The focus of a parabola is (3,-7) and the directrix is y = -4.
What is an equation of the parabola?

Answer:

The correct option is;

B. s ≥ 12 - t, s ≤ 30 - t, s ≤ 24 - 0.66·t

Step-by-step explanation:

The given parameters are;

The number of T-shirts, t, and shorts, s, Tim must design a day = 12

The maximum number of T-shirts and shorts Tim can design a day = 30

The maximum number of hours Tim can work = 18 hours

Therefore, we have;

The number of shorts Tim designs in a day is ≥ The minimum number of T-shirts and shorts Tim must design a day less the number of T-shirts Tim designs

Which gives;

s ≥ 12 - t

Also the number of shorts Tim designs in a day is ≤ The maximum number of T-shirts, and shorts, Tim can design a day less the number of T-shirts Tim designs

Which gives;

s ≤ 30 - t

The number of 45 minute period for the design of shorts in 18 hours = 18×60/45 = 24

The fraction of 36 minutes in 45 minutes = 36/45 = 0.667

Therefore we have;

The number of shorts Tim designs in a day is ≤ The number of 45 minute periods in 18 hours less the number of 36 minutes periods used to design T-shirts

Which gives;

s ≤ 24 - 0.66·t

The correct option is s ≥ 12 - t, s ≤ 30 - t, s ≤ 24 - 0.66·t.

Answer:

B. s> 12-tss 30 - t Ss 24 -0.66t, s 2 0; t> 0

Step-by-step explanation:

Hope this helps!!

Answer:

5(12 : 3) -8

Step-by-step explanation

when you solve the first half of the equation you get 1.

so 9-1 is 8.

Answer: 0

Work Shown:

Factors of 48 = {1, 2, 3, 4, 6, 8, 12, 16, 24, 48}

Erase the odd numbers of that list to get {2, 4, 6, 8, 12, 16, 24, 48}

Then highlight stuff that is greater than 24, and less than 48 at the same time.

No factors fit this description since 24 cannot be larger than itself, and 48 cannot be smaller than itself.

Answer: 0

Step-by-step explanation:

There is no number greater than 24 and less than 48.

Answer:

the percentage share for BBC2 remained almost the same at about 11 % each year

if you look at the chart the BBC2 almost remains stable between 10 and 12 %

1980 ( between 39 and 51)

1985 ( between 37 and 49 ) and so on

( these numbers are not exactly the same , it is about or approximately)

Answer:

The total amount left by Manavi and Kuber is: (1) 399

Step-by-step explanation:

Manavi

saving account +  amount spent at the mall:  1/'2 + 1/4 =  3/4

left over: 1 - 3/4 = 4-3/4 = 1/4

1260 ( 1/4) = 315

The total leftover for Manavi is Rs.315.

Now do the same steps with Kuber.

Kuber

saving account +  amount spent at the mall: 1/3+ 3/5 = 14/15

left over: 1- 14/15 = 15-14/15 = 1/15

1260 (1/15) = 84

The total leftover for Kuber is Rs.84.

Lastly, just add both left over amount together.

315+84 = 399

The total amount left by Manavi and Kuber is: (1) 399

Answer:

The total number of cups in arranged in an hexagonal area = 19 cups

Step-by-step explanation:

The pack the most circles within an area, the arrangement with the densest packing is the hexagonal lattice structure similar to the bee's honeycomb as has been proved Gauss and Fejes Toth.

Therefore, we pack the circles in an hexagonal lattice structure in an assumed hexagonal area where we have;

The longest straight line is five cups the next on either side are four cups and the final line on either side has three cups

The total number of cups = 3 + 4 + 5 + 4 + 3 = 19 cups

The total number of cups = 19 cups.

Answer:

C. [tex]x[/tex] and $(x-6)$

Step-by-step explanation:

The roots of the quadratic equation are $0$ and $6$.

Hence the equation is $(x-0)(x-6)=x(x-6)$

Answer:

See below

Step-by-step explanation:

Answer:

[tex] \boxed{13}[/tex]

Step-by-step explanation:

Arranging the data in ascending order:

8 , 8 , 10 , 11 , 13 , 13 ,13 , 14 , 14 , 15 , 16 , 17 , 18 , 18 ,

In the case of discrete data, mode can be found just by inspection, i.e just by taking an item with highest frequency.

Here, 13 has the highest frequency

So, Mode = 13

Extra information

Mode

The mode of a set of data is the value with the highest frequency. A distribution that has two modes is called bimodal. The mode of a set of data is denoted by Mo.

Hope I helped!

Best regards!

Answer:

Hey there!

6(x-5)

6(7-5)

6(2)

12

Hope this helps :)

Answer:

12

Step-by-step explanation:

Replace x by 7 in 6(x-5) to be able to evaluate the expression.

● 6(x-5)

● 6(7-5)

● 6 × 2

● 12

So the expression is equal to 12 when x=7

Answer:

the value of x = 9  and y =11.

Given the system of equation:

12x + 4y =152                  .......[1]

32x + 12y = 420              ......[2]

Multiply equation [1] by 3 we get;

Using distributive property:  

            ......[3]

On solving equation [2] and [3] simultaneously we get;

x = 9

Substitute the value of x= 9 in [1] to solve for y;

108 + 4y = 152

Subtract 108 from both sides we have;

108 + 4y -108 = 152- 108

Simplify:

4y = 44

Divide both sides by 4 we get;

Simplify:

y= 11

therefore, the value of x = 9  and y =11.

Answer:

STEP 1: Find the circumference:

Circumference = 2πr

Circumference = 2π(14) = 28π cm

............................................................................................

STEP 2: Find the length of the arc:

Length of the arc = 36/360 x 28π

Length of the arc = 8.8 cm

.............................................................................................

Answer: The length of the arc is 8.8 cm

............................................................................................

hope it helpssss

Mark it as brilliant answer plzzz

ФωФ

Answer:

27°

Step-by-step explanation:

arc length = circumference × fraction of circle

let x be the central angle, then

2πr × [tex]\frac{x}{360}[/tex] = 6.6

2 × [tex]\frac{22}{7}[/tex] × 14 × [tex]\frac{x}{360}[/tex] = 6.6

88 ×[tex]\frac{x}{360}[/tex] = 6.6 ( multiply both sides by 360 )

88x = 2376 ( divide both sides by 88 )

x = 27

Thus central angle is 27°

Answer:

3053.5517 cm^3 ; 1/8

Step-by-step explanation:

Given the following :

Volume (V) of sphere = (4/3)πr^3 where r = radius

Diameter of sphere = 18 ; radius(r) = diameter / 2 = 18/2 = 9cm

V = (4/3) × π × 9^3

V = 1.3333 × π × 729

V = 3053.5517 cm^3

When diameter(d) is reduced to half

d = d/2

Volume (V1) of sphere with diameter 'd' =

V1 = (4/3)π(d/2)^3

Volume (V2) of sphere with diameter 'd' reduced to half, d = d/2, d/2 * 1/2 = d/4

V2 = (4/3)π(d/4)^3

V1 / V2 = [(4/3)π(d/2)^3] / [(4/3)π(d/4)^3]

V1 / V2 = (d/2)^3 / (d/4)^3

V1 / V2 = [d^3 / 2^3] / [d^3 / 4^3]

V1 / V2 = 8 / 64

V1 / V2 = 1 / 8

Answer:

first blank is 972

second blank is 1/8

yup

Step-by-step explanation:

Answer:

n = 5

Step-by-step explanation:

To start off, we know that whenever the bases are the same, their exponents are equal to each other. Therefore, since both of the numbers bases are the same (both are z), we know that they will be equal.

The n can be distributed to the [tex]z^2[/tex] so that it now reads to be:

[tex]z^2^n = z^{10}[/tex]

Exponents are equal, so:

2n=10

Divide the 2 on both sides:

n=5

Answer:

n =5

Step-by-step explanation:

z^2^n

We know that a^b^c = a^ (b*c)

z^(2n)

This is equal to z^10

Since the bases are the same, the exponents are the same

2n = 10

Divide by 2

2n/2 = 10/2

n = 5

Answer:

[tex]\dfrac{1}{6561}[/tex]

Step-by-step explanation:

Given the expression [tex][(2^{-2})(3^{4})]^{-3} * [(2^{-3})(3^2)]^{2}[/tex], Using the laws of indices to simplify the expression. The following laws will be applicable;

[tex]a^m*a^n = a^{m+n}\\(a^m)^n = a^{mn}\\[/tex]

[tex]a^{-m} = 1/a^m[/tex]

Given [tex][(2^{-2})(3^{4})]^{-3} * [(2^{-3})(3^2)]^{2}[/tex]

open the parenthesis

[tex]= (2^{-2})^{-3}(3^{4})^{-3}* (2^{-3})^2(3^2)^2\\\\= 2^{-2*-3}* 3^{4*-3} * 2^{-3*2} * 3^{2*2}\\\\= 2^6 * 3^{-12} * 2^{-6} * 3^4\\\\collecting \ like \ terms\\\\= 2^6 * 2^{-6} * 3^{-12} * 3^4\\\\= 2^{6-6} * 3^{-12+4}\\\\= 2^0 * 3^{-8}\\\\= 1 * \frac{1}{3^8}\\ \\= \frac{1}{6561}[/tex]

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Write it out as an equation:

(48 /(5+(11-8))) -7

Simplify:

(48/(5+3))-7

(48/8)-7

6-7 = -1

The answer is -1

Answer:

[tex] \boxed{\sf {18}^{2} + {24}^{2} = {x}^{2}} [/tex]

To Find:

Length of hypotenuse of the right triangle i.e. x

Step-by-step explanation:

Pythagoras theorem states that “In a right-angled triangle, the square of the hypotenuse side is equal to the sum of squares of the other two sides”.

[tex] \therefore [/tex]

[tex] \sf \implies {18}^{2} + {24}^{2} = {x}^{2} [/tex]

Answer:

18²+24²=x²

Step-by-step explanation:

to answer this question you must know Pythagorean theorem

a^ 2+b^2 =c^2

a and b stands for the sides with length 24 and 18 and c stands for the HYPOTENUSE . so the correct answer for the above question is 18²+24²=x²

Answer:

354.20 + 50.60w ≥ 1099.51

Step-by-step explanation:

354.20 + 50.60w ≥ 1099.51

Answer:

the other factor is (x+7)

Step-by-step explanation:

Given x^2+11x+28

factor into

x^2+7x + 4x + 28

=x(x+7) + 4(x+7)

= (x+4)(x+7)

Answer: the other factor is (x+7)

Answer:

n = 24

Step-by-step explanation:

Given the fraction:

[tex]$\frac{n}{n+101}$[/tex]

To find:

Smallest positive integer [tex]$n$[/tex] such that the fraction is equal to a terminating decimal.

Solution:

The rule that a fraction is equal to a terminating decimal states that, the denominator must contain factors of only 2 and 5.

i.e. Denominator must look like [tex]2^m\times 5^n[/tex], only then the fraction will be equal to a terminating decimal.

Now, let us have a look at the denominator, [tex]n+101[/tex]

Let us use hit and trial method to find the value of [tex]n[/tex] as positive integer.

n = 1, denominator becomes 102 = [tex]2 \times 3 \times 17[/tex] not of the form [tex]2^m\times 5^n[/tex].

n = 4, denominator becomes 105 = [tex]5 \times 3 \times 7[/tex] not of the form [tex]2^m\times 5^n[/tex].

n = 9, denominator becomes 110 = [tex]2 \times 5 \times 11[/tex] not of the form [tex]2^m\times 5^n[/tex].

n = 14, denominator becomes 115 = [tex]5 \times 23[/tex] not of the form [tex]2^m\times 5^n[/tex].

n = 19, denominator becomes 120 = [tex]5 \times 3 \times 2^3[/tex] not of the form [tex]2^m\times 5^n[/tex].

n = 24, denominator becomes 125 = [tex]2^0 \times 5 ^3[/tex] It is of the form [tex]2^m\times 5^n[/tex].

So, the answer is n = 24

Answer:

5x(25)

Step-by-step explanation:

50 plants total, 40% are vegetables

40% = 40/100 = 0.40

40% of 50 = 0.40*50 = 20

Answer:

≈ 36.1%

Step-by-step explanation:

In any circle the following ratio is equal

[tex]\frac{arc}{circmference}[/tex] = [tex]\frac{centralangle}{360}[/tex] = [tex]\frac{130}{360}[/tex] , thus

percentage = [tex]\frac{130}{360}[/tex] × 100% ≈ 36.1%

an arc measuring 130° is approximately 36.11% of the circumference of the circle.

To find the percentage of the circumference that an arc measuring 130° represents, we need to calculate the ratio of the arc length to the circumference of the circle and then convert it to a percentage.

The circumference of a circle is given by the formula C = 2πr, where r is the radius of the circle.

Let's assume the radius of the circle is r.

The circumference of the circle is C = 2πr.

To find the length of the arc corresponding to 130°, we need to calculate the fraction of the total angle (360°) that 130° represents:

Fraction of the angle = (130° / 360°) = (13/36).

Since the fraction of the angle is equal to the fraction of the arc length to the circumference, the length of the arc can be calculated as:

Arc length = Fraction of the angle * Circumference = (13/36) * (2πr).

Now, to find the percentage of the circumference that the arc length represents, we divide the arc length by the circumference and multiply by 100:

Percentage = (Arc length / Circumference) * 100

Percentage = [(13/36) * (2πr)] / (2πr) * 100

Percentage = (13/36) * 100

Percentage = 36.11%

Therefore, an arc measuring 130° is approximately 36.11% of the circumference of the circle.

Learn more about arc length here

https://brainly.com/question/10266974

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Answer: x = 3

Step-by-step explanation:

Sqrt(x+7) - 1  = x

Sqrt(x+7) = x + 1

x+7 = x^2 + 1

x = x^2 - 6

x=3

Answer:

Below

Step-by-step explanation:

All figures are squares. The area of a square is the side times itself

Let A be the area of the big square and A' the area of the small one in all the 5 exercices

51)

● (a) = A - A'

A = c^2 and A' = d^2

● (a) = c^2 - d^2

We can express this expression as a product.

● (b) = (c-d) (c+d)

■■■■■■■■■■■■■■■■■■■■■■■■■■

52)

● (a) = A-A'

A = (2x)^2 = 4x^2 and A'= y^2

● (a) = 4x^2 - y^2

● (b) = (2x-y) ( 2x+y)

■■■■■■■■■■■■■■■■■■■■■■■■■■

53)

● (a) = A-A'

A = x^2 and A' = y^2

● (a) = x^2-y^2

● (b) = (x+y) (x-y)

■■■■■■■■■■■■■■■■■■■■■■■■■■

54)

● (a) = A-A'

A = (5a)^2 = 25a^2 and A' =(2b)^2= 4b^2

● (a) = 25a^2 - 4b^2

● (a) = (5a-2b) (5a+2b)

■■■■■■■■■■■■■■■■■■■■■■■■■■

55)

● (a) = A - 4A'

A = (3x)^2 = 9x^2 and A'= (2y)^2 = 4y^2

● (a) = 9x^2 - 4 × 4y^2

● (a) = 9x^2 - 16y^2

● (a) = (3x - 4y) (3x + 4y)

Answer:

[tex]\frac{5}{9}[/tex]

Step-by-step explanation:

Using the rules of exponents/ radicals

[tex]a^{\frac{m}{n} }[/tex] ⇔ [tex]\sqrt[n]{a^{m} }[/tex] , [tex]a^{0}[/tex] = 1

[tex]a^{-m}[/tex] = [tex]\frac{1}{a^{m} }[/tex]

Given

[tex]27^{-\frac{2}{3} }[/tex] × [tex]25^{\frac{1}{2} }[/tex] × [tex]5^{0}[/tex]

= [tex]\frac{1}{27^{\frac{2}{3} } }[/tex] × [tex]\sqrt{25}[/tex] × 1

= [tex]\frac{1}{9}[/tex] × 5 × 1

=[tex]\frac{5}{9}[/tex]

Answer:

Step-by-step explanation:

Adding both equations

4x+5y+5y-4x=19+38

10y = 57

y= 5.7

Subtracting equation i from ii

5y-4x-4x-5y=38-19

-8x=9

x= -0.9

Answer:

G

Step-by-step explanation:

let his fixed price be x and his hourly fee be y;

270 = 4y + x

420 = 7y + x

x is common in both equations

equate the two;

x = 270-4y and x = 420-7y

270-4y = 420-7y

3y = 150

y = 50

x = 270-4*50

x = 70

Answer:

f(x) = 5 * ( 8/5) ^x

Step-by-step explanation:

f(x) = a b^x

Let x = 0

5 = a * b^0

5 = a*1

a = 5

Let x = 1

8 = 5 * b^1

Divide each side by 5

8/5 = b

f(x) = 5 * ( 8/5) ^x

Answer:

For "Negative 23 greater-than x" , highlight the left half of the number line starting at -23 and use a parenthesis ) on -23.

For "x greater-than-or-equal-to negative 23", highlight the right half of the number line starting at -23, and use a square bracket [ on -23.

Step-by-step explanation:

Start by locating the number -23 on the number line. Please see attached image to accompany the explanation.

In the first case:  "Negative 23 greater-than x" , which is expressed mathematically as:

[tex]-23 >x[/tex]

notice that "x" has to be strictly smaller than the number -23, therefore those sought x values must reside to the left of the number -23, so we have to highlight that half of the number line. Apart from that, we need to include a symbol on top of the number -23, that indicates that -23 itself shouldn't be considered as part of the set, that symbol is by convention a parenthesis ).

In the second case: "x greater-than-or-equal-to negative 23", which is expressed mathematically as:

[tex]x\geq -23[/tex]

notice that "x" has to be greater than or equal to the number -23, therefore those sought x values must reside to the right of the number -23, so we have to highlight that half of the number line. Apart from that, we need to include a symbol on top of the number -23, that indicates that -23 itself should be considered as part of the set, that symbol is by convention a square bracket [.

Answer:

the answer is A

Step-by-step explanation: