The force of gravitation between two cricket balls is extremly small but that between a cricket ball and earth is extremly is large?

By the work-energy theorem, the total work done on the mass as it swings is

W = ∆K = 1/2 (18 kg) (17 m/s)² = 153 J

No work is done by the tension in the string, since it's directed perpendicular to the mass at every point in the arc. Similarly, the component of the mass's weight mg pointing perpendicular to the arc also performs no work.

If we ignore friction/drag for the moment, the only remaining force is the parallel component of weight, which performs mgh = (176.4 N) h of work, where h is the vertical distance between points A and B.

Now, if w is the amount of work done by friction/air resistance, then

(176.4 N) h - w = 153 J

If you know the starting height h, then you can solve for w.

Answer:

v = 17.68 m/s

Explanation:

Given that,

While standing at a crosswalk, you hear a frequency of 510 Hz from an approaching police car.

After the police car passes, its frequency is 460Hz.

We need to find the speed of the police car.

The formula is as follows :

[tex]v=\dfrac{v_o(f-f')}{f+f'}[/tex]

Put all the values,

[tex]v=\dfrac{343(510-460)}{510+460}\\\\=17.68\ m/s[/tex]

So, the speed of the police car is 17.68 m/s.

Explanation:

The kinetic molecular theory of matter states that: ... The average amount of empty space between molecules gets progressively larger as a sample of matter moves from the solid to the liquid and gas phases. There are attractive forces between atoms/molecules, and these become stronger as the particles move closer together.

Answer:

Velocity and force consists of two vectors as they both have magnitude and direction

Pair of physical quantities consists of two vectors are velocity and force.

"The seven elemental physical quantities are mass, time, temperature, mole, length, luminosity, and electrical charge. "Some derived physical quantities are velocity, heat, density, pressure, and momentum. Extensive physical quantities depend on the amount of substance or the size of the object.

"Velocity is the speed at which something moves in a particular direction. For example as the speed of a car travelling north on a highway, or the speed a rocket travels after launching. "The scalar means the absolute value magnitude of the velocity vector is always be the speed of the motion.

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41.23

v(B,E)=40 GOING EAST

V(R,E)=10 COMING DOWN

then 41.23

Answer:

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Explanation:

Answer:

The weight of the probe is 50 Newtons

Explanation:

Newtons second law states that F = ma

Given the mass of 25kg, and the acceleration of 2m/s^2, we can substitute both values into the equation to find the weight force.

[tex]F = ma[/tex]

[tex]F = 25 * 2[/tex]

[tex]F = 50N[/tex]

The weight of the probe is 50 Newtons

Answer:

A flower emits only visible light

A flower reflects much of the light that hits it

Answer:

It increases twice the original

Answer:

300 m/s

Explanation:

The difference in time between the two bangs is 1 s.

Thus;

t2 - t1 = 1

We know that distance/time = speed.

Thus;

d2/v - d1/v = 1

Multiply through by v to get;

d2 - d1 = v

Where v is speed of sound in air.

d1 = 350 m

d2 = (150 × 2) + 350 = 650 m

Thus;

v = d2 - d1 = 650 - 350 = 300 m/s

a. cool air warms as it mixes with denser air

Explanation:

c. warm air is displaced by cooler denser air

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Answer:

[tex]\triangle I=8.60*10^{-4}m[/tex]

Explanation:

From the question we are told that:

Diameter [tex]d=1.27cm[/tex]

Length [tex]l=5.75m[/tex]

Diameter of aluminum column [tex]d_a=16.14cm[/tex]

Length of aluminum column [tex]l_a=3.25m[/tex]

Load Force [tex]F=8500N[/tex]

Generally the equation for Young modulus is mathematically given by

[tex]\gamma=\frac{FL}{A \triangle L}[/tex]

Given the The load force

[tex]F=\frac{Y_aA_a\triangle I}{L_a}+\frac{YA \triangle I}{L}[/tex]

[tex]\triangle I=\frac{F}{\frac{Y_aA_a}{L_a}}+\frac{YA}{L}[/tex]

[tex]\triangle I=\frac{8500N}{ \frac{7*10^{10} \pi (0.1624^2-0.1614^2)}{4*3.15}+ \frac{20*10^10 \pi (0.0127^2)}{4(5.75)}}[/tex]

[tex]\triangle I=8.60*10^{-4}m[/tex]

Answer:

Explanation:

This is a torque problem where balance is achieved when the sum of the torques equal 0. The equation for torque is

[tex]\tau=F*r[/tex] where F is the force in Newtons that is perpendicular to the lever arm, and r is the length of the lever arm in meters.

450(2) = 350r and

[tex]\frac{450(2)}{350}=r[/tex] so

r = 2.6 m

Answer: 8000N

Explanation: since it is frictionless that means it has 100% efficiency therefore the mechanical advantage is 1 meaning the load equals to the effort

Answer:

• riding on a Ferris wheel whose entrance and exit are the same

• walking around the block, starting from and ending at the same house

• running exactly one lap around a racetrack

Explanation:

Displacement simply means the.change in position of an object. In a situation whereby the initial and final position are thesame, the displacement will be zero.

The statements that describe a situation with a displacement of zero include:

• riding on a Ferris wheel whose entrance and exit are the same

• walking around the block, starting from and ending at the same house

• running exactly one lap around a racetrack

Answer:

• riding on a Ferris wheel whose entrance and exit are the same

• walking around the block, starting from and ending at the same house

• running exactly one lap around a racetrack

Explanation:

B,C,E

Answer:

The total power they will consume in series is approximately 2.257 W

Explanation:

The connection arrangement of the headlight and the engine starter = Parallel to the battery

The voltage of the battery, V = 12.0 V

The power at which the headlight operates in parallel, [tex]P_{headlight}[/tex] = 38 W

The power at which the kick starter operates in parallel, [tex]P_{kick \ starter}[/tex] = 2.40 kW

We have;

P = V²/R

Where;

R = The resistance

V = The voltage = 12 V (The voltage is the same in parallel circuit)

For the headlight, we have;

R₁ = V²/[tex]P_{headlight}[/tex]  = 12²/38 = 72/19

R₁ = 72/19 Ω

For the kick starter, we have;

R₂ = V²/[tex]P_{kick \ starter}[/tex] = 12²/2.4 = 60

R₂ = 60 Ω

When the headlight and kick starter are rewired to be in series, we have;

Total resistance, R = R₁ + R₂

Therefore;

R = ((72/19) + 60) Ω = (1212/19) Ω

The current flowing, I = V/R

∴ I = 12 V/(1212/19) Ω = (19/101) A

We note that power, P = I²R

In the series connection, we have;

[tex]P_{headlight}[/tex] = I² × R₁

∴ [tex]P_{headlight}[/tex] = ((19/101) A)² × 72/19 Ω = 1368/10201 W ≈ 0.134 W

The power at which the headlight operates in series, [tex]P_{headlight, S}[/tex] ≈ 0.134 W

[tex]P_{kick \ starter}[/tex] = ((19/101) A)² × 60 Ω = 21660/10201 W ≈ 2.123 W

The power at which the kick starter operates in series, [tex]P_{kick \ starter, S}[/tex] ≈ 2.123 W

The total power they will consume, [tex]P_{Total}[/tex] = [tex]P_{headlight, S}[/tex] + [tex]P_{kick \ starter, S}[/tex]

Therefore;

[tex]P_{Total}[/tex] ≈ 0.134 W + 2.123 W = 2.257 W

Answer:

Seafloor spreading is a geological process that occurs in the ocean. It is occurs due to divergent plate tectonics. As, lithospheric plates of the ocean moves away from each other, the heat from the mantle liberates as convection currents that decreases the density of the crust. The less dense material rises, resulting the elevation of the seafloor, which is called as sea floor spreading.

Explanation:

Answer:

6.9 m/s

Explanation:

1000m = 1km

3600s = 1hr

25000m/3600s

6.9m/s

Answer:

v_f = 30 m/s

Explanation:

v_f = v_I + a*t

v_f = 0m/s + (9.81m/s²)*(3s)

v_f = 29.43m/s

v_f = 30 m/s

Since the object is being launched horizontally off the cliff the only vertical force acting on the ball is gravity which is an acceleration of 9.81m/s². So we have all the flowing information to use the the kinematic equation: v_f = v_I + a*t.

Answer:

D. Fats

Explanation:

they are the long term energy storing nutrient carbohydrates are a quick way for energy minerals dont contain any energy and neither do proteins

fats

Explanation:

it is nutrient kept in the body

Explanation:

The square meter is the SI-derived unit of area. It has a symbol m² (33A1 in Unicode). It is defined as the area of a square whose sides measure exactly one metre.

Answer:

ballance

i just took the quiz

Answer:

22%

Explanation:

55 - 45 = 10

10/45 simplifies to 2/9

2/9 = 0.22222... so 22.22% (rounded 22%)

Answer:

Explanation:

The formula for this, the easy one, is

[tex]N=N_0(\frac{1}{2})^{\frac{t}{H}[/tex] where No is the initial amount of the element, t is the time in years, and H is the half life. Filling in:

[tex]N=48.0(\frac{1}{2})^{\frac{49.2}{12.3}[/tex] and simplifying a bit:

[tex]N=48.0(.5)^4[/tex] and

N = 48.0(.0625) so

N = 3 mg left after 12.3 years

How many half-lifes is 49.2 years ?

(49.2 years) / (12.3 years per half-life)  =  4 half-lifes.

In 4 half-lifes, (1/2) · (1/2) · (1/2) · (1/2) of the original sample remains.

That's (1/2⁴) or (1/16) of the original.

(1/16) of 48.0 mg  =  3 mg .

=======================

Step-by-step:

== Start with 48 mg .

== After one half-life, 24 mg remains.

== Then, after the second half-life, 12 mg remains.

== Then, after the third half-life, 6 mg remains.

== Then, after the fourth half-life, 3 mg remains.

Answer:

The maximum height reached is 413.27 m.

Explanation:

How long will it take for a body to reach its maximum height, knowing that it was thrown, vertically upwards, with a velocity whose value was 90 m / s?

initial velocity , u = 90 m/s

gravity, g = 9.8 m/s^2

Let the maximum height is h.

At maximum height the velocity v = 0

Use third equation of motion

[tex]v^2 = u^2 - 2 gh\\\\0 = 90\times 90 - 2 \times 9.8 \times h\\\\h = 413.27 m[/tex]

Answer:

The hammer must be moving at a speed of approximately 4.082 meters per second.

Explanation:

According to the statement and based on Principle of Energy Conservation, change in gravitational potential energy experimented by the metal piece ([tex]U_{g,o}[/tex]), in joules, must be equal to 18.8 percent of the translational kinetic energy of the hammer ([tex]K_{h}[/tex]), in joules.

[tex]U_{g, o} = 0.188\cdot K_{h}[/tex] (1)

By definitions of gravitational potential and translational kinetic energies, we expand (1):

[tex]m_{o}\cdot g\cdot h = 0.188\cdot \left(\frac{1}{2}\cdot m_{h}\cdot v^{2}\right)[/tex] (2)

Where:

[tex]m_{o}[/tex] - Mass of the metal piece, in kilograms.

[tex]g[/tex] - Gravitational acceleration, in meters per square second.

[tex]h[/tex] - Distance travelled by the metal piece, in meters.

[tex]m_{h}[/tex] - Mass of the hammer, in kilograms.

[tex]v[/tex] - Initial speed of the hammer, in meters per second.

If we know that [tex]m_{o} = 0.408\,kg[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], [tex]h = 4.23\,m[/tex] and [tex]m_{h} = 10.8\,kg[/tex], then the initial speed of the hammer is:

[tex]m_{o}\cdot g\cdot h = 0.188\cdot \left(\frac{1}{2}\cdot m_{h}\cdot v^{2}\right)[/tex]

[tex]10.638\cdot m_{o}\cdot g \cdot h = m_{h}\cdot v^{2}[/tex]

[tex]v = 3.261\cdot \sqrt{\frac {m_{o}\cdot g \cdot h}{m_{h}}}[/tex]

[tex]v = 3.261\cdot \sqrt{\frac{(0.408\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (4.23\,m)}{10.8\,kg} }[/tex]

[tex]v \approx 4.082\,\frac{m}{s}[/tex]

The hammer must be moving at a speed of approximately 4.082 meters per second.