T=3 and t=5 to determine if the expression 4(t+3) and 4 t+12 are equivalent

Answer:

..............................what this

Answer:

356 streams

Step-by-step explanation:

From the graph, you will see that the line cross the x-axis at x = 8.8

Substitute into the expression y = 40x + 4

y = 40(8.8)+4

y = 352 + 4

y = 356

Hence the distributor charges will be paid for after 356 streams

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Answer:

16 and 3

Step-by-step explanation:

Let x and y represent the positive integers. We know that

[tex]x + y = 19[/tex]

[tex]xy = 48[/tex]

Isolate the top equation for the x variable.

[tex]x = 19 - y[/tex]

Substitute into the second equation.

[tex](19 - y)y = 48[/tex]

[tex]19y - {y}^{2} = 48[/tex]

[tex] - {y}^{2} + 19y = 48[/tex]

[tex] - {y}^{2} + 19y - 48[/tex]

[tex](y - 16)(y - 3)[/tex]

So our values are

16 and 3.

Answer:

[tex]c =\frac{8}{3}[/tex]

Step-by-step explanation:

Given

[tex]c = \sqrt{\frac{4 + \sqrt 7}{4 - \sqrt 7}} + \sqrt{\frac{4 - \sqrt 7}{4 + \sqrt 7}}[/tex]

Required

Shorten

We have:

[tex]c = \sqrt{\frac{4 + \sqrt 7}{4 - \sqrt 7}} + \sqrt{\frac{4 - \sqrt 7}{4 + \sqrt 7}}[/tex]

Rationalize

[tex]c = \sqrt{\frac{4 + \sqrt 7}{4 - \sqrt 7} * \frac{4 + \sqrt 7}{4 + \sqrt 7}} + \sqrt{\frac{4 - \sqrt 7}{4 + \sqrt 7}*\frac{4 - \sqrt 7}{4 - \sqrt 7}}[/tex]

Expand

[tex]c = \sqrt{\frac{(4 + \sqrt 7)^2}{4^2 - (\sqrt 7)^2}} + \sqrt{\frac{(4 - \sqrt 7)^2}{4^2 - (\sqrt 7)^2}[/tex]

[tex]c = \sqrt{\frac{(4 + \sqrt 7)^2}{16 - 7}} + \sqrt{\frac{(4 - \sqrt 7)^2}{16 - 7}[/tex]

[tex]c = \sqrt{\frac{(4 + \sqrt 7)^2}{9}} + \sqrt{\frac{(4 - \sqrt 7)^2}{9}[/tex]

Take positive square roots

[tex]c =\frac{4 + \sqrt 7}{3} + \frac{4 - \sqrt 7}{3}[/tex]

Take LCM

[tex]c =\frac{4 + \sqrt 7 + 4 - \sqrt 7}{3}[/tex]

Collect like terms

[tex]c =\frac{4 + 4+ \sqrt 7 - \sqrt 7}{3}[/tex]

[tex]c =\frac{8}{3}[/tex]

Answer:

The answer is "[tex]\bold{\frac{22}{171}}[/tex]"

Step-by-step explanation:

There are 22 million males that have completed four years of undergraduate, according to the data below: (or more). This is predicated on a population of 171 million.

The chances we're searching about [tex]\frac{(22\ million)}{(171\ million)} = \frac{22}{171}[/tex]

however

This proportion could be further reduced because 22 and 171 have no common features (other than 1).

Step-by-step explanation:

the answer is in picture

it is helpful to you

Answer:

14 and 21 and 28

Step-by-step explanation:

2:3:4.

The shortest side is 14

14/2 = 7

Multiply each side by 7

2*7:3*7:4*7

14 : 21 : 28

Answer:

-[tex]x^{2} + 3x -8 = 0[/tex]

Step-by-step explanation:

Answer:

35 full bags

Step-by-step explanation:

$305-$35.75=$269.25

$269.25 divided by $7.50=35.9 bags (round off to lowest for number of full                                            bags)

9514 1404 393

Answer:

  d/15 = y/20

Step-by-step explanation:

At a given rate, distance is proportional to time. The distance d that Jack can drive in 15 minutes will be ...

 d/15 = y/20 . . . . the equation

  d = (3/4)y . . . . . the solution (multiply the above equation by 15, reduce)

Answer:

the domain is ALL reals numbers except ZERO

- ∞ < x < 0    ∪   0 <  x < ∞

Step-by-step explanation:

Answer:

(-∞,0) ∪ (0,∞), {x|x≠0}

Step-by-step explanation:

I think this is it. Im not completely sure though

9514 1404 393

Answer:

  3. 151°

  4. 42°

Step-by-step explanation:

3. The measure of the supplement is found by subtracting the angle from 180°.

  supplement of 29° = 180° -29° = 151°

__

4. The total of angles in a triangle is 180°, so the third one can be found by subtracting the other two from 180°.

  third angle = 180° -128° -10° = 42°

Answer:

0 senior tickets were sold

5 more adult tickets were sold than chil tickets

Step-by-step explanation:

You need to see the frequency of each bar

Answer by Gauthmath

Answer:

Step-by-step explanation:

Answer:

b=14 cm

Step-by-step explanation:

Use pythagorean equation

A^2+b^2=c^2

1^2+b^2=14^2

1+b^2=196

b^2=195

b=13.964

Answer:

let length be x

b = x - 3

perimeter = 2( l + b)

54 = 2(x+x-3)

27 = 2x - 3

30 = 2x

x = 15

l = 15

b = 15 - 3

b = 12

Answer:

3:5 = 6:10

3x2 : 5x2

= 6:10

Answer:

Step-by-step explanation:

Draw 3:5 balls shaded, and draw 6:10 balls shaded. Then, divide the 10 balls into two, with three shaded balls and 5 total balls on one side.

(3a^4b/2b^3)^3

cube all the terms:

3^3 = 27

b^3

(a^4)^3 = a^(4*3) = a^12

2^3 = 8

(b^3)^3 = b^3*3 = b^9

27a^12b^3 / 8b^9

Divide the b terms to get the final answer:

27a^12 / 8b^6

Answer:

Step-by-step explanation:

If the 2s are exponents, you need to indicate this with "^":  

x^2 = 144^2 means x² = 144²

x = ±√144² = ±144

Answer:

Step-by-step explanation:

f the 2s are exponents, you need to indicate this with "^":  

x^2 = 144^2 means x² = 144²

x = ±√144² = ±144

Answer:

-2.9 > w

Step-by-step explanation:

1.8>4.7+w

Subtract 4.7 from each side

1.8-4.7>4.7-4.7+w

-2.9 > w

Answer:

w = -2.9

Step-by-step explanation:

Answer: Hello your question is poorly written attached below is the complete question

answer:

[tex]y = \left[\begin{array}{ccc}-4\\-11\\5\end{array}\right][/tex]

[tex]x = \left[\begin{array}{ccc}16\\12\\-40\end{array}\right][/tex]

Step-by-step explanation:

[tex]y = \left[\begin{array}{ccc}-4\\-11\\5\end{array}\right][/tex]

[tex]x = \left[\begin{array}{ccc}16\\12\\-40\end{array}\right][/tex]

attached below is the detailed solution using LU factorization

Answer:

3 : 15 : 2

Step-by-step explanation:

Let cranberry juice = x,

3/4 + 1/10 + x = 1

x = 3/20

Ratio = cranberry : apple : orange

= 3/20 : 3/4 : 1/10

= 3 : 15 : 2 (Times everything with 20)

Answer:

Since [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex], the normal distribution can be used to approximate the binomial distribution.

The mean is 13.3 and the standard deviation is 3.28.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x successes on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

[tex]E(X) = np[/tex]

The standard deviation of the binomial distribution is:

[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]

Normal probability distribution

Problems of normally distributed distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that [tex]\mu = E(X)[/tex], [tex]\sigma = \sqrt{V(X)}[/tex], if [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex].

The probability than an adult never had the flu is 19%.

This means that [tex]p = 0.19[/tex]

You randomly select 70 adults and ask if he or she ever had the flu.

This means that [tex]n = 70[/tex]

Decide whether you can use the normal distribution to approximate the binomial distribution

[tex]np = 70*0.19 = 13.3 \geq 10[/tex]

[tex]n(1-p) = 70*0.81 = 56.7 \geq 10[/tex]

Since [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex], the normal distribution can be used to approximate the binomial distribution.

Mean:

[tex]\mu = E(X) = np = 70*0.19 = 13.3[/tex]

Standard deviation:

[tex]\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{70*0.19*0.81} = 3.28[/tex]

The mean is 13.3 and the standard deviation is 3.28.

Answer:

0

Step-by-step explanation:

it says the answer is zero

First integrate the indefinite integral,

[tex]\int(1-x^2)^{3/2}dx[/tex]

Let [tex]x=\sin(u)[/tex] which will make [tex]dx=\cos(u)du[/tex].

Then

[tex](1-x^2)^{3/2}=(1-\sin^2(u))^{3/2}=\cos^3(u)[/tex] which makes [tex]u=\arcsin(x)[/tex] and our integral is reshaped,

[tex]\int\cos^4(u)du[/tex]

Use reduction formula,

[tex]\int\cos^m(u)du=\frac{1}{m}\sin(u)\cos^{m-1}(u)+\frac{m-1}{m}\int\cos^{m-2}(u)du[/tex]

to get,

[tex]\int\cos^4(u)du=\frac{1}{4}\sin(u)\cos^3(u)+\frac{3}{4}\int\cos^2(u)du[/tex]

Notice that,

[tex]\cos^2(u)=\frac{1}{2}(\cos(2u)+1)[/tex]

Then integrate the obtained sum,

[tex]\frac{1}{4}\sin(u)\cos^3(u)+\frac{3}{8}\int\cos(2u)du+\frac{3}{8}\int1du[/tex]

Now introduce [tex]s=2u\implies ds=2du[/tex] and substitute and integrate to get,

[tex]\frac{3\sin(s)}{16}+\frac{1}{4}\sin(u)\cos^3(u)+\frac{3}{8}\int1du[/tex]

[tex]\frac{3\sin(s)}{16}+\frac{3u}{4}+\frac{1}{4}\sin(u)\cos^3(u)+C[/tex]

Substitute 2u back for s,

[tex]\frac{3u}{8}+\frac{1}{4}\sin(u)\cos^3(u)+\frac{3}{8}\sin(u)\cos(u)+C[/tex]

Substitute [tex]\sin^{-1}[/tex] for u and simplify with [tex]\cos(\arcsin(x))=\sqrt{1-x^2}[/tex] to get the result,

[tex]\boxed{\frac{1}{8}(x\sqrt{1-x^2}(5-2x^2)+3\arcsin(x))+C}[/tex]

Let [tex]F(x)=\frac{1}{8}(x\sqrt{1-x^2}(5-2x^2)+3\arcsin(x))+C[/tex]

Apply definite integral evaluation from b to a, [tex]F(x)\Big|_b^a[/tex],

[tex]F(x)\Big|_b^a=F(a)-F(b)=\boxed{\frac{1}{8}(a\sqrt{1-a^2}(5-2a^2)+3\arcsin(a))-\frac{1}{8}(b\sqrt{1-b^2}(5-2b^2)+3\arcsin(b))}[/tex]

Hope this helps :)

Answer:[tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{3arcsin(a) + 2a(1 - a^2)^\Big{\frac{3}{2}} + 3a\sqrt{1 - a^2}}{8} - \frac{3arcsin(b) + 2b(1 - b^2)^\Big{\frac{3}{2}} + 3b\sqrt{1 - b^2}}{8}[/tex]General Formulas and Concepts:

Pre-Calculus

Calculus

Differentiation

Integration

Integration Rule [Reverse Power Rule]:                                                               [tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]

Integration Rule [Fundamental Theorem of Calculus 1]:                                    [tex]\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)[/tex]

U-Substitution

Reduction Formula:                                                                                               [tex]\displaystyle \int {cos^n(x)} \, dx = \frac{n - 1}{n}\int {cos^{n - 2}(x)} \, dx + \frac{cos^{n - 1}(x)sin(x)}{n}[/tex]

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx[/tex]

Step 2: Integrate Pt. 1

Identify variables for u-substitution (trigonometric substitution).

Step 3: Integrate Pt. 2

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

Book: College Calculus 10e