Test the claim that the mean GPA of night students is larger than the mean GPA of day students at the 0.10 significance level. The null and alternative hypothesis would be: H 0 : p N ≥ p D H 1 : p N < p D H 0 : p N ≤ p D H 1 : p N > p D H 0 : p N = p D H 1 : p N ≠ p D H 0 : μ N ≤ μ D H 1 : μ N > μ D H 0 : μ N ≥ μ D H 1 : μ N < μ D H 0 : μ N = μ D H 1 : μ N ≠ μ D The test is: two-tailed right-tailed left-tailed The sample consisted of 30 night students, with a sample mean GPA of 3.34 and a standard deviation of 0.02, and 30 day students, with a sample mean GPA of 3.32 and a standard deviation of 0.08. The test statistic is: (to 2 decimals) Use the conservative degree of freedoms. The p-value is: (to 2 decimals) Based on this we: Reject the null hypothesis Fail to reject the null hypothesis

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Answer:

  see attached

Step-by-step explanation:

The attachment shows the ordered pairs (x, f(x)) and their graph.

[tex]\huge{\boxed{\boxed{ Solution ⎇}}} \ [/tex]

[tex] - 3x \times (2x + 5) \\ = - 3x \times 2x + - 3x \times 5 \\ = - 6x ^{2} - 15x[/tex]

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ ツ

꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐

[tex] \huge\boxed{\mathfrak{Answer}}[/tex]

[tex] - 3x \times (2x + 5) \\ = - 3x \times 2x + - 3x \times 5 \\ = - 6x ^{2} - 15x [/tex]

Answer ⟶ - 6x² - 15x

Answer:

the answer is 50 but I don't know if

Answer:

0.1512 = 15.12% probability that fewer than four tornadoes occur in a three-week period.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

In which

x is the number of sucesses

e = 2.71828 is the Euler number

[tex]\mu[/tex] is the mean in the given interval.

In a given region, the number of tornadoes in a one-week period is modeled by a Poisson distribution with mean 2

Three weeks, so [tex]\mu = 2*3 = 6[/tex]

Calculate the probability that fewer than four tornadoes occur in a three-week period.

This is:

[tex]P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)[/tex]

In which

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

[tex]P(X = 0) = \frac{e^{-6}*6^{0}}{(0)!} = 0.0025[/tex]

[tex]P(X = 1) = \frac{e^{-6}*6^{1}}{(1)!} = 0.0149[/tex]

[tex]P(X = 2) = \frac{e^{-6}*6^{2}}{(2)!} = 0.0446[/tex]

[tex]P(X = 3) = \frac{e^{-6}*6^{3}}{(3)!} = 0.0892[/tex]

Then

[tex]P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0025 + 0.0149 + 0.0446 + 0.0892 = 0.1512[/tex]

0.1512 = 15.12% probability that fewer than four tornadoes occur in a three-week period.

Answer:

2w<23

Step-by-step explanation:

The product of w and 2 mean that w multiplied by 2

Answer:

D = -23

Step-by-step explanation:

Answer:

D) -23

Step-by-step explanation:

Definitely

Answer:

Point D

Step-by-step explanation:

The intersection(s) of lines represents where they cross or intersect. We can see that lines AD and DE cross or intersect as Point D, hence the answer being Point D.

Answer: Point D

Step-by-step explanation: The intersection of two figures is the set of points that is contained in both figures. In the diagram shown, D is the intersection of lines AD and DE because D is the point contained by both line AD and DE.

Answer:

50 dozen total

Step-by-step explanation:

8/12 & 10/12.... average 9/12

11/12 - 9/12 =

2/12x = 100

2x = 1200

x = 600/12

50 dozen total

Answer:

Step-by-step explanation:

If X is a normal random variable with a mean of 6 and a standard deviation of 3.0, then find the value x such that P(Z>x)is equal to .7054.

-----

Find the z-value with a right tail of 0.7054

z = invNorm(1-0.7054) = -0.5400

x = zs+u

x = -5400*3+6 = 4.38

Answer:

0.5587 = 55.87% probability that the sample mean would differ from the true mean by less than 1.1 dollars.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The cost of 5 gallons of ice cream has a variance of 64 with a mean of 34 dollars during the summer.

This means that [tex]\sigma = \sqrt{64} = 8, \mu = 34[/tex]

Sample of 38

This means that [tex]n = 38, s = \frac{8}{\sqrt{38}}[/tex]

What is the probability that the sample mean would differ from the true mean by less than 1.1 dollars ?

P-value of Z when X = 34 + 1.1 = 35.1 subtracted by the p-value of Z when X = 34 - 1.1 = 32.9. So

X = 35.1

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{35.1 - 34}{\frac{8}{\sqrt{38}}}[/tex]

[tex]Z = 0.77[/tex]

[tex]Z = 0.77[/tex] has a p-value of 0.77935

X = 32.9

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{32.9 - 34}{\frac{8}{\sqrt{38}}}[/tex]

[tex]Z = -0.77[/tex]

[tex]Z = -0.77[/tex] has a p-value of 0.22065

0.77935 - 0.22065 = 0.5587

0.5587 = 55.87% probability that the sample mean would differ from the true mean by less than 1.1 dollars.

Answer:

The second number is 100.

Step-by-step explanation:

Let the first integer be x.

Then since the five integers are consecutive, the second integer will be (x + 1), the third (x + 2), fourth (x + 3), and the fifth (x + 4).

They total 505. Hence:

[tex]\displaystyle x+(x+1)+(x+2)+(x+3)+(x+4)=505[/tex]

Solve for x. Combine like terms:

[tex]5x+10=505[/tex]

Subtract 10 from both sides:

[tex]5x=495[/tex]

And divide both sides by five. Hence:

[tex]x=99[/tex]

Thus, our sequence is 99, 100, 101, 102, and 103.

The second number is 100.

Answer:

[tex](5xy + 7)(5xy-7) = 25x^2 y^2 - 49[/tex]

Step-by-step explanation:

[tex](a - b)(a +b ) = a^2 - b^2 \\\\From \ given \ expression \ a = 5xy \ , \ b = 7\\\\Therefore , (5xy + 7 )(5xy - 7 ) = ( 5xy)^2 - ( 7)^2 \\[/tex]

                                             [tex]= 25x^2 y^2 - 49[/tex]

Answer:

25x²y² - 49

Step-by-step explanation:

We can do this by using the a+b formula:

(a+b)(a-b)= a² - b²

So,

(5xy+7)(5xy-7)

=(5xy)² - 7²

= 25x²y² - 49

Another way we can do this by expanding the algebraic expression:

(5xy+7)(5xy-7)

= 5xy(5xy-7) + 7(5xy-7)

= 25x²y² - 35xy + 35xy - 49

= 25x²y²- 49

Answer:

$196.28

Step-by-step explanation:

Original cost: 39 × $8 = $312

Revenue: 32 × $16.19 = $518.08

Return charge: 7 × $1.4 = $9.8

$312 + $9.8 = total cost, which is $321.8

$518.08 - $321.8 = profit

Profit = $196.28

Answer:

Yes, it is possible to have  a relation on the set {a, b, c} that is both symmetric and transitive but not reflexive

Step-by-step explanation:

Let

Set A={a,b,c}

Now, define a relation R on set A is given by

R={(a,a),(a,b),(b,a),(b,b)}

For reflexive

A relation is called reflexive if (a,a)[tex]\in R[/tex] for every element a[tex]\in A[/tex]

[tex](c,c)\notin R[/tex]

Therefore, the relation R is  not reflexive.

For symmetric

If [tex](a,b)\in R[/tex] then [tex](b,a)\in R[/tex]

We have

[tex](a,b)\in R[/tex] and [tex](b,a)\in R[/tex]

Hence, R is symmetric.

For transitive

If (a,b)[tex]\in R[/tex] and (b,c)[tex]\in R[/tex] then (a,c)[tex]\in R[/tex]

Here,

[tex](a,a)\in R[/tex] and [tex](a,b)\in R[/tex]

[tex]\implies (a,b)\in R[/tex]

[tex](a,b)\in R[/tex] and [tex](b,a)\in R[/tex]

[tex]\implies (a,a)\in R[/tex]

Therefore, R is transitive.

Yes, it is possible to have  a relation on the set {a, b, c} that is both symmetric and transitive but not reflexive.

Answer:

Step-by-step explanation:

4*(n +5) - 2*(5 + 7n) = -70

4*n + 4*5 + 5*(-2) + 7n*(-2) = -70

4n + 20 - 10 - 14n = -70

4n - 14n + 20 - 10 = -70

- 10n + 10 = -70

Subtract 10 from both sides

-10n = -70 - 10

-10n = -80

Divide both sides by (-10)

n = -80/-10

n = 8

Step-by-step explanation:

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Answer:

8 pairs of large glasses and 12 pairs of small ones

Step-by-step explanation:

Let's say the number of large frames she buys is l, and the number of small frames is s. She buys 20 frames of assorted sizes, but they can only be small or large. Therefore, s + l = 20.

Next, the total cost of large frames is 12 dollars for each frame. Therefore, the total cost for the large frames is equal to 12 * l. Similarly, the total cost for the small frames is equal to 5 * s. The total cost of all frames is equal to 156, so

12* l + 5 * s = 156

s + l = 20

In the second equation, we can subtract l from both sides to get

s = 20 - l

We can then plug that into the first equation to get

12 * l + 5 * (20-l) = 156

12 * l + 100 - 5*l = 156

subtract both sides by 100 to isolate the variable and its coefficient

12 * l  -  5 * l = 56

7 * l = 56

divide both sides by 7 to isolate the l

l = 8

The woman buys 8 pairs of large glasses. The number of small glasses is equal to 20-l=20-8=12

Answer:

1. -6x + 14 < -28

6x<42

x<7

2.  3x + 28 < 25

3x < -3

x<-1

Hope This Helps!!!

Answer:

[tex]Pr = 0.153[/tex]

Step-by-step explanation:

Given

[tex]p = 15.3\%[/tex]

Required

Probability of alarm not working

[tex]p = 15.3\%[/tex] implies that the alarm has a probability of not working on a given day.

So, the probability that the alarm will not work on an exam date is:

[tex]Pr = 15.3\%[/tex]

Express as decimal

[tex]Pr = 0.153[/tex]

Answer:

Approximately [tex]4.75[/tex].

Step-by-step explanation:

Remark: this approach make use of the fact that in the original solution, the concentration of  [tex]\rm CH_3COOH[/tex] and [tex]\rm CH_3COO^{-}[/tex] are equal.

[tex]{\rm CH_3COOH} \rightleftharpoons {\rm CH_3COO^{-}} + {\rm H^{+}}[/tex]

Since [tex]\rm CH_3COONa[/tex] is a salt soluble in water. Once in water, it would readily ionize to give [tex]\rm CH_3COO^{-}[/tex] and [tex]\rm Na^{+}[/tex] ions.

Assume that the [tex]\rm CH_3COOH[/tex] and [tex]\rm CH_3COO^{-}[/tex] ions in this solution did not disintegrate at all. The solution would contain:

[tex]0.3\; \rm L \times 0.2\; \rm mol \cdot L^{-1} = 0.06\; \rm mol[/tex] of [tex]\rm CH_3COOH[/tex], and

[tex]0.06\; \rm mol[/tex] of [tex]\rm CH_3COO^{-}[/tex] from [tex]0.2\; \rm L \times 0.3\; \rm mol \cdot L^{-1} = 0.06\; \rm mol[/tex] of [tex]\rm CH_3COONa[/tex].

Accordingly, the concentration of [tex]\rm CH_3COOH[/tex] and [tex]\rm CH_3COO^{-}[/tex] would be:

[tex]\begin{aligned} & c({\rm CH_3COOH}) \\ &= \frac{n({\rm CH_3COOH})}{V} \\ &= \frac{0.06\; \rm mol}{0.5\; \rm L} = 0.12\; \rm mol \cdot L^{-1} \end{aligned}[/tex].

[tex]\begin{aligned} & c({\rm CH_3COO^{-}}) \\ &= \frac{n({\rm CH_3COO^{-}})}{V} \\ &= \frac{0.06\; \rm mol}{0.5\; \rm L} = 0.12\; \rm mol \cdot L^{-1} \end{aligned}[/tex].

In other words, in this buffer solution, the initial concentration of the weak acid [tex]\rm CH_3COOH[/tex] is the same as that of its conjugate base, [tex]\rm CH_3COO^{-}[/tex].

Hence, once in equilibrium, the [tex]\rm pH[/tex] of this buffer solution would be the same as the [tex]{\rm pK}_{a}[/tex] of [tex]\rm CH_3COOH[/tex].

Calculate the [tex]{\rm pK}_{a}[/tex] of [tex]\rm CH_3COOH[/tex] from its [tex]{\rm K}_{a}[/tex]:

[tex]\begin{aligned} & {\rm pH}(\text{solution}) \\ &= {\rm pK}_{a} \\ &= -\log_{10}({\rm K}_{a}) \\ &= -\log_{10} (1.76 \times 10^{-5}) \\ &\approx 4.75\end{aligned}[/tex].

Let the <C=x

We know in a triangle

☆Sum of angles=180°

[tex]\\ \sf\longmapsto 51+26+x=180[/tex]

[tex]\\ \sf\longmapsto 77+x=180[/tex]

[tex]\\ \sf\longmapsto x=180-77[/tex]

[tex]\\ \sf\longmapsto x=103°[/tex]

Answer:

Step-by-step explanation:

I have this saved on my computer in notepad b/c this type of question get asked sooo often :/

point P1 (-4,-2)  in the form (x1,y1)

point P2(3,1)  in the form (x2,y2)

slope = m

m = (y2-y1) / (x2-x1)

My suggestion is copy that above and save it on your computer for questions like this

now use it

Point 1  , P1 = (2,-4)   in the form (x1,y1)

Point 2 , P2 = (4,-1)  in the form (x2,y2)

m = [ -1-(-4) ]  /  [ 4-2]

m =  (-1+4) / 2

m = 3 / 2

so now we know the slope is  3/2  :)  

Step-by-step explanation:

√19200cm²

=138.56cm

then the highest possible volume

=(138.56)³

=2660195.926cm³

The largest possible volume of the box is; V = 25600 cm³

Let us denote the following of the square box;

Length = x

Width = y

height = h

Formula for volume of a box is;

V = length * width * height

Thus; V = xyh

but we are dealing with a square box and as such, the base sides are all equal and so; x = y. Thus;

V = x²h

The box has an open top and as such, the surface are of the box is;

S = x² + 4xh

We are given S = 19200 cm². Thus;

19200 = x² + 4xh

h = (19200 - x²)/4x

Put (19200 - x²)/4x for h in volume equation to get;

V = x²(19200 - x²)/4x

V = 4800x - 0.25x³

To get largest possible volume, it will be dimensions when dV/dx = 0. Thus;

dV/dx = 4800 - 0.75x²

At dV/dx = 0, we have;

4800 - 0.75x² = 0

0.75x² = 4800

x² = 4800/0.75

x² = 6400

x = √6400

x = 80 cm

From h = (19200 - x²)/4x;

h = (19200 - 80²)/(4 × 80)

h = (19200 - 6400)/3200

h = 4 cm

Largest possible volume = 80² × 4

Largest possible volume = 25600 cm³

Read more at; https://brainly.com/question/19053087

the median of restaurant b's cleanliness ratings is 2.

the median of restaurant b's food quality ratings is 4.

the median of restaurant b's service ratings is 3.

:))

Answer:

2

Step-by-step explanation:

8*8 is 64

Since it looks like the empty box is an exponent, and there are 2 8s being multiplied, the answer is 2

Answer:

The answer is $1.50/bottle.

Step-by-step explanation:

To get the unit price, you need to divide the total by the amount of bottles.

[tex]9.00/6=1.50[/tex]

Answer:

0.025 = 2.5% probability that a given class period runs between 51.25 and 51.5 minutes.

Step-by-step explanation:

Uniform probability distribution:

An uniform distribution has two bounds, a and b.

The probability of finding a value between c and d is:

[tex]P(c \leq X \leq d) = \frac{d - c}{b - a}[/tex]

Uniformly distributed between 47.0 and 57.0 minutes.

This means that [tex]a = 47, b = 57[/tex]

Find the probability that a given class period runs between 51.25 and 51.5 minutes.

[tex]P(c \leq X \leq d) = \frac{51.5 - 51.25}{57 - 47} = 0.025[/tex]

0.025 = 2.5% probability that a given class period runs between 51.25 and 51.5 minutes.

Answer:

Total earning last month with x articles is:

This is same amount as 2000

The equation is:

Step-by-step explanation:

3x-2x=5+10 [taking variables on one side and constant on other]

x=15

soln:

3x-5= 2x+10

3x -5+5=2x+10+5 [ adding 5 on both side]

3x=2x+15

3x-2x=2x+15-2x [subtracting 2x on both side]

x=15

Ans=15

Answer:

[tex]x = 15[/tex]

Step-by-step explanation:

[tex]3x - 5 = 10 + 2x[/tex]

[tex]3x - 2x = 10 + 5[/tex]

[tex]1x = 15[/tex]

[tex]x = 15[/tex]