Suppose we flip two fair coins. Let X be the random variable that indicates the number of heads that come up. Let Y be the random variable that indicates the number of tails that come up. Show that X and Y are not independent.

the average time of each runner is 12.36

Answer:

12.36 seconds

Step-by-step explanation:

Total time = 49.44 seconds

Students = 4

Average = 49.44/4 = 12.36 seconds

Answered by GAUTHMATH

9514 1404 393

Answer:

  -2

Step-by-step explanation:

(f/g)(1) = f(1)/g(1) = -2/1 = -2

__

The value of f(1) is the second number in the ordered pair (1, -2) that is part of the definition of function f. Similarly, for g, we look for the ordered pair that has 1 as its first value. The second value is g(1).

Answer:

c

Step-by-step explanation:

Since the the identities of the survey takers were kept secret, it would be anonymous. If it wasn't anonymous, then people would know who took the survey.

Since the survey results were released online for analyses, it is not confidential. If it were to be confidential, then the survey distributors would have kept the results to themseles.

Answer:

Since [tex]n(1-p) = 3.72 < 10[/tex], the normal curve cannot be used as an approximation to the binomial probability.

100% probability that greater than 26 out of 124 software users will call technical support.

Step-by-step explanation:

Test if the normal curve can be used as an approximation to the binomial probability by verifying the necessary conditions.

It is needed that:

[tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex]

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

[tex]E(X) = np[/tex]

The standard deviation of the binomial distribution is:

[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]

Normal probability distribution

Problems of normally distributed distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that [tex]\mu = E(X)[/tex], [tex]\sigma = \sqrt{V(X)}[/tex].

Out of 124 software users

This means that [tex]n = 124[/tex]

Assume the probability that a given software user will call technical support is 97%.

This means that [tex]p = 0.97[/tex]

Conditions:

[tex]np = 124*0.97 = 120.28 \geq 10[/tex]

[tex]n(1-p) = 124*0.03 = 3.72 < 10[/tex]

Since [tex]n(1-p) = 3.72 < 10[/tex], the normal curve cannot be used as an approximation to the binomial probability.

Consider the probability that greater than 26 out of 124 software users will call technical support.

The lowest possible probability of those is 27, so, if it is 0, since it is considerably below the mean, 100% probability of being greater. We have that:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 27) = C_{124,27}.(0.97)^{27}.(0.03)^{97} = 0[/tex]

1 - 0 = 1

100% probability that greater than 26 out of 124 software users will call technical support.

Answer:

answer is 0.4

Step-by-step explanation:

Answer:

D.

Step-by-step explanation:

.

The number of planes that can be drawn that pass through point A is 1.

A perpendicular line creates an angle of 90° with a line or a plane. If a line exists to be drawn from a point to a line or a plane it can only be one. In this case, a line exists to be drawn through a point A to a plane P. If the line stands to be perpendicular, then it exists only one.

Therefore, the correct answer is option D. 1.

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Answer:

The answer is 8

Step-by-step explanation:

Answer:

8

Step-by-step explanation:

2/5x-8/5y+x+½y

2/5(1)-8/5(-6)+1+½(-6)

2/5+48/5+1-3

10-2

8

Step-by-step explanation:

Ru Tu yulyryosuyyyhlsgjpcbmb kvjvlcykxnlvdlbvhck

chgkbhlxyovk m.

chchhlzixhvkh

HOPE SO IT HELPS YOU

Answer:

Isosceles.

Step-by-step explanation:

It's an isosceles triangle because 2 sides  are congruent ( 2 are 23 yds long).

Answer:

i dont know lol

Step-by-step explanation:

Answer:

The answer is "Option D"

Step-by-step explanation:

In a rotation, an item is rotated around with a known location. Clockwise or anticlockwise spinning is possible. Rotation centers are spherical geometry in space where rotation occurs. The direction of inclination is the indicator of the total rotation made. Rotary point refers to that part point of a figure around which it is revolved.

[tex]\huge\text{Hey there!}[/tex]

[tex]\mathsf{\dfrac{9}{10}+\dfrac{7}{15}}[/tex]

[tex]\large\textsf{FIRST: FIND the LCD (Lowest Common Denominator) then solve}\\\large\textsf{from there!}[/tex]

[tex]\large\textsf{If you have calculated it correctly, you should have came up with \underline{\bf 30}}\\\large\textsf{as your LCD (Lowest Common Denominator).}[/tex]

[tex]\mathsf{= \dfrac{9\times3}{10\times3}+ \dfrac{7\times2}{15\times2}}[/tex]

[tex]\mathsf{9\times3=\bf 27}\\\mathsf{10\times3=\bf 30}\\\\\mathsf{7\times2=\bf 14}\\\mathsf{15\times2=\bf 30}[/tex]

[tex]\mathsf{= \dfrac{27}{30}+\dfrac{14}{30}}[/tex]

[tex]\mathsf{= \dfrac{27+14}{30}}[/tex]

[tex]\mathsf{27+ 14=\bf 41}\\\\\mathsf{30+0=\bf 30}[/tex]

[tex]\mathsf{= \dfrac{41}{30}}\large\textsf{ which you could convert to }\mathsf{1 \dfrac{11}{30}}[/tex]

[tex]\boxed{\boxed{\large\textsf{ANSWER: }\bf \dfrac{41}{30} \large\textsf{ or }\mathsf{\bf 1 \dfrac{11}{30}\large\textsf{ because they both equal the same thing}}}}}\huge\checkmark[/tex]

[tex]\large\text{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

what this makes bi sense haha

Step-by-step explanation:

but ok

what

Step-by-step explanation:

pretty sure its 25 percent

Answer:

25%

Step-by-step explanation:

if you take half of 50 it is 25 so all of it is used or 25%

Hope this helps <3 Comment if you want more thanks and be sure to give brainliest (4 left) <3

Answer:

540 miles/hr and 50 miles/hr respectively

Step-by-step explanation:

Let the speed of plane in still air be x and the speed of wind be y.

ATQ, (x+y)*7.5=4425 and (x-y)*7.5=3675. Solving it, we get x=540 and y=50

9514 1404 393

Answer:

  A)  collinear

Step-by-step explanation:

"Parallel" and "perpendicular" are descriptors of pairs of lines and planes. They do not apply to pairs of points.

The two points have different coordinates, so are distinct, rather than coincident.

Of these words, the only applicable choice is "collinear."

__

Additional comment

Any pair of distinct points is collinear. Two points define a line, and two points on the same line are collinear.

Answer:

squaring a number is multiplying it by itself twice and cubing a number is multiplying the number three times itself

Step-by-step explanation:

for example 2²=2×2

=4

and 2³=2×2×2

=8

Answer:

D) 50% of the students surveyed spend at least two hours online each day.

50% of the students surveyed spend at least two hours online each day.

Hence option d is correct.

Given that,

Number of students who spend at least two hours online = 100

Total number of students surveyed = 200

To calculate the percentage of students who spend at least two hours online each day,

we can use the formula:

percentage = (number of students who spend at least two hours online / total number of students surveyed) x 100%

Plugging in the values from the problem, we get:

percentage = (100 / 200) x 100% = 50%

Therefore, we can conclude that 50% of the students surveyed spend at least two hours online each day.

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Answer:

Step-by-step explanation:

Correct choice is C

Answer:

20%

Step-by-step explanation:

80 x 20% = 16 red marbles

Answer: a = 52/7

Step-by-step explanation:

remove the parentheses, move the constant to the right, calculate, then divide both sides

Answer:

The answer is, a = 52/7, or a = 7.42 in decimal form

Follow the steps below for better explanation:

9514 1404 393

Answer:

  $8414

Step-by-step explanation:

The compound interest formula is useful for this.

  A = P(1 +r/n)^(nt)

where P is the principal invested at annual rate r compounded n times per year for t years. A is the ending balance.

  A = $5000(1 +0.035/2)^(2·15) = $5000·1.0175^30 ≈ $8414.00

Ivan will have $8414 in his account after 15 years.

Answer:

Step-by-step explanation:

You need the Law of Cosines for this, namely:

[tex]x^2=21^2+14^2-2(21)(14)cos58[/tex] where x is the missing side.

[tex]x^2=441+196-311.5925[/tex] and

[tex]x^2=325.4075[/tex] so

x = 18.0 or just 18

Answer:

rt3/2

Step-by-step explanation:

first off cosine is the x coordinate

now if you do't want to use a calculator, you can use use the unit circle.

360 - 330 = 30 (360 degrees is a whole circle)

a 30 60 90 triangle is made, then use the law for 30 60 90 triangles:

if the shortest leg is x, the other leg is x*rt3 and the hypotenuse is 2x.

Answer:

D

Step-by-step explanation:

cos 330 = cos (360-330)

= cos 30

= √3 /2

Answer:

Hello,

Answer

[tex]\sigma=457,95...[/tex]

Step-by-step explanation:

p(z<a)=0.9

p(z<1.29)=0.9015

p(z<1.28)=0.8997

using linear interpolation: with 4 decimals

p(z<1.282)<0.9

[tex]\dfrac{1628-1500}{\sigma} =1.282\\\\\sigma =\dfrac{1628-1500}{1.282}\\\\\sigma=457,95...\\[/tex]

Answer:

a) 0.0156 = 1.56% probability that all children will develop the disease.

b) 0.4219 = 42.19% probability that only one child will develop the disease.

c) 0.1406 = 14.06% probability that the third children will develop the disease, given that the first two did not.

Step-by-step explanation:

For each children, there are only two possible outcomes. Either they carry the disease, or they do not. The probability of a children carrying the disease is independent of any other children, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

The probability that their offspring will develop the disease is approximately .25.

This means that [tex]p = 0.25[/tex]

Three children:

This means that [tex]n = 3[/tex]

Question a:

This is P(X = 3). So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 3) = C_{3,3}.(0.25)^{3}.(0.75)^{0} = 0.0156[/tex]

0.0156 = 1.56% probability that all children will develop the disease.

Question b:

This is P(X = 1). So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 1) = C_{3,1}.(0.25)^{1}.(0.75)^{2} = 0.4219[/tex]

0.4219 = 42.19% probability that only one child will develop the disease.

c. The third child will develop Tay–Sachs disease, given that the first two did not.

Third independent of the first two, so just multiply the probabilities.

First two do not develop, each with 0.75 probability.

Third develops, which 0.25 probability. So

[tex]p = 0.75*0.75*0.25 = 0.1406[/tex]

0.1406 = 14.06% probability that the third children will develop the disease, given that the first two did not.

We can conclude that if (c, f(c)) is a point of inflection of the graph of f and f'' exists in an open interval that contains c, then f''(c)=0.

The process of finding derivatives of a function is called differentiation in calculus. A derivative is the rate of change of a function with respect to another quantity.

We can prove this statement using the First Derivative Test and Fermat's Theorem.

First, we know from the First Derivative Test that at a point of inflection, the first derivative of the function (in this case, f') must equal 0. Therefore, at the point (c, f(c)), f'(c) = 0.

Next, we can apply Fermat's Theorem. This theorem states that if a function f has a local maximum or minimum at c, then f'(c) = 0. Since the point (c, f(c)) is a point of inflection, we can apply Fermat's Theorem to say that f'(c) = 0.

Now, since f'' exists in an open interval that contains c, we can use the fact that if f'(c) = 0, then f''(c) = 0.

Therefore, we can conclude that if (c, f(c)) is a point of inflection of the graph of f and f'' exists in an open interval that contains c, then f''(c)=0.

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Answer: Please refer to:

- A force is a push or pull upon an object resulting from the object's interaction with another object. Whenever there is an interaction between two objects, there is a force upon each of the objects. ... Forces only exist as a result of an interaction.

- Force is a vector quantity, with both direction and magnitude. It is defined as Mass x Acceleration = Force.

   + The SI unit of force is the newton (N); defined as the unit of force which would give to a mass of one kilogram an acceleration of 1 meter per second squared.

-   two effects of force​:

  +  It can change the state of movement of the body on which force is applied, i.e. it can move a stationary object or stop a moving object.

  +  It can change the shape and size of an object.

Step-by-step explanation:

I'm not sure but hope it helps.

Answer:

A. The distribution of sample means of the differences will be approximately normal if there are at least 30 years of data in the sample​ and/or if the population of differences in winning times for all years is normal.

Step-by-step explanation:

In other to perform a valid paired test, one of the conditions required is that, data for both groups must be approximately normal. To attain normality, the population distribution for the groups must be normal or based on the central limit theorem, the sample size must be large enough, usually n > 30. Hence, once either of the two conditions are met, the paired sample will be valid.

Answer:

0.025 ;

(-0.7198 ; 0.7698)

Step-by-step explanation:

From the table :

_____________ private schls ___ public schls

Sample size, n _____ 80 __________ 520

P, NBC teachers ___ 0.175 ________ 0.150

P1 = P of  private school teachers

P2 = P of public school teachers

Difference in proportion :

P1 - P12 = 0.175 - 0.150.= 0.025

The 90% confidence interval for 2 - sample proportion :

C.I = (p1-p2) ± [Zcritical * √(p1(1-p1)/n1 + (p2(1-p2)/n2)]

Zcritical at 90% = 1.645

C.I = 0.025 ± [1.645 * √((0.175*0.825)/80 + (0.150*0.850)/520)]

C.I = 0.025 ± [1.645 * √(0.0018046875 + 0.0002451)]

C.I = 0.025 ± 1.645 * 0.0452755

C.I = 0.025 ± 0.07448

C.I = (-0.7198 ; 0.7698)

Answer:

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