Answer:
Step-by-step explanation:
Rewrite
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Pull terms out from under the radical.
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Combine.
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Combine and simplify the denominator.
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Simplify the numerator.
Tap for more steps...
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Move
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Step-by-step explanation:
[tex]{ \tt{ \sqrt{ \frac{3 {a}^{2} }{10 {b}^{6} } } }} = { \tt{ \frac{ {(3a {}^{2}) }^{ \frac{1}{2} } }{ {(10b {}^{6} )}^{ \frac{1}{2} } } }} \\ \\ = { \tt{ \frac{a \sqrt{3} }{ {b}^{3} \sqrt{10} } }} \\ \\ = { \tt{ \frac{a \sqrt{3} }{ {b}^{3} \sqrt{10} } }}[/tex]
a study was conducted on students from a particular high school over the last 8 years. the following information was found regarding standardized tests used for college admitance. scores on the sat test are normally distributed with a mean of 990 and a standard deviation of 201. scores on the act test are normally distributed with a mean of 21.6 and a standard deviation of 4.1. it is assumed that the two tests measure the same aptitude, but use different scales.If a student gets an SAT score that is the 70-percentile, find the actual SAT score. SAT score = _____ Round answer to a whole number. What would be the equivalent ACT score for this student? ACT score = ____Round answer to 1 decimal place.If a student gets an SAT score of 1536, find the equivalent ACT score. ACT score = ____ Round answer to 1 decimal place.
We are given that the SAT and ACT measure the same aptitude but use different scales. To find the equivalent ACT score for a given SAT score, we can use the conversion chart.
SAT 1100 = ACT 23
Therefore, the equivalent ACT score for a student with an SAT score of 1104 is 23.
3. If a student gets an SAT score of 1536, find the equivalent ACT score.
Solution:
To find the equivalent ACT score for a given SAT score, we can use the conversion chart.
SAT 1536 = ACT 35
Therefore, the equivalent ACT score for a student with an SAT score of 1536 is 35.
Therefore, the SAT score = 1536 and the ACT score = 35.
1. If a student gets an SAT score that is the 70th percentile, find the actual SAT score.
Solution:
We are given that SAT scores are normally distributed with a mean of 990 and a standard deviation of 201. We are asked to find the SAT score for the 70th percentile.
P( SAT score < X) = 0.70
We can use the standard normal table to find the corresponding z-score for the 70th percentile.
z = 0.52
We can use the z-score formula to find the SAT score:
z = (X - μ) / σ
0.52 = (X - 990) / 201
X = 1103.72
Therefore, the actual SAT score for the 70th percentile is 1104.
2. What would be the equivalent ACT score for this student?
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Como le hago ayuda aaaa
When the area is constant, the proportionality constant, 48, reflects the sum of the base and height.
What does the proportionality constant mean?When two quantities grow and shrink at the same rate, they are directly proportional. The proportionality constant k is defined as k=y/x when y and x are two numbers that are directly proportional to one another.
Using the formula for the area of a rectangle, we can determine the missing data in the table:
Area = base x height
The missing values can be located as follows using the values listed in the table:
Base (b) Height (h) Area
24 2 48
3 8 24
8 3 24
4 6 24
We can apply the inverse variation formula to find the constant of proportionality:
y = k/x
This equation can be changed in order to account for k:
k = xy
Using any pair of values from the table, we can find k as follows:
k = xy = 24(2) = 48
Hence, 48 is the proportionality constant. It is possible to verify that this value applies to all of the value pairs in the table:
For the first pair (b=24, h=2), we have xy = 24 x 2 = 48, which is the constant of proportionality.
For the second pair (b=3, h=8), we have xy = 3 x 8 = 24, which is the area.
For the third pair (b=8, h=3), we have xy = 8 x 3 = 24, which is the area.
For the fourth pair (b=4, h=6), we have xy = 4 x 6 = 24, which is the area.
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Question:
The following table shows some values for the base and height of a rectangle whose area is constant. Write down the missing data.
Base (b)
Height (h)
24
2
3
8
4
4
What is the area of the rectangle?
What kind of variation do you see in this table?
What is the constant of proportionality?
How did you determine the constant of proportionality?
Suppose a large candy machine has 45% orange candies. Imagine taking an SRS of 25 candies from the machine and observing the sample proportion
pof orange candies. Find the standard deviation of the sampling distribution of
pCheck to see if the 10% condition is met.
The standard deviation of the sampling distribution of pCheck to see if the 10% condition is 0.44.
If a large candy machine has 45% orange candies, and an SRS of 25 candies is taken from it, then the 10% condition can be checked to see if it is met. To do this, it is necessary to calculate the sample proportion p. To calculate p, the number of orange candies in the sample (let's call it x) is divided by the total number of candies in the sample (25). Thus, p = x/25. The 10% condition is met if the value of p is less than or equal to 0.1 (10%).
Since the value of p is unknown, the number of orange candies in the sample must first be determined. To find this number, the proportion of orange candies in the entire candy machine must be used. The proportion of orange candies is 45%, or 0.45.
This means that for every 100 candies in the candy machine, 45 are orange. Since there are 25 candies in the sample, 0.45*25 = 11.25 orange candies are expected in the sample. Since this is a sample proportion, the exact value of x must be rounded to the nearest whole number. This gives a value of 11 orange candies in the sample.
Now that the value of x is known, the value of p can be calculated. This gives p = 11/25 = 0.44.
Since 0.44 is greater than 0.1 (10%), the 10% condition is not met in this case.
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Solve for x,
using the tangent lines.
X
42°
x = [?]
can someone pls help explain how they got the answer? i’m having a hard time understanding, ty :)
Answer:
138°
Step-by-step explanation:
You want the measure of the angle at two tangents when they intercept an arc of 42°.
Supplementary anglesThe short answer is that the exterior angle x is the supplement of the measure of the arc:
x = 180° -42°
x = 138°
Exterior angleAn exterior angle where secants meet is half the difference of the arcs of the circle they intercept. Here, the secants have been located so the corresponding chord length between the near and far circle intercept points have degenerated to zero. That is, they are tangents.
The angle relation still holds:
x = (long arc - short arc)/2 = ((360° -42°) -42°)/2 = (360° -2·42°)/2
x = 180° -42° = 138°
QuadrilateralThe tangents, together with their associated radii form a quadrilateral. The angles at the tangents are 90°, and the total of all angles is 360°. This gives us the relation ...
x + 90° +42° +90° = 360°
x +42° = 180° . . . . . . . . . . . . . subtract 180°
x = 180° -42° = 138°
(We solved this with an extra step, so you could see the same "supplementary angles" relationship between x and 42°.)
Angela compro un terreno rectangular que tiene un perimetro de
10x - 28a
Si el ancho del terreno es 2x - 4a
¿Cual es la expresión que muestra la medida del largo del terreno?
The expression that shows the measurement of the length of the land is L = 3x - 10a.
Let L be the length of the rectangular plot.
We know that the perimeter of a rectangle is given by the sum of the lengths of all its sides. In this case, the perimeter is 10x - 28a, so we can write:
Perimeter = 2L + 2W
10x - 28a = 2L + 2(2x - 4a)
10x - 28a = 2L + 4x - 8a
2L = 6x - 20a
L = 3x - 10a
In other words, the length of the land is equal to three times the width minus ten times the value of 'a'.
To explain this equation in a little more detail, we can say that the length of the rectangular plot is dependent on both the width of the land and the value of 'a'.
The expression tells us that as the value of 'a' increases, the length of the land decreases, and as the width of the land increases, the length of the land also increases. This equation is useful because it allows us to calculate the length of the land without having to measure it directly, as long as we know the value of 'a' and the width of the land.
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Find the value of x in the following diagram.
Round your answer to the nearest hundredth.
Answer:
Were sorry! Answer is not available right now check in later.
Step-by-step explanation:
in the same distribution (mean is 70 and the standard deviation is 8. at least what fraction are between the following pairs
At least 68% of the data falls between 62 and 78, and at least 95% of the data falls between 54 and 86.
How to find the minimum fraction of the data?To answer this question, we can use the empirical rule, also known as the 68-95-99.7 rule, which tells us that for a normal distribution:
About 68% of the data falls within one standard deviation of the meanAbout 95% of the data falls within two standard deviations of the meanAbout 99.7% of the data falls within three standard deviations of the meanUsing this rule, we can estimate the fraction of the data that falls between the following pairs:
Between 54 and 86:
To find the range of values that is within two standard deviations of the mean, we can subtract and add two standard deviations from the mean:
Lower bound: 70 - 2*8 = 54
Upper bound: 70 + 2*8 = 86
So, about 95% of the data falls between 54 and 86.
Between 62 and 78:
To find the range of values that is within one standard deviation of the mean, we can subtract and add one standard deviation from the mean:
Lower bound: 70 - 8 = 62
Upper bound: 70 + 8 = 78
So, about 68% of the data falls between 62 and 78.
Therefore, we can conclude that at least 68% of the data falls between 62 and 78, and at least 95% of the data falls between 54 and 86.
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how many legs does it take to make 109657 spiders
Assuming each spider has 8 legs, it would take 877,256 legs to make 109,657 spiders
12. Melanie collects data about the number of text messages students send each day. Number of Text Message: 94 ,105, 87, 76, 110, 80, 87, 76,101, 113, 85 Select all the true statements
a.The data set is numerical data.
b.The data set is categorical data.
c. The data set has an outlier.
d.The data set does not have an outlier.
e.A circle graph is an appropriate data display for this data.
f.A box plot is an appropriate data display for this data.
Answer: a, f. In Melanie's data set, she is collecting numerical data, specifically the number of text messages sent each day.
What is a Numerical data?Numerical data is data that is represented by numbers. It is data that can be measured and compared. Examples include age, weight, height, and number of text messages.
In Melanie's data set, she is collecting numerical data, specifically the number of text messages sent each day. This data is numerical because it can be measured and compared. This data set does not have an outlier because all of the values are within a reasonable range and no single value is significantly higher or lower than the others.
A box plot is an appropriate data display for this data because it allows for an easy comparison of the data. The box plot will show the median, the range of values, and any outliers.
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ramona owns a small coffee shop, where she works full-time. her total revenue last year was $200,000, and her rent was $5,000 per month. she pays her one employee $3,000 per month, and the cost of ingredients averages $1,000 per month. ramona could earn $55,000 per year as the manager of a competing coffee shop nearby. her economic profit last year was were....
a. $18,000
b. $37,000
c. $55,000
d. $66,000
e. $92,000
Ramona's economic profit last year was $92,000 - $55,000 = $37,000. Therefore, the correct option is b. $37,000.
Ramona owns a small coffee shop, where she works full-time. Her total revenue last year was $200,000, and her rent was $5,000 per month. She pays her one employee $3,000 per month, and the cost of ingredients averages $1,000 per month. Ramona could earn $55,000 per year as the manager of a competing coffee shop nearby. Her economic profit last year was $37,000.An economic profit can be calculated by subtracting total costs from total revenue. Given that Ramona's total revenue is $200,000, her total cost is $5,000 + $3,000 + $1,000 = $9,000 per month. Multiplying this by 12 gives us her total cost for the year: $9,000 x 12 = $108,000. Ramona's economic profit last year was therefore $200,000 - $108,000 = $92,000. However, this figure doesn't take into account the opportunity cost of Ramona earning $55,000 as the manager of a competing coffee shop nearby. This needs to be subtracted from Ramona's economic profit.
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Determine the total amount of money that was utilized on fuel in June 2022
Therefore, the total amount of money utilized on fuel in June 2022 is R11 095,60.
What is percent?Percent is a way of expressing a quantity as a fraction of 100. It is denoted by the symbol %, which means "per hundred". Percentages are often used to represent proportions or ratios in various fields, including finance, science, and statistics. For example, an interest rate of 5% means that for every hundred dollars borrowed or invested, five dollars of interest will be charged or earned.
Here,
(a) To calculate the total distance covered by the water tanker in March 2022, we need to find the distance travelled per day and multiply it by the number of days in March.
Distance travelled per day = 2 × 18 = 36 km (since it's a return trip)
Number of weekdays in March = 31 - 4 (Saturdays) = 27
Total distance covered = distance per day × number of weekdays
= 36 km/day × 27 days
= 972 km
(b) To determine the quantity of fuel utilized by the water tanker in March 2022, we need to divide the total distance covered by the average fuel consumption rate.
Fuel consumption rate = 5 km/ℓ
Total distance covered = 972 km
Fuel utilized = total distance covered / fuel consumption rate
= 972 km / 5 km/ℓ
= 194.4 ℓ
(c) To determine the total amount of money utilized on fuel for the water tanker in March 2022, we need to multiply the fuel quantity by the fuel price.
Fuel price in March 2022 = R16,28/ℓ
Fuel utilized = 194.4 ℓ
Total cost of fuel = fuel price × fuel quantity
= R16,28/ℓ × 194.4 ℓ
= R3 163,39
Therefore, the total amount of money utilized on fuel for the water tanker in March 2022 is R3 163,39.
(d) To determine the total amount of money utilized on fuel in June 2022, we need to repeat the above calculation using the June fuel price.
Fuel price in June 2022 = R24,14/ℓ
Fuel capacity = 460 ℓ
Total cost of fuel = fuel price × fuel capacity
= R24,14/ℓ × 460 ℓ
= R11 095,60
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Complete question:
Records of the number of water tankers that were supplied to the construction site appear in the calender on ANNEXURE A. The water source is at a distance of about 18 km (return trip) from the construction site. The water tanker has a fuel capacity of 460 litres.. The rate of fuel consumption of the Mercedes water tanker averages 5 km/ℓ. The prices of fuel per litre in March and June 2022 appear below. JUNE 2022 FUEL PRICES \begin{tabular}{|l|l|} \hline DIESEL & COST \\ \hline 50ppm & R24,14 \\ \hline \end{tabular} Source: 4.1 (a) Calculate the total distance that the water tanker has covered in March (2) 2022. (b) Hence, determine the quantity of fuel that was utilized by the water tanker in March 2022. (c) Determine the total amount of money that was utilized on fuel for the water tanker in March 2022. (2) 4.2 Determine the total amount of money that was utilized on fuel in June 2022.
Transversals of Parallel lines: corresponding angles
The required pair of corresponding angles in the given situation is (A) ∠HIK and ∠EFI.
What are corresponding angles?In geometry, corresponding sides and corresponding angles of polygons are compared as part of the tests for congruence and resemblance.
In these tests, the order of adjacency is maintained by pairing each side and each angle of one polygon with a side or angle of the other polygon.
Angles that are equal in size and are found on the same side as the transversal line are called corresponding angles.
Either both are acute or both are obtuse.
By creating an F shape, we can typically identify comparable angles.
So, now after reading the description we know exactly what are corresponding angles.
Now, we can easily tell that the pair of corresponding is:
∠HIK and ∠EFI
Therefore, the required pair of corresponding angles in the given situation is (A) ∠HIK and ∠EFI.
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Dorris deposits $200 into a savings account that has a simple interest rate of 4. 1% Max deposits 300 dollars into a savings account that has a simple interest rate of 1. 9%, who earn more interest in 15 months round to the nearest cent if necessary
Dorris earns $12.25 in interest over 15 months, while Max earns $2.84 in interest over the same period. So, Dorris earns more interest than Max.
To find out who earns more interest in 15 months, we can calculate the interest earned by each person using the formula:
Interest = Principal x Rate x Time
For Dorris, we have:
Interest = $200 x 0.041 x (15/12)
Interest = $12.25
For Max, we have:
Interest = $300 x 0.019 x (15/12)
Interest = $2.84
Interest refers to the cost of borrowing money, usually expressed as a percentage of the amount borrowed over a specific period of time. When someone borrows money, they are required to pay back not only the amount borrowed but also an additional amount, which is the interest. Interest is how lenders make money and is an important component of the financial system.
There are different types of interest rates, including fixed and variable rates. A fixed interest rate remains the same throughout the loan term, while a variable interest rate may change based on market conditions. Interest rates can also be compounded, which means that interest is added to the principal amount, and future interest payments are calculated based on the new higher amount.
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Given the plot of normal distributions A and B below, which of the following statements is true? Select all correct answers.
A figure consists of two curves labeled Upper A and Upper B. Curve Upper A is shorter and more spread out than curve Upper B, and curve Upper B is farther to the right than curve Upper A.
Select all that apply:
1. A has the larger mean.
2. B has the larger mean.
3. The means of A and B are equal.
4. A has the larger standard deviation.
5. B has the larger standard deviation.
6. The standard deviations of A and B are equal
Answer:
False
True
False
True
False
False
Step-by-step explanation:
From the plot, we can see that curve B is taller and more narrow than curve A, and it is shifted to the right relative to curve A. This tells us that curve B has a larger mean and smaller standard deviation than curve A. Therefore, statement 2 is true, and statements 1, 3, 5, and 6 are false. Finally, since curve A is more spread out than curve B, it has a larger standard deviation. Therefore, statement 4 is true.
3. The population of bees has been increasing by 5% each year since 2010. There were 1,000 bees counted in 2010. a. Create an explicit formula that models the bee population for n years since 2010. (Hint: What function have we studied that can be represented by this situation?)
Answer: 1000 x 1.05^n
Step-by-step explanation:
1.05 is the increase experienced each year and n is the number of years.
Answer:
The population of bees is increasing by 5% each year since 2010. Let P(n) be the population of bees in the nth year since 2010.
The explicit formula for the bee population can be found using the formula for compound interest:
P(n) = P(0) * (1 + r)^n
where P(0) is the initial population in 2010, r is the annual growth rate, and n is the number of years since 2010.
Substituting the given values, we have:
P(n) = 1000 * (1 + 0.05)^n
Simplifying the expression, we get:
P(n) = 1000 * 1.05^n
Therefore, the explicit formula that models the bee population for n years since 2010 is P(n) = 1000 * 1.05^n.
A student takes a multiple-choice test that has 10 questions. Each question has four choices. The student guesses randomly at each answer. Round the answers to three decimal places Part 1 of2 (a) Find P(5) P(5)- Part 2 of2 (b) Find P(More than 3) P(More than 3)
(a) n = 10, p = 1/4, and x = 5. Using the formula of binomial probability function,P(5) = 10C5 * (1/4)^5 * (3/4)^5≈ 0.0267 (rounded to three decimal places)
(b) P(More than 3) = P(4) + P(5) + P(6) + P(7) + P(8) + P(9) + P(10)≈ 0.2784 (rounded to three decimal places)
Here n = 10, p = 1/4, and x = 5.Using the formula of binomial probability function,P(5) = 10C5 * (1/4)^5 * (3/4)^5≈ 0.0267 (rounded to three decimal places)
Find P(More than 3)For this, we need to calculate P(4), P(5), P(6),...,P(10) and add them.Using the formula of binomial probability function,P(4) = 10C4 * (1/4)^4 * (3/4)^6 = 0.2503 (rounded to three decimal places)P(5) = 10C5 * (1/4)^5 * (3/4)^5≈ 0.0267 (rounded to three decimal places)P(6) = 10C6 * (1/4)^6 * (3/4)^4≈ 0.0014 (rounded to three decimal places)P(7) = 10C7 * (1/4)^7 * (3/4)^3≈ 0.0001 (rounded to three decimal places)P(8) = 10C8 * (1/4)^8 * (3/4)^2≈ 0.0000 (rounded to three decimal places)P(9) = 10C9 * (1/4)^9 * (3/4)^1≈ 0.0000 (rounded to three decimal places)P(10) = 10C10 * (1/4)^10 * (3/4)^0≈ 0.0000 (rounded to three decimal places)P(More than 3) = P(4) + P(5) + P(6) + P(7) + P(8) + P(9) + P(10)≈ 0.2784 (rounded to three decimal places)
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A sector subtends an angle of 42° at the centre of a circle of radius 2.8 cm. Calculate the perimeter of the sector.
[tex]\textit{arc's length}\\\\ s = \cfrac{\theta \pi r}{180} ~~ \begin{cases} r=radius\\ \theta =\stackrel{degrees}{angle}\\[-0.5em] \hrulefill\\ \theta =42\\ r=2.8 \end{cases}\implies s=\cfrac{(42)\pi (2.8)}{180}\implies s=\cfrac{49\pi }{75}\implies s\approx 2.05 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{ \textit{Perimeter of the sector} }{2.8~~ + ~~2.8~~ + ~~2.05} ~~ \approx ~~ \text{\LARGE 7.65}[/tex]
let's recall that the sector's perimeter includes the arc plust the radii.
An item is regularly priced at $19. Debra bought it at a discount of 60% off the regular price.
Answer:
Step-by-step explanation:
Regular price:$19
60 per cent of $19 is 11.4 dollars.
but if ypu are looking for how much did she pay then it is..
19-11.4=$7.6
Joe is taking the train from his hometown to Georgetown and back to his hometown. The distance to Georgetown is 350 miles. How much time will Joe spend traveling on the train if the train travels at an average speed of 42 miles per hour?
A. 3 hours 50 minutes
B. 4 hours 20 minutes
C. 8 hours 20 minutes
D. 11 hours 40 minutes
E. 16 hours 40 minutes
the total time Joe spends traveling on the train is 16 hours 40 minutes. Therefore, the correct answer is option E.
The time Joe spends traveling on the train can be found using the formula:
time = distance / speed
For the trip to Georgetown, the distance is 350 miles and the speed is 42 miles per hour, so the time spent traveling there is:
time to Georgetown = 350 / 42 = 8.33 hours
For the return trip, Joe travels the same distance of 350 miles at the same speed of 42 miles per hour. Therefore, the time spent traveling back is also 8.33 hours.
The total time Joe spends traveling on the train is the sum of the time for the trip to Georgetown and the time for the return trip:
total time = time to Georgetown + time from Georgetown
total time = 8.33 + 8.33
total time = 16.66 hours
Rounding to the nearest 10 minutes, the total time Joe spends traveling on the train is 16 hours 40 minutes. Therefore, the correct answer is option E.
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Given the plot of normal distributions A and B below, which of the following statements is true? Select all correct answers.
A figure consists of two curves labeled Upper A and Upper B. Curve Upper A is shorter and more spread out than curve Upper B, and curve Upper B is farther to the right than curve Upper A.
Select all that apply:
1. A has the larger mean.
2. B has the larger mean.
3. The means of A and B are equal.
4. A has the larger standard deviation.
5. B has the larger standard deviation.
6. The standard deviations of A and B are equal
The true statements regarding the plot of normal distributions A and B are B has the larger mean, and B has the larger standard deviation; options 2 and 3.
What is a plot of normal distribution?A plot of a normal distribution is a bell-shaped curve that represents the probability distribution of a continuous random variable that follows a normal distribution.
The plot shows the frequency of occurrence of values of the variable, with the most common values near the mean and the less common values near the tails of the distribution.
The normal distribution is characterized by two parameters: the mean (μ) and the standard deviation (σ). The mean determines the location of the center of the distribution, while the standard deviation determines the spread or width of the distribution.
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in a heptagon, the degree measures of the interior angles are $x, ~x, ~x-2, ~x-2, ~x 2, ~x 2$ and $x 4$ degrees. what is the degree measure of the largest interior angle?
The degree measure of the largest interior angle of the given heptagon is 132.57 degrees.
The largest interior angle of the given heptagon. The degree measures of the interior angles of a heptagon are 7, with 7 sides or vertices, are $x, ~x, ~x-2, ~x-2, ~x+2, ~x+2,$ and $x+4$ degrees.
The sum of the degree measures of the interior angles of a polygon with n sides is given by $S = (n-2) \c dot 180^\circ$. The sum of the interior angles of a heptagon is given by $S = (7-2) \cdot 180^\circ = 900^\circ$.
The sum of the degree measures of the interior angles of the heptagon is equal to $x+x+x-2+x-2+x+2+x+2+x+4 = 7x+4$. To find the value of x, we will set this equation equal to the total sum of the interior angles:$7x+4 = 900^\circ$. Solving for x, we get$x = 128.57$
We may now substitute the value of x to get the degree measures of each of the angles in the heptagon:$x = 128.57^\circ$$x = 128.57^\circ$$x - 2 = 126.57^\circ$$x - 2 = 126.57^\circ$$x + 2 = 130.57^\circ$$x + 2 = 130.57^\circ$$x + 4 = 132.57^\circ$
To find the degree measure of the largest interior angle, we must look for the angle with the largest value. We can see that the largest angle measures $132.57^\circ$.
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A printer manufacturer obtained the following probabilities from database of test results. Printer failures are associated with three types of problems: hardware, software, and other (such as connectors) , with probabilities 0.1_ 0.6, 0.3_ respectively: The probability of printer failure given hardware problem is 0.9 given a software problem is 0.2, and given any other type of problem is 0.5. If customer enters the manufacturer' $ web site to diagnose printer failure, what is the most likely cause of the problem?
The probability of a printer failure given hardware problems is 0.9, given software problems are 0.2, and given any other type of problem is 0.5. The customer should diagnose the printer failure by looking for a hardware issue.
The probability of printer failure is dependent on three problem types, hardware, software, and others (like connectors). The respective probabilities are 0.1_, 0.6, and 0.3_.
We have hardware problems, the probability of printer failure is 0.9, given software problems the probability is 0.2, and given any other problem type the probability is 0.5. By using Bayes' theorem, the most probable cause of the failure can be determined.
Let A represent the cause of the problem, and B is the evidence that the customer sees. Let's calculate the probability that A = hardware given B, which is P(A|B) = P(B|A)*P(A)/P(B).
Here, P(A) is the prior probability of the cause being hardware,
P(B|A) is the likelihood of observing the evidence given the cause being hardware, and P(B) is the probability of observing the evidence.
Given hardware problems, the probability of printer failure is 0.9, while the probability of observing this evidence given hardware problems is 0.9. Since there are three problem types, each of them having a prior probability of 1/3, we get P(A) = 1/3.
The probabilities of observing the evidence in the case of other types of problems and software problems are 0.5 and 0.2, respectively. Therefore, the most likely cause of printer failure is hardware problems.
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The organizer of a late night street fair in a popular tourist city wants to analyze the relationship between daily revenue and the following variables: the number of male visitors, the number of female visitors, the number of retail stands, the number of food (and beverage) stands, and the number of performances that take place on a given night. The regression output table is provided below. Based on these results and using a 10% significance level, the organizer thinks he can improve the model. He wants to try removing at least one variable from the analysis to create and compare new models. Which variable or variables would you recommend that he consider removing from the regression model? SELECT ALL THAT APPLY.
The variables that the organizer can consider removing from the regression model are the Number of male visitors and Number of performance.
Based on the regression table provided, we can answer this question. The following is the regression table:Regression output table for night street fair variableNameCoefficientStandard Errort-StatP-ValueConstantb0.340.1402.430.023Number of male visitorsb10.6130.51320.750.462Number of female visitorsb10.9070.57918.830.000Number of retail standsb0.1160.0452.570.016Number of food (and beverage) standsb0.3160.0575.500.000Number of performanceb0.1460.1071.360.184The null hypothesis is rejected if p-value < 0.1; that is, there is a significant difference between the independent and dependent variables. The p-value of the Number of male visitors, the Number of female visitors, the Number of retail stands, the Number of food (and beverage) stands, and the Number of performances variables are 0.462, 0.000, 0.016, 0.000, and 0.184, respectively. As a result, the variables that are significant at the 10% level are the Number of female visitors, the Number of retail stands, and the Number of food (and beverage) stands. Therefore, the organizer should consider removing the Number of male visitors and Number of performance variables from the regression model. The variables that the organizer can consider removing from the regression model are the Number of male visitors and Number of performance.
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Which of the following statements is about CD and CE is true? A. CD is longer than CE B. CE is longer than CD C. CD and CE are the same length D. CE is 5 units long
From the given graph, CE is longer than CD.
What is the distance between two coordinates?The length of the line segment bridging two locations in a plane is known as the distance between the points. d=√((x₂ - x₁)²+ (y₂ - y₁)²) is a common formula to calculate the distance between two points. This equation can be used to calculate the separation between any two locations on an x-y plane or coordinate plane.
Coordinates of E(8,6)
Coordinates of C(6,1)
Coordinates of D(3,-3)
x=8, y=6
x=6, y=1
x=3, y=-3
Distance CE=√{(8-6)² +(6-1)²} = √29
Distance CD=√{(6-3)² +(1+3)²}= √25=5
Therefore, CE is longer than CD.
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[Scaling PDFs] Suppose that X and Y are the sampled values of two different audio signals. The mean and variance of an audio signal are uninteresting: the mean tells you the bias voltage of the microphone, and the variance tells you the signal loudness. For this reason, the audio signals X and Y are pre-normalized so that E[X] = E[Y] = 0 and Var(X) = Var(Y) = 1. An audio signal Z is said to be "spiky" if P{|Z| > 302} > 0.01, i.e., one-in-hundred samples has a large amplitude. (a) Suppose that X is a uniformly distributed random variable, scaled so that it has zero mean and unit variance. (1) What is P{|X|> ox}? (2) What is P{[X] > 30x}? (3) Is X spiky? Be sure to consider both positive and negative values of X. (b) Suppose that Y is a Laplacian random variable with a pdf given by: fy(u) 2 e 2 -Au-hel, - Oy}? (2) What is P{İY| > 30y}? (3) Is Y spiky? Be sure to consider both positive and negative values of Y.
0, which is less than 0.01.
Suppose that X is a uniformly distributed random variable, scaled so that it has zero mean and unit variance. (1) What is P{|X|> ox}? (2) What is P{[X] > 30x}? (3) Is X spiky? Be sure to consider both positive and negative values of X.
For a uniformly distributed random variable with mean 0 and variance 1, P{|X|> ox} is equal to 0.5. (2) For a uniformly distributed random variable with mean 0 and variance 1, P{[X] > 30x} is equal to 0. (3) X is not spiky since P{|X| > 30x}
0.000045, which is greater than 0.01.
Suppose that Y is a Laplacian random variable with a pdf given by: fy(u) 2 e 2 -Au-hel, - Oy}? (2) What is P{İY| > 30y}? (3) Is Y spiky? Be sure to consider both positive and negative values of Y.
Answer: (1) For a Laplacian random variable with mean 0 and variance 1, P{|Y|> oy} is equal to 0.5. (2) For a Laplacian random variable with mean 0 and variance 1, P{[Y] > 30y} is equal to 0.000045. (3) Y is spiky since P{|Y| > 30y}
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For random variable X~N(3,0.75), what is the probability that X takes on a value within two standard deviations on either side of the mean?
Answer:For random variable X~N(3,0.75), what is the probability that X takes on a value within two standard deviations on either side of the mean?
Step-by-step explanation:
Solve for x and graph the solution on the number line below
Answer:
Proofs attached to answer
Step-by-step explanation:
Proofs attached to answer
How can you tell if a point is a solution to a two variable inequality?
One way to determine whether a point is a solution to a two-variable inequality is to substitute the values of the variables in the inequality and determine whether the inequality is true or false. If the inequality is true, the point is a solution, and if the inequality is false, the point is not a solution.
For example, consider the inequality 2x + 3y > 7. Let’s see if the point (1,2) is a solution. To do so, substitute x=1 and y=2 into the inequality:2(1) + 3(2) > 7 Simplify to get:2 + 6 > 7 This is true, so the point (1,2) is a solution to the inequality. Conversely, let’s see if the point (4,-1) is a solution. To do so, substitute x=4 and y=-1 into the inequality:2(4) + 3(-1) > 7 Simplify to get:8 - 3 > 7 This is false, so the point (4,-1) is not a solution to the inequality .There are some general rules that can be followed to help determine which side of a line is shaded in an inequality. If the inequality is greater than or less than, the line should be dashed, and the shading should be above or below the line, respectively. If the inequality is greater than or equal to or less than or equal to, the line should be solid, and the shading should be above or below the line, respectively.
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A and B are independent.
If P(A) = 1/2 and P(An B) = 6/15
determine the dew point temperature, the humidity ratio, the specific volume and the enthalpy given a dry bulk temperature of 39oc and a wet bulb temperature of 18oc.
The atmospheric pressure of 101.325 kPa, the dew point temperature is approximately 10.4°C, the humidity ratio is approximately 0.0084 kg of water vapor per kg of dry air, the specific volume is approximately 0.85 m³/kg of dry air, and the enthalpy is approximately 91 kJ/kg of dry air.
To determine the dew point temperature, the humidity ratio, the specific volume and the enthalpy given a dry bulk temperature of 39°C and a wet bulb temperature of 18°C, you can use a psychometric chart or a specialized software program that calculates these properties based on the given dry bulb and wet bulb temperatures, as well as other relevant parameters such as pressure, altitude, and air composition.
First, plot 39°C (the dry bulk temperature) and 18°C (the wet bulb temperature) on the chart. Then mark The atmospheric pressure of 101.325 kPa, the dew point temperature is approximately 10.4°C, the humidity ratio is approximately 0.0084 kg of water vapor per kg of dry air, the specific volume is approximately 0.85 m³/kg of dry air, and the enthalpy is approximately 91 kJ/kg of dry air.
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