Physics Middle School

The industry that provides the service of people's experience,
knowledge, or skills is known as the tertiary or
Services industry.

Answers

Answer 1

Answer:

Explanation:

true

Answer 2

The industry which provides service to the experience, knowledge or skill of the people is known as tertiary or service industry. This statement is True.

What is Service industry?

Tertiary industry provides services to its consumers which is also known as service industry/sector which is also known as service industry/sector.

This sector includes a wide range of activities ranging from commerce to administration, transportation, financial and real estate activities, business and personal services, education, health and social work.

Companies within a service industry provide specific products or services that satisfy a need or are otherwise useful to customers such as manufacturing or production, service industries do not rely on the sale of goods or physical products that they otherwise provide to the public. provide essential services.

Thus, the industry which provides service to the experience, knowledge or skill of the people is known as tertiary or service industry. This statement is True.

Learn more about Tertiary industry, here:

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Related Questions

two trucks leave at different times (from the same place) headed for the same city. Both trucks arrive at the same time. Based on the this information, which of the following statements is true? A. The trucks traveled the same distance in the same amount of time B. The trucks were traveling at the same average speed C. The trucks traveled different distances D. The truck that left later traveled faster

Answers

the answer is A because everything would have to be constant to arrive at the same place at the same time and A is the only option that is constant

A researcher is studying traffic patterns at an intersection before an upcoming construction project. As part of this investigation, the researcher writes a scientific question, develops a procedure to observe traffic specifically at this intersection, and draws a conclusion. Which type of investigation is the researcher conducting? descriptive comparative experimental procedural

Answers

Answer:

Procedural is the answer

hope this helps

Answer: Procedural

Explanation: It states in the question that he developed a procedure! If this was something you have heard before, this is definitely the answer. Goodluck! ☺️

HELP PLSSSSSSS ASAP FIRST CORRECT ANSWER WILL GET BRANLIST. A bunny accidentally knocks a basket of eggs off of a table. Luckily the basket lands safely on the floor with all the eggs unbroken. Air resistance is negligible. What is the acceleration of the egg-basket system in midair? A)The acceleration cannot be determined without knowing how hard the basket was pushed. B) Acceleration is downward and less than g because the eggs are light. C) The acceleration fluctuates because of the rolling of the eggs. D) Acceleration is downward with a magnitude of g because the system is a projectile.

Answers

Answer: i think is C

Explanation:

Because eggs do not have a good weight and the basket swings because not all eggs weigh the same there are small and large in the basket

I think it's this good luck :)

Answer:

Acceleration is downward with a magnitude of g because the system is a projectile.

Explanation:

What is the average velocity of atoms in 2.00 mol of neon (a monatomic gas)
at 308 K? Use the equation: -mv2
2
For m, use 0.02000 kg. Remember that R = 8.31 J/(mol-K).
= ER
3
2
nRT
A. 1540 m/s
B. 876 m/s
C. 87.6 m/s
O D. 15,400 m/s

Answers

Answer:

v = 876 m/s

Explanation:

It is given that,

Number of mol of Neon is 2 mol

Temperature, T = 308 K

Mass, m = 0.02 kg

Value of R - 8.31 J/mol-K

We need to find the average velocity of atoms in 2.00 mol of neon. Neon is a monoatomic gas. Let v is the velocity. So,

[tex]\dfrac{1}{2}mv^2=\dfrac{3}{2}nRT\\\\v=\sqrt{\dfrac{3nRT}{m}} \\\\v=\sqrt{\dfrac{3\times 2\times 8.314\times 308}{0.02}} \\\\v=876.47\ m/s[/tex]

So, the correct option is (B).

I think it is 887m/s I hope this helps if not I’m really sry

In the diagram, q1= +8.0 C, q2= +3.5 C, and q3 = -2.5 C. q1 to q2 is 0.10 m, q2 to q3 is 0.15 m. What is the net force on q2? Label sign for charges (+ or -). (Unit = N). pls help?

Answers

Answer:

f(t) =  28,7 [N]

Explanation: IMPORTANT NOTE: IN PROBLEM STATEMENT CHARGES ARE IN C (COULOMBS) AND IN THE DIAGRAM IN μC. WE ASSUME CHARGES ARE IN μC.

The net force on +q₂  is the sum of the force of +q₁  on +q₂ ( is a repulsion force since charges of equal sign repel each other ) and the force of -q₃ on +q₂ ( is an attraction force, opposite sign charges attract each other)

The two forces have the same direction to the right of charge q₂, we have to add them

Then

f(t) = f₁₂ + f₃₂

f₁₂ = K * ( q₁*q₂ ) / (0,1)²

q₁  = + 8 μC     then   q₁ = 8*10⁻⁶ C

q₂ =  + 3,5 μC  then  q₂ = 3,5 *10⁻⁶ C

K = 9*10⁹  [ N*m² /C²]

f₁₂ = 9*10⁹ * 8*3,5*10⁻¹²/ 1*10⁻²   [ N*m² /C²]* C*C/m²

f₁₂ = 252*10⁻¹ [N]

f₁₂ = 25,2 [N]

f₃₂ =  9*10⁹*3,5*10⁻⁶*2,5*10⁻⁶ /(0,15)²

f₃₂ =  78,75*10⁻³/ 2,25*10⁻²

f₃₂ =  35 *10⁻¹

f₃₂ =  3,5 [N]

f(t) =  28,7 [N]

Answer:

facts

Explanation:

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