Mathematics High School

The conjugate of (2+i)²/3+i, in the form of a+ib, is
13/2 + i(25/2)
13/10 + i(-15/2)
13/10 +(-9/10)
13/10+(9/10)​

Answers

Answer 1

Given that

(2+i)²/(3+i)

On multiplying both numerator and the denominator with (3-i) then

⇛ [(2+i)²/(3+i)]×[(3-i)/(3-i)]

⇛ [(2+i)²(3-i)]/[(3+i)(3-i)]

⇛ [(2+i)²(3-i)]/[(3²-i²)

⇛ [(2+i)²(3-i)]/(9-i²)

⇛ [(2+i)²(3-i)]/[9-(-1)]

Since ,i² = -1

⇛ [(2+i)²(3-i)]/(9+1)

⇛ [(2+i)²(3-i)]/10

⇛ [{2²+i²+2(2)(i)}(3-i)]/10

⇛ (4+i²+4i)(3-i)/10

⇛ (4-1+4i)(3-i)/10

⇛ (3+4i)(3-i)/10

⇛ (9-3i+12i-4i²)/10

⇛ (9+9i-4(-1))/10

Since, i² = -1

⇛(9+9i+4)/10

⇛(13+9i)/10

⇛ (13/10)+ i (9/10)

We know that

The conjugate of a+ib is a-ib

So,

The conjugate of (13/10)+ i (9/10) is

(13/10)-i(9/10) ⇛ (13/10)+i (-9/10)

Answer:-The conjugate of (13/10)+ i (9/10) is (13/10)+i (-9/10)

Additional comment:

The conjugate of a+ib is a-ib and i = -1(a+b)² = a²+2ab+b² • (a+b)(a-b)=a²-b² •(a-b)²=a²-2ab+b².

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That’s the answer for the question

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Answers

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I DON'T KNOW IF CORRECT

Answer:

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Step-by-step explanation:

i) 29/10 = 2.9

ii) 329/100 = 3.29

iii) 72/1000 = 0.072

iv) 2/1000 = 0.002

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Step-by-step explanation:

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Answers

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Answer:

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Step-by-step explanation:

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Answers

Answer:

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Answers

Answer:

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Answers

Answer:

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__

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

See attached

Step-by-step explanation:

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  I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

I GIVE BRAINLIST ON ALL MY QUESTIONS !!

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Step-by-step explanation:

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