The circle graph describes the distribution of preferred music from a sample of 400 randomly selected middle school students.

a circle graph titled preferred music, with five sections labeled rock 13 percent, hip hop 25 percent, pop 35 percent, classical 13 percent, and jazz 14 percent

Which of the following conclusions can we draw from the circle graph?

Pop is the preferred music for 35 students.
Jazz is the preferred music for 56 students.
Together, Hip Hop, Rock, and Jazz are the preferred music for less than half the students.
Together, Hip Hop and Pop are the preferred music for 260 students.

Answer:

[tex]\large\boxed{\textsf{The Original Number is 13.}}[/tex]

Step-by-step explanation:

[tex]\textsf{We are asked to identify the original number.}[/tex]

[tex]\textsf{Many changes have happened to the original number that it is 9.}[/tex]

[tex]\textsf{We can identify the original number by using the Inverse Operation.}[/tex]

[tex]\large\underline{\textsf{What are Inverse Operations?}}[/tex]

[tex]\textsf{Inverse Operations are like normal operations, but they are reverse.}[/tex]

[tex]\mathtt{(+ , -, \times, \div)}[/tex]

[tex]\large\underline{\textsf{For Example;}}[/tex]

[tex]\textsf{The Inverse Operation of Addition is Subtraction.}[/tex]

[tex]\textsf{The Inverse Operation of Division is Multiplication.}[/tex]

[tex]\textsf{Basically, we will work backwards to find the original number.}[/tex]

[tex]\large\underline{\textsf{Solve;}}[/tex]

[tex]\textsf{Let's start with 9.}[/tex]

[tex]\mathtt{9 \times 5 = 45.} \ \textsf{(The Inverse Operation is Multiplication.)}[/tex]

[tex]\mathtt{45-10=35} \ \textsf{(The Inverse Operation is Subtraction.)}[/tex]

[tex]\mathtt{35 \div 7 = 5} \ \textsf{(The Inverse Operation is Division.)}[/tex]

[tex]\mathtt{5+8=13} \ \textsf{(The Inverse Operation is Addition.)}[/tex]

[tex]\large\boxed{\textsf{The Original Number is 13.}}[/tex]

Answer:

3.5

Step-by-step explanation:

y = 3x+2

= 3(0.5) + 2

= 1.5+2

= 3.5

Answer: 25:68

Step-by-step explanation:

If 68 is the total number of students, and 25 is the number of students who have vanilla, the ratio of the number of students who have vanilla to the total number of students is 25:68.

The ratio of the number of students who have chocolate to the total number of students is [tex]\frac{43}{68}[/tex]

In the above question it is given that,

There are students some of them have gotten the vanilla ice-cream and some have chocolate ice-cream

The total number of students are = 68

The number of students who had vanilla ice-cream are = 25

The number of students who had chocolate ice-cream are = 68 - 25 = 43

We need to find the ratio of the number of students who have chocolate to the total number of students

Therefore, the ratio of the number of students who have chocolate to the total number of students = [tex]\frac{43}{68}[/tex]

Hence, the ratio of the number of students who have chocolate to the total number of students is [tex]\frac{43}{68}[/tex]

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From the given data of hunters and do we find out there are 9 hunters and 15 dogs.

Let's assume that there were "h" hunters and "d" dogs.

Each hunter has two legs, and each dog has four legs, so the total number of legs can be expressed as:

2h + 4d = 78

We can simplify this equation by dividing both sides by 2:

h + 2d = 39

We also know that there were 24 heads in total, which includes the hunters and the dogs:

h + d = 24

We can now solve these two equations simultaneously to find the values of h and d.

First, we can solve for h in terms of d from the second equation:

h = 24 - d

We can substitute this expression for h in the first equation:

(24 - d) + 2d = 39

Simplifying and solving for d:

d = 15

Now that we know there were 15 dogs, we can substitute this value back into one of the equations to find the number of hunters:

h + d = 24

h + 15 = 24

h = 9

Therefore, there were 9 hunters and 15 dogs.

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Therefore , the solution of the given problem of mean comes out to be  15 is the solution.

The sum of all values divided by all of the values constitutes the result from a collection, also referred to as the arithmetic mean. It is often referred to be known as "mean" as well as is one of the most frequency used main trend indicators. To find the answer, multiply the collection's overall amount of numbers by all of its values. Either the original data or data which has been combined into frequency charts can be used for calculations.

Here,

We can use linear interpolation between the two closest latitude numbers in the table, 45 and 50, to determine the typical temperature for a city with a latitude of 48.

Let T(45) and T(50) represent the typical temperatures at respective latitudes of 45 and 50, respectively. The following algorithm can be used to determine the temperature at 48 degrees latitude:

=> T(48) = T(45) + (T(50) - T(45)) * (48 - 45)/(50 - 45)

Using the numbers from the table as inputs, we obtain:

=> T(48) = 14 + (16 - 14) * (48 - 45)/(50 - 45)

=> T(48) = 14 + 2 * 3/5

=> T(48) = 14 + 1.2

=> T(48) = 15.2

The estimated average temperature for a city with a latitude of 48 is 15, rounded to the closest whole number.

Consequently, 15 is the solution.

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By using Euler's method with a step size of 0.2, we estimate that y(1) = 4.5429.

The Euler's method is used to estimate a numerical solution of a first-order differential equation. The formula of Euler's method is given by:

y_1 = y_0 + hf(x_0, y_0)

Where: y_1 is the next value of y after one iterationy

0 is the initial value of yy' = f(x, y)h is the step size

This method is an iterative procedure that advances the estimate of y by one step by approximating the curve using a tangent line at each point along the curve.

Given that y(0) = 4 and h = 0.2, we can use Euler's method to estimate y(1) where y(x) is the solution of the initial-value problemy' = x2 + xy, y(0) = 4

Using Euler's method with a step size of 0.2, we get:

1) When x = 0, y = 4

y_1 = y_0 + hf(x_0, y_0) = 4 + 0.2(0 + 4(0))= 4.02

When x = 0.2, y = 4.02

y_2 = y1 + hf(x_1, y_1) = 4.02 + 0.2(0.2^2 + 0.2(4.02))= 4.10523

When x = 0.4, y = 4.1052

y_3 = y_2 + hf(x_2, y_2) = 4.1052 + 0.2(0.4^2 + 0.4(4.1052))= 4.1994144

When x = 0.6, y = 4.1994

4 = y_3 + hf(x_3, y_3) = 4.1994 + 0.2(0.6^2 + 0.6(4.1994))= 4.3032545

When x = 0.8, y = 4.3033

y_5 = y_4 + hf(x_4, y_4) = 4.3033 + 0.2(0.8^2 + 0.8(4.3033))= 4.4174496

When x = 1, y = 4.4174

y_6 = y_5 + hf(x_5, y_5) = 4.4174 + 0.2(1^2 + 1(4.4174))= 4.5429404

Therefore, using Euler's method with a step size of 0.2, we estimate that y(1) = 4.5429 (rounded to four decimal places).

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Based on the picture, we can use the Pythagorean theorem to find MBC. Therefore, MBC is equal to  [tex]7[/tex]√2.

Theorem of Linear Pairs Two angles are supplementary if they create a linear pair. Additional theorem, Two angles are congruent if they are supplements of the same angle.

Theorem of congruent complements an of thes., but it will be the first of a series of events that will result in a new set of rules and the.

First, we can find AB:

AB = √(AD² + BD²)

= √ [tex](3^2 + 4^2)[/tex]

= √[tex](9 + 16)[/tex]

= √ [tex]25[/tex]

[tex]= 5[/tex]

Next, we can find AC:

AC = √(AD² + CD²)

= √[tex](3^2 + 8^2)[/tex]

= √ [tex](9 + 64)[/tex]

= √[tex]73[/tex]

Finally, we can find BC:

[tex]BC = √(AB^2 + AC^2)[/tex]

= √(5² + (√73)²)

= √(25 + 73)

= √98

= 7√2

Therefore, m Bc is = 7√2

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The set of all possible y-values for the function h constitutes its range. The range is therefore [-3, 0].

The collection of all feasible output values (dependent variable) of a function is known as the range in mathematics. It is the totality of all possible numbers that the function can accept as input (an independent variable) and output. On the number line, the range is frequently represented by an interval or group of intervals. For instance, the range can be written as [-3, 3] if the domain of a function f(x) is [-2, 2] and its output numbers fall within [-3, 3].

given

The collection of all x-values for which h(x) is specified is the domain of the function h.

The graph's [-2, 4] domain can be determined by looking at the graph, which shows that it begins at x=-2 and concludes at x=4.

The set of all possible y-values for the function h constitutes its range. Looking at the graph, we can see that it takes all values between y=-3 and y=0, and that it begins at y=-3.

The range is therefore [-3, 0].

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The complete question is :-  The entire graph of the function h is shown in the figure below. Write the domain and range of h as intervals or unions of intervals.

-2

-3-

4-

domain =

range =

Using coefficients ak, the following product may be extended into a power series: the expression is provided in the attached file. For each of the [tex]k 2 N[/tex]phrases, determine the coefficients ak before them. The formula [tex]ak = (-1)k(k+1)/2[/tex] yields the coefficients ak.

To get the coefficients ak, we may first simplify the above formula by factoring out a -x and rearranging terms. This results in the equation: [tex](1-x)/(1+x)2 = -x/(1+x) - x2/(1+x)2.[/tex]

Now, each term in the statement may be expanded into a power series using the formula for the geometric series. This results in: Both[tex]-x/(1+x) and -x2/(1+x)2[/tex] are equal to[tex]-x + x + x + 2 + x + 3 +...[/tex]

By combining like terms and adding these two power series, we can determine that the coefficient in front of [tex]xk is (-1)k(k+1)/2.[/tex]  Hence,[tex]ak = (-1)k(k+1)/2[/tex] is the formula for the coefficients ak.

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Answer:

A ,B ,C

Step-by-step explanation:

2+2+2+2 equals 8

4x2 equals 8 and

1x8 equals 8

Answer:

A) 2 + 2 + 2 + 2

B) 4 × 2

C) 1 × 8

Hope this helps!

Step-by-step explanation:

A = 4 + 4 = 8

B = 8

C = 8

D = 16

E = 16

The correct option is C, A 95% confidence interval for the average starting salary of all attorneys in the city is (91331.94, 113352.06)

We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:

∝= [tex]\frac{1-0.95}{2} = 0.025[/tex]

Now, we have to find z in the Ztable as such z has a p-value of 1-∝.

So it is z with a value of, so [tex]1-0.025=0.975,Soz= 1.96[/tex]

Now, find M as such

[tex]M= z*\frac{1}{\sqrt{n} } *[/tex]σ

In which is the standard deviation of the population and n is the size of the sample.

[tex]M= 1.96* \frac{21756}{\sqrt{15}} =11010.06[/tex]

The lower end of the interval is the sample mean subtracted by M. So it is 102342 - 11010.06 = 91331.94.

The upper end of the interval is the sample mean added to M. So it is 102342 + 11010.06 = 113.352.06.

So the correct answer is:

(91331.94, 113352.06)

Standard deviation is a measure of how much the values in a data set vary from the average or mean value. It is a statistical measure that indicates the extent to which the values are spread out from the mean. A low standard deviation indicates that the values are clustered around the mean, while a high standard deviation indicates that the values are more widely spread out.

Standard deviation is commonly used in statistics and probability theory to measure the uncertainty or risk associated with a particular event or outcome. It is also used in fields such as finance, economics, and engineering to analyze data and make predictions. Standard deviation can provide valuable insights into the distribution of data and help identify trends and patterns in the data set.

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Complete Question:

A random sample of 15 recent college graduates found that starting salaries for attorneys in New York City had a mean of $102,342 and a standard deviation of $21,756. There are no outliers in the sample data set. Construct a 95% confidence interval for the average starting salary of all attorneys in the city. Group of answer choices

A). (89869.82, 114814.18)

B). (90292.73, 114391.27)

C). (91331.94, 113352.06)

D). (90371.37, 114312.63)

The number Tamika should multiply the cost of the meal by to find the total plus tip in one step is 1.29.

Let x be the cost of meal.

Let m be the number she should multiply the cost of the meal by to find the total plus tip in one step.

Then Total amount Tamika pays(including tip) = mx.

We need to determine the value of m.

Given Tamika wanted to leave a tip of 29% of the bill amount.

Then the amount of tip [tex]= (\frac{29}{100} )x = 0.29x[/tex]

Thus, Total amount Tamika pays(including tip) = x + 0.29x = 1.29.

We found Total amount Tamika pays(including tip) = mx.

Comparing we have m = 1.29.

A bill amount is the total cost of goods or services purchased or availed of by an individual or organization. It represents the amount that the customer owes to the provider of the goods or services. A bill may include various components such as the price of the goods or services, taxes, fees, and other charges that may be applicable.

When a customer receives a bill, they typically have a certain amount of time to pay it in full. Failure to pay the bill on time may result in additional fees, penalties, or even legal action. It is important for customers to carefully review their bills to ensure that they are accurate and that they understand all of the charges included.

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The height and radius of the cone that will use the smallest amount of paper are h ≈ 2.45 cm and r ≈ 1.22 cm, respectively.

The minimum paper will be used when the surface area of the cone is minimized. Let the height and radius of the cone be h and r, respectively. Then, using the formula for the volume of a cone, we have:

V = (1/3)πr^2h = 33 cm^3

Solving for h, we get:

h = 99/(πr^2)

Next, we need to express the surface area of the cone in terms of r. The surface area is given by:

A = πr√(r^2 + h^2)

Substituting the expression for h obtained above, we have:

A = πr√(r^2 + (99/πr^2)^2)

To find the value of r that minimizes A, we take the derivative of A with respect to r and set it equal to zero:

dA/dr = π(2r√(r^2 + (99/πr^2)^2) + (r^2 + (99/πr^2)^2)^(-1/2)(2r(99/πr^3)))

Setting dA/dr = 0 and solving for r, we get:

r = (33/(2π))^(1/4) ≈ 1.22 cm

Substituting this value of r back into the equation for h, we obtain:

h ≈ 2.45 cm

Therefore, the height and radius of the cone that will use the smallest amount of paper are h ≈ 2.45 cm and r ≈ 1.22 cm, respectively.

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The p-value for the Box-Ljung Q test of returns is greater than 5%, which means that we do not reject the null hypothesis and find no evidence of volatility clustering in the raw returns.

In statistics, p-value is a measure of the strength of evidence against the null hypothesis. It is defined as the probability of obtaining the observed results, or results more extreme, assuming that the null hypothesis is true.

The null hypothesis is a statement that assumes there is no significant difference or relationship between two groups or variables being compared. The alternative hypothesis is the statement that there is a significant difference or relationship.

Given by the question.

Based on the information provided, we can conclude that there is evidence of volatility clustering in the IBM data using 15 lags. This is indicated by the p-value being less than 5% for the Box-Ljung Q test of squared returns. Therefore, we reject the null hypothesis and find evidence of volatility clustering.

However, since the test is conducted on squared returns, it is the p-value for this test that is more relevant in assessing volatility clustering.

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Answer: The graph of function g(x) is shifting down by 3 (vertical shift) because the -3 is not part of x but y (the whole graph). Originally there is no y-intercept and the f(x) function crosses the origin, but now there is a y-intercept at (0, -3)

Answer:

17

Step-by-step explanation:

5+T(6-3); T=4

Use order of operations. Parenthesis, multiplying, then add last.

= 5 + 4(6 -3)

= 5 + 4(3)

= 5 + 12

= 17

Hello,

3m + 5 > 2(m - 7) =

3m + 5 > 2m - 14

3m - 2m > - 14 - 15

x > - 29

Step-by-step explanation:

3m±2m>-14-5

5m>-19

m>-19/5

m>3.8

By answering the presented question, we may conclude that Therefore, equation the cost per pound of turkey is $1.99 and the cost per pound of ham is [tex]$2.39[/tex]  .

In mathematics, an equation is an assertion that affirms the equivalence of two factors. An algebraic equation (=) separates two sides of an equation. For instance, the assertion [tex]"2x + 3 = 9"[/tex] states that the word "2x + 3" corresponds to the number "9".

The goal of solution solving is to figure out which variable(s) must still be adjusted for the equations to be true. It is possible to have simple or intricate equations, recurring or complex equations, and equations with one or more components.

For example, in the equations  [tex]"x2 + 2x - 3 = 0,"[/tex] the variable x is lifted to the powercell. Lines are utilised in many areas of mathematics, include algebra, arithmetic, and geometry.

Therefore,Let's denote the cost per pound of turkey as $t, and the cost per pound of ham as $h. Then we can write the following system of linear equations.

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Answer: n=40

Step-by-step explanation:

let me know if i got this right for you broski

now dance

Answer:

£ 6904.13

Step-by-step explanation:

the final value is given by

[tex]8500 (0.90)[/tex] at the final of the first year
then you need to add (0.95) twice (one from second and one from third year)

Notice if the depreciation is 5% the final value is 0.95 of the initial value at the beginning of the year

finally:

[tex]8500 (0.90) (0.95)^2 = 6904.13[/tex] (rounded to nearest cent!)

A translation of the sentence "Eight less than the product of a number N and 1/7 is no more than 98" is N/7 - 8 ≤ 98.

In order to translate a word sentence into an algebraic expression, we would have to assign a variable to the unknown number:

Let the variable N represent the unknown number.

By translating the word sentence into an algebraic expression, we have the following;

The product of a number N and 1/7 is N × 1/7 = N/7

Eight less than the above expression is N/7 - 8.

The inequality symbol for no more than is ≤. Therefore, we have the following:

N/7 - 8 ≤ 98.

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As per the distance, the length of the curve y = 3x − 2 for −3 ≤ x ≤ 1 is 4√10.

To begin, let us recall that the arc length formula gives us a way to find the length of a curve in terms of the function that defines it. The formula is given by:

L = ∫aᵇ √[1 + (dy/dx)²] dx

where L is the length of the curve, a and b are the endpoints of the curve, and dy/dx is the derivative of the function that defines the curve with respect to x.

For the curve y = 3x − 2, we can find dy/dx by taking the derivative of the function with respect to x. This gives us:

dy/dx = 3

We can now substitute this into the arc length formula and integrate over the interval −3 ≤ x ≤ 1:

L = ∫−3¹ √[1 + (3)²] dx

L = ∫−3¹ √10 dx

L = √10 ∫−3¹ dx

L = √10 (1 - (-3))

L = √10 (4)

L = 4√10

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0.64 is the probability that a student chosen at random is in the choir or the band or both.

What does a probability simple definition entail?

A probability is a number that expresses the possibility or likelihood that a specific event will take place. Probabilities can be stated as proportions with a range of 0 to 1, or as percentages with a range of 0% to 100%.

  60 are in choir and band, which leaves 50 (110 - 60) in choir and not band, and 180 (240 - 60) in band and not choir, and the remaining 220 (40 - 50 - 180) students don't belong to either. So

    P( choir or band ) = P(choir) + P(band ) - P( choir and band )

                      = 50/450 + 182/450 - 60/450 = 170/450

                      ≈ 0.38

If instead "110 of them are in choir" means 110 students are in choir and NOT in band, and "240 of them are in bad" means 240 students are in band and NOT choir, then

    P( choir or band ) = 110/450 + 240/450 - 60/450

                                  = 0.64

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Therefore, the exponential function that passes through the points (2,45) and (5,3072) is: y = (45/16) ([tex]4^{x}[/tex]).

In mathematics, a function is a rule that assigns to each element in a set called the domain, a unique element in another set called the range. In other words, a function is a mathematical object that takes an input and produces a specific output, according to a specific set of rules or operations.

by the question.

The general form of the exponential function is y = [tex]ab^{x}[/tex] where a and b are constants. To find the values of a and b that satisfy the given conditions, we can use the two points (2,45) and (5,3072) and solve for a and b.

First, we can write two equations based on the two points:

45 = a[tex]b^{2}[/tex] (1)

3072 = ab^5 (2)

We can then divide (2) by (1) to eliminate a:

3072/45 = (a[tex]b^{5}[/tex])/ (a[tex]b^{2}[/tex])

68 = [tex]b^{3}[/tex]

Solving for b, we get:

b = 4

Substituting this value of b into either (1) or (2) to solve for a, we get:

45 = a ([tex]4^{2}[/tex])

a = 45/16

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Answer:

p ≥ 228

Step-by-step explanation:

p ≥ 228

This inequality means the Bowlers have to score at least 228 points to move on.

Hope this helped!

the given form of the rate function:[tex]tan² (t) + 1 = sec²[/tex](t)

Therefore, we can write the given function as:c (t) dtUsing integration by substitution, we haveu = tan (t) ⇒ du = sec² (t) dt

Therefore,S [tex]π/t tan (t) sec² (t) dt= S u du= ln |tan (t)| + C[/tex]Thus, the equivalent closed form of the given function is:S π/t 4tan (t) dt= 4 ln |tan (t)| + C

a. S π/π/4 5t+4/t² + 1 dt equivalent closed formThe question demands to find an equivalent closed form for each function. So let's find the equivalent closed form for the given functions:a. S π/π/4 5t+4/t² + 1 dt

Hint: begin by writing as a sum of two functionsNow, we need to write the given function as a sum of two functions. Let's first write the numerator of the function as a sum of two functions.

Using the formula, a²-b² = (a+b)(a-b), we have5t + 4 = (2 + √21)(√21 - 2)Therefore, we can write the numerator of the function as follows:5t + 4 = (√21 - 2)² - 17Using this in the given function,

we haveπ/π/4 [(√21 - 2)² - 17]/t² + 1 dtLet's further simplify the numeratorπ/π/4 [21 + 4 - 4√21 - 17t² + 34t - 17] / (t² + 1) dt= π/π/4 [-17t² + 34t + 8 - 4√21]/(t² + 1) dtLet's now find the closed form of this function using the integration formulaS f(x) dx = ln |f(x)| + C Therefore, the equivalent closed form of the function is:

S π/π/4 5t+4/t² + 1 dt= π/π/4 [-17t² + 34t + 8 - 4√21]/(t² + 1) dt= - π/2 ln |t² + 1| + 34 π/2 arctan (t) - 17 π/2 t + 2 π/√21 arctan [(2t-√21)/ √21] + Cb. S π/t 4tan (t) dt equivalent closed formNow, let's find the equivalent closed form of the second given function.b. S π/t 4tan (t)

dtHint: begin by using a trig identity to change the form of the rate function Let's now use the following trig identity to change

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Options B and C, Utilizing basic fractions, the qualities scenario displays a result of 0. 4 Jesse completed 40 out of 100 arithmetic problems and rode his bike for 4 of the 10 kilometers.

We are seeking a scenario that corresponds to a value of 0.4 or 40% among the possibilities mentioned, which represent various sections or fractions of a total.

Jesse rode his bike 4 out of the 10 miles in option B, which is equal to 0.4 or 40%.

Similarly, Jesse completed 40 of the 100 arithmetic problems in option C, which is likewise 0.4 or 40%. The other choices don't correspond to a 0.4 value.

A fraction of 2/3, or 0.666, is represented by choice A, a fraction of 4/100, or 0.04, by option D, and a fraction of 1/2, or 0.5, by option E.

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The question is -

Which of the following scenarios shows a value of 0.4? Select all that apply.

A. Jesse sold 40 out of 60 items at a garage sale.

B. Jesse rode 4 out of 10 miles on his bike.

C. Jesse finished 40 out of 100 math problems.

D. Jesse ate 4 out of 100 jellybeans.

E. Jesse returned 4 out of 8 library books.

Step-by-step explanation:

1. Draw a line of 8cm.

2. Take a compass and keep it in the length of more than 8 cm.

3. Draw an arc from point A and B which will intersect at point between A and B.

4. Draw a straight line from the arc.

5. You will find out that the line will be drawn exactly between A and B at 4cm.

Answer: 36% passed the science test, while 25% passed the history test.

In order to find a percentage we divide our two know numbers

Science Class- 9/25 is a fraction with / standing for divided by. 9 divided by 25 is .36   This means 36% of the class passed the science test.

History Class- 4/16 is a fraction with / standing for divided by. 4 divided by 16 is .25   This means 25% of the class passed the science test.

I hope this helped & Good Luck <3!!!!