Answer:
Step-by-step explanation:
The domain includes all the "allowed" x values. Looking at the graph, it appears to start a tiny tiny bit to the right of 0, so it doesn't include 0. It also does not go to the left of 0. Therefore, the domain of the graph is x > 0
lowkey need help with this.
9514 1404 393
Answer:
c = 14
no extraneous solutions
Step-by-step explanation:
You can subtract the right-side expression, combine fractions, and set the numerator to zero.
[tex]\dfrac{c-4}{c-2}-\left(\dfrac{c-2}{c+2}-\dfrac{1}{2-c}\right)=0\\\\\dfrac{c-4}{c-2}-\dfrac{1}{c-2}-\dfrac{c-2}{c+2}=0\\\\\dfrac{(c-5)(c+2)-(c-2)^2}{(c-2)(c+2)}=0\\\\\dfrac{(c^2-3c-10)-(c^2-4c +4)}{(c-2)(c+2)}=0\\\\\dfrac{c-14}{(c-2)(c+2)}=0\\\\\boxed{c=14}[/tex]
__
Check
(14 -4)/(14 -2) = (14 -2)/(14 +2) -1/(2 -14) . . . . substitute for c
10/12 = 12/16 -1/-12
5/6 = 3/4 +1/12 . . . . true
There is one solution (c=14) and it is a solution to the original equation. There are no extraneous solutions.
Calculus!
The volume of a substance, A, measured in cubic centimeters increases according to the exponential growth model dA/dt = 0.3A, where t is measured in hours. The volume of another substance, B, also measured in cubic centimeters increases at a constant rate of 1 cm^3 per hour according to the linear model dB/dt = 1. At t = 0, substance A has a volume A(0) = 3 and substance B has size B(0) = 5. At what time will both substances have the same volume?
Would it be correct to write the growth model of substance B as x + 5? And how could I write the growth model of substance A? Thank you in advance, and sorry for the poor formatting.
Answer:
The two substances will have the same volume after approximately 3.453 hours.
Step-by-step explanation:
The volume of substance A (measured in cubic centimeters) increases at a rate represented by the equation:
[tex]\displaystyle \frac{dA}{dt} = 0.3 A[/tex]
Where t is measured in hours.
And substance B is represented by the equation:
[tex]\displaystyle \frac{dB}{dt} = 1[/tex]
We are also given that at t = 0, A(0) = 3 and B(0) = 5.
And we want to find the time(s) t for which both A and B will have the same volume.
You are correct in that B(t) is indeed t + 5. The trick here is to multiply both sides by dt. This yields:
[tex]\displaystyle dB = 1 dt[/tex]
Now, we can take the integral of both sides:
[tex]\displaystyle \int 1 \, dB = \int 1 \, dt[/tex]
Integrate. Remember the constant of integration!
[tex]\displaystyle B(t) = t + C[/tex]
Since B(0) = 5:
[tex]\displaystyle B(0) = 5 = (0) + C \Rightarrow C = 5[/tex]
Hence:
[tex]B(t) = t + 5[/tex]
We can apply the same method to substance A. This yields:
[tex]\displaystyle dA = 0.3A \, dt[/tex]
We will have to divide both sides by A:
[tex]\displaystyle \frac{1}{A}\, dA = 0.3\, dt[/tex]
Now, we can take the integral of both sides:
[tex]\displaystyle \int \frac{1}{A} \, dA = \int 0.3\, dt[/tex]
Integrate:
[tex]\displaystyle \ln|A| = 0.3 t + C[/tex]
Raise both sides to e:
[tex]\displaystyle e^{\ln |A|} = e^{0.3t + C}[/tex]
Simplify:
[tex]\displaystyle |A| = e^{0.3t} \cdot e^C = Ce^{0.3t}[/tex]
Note that since C is an arbitrary constant, e raised to C will also be an arbitrary constant.
By definition:
[tex]\displaystyle A(t) = \pm C e^{0.3t} = Ce^{0.3t}[/tex]
Since A(0) = 3:
[tex]\displaystyle A(0) = 3 = Ce^{0.3(0)} \Rightarrow C = 3[/tex]
Therefore, the growth model of substance A is:
[tex]A(t) = 3e^{0.3t}[/tex]
To find the time(s) for which both substances will have the same volume, we can set the two functions equal to each other:
[tex]\displaystyle A(t) = B(t)[/tex]
Substitute:
[tex]\displaystyle 3e^{0.3t} = t + 5[/tex]
Using a graphing calculator, we can see that the intersect twice: at t ≈ -4.131 and again at t ≈ 3.453.
Since time cannot be negative, we can ignore the first solution.
In conclusion, the two substances will have the same volume after approximately 3.453 hours.
There were 642 students enrolled in a freshman-level chemistry class. By the end of the semester, the number of students who passed was 5 times the number of students who failed. Find the number of students who passed and the number who failed.
Answer:
535 students passed and 107 students failed
Step-by-step explanation:
Create a system of equations where p is the number of students who passed and f is the number of students who failed:
p + f = 642
p = 5f
Solve by substitution by plugging in 5f as p into the first equation, then solving for f:
p + f = 642
5f + f = 642
6f = 642
f = 107
So, 107 students failed.
Find how many students passed by multiplying this by 5:
107(5)
= 535
535 students passed and 107 students failed.
What is the complete factorization of What is the complete factorization of 5x2 − 11x − 12?
Answer:
(x-3)(5x+4)
x=3 x=-4/5
Answer:
(5x + 4)(x - 3)
Step-by-step explanation:
Hello!
Factor:
5x² - 11x - 12Think: What two numbers add up to -11 but multiply to (5)(-12)?
Answer: -15 and 4
Continue:
5x² - 11x - 125x² - 15x + 4x - 12 Expand with the values we found5x(x - 3) + 4(x - 3) Factor by grouping(5x + 4)(x - 3)The factored expression is (5x + 4)(x - 3)
Which statement is true about the polynomial
–10m4n3 + 8m2n6 + 3m4n3 – 2m2n6 – 6m2n6 after it has been fully simplified?
It is a monomial with a degree of 4.
It is a monomial with a degree of 7.
It is a binomial with a degree of 6.
It is a binomial with a degree of 8.
Answer:
–10m4n3 + 8m2n6 + 3m4n3 – 2m2n6 – 6m2n6 = -7m4n3
⇒It is a monomial with a degree of 7 is correct
Step-by-step explanation:
maths class 9
Multiply: 4√12 2√12
Answer:
[tex]4 \sqrt{122} \sqrt{12} \\ (4 \times 2) \times ( \sqrt{12} \times \sqrt{12} ) \\ (4 \times 2) \times 12 \\ 8 \times 12 \\ 96[/tex]
What is the measure of JK?
which equation represent this relation
Answer:
hello,
answer A c=n+2
Step-by-step explanation:
if n=0 then c=2
if n=2 then c=4
slope=m=(4-2)/(2-0) =2/2=1
c-2=1*(n-0)
c=n+2
Find the values of the missing sides. You must use exact answers! PLEASE HURRY AND HELP
Answer:
x=4sqrt3 a=4 b=3 ,y=8sqrt3 c=8 d=3
Step-by-step explanation:
because this is a 30-60-90 triangle, it is easy to find the side lengths. the longer leg is sqrt(3) times the shorter leg so x= 12/sqrt(3) or 4sqrt(3). the hypotenuse is 2 times the shorter leg so y= 8sqrt(3)
what is -3/5 as a decimal
Answer:
-0.6
Step-by-step explanation:
Answer:
⅗ as a decimal is -0.6
Hope it's right if not then sorry, have a great day:)Which of the following has all the justifications Kelsey used to solve this equation?
(9th grade Algerbra 1)
If 12(x - a)(x - b) = 12x² - 7x - 12 , then ab =
Answer choices :
1
-1
7
12
-12
Answer: -1
Step-by-step explanation:
12x^2-7x-12 = (4x+3)(3x-4)
4x+3=0. X = -3/4
3x-4=0. X = 4/3
(-3/4) (4/3) = -1
Deion is saving up to buy a new phone. He already has $95 and can save an additional $7 per week using money from his after school job. How much total money would Deion have after 6 weeks of saving? Also, write an expression that represents the amount of money Deion would have saved in w weeks.
The expression that represents the amount of money Deion would have saved in w weeks is 95 + 7w and the total savings after 6 weeks will be $137.
What is an expression?A statement expressing the equality of two mathematical expressions is known as an equation.
A mixture of variables, numbers, addition, subtraction, multiplication, and division are called expressions.
An expression is a mathematical proof of the equality of two mathematical expressions.
As per the given,
Initial fixed money = $95
Per week saving $7/week
Total money = fixed money + money in w weeks.
⇒ 95 + 7w
For 6 weeks, w = 6
⇒ 95 + 7× 6 = $137.
Hence "The expression that represents the amount of money Deion would have saved in w weeks is 95 + 7w and the total savings after 6 weeks will be $137".
To learn more about expression,
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Find the value of x and y in the following figure
Step-by-step explanation:
y+80+70=180
y+150=180
y=30
Now you can, easily find x
The side measurement of the wall of the Green House is 9m. Find the cost of the glass required for the walls of the Green House, if the cost of 1m2 glass is AED 12.
Answer:
AED 972
Step-by-step explanation:
Area of the wall = 9² = 81 m²
each m² costs AED 12
so 81 m² will cost 12×81 = AED 972
a random number generator is used to model the patters of animals in the wild. this type of study is called
Answer:
This type of study is called a simulation
Step-by-step explanation:
what's the median of -13.78, -3.01, -2.41, -0.28, 0.66, 0.67, 1.05, 1.39, 2.03, 2.2, 2.64, 4.02
x and y are integers and 0 < x < y.
Write down two sets of values for x and y such that 6 = /3x+2y.
Answer:
x = 1
y=1.5
Step-by-step explanation:
3*1+2*1.5=6
The values of x and y in equation 6=3x+2y is for x is 1 and for y is 1.5.
We have given that,
x and y are integers and 0 < x < y.
6 = /3x+2y.
x=1 then
What is inequality?A statement of an order relationship greater than, greater than or equal to, less than, or less than or equal to between two numbers or algebraic expressions.
6=3+2y
6-3=2y
3/2=y
y=1.5
3*1+2*1.5=6
Therefore we get the values of x and y is for x is 1 and for y is 1.5.
To learn more about the values visit:
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Find the sin P rounded to the nearest hundredth
Answer:
SOH-CAH-TOA
[tex]\sin \left(x\right)=\frac{6}{\sqrt{49+36}}[/tex] = 40.60°
SOH = SIN = OPP/HYP
SIN(Θ) = 6/[tex]\sqrt{49+36 }[/tex]
Step-by-step explanation:
help me with this two I don't understand
Step-by-step explanation:
5.
[tex](5 + 4 \sqrt{7} ){x}^{2} + (4 - 2 \sqrt{7} ) x- 1 = 0[/tex]
Simplify both radicals.
[tex](5 + \sqrt{112) {x}^{2} } + (4 - \sqrt{28} )x - 1 = 0[/tex]
Apply Quadratic Formula
First. find the discramnint.
[tex](4 - \sqrt{28} ) {}^{2} - 4(5 + \sqrt{112} )( - 1) = 64[/tex]
Now find the divisor 2a.
[tex]2(5 + \sqrt{112} ) = 10 + 8 \sqrt{7} [/tex]
Then,take the square root of the discrimant.
[tex] \sqrt{64} = 8[/tex]
Finally, add -b.
[tex] - (4 + 2 \sqrt{7} )[/tex]
So our possible root is
[tex] - (4 + 2 \sqrt{7} ) + \frac{8}{10 + 8 \sqrt{7} } [/tex]
Which simplified gives us
[tex] \frac{ 4 + 2 \sqrt{7} }{10 + 8 \sqrt{7} } [/tex]
Rationalize the denominator.
[tex] \frac{4 + 2 \sqrt{7} }{10 + 8 \sqrt{7} } \times \frac{10 - 8 \sqrt{7} }{10 - 8 \sqrt{7} } = \frac{ - 72 - 12 \sqrt{7} }{ - 348} [/tex]
Which simplified gives us
[tex] \frac{6 + \sqrt{7} }{29} [/tex].
6. The answer is 2.
9514 1404 393
Answer:
5. x = (6 +√7)/29; a=6, b=1, c=29
6. x = 2
Step-by-step explanation:
5.The quadratic formula can be used, where a=(5+4√7), b=(4-2√7), c=-1.
[tex]x=\dfrac{-b+\sqrt{b^2-4ac}}{2a}=\dfrac{-(4-2\sqrt{7})+\sqrt{(4-2\sqrt{7})^2-4(5+4\sqrt{7}})(-1)}{2(5+4\sqrt{7})}\\\\=\dfrac{-4+2\sqrt{7}+\sqrt{16-16\sqrt{7}+28+20+16\sqrt{7}}}{10+8\sqrt{7}}=\dfrac{4+2\sqrt{7}}{2(5+4\sqrt{7})}\\\\=\dfrac{(2+\sqrt{7})(5-4\sqrt{7})}{(5+4\sqrt{7})(5-4\sqrt{7})}=\dfrac{10-3\sqrt{7}-28}{25-112}=\boxed{\dfrac{6+\sqrt{7}}{29}}[/tex]
__
6.Use the substitution z=3^x to put the equation in the form ...
z² -3z -54 = 0
(z -9)(z +6) = 0 . . . . . factor
z = 9 or -6 . . . . . . . . value of z that make the factors zero
Only the positive solution is useful, since 3^x cannot be negative.
z = 9 = 3^2 = 3^x . . . . use the value of z to find x
x = 2
Factorize :solve no g and h
Answer:
Hello,
do you mean factorise but not solve ?
Just one formula:
[tex]\boxed{a^2-b^2=(a-b)(a+b)}[/tex]
Step-by-step explanation:
[tex]g)\\\\16x^3y-81xy^5\\\\=xy(16x^2-81y^4)\\\\=xy(4x^2+9y^2)(4x^2-9y^2)\\\\=xy(2x-3y)(2x+3)(4x^2+9y^2)\\\\\\\\h)\\\\x^8-y^8\\\\=(x^4+y^4)(x^4-y^4)\\\\=(x^4+y^4)(x^2+y^2)(x^2-y^2)\\\\=(x-y)(x+y)(x^2+y^2)(x^4+y^4)\\[/tex]
Answer:
here only one formula to use in both question
a^2+b^2= (a+b)(a-b)
Tuto
Combine any like terms in the expression. If there are no like terms, rewrite the expression.
8r + 9pg - pg - pq
Answer:
8r+8pg-pq
Step-by-step explanation:
The subtractable pg cancels out one of the 9 pg's. So 9 pg-1 pg= 8 pg
Hope this helps!
pls help me asap !!!!
Answer:
9--7
Step-by-step explanation:
GIVING BRAINLIEST TO CORRECT ANSWERS
Answer:
b is the correct answer
Step-by-step explanation:
If m2 DOC = 44º and m2 COB = 80°,
find the measure of the indicated arc
in circle o.
mCB = [?]°
Answer:
80°
Step-by-step explanation:
m<COB = 80°, it's the central angle for arc CB,
so mCB = 80°
Determine the measure of the interior angle at vertex F
Answer:
72
Step-by-step explanation:
The interior angles of a 6 sided figure add to (n-2) * 180
where n is the number of sides
(6-2) *180
4*180
720
2x+4x+4x+4x+4x+2x = 720
20x = 720
Divide by 20
20x/20 = 720/20
x =36
We want <F
<F = 2x = 2*36 = 72
Find the value of x. PLEASE HELP ASAP!
A.4
B. 16
С. 5
D. 12
Answer: x>12
so i think x is 16.
help me please its confusing pleasee
Answer:
a) -8x³+x²+6x
d) 16x²-9
Step-by-step explanation:
a) -2x(x+4x²)+3(x²+2x)
Expand each bracket:
-2x(x+4x²)
As the -2x is on the outside of the bracket, you have to times everything inside the bracket by -2x.
-2x times x equals -2x²
-2x times 4x² equals -8x³
Then we expand the other bracket:
3(x²+2x)
3 times x² equals 3x²
3 times 2x equals 6x
We then put all of it together:
-2x²-8x³+3x²+6x
Collect like terms:
-8x³+x²+6x
b) (4x-3)(4x+3)
We will use the FOIL method:
F-First
O-outer
I-Inner
L-Last
Times the first two terms in each bracket:
4x times 4x equals 16x²
Times the outer terms in the bracket:
4x times 3 equals 12x
Times the inside terms in the bracket:
-3 times 4x equals -12x
Times the last terms in the bracket:
-3 times 3 equals -9
Put it together:
16x²+12x-12x-9
The 12x and -12x cancel out to leave 16x²-9
Hope this helps :)
which exponential expression is equivalent to
Answer:
B
Step-by-step explanation:
(y^(4))^(1/5)=y^(4/5)
In ATUV, Y is the centroid. If TY = 30, what is YW?
A.15
B.45
C.30
D.60
We know at centroid medians bisect each other in the ratio 2:1.
TY=30Let YW be x[tex]\\ \sf\longmapsto TY=2x[/tex]
[tex]\\ \sf\longmapsto 2x=30[/tex]
[tex]\\ \sf\longmapsto x=\dfrac{30}{2}[/tex]
[tex]\\ \sf\longmapsto x=15[/tex]
Answer:
A
Step-by-step explanation:
On the median TW the distance from the vertex to the centroid is twice the distance from the centroid to the midpoint , then
YW = [tex]\frac{1}{2}[/tex] × TY = [tex]\frac{1}{2}[/tex] × 30 = 15