The graph of y=x√ is translated 5 units to the left and 7 units up. What is the equation of the graph that results from this translation?

9514 1404 393

Answer:

Step-by-step explanation:

To find the initial amount, put 0 where t is in the formula and do the arithmetic.

  A(0) = 523(1/2)^0 = 523(1) = 523

The initial amount is 523 grams.

__

To find the amount remaining after 100 years, put 100 where t is in the formula and do the arithmetic.

  A(100) = 523(1/2)^(100/30) ≈ 523(0.0992123) ≈ 52

About 52 grams will remain after 100 years.

Answer:

0.713 = 71.3% probability that the county office will get more than 0 calls in a 15 minute period.

Step-by-step explanation:

We have the mean during a time-period, which means that the Poisson distribution is used to solve this question.

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

In which

x is the number of sucesses

e = 2.71828 is the Euler number

[tex]\mu[/tex] is the mean in the given interval.

A county office gets an average of 10 calls in a 2 hour time period.

10 calls each 120 minutes, which means that the mean for n minutes is:

[tex]\mu = \frac{10n}{120} = \frac{n}{12}[/tex]

15 minute period:

This means that [tex]n = 15, \mu = \frac{15}{12} = 1.25[/tex]

What is the probability that the county office will get more than 0 calls in a 15 minute period?

This is:

[tex]P(X > 0) = 1 - P(X = 0)[/tex]

In which

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

[tex]P(X = 0) = \frac{e^{-1.25}*1.25^{0}}{(0)!} = 0.287[/tex]

So

[tex]P(X > 0) = 1 - P(X = 0) = 1 - 0.287 = 0.713[/tex]

0.713 = 71.3% probability that the county office will get more than 0 calls in a 15 minute period.

Step-by-step explanation:

1. The inputs are the dice values. Since the cube is six sided, the possible. values are (1,2,3,4,5,6).

2. The outputs values are points if we roll the number. If we land in a special space, we must respect that rule so our outputs are

(2,2,8,5,6,8).

3. I cant show a mapping diagram on brainly. Draw a mapping diagram and make sure to connect the x values and y values of the following.Also make sure to start on square 1.

4. The domain of the function is the same as the input. The dice values, 1,2,3,4,5,6

5.The range are the. values that occur if we roll the number about square 1.

2,2,8,5,6,8

6. No, the player could have rolled 3 and landed on 8. The player also could have rolled 6.

7. Yes, every one x value corresponds with one y value.

Answer:

VW = 4.9

Step-by-step explanation:

From the question given above, the following data were obtained:

Angle θ = 46°

Hypothenus = VU = 7

Adjacent = VW =?

The value of VW can be obtained by using the cosine ratio as illustrated below:

Cos θ = Adjacent / Hypothenus

Cos 46 = VW / 7

Cross multiply

VW = 7 × Cos 46

VW = 4.9

Therefore, the value of VW is 4.9

Answer:

a) 0.3056 = 30.56% probability that 3 females and 2 males are selected.

b) 0.0306 = 3.06% probability that all five students selected are males.

c) 0.0131 = 1.31% probability that all five students selected are females.

d) 0.9869 = 98.69% probability that at least one male is selected.

Step-by-step explanation:

The students are chosen from the sample without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

In this question:

15 + 13 = 28 students, which means that [tex]N = 28[/tex]

5 are selected, which means that [tex]n = 5[/tex]

13 females, which means that [tex]k = 13[/tex]

a. 3 females and 2 males are selected?

3 females, so this is P(X = 3).

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]

[tex]P(X = 3) = h(3,28,5,13) = \frac{C_{13,3}*C_{15,2}}{C_{28,5}} = 0.3056[/tex]

0.3056 = 30.56% probability that 3 females and 2 males are selected.

b.all five students selected are males?

0 females, so this is P(X = 0).

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]

[tex]P(X = 0) = h(0,28,5,13) = \frac{C_{13,0}*C_{15,5}}{C_{28,5}} = 0.0306[/tex]

0.0306 = 3.06% probability that all five students selected are males.

c. all five students selected are females?

This is P(X = 5). So

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]

[tex]P(X = 5) = h(5,28,5,13) = \frac{C_{13,5}*C_{15,0}}{C_{28,5}} = 0.0131[/tex]

0.0131 = 1.31% probability that all five students selected are females.

d.at least one male is selected?

Less than five females, so:

[tex]P(X < 5) = 1 - P(X = 5) = 1 - 0.0131 = 0.9869[/tex]

0.9869 = 98.69% probability that at least one male is selected.

Answer:

75

Step-by-step explanation:

We line up the tens place of 33 and 42 as well as the ones place so that it looks like:

33

+42

--------

Then we add first the ones, which is 3 + 2 for 5. Then we add the tens together, 3 + 4 is 7. We put the five first since its in the ones place and the 7 second since its in the tens place for 75.

Step-by-step explanation:

43 is the answer

mark me brainlist and heart

Answer:

s = 7√6.

Step-by-step explanation:

From the 30-60-90 triangle we know that cos 30 = √3/2.

cos 30 = s / 14√2

√3/2 =  s / 14√2

2s = 14√2√3

s = 14√2√3 / 2

s = 7√6.

Answer:

3

Step-by-step explanation:

out of 2 we need to create 2+4=6

and out of 3 we need to create 3+6=9.

2×f = 6

f = 6/2 = 3

and it fits also in the other relation

3×f = 3×3 = 9

perfect.

Answer:

I think the answer is 5/6

Step-by-step explanation:

There are three even numbers and two uneven numbers less than four. Therefore, on a standard die, the.probability of Rollin a number that is even or less than for is 5/6.

Answer:

Symmetric with respect to the x-axis

Symmetric with respect to the y-axis

Symmetric with respect to the origin

Answer:

h = 6.2 units

Step-by-step explanation:

Given triangle ABC is a right triangle with the measures of the two sides,

BC = [tex]\frac{10}{2}[/tex] = 5 units

AC = 8 units

By applying Pythagoras theorem in the given triangle,

AC² = AB² + BC²

8² = AB² + 5²

AB² = 64 - 25

AB = √39

AB = 6.24 units

AB ≈ 6.2 units

Answer:

t = 2

Step-by-step explanation:

5(6t-3)=5t+35

Step 1 distribute the 5 by multiplying 5 to what is inside of the parenthesis

5(6t) - 5(3) = 5t + 35

Outcome: 30t - 15 = 5t + 35

Step 2 add 15 to both sides

30t - 15 + 15 = 5t + 35 + 15

Outcome: 30t = 5t + 50

Step 3 subtract 5t from both sides

30t - 5t = 5t - 5t + 50

Outcome: 25t = 50

Step 4 divide both sides by 25

25t/25 = 50 we're left with t = 2

Answer:

5 cases

10 additional units

Step-by-step explanation:

Given that :

Total number of units needed = 60 units

Total number of units per case = 14

Hence, the total number of cases required will be :

Number of units needed / number of units per case

Number of cases required = 60 / 14 = 4.285 (this means that 5 cases are required as 4 cases won't be up to 60 units)

With 5 cases, we have exceeded the required units needed :

Additional units will be : (14 * 5) - 60

Additional units = 70 - 60 = 10 units

Step-by-step explanation:

1 300 × 2.95/100× 4 = $153.40

Answer:

432x^13

Step-by-step explanation:

(4x^2)^2 • (3x^3)^3

We know that a^b^c = a^(b*c)

4^2 x^2^2  * 3^3 x^3^3

16 x^4  * 27 x^9

We know that a^b ^ a^c = a^(b+c)

16*27 x^(4+9)

432x^13

Answer:

432x¹³

Step-by-step explanation:

( 4x² ) ² • ( 3x³ ) ²

( 16x²)² • ( 27x³)²

[tex]16 x{}^{2 \times 2} \times 6 {}^{3 \times 3 } \\ 16x {}^{4} \times27 {}^{9} [/tex]

[tex](16 \times 27)x {}^{4 + 9} [/tex]

432x¹³

9514 1404 393

Answer:

  ₹14000

Step-by-step explanation:

Let c represent the cost price, and m represent the marked price.

  c × (1 +40%) = m

  m × (1 -15%) - c = ₹1900

Using the first expression for m, the second equation becomes ...

  1.40c×0.85 -c = ₹1900

  0.19c = ₹1900

  c = ₹1900/0.19 = ₹10000

Then the marked price was ...

  m = 1.40c = 1.40×₹10000 = ₹14000

The marked price was ₹14000.

_____

The selling price was ₹11900.

Answer:

the area of rombus is produt of diagonals divide by 2

The answer is 4 because the frequency is the number of cycles completed in one interval. Typically, the interval given is 2π. Here, you can count the cycles and get 4.

This question is incomplete, the complete question is;

Many people grab a granola bar for breakfast or for a snack to make it through the afternoon slump at work. A Kashi GoLean Crisp Chocolate Caramel bar weighs 45 grams. The mean amount of protein in each bar is 8 grams. Suppose the amount of protein in the bars have a normal distribution with a standard deviation of 0.32 grams and a random Kashi bar is selected.  

Suppose the amount of protein is at least 8.6 grams. What is the probability that it is more than 8.7 grams

Answer:

the required probability is 0.472

Step-by-step explanation:

Given the data in the question;

Let x represent the random variable that shows the protein in the bar.

{ normal distribution }

mean μ = 8

standard deviation σ =  0.32

Now, Suppose the amount of protein is at least 8.6 grams. What is the probability that it is more than 8.7 grams

first we get the z-score for x = 8.6

z = x - μ / σ

z = ( 8.6 - 8 ) / 0.32

z = 0.6 / 0.32

z = 1.875

so

P( x ≥ 8.6 ) = P( z ≥ 1.875 ) = 1 - 0.9696 = 0.0304

Also for, x = 8.7

z = x - μ / σ

z = ( 8.7 - 8 ) / 0.32

z = 0.7 / 0.32

z = 2.1875

so

P( x > 8.7 ∩ x ≥ 8.6 ) = P( x > 8.7 ) = P( z > 2.1875 ) = 1 - 0.98565 = 0.01435

Now, the required probability will be;

P( x > 8.7 | x ≥ 8.6 ) = [P( x > 8.7 ∩ x ≥ 8.6 )] / [ P( x ≥ 8.6 ) ]

= 0.01435 / 0.0304

= 0.472

Therefore, the required probability is 0.472

An

Step-by-step explon:

Answer:

i think its the 3 line. they are congruent.

Answer:

its the 3rd option

Step-by-step explanation:

first of all AA means angle-angle which means we are using their angles to compare them

second, those lines on the sides are only there to tell you they are in the exact same angle, and the two boxes on the bottom show that the angle of both triangles is 90° therefore they are the same

From the test the person wants, and the sample data, we build the test hypothesis, find the test statistic,  and use this to reach a conclusion both using the critical value and the p-value.

Doing this, the conclusions are:

---------------------------------------------------------

Hypothesis:

A machine in a factory must be repaired if it produces more than 10% defectives in production.

At the null hypothesis, we test if it does not have to be repaired, that is,  the proportion is of at most 10%. So

[tex]H_0: p \leq 0.1[/tex]

At the alternative hypothesis, we test if it does have to be repaired, that is, the proportion is greater than 10%. So

[tex]H_1: p > 0.1[/tex]

------------------------------------------------------

Decision rule:

0.01 significance level, using a left-tailed test(testing if the mean is more than a value), which means that:

----------------------------------------------------------

The test statistic is:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

In which X is the sample mean, is the value tested at the null hypothesis, is the standard deviation and n is the size of the sample.

0.1 is tested at the null hypothesis:

This means that [tex]\mu = 0.1, \sigma = \sqrt{0.1*0.9}[/tex]

A random sample of 100 items from a day's production contains 15 defectives.

This means that [tex]n = 100, X = \frac{15}{100} = 0.15[/tex]

Value of the test-statistic:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

[tex]z = \frac{0.15 - 0.1}{\frac{\sqrt{0.1*0.9}}{\sqrt{100}}}[/tex]

[tex]z = 1.67[/tex]

----------------------------------------------

Decision: Critical region

The test statistic is [tex]z = 1.67 < z_c[/tex], meaning that there is not enough evidence to conclude that the proportion of defectives is above 10%, that is, it does not support his decision to repair at the 0.01 significance level.

Decision: p-value

The p-value of the test is the probability of finding a sample proportion above 0.15, which is 1 subtracted by the p-value of z = 1.67.

Looking at the z-table, z = 1.67 has a p-value of 0.9525.

1 - 0.9525 = 0.0475.

The p-value of the test is 0.0475 > 0.01, meaning that there is not enough evidence to conclude that the proportion of defectives is above 10%, that is, it does not support his decision to repair at the 0.01 significance level.

A similar problem is found at https://brainly.com/question/24326664

Explanation:

P(A) represents the probability of event A

P(not A) is the probability that event A doesn't happen

We only have two choices: Either A happens or it doesn't

So that means P(A) + P(not A) = 1

The "1" represents a 100% chance, aka certainty.

Answer:

Step-by-step explanation:

The probability that a person answered incorrectly is 4/5

P(1st answered incorrectly AND 2nd answered incorrectly AND

3rd answered incorrectly AND 4th answered incorrectly AND

5th answered incorrectly AND 6th answered incorrectly AND

7th answered incorrectly AND 8th answered incorrectly)

Since "AND" mean to multiply, the probability that none of the 8 guessed correctly is

4/5×4/5×4/5×4/5×4/5×4/5×4/5×4/5

=(4/5)^8

=0.16777216

Answer:

The center is (0,0) and the radius is 1/4

Step-by-step explanation:

The formula for a circle is

(x-h)^2 + (y-k)^2 = r^2  where (h,k) is the center and r is the radius

16x^2+16y^2=1

Divide  by 16

x^2+y^2=1/16

x^2 + y^2 = (1/4) ^2

(x-0)^2 + (y-0)^2 = (1/4) ^2

The center is (0,0) and the radius is 1/4

Answer:

See Below.

Step-by-step explanation:

We are given that:

[tex]\displaystyle I = I_0 e^{-kt}[/tex]

Where I₀ and k are constants.

And we want to prove that:

[tex]\displaystyle \frac{dI}{dt}+kI=0[/tex]

From the original equation, take the derivative of both sides with respect to t. Hence:

[tex]\displaystyle \frac{d}{dt}\left[I\right] = \frac{d}{dt}\left[I_0e^{-kt}\right][/tex]

Differentiate. Since I₀ is a constant:

[tex]\displaystyle \frac{dI}{dt} = I_0\left(\frac{d}{dt}\left[ e^{-kt}\right]\right)[/tex]

Using the chain rule:

[tex]\displaystyle \frac{dI}{dt} = I_0\left(-ke^{-kt}\right) = -kI_0e^{-kt}[/tex]

We have:

[tex]\displaystyle \frac{dI}{dt}+kI=0[/tex]

Substitute:

[tex]\displaystyle \left(-kI_0e^{-kt}\right) + k\left(I_0e^{-kt}\right) = 0[/tex]

Distribute and simplify:

[tex]\displaystyle -kI_0e^{-kt} + kI_0e^{-kt} = 0 \stackrel{\checkmark}{=}0[/tex]

Hence proven.

Answer:

A

Step-by-step explanation:

Because it’s correct, and explains the property correctly

Answer:

See answers below

Step-by-step explanation:

Given the following functions:

r(x) = x - 6

s(x) = 2x²

r(s(x)) = r(2x²)

Replacing x with 2x² in r(x) will give;

r(2x²) = 2x² - 6

r(s(x)) = 2x² - 6

(r-s)(x) = r(x) - s(x)

(r-s)(x) = x - 6 - 2x²

Rearrange

(r-s)(x) = - 2x²+x-6

(r+s)(x) = r(x) + s(x)

(r-s)(x) = x - 6 + 2x²

Rearrange

(r-s)(x) = 2x²+x-6

Answer:

80 Seconds

I dont really want to type the whole thing out, just think about it again, or go to a tutor website, you should be able to get it, you have to use these, multiplication of three numbers, and multiplication and division by factorization of numbers.