TTT TTN TNT NTT TNN NTN NNT NNN
The adults were randomly selected, indicating these can be seen as independent events. Therefore, the multiplication rule can be used. Recall the multiplication rule states that for independent events, the probability that they all occur is the product of their respective probabilities. Let x be the number of adults who admit to texting while driving. Since three adults are randomly selected, then x can take on the values 0, 1, 2, or 3.
When x = 0, then no adult in the group of three admits to texting while driving. This corresponds to the simple event NNN whose probability is calculated as below.
P(x = 0) = P(NNN)
= P(N)P(N)P(N)
= 0.39(0.39)(0.39)
=
When x = 1, then only one adult in the group admits to texting while driving. This corresponds to the simple events TNN, NTN, and NNT. First, calculate the probability of each simple event by multiplying the individual probabilities. Then sum the three simple events to find
P(x = 1).
Calculate
P(x = 1).
P(x = 1) = P(TNN) + P(NTN) + P(NNT)
= P(T)P(N)P(N) + P(N)P(T)P(N) + P(N)P(N)P(T)
= 0.61(0.39)(0.39) + 0.39(0.61)(0.39) + 0.39(0.39)(0.61)
=
Find the remaining probabilities
P(x = 2)
and
P(x = 3).
P(x = 2) = P(TTN) + P(TNT) + P(NTT)
= P(T)P(T)P(N) + P(T)P(N)P(T) + P(N)P(T)P(T)
= 0.61(0.61)(0.39) + 0.61(0.39)(0.61) + 0.39(0.61)(0.61)
=
P(x = 3) = P(TTT)
= P(T)P(T)P(T)
= 0.61(0.61)(0.61)
=

Answers

Answer:

Step-by-step explanation:

X P(X=x)

0 0.39*0.39*0.39 = 0.059319

1 3*0.61*0.39*0.39 = 0.278343

2 3*0.61*0.61*0.39 = 0.435357

3 0.61*0.61*0.61 = 0.226981

HELP ASAP. I can’t miss anymore please help

Answers

[tex]4\pi[/tex]

Step-by-step explanation:

[tex]C = 2\pi r,\:\:\:\:r = 4[/tex]

The circumference of the circle of radius 4 is [tex]8\pi[/tex]. Since we are dealing with only half of the circle, the arc length is then half the circumference or [tex]4\pi[/tex].

Determine how much simple interest you would earn on the following investment:
$13,400 invested at a 6/2 % interest rate for 4 years.

Answers

Answer:

How do you mean 6/2%? Clarify it for assistance

Answer:

Simple interest = $ 3,484.00

Step-by-step explanation:

I= P×R×T ÷ 100

The rate is 6 1/2 and I will use the decimal form 6.5,to change that to a whole number we simply move the decimal point one place behind.

Since we moved the decimal point in the numerator we need to do the same for the denominator.Therefore 100 becomes 1000.

13400 × 65 × 4    = $ 3,484.00

        1000

1. Find the exact value of sin( a−B), given that sin a=−4/5 and cos B=12/13, with a in quadrant III and B in quadrant IV.

2. Find all real numbers in the interval [0,2pi) that satisfy the equation.

3sec^2 x tan x =4tan x

3. Simplify the following trigonometric expressions, using identities as needed:

sin(x)/1−cos(x) + 1−cos(x)/sin(x)

Answers

(1) Recall that

sin(x - y) = sin(x) cos(y) - cos(x) sin(y)

sin²(x) + cos²(x) = 1

Given that α lies in the third quadrant, and β lies in the fourth quadrant, we expect to have

• sin(α) < 0 and cos(α) < 0

• sin(β) < 0 and cos(β) > 0

Solve for cos(α) and sin(β) :

cos(α) = -√(1 - sin²(α)) = -3/5

sin(β) = -√(1 - cos²(β)) = -5/13

Then

sin(α - β) = sin(α) cos(β) - cos(α) sin(β) =  (-4/5) (12/13) - (-3/5) (-5/13)

==>   sin(α - β) = -63/65

(2) In the second identity listed above, multiplying through both sides by 1/cos²(x) gives another identity,

sin²(x)/cos²(x) + cos²(x)/cos²(x) = 1/cos²(x)

==>   tan²(x) + 1 = sec²(x)

Rewrite the equation as

3 sec²(x) tan(x) = 4 tan(x)

3 (tan²(x) + 1) tan(x) = 4 tan(x)

3 tan³(x) + 3 tan(x) = 4 tan(x)

3 tan³(x) - tan(x) = 0

tan(x) (3 tan²(x) - 1) = 0

Solve for x :

tan(x) = 0   or   3 tan²(x) - 1 = 0

tan(x) = 0   or   tan²(x) = 1/3

tan(x) = 0   or   tan(x) = ±√(1/3)

x = arctan(0) +   or   x = arctan(1/√3) +   or   x = arctan(-1/√3) +

x =   or   x = π/6 +   or   x = -π/6 +

where n is any integer. In the interval [0, 2π), we get the solutions

x = 0, π/6, 5π/6, π, 7π/6, 11π/6

(3) You only need to rewrite the first term:

[tex]\dfrac{\sin(x)}{1-\cos(x)} \times \dfrac{1+\cos(x)}{1+\cos(x)} = \dfrac{\sin(x)(1+\cos(x))}{1-\cos^2(x)} = \dfrac{\sin(x)(1+\cos(x)}{\sin^2(x)} = \dfrac{1+\cos(x)}{\sin(x)}[/tex]

Then

[tex]\dfrac{\sin(x)}{1-\cos(x)}+\dfrac{1-\cos(x)}{\sin(x)} = \dfrac{1+\cos(x)+1-\cos(x)}{\sin(x)}=\dfrac2{\sin(x)}[/tex]

Can someone help me please! Thanks

Answers

This is a re-entrant hexagon (6 sides)
It can be cut into 4 triangles so the angle sum is 4 x 180 = 720 degrees
x = 720 - 84 - 99 - 157 - 24 - 281 = 75 degrees

Answer:

hello again.. I think you have a problem about figures

Step-by-step explanation:

please be brave when you try to solve..try to draw new lines to get angle and then look at the overall of shape.. the photo helps you good bye

Jason planted and staked a tree. The stakes are 21 ft from the base of the tree. They are connected to wires that attach to the trunk at a height of 20 ft. Find the length of a wire.

14 ft
15 ft
20 ft
29 ft

Answers

Based on the height that the wires attach, and the base length of the stakes, the length of the wire is 29 ft.

How long are the wires?

This can be solved with the Pythagorean theorem because the height can be treated as the height of a right-angled triangle. The base as the base of the triangle.

The length of the wire is the hypothenuse.

Length:
c² = a² + b²

c² = 21² + 20²

c² = 841

c = √841

= 29 ft

Find out more on the Pythagorean theorem at https://brainly.com/question/343682.

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2.According to www.city-data, the mean price for a detached house in Franklin County, OH in 2009 was $192,723. Suppose we know that the standard deviation was $42,000. Check the three assumptions associated with the Central Limit Theorem. What is the probability that a random sample of 75 detached houses in Franklin County had a mean price greater than $190,000 in 2009

Answers

Answer:

0.7123 = 71.23% probability that a random sample of 75 detached houses in Franklin County had a mean price greater than $190,000 in 2009.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The mean price for a detached house in Franklin County, OH in 2009 was $192,723. Suppose we know that the standard deviation was $42,000.

This means that [tex]\mu = 192723, \sigma = 42000[/tex]

Sample of 75:

This means that [tex]n = 75, s = \frac{42000}{\sqrt{75}}[/tex]

What is the probability that a random sample of 75 detached houses in Franklin County had a mean price greater than $190,000 in 2009?

1 subtracted by the p-value of Z when X = 190000. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{190000 - 192723}{\frac{42000}{\sqrt{75}}}[/tex]

[tex]Z = -0.56[/tex]

[tex]Z = -0.56[/tex] has a p-value of 0.2877

1 - 0.2877 = 0.7123

0.7123 = 71.23% probability that a random sample of 75 detached houses in Franklin County had a mean price greater than $190,000 in 2009.

A service station has both self-service and full-service islands. On each island, there is a single regular unleaded pump with two hoses. Let X denote the number of hoses being used on the self-service island at a particular time, and let Y denote the number of hoses on the full-service island in use at that time. The joint pmf of X and Y appears in the accompanying tabulation.

Y
p(x,y) 0 1 2
x 0 0.10 0.04 0.02
1 0.08 0.20 0.06
2 0.06 0.14 0.30

a. What is P(X = 1 and Y = 1)?
b. Compute P(X ≤ 1 and Y ≤ 1).
c. Give a word description of the event {X ≠ 0 and Y ≠ 0}, and compute the probability of this event.
d. Compute the marginal pmf of X and of Y. Using pX(x), what is P(X ≤ 1)?
e. Are X and Y independent rv’s? Explain.

Answers

Answer:

a. 0.2

b. 0.42

c. 0.7

d. the solution is in the explanation

e. x and y are not independent

Step-by-step explanation:

a. from the joint probability mass function table,

p(x=1) and p(Y= 1)

= p(1,1) = 0.2

b. prob(0,0)+prob(0,1)+prob(1,0)+prob(1,1)

= 0.10 + 0.04 + 0.08 + 0.20

= 0.42

P(X ≤ 1 and Y ≤ 1) = 0.42

c. prob {X ≠ 0 and Y ≠ 0}

= prob(1,1) + prob(1,2) + prob(2,1) + prob(2,2)

= 0.20 + 0.06 + 0.14 + 0.30

= 0.7

d. we have to calculate the marginal pmf of x and y here.

we have the x values as 0,1,2

prob(x=0) = 0.1 + 0.04 + 0.02

= 0.16

prob(x=1) = 0.08 + 0.2 + 0.06

= 0.34

prob(x=2) = 0.06+0.14+0.3

= 0.50

we have y values as 0,1,2

prob(y=0) = .1+.08+.06

= 0.24

prob(y=1) = .04+.2+.14

= 0.38

prob(y = 2) = 0.02+0.06+0.3

= 0.38

P(X ≤ 1) = prob(x=0)+prob(x=1)

= 0.34+0.16

= 0.50

e. from the joint table we have this,

prob(1,1) = 0.2

prob(x=1) = 0.34

prob(y=1) = 0.38

then prob(x=1)*prob(y=1)

= 0.34*0.38

= 0.1292

therefore prob(1,1) is not equal to prob(x=1)*prob(y=1)

0.2≠0.1292

x and y are not independent

Consider the equations y = VI and y
32 – 1.
The system of equations is equal at approximately

Answers

Answer:

[tex]x = 2.62[/tex] and [tex]x = 0.381[/tex]

Step-by-step explanation:

[tex]y = \sqrt x\\[/tex]

[tex]y = x - 1[/tex]

Required

y, when they are equal.

To do this, we set them to another

[tex]\sqrt{x} = x - 1[/tex]

Square both sides

[tex]x = (x - 1)^2[/tex]

Expand

[tex]x = x^2 - 2x + 1[/tex]

Collect like terms

[tex]x^2 -x-2x+1 = 0[/tex]

[tex]x^2 - 3x + 1 = 0[/tex]

Using quadratic formula

[tex]x = 2.62[/tex] and [tex]x = 0.381[/tex]

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