Square root of
3a^2/10b^6

The degree measure of the largest interior angle of the given heptagon is 132.57 degrees.

The largest interior angle of the given heptagon. The degree measures of the interior angles of a heptagon are 7, with 7 sides or vertices, are $x, ~x, ~x-2, ~x-2, ~x+2, ~x+2,$ and $x+4$ degrees.

The sum of the degree measures of the interior angles of a polygon with n sides is given by $S = (n-2) \c dot 180^\circ$. The sum of the interior angles of a heptagon is given by $S = (7-2) \cdot 180^\circ = 900^\circ$.

The sum of the degree measures of the interior angles of the heptagon is equal to $x+x+x-2+x-2+x+2+x+2+x+4 = 7x+4$. To find the value of x, we will set this equation equal to the total sum of the interior angles:$7x+4 = 900^\circ$. Solving for x, we get$x = 128.57$

We may now substitute the value of x to get the degree measures of each of the angles in the heptagon:$x = 128.57^\circ$$x = 128.57^\circ$$x - 2 = 126.57^\circ$$x - 2 = 126.57^\circ$$x + 2 = 130.57^\circ$$x + 2 = 130.57^\circ$$x + 4 = 132.57^\circ$

To find the degree measure of the largest interior angle, we must look for the angle with the largest value. We can see that the largest angle measures $132.57^\circ$.

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Answer:For random variable X~N(3,0.75), what is the probability that X takes on a value within two standard deviations on either side of the mean?

Step-by-step explanation:

Answer:

Step-by-step explanation:

Regular price:$19

60 per cent of $19 is 11.4 dollars.

but if ypu are looking for how much did she pay then it is..

19-11.4=$7.6

The probability of a printer failure given hardware problems is 0.9, given software problems are 0.2, and given any other type of problem is 0.5. The customer should diagnose the printer failure by looking for a hardware issue.

The probability of printer failure is dependent on three problem types, hardware, software, and others (like connectors). The respective probabilities are 0.1_, 0.6, and 0.3_.

We have hardware problems, the probability of printer failure is 0.9, given software problems the probability is 0.2, and given any other problem type the probability is 0.5. By using Bayes' theorem, the most probable cause of the failure can be determined.

Let A represent the cause of the problem, and B is the evidence that the customer sees. Let's calculate the probability that A = hardware given B, which is P(A|B) = P(B|A)*P(A)/P(B).

Here, P(A) is the prior probability of the cause being hardware,

P(B|A) is the likelihood of observing the evidence given the cause being hardware, and P(B) is the probability of observing the evidence.

Given hardware problems, the probability of printer failure is 0.9, while the probability of observing this evidence given hardware problems is 0.9. Since there are three problem types, each of them having a prior probability of 1/3, we get P(A) = 1/3.

The probabilities of observing the evidence in the case of other types of problems and software problems are 0.5 and 0.2, respectively. Therefore, the most likely cause of printer failure is hardware problems.

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the total time Joe spends traveling on the train is 16 hours 40 minutes. Therefore, the correct answer is option E.

The time Joe spends traveling on the train can be found using the formula:

time = distance / speed

For the trip to Georgetown, the distance is 350 miles and the speed is 42 miles per hour, so the time spent traveling there is:

time to Georgetown = 350 / 42 = 8.33 hours

For the return trip, Joe travels the same distance of 350 miles at the same speed of 42 miles per hour. Therefore, the time spent traveling back is also 8.33 hours.

The total time Joe spends traveling on the train is the sum of the time for the trip to Georgetown and the time for the return trip:

total time = time to Georgetown + time from Georgetown

total time = 8.33 + 8.33

total time = 16.66 hours

Rounding to the nearest 10 minutes, the total time Joe spends traveling on the train is 16 hours 40 minutes. Therefore, the correct answer is option E.

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Answer:

  138°

Step-by-step explanation:

You want the measure of the angle at two tangents when they intercept an arc of 42°.

The short answer is that the exterior angle x is the supplement of the measure of the arc:

  x = 180° -42°

  x = 138°

An exterior angle where secants meet is half the difference of the arcs of the circle they intercept. Here, the secants have been located so the corresponding chord length between the near and far circle intercept points have degenerated to zero. That is, they are tangents.

The angle relation still holds:

  x = (long arc - short arc)/2 = ((360° -42°) -42°)/2 = (360° -2·42°)/2

  x = 180° -42° = 138°

The tangents, together with their associated radii form a quadrilateral. The angles at the tangents are 90°, and the total of all angles is 360°. This gives us the relation ...

  x + 90° +42° +90° = 360°

  x +42° = 180° . . . . . . . . . . . . . subtract 180°

  x = 180° -42° = 138°

(We solved this with an extra step, so you could see the same "supplementary angles" relationship between x and 42°.)

The variables that the organizer can consider removing from the regression model are the Number of male visitors and Number of performance.

Based on the regression table provided, we can answer this question. The following is the regression table:Regression output table for night street fair variableNameCoefficientStandard Errort-StatP-ValueConstantb0.340.1402.430.023Number of male visitorsb10.6130.51320.750.462Number of female visitorsb10.9070.57918.830.000Number of retail standsb0.1160.0452.570.016Number of food (and beverage) standsb0.3160.0575.500.000Number of performanceb0.1460.1071.360.184The null hypothesis is rejected if p-value < 0.1; that is, there is a significant difference between the independent and dependent variables. The p-value of the Number of male visitors, the Number of female visitors, the Number of retail stands, the Number of food (and beverage) stands, and the Number of performances variables are 0.462, 0.000, 0.016, 0.000, and 0.184, respectively. As a result, the variables that are significant at the 10% level are the Number of female visitors, the Number of retail stands, and the Number of food (and beverage) stands. Therefore, the organizer should consider removing the Number of male visitors and Number of performance variables from the regression model. The variables that the organizer can consider removing from the regression model are the Number of male visitors and Number of performance.

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The true statements regarding the plot of normal distributions A and B are B has the larger mean, and B has the larger standard deviation; options 2 and 3.

A plot of a normal distribution is a bell-shaped curve that represents the probability distribution of a continuous random variable that follows a normal distribution.

The plot shows the frequency of occurrence of values of the variable, with the most common values near the mean and the less common values near the tails of the distribution.

The normal distribution is characterized by two parameters: the mean (μ) and the standard deviation (σ). The mean determines the location of the center of the distribution, while the standard deviation determines the spread or width of the distribution.

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Assuming each spider has 8 legs, it would take 877,256 legs to make 109,657 spiders

From the given graph, CE is longer than CD.

The length of the line segment bridging two locations in a plane is known as the distance between the points. d=√((x₂ - x₁)²+ (y₂ - y₁)²) is a common formula to calculate the distance between two points. This equation can be used to calculate the separation between any two locations on an x-y plane or coordinate plane.

Coordinates of E(8,6)

Coordinates of C(6,1)

Coordinates of D(3,-3)

x=8, y=6

x=6, y=1

x=3, y=-3

Distance CE=√{(8-6)² +(6-1)²} = √29

Distance CD=√{(6-3)² +(1+3)²}= √25=5

Therefore, CE is longer than CD.

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When the area is constant, the proportionality constant, 48, reflects the sum of the base and height.

When two quantities grow and shrink at the same rate, they are directly proportional. The proportionality constant k is defined as k=y/x when y and x are two numbers that are directly proportional to one another.

Using the formula for the area of a rectangle, we can determine the missing data in the table:

Area = base x height

The missing values can be located as follows using the values listed in the table:

Base (b) Height (h) Area

24 2 48

3 8 24

8 3 24

4 6 24

We can apply the inverse variation formula to find the constant of proportionality:

y = k/x

This equation can be changed in order to account for k:

k = xy

Using any pair of values from the table, we can find k as follows:

k = xy = 24(2) = 48

Hence, 48 is the proportionality constant. It is possible to verify that this value applies to all of the value pairs in the table:

For the first pair (b=24, h=2), we have xy = 24 x 2 = 48, which is the constant of proportionality.

For the second pair (b=3, h=8), we have xy = 3 x 8 = 24, which is the area.

For the third pair (b=8, h=3), we have xy = 8 x 3 = 24, which is the area.

For the fourth pair (b=4, h=6), we have xy = 4 x 6 = 24, which is the area.

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Question:

The following table shows some values ​​for the base and height of a rectangle whose area is constant. Write down the missing data.

Base (b)

Height (h)

24

2

3

8

4

4

What is the area of ​​the rectangle?

What kind of variation do you see in this table?

What is the constant of proportionality?

How did you determine the constant of proportionality?

One way to determine whether a point is a solution to a two-variable inequality is to substitute the values of the variables in the inequality and determine whether the inequality is true or false. If the inequality is true, the point is a solution, and if the inequality is false, the point is not a solution.

For example, consider the inequality 2x + 3y > 7. Let’s see if the point (1,2) is a solution. To do so, substitute x=1 and y=2 into the inequality:2(1) + 3(2) > 7 Simplify to get:2 + 6 > 7 This is true, so the point (1,2) is a solution to the inequality. Conversely, let’s see if the point (4,-1) is a solution. To do so, substitute x=4 and y=-1 into the inequality:2(4) + 3(-1) > 7 Simplify to get:8 - 3 > 7 This is false, so the point (4,-1) is not a solution to the inequality .There are some general rules that can be followed to help determine which side of a line is shaded in an inequality. If the inequality is greater than or less than, the line should be dashed, and the shading should be above or below the line, respectively. If the inequality is greater than or equal to or less than or equal to, the line should be solid, and the shading should be above or below the line, respectively.

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Dorris earns $12.25 in interest over 15 months, while Max earns $2.84 in interest over the same period. So, Dorris earns more interest than Max.

To find out who earns more interest in 15 months, we can calculate the interest earned by each person using the formula:

Interest = Principal x Rate x Time

For Dorris, we have:

Interest = $200 x 0.041 x (15/12)

Interest = $12.25

For Max, we have:

Interest = $300 x 0.019 x (15/12)

Interest = $2.84

Interest refers to the cost of borrowing money, usually expressed as a percentage of the amount borrowed over a specific period of time. When someone borrows money, they are required to pay back not only the amount borrowed but also an additional amount, which is the interest. Interest is how lenders make money and is an important component of the financial system.

There are different types of interest rates, including fixed and variable rates. A fixed interest rate remains the same throughout the loan term, while a variable interest rate may change based on market conditions. Interest rates can also be compounded, which means that interest is added to the principal amount, and future interest payments are calculated based on the new higher amount.

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The standard deviation of the sampling distribution of pCheck to see if the 10% condition is 0.44.

If a large candy machine has 45% orange candies, and an SRS of 25 candies is taken from it, then the 10% condition can be checked to see if it is met. To do this, it is necessary to calculate the sample proportion p. To calculate p, the number of orange candies in the sample (let's call it x) is divided by the total number of candies in the sample (25). Thus, p = x/25. The 10% condition is met if the value of p is less than or equal to 0.1 (10%).

Since the value of p is unknown, the number of orange candies in the sample must first be determined. To find this number, the proportion of orange candies in the entire candy machine must be used. The proportion of orange candies is 45%, or 0.45.

This means that for every 100 candies in the candy machine, 45 are orange. Since there are 25 candies in the sample, 0.45*25 = 11.25 orange candies are expected in the sample. Since this is a sample proportion, the exact value of x must be rounded to the nearest whole number. This gives a value of 11 orange candies in the sample.

Now that the value of x is known, the value of p can be calculated. This gives p = 11/25 = 0.44.

Since 0.44 is greater than 0.1 (10%), the 10% condition is not met in this case.

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Answer: a, f. In Melanie's data set, she is collecting numerical data, specifically the number of text messages sent each day.

Numerical data is data that is represented by numbers. It is data that can be measured and compared. Examples include age, weight, height, and number of text messages.

In Melanie's data set, she is collecting numerical data, specifically the number of text messages sent each day. This data is numerical because it can be measured and compared. This data set does not have an outlier because all of the values are within a reasonable range and no single value is significantly higher or lower than the others.

A box plot is an appropriate data display for this data because it allows for an easy comparison of the data. The box plot will show the median, the range of values, and any outliers.

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The expression that shows the measurement of the length of the land is L = 3x - 10a.

Let L be the length of the rectangular plot.

We know that the perimeter of a rectangle is given by the sum of the lengths of all its sides. In this case, the perimeter is 10x - 28a, so we can write:

Perimeter = 2L + 2W

10x - 28a = 2L + 2(2x - 4a)

10x - 28a = 2L + 4x - 8a

2L = 6x - 20a

L = 3x - 10a

In other words, the length of the land is equal to three times the width minus ten times the value of 'a'.

To explain this equation in a little more detail, we can say that the length of the rectangular plot is dependent on both the width of the land and the value of 'a'.

The expression tells us that as the value of 'a' increases, the length of the land decreases, and as the width of the land increases, the length of the land also increases. This equation is useful because it allows us to calculate the length of the land without having to measure it directly, as long as we know the value of 'a' and the width of the land.

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Answer: 1000 x 1.05^n

Step-by-step explanation:

1.05 is the increase experienced each year and n is the number of years.

Answer:

The population of bees is increasing by 5% each year since 2010. Let P(n) be the population of bees in the nth year since 2010.

The explicit formula for the bee population can be found using the formula for compound interest:

P(n) = P(0) * (1 + r)^n

where P(0) is the initial population in 2010, r is the annual growth rate, and n is the number of years since 2010.

Substituting the given values, we have:

P(n) = 1000 * (1 + 0.05)^n

Simplifying the expression, we get:

P(n) = 1000 * 1.05^n

Therefore, the explicit formula that models the bee population for n years since 2010 is P(n) = 1000 * 1.05^n.

[tex]\textit{arc's length}\\\\ s = \cfrac{\theta \pi r}{180} ~~ \begin{cases} r=radius\\ \theta =\stackrel{degrees}{angle}\\[-0.5em] \hrulefill\\ \theta =42\\ r=2.8 \end{cases}\implies s=\cfrac{(42)\pi (2.8)}{180}\implies s=\cfrac{49\pi }{75}\implies s\approx 2.05 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{ \textit{Perimeter of the sector} }{2.8~~ + ~~2.8~~ + ~~2.05} ~~ \approx ~~ \text{\LARGE 7.65}[/tex]

let's recall that the sector's perimeter includes the arc plust the radii.

Answer:    

   False

   True

   False

   True

   False

   False

Step-by-step explanation:

From the plot, we can see that curve B is taller and more narrow than curve A, and it is shifted to the right relative to curve A. This tells us that curve B has a larger mean and smaller standard deviation than curve A. Therefore, statement 2 is true, and statements 1, 3, 5, and 6 are false. Finally, since curve A is more spread out than curve B, it has a larger standard deviation. Therefore, statement 4 is true.

The atmospheric pressure of 101.325 kPa, the dew point temperature is approximately 10.4°C, the humidity ratio is approximately 0.0084 kg of water vapor per kg of dry air, the specific volume is approximately 0.85 m³/kg of dry air, and the enthalpy is approximately 91 kJ/kg of dry air.

To determine the dew point temperature, the humidity ratio, the specific volume and the enthalpy given a dry bulk temperature of 39°C and a wet bulb temperature of 18°C, you can use a psychometric chart  or a specialized software program that calculates these properties based on the given dry bulb and wet bulb temperatures, as well as other relevant parameters such as pressure, altitude, and air composition.

First, plot 39°C (the dry bulk temperature) and 18°C (the wet bulb temperature) on the chart. Then mark The atmospheric pressure of 101.325 kPa, the dew point temperature is approximately 10.4°C, the humidity ratio is approximately 0.0084 kg of water vapor per kg of dry air, the specific volume is approximately 0.85 m³/kg of dry air, and the enthalpy is approximately 91 kJ/kg of dry air.

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Answer:

Were sorry! Answer is not available right now check in later.

Step-by-step explanation:

At least 68% of the data falls between 62 and 78, and at least 95% of the data falls between 54 and 86.

To answer this question, we can use the empirical rule, also known as the 68-95-99.7 rule, which tells us that for a normal distribution:

Using this rule, we can estimate the fraction of the data that falls between the following pairs:

Between 54 and 86:

To find the range of values that is within two standard deviations of the mean, we can subtract and add two standard deviations from the mean:

Lower bound: 70 - 2*8 = 54

Upper bound: 70 + 2*8 = 86

So, about 95% of the data falls between 54 and 86.

Between 62 and 78:

To find the range of values that is within one standard deviation of the mean, we can subtract and add one standard deviation from the mean:

Lower bound: 70 - 8 = 62

Upper bound: 70 + 8 = 78

So, about 68% of the data falls between 62 and 78.

Therefore, we can conclude that at least 68% of the data falls between 62 and 78, and at least 95% of the data falls between 54 and 86.

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The required pair of corresponding angles in the given situation is (A) ∠HIK and ∠EFI.

In geometry, corresponding sides and corresponding angles of polygons are compared as part of the tests for congruence and resemblance.

In these tests, the order of adjacency is maintained by pairing each side and each angle of one polygon with a side or angle of the other polygon.

Angles that are equal in size and are found on the same side as the transversal line are called corresponding angles.

Either both are acute or both are obtuse.

By creating an F shape, we can typically identify comparable angles.

So, now after reading the description we know exactly what are corresponding angles.

Now, we can easily tell that the pair of corresponding is:

∠HIK and ∠EFI

Therefore, the required pair of corresponding angles in the given situation is (A) ∠HIK and ∠EFI.

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Answer:

Proofs attached to answer

Step-by-step explanation:

Proofs attached to answer

0, which is less than 0.01.

Suppose that X is a uniformly distributed random variable, scaled so that it has zero mean and unit variance. (1) What is P{|X|> ox}? (2) What is P{[X] > 30x}? (3) Is X spiky? Be sure to consider both positive and negative values of X.

For a uniformly distributed random variable with mean 0 and variance 1, P{|X|> ox} is equal to 0.5. (2) For a uniformly distributed random variable with mean 0 and variance 1, P{[X] > 30x} is equal to 0. (3) X is not spiky since P{|X| > 30x}

0.000045, which is greater than 0.01.
Suppose that Y is a Laplacian random variable with a pdf given by: fy(u) 2 e 2 -Au-hel, -  Oy}? (2) What is P{İY| > 30y}? (3) Is Y spiky? Be sure to consider both positive and negative values of Y.
Answer: (1) For a Laplacian random variable with mean 0 and variance 1, P{|Y|> oy} is equal to 0.5. (2) For a Laplacian random variable with mean 0 and variance 1, P{[Y] > 30y} is equal to 0.000045. (3) Y is spiky since P{|Y| > 30y}

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(a)  n = 10, p = 1/4, and x = 5. Using the formula of binomial probability function,P(5) = 10C5 * (1/4)^5 * (3/4)^5≈ 0.0267 (rounded to three decimal places)

(b) P(More than 3) = P(4) + P(5) + P(6) + P(7) + P(8) + P(9) + P(10)≈ 0.2784 (rounded to three decimal places)

Here n = 10, p = 1/4, and x = 5.Using the formula of binomial probability function,P(5) = 10C5 * (1/4)^5 * (3/4)^5≈ 0.0267 (rounded to three decimal places)

Find P(More than 3)For this, we need to calculate P(4), P(5), P(6),...,P(10) and add them.Using the formula of binomial probability function,P(4) = 10C4 * (1/4)^4 * (3/4)^6 = 0.2503 (rounded to three decimal places)P(5) = 10C5 * (1/4)^5 * (3/4)^5≈ 0.0267 (rounded to three decimal places)P(6) = 10C6 * (1/4)^6 * (3/4)^4≈ 0.0014 (rounded to three decimal places)P(7) = 10C7 * (1/4)^7 * (3/4)^3≈ 0.0001 (rounded to three decimal places)P(8) = 10C8 * (1/4)^8 * (3/4)^2≈ 0.0000 (rounded to three decimal places)P(9) = 10C9 * (1/4)^9 * (3/4)^1≈ 0.0000 (rounded to three decimal places)P(10) = 10C10 * (1/4)^10 * (3/4)^0≈ 0.0000 (rounded to three decimal places)P(More than 3) = P(4) + P(5) + P(6) + P(7) + P(8) + P(9) + P(10)≈ 0.2784 (rounded to three decimal places)

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Ramona's economic profit last year was $92,000 - $55,000 = $37,000. Therefore, the correct option is b. $37,000.

Ramona owns a small coffee shop, where she works full-time. Her total revenue last year was $200,000, and her rent was $5,000 per month. She pays her one employee $3,000 per month, and the cost of ingredients averages $1,000 per month. Ramona could earn $55,000 per year as the manager of a competing coffee shop nearby. Her economic profit last year was $37,000.An economic profit can be calculated by subtracting total costs from total revenue. Given that Ramona's total revenue is $200,000, her total cost is $5,000 + $3,000 + $1,000 = $9,000 per month. Multiplying this by 12 gives us her total cost for the year: $9,000 x 12 = $108,000. Ramona's economic profit last year was therefore $200,000 - $108,000 = $92,000. However, this figure doesn't take into account the opportunity cost of Ramona earning $55,000 as the manager of a competing coffee shop nearby. This needs to be subtracted from Ramona's economic profit.

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We are given that the SAT and ACT measure the same aptitude but use different scales. To find the equivalent ACT score for a given SAT score, we can use the conversion chart.
SAT 1100 = ACT 23
Therefore, the equivalent ACT score for a student with an SAT score of 1104 is 23.
3. If a student gets an SAT score of 1536, find the equivalent ACT score.
Solution:
To find the equivalent ACT score for a given SAT score, we can use the conversion chart.
SAT 1536 = ACT 35
Therefore, the equivalent ACT score for a student with an SAT score of 1536 is 35.
Therefore, the SAT score = 1536 and the ACT score = 35.

1. If a student gets an SAT score that is the 70th percentile, find the actual SAT score.
Solution:
We are given that SAT scores are normally distributed with a mean of 990 and a standard deviation of 201. We are asked to find the SAT score for the 70th percentile.
P( SAT score < X) = 0.70
We can use the standard normal table to find the corresponding z-score for the 70th percentile.
z = 0.52
We can use the z-score formula to find the SAT score:
z = (X - μ) / σ
0.52 = (X - 990) / 201
X = 1103.72
Therefore, the actual SAT score for the 70th percentile is 1104.
2. What would be the equivalent ACT score for this student?

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Therefore, the total amount of money utilized on fuel in June 2022 is R11 095,60.

Percent is a way of expressing a quantity as a fraction of 100. It is denoted by the symbol %, which means "per hundred". Percentages are often used to represent proportions or ratios in various fields, including finance, science, and statistics. For example, an interest rate of 5% means that for every hundred dollars borrowed or invested, five dollars of interest will be charged or earned.

Here,

(a) To calculate the total distance covered by the water tanker in March 2022, we need to find the distance travelled per day and multiply it by the number of days in March.

Distance travelled per day = 2 × 18 = 36 km (since it's a return trip)

Number of weekdays in March = 31 - 4 (Saturdays) = 27

Total distance covered = distance per day × number of weekdays

= 36 km/day × 27 days

= 972 km

(b) To determine the quantity of fuel utilized by the water tanker in March 2022, we need to divide the total distance covered by the average fuel consumption rate.

Fuel consumption rate = 5 km/ℓ

Total distance covered = 972 km

Fuel utilized = total distance covered / fuel consumption rate

= 972 km / 5 km/ℓ

= 194.4 ℓ

(c) To determine the total amount of money utilized on fuel for the water tanker in March 2022, we need to multiply the fuel quantity by the fuel price.

Fuel price in March 2022 = R16,28/ℓ

Fuel utilized = 194.4 ℓ

Total cost of fuel = fuel price × fuel quantity

= R16,28/ℓ × 194.4 ℓ

= R3 163,39

Therefore, the total amount of money utilized on fuel for the water tanker in March 2022 is R3 163,39.

(d) To determine the total amount of money utilized on fuel in June 2022, we need to repeat the above calculation using the June fuel price.

Fuel price in June 2022 = R24,14/ℓ

Fuel capacity = 460 ℓ

Total cost of fuel = fuel price × fuel capacity

= R24,14/ℓ × 460 ℓ

= R11 095,60

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Complete question:

Records of the number of water tankers that were supplied to the construction site appear in the calender on ANNEXURE A. The water source is at a distance of about 18 km (return trip) from the construction site. The water tanker has a fuel capacity of 460 litres.. The rate of fuel consumption of the Mercedes water tanker averages 5 km/ℓ. The prices of fuel per litre in March and June 2022 appear below. JUNE 2022 FUEL PRICES \begin{tabular}{|l|l|} \hline DIESEL & COST \\ \hline 50ppm & R24,14 \\ \hline \end{tabular} Source: 4.1 (a) Calculate the total distance that the water tanker has covered in March (2) 2022. (b) Hence, determine the quantity of fuel that was utilized by the water tanker in March 2022. (c) Determine the total amount of money that was utilized on fuel for the water tanker in March 2022. (2) 4.2 Determine the total amount of money that was utilized on fuel in June 2022.