Answer:
Use calculation for the population standard deviation
Step-by-step explanation:
We are given that the data data set represents the ages of all 6 of Nancy's grandchildren
11,8,5,6,3,9
We have to determine which standard deviation would used for calculation of the given data set.
Sample standard deviation :If the data values represent the data collected from subset of population .Then the sample standard deviation should be used.
Population standard deviation:
If the data values represents the data collected from entire population, then population standard deviation should be used.
We can see that the given data collected from entire population.
Therefore, we would use calculation for population standard deviation of given data set.
Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 5?
Select one:
a. 420
4
20
b. 320
3
20
c. 520
5
20
d. 120
1
20
Answer:
4 / 20 = 1/5
Step-by-step explanation:
Given that:
Ticket numbering is from 1 - 20
Hence, total possible number of tickets : (1, 2, 3, 4, 5, 6, 7, 8,9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20)
Total possible outcomes = 20
Required outcome = multiples of 5 ; the multiples of 5 from the entire ticket numbers are : 5, 10, 15, 20
Required outcome = 4
P(multiple of 5) = Required outcome / Total possible outcomes
P(multiple of 5) = 4 / 20 = 1 / 5
At a store sales tax is charged at a rate of 2% on the cost price of an item . the sales tax on a dress which cost $180 is
Answer:
$3.60
Step-by-step explanation:
100% = 180
1% = 180/100 = $1.80
2% = 1%×2 = 1.8×2 = $3.60
1. S = 10 mm
V= S×S×S
=___×___×___
=____ mm3
Hi there!
»»————- ★ ————-««
I believe your answer is:
[tex]V=1000\text{mm}^3[/tex]
»»————- ★ ————-««
Here’s why:
⸻⸻⸻⸻
I am assuming by the infomation given that the figure is a cube.
⸻⸻⸻⸻
[tex]\boxed{\text{Finding the volume of the cube...}}\\\\S = 10mm; V= s^3\\--------------\\\rightarrow V = 10^3\\\\\rightarrow V = 10 * 10 * 10\\\\\rightarrow \boxed{V=1000\text{mm}^3}[/tex]
⸻⸻⸻⸻
»»————- ★ ————-««
Hope this helps you. I apologize if it’s incorrect.
4,3,5,9,12,17,...what is the next number?
Answer:
The next number is going to be 21
Answer:
19
Step-by-step explanation:
4 even number
3,5,7 odd numbers
14 even
17, 19, 21 even
Determine, without graphing, whether the given quadratic function has a maximum value or a minimum value and then find the value.
f(x)=6x^2+12x
Answer:
(-1, -6)
Step-by-step explanation:
This a term in this function is not negative, which would make it be flipped over the x-axis. Therefore this function takes the typical parabola shape, and it will have a minimum point.
To find the x-value of the minimum use the formula -b / 2a.
-12 / 2(6) = -1
Then plug in the x-value and find the y-value for this function
f(-1) = 6(-1)^2 + 12(-1) = -6
Write the equations for a line parallel to the line:
y=-4/3x-4
That goes through the point (-7,-6)
Write your equation in slope intercept form, using reduced fractions for the slope and intercept if necessary.
Answer:
y = -4/3x -46/3
Step-by-step explanation:
The question tells us to write an equation that is:
- parallel to the given line
- goes through the point (-7, -6)
Parallel lines will have the same slope, because if the slope was different, they would eventually intersect and not be parallel lines anymore.
We are going to use the point-slope form to find the other line.
Point-slope form uses a point that the graph will cross through and the slope of the graph to find the graph in y = mx + b form (also called slope-intercept form).
(I attached the point-slope form as an image below)
m = slope
x1 = x coordinate of the point
y1 = y coordinate of the point
We are going to substitute our slope into the form first:
y - y1 = (-4/3)(x - x1)
Next let's put in our point (-7, -6):
(Remember! -7 is our x coordinate & -6 is our y coordinate :-) )
y - (-6) = -4/3(x - (-7))
(cancel out the negatives to make them positive)
y + 6 = -4/3 (x +7)
Now solve for x using basic algebra:
y + 6 = -4/3 (x +7)
(distribue the -4/3)
y + 6 = -4/3x - 28/3
(subtract 6 from both sides)
y = -4/3x -46/3
That's your answer!
Hope it helps (●'◡'●)
Answer:
Step-by-step explanation:
y + 6 = -4/3(x + 7)
y + 6 = -4/3x - 28/3
y + 18/3 = -4/3x - 28/3
y = -4/3x - 46/3
the blueprint dimensions of the playground are 23/147 yd x 3/14 yd after reducing them by the factor of 2/147 what are the original dimensions if the playground in yards
Answer:
The original dimensions of the park are:
(23/2) yards by 7 yards.
Step-by-step explanation:
Suppose that you have a given dimension X
if you want to reduce that dimension by a scale factor k, such that:
0 < k < 1
The reduced dimension is just:
X' = k*X
Now let's solve the problem:
We know that the dimensions on the blueprint are:
(23/147)yd by (3/14)yd
And the original dimensions are:
A yd by B yd
We know that, to get the blueprint dimensions, we reduced the original dimensions by a factor of 2/147
Then we just have that:
(2/147)*A = 23/147
(2/147)*B = 3/14
Now we just can solve these two equations for A and B
A = (23/147)*(147/2) = 23/2
B = (3/14)*(2/147) = (3/7)*(1/147) = 49/7 = 7
Then the original dimensions of the park are:
(23/2) yards by 7 yards.
a. Consider the situation where you have three game chips, each labeled with one of the the numbers 3, 5, and 10 in a hat a. If you draw out 2 chips without replacement between each chip draw, list the entire sample space of po ssible results that can occur in the draw Use the three events are defined as follows, to answer parts b through n below:
Event A: the sum of the 2 drawn numbers is even.
Event B: the sum of the 2 drawn numbers is odd.
Event C: the sum of the 2 drawn numbers is a prime number
Now, using your answer to part a find the following probability values
b. P (A)=
c. P (B)=
d. P (C)=
e. P (A and C)-=
f. P(A or B)=
g. P (B andC)=
h. P(A or C)- =
i. P (C given B)=
j. P(C given A)=
k. P (not B)=
l. P (not C)=
Are events A and B mutually exclusive?Why or why not?
Are events B and C mutually exclusive? Why or why not?
Answer:
a) {3,5}{3,10}{5,10}
b) [tex]P(A)=\frac{1}{3}[/tex]
c) [tex]P(B)=\frac{2}{3}[/tex]
d) [tex]P(C)=\frac{1}{3}[/tex]
e) [tex]P(A and C)=0[/tex]
f) [tex]P(A or B)=1[/tex]
g) [tex]P(B and C)=\frac{1}{3}[/tex]
h) [tex]P(A or C)=\frac{2}{3}[/tex]
i) [tex]P(C given B)=\frac{1}{2}[/tex]
j) [tex]P(C given A)=0[/tex]
k) [tex]P(not B)=\frac{1}{3}[/tex]
l) [tex]P(not C)=\frac{2}{3}[/tex]
Yes, events A and B are mutually exclusive. Because the results can either be even or odd, not both. No, events B and C are not mutually exclusive because the result can be both, odd and prime.
Step-by-step explanation:
a)
In order to solve part a of the problem, we need to find the possible outcomes, in this case, the possible outcomes are:
{3,5}{3,10} and {5,10}
We could think of the oppsite order, for example {5,3}{10,3}{10,5} but these are basically the same as the previous outcomes, so we will just take three outcomes in our sample space. We can think of it as drawing the two chips at the same time.
b)
Now the probability of the sum of the chips to be even. There is only one outcome where the sum of the chips is even, {3,5} since 3+5=8 the other outcomes will give us an odd number, so:
[tex]P=\frac{#desired}{#possible}[/tex]
[tex]P(A)=\frac{1}{3}[/tex]
c) For the probability of the sum of the chips to be odd, there are two outcomes where the sum of the chips is odd, {3,10} since 3+10=13 and {5,10} since 5+10=15 the other outcomes will give us an even number, so:
[tex]P(B)=\frac{2}{3}[/tex]
d) The probability of the sum of the chips is prime. There is only one outcome where the sum of the chips is prime, {3,10} since 3+10=13 the other outcomes will give us non prime results, so:
[tex]P(C)=\frac{1}{3}[/tex]
e) The probability of the sum of the chips to be even and prime. There are no results where we can get an even and prime number, since the only even and prime number there is is number 2 and no outcome will give us that number, so:
P(A and C)=0
f) The probability of the sum of the chips is even or odd. We can either get even or odd results, so no matter what outcome we get, we will get an odd or even result so:
[tex]P(A or B)=1[/tex]
g) The probability of the sum of the chips is odd and prime. There is only one outcome where the sum of the chips is odd and prime, {3,10} since 3+10=13 the other outcomes will give us non prime results, so:
[tex]P(B and C)=\frac{1}{3}[/tex]
h) The probability of the sum of the chips is even or prime. There are two outcomes where the sum of the chips is even or prime, {3,10} since 3+10=13 and {3,5} since 3+5=8 so:
[tex]P(A or C)=\frac{2}{3}[/tex]
i) The probability of the sum of the chips is prime given that the sum of the chips is odd. There are two possible results where the sum of the chips is odd {3,10} and {5,10} and only one of those results is even, {3,10}, so
[tex]P(C given B)=\frac{1}{2}[/tex]
j) The probability of the sum of the chips is prime given that the sum of the chips is even. There is only one possible even result: {3,5} but that result isn't prime, so
[tex]P(C given A)=0[/tex]
k) The probability of the sum of the chips is not odd. There is only one outcome where the sum of the chips is not odd (even), {3,5} so:
[tex]P(not B)=\frac{1}{3}[/tex]
l) The probability of the sum of the chips is not prime. There are two outcomes where the sum of the chips is not prime, {3,5} and {5,10} so:
[tex]P(not C)=\frac{2}{3}[/tex]
Are events A and B mutually exclusive?
Yes, events A and B are mutually exclusive.
Why or why not?
Because the results can either be even or odd, not both.
Are events B and C mutually exclusive?
No, events B and C are not mutually exclusive.
Why or Why not?
Because the result can be both, odd and prime.
Bateman Corporation sold an office building that it used in its business for $800,800. Bateman bought the building 10 years ago for $599,600 and has claimed $201,200 of depreciation expense. What is the amount and character of Bateman's gain or loss?
Answer:
$402.700 capital gain
Step-by-step explanation:
What is the point estimate for the number of cars sold per week for a sample consisting of the following weeks: 1, 3, 5, 7, 10, 13, 14, 17, 19, 21?
A.
4.8
B.
5.22
C.
6.38
D.
6.1
Answer: A.
Step-by-step explanation:
Hope this helps!
what is the answer some one help me please so i can do this
Answer:
They can buy up to 240 drinks.
Step-by-step explanation:
Let x = number of drinks
The price of 1 drink is 75¢ = $0.75
The price of x drinks is 0.75x
The store gives a discount of $100.
The rice of x drinks is
0.75x - 100
The total price of the drinks must be less than or equal to $80.
0.75x - 100 ≤ 80
Add 100 to both sides.
0.75x ≤ 180
Divide both sides by 0.75
x ≤ 240
Answer: They can buy up to 240 drinks.
Pls help me someone this is annoying me
Answer:
They are both 42 cm
Step-by-step explanation:
Triangle A'B'C' is formed by a reflection over x = 1 and dilation by a scale factor of 2 from the origin. Which equation shows the correct relationship between AABC
and A'B'C'?
Answer:
[tex]\frac{AB}{A"B"}=\frac{1}{2}[/tex]
Step-by-step explanation:
Given
[tex]k = 2[/tex] --- scale factor
Required
Relationship between ABC and A"B"C"
[tex]k = 2[/tex] implies that the sides of A"B"C" are bigger than ABC
i.e.
[tex]A"B" = 2AB[/tex]
[tex]A"C" = 2AC[/tex]
[tex]B"C" = 2BC[/tex]
In [tex]A"B" = 2AB[/tex]
Divide both sides by A"B"
[tex]1 = \frac{2AB}{A"B"}[/tex]
Divide both sides by 2
[tex]\frac{1}{2} = \frac{AB}{A"B"}[/tex]
Rewrite as:
[tex]\frac{AB}{A"B"}=\frac{1}{2}[/tex]
(a) is correct
how many crores are there in 20 million
Answer:
20 million = 2 crore
Step-by-step explanation:
Here we will show you how to convert 20 million to crores (twenty million in crores). This may be useful if you for example want to convert 20 million rupees to crore rupees or 20 million dollars to crore dollars.
In some parts of the world like the United States, large numbers are separated with commas in three-digit-interval format like this:
...,BBB,MMM,TTT,HHH
BBB = billions
MMM = millions
TTT = thousands
HHH = hundreds
In certain parts of Asia, the format is a little different. From right to left, it starts out with three digits followed by a comma like the US, but after that, it is in intervals of two digits like this:
..,AA,CC,LL,TT,HHH
AA = arabs
CC = crores
LL = lakhs
TT = thousands
HHH = hundreds
Below we have displayed 20 million with the two number systems, based on the information above:
MM,TTT,HHH
20,000,000
=
C,LL,TT,HHH
2,00,00,000
When you match up 20 million with the C,LL,TT,HHH format above, you can see what 20 million is in crores. The answer to 20 million in crores is as follows:
20 million
= 2 crore
Work out m and c for the line:
y – 37 = 5
Answer:
first thing is y - 35 = 5
then y = 35 + 5 because when = come here - will be + and
then we should do+ y=40 answer
(c) Construct a 99% confidence interval for u if the sample
size, n, is 35.
Answer:
The confidence interval is [tex](\overline{x} - 1.99\frac{\sigma}{\sqrt{35}}, \overline{x} + 1.99\frac{\sigma}{\sqrt{35}})[/tex], in which [tex]\overline{x}[/tex] is the sample mean and [tex]\sigma[/tex] is the standard deviation for the population.
Step-by-step explanation:
We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:
[tex]\alpha = \frac{1 - 0.99}{2} = 0.005[/tex]
Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].
That is z with a pvalue of [tex]1 - 0.005 = 0.995[/tex], so Z = 2.575.
Now, find the margin of error M as such
[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]
In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.
In this question:
[tex]M = 1.99\frac{\sigma}{\sqrt{35}}[/tex]
The lower end of the interval is the sample mean subtracted by M, while upper end of the interval is the sample mean added to M. Thus, the confidence interval is [tex](\overline{x} - 1.99\frac{\sigma}{\sqrt{35}}, \overline{x} + 1.99\frac{\sigma}{\sqrt{35}})[/tex], in which [tex]\overline{x}[/tex] is the sample mean and [tex]\sigma[/tex] is the standard deviation for the population.
The linear equation Y = a + bX is often used to express cost formulas. In this equation:_________
a) the b term represents variable cost per unit of activity.
b) the a term represents variable cost in total.
c) the X term represents total cost.
d) the Y term represents total fixed cost.
Tiham is the only striker of his team. He can catch one of the four passes delivered to him and when he get a pass he takes the shot. One of his four shots go towards the net but the goal keeper of the opposite team stop one of every two shots. What is the minimum number of passes have to be delivered to Tiham to score minimum one goal?
Answer:
1/4 *1/4*1/2 =0.03125
which as a fraction is 1/32
so the minimuim number of passes that will get him a goal is 1 since he could get it on the first try
Hope This Helps!!!
Find m angle JRQ if m angle SRQ=166^ and m angle SRJ=110^
Answer:
[tex] \large{ \tt{❃ \: S \: O \: L \: U \: T \: I \: O \: N : }}[/tex]
[tex] \large{ \tt{❉ \: m \: \angle \:SRQ = m \: \angle \: SRJ\: + \: m \: \angle \:JRQ}}[/tex]
[tex] \large{ \tt{⟼ \: 166 \degree = 110 \degree + m \: \angle \: JRQ}}[/tex]
[tex] \large{ \tt{⟼ \: 166 \degree - 110 \degree = m \: \angle \: JRQ}}[/tex]
[tex] \boxed{ \large{ \tt{⟼ \: 56 \degree = m \: \angle \: JRQ}}}[/tex]
Our final answer is 56° . Hope I helped! Let me know if you have any questions regarding my answer! :)A binomial experiment consists of 11 trials. The probability of success on trial 4 is 0.41. What is the probability of success on trial 8?A. 0.71B. 0.41C. 0.39D. 0.84E. 0.14
Answer:
B. 0.41
Step-by-step explanation:
Binomial experiment:
In a binomial experiment, the probability of the success on each trial is always the same.
The probability of success on trial 4 is 0.41.
This means that the probability of success on trial 8, and all the other 10 trials, is of 0.41, and thus the correct answer is given by option B.
Help please asap!!! Thank you!
Answer:
Here's your answer.
Step-by-step explanation:
Just multiply in
The radius of a circle is 5 yd.
Answer the parts below. Make sure that you use the correct units in your answers.
If necessary, refer to the list of geometry formulas.
Answer:
Circumference =10 pi yard
Area =25 pi yard squared
Step-by-step explanation:
C=2*pi*r
Circumfrance =10 pi
A=pi r^2
Area =25 pi
For the estimate just sub in pi on the calculator for pi, then round to the hundreth.
Circumfrence= just the unit
Area= squared
Lost-time accidents occur in a company at a mean rate of 0.4 per day. What is the probability that the number of lost-time accidents occurring over a period of 9 days will be no more than 5
Answer:
0.8441
Step-by-step explanation:
This question can be solved by using the microsoft excel command.
we start off by solvingfor the mean rate for 9 days
mean rate = 0.4
for 9 days = 0.4*9 = 3.6
using the excel command,
POISSON (5, 3.6, TRUE)
p(x≤ 5) = 0.8441
so in conclusion 0.8441 is the probability that lost time accidents over 9 days would not be greater than 5.
the attachment is an excel sheet showing the input and the result.
(3b-4)(b+2) in standard form
Answer:
3b^2 + 2b -8
Step-by-step explanation:
* means multiply
^ means exponent
3b * b = 3b^2
3b * 2 = 6b
-4 * b = -4b
-4 * 2 = -8
3b^2 + 6b -4b -8
3b^2 + 2b -8
Write a polynomial f (x) that satisfies the given conditions. Polynomial of lowest degree with zeros of -4 (multiplicity 3), 1 (multiplicity 1), and with f(0) = 320.
Answer:
Step-by-step explanation:
Polynomial f(x) has the following conditions: zeros of -4 (multiplicity 3), 1 (multiplicity 1), and with f(0) = 320.
The first part zeros of -4 means (x+4) and multiplicity 3 means (x+4)^3.
The second part zeros of 1 means (x-1) and multiplicity 1 means (x-1).
The third part f(0) = 320 means substituting x=0 into (x+4)^3*(x-1)*k =320
(0+4)^3*(0-1)*k = 320
-64k = 320
k = -5
Combining all three conditions, f(x)
= -5(x+4)^3*(x-1)
= -5(x^3 + 3*4*x^2 + 3*4*4*x + 4^3)(x-1)
= -5(x^4 + 12x^3 + 48x^2 + 64x - x^3 - 12x^2 - 48x - 64)
= -5(x^4 + 11x^3 + 36x^2 + 16x -64)
= -5x^3 -55x^3 - 180x^2 - 80x + 320
Answer:
Step-by-step explanation:
-4 is a root for 3 times and 1 is root for once
so (x+4)^3 * (x-1) is part of f(x)
the constant term there is 4^3*(-1)=-64
so there is a multiplier of 320/-64=-5
f(x) = -5 * (x+4)^3 * (x-1)
A fair dice is rolled. Work out the probability of getting a number less than 5. Give your answer in its simplest form.
Step-by-step explanation:
4/6
=2/3
That's what I could show you
Trapezoid A B C D is shown. A diagonal is drawn from point B to point D. Sides B C and A D are parallel. Sides B A and C D are congruent. Angle C B D is 24 degrees and angle B A D is 116 degrees.
What is the measure of angle ABD in trapezoid ABCD?
24°
40°
64°
92°
Answer:
40 degrees un edge
Step-by-step explanation:
Answer:
The person above me got this correct, so the answer to this is 40! I just did the Unit Test and got a 100%!
What is the sum?
CO
3 5
x2-gx+3
+
8
x2+x-6
O
5x-12
X-3
-5x
(x+3)(x-3)
O
5x-12
(x+3)(x-3)
2.
The height of a kicked football can be represented by the polynomial - 16+ + 22t+
3, where tis the time in seconds. Find the factored form of the polynomial.
-
5
A) (8t + 3)(-2t + 1)
OB) (-8t+ 3)(2t+ 1)
8
OC) (8t+ 1)(-2t + 3)
OD) (-8t + 1)(2t+ 3)
5t/4y=3b/4c (solve for y)
I also need to know the steps.
thanks.
Answer:
[tex]y = \frac{5ct}{3b}[/tex]
Step-by-step explanation:
[tex]\frac{5t}{4y} =\frac{3b}{4c}[/tex]
1. start by multiplying y to both sides:
y × [tex]\frac{5t}{4y} =\frac{3b}{4c}[/tex] × y
[tex]\frac{5t}{4} =\frac{3b}{4c}y[/tex]
2. divide both sides by [tex]\frac{3b}{4c}[/tex]
[tex]\frac{5t}{4}/\frac{3b}{4c} =\frac{3b}{4c}y/\frac{3b}{4c}[/tex]
[tex]y = \frac{5ct}{3b}[/tex]
