The fraction model below shows the steps that a student performed to find a quotient. Which statement best interprets the quotient? A: There are 5 1/5 five-sixths in 4 1/3. B: There 6 1/6 five sixths-in 4 1/3. C: There are 5 1/5 four and one-thirds in 5/6. D: There are 6 1/6 four and one-thirds in 5/6.

Answer:

AB

Step-by-step explanation:

For the multiplication of two matrices to be defined then the number of columns of the first matrix must be equal to the number of rows of the second matrix. For example, 2*3 and 3*2 matrices can be multiplied since the number of columns of the first matrix must be equal to the number of rows of the second matrix.

Matrix A = 2*2

Matrix B = 2*3

Matrix C = 3*3

Matrix D = 1 * 3

From the matrices given, we can see that the matrices that can be multiplied together are AB and BC since the number of columns of the first matrix must be equal to the number of rows of the second matrix. Hence the correct option is AB

Answer:

Not very sure what you mean,

But in the provided set, 8 is the greatest number, and 1 is the smallest.

Hope this helps!!

Answer:

1)17

2)33

3)9

4)27

5)1252

6)50

Step-by-step explanation:

That's a question about quadratic function.

Any quadratic function can be represented by the following form:

[tex]\boxed{f(x)=ax^2+bx+c}[/tex]

Example:

[tex]f(x)= -3x^2-9x+57[/tex] is a function where [tex]a=-3[/tex], [tex]b=-9[/tex] and [tex]c=57[/tex].

Okay, in our problem, we need to find the value of x when [tex]f(x)=0[/tex]. That's mean that the result of our function is equal to zero. Therefore, we have the quadratic equation below:

[tex]x^2+4x-5=0[/tex]

To solve a quadratic equation, we use the Bhaskara's formula. Do you remember the value of a, b and c? They going to be important right now. This is the Bhaskara's formula:

[tex]\boxed{x=\frac{-b\pm \sqrt{b^2-4ac} }{2a} }[/tex]

So, let's see the values of a, b and c in our equation and apply them in the Bhaskara's formula:

In [tex]x^2+4x-5=0[/tex] equation, [tex]a=1[/tex], [tex]b=4[/tex] and [tex]c=-5[/tex]. Let's replace those values:

[tex]x=\frac{-b\pm \sqrt{b^2-4ac} }{2a}[/tex]

[tex]x=\frac{-4\pm \sqrt{4^2-4\times1\times(-5)} }{2\cdot1}[/tex]

[tex]x=\frac{-4\pm \sqrt{16-(-20)} }{2}[/tex]

[tex]x=\frac{-4\pm \sqrt{16 + 20)} }{2}[/tex]

[tex]x=\frac{-4\pm \sqrt{36} }{2}[/tex]

[tex]x=\frac{-4\pm 6 }{2}[/tex]

From now, we have two possibilities:

To add:

[tex]x_1 = \frac{-4+6}{2} \\x_1=\frac{2}{2} \\x_1=1[/tex]

To subtract:

[tex]x_2=\frac{-4-6}{2} \\x_2=\frac{-10}{2} \\x_2=-5[/tex]

Therefore, the result of our problem is: [tex]x_1 = 1[/tex] and [tex]x_2=-5[/tex].

I hope I've helped. ^^

Enjoy your studies.  \o/

y + z + r + x = 360

2x + 3x + 4x + x = 360

10x = 360

x = 360/10

x = 36

Now

x = 36

y = 72

z = 108

r = 144

Answered by Gauthmath must click thanks and mark brainliest

Answer:

$343

step by step explanation: interest=PRT/100

:I=700×7×7/100

:I=$343.

Given:

Principal, P = $700

Rate of interest, R = 7% = 0.07

Time period, T = 7 months (it is considered as a monthly investment)

∴ Simple Interest, SI = PRT

SI = 700 × 0.07 × 7

SI = $343

Straightforward Simple Interest is the strategy for working out the premium sum for a specific chief measure of cash at some pace of revenue. For instance, when an individual takes credit of Rs. 5000, at a pace of 10 p.a. for a very long time, the individual's advantage for quite some time will be S.I. on the acquired cash.

Straightforward recipes generally start with an equivalent sign (=), trailed by constants that are numeric qualities and computation administrators like in addition to (+), short (- ), asterisk(*), or forward cut (/) signs.

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9514 1404 393

Answer:

  246.6 in²

Step-by-step explanation:

The surface area is the sum of the base area and the areas of the four triangular faces. The relevant area formulas are ...

  A = s² . . . . . . area of a square of side length s

  A = 1/2bh . . . . area of a triangle with base b and height h

Then the surface area of this figure is ...

  A = (9 in)² + 4×(1/2)(9 in)(9.2 in) = 81 in² +165.6 in² = 246.6 in²

Answer:

Reflection

Step-by-step explanation:

It is the opposite of the first,...

Answer:

sin A = 4/5

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

sin A = opp / hyp

sin A = 24/ 30

Dividing the top and bottom by 6

sin A = 4/5

sinØ=Perpendicular/Hypotenuse

13x - 4[x + (3 - x)] =

= 13x - 4(x + 3 - x) =

= 13x - 4 · 3 = 13x - 12

C.

Answer:

13x -12

Step-by-step explanation:

13 x - 4[ x + (3 - x )].

Combine like terms inside the brackets

13 x - 4[ 3 -0x]

13x - 4[3]

Multiply

13x -12

let the number be x

ATQ

[tex]\\ \sf\longmapsto 5x+2x+2=16[/tex]

[tex]\\ \sf\longmapsto (5+2)x+2=16[/tex]

[tex]\\ \sf\longmapsto 7x+2=16[/tex]

[tex]\\ \sf\longmapsto 7x=16-2[/tex]

[tex]\\ \sf\longmapsto 7x=14[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{14}{7}[/tex]

[tex]\\ \sf\longmapsto x=2[/tex]

Answer:

The number is

2

Explanation:

Let

n

represent the number.

Translating the given statement into algebraic notation, we have

XXX

5

n

+

2

n

+

2

=

16

Therefore

XXX

7

n

+

2

=

16

XXX

7

n

=

14

XXX

n

=

2

answered by: Alan P.

use x^2 when x=0 because the restriction for it is "use x if x is less than or equal to 1"

when x = 0, (0)^2 will make f(x) = 0

the graph of f(x) will just be a dot at 0

Let a, b, and c be vectors each starting at the origin and terminating at the points (x, x + 1), (x + 2, x + 3), and (x + 3, 2x + 4), respectively.

Then the vectors a - b, a - c, and b - c are vectors that point in directions parallel to each of the legs formed by the triangle with these points as its vertices.

If this triangle is to contain a right angle, then exactly one of these pairs of vectors must be orthogonal. In other words, one of the following must be true:

(a - b) • (a - c) = 0

or

(a - b) • (b - c) = 0

or

(a - c) • (b - c) = 0

We have

a - b = (x, x + 1) - (x + 2, x + 3) = (-2, -2)

a - c = (x, x + 1) - (x + 3, 2x + 4) = (-3, -x - 3)

b - c = (x + 2, x + 3) - (x + 3, 2x + 4) = (-1, -x - 1)

Case 1: If (a - b) • (a - c) = 0, then

(-2, -2) • (-3, -x - 3) = (-2)×(-3) + (-2)×(-x - 3) = 2x + 12 = 0   ==>   x = -6

which would make a - c = (-3, 3) and b - c = (-1, 5), and their dot product is not zero. Then the triangles vertices are at the points (-6, -5), (-4, -3), and (-3, -8).

Case 2: If (a - b) • (b - c) = 0, then

(-2, -2) • (-1, -x - 1) = (-2)×(-1) + (-2)×(-x - 1) = 2x + 4 = 0   ==>   x = -2

which would make a - c = (-3, -1) and b = (-1, 1), and their dot product is also not zero. The vertices are the points (-2, -1), (0, 1), and (1, 0).

Case 3: If (a - c) • (b - c) = 0, then

(-3, -x - 3) • (-1, -x - 1) = (-3)×(-1) + (-x - 3)×(-x - 1) = x ² + 4x + 6 = 0

but the solutions to x here are non-real, so we throw out this case.

So there are two possible values of x that make a right triangle, x = -6 and x = -2.

Answer:

Quadratic

Step-by-step explanation:

Answer:

Linear

Step-by-step explanation:

for every one unit increase in x, there is a 3 unit increase in y

The slope of the plot line would be 3

The y intercept of the plot line would be -1

y = 3x - 1

Step-by-step explanation:

In right angled triangle ABC,

Taking alpha as reference angle,

By pythagoras theorem,

p=BC,h=AB,b=AC

Taking thita as reference angle,

p=AC,h=AB,b=BC

Keep smiling and hope u are satisfied with my answer.Have a good day :)

Answer:

Megan’s at 2.5 inches per week

Answer:

Slope = 5

Step-by-step explanation:

To find the slope of a line perpendicular to a given line, take the opposite reciprocal of the given line's slope.

Ex. -1/5 ⇒ 5

Opposite = opposite sign (- ⇒ +)

Reciprocal = numerator and denominator flipped (1/5 ⇒ 5/1 = 5)

9514 1404 393

Answer:

  y < 3x -4

Step-by-step explanation:

The boundary line has a slope (rise/run) of 3/1 = 3. It has a y-intercept of -4. The shaded area is below the line and the solution does not include the line. The relevant inequality can be written ...

  y < 3x -4

Answer:

a. 1.44

Step-by-step explanation:

We are interested in determining whether or not the proportion of the population in favor of Candidate A is significantly more than 40%.

At the null hypothesis, it is tested if the proportion is of at most 40%, that is:

[tex]H_0: p \leq 0.4[/tex]

At the alternative hypothesis, it is tested if the proportion is of more than 40%, that is:

[tex]H_1: p > 0.4[/tex]

The test statistic is:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.

0.4 is tested at the null hypothesis:

This means that [tex]p = 0.4, \sigma = \sqrt{0.4*0.6}[/tex]

A random sample of 200 people was taken. 90 of the people in the sample favored Candidate A.

This means that:

[tex]n = 200, X = \frac{90}{200} = 0.45[/tex]

Value of the test statistic:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

[tex]z = \frac{0.45 - 0.4}{\frac{\sqrt{0.4*0.6}}{\sqrt{200}}}[/tex]

[tex]z = 1.44[/tex]

Thus the correct answer is given by option a.

Let it be x

Using basic proportionality theorem

[tex]\\ \sf\longmapsto \dfrac{x}{10}=\dfrac{14}{7}[/tex]

[tex]\\ \sf\longmapsto \dfrac{x}{10}=2[/tex]

[tex]\\ \sf\longmapsto x=10(2)[/tex]

[tex]\\ \sf\longmapsto x=20[/tex]

There are 135 ways someone can order a meal consisting of one choice from each category.

To find the total number of ways someone can order a meal consisting of one choice from each category, we need to multiply the number of options in each category:

Number of options for the main course = 5

Number of options for the side dish = 3

Number of options for the dessert = 3

Number of options for the beverage = 3

Using the multiplication principle, the total number of ways to order a meal is:

5 x 3 x 3 x 3 = 135

Therefore, there are 135 ways someone can order a meal consisting of one choice from each category.

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We have to convert it to m/s

[tex]\boxed{\sf 1km/h=\dfrac{5}{18}m/s}[/tex]

[tex]\\ \sf\longmapsto 40km/h[/tex]

[tex]\\ \sf\longmapsto 40\times \dfrac{5}{18}[/tex]

[tex]\\ \sf\longmapsto \dfrac{200}{18}[/tex]

[tex]\\ \sf\longmapsto 11.1m/s[/tex]

km/h > m/s

when converting km/h to m/s all you need to do is divide by 3.6

and vise versa when converting m/s to km/h multiply by 3.6

so therefore,

40km/h > m/s

= 40 / 3.6

= 11.11 m/s (4sf)

Answer:

3.75 hours

Step-by-step explanation:

d = rt

where d is the distance, r is the rate and t is the time

45 = 12 t

Divide each side by 12

45/12 = t

3.75 hours = t

41.9 mi

Step-by-step explanation:

First, we convert the angle from degree measure to radian measure:

[tex]\theta = 240°×\left(\dfrac{\pi}{180°}\right)= \dfrac{4\pi}{3}\:\text{rad}[/tex]

Using the definition of an arc length [tex]s[/tex]

[tex]s = r\theta[/tex]

[tex]\:\:\:\:=(10\:\text{mi})\left(\dfrac{4\pi}{3}\:\text{rad}\right)[/tex]

[tex]\:\:\:\:= 41.9\:\text{mi}[/tex]

In this, question the equation is missing that's why in the solution we define the equation and its complete solution:

Let the given equation:

[tex]\bold{\hat{h}=17.6+3.8x_1-2.3x_2+7.6x_3+2.7x_4}[/tex]

[tex]\bold{b1 = 3.8}[/tex] units expect changes in the y for each 1 unit change in [tex]\bold{x_1}[/tex]

[tex]\bold{b2 = -2.3 }[/tex] units expect changes in the y for each 1 unit change in  [tex]\bold{x_2}[/tex]

[tex]\bold{b3 = 7.6 }[/tex] units expect changes in the y for each 1 unit change in [tex]\bold{x_3}[/tex]

[tex]\bold{b4 = 2.7}[/tex] units expect changes in the y for each 1 unit change in [tex]\bold{x_4}[/tex]

Calculating the estimated value of the y when:

[tex]\to \bold{x_1 = 10}\\\\ \to \bold{x_2 = 5}\\\\\to \bold{x_3 = 1}\\\\\to \bold{x_4 = 2}\\\\[/tex]

Put the value into the above-given equation:

[tex]\to \bold{17.6 + 3.8(10) - 2.3(5) + 7.6(1) + 2.7(2)} \\\\\to \bold{17.6 + 38 - 11.5 + 7.6 + 5.4} \\\\\to \bold{17.6 + 38 - 11.5 + 7.6 + 5.4} \\\\\to \bold{68.6-11.5}\\\\\to \bold{57.1}[/tex]

So, the final answer is "57.1".  

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Answer:

True

Step-by-step explanation:

The first derivative tells you the slope of the graph at a specific point. If f'(c) =0, then that means that at f(c), the slope of the graph is 0. It is neither going up nor down

The second derivative tells you the slope of the slope of the graph. If f''(c) < 0, this means that the slope is decreasing. This means that going from the left to f(c), the slope is greater than the slope at f(c), and going from f(c) to the right, the slope is less than the slope at f(c).

Therefore, since the slope at f(c) is 0, the slope is positive to the left of f(c) and negative to the right of f(c). This means that the graph is going up until it hits f(c) and then goes down. Because f(c) is greater than the values to the left of it (because it is going up until it hits f(c)) and the values to the right of it (because it is going down past f(c)), f(c) is a local maximum

Answer:

B.17

Step-by-step explanation:

B.17

B.17

B.17

B.17