The length L of the base of a rectangle is 5 less than twice its height H. Then the algebraic expression be, area of rectangle = 2H² - 5H.
What is the algebraic expression to model the area of the rectangle?Let, the given information be "The length L of the base of a rectangle is 5 less than twice its height H".
L be the length of the rectangle
H be the height of the rectangle
By converting the given information into an algebraic expression, we get
Length = 2H - 5
The area of a rectangle is given by the formula;
Area of rectangle = L [tex]*[/tex] H
Where L is the Length.
H is the Height.
Substituting the values into the formula, we have;
Area of rectangle = (2H - 5) [tex]*[/tex] H
Area of rectangle = 2H² - 5H
Therefore, the area of rectangle = 2H² - 5H.
To learn more about algebraic expression of rectangle
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Assume that abc = pqr. Which of the following congruence statements are correct? Check all that apply
Answer:
A and E are correct congruence statements.
Answer:
A E
Step-by-step explanation:
The shaded area in the distribution below represents approximately 95% of the data. Use the diagram to find the mean and the standard deviation.
Answer:
mean = 85, standard deviation = 3.5
Step-by-step explanation:
The empirical rule states that for a normal distribution, 68% of the data falls within one standard deviation of the mean, 95% falls within two standard deviation of the mean and 99.7% falls within three standard deviation of the mean.
From the diagram since the shaded are is approximately 95% of the data. Hence 95% falls within two standard deviations of the mean.
σ = standard deviation, μ = mean
Hence; μ ± 2σ = (78, 92)
μ - 2σ = 78 (1);
μ + 2σ = 92 (2)
Adding equation 1 and 2, gives 2μ = 170
μ = 85
μ - 2σ = 78
85- 2σ = 78
2σ = 7
σ = 3.5
Question 2
Find HY if YL = 9 .
Answer:
HY = 18
Step-by-step explanation:
The distance from the vertex to the centroid is twice the distance from the centroid to the midpoint , so
HY = 2 YL = 2 × 9 = 18
Arnold makes a chart to summarize what happens when light interacts with matter and is reflected. Which idea does Arnold need to correct? In specular reflection, reflected rays move in the same direction. In scattering, light strikes particles in the atmosphere. In diffuse reflection, reflected rays move in different directions. In scattering, long wavelengths are scattered the most.
Answer:
In diffuse reflection, reflected rays move in different directions.
Step-by-step explanation:
Reflection refers to the bouncing off of light from a surface. Reflection can be regular or diffuse.
Regular reflection occurs when light bounces off a well polished surface while diffuse reflection occurs when light bounces off a rough surface.
During diffuse reflection, light is reflected in different directions.
Answer:
In scattering, long wavelengths are scattered the most.
Step-by-step explanation: took the test for Edg 21
what type of polynomial is p(x)=4x−2x2+3
a. quadratic
b. quartic
c. quintic
d. cubic
Answer:
a. quadratic.
The given polynomial p(x)=4x−2x²+3 is a quadratic polynomial. The correct option is A.
What is a polynomial?A polynomial in mathematics is an expression made up of coefficients and indeterminates and involves only the operations of multiplication, addition, subtraction, and non-negative integer exponentiation of variables.
In algebra, a polynomial function with one or more variables in which the highest-degree term is of the second degree is known as a quadratic function, a quadratic polynomial, a polynomial of degree 2, or simply a quadratic.
In the given polynomial p(x)=4x−2x²+3 it can be observed that the degree of the polynomial is 2 or the highest power of the variable is 2.
Therefore, the given polynomial p(x)=4x−2x²+3 is a quadratic polynomial. The correct option is A.
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Which expressions are equivalent to 2^5•2^4? Check all that apply.
Answer:
2⁵×2⁴=2⁹
2⁵×2⁴=2×2×2×2×2×2×2×2×2
2⁵×2⁴=4⁵
2⁵×2⁴=8³×2
Answer:
[see below]
Step-by-step explanation:
Recall the product rule: [tex]a^x+a^y=a^{x+y}[/tex]
[tex]2^5 + 2^4 = 2^{5 + 4} = \boxed{2^9}[/tex]
Other expressions could be:
[tex]2^{-2} *2^{11}=2^{-2+11} = \boxed{2^9}[/tex]
[tex](2*2*2*2*2)(2*2*2*2) = 2^5 + 2^4 = \boxed{2^9}[/tex]
Hope this helps.
At a farmers market, oranges sell for $5 per bag and apples sell for $3 per
bag. Marc buys 7 bags of fruit for $29. How many bags of each type of fruit
did he buy?
Answer: 4 bags of oranges and 3 bags of apple
Step-by-step explanation:
Each bag of oranges is 5 and 5 times 4 is 20 Each bag of apples is 3 and 3 times 3 is 9 so 20 + 9 = 29
A local store sells oranges at a price for 6 fo $9.00. If Alley wants to buy 10 oranges what would the total price be?
Answer:
15$
Step-by-step explanation:
you need to check how much of e costs and you do that by dividing the price by the amount and than comes up to 1.5 that's for 1 and for 10 it's 15 hope that helps
What is the product?
43 .4-3
0)
1)
4)
6)
Answer:
1
Step-by-step explanation:
So we can actually simplify the exponents here. The power rule for exponents is that when multiplying, you add the exponents. So,
3 + (-3) = 0
so the number is now 4^0.
Everything by the power of 0 is equal to 1, so the answer is 1.
Hope this helps !!
-Ketifa
Find four fractions between 1/10 and 1/8
9514 1404 393
Answer:
5/48, 5/46, 5/44, 5/42
Step-by-step explanation:
We can choose unit fractions with denominators between 8 and 10, separated by (10-8)/5 = 0.4 units:
1/8.4 = 5/42
1/8.8 = 5/44
1/9.2 = 5/46
1/9.6 = 5/48
__
Check
1/8 = 0.1255/42 ≈ 0.1195/44 ≈ 0.1145/46 ≈ 0.1095/48 ≈ 0.1041/10 = 0.100_____
Additional comment
There are an infinite number of such fractions. We are given unit fractions with different denominators, so it works reasonably well to choose denominators between those given. Then the trick is to convert the fraction to a ratio of integers. In this case, multiplying by (5/5) does the trick.
__
Another approach is to write the fractions with a common denominator, then choose numerators between the ones given. For example, 1/10 = 4/40, and 1/8 = 5/40, so you could write some fractions with numerators between 4 and 5. Possibilities are 4.1/40 = 41/400, 4.3/40 = 43/400, 4.7/40 = 47/400, 4.9/40 = 49/400.
Please help me with this I really need help (ಥ_ಥ)
Answer:
i can help you i know this question
A triangle and a parallelogram have the same base and the same area.
If the sides of the triangle are 26 cm, 28 cm and 30 cm and the
parallelogram stands on the base 28 cm. Find the height of the
parallelogram.
Answer:
12 centimeters
Step-by-step explanation:
The side lengths of the triangle are: 26, 28, and 30 centimeters
a = 26 cm, b = 28 cm, c = 30 cm
To find the area, we first must find the semi-perimeter with the following equation:
s = (a+b+c)/2
= (28+26+30)/2
= 42 centimeters
Now, to find the area, we can use Heron's formula:
A = [tex]\sqrt{s (s-a)(s-b)(s-c)}[/tex]
[tex]\sqrt{42(42-28)(42-26)(42-30)[/tex]
[tex]\sqrt{42(14)(16)(12)}[/tex]
[tex]\sqrt{112896}[/tex]
336 squared centimeters
Since the area of the parallelogram is equal to the area of our triangle:
Area of Parallelogram = Area of Triangle
base ⋅ height = 336 squared centimeters
28 ⋅ height = 336 squared centimeters
height = 336/28
height = 12 centimeters
i need help in this plz!!!!
Step-by-step explanation:
1) = {5(x+y)} - 2x
= 5x + 5y - 2x
= 3x + 5y
2)= {2(p×q)} + (p×q)
= (2p×2q)+ p×q
= 4pq + pq
= 5pq
3)= 6a + (8b + 2a)
= 8a + 8b
= 8(a+b)
4)= 3x² + ( x²+7x)
= 4x² + 7x
= x(4x+7)
Answer:
Step-by-step explanation:
72) 5*(x +y) - 2x
= 5x + 5y - 2x {Distributive property}
= (5x - 2x) + 5y {Combine like terms}
= 3x + 5y
73) 2*(pq) + pq
= 2pq + pq {Combine like terms}
= 3pq
74) 6a + (8b + 2a)
= 6a + 2a + 8b {Combine like terms}
= 8a + 8b
75) 3*x² + (x² + 7x)
= 3x² + x² + 7x {Combine like terms}
= 4x² + 7x
The diagonals of a quadrilateral must be bisect each other and be perpendicular to gurarantee that the quadrilateral is a parrelogram
Answer:
False
Step-by-step explanation:
A quadrilateral is a closed geometrical figure that have four sides and four vertices. Thus the following includes in a quadrilateral : parallelogram, square, rhombus, rectangle and trapezium.
If the diagonals of the quadrilateral bisects each other and are perpendicular to each other, then the quadrilateral forms a rhombus.
Hence the answer is FALSE.
50 Points:
What are the coordinates of the point that is
2/3 of the way from A to B?
Point A: -4,-1
Point B: 5,5
A. 1,2
B. 0,5/3
C. 2,3
D. -1,1
Answer:
(-2,3)
Step-by-step explanation:
For the point to be 2/3 of the way; it means it divides AB into the ratio 2 to 1
Now, we can use the internal section formula to get the coordinates of this point
(x,y) = (nx1 + mx2)/(m + n), (ny1 + my2)/(m + n)
where (m,n) = (2,1)
(x1,y1) = (-4,-1)
(x2,y2) = (5,5)
(x,y) = (1(-4) + 2(-1)/(1+2), (1(-1)+2(5)/(1+2)
(x,y) = (-4-2)/3, (-1 + 10)/3
(x,y) = (-2,3)
Which segment is the hypotenuse?
Answer:
SU
Step-by-step explanation:
The hypotenuse is opposite the right angle
The hypotenuse is US or SU
We have to pick,
The segment which is hypotenuse,
Hypotenuse will be the opposite segment of the right angle.
Now it will be,
→ SU (or) US
Hence, SU is the hypotenuse.
Finding an angle measure
Answer:
C. 50 degrees
Step-by-step explanation:
Angle EDG is 90 degrees
x = 10
5 multiplied by 10 is 50
4 multiplied by 10 is 40
40+50=90
Answer:
50 = EDH
Step-by-step explanation:
We know that angle EDG is a right triangle (measures 90°). We also know that angle EDH and angle HDG make up angle EDG which is 90°. So ultimately we can state that;
EDH + HDG = EDG
5x + 4x = 90
9x = 90
x = 90/9
x = 10
Now that we know that value of x, we can say that;
EDH = 5x
since x = 10
EDH = 5(10)
EDH = 50
Hope this helps!
Which of the
x
xx-values are solutions to the following inequality?
x
>
111
x>111x, \gt, 111
Choose all answers that apply:
Choose all answers that apply:
(Choice A)
A
x
=
97
x=97x, equals, 97
(Choice B)
B
x
=
101
x=101x, equals, 101
(Choice C)
C
x
=
119
x=119x, equals, 119
Given:
The inequality is:
[tex]x>111[/tex]
To find:
The x-values that are the solutions to the given inequality.
Solution:
We have,
[tex]x>111[/tex]
It means all the real numbers greater than 111 are the solutions to the given inequality.
[tex]97<111[/tex], so 97 is not a solution.
[tex]101<111[/tex], so 101 is not a solution.
[tex]119>111[/tex], so 119 is a solution.
Therefore, the correct option is C.
Given:
The inequality is:
To find:
The x-values that are the solutions to the given inequality.
Solution:
We have,
It means all the real numbers greater than 111 are the solutions to the given inequality.
, so 97 is not a solution.
, so 101 is not a solution.
, so 119 is a solution.
Therefore, the correct option is C.
Line K has a slope of -3/4. If the slope of of lines that are perpendicular to each other are opposite reciprocals, what is the slope of a line perpendicular to line k?
Answer:
+4/3
Step-by-step explanation:
-3/4 * -1 = 3/4 then flip it to 4/3
Answer:
4/3
Step-by-step explanation:
the slope of a perpedicular line is the inverse times negative one.
1)the inverse of -3/4 is -4/3
2)-4/3*-1 is 4/3
which expression is equivalent to (4 square root 5 to the power of 3) to the power of 1/2
ASAppppppppppppppppppppppppppppppppppp
Answer:
3/8
Step-by-step explanation:
that is the answer
I solved it using a calculator
please give me brainliest
the answer is 3/8 because im right
A group of students is arranging squares into layers to create a project. The first layer has 6 squares. The second layer has 12 squares. Which formula represents an arithmetic explicit formula to determine the number of squares in each layer?
f(1) = 6; f(n) = 6 + d(n − 1), n > 0
f(1) = 6; f(n) = 6 ⋅ d(n − 1), n > 0
f(1) = 6; f(n) = 6 ⋅ d(n + 1), n > 0
f(1) = 6; f(n) = 6 + d(n + 1), n > 0
Answer:
a.
f(1)=6; f(n)=6+d(n-1), n>0
Step-by-step explanation:
We are given that
First layer has squares, a=6
Second layer has squares, a2=12
We have to find an arithmetic explicit formula to determine the number of squares in each layer.
[tex]d=a_2-a_1=12-6[/tex]
nth term of an A.P
[tex]a_n=a+(n-1)d[/tex]
Substitute the value of a
Now, we get
[tex]a_n=6+(n-1)d[/tex]
f(1)=a=6
[tex]a_n=f(n)=6+d(n-1)[/tex]
Hence, option a is correct.
a.
f(1)=6; f(n)=6+d(n-1), n>0
Answer:
f(1) = 6; f(n) = 6 + d(n − 1), n > 0
Step-by-step explanation:
I took the test on flvs and got it right.
100% Guaranteed Correct :)
, Hope this helps
Have a great day!!
Express the following as ONE fraction:
(( b - c )/ b ) + (b / ( b + c ))
Answer:
Step-by-step explanation:
(b - c)/b * (b+c)/b Notice how the second fraction is inverted and multiplied. That's how you handle a 4 tier fraction. Here's a simpler example
[tex]\frac{\frac{2}{3} }{\frac{4}{5} } = \frac{2}{3} * \frac{5}{4}[/tex]
What you get with your problem is
(b^2 - c^2)/b^2
tìm x,y nguyên tố thỏa mãn:y^2-2x^2=1
Answer:
dx/dy = y/2x
Step-by-step explanation:
-4x × dx/dy = -2y..... that's all
HELP PLSSSSS ON KHAN ACADEMY
[tex]\boxed{\large{\bold{\blue{ANSWER~:) }}}}[/tex]
See this attachment
PLEASE PLEASE PLEASE HELP. I WILL BE SO SO SO HAPPY!! WILL GOVE BRANLIEST! AND FOREVER BE SO HAPPY! POINTS!
Answer:
a
Step-by-step explanation:
follows geometric sequence. starting value is 1/3 and is multiplied by 1/3 every time
**HELP**
find the angle measures given the figure is a rhombus.
Answer:
m<1=74
m<2=37
Step-by-step explanation:
m<2 is the same as the other angle, 37 degrees. So now we need to find the other angle in the triangle.
37+37+x=180.
The total degree of a triangle is 180.
x=106
Subtract that from 180 to get m<1.
180-106=74
I hope this helps!
Good luck!
Can anyone help me please
Answer:
1
Step-by-step explanation:
Basically you just need to find the square root of all of them
36=6 -1=1 9=3 . -1=1
6-1-3-1=1
By converting to an exponential expression, solve log3 (x + 9) = 5.
Answer:
[tex]{ \tt{ log_{3}(x + 9) = 5 }} \\ { \tt{x + 9 = {3}^{5} }} \\ { \tt{x + {3}^{2} = {3}^{5} }} \\ { \tt{x = {3}^{5} - {3}^{2} }} \\ { \tt{x = 234}}[/tex]
PLEASE HELP A boat travels downstream 10 miles and returns to the starting point in 2
hours. If the speed of the stream is 15 mph, find the speed of the boat in still
water. A. 20.81mph B. 30.24mph C.25.67 D.15mph
Answer:
A. 20.81 mph
Step-by-step explanation:
x = speed of the boat in still water.
one part of the trip is 10 miles downstream, where the speed of the boat and the speed of the current add together.
and the other part of the trip is the trip back the 10 miles upstream, where the speed of the current works against the speed of the boat :
10/(x + 15) + 10/(x - 15) = 2
10 + 10×(x+15)/(x-15) = 2×(x+15)
10×(x-15) + 10×(x+15) = 2×(x+15)×(x-15)
20x = 2×(x² - 225)
10x = x² - 225
0 = x² - 10x - 225
solution of a quadratic equation
x = (-b ± sqrt(b² - 4ac)) / (2a)
a = 1
b = -10
c = - 225
(10 ± sqrt(100 - 4×1×-225)) / 2 =
= (10 ± sqrt (100 + 900)) / 2 = (10 ± sqrt(1000)) / 2 =
= (10 ± 31.62) / 2
x1 = 41.62 / 2 = 20.81 mph
x2 is negative and did not make any sense.
