Suppose you are given a text file. Design a Python3 program to encrypt/decrypt that text file as follows:
If the character is an upper case character then shift that character forward, s characters forward in the alphabet.
If the character is a lower case character then shift that character backwards, s characters backwards in the alphabet.
If the character is a numeric character then shift that character also backwards, s characters backwards in the 1-digit numbers set {0,1,2,3,4,5,6,7,8,9}.
You must design two functions; one to encrypt. The other one is to decrypt. All white space and punctuation marks must be ignored(cannot be changed). If you reach Z, or A, the shifting may continue as a cycle(A comes after Z, Z comes before A). Both files (original text file and the encrypted text file) must be stored in the working directory of Python.
An example;
Let s=1 and the text file:
11300Hello World
Then encoded text file;
002991dkkn Xnqke

Answers

Answer 1

Answer:

Explanation:

Please find attachment for the Python program


Related Questions

Describe how DMA is
used to
transfer data
from peripherals.

Answers

Answer:

Think of DMA as a co-processor that is used to quickly transfer data between main memory and peripherals without the intervention of the CPU.

Help its simple but I don't know the answer!!!

If you have a -Apple store and itunes gift card-

can you use it for in app/game purchases?

Answers

Answer:

yes you can do that it's utter logic

Answer:

Yes.

Explanation:

Itunes gift cards do buy you games/movies/In app purchases/ect.

You can use this area to create your resume.

Answers

Answer:

YOUR NAME

YOUR CITY, STATE, AND ZIP CODE

YOUR PHONE NUMBER

YOUR EMAIL

Professional Summary

Reliable, top-notch sales associate with outstanding customer service skills and relationship-building strengths. Dedicated to welcoming customers and providing comprehensive service. In-depth understanding of sales strategy and merchandising techniques. Dependable retail sales professional with experience in dynamic, high-performance environments. Skilled in processing transactions, handling cash, using registers and arranging merchandise. Maintains high-level customer satisfaction by smoothly resolving customer requests, needs and problems. Seasoned Sales Associate with consistent record of exceeding quotas in sales environments. Delivers exceptional customer service and product expertise to drive customer satisfaction ratings. Proficient in use and troubleshooting of POS systems.

Skills

Returns and Exchanges

Adaptable and Flexible

Excellent Written and Verbal Communication

Meeting Sales Goals

Strong Communication and Interpersonal Skills

Time Management

Cash Handling

Reliable and Responsible

Work History

March 2020 to September 2021

Goodwill OF YOUR STATE

Retail Sales Associate    

Helped customers complete purchases, locate items and join reward programs.

Checked pricing, scanned items, applied discounts and printed receipts to ring up customers.

Folded and arranged merchandise in attractive displays to drive sales.

Greeted customers and helped with product questions, selections and purchases.

Organized store merchandise racks and displays to promote and maintain visually appealing environments.

Monitored sales floor and merchandise displays for presentable condition, taking corrective action such as restocking or reorganizing products.

Balanced and organized cash register by handling cash, counting change and storing coupons.

Trained new associates on cash register operations, conducting customer transactions and balancing drawer.

Answered questions about store policies and addressed customer concerns.

Issued receipts and processed refunds, credits or exchanges.

Maintained clean sales floor and straightened and faced merchandise.

Education

YOUR HIGH SCHOOL THAT YOU ATTEND  

Languages

Spanish

Explanation:

THIS IS MY RESUME IF YOU HAVE MORE WORK EXPERIENCE THEN ADD IT AFTER THE GOODWILL. I GOT A 100% ON EDGE.


(a) What is the difference between a compare validator and a range validator?

(b) When would you choose to use one versus the other?

Answers

Answer:

Check the explanation

Explanation:

a) A compare validator: A compare validator can be described as a particular method that is utilized to control and also enabled to perform different types of validation tasks. It is being used to carry out as well as to execute a correct data type that determines the entered value is proper value into a form field or not. For instance when in an application registration it makes use of the confirm password after the first-password.

(b) Whenever it is compulsory to determine if the value that has been entered is the correct value into the form field then the usage of compare validator will be needed whereas a range validator is used to confirm the entered value is in a specific range.

Explanation:

a) A compare validator: A compare validator can be described as a particular method that is utilized to control and also enabled to perform different types of validation tasks. It is being used to carry out as well as to execute a correct data type that determines the entered value is proper value into a form field or not. For instance when in an application registration it makes use of the confirm password after the first-password.

(b) Whenever it is compulsory to determine if the value that has been entered is the correct value into the form field then the usage of compare validator will be needed whereas a range validator is used to confirm the entered value is in a specific range.

In this question, we give two implementations for the function: def intersection_list(lst1, lst2) This function is given two lists of integers lst1 and lst2. When called, it will create and return a list containing all the elements that appear in both lists. For example, the call: intersection_list([3, 9, 2, 7, 1], [4, 1, 8, 2])could create and return the list [2, 1]. Note: You may assume that each list does not contain duplicate items. a) Give an implementation for intersection_list with the best worst-case runtime. b) Give an implementation for intersection_list with the best average-case runtime.

Answers

Answer:

see explaination

Explanation:

a)Worst Case-time complexity=O(n)

def intersection_list(lst1, lst2):

lst3 = [value for value in lst1 if value in lst2]

return lst3

lst1 = []

lst2 = []

n1 = int(input("Enter number of elements for list1 : "))

for i in range(0, n1):

ele = int(input())

lst1.append(ele) # adding the element

n2 = int(input("Enter number of elements for list2 : "))

for i in range(0, n2):

ele = int(input())

lst2.append(ele) # adding the element

print(intersection_list(lst1, lst2))

b)Average case-time complexity=O(min(len(lst1), len(lst2))

def intersection_list(lst1, lst2):

return list(set(lst1) & set(lst2))

lst1 = []

lst2 = []

n1 = int(input("Enter number of elements for list1 : "))

for i in range(0, n1):

ele = int(input())

lst1.append(ele)

n2 = int(input("Enter number of elements for list2 : "))

for i in range(0, n2):

ele = int(input())

lst2.append(ele)

print(intersection_list(lst1, lst2))

Which of the following should be the first page of a report?
O Title page
Introduction
O Table of contents
Terms of reference

Answers

Answer:

Title page should be the first page of a report.

hope it helps!

A cloud provider is deploying a new SaaS product comprised of a cloud service. As part of the deployment, the cloud provider wants to publish a service level agreement (SLA) that provides an availability rating based on its estimated availability over the next 12 months. First, the cloud provider estimates that, based on historical data of the cloud environment, there is a 25% chance that the physical server hosting the cloud service will crash and that such a crash would take 2 days before the cloud service could be restored. It is further estimated that, over the course of a 12 month period, there will be various attacks on the cloud service, resulting in a total of 24 hours of downtime. Based on these estimates, what is the availability rating of the cloud service that should be published in the SLA?

Answers

Answer:

99.6

Explanation:

The cloud provider  provides the certain modules of the cloud service like infrastructure as a service , software as a service ,etc to other companies .The cloud provider implements a new SaaS service that includes a cloud platform also the cloud provider intends to disclose the Service Level Agreement that is score based on its approximate accessibility during the next 12 months.

The Cloud providers predict that, depending on past cloud system data, it is a 25 % risk that a physical server holding the cloud platform will fail therefore such a failure will require 2 days to recover the cloud service so 99.6 is the Cloud storage accessibility ranking, to be released in the SLA.

Evaluati urmatoarele expresii


5+2*(x+4)/3, unde x are valoare 18


7/ 2*2+4*(5+7*3)>18


2<=x AND x<=7 , unde x are valoare 23


50 %10*5=


31250/ 5/5*2=

Answers

Answer:

A) 22 ⅓

B) 111>18

C) There is an error in the expression

D) 25

E) 62500

Question:

Evaluate the following expressions

A) 5 + 2 * (x + 4) / 3, where x has a value of 18

B) 7/2 * 2 + 4 * (5 + 7 * 3) & gt; 18

C) 2 <= x AND x<= 7, where x has value 23

D) 50% 10 * 5 =

F) 31250/5/5 * 2 =

Explanation:

A) 5 + 2 * (x + 4) / 3

x = 18

First we would insert the value of x

5 + 2 * (x + 4) / 3

5 + 2(18 + 8) / 3

Then we would evaluate the expression by applying BODMAS : This stands for Bracket, Of, Division, Multiplication, addition and subtraction.

= 5 + 2(26) / 3

= 5 + 52/3

= 5 + 17 ⅓

= 22 ⅓

B) 7/2 * 2 + 4 * (5 + 7 * 3) > 18

we would evaluate the expression by applying BODMAS : This stands for Bracket, Of, Division, Multiplication, addition and subtraction.

7/2 * 2 + 4 * (5 + 7 * 3) >18

= 7/2 × 2 + 4× (5 + 7 × 3)>18

= (7×2)/2 + 4× (5+21) >18

= 14/2 + 4(26) >18

= 7 + 104 >18

= 111>18

C) 2 <= x AND x<= 7, where x has value 23

There is an error in the expression

D) 50% of 10 * 5

we would evaluate the expression by applying BODMAS : This stands for Bracket, Of, Division, Multiplication, addition and subtraction.

The 'of' expression means multiplication

= 50% × 10×5

= 50% × 50

50% = 50/100

=50/100 × 50

= 1/2 × 50

= 25

F) 31250/5/5 * 2

The expression has no demarcation. Depending on how it is broken up, we would arrive at different answers. Let's consider:

31250/(5/5 × 2)

Apply BODMAS

= 31250/[5/(5 × 2)]

= 31250/(5/10)

= 31250/(1/2)

Multiply by the inverse of 1/2 = 2/1

= 31250 × (2/1)

= 62500

You work at a cheeseburger restaurant. Write a program that determines appropriate changes to a food order based on the user’s dietary restrictions. Prompt the user for their dietary restrictions: vegetarian, lactose intolerant, or none. Then using if statements and else statements, print the cook a message describing how they should modify the order. The following messages should be used: - If the user enters "lactose intolerant", say "No cheese." - If the user enters "vegetarian", say "Veggie burger." - If the user enters "none", say "No alterations."

Answers

Answer:

See explaination

Explanation:

dietary_restrictions = input("Any dietary restrictions?: ")

if dietary_restrictions=="lactose intolerant":

print("No cheese")

elif dietary_restrictions == "vegetarian":

print("Veggie burger")

else:

print("No alteration")

6. Why did he choose to install the window not totally plumb?

Answers

Answer:

Because then it would break

Explanation:

You achieve this by obtaining correct measurements. When measuring a window, plumb refers to the vertical planes, and level refers to the horizontal planes. So he did not install the window totally plumb

Design an application for Bob's E-Z Loans. The application accepts a client's loan amount and monthly payment amount. Output the customer's loan balance each month until the loan is paid off. b. Modify the Bob's E-Z Loans application so that after the payment is made each month, a finance charge of 1 percent is added to the balance.

Answers

Answer:

part (a).

The program in cpp is given below.

#include <stdio.h>

#include <iostream>

using namespace std;

int main()

{

   //variables to hold balance and monthly payment amounts

   double balance;

   double payment;

   //user enters balance and monthly payment amounts

   std::cout << "Welcome to Bob's E-Z Loans application!" << std::endl;

   std::cout << "Enter the balance amount: ";

   cin>>balance;

   std::cout << "Enter the monthly payment: ";

   cin>>payment;

   std::cout << "Loan balance: " <<" "<< "Monthly payment: "<< std::endl;

   //balance amount and monthly payment computed

   while(balance>0)

   {

       if(balance<payment)    

         { payment = balance;}

       else

       {  

           std::cout << balance <<"\t\t\t"<< payment << std::endl;

           balance = balance - payment;

       }

   }

   return 0;

}

part (b).

The modified program from part (a), is given below.

#include <stdio.h>

#include <iostream>

using namespace std;

int main()

{

   //variables to hold balance and monthly payment amounts

   double balance;

   double payment;

   double charge=0.01;

   //user enters balance and monthly payment amounts

   std::cout << "Welcome to Bob's E-Z Loans application!" << std::endl;

   std::cout << "Enter the balance amount: ";

   cin>>balance;

   std::cout << "Enter the monthly payment: ";

   cin>>payment;

   balance = balance +( balance*charge );

   std::cout << "Loan balance with 1% finance charge: " <<" "<< "Monthly payment: "<< std::endl;

   //balance amount and monthly payment computed

   while(balance>payment)

   {

           std::cout << balance <<"\t\t\t\t\t"<< payment << std::endl;

           balance = balance +( balance*charge );

           balance = balance - payment;

       }

   if(balance<payment)    

         { payment = balance;}          

   std::cout << balance <<"\t\t\t\t\t"<< payment << std::endl;

   return 0;

}

Explanation:

1. The variables to hold the loan balance and the monthly payment are declared as double.

2. The program asks the user to enter the loan balance and monthly payment respectively which are stored in the declared variables.  

3. Inside a while loop, the loan balance and monthly payment for each month is computed with and without finance charges in part (a) and part (b) respectively.

4. The computed values are displayed for each month till the loan balance becomes zero.

5. The output for both part (a) and part (b) are attached as images.

Create a Binary Expressions Tree Class and create a menu driven programyour program should be able to read multiple expressions from a file and create expression trees for each expression, one at a timethe expression in the file must be in "math" notation, for example x+y*a/b.display the preorder traversal of a binary tree as a sequence of strings each separated by a tabdisplay the postorder traversal of a binary tree in the same form as aboveWrite a function to display the inorder traversal of a binary tree and place a (before each subtree and a )after each subtree. Don’t display anything for an empty subtree. For example, the expression tree should would be represented as ( (x) + ( ( (y)*(a) )/(b) ) )

Answers

Answer:

Explanation:

Program:

#include<iostream>

#include <bits/stdc++.h>

using namespace std;

//check for operator

bool isOperator(char c)

{

switch(c)

{

case '+': case '-': case '/': case '*': case '^':

return true;

}

return false;

}

//Converter class

class Converter

{

private:

string str;

public:

//constructor

Converter(string s):str(s){}

//convert from infix to postfix expression

string toPostFix(string str)

{

stack <char> as;

int i, pre1, pre2;

string result="";

as.push('(');

str = str + ")";

for (i = 0; i < str.size(); i++)

{

char ch = str[i];

if(ch==' ') continue;

if (ch == '(')

as.push(ch);

else if (ch == ')')

{

while (as.size() != 0 && as.top() != '('){

result = result + as.top() + " ";

as.pop();

}

as.pop();

}

else if(isOperator(ch))

{

while (as.size() != 0 && as.top() != '(')

{

pre1 = precedence(ch);

pre2 = precedence(as.top());

if (pre2 >= pre1){

result = result + as.top() + " ";

as.pop();

}

else break;

}

as.push(ch);

}

else

{

result = result + ch;

}

}

while(as.size() != 0 && as.top() != '(') {

result += as.top() + " ";

as.pop();

}

return result;

}

//return the precedence of an operator

int precedence(char ch)

{

int choice = 0;

switch (ch) {

case '+':

choice = 0;

break;

case '-':

choice = 0;

break;

case '*':

choice = 1;

break;

case '/':

choice = 1;

break;

case '^':

choice = 2;

default:

choice = -999;

}

return choice;

}

};

//Node class

class Node

{

public:

string element;

Node *leftChild;

Node *rightChild;

//constructors

Node (string s):element(s),leftChild(nullptr),rightChild(nullptr) {}

Node (string s, Node* l, Node* r):element(s),leftChild(l),rightChild(r) {}

};

//ExpressionTree class

class ExpressionTree

{

public:

//expression tree construction

Node* covert(string postfix)

{

stack <Node*> stk;

Node *t = nullptr;

for(int i=0; i<postfix.size(); i++)

{

if(postfix[i]==' ') continue;

string s(1, postfix[i]);

t = new Node(s);

if(!isOperator(postfix[i]))

{

stk.push(t);

}

else

{

Node *r = nullptr, *l = nullptr;

if(!stk.empty()){

r = stk.top();

stk.pop();

}

if(!stk.empty()){

l = stk.top();

stk.pop();

}

t->leftChild = l;

t->rightChild = r;

stk.push(t);

}

}

return stk.top();

}

//inorder traversal

void infix(Node *root)

{

if(root!=nullptr)

{

cout<< "(";

infix(root->leftChild);

cout<<root->element;

infix(root->rightChild);

cout<<")";

}

}

//postorder traversal

void postfix(Node *root)

{

if(root!=nullptr)

{

postfix(root->leftChild);

postfix(root->rightChild);

cout << root->element << " ";

}

}

//preorder traversal

void prefix(Node *root)

{

if(root!=nullptr)

{

cout<< root->element << " ";

prefix(root->leftChild);

prefix(root->rightChild);

}

}

};

//main method

int main()

{

string infix;

cout<<"Enter the expression: ";

cin >> infix;

Converter conv(infix);

string postfix = conv.toPostFix(infix);

cout<<"Postfix Expression: " << postfix<<endl;

if(postfix == "")

{

cout<<"Invalid expression";

return 1;

}

ExpressionTree etree;

Node *root = etree.covert(postfix);

cout<<"Infix: ";

etree.infix(root);

cout<<endl;

cout<<"Prefix: ";

etree.prefix(root);

cout<<endl;

cout<< "Postfix: ";

etree.postfix(root);

cout<<endl;

return 0;

}

Implement the function get_stats The function get_stats calculates statistics on a sample of values. It does the following: its input parameter is a csv string a csv (comma separated values) string contains a list of numbers (the sample) return a tuple that has 3 values: (n, stdev, mean) tuple[0] is the number of items in the sample tuple[1] is the standard deviation of the sample tuple[2] is the mean of the sample

Answers

Answer:

Check the explanation

Explanation:

PYTHON CODE: (lesson.py)

import statistics

# function to find standard deviation, mean

def get_stats(csv_string):

   # calling the function to clean the data

   sample=clean(csv_string)

   # finding deviation, mean

   std_dev=statistics.stdev(sample)

   mean=statistics.mean(sample)

   # counting the element in sample

   count=len(sample)

   # return the results in a tuple

   return (count, std_dev, mean)

# function to clean the csv string

def clean(csv_string):

   # temporary list

   t=[]

   # splitting the string by comma

   data=csv_string.split(',')

 

   # looping item in data list

   for item in data:

       # removing space,single quote, double quote

       item=item.strip()

       item= item.replace("'",'')

       item= item.replace('"','')

       # if the item is valid      

       if item:

           # converting into float

           try:

             

               t.append(float(item))

           except:

               continue

   # returning the list of float

   return t

if __name__=='__main__':

   csv = "a, 1, '-2', 2.35, None,, 4, True"

   print(clean(csv))

   print(get_stats('1.0,2.0,3.0'))

TRUE OR FALSE! HELP!!

Answers

Answer:

True

Explanation:

There's no one law that governs internet privacy.

Write a statement that calls the recursive method backwardsAlphabet() with parameter startingLetter.
import java.util.Scanner; public class RecursiveCalls { public static void backwardsAlphabet(char currLetter) { if (currLetter == 'a') { System.out.println(currLetter); } else { System.out.print(currLetter + " "); backwardsAlphabet((char)(currLetter - 1)); } } public static void main (String [] args) { Scanner scnr = new Scanner(System.in); char startingLetter; startingLetter = scnr.next().charAt(0); /* Your solution goes here */ } }

Answers

Answer:

Following are the code to method calling

backwardsAlphabet(startingLetter); //calling method backwardsAlphabet

Output:

please find the attachment.

Explanation:

Working of program:

In the given java code, a class "RecursiveCalls" is declared, inside the class, a method that is "backwardsAlphabet" is defined, this method accepts a char parameter that is "currLetter". In this method a conditional statement is used, if the block it will check input parameter value is 'a', then it will print value, otherwise, it will go to else section in this block it will use the recursive function that prints it's before value. In the main method, first, we create the scanner class object then defined a char variable "startingLetter", in this we input from the user and pass its value into the method that is "backwardsAlphabet".

the smallest unit of time in music called?

Answers

Answer:

Ready to help ☺️

Explanation:

A tatum is a feature of music that has been defined as the smallest time interval between notes in a rhythmic phrase.

Answer:

A tatum bc is a feature of music that has been variously defined as the smallest time interval between successive notes in a rhythmic phrase "the shortest durational value

Trace the complete execution of the MergeSort algorithm when called on the array of integers, numbers, below. Show the resulting sub-arrays formed after each call to merge by enclosing them in { }. For example, if you originally had an array of 5 elements, a = {5,2,8,3,7}, the first call to merge would result with: {2, 5} 8, 3, 7 ← Note after the first call to merge, two arrays of size 1 have been merged into the sorted subarray {2,5} and the values 2 and 5 are sorted in array a You are to do this trace for the array, numbers, below. Be sure to show the resulting sub-arrays after each call to MergeSort. int[] numbers = {23, 14, 3, 56, 17, 8, 42, 18, 5};

Answers

Answer:

public class Main {

public static void merge(int[] arr, int l, int m, int r) {

int n1 = m - l + 1;

int n2 = r - m;

int[] L = new int[n1];

int[] R = new int[n2];

for (int i = 0; i < n1; ++i)

L[i] = arr[l + i];

for (int j = 0; j < n2; ++j)

R[j] = arr[m + 1 + j];

int i = 0, j = 0;

int k = l;

while (i < n1 && j < n2) {

if (L[i] <= R[j]) {

arr[k] = L[i];

i++;

} else {

arr[k] = R[j];

j++;

}

k++;

}

while (i < n1) {

arr[k] = L[i];

i++;

k++;

}

while (j < n2) {

arr[k] = R[j];

j++;

k++;

}

printArray(arr, l, r);

}

public static void sort(int[] arr, int l, int r) {

if (l < r) {

int m = (l + r) / 2;

sort(arr, l, m);

sort(arr, m + 1, r);

merge(arr, l, m, r);

}

}

static void printArray(int[] arr, int l, int r) {

System.out.print("{");

for (int i = l; i <= r; ++i)

System.out.print(arr[i] + " ");

System.out.println("}");

}

public static void main(String[] args) {

int[] arr = {23, 14, 3, 56, 17, 8, 42, 18, 5};

sort(arr, 0, arr.length - 1);

}

}

Explanation:

See answer

The relationship between the temperature of a fluid (t, in seconds), temperature (T, in degrees Celsius), is dependent upon the initial temperature of the liquid (T0, in degrees Celsius), the ambient temperature of the surroundings (TA, in degrees Celsius) and the cooling constant (k, in hertz); the relationship is given by: ???? ???? ???????? ???? ???????????? ???? ???????????? ???????????????? Ask the user the following questions:  From a menu, choose fluid ABC, FGH, or MNO.  Enter the initial fluid temperature, in units of degrees Celsius.  Enter the time, in units of minutes.  Enter the ambient air temperature, in units of degrees Celsius. Enter the following data into the program. The vector contains the cooling constant (k, units of hertz) corresponding to the menu entries. K Values = [0.01, 0.03, 0.02] Create a formatted output statement for the user in the Command Window similar to the following. The decimal places must match. ABC has temp 83.2 degrees Celsius after 3 minutes. In

Answers

Answer:

See explaination

Explanation:

clc;

clear all;

close all;

x=input(' choose abc or fgh or mno:','s');

to=input('enter intial fluid temperature in celcius:');

t1=input('enter time in minutes:');

ta=input('enter ambient temperature in celcius:');

abc=1;

fgh=2;

mno=3;

if x==1

k=0.01;

elseif x==2

k=0.03;

else

k=0.02;

end

t=ta+((to-ta)*exp((-k)*t1));

X = sprintf('%s has temp %f degrees celcius after %d minutes.',x,t,t1);

disp(X);

Algorithmic Complexity: what is the asymptotic complexity (Big-O) of each code section? Identify the critical section of each.\ Line 1: for (int i=0; i<532; i++) { f(n) = O( ) Line 2: for (int j=1; j

Answers

Answer:

Check the explanation

Explanation:

1) f(n) = O( 1 ), since the loops runs a constant number of times independent of any input size

there is no critical section in the code, as a critical section is some part of code which is shared by multiple threads or even processes to modify any shared variable.This code does not contain any variable which can be shared.

2) f(n) = O( log n! ), the outer loop runs for n times, and the inner loop runs log k times when i = k,ie the total number of print will be – log 1 + log2 +log3 +log4+…...+ log n = log (1 . 2 . 3 . 4 . ……. . n ) =log n!

there is no critical section in the code, as a critical section is some part of code which is shared by multiple threads or even processes to modify any shared variable.This code does not contain any variable which can be shared.

Note : Log (m *n) = Log m + Log n : this is property of logarithm

3) f(n) = [tex]O( n^2 )[/tex], since both outer and inner loop runs n times hence , the total iterations of print statement will be : n +n+n+…+n

for n times, this makes the complexity – n * n = n2

there is no critical section in the code, as a critical section is some part of code which is shared by multiple threads or even processes to modify any shared variable.This code does not contain any variable which can be shared.

"Write pseudocode that outputs the contents of parallel arrays. You do NOT have to write the entire program. The first array will hold phone numbers The second array will hold company names You do NOT need to load the arrays. Your code can assume they are already loaded with data. The arrays are named phone[ ] and company[ ] Output the phone number and associated company name for every entry in the array."

Answers

Answer:

Check the explanation

Explanation:

PSEUDO CODE:

for(int i=0,j=0;i<phone.length,j<company.length;i++,j++)

{

print(phone[i]," - ",company[j]);

}

this for loop will print each phone number associated with the company names.

Donnell backed up the information on his computer every week on a flash drive. Before copying the files to the flash drive, he always ran a virus scan against the files to ensure that no viruses were being copied to the flash drive. He bought a new computer and inserted the flash drive so that he could transfer his files onto the new computer. He got a message on the new computer that the flash drive was corrupted and unreadable; the information on the flash drive cannot be retrieved. Assuming that the flash drive is not carrying a virus, which of the following does this situation reflect?
a. Compromise of the security of the information on the flash drive
b. Risk of a potential breach in the integrity of the data on the flash drive
c. Both of the above
d. Neither of the above.

Answers

Answer:

b. Risk of a potential breach in the integrity of the data on the flash drive

Explanation:

The corrupted or unreadable file error is an error message generated if you are unable to access the external hard drive connected to the system through the USB port. This error indicates that the files on the external hard drive are no longer accessible and cannot be opened.

There are several reasons that this error message can appear:

Viruses and Malware affecting the external hard drive .Physical damage to external hard drive or USB memory .Improper ejection of removable drives.

Zoom Vacuum, a family-owned manufacturer of high-end vacuums, has grown exponentially over the last few years. However, the company is having difficulty preparing for future growth. The only information system used at Zoom is an antiquated accounting system. The company has one manufacturing plant located in Iowa; and three warehouses, in Iowa, New Jersey, and Nevada. The Zoom sales force is national, and Zoom purchases about 25 percent of its vacuum parts and materials from a single overseas supplier. You have been hired to recommend the information systems Zoom should implement in order to maintain their competitive edge. However, there is not enough money for a full-blown, cross-functional enterprise application, and you will need to limit the first step to a single functional area or constituency. What will you choose, and why?

Answers

Answer:A TPS focusing on production and manufacturing to keep production costs low while maintaining quality, and for communicating with other possible vendors. The TPS would later be used to feed MIS and other higher level systems.

Explanation:

Write a program with total change amount as an integer input that outputs the change using the fewest coins, one coin type per line. The coin types are dollars, quarters, dimes, nickels, and pennies. Use singular and plural coin names as appropriate, like 1 penny vs. 2 pennies. Ex: If the input is: 0 or less, the output is: no change Ex: If the input is: 45 the output is: 1 quarter 2 dimes

Answers

Answer:.

// Program is written in C++.

// Comments are used for explanatory purposes

// Program starts here..

#include<iostream>

using namespace std;

int main()

{

// Declare Variables

int amount, dollar, quarter, dime, nickel, penny;

// Prompt user for input

cout<<"Amount: ";

cin>>amount;

// Check if input is less than 1

if(amount<=0)

{

cout<<"No Change";

}

else

{

// Convert amount to various coins

dollar = amount/100;

amount = amount%100;

quarter = amount/25;

amount = amount%25;

dime = amount/10;

amount = amount%10;

nickel = amount/5;

penny = amount%5;

// Print results

if(dollar>=1)

{

if(dollar == 1)

{

cout<<dollar<<" dollar\n";

}

else

{

cout<<dollar<<" dollars\n";

}

}

if(quarter>=1)

{

if(quarter== 1)

{

cout<<quarter<<" quarter\n";

}

else

{

cout<<quarter<<" quarters\n";

}

}

if(dime>=1)

{

if(dime == 1)

{

cout<<dime<<" dime\n";

}

else

{

cout<<dime<<" dimes\n";

}

}

if(nickel>=1)

{

if(nickel == 1)

{

cout<<nickel<<" nickel\n";

}

else

{

cout<<nickel<<" nickels\n";

}

}

if(penny>=1)

{

if(penny == 1)

{

cout<<penny<<" penny\n";

}

else

{

cout<<penny<<" pennies\n";

}

}

}

return 0;

}

#define DIRECTN 100
#define INDIRECT1 20
#define INDIRECT2 5
#define PTRBLOCKS 200

typedef struct {
filename[MAXFILELEN];
attributesType attributes; // file attributes
uint32 reference_count; // Number of hard links
uint64 size; // size of file
uint64 direct[DIRECTN]; // direct data blocks
uint64 indirect[INDIRECT1]; // single indirect blocks
uint64 indirect2[INDIRECT2]; // double indirect

} InodeType;

Single and double indirect inodes have the following structure:

typedef struct
{
uint64 block_ptr[PTRBLOCKS];
}
IndirectNodeType;

Required:
Assuming a block size of 0x1000 bytes, write pseudocode to return the block number associated with an offset of N bytes into the file.

Answers

Answer:

WOW! that does not look easy!

Explanation:

I wish i could help but i have no idea how to do that lol

write the steps to insert picture water mark​

Answers

Answer:

Is there a picture of the question?

Explanation:

Create a macro named mReadInt that reads a 16- or 32-bit signed integer from standard input and returns the value in an argument. Use conditional operators to allow the macro to adapt to the size of the desired result. Write a program that tests the macro, passing it operands of various sizes.

Answers

Answer:

;Macro mReadInt definition, which take two parameters

;one is the variable to save the number and other is the length

;of the number to read (2 for 16 bit and 4 for 32 bit) .

%macro mReadInt 2

mov eax,%2

cmp eax, "4"

je read2

cmp eax, "2"

je read1

read1:

mReadInt16 %1

cmp eax, "2"

je exitm

read2:

mReadInt32 %1

exitm:

xor eax, eax

%endmacro

;macro to read the 16 bit number, parameter is number variable

%macro mReadInt16 1

mov eax, 3

mov ebx, 2

mov ecx, %1

mov edx, 5

int 80h

%endmacro

;macro to read the 32 bit number, parameter is number variable

%macro mReadInt32 1

mov eax, 3

mov ebx, 2

mov ecx, %1

mov edx, 5

int 80h

%endmacro

;program to test the macro.

;data section, defining the user messages and lenths

section .data

userMsg db 'Please enter the 32 bit number: '

lenUserMsg equ $-userMsg

userMsg1 db 'Please enter the 16 bit number: '

lenUserMsg1 equ $-userMsg1

dispMsg db 'You have entered: '

lenDispMsg equ $-dispMsg

;.bss section to declare variables

section .bss

;num to read 32 bit number and num1 to rad 16-bit number

num resb 5

num1 resb 3

;.text section

section .text

;program start instruction

global _start

_start:

;Displaying the message to enter 32bit number

mov eax, 4

mov ebx, 1

mov ecx, userMsg

mov edx, lenUserMsg

int 80h

;calling the micro to read the number

mReadInt num, 4

;Printing the display message

mov eax, 4

mov ebx, 1

mov ecx, dispMsg

mov edx, lenDispMsg

int 80h

;Printing the 32-bit number

mov eax, 4

mov ebx, 1

mov ecx, num

mov edx, 4

int 80h

;displaying message to enter the 16 bit number

mov eax, 4

mov ebx, 1

mov ecx, userMsg1

mov edx, lenUserMsg1

int 80h

;macro call to read 16 bit number and to assign that number to num1

;mReadInt num1,2

;calling the display mesage function

mov eax, 4

mov ebx, 1

mov ecx, dispMsg

mov edx, lenDispMsg

int 80h

;Displaying the 16-bit number

mov eax, 4

mov ebx, 1

mov ecx, num1

mov edx, 2

int 80h

;exit from the loop

mov eax, 1

mov ebx, 0

int 80h

Explanation:

For an assembly code/language that has the conditions given in the question, the program that tests the macro, passing it operands of various sizes is given below;

;Macro mReadInt definition, which take two parameters

;one is the variable to save the number and other is the length

;of the number to read (2 for 16 bit and 4 for 32 bit) .

%macro mReadInt 2

mov eax,%2

cmp eax, "4"

je read2

cmp eax, "2"

je read1

read1:

mReadInt16 %1

cmp eax, "2"

je exitm

read2:

mReadInt32 %1

exitm:

xor eax, eax

%endmacro

;macro to read the 16 bit number, parameter is number variable

%macro mReadInt16 1

mov eax, 3

mov ebx, 2

mov ecx, %1

mov edx, 5

int 80h

%endmacro

;macro to read the 32 bit number, parameter is number variable

%macro mReadInt32 1

mov eax, 3

mov ebx, 2

mov ecx, %1

mov edx, 5

int 80h

%endmacro

;program to test the macro.

;data section, defining the user messages and lenths

section .data

userMsg db 'Please enter the 32 bit number: '

lenUserMsg equ $-userMsg

userMsg1 db 'Please enter the 16 bit number: '

lenUserMsg1 equ $-userMsg1

dispMsg db 'You have entered: '

lenDispMsg equ $-dispMsg

;.bss section to declare variables

section .bss

;num to read 32 bit number and num1 to rad 16-bit number

num resb 5

num1 resb 3

;.text section

section .text

;program start instruction

global _start

_start:

;Displaying the message to enter 32bit number

mov eax, 4

mov ebx, 1

mov ecx, userMsg

mov edx, lenUserMsg

int 80h

;calling the micro to read the number

mReadInt num, 4

;Printing the display message

mov eax, 4

mov ebx, 1

mov ecx, dispMsg

mov edx, lenDispMsg

int 80h

;Printing the 32-bit number

mov eax, 4

mov ebx, 1

mov ecx, num

mov edx, 4

int 80h

;displaying message to enter the 16 bit number

mov eax, 4

mov ebx, 1

mov ecx, userMsg1

mov edx, lenUserMsg1

int 80h

;macro call to read 16 bit number and to assign that number to num1

;mReadInt num1,2

;calling the display mesage function

mov eax, 4

mov ebx, 1

mov ecx, dispMsg

mov edx, lenDispMsg

int 80h

;Displaying the 16-bit number

mov eax, 4

mov ebx, 1

mov ecx, num1

mov edx, 2

int 80h

;exit from the loop

mov eax, 1

mov ebx, 0

int 80h

How can u refer to additional information while giving a presentation

Answers

Answer:

There are various ways: Handing out papers/fliers to people, or presenting slides.

Write a functionvector merge(vector a, vector b)that merges two vectors, alternating elements from both vectors. If one vector isshorter than the other, then alternate as long as you can and then append the remaining elements from the longer vector. For example, if a is 1 4 9 16and b is9 7 4 9 11then merge returns the vector1 9 4 7 9 4 16 9 1118. Write a predicate function bool same_elements(vector a, vector b)that checks whether two vectors have the same elements in some order, with the same multiplicities. For example, 1 4 9 16 9 7 4 9 11 and 11 1 4 9 16 9 7 4 9 would be considered identical, but1 4 9 16 9 7 4 9 11 and 11 11 7 9 16 4 1 would not. You will probably need one or more helper functions.19. What is the difference between the size and capacity of a vector

Answers

Answer:

see explaination for code

Explanation:

CODE

#include <iostream>

#include <vector>

using namespace std;

vector<int> merge(vector<int> a, vector<int> b) {

vector<int> result;

int k = 0;

int i = 0, j = 0;

while (i < a.size() && j < b.size()) {

if (k % 2 == 0) {

result.push_back(a[i ++]);

} else {

result.push_back(b[j ++]);

}

k ++;

}

while (i < a.size()) {

result.push_back(a[i ++]);

}

while(j < b.size()) {

result.push_back(b[j ++]);

}

return result;

}

int main() {

vector<int> a{1, 4, 9, 16};

vector<int> b{9, 7, 4, 9, 11};

vector<int> result = merge(a, b);

for (int i=0; i<result.size(); i++) {

cout << result[i] << " ";

}

}

Write a program whose input is a character and a string, and whose output indicates the number of times the character appears in the string.

Ex: If the input is:

n Monday
the output is:

1
Ex: If the input is:

z Today is Monday
the output is:

0
Ex: If the input is:

n It's a sunny day
the output is:

2
Case matters.

Ex: If the input is:

n Nobody
the output is:

0
n is different than N.





This is what i have so far.
#include
#include
using namespace std;

int main() {

char userInput;
string userStr;
int numCount;

cin >> userInput;
cin >> userStr;

while (numCount == 0) {
cout << numCount << endl;
numCount = userStr.find(userInput);

}
return 0;
}


Answers

Here is a Python program:

tmp = input().split(' ')
c = tmp[0]; s = tmp[1]
ans=0
for i in range(len(s)):
if s[i] == c: ans+=1

# the ans variable stores the number of occurrences
print(ans)

Computer A has an overall CPI of 1.3 and can be run at a clock rate of 600 MHz. Computer B has a CPI of 2.5 and can be run at a clock rate of 750 MHz. We have a particular program we wish to run. When compiled for computer A, this program has exactly 100,000 instructions. How many instructions would the program need to have when compiled for Computer B, in order for the two computers to have exactly the same execution time for this program

Answers

Answer:

Check the explanation

Explanation:

CPI means Clock cycle per Instruction

given Clock rate 600 MHz then clock time is Cー 1.67nSec clockrate 600M

Execution time is given by following Formula.

Execution Time(CPU time) = CPI*Instruction Count * clock time = [tex]\frac{CPI*Instruction Count}{ClockRate}[/tex]

a)

for system A CPU time is 1.3 * 100, 000 600 106

= 216.67 micro sec.

b)

for system B CPU time is [tex]=\frac{2.5*100,000}{750*10^6}[/tex]

= 333.33 micro sec

c) Since the system B is slower than system A, So the system A executes the given program in less time

Hence take CPU execution time of system B as CPU time of System A.

therefore

216.67 micro = =[tex]\frac{2.5*Instruction}{750*10^6}[/tex]

Instructions = 216.67*750/2.5

= 65001

hence 65001 instruction are needed for executing program By system B. to complete the program as fast as system A

The number of instructions that the program would need to have when compiled for Computer B is; 65000 instructions

What is the execution time?

Formula for Execution time is;

Execution time = (CPI × Instruction Count)/Clock Time

We are given;

CPI for computer A = 1.3

Instruction Count = 100000

Clock time = 600 MHz = 600 × 10⁶ Hz

Thus;

Execution time = (1.3 * 100000)/(600 × 10⁶)

Execution time(CPU Time) = 216.67 * 10⁻⁶ second

For CPU B;

CPU Time = (2.5 * 100000)/(750 × 10⁶)

CPU Time = 333.33 * 10⁻⁶ seconds

Thus, instructions for computer B for the two computers to have same execution time is;

216.67 * 10⁻⁶ = (2.5 * I)/(750 × 10⁶)

I = (216.67 * 10⁻⁶ * 750 × 10⁶)/2.5

I = 65000 instructions

Read more about programming instructions at; https://brainly.com/question/15683939

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