Someone please help me with this math problem? !!

Someone Please Help Me With This Math Problem? !!

Answers

Answer 1

Answer:

x = -1

Step-by-step explanation:

If you input -1 to both functions, you get 3.


Related Questions

Which of the following numbers does not have
factors that include the smallest factor (other
than 1) of 119 ?
A. 28
B. 35
C. 40
D. 63

Answers

Answer:

C. 40

Step-by-step explanation:

The smallest factor of 119 (other than 1) is 7.

28/7 = 4,

35/7 = 5,

40/7 = 5 5/7

63/7 = 9

So it is 40

Given ACM, angle C=90º. AP=9, PM=12. Find AC, CM, AM.

Answers

Answer:

AM = 25, AC = 15, CM = 20

Step-by-step explanation:

The given parameters are;

In ΔACM, ∠C = 90°, [tex]\overline{CP}[/tex] ⊥ [tex]\overline{AM}[/tex], AP = 9, and PM = 16

[tex]\overline{AC}[/tex]² + [tex]\overline{CM}[/tex]² = [tex]\overline{AM}[/tex]²

[tex]\overline{AM}[/tex] = [tex]\overline{AP}[/tex] + PM = 9 + 16 = 25

[tex]\overline{AM}[/tex] = 25

[tex]\overline{AC}[/tex]² = [tex]\overline{AP}[/tex]² + [tex]\overline{CP}[/tex]² = 9² +  [tex]\overline{CP}[/tex]²

∴ [tex]\overline{AC}[/tex]² = 9² +  [tex]\overline{CP}[/tex]²

Similarly we get;

[tex]\overline{CM}[/tex]² = 16² + [tex]\overline{CP}[/tex]²

Therefore, we get;

[tex]\overline{AC}[/tex]² + [tex]\overline{CM}[/tex]² = 9² +  [tex]\overline{CP}[/tex]² + 16² + [tex]\overline{CP}[/tex]² = [tex]\overline{AM}[/tex]² = 25²

2·[tex]\overline{CP}[/tex]² = 25² - (9² + 16²) = 288

[tex]\overline{CP}[/tex]² = 288/2 = 144

[tex]\overline{CP}[/tex] = √144 = 12

From [tex]\overline{AC}[/tex]² = 9² +  [tex]\overline{CP}[/tex]², we get

[tex]\overline{AC}[/tex] = √(9² +  12²) = 15

[tex]\overline{AC}[/tex] = 15

From, [tex]\overline{CM}[/tex]² = 16² + [tex]\overline{CP}[/tex]², we get;

[tex]\overline{CM}[/tex] = √(16² + 12²) = 20

[tex]\overline{CM}[/tex] = 20.

[tex]\sqrt{x} 8xyx^{2}[/tex]

Answers

Answer:

nom nom

Step-by-step explanation:

nom nommy nom nom

Which of the following is ordered pair for point C?

Answers

Answer:

B. (4,2)

Step-by-step explanation:

Answer:

B(4,2)

Step-by-step explanation:

as you can see that if want to find coordinates u should know that the position of x and y is (x,y). So u can that c on the x is lower than 5 so that u can say it is 4 and y is too far away from 5 also u it will be 2.

Which of the following describes point D?

Answers

Point g I hope it helps

The coordinates that describe the point D are: Option C: (0, 4)

How to find the coordinates of the graph?

The graph shows that the vertical axis is labelled as the y-axis while the horizontal axis is labelled as the x -axis.

Normally, the coordinate system of writing the given points of the graph is (x, y)

Thus, the point D on the graph is seem to be 4 units on the positive y-axis and 0 units on the positive x-axis and as such, we can say that the coordinates of point D are:

D(0, 4)

Read more about Graph Coordinates at: https://brainly.com/question/11337174

Complete question is:

Which of the following describes point D?

(-4, 0)

(0, -4)

(0, 4)

(4, 0)

Joel Trump is paid one and one-half times the regular hourly rate for all hours worked in excess of 40 hours per week and double time for work on Sunday. Trump's regular rate is $8 per hour. During the week ended October 10, he worked 9 hours each day from Monday through Friday, 6 hours on Saturday, and 4 hours on Sunday. Trump's total earnings for the week ended October 10 are a.$320. b.$430. c.$516. d.$110.

Answers

Answer:

C. $516

Step-by-step explanation:

His regular rate is $8 per hour.

Since it's 40 hours a week, it means from Monday to Friday his regular work time is 8 hours per day.

Thus, for the regular week work, he is to be paid;

40 × 8 = $320

Now, we are told he worked 9 hours each day from Monday through Friday.

This means that;

He worked 1 hour each day.

That is 5 hours extra from Monday to Friday.

He is paid one and one-half times the regular hourly rate.

Thus, for this 5 extra hours, he will be paid 1½ × 5 × 8 = $60

He works 6 hours on Saturday, and 4 hours on Sunday.

Thus;

For Saturday, he is also paid one and one-half of regular pay. Thus, he is due for;

1½ × 8 × 6 = $72

He is paid double the regular hourly pay for Sundays.

Thus, for 4 hours on Sunday, he is paid;

2 × 8 × 4 = $64

Total he is due = $320 + $60 + $72 + $64 = $516

PLEASE ASAP
c) Next, you will make a scatterplot. Name a point that will be on your scatterplot and describe what it represents.

d) Using the regression calculator in your tool bar, create a scatterplot using your data set from step 1. Insert a screenshot of your scatterplot, or recreate it below.

The data is in the pic below

If u want more points for the answer, pls answer the previous question (same one) in my profile worth 30 points)
THX

Answers

Answer:

C)Ok i pick the point (18,4)

this point represents that if this person studied from 18 hours they got a GPA of 4.0

D) the chart below is the scatter plot

Hope This Helps!!!

ratio and proportion

One of the angle of pair of supplementary angle is 120 degree. find the ratio of pair of supplementary angles.​

Answers

Answer:

2 : 1

Step-by-step explanation:

Supplementary angles are two angles whose measures add up to 180°

If one of the angle = 120°

The other angle = sum of supplementary angle - one of the angle

= 180° - 120°

= 60°

The other angle = 60°

ratio of pair of supplementary aangle = 120° : 60°

= 120° / 60°

= 2/1

= 2 : 1

ratio of pair of supplementary aangle = 2 : 1

simplify 3[(15-3)^2 + 4]

Answers

Answer:

444

Step-by-step explanation:

3 [ ( 15 - 3 )^2 + 4 ]

= 3 [ ( 15 - 3 )^2 + 4 ]

= 3 [ ( 12 )^2 + 4 ]

= 3 [ 144 + 4 ]

= 3 [ 148 ]

= 444

Step-by-step explanation:

3(15-3)²+4

3(12)²+4

3×144+4

432+4

436 Answer

The equation of line r is y = 1/2 * x + 1 line runs parallel to line r and passes through (2, 5) what would be the equation of line 8 ?help please

Answers

Answer:

x - 2y + 8 = 0

Step-by-step explanation:

that is the procedure above

what is the mid point of AB?

Answers

Answer:

G

Step-by-step explanation:

I did this on edge and it was right

Answer:

O  Point G

Step-by-step explanation:

A = -6

B = 8

To find the midpoint, calculate how much would it take for both points to have a value of zero.

-6 + ? = 0

-6 + 6 = 0

8 - ? = 0

8 - 8 = 0

so the midpoint will be about 7 (between 6 & 8)

Now which of the points best shows 7 units apart of AB

Answer: point G

What is the surface area of this right circular cone?
radius=12
height=40

Answers

Answer:

2026.75 (units) squared

Step-by-step explanation:

SA of a cone = πr(r+h2+r2)

SA = π(12)(12+√(40^2)+(12^2))

SA = 12π(12+√1744)

Put in calculator and get 2026.75

Helpp m and explain ,I will mark brainlest:)

Answers

Answer:

(0,3) ; (2,3) ; (0,0) ; (3.5,0)

Step-by-step explanation:

Firstly, we have to plot all the giving inequalities as constraints

Not to forget, f(x) can be written as y

Kindly find the plot as an attachment

Upon plotting, we have the following vertices;

(0,3) ; (2,3) ; (0,0) ; (3.5,0)

(Algebra ll) Given the function below

Answers

Answer: B

Step-by-step explanation:

To find the values of x, we first need to write the function into an equation. We can derive 2 equations from the problem.

Equation 1: y=2|x+6|-4

Equation 2: y=6

Now, we can substitute.

2|x+6|-4=6

Let's solve for x.

2|x+6|-4=6        [add both sides by 4]

2|x+6|=10          [divide both sides by 2]

|x+6|=5              [subtract both sides by 6]

x=-1

Now that we know x=-1 is one of the solutions, we can eliminate C and D.

We know that the absolute value makes the number inside positive always. Therefore, let's solve for x with -5 instead.

|x+6|=-5              [subtract both sides by 6]

x=-11

Therefore, we know that B is the correct answer.

Quadrilateral ABCD is reflected across the x-axis and then reflect across the y-axis to form quadrilateral A′B′C′D′. If the coordinates of vertex A are (-7, 3), what are the coordinates of vertex A′?

Answers

Answer:


(7,3)


Hope this helps

10 ^ (th) term for AP-5,-10,-15,..... is :-(A) -955 (B) 50 (C) -50 (D) 955​

Answers

Answer:

C

Step-by-step explanation:

The nth term of an AP is

[tex]a_{n}[/tex] = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = - 5 and d = a₂ - a₁ = - 10 - (- 5) = - 10 + 5 = - 5 , then

a₁₀ = - 5 + (9 × - 5) = - 5 - 45 = - 50 → C


A company that manufactures hair ribbons knows that the number of ribbons it can sell each week, x, is related to the price p per ribbon by the equation below.
x = 1,000 − 100p
At what price should the company sell the ribbons if it wants the weekly revenue to be $1,600? (Remember: The equation for revenue is R = xp.)
p = $ (smaller value)
p = $ (larger value)

Answers

Given:

The number of ribbons it can sell each week, x, is related to the price p per ribbon by the equation:

[tex]x=1000-100p[/tex]

To find:

The selling price if the company wants the weekly revenue to be $1,600.

Solution:

We know that the revenue is the product of quantity and price.

[tex]R=xp[/tex]

[tex]R=(1000-100p)p[/tex]

[tex]R=1000p-100p^2[/tex]

We need to find the value of p when the value of R is $1600.

[tex]1600=1000p-100p^2[/tex]

[tex]1600-1000p+100p^2=0[/tex]

[tex]100(16-10p+p^2)=0[/tex]

Divide both sides by 100.

[tex]p^2-10p+16=0[/tex]

Splitting the middle term, we get

[tex]p^2-8p-2p+16=0[/tex]

[tex]p(p-8)-2(p-8)=0[/tex]

[tex](p-8)(p-2)=0[/tex]

Using zero product property, we get

[tex]p-8=0[/tex] or [tex]p-2=0[/tex]

[tex]p=8[/tex] or [tex]p=2[/tex]

Therefore, the smaller value of p is $2 and the larger value of p is $8.

Hello please help ASAP!

Answers

Correct answer is B, Length is 32 while the width is 40

Work out the area of the shaded

Answers

Hi there!

[tex]\large\boxed{73m^2}}[/tex]

Once again, divide the figure into 3 rectangles:

Top rectangle:

3m × 5m = 15m²

Long rectangle (subtract 5m from 9m to get the width):

12m × 4m = 48m²

Bottom rectangle:

2m × 5m = 10m²

Add up areas:

15m² + 48m² + 10m² = 73m²

I need help pls !!!!!!!

Answers

Should always be presented while using a factor 2
I think c because the scales are usally 2x smaller than usual

someone help me please with this algebra problem

Answers

Answer:

60

Step-by-step explanation:

5x + 10y = 800

y = 50

5x + 10(50) = 800

5x + 500 = 800

5x = 300

x = 60

Answer: 60

Step-by-step explanation:

If x = small vehicles and if y = large vehicles and y = 50, then substitute and solve for x. So,

5x + 10(50) = 800

5x + 500 = 800

5x = 300

x = 60

So, the number of small vehicles is 60.

Adya and Ashley complete a work separately in 20 and 25 days respectively. After 10 days of their working together, they both left then Amber came and completed the remaining work in 3 days. If Amber alone would do the work, calculate how many days he would take to complete the work.?​

Answers

[tex]\huge\boxed{\boxed{\underline{\textsf{\textbf{Answer}}}}}[/tex]

Number of days Adya took to complete the work = 20

Work done by Adya in 1 day = [tex]\frac{1}{20}[/tex]

Number of days Ashley took to complete the work = 25

Work done by Ashley in 1 day = [tex]\frac{1}{25}[/tex]

So,

Total work by Adya & Ashley in 1 day =

[tex] \frac{1}{20} + \frac{1}{20} \\ = \frac{5 + 4}{100} \\ = \frac{9}{100} [/tex]

•°• Their total work in 10 days =

[tex] \frac{9 \times 10}{100} \\ = \frac{90}{100} \\ = \frac{9}{10} [/tex]

Now,

The work left to be completed =

[tex]1 - \frac{9}{10} \\ = \frac{10}{10} - \frac{9}{10} \\ = \frac{1}{10} [/tex]

From this we know that,

Amber completes [tex]\frac{1}{10}[/tex] of the work in 3 days.

So,

Time taken by Amber to complete the whole work =

[tex]3 \times 10 \\ = 30 \: \: days[/tex]

↦ If Amber alone would do the whole work, he would take [tex]\boxed{30 \ \ days}[/tex] to complete it.

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ ツ

꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐

Shjdksjcksmcjcsnuckamc

Answers

Answer:

you should make the picture more clear, i cant see the answer choices

Answer:

use pythogoream theorem that is,

Step-by-step explanation:

c*2=a*2+b*2

so in order to find a*2;

a*2=c*2-b*2

In the equation 17x2 = 12x, the value of c is:
O
0 12
O 17

Answers

Answer:

ok ok ok ok ok ok ok

Step-by-step explanation:

Please help, im confused ;w;

Answers

Answer:

[tex]x=7\text{ and } m\angle KLM = 34^\circ[/tex]

Step-by-step explanation:

We are given ethat KM and JN are parallel.

And we want to find the value of x.

Notice that ∠JKM and ∠LKM form a linear pair. Linear pairs total 180°. Therefore:

[tex]m\angle JKM + m\angle LKM = 180[/tex]

We know that ∠JKM measures (14x + 8). Substitute:

[tex](14x+8)+m\angle LKM =180[/tex]

Solve for ∠LKM:

[tex]m\angle LKM = 172-14x[/tex]

Next, since KM and JN are parallel, by the Corresponding Angles Theorem:

[tex]\angle JNM \cong \angle KML[/tex]

Since we know that ∠JNM measure (10x + 2), we can conclude that:

[tex]m\angle KML = 10x+2[/tex]

Next, recall that the three interior angles of a triangle must total 180°. Therefore:

[tex]m\angle KLM + m\angle LKM + m\angle KML = 180[/tex]

Substitute:

[tex](5x-1)+(172-14x)+(10x+2)=180[/tex]

Solve for x. Rewrite:

[tex](5x-14x+10x)+(-1+172+2)=180[/tex]

Combine like terms:

[tex](1x)+(173)=180[/tex]

Therefore:

[tex]x=7[/tex]

To find ∠KLM, substitute in 7 for x and evaluate. So:

[tex]m\angle KLM = 5(7) - 1 =34^\circ[/tex]

I have a lot of algebra problems. Someone help me even with this one please!

Answers

X -Y =44 will represent the number of glasses of ice tea .

Which is the pair of congruent right angles?
A).CAB=DAE
B).CBA=DEA
C).BCA=EDA
D).ACB=ADE

Answers

Answer:

It's C

Step-by-step explanation:

this is my last set of questions if anyone could get them all completed I have 15 points on it If you could add a small explanation so I can learn from it really appreciate it :) brainliest for anyone who does all 3 questions

Answers

Answer:

832.5

A unit rate is a rate with 1 in the denominator.

Summer school math problem

Answers

Hello!

4/18 = 6/27 ?

4 × 27 = 18 × 6

108 = 18 × 6

108 = 108 => 4/18 = 6/27

4/6 = 16/36 ?

4 × 36 = 6 × 16

144 = 6 × 16

144 96 => 4/6 16/36

3/4 = 9/12 ?

3 × 12 = 4 × 9

36 = 4 × 9

36 = 36 => 3/4 = 9/12

5/9 = 8/12 ?

5 × 12 = 9 × 8

60 = 9 × 8

60 72 => 5/9 8/12

Good luck! :)

Let N be the smallest positive integer whose sum of its digits is 2021. What is the sum of the digits of N + 2021?

Answers

Answer:

[tex]10[/tex].

Step-by-step explanation:

See below for a proof of why all but the first digit of this [tex]N[/tex] must be "[tex]9[/tex]".

Taking that lemma as a fact, assume that there are [tex]x[/tex] digits in [tex]N[/tex] after the first digit, [tex]\text{A}[/tex]:

[tex]N = \overline{\text{A} \, \underbrace{9 \cdots 9}_{\text{$x$ digits}}}[/tex], where [tex]x[/tex] is a positive integer.

Sum of these digits:

[tex]\text{A} + 9\, x= 2021[/tex].

Since [tex]\text{A}[/tex] is a digit, it must be an integer between [tex]0[/tex] and [tex]9[/tex]. The only possible value that would ensure [tex]\text{A} + 9\, x= 2021[/tex] is [tex]\text{A} = 5[/tex] and [tex]x = 224[/tex].

Therefore:

[tex]N = \overline{5 \, \underbrace{9 \cdots 9}_{\text{$224$ digits}}}[/tex].

[tex]N + 1 = \overline{6 \, \underbrace{000 \cdots 000000}_{\text{$224$ digits}}}[/tex].

[tex]N + 2021 = 2020 + (N + 1) = \overline{6 \, \underbrace{000 \cdots 002020}_{\text{$224$ digits}}}[/tex].

Hence, the sum of the digits of [tex](N + 2021)[/tex] would be [tex]6 + 2 + 2 = 10[/tex].

Lemma: all digits of this [tex]N[/tex] other than the first digit must be "[tex]9[/tex]".

Proof:

The question assumes that [tex]N\![/tex] is the smallest positive integer whose sum of digits is [tex]2021[/tex]. Assume by contradiction that the claim is not true, such that at least one of the non-leading digits of [tex]N[/tex] is not "[tex]9[/tex]".

For example: [tex]N = \overline{(\text{A})\cdots (\text{P})(\text{B}) \cdots (\text{C})}[/tex], where [tex]\text{A}[/tex], [tex]\text{P}[/tex], [tex]\text{B}[/tex], and [tex]\text{C}[/tex] are digits. (It is easy to show that [tex]N[/tex] contains at least [tex]5[/tex] digits.) Assume that [tex]\text{B} \![/tex] is one of the non-leading non-"[tex]9[/tex]" digits.

Either of the following must be true:

[tex]\text{P}[/tex], the digit in front of [tex]\text{B}[/tex] is a "[tex]0[/tex]", or[tex]\text{P}[/tex], the digit in front of [tex]\text{B}[/tex] is not a "[tex]0[/tex]".

If [tex]\text{P}[/tex], the digit in front of [tex]\text{B}[/tex], is a "[tex]0[/tex]", then let [tex]N^{\prime}[/tex] be [tex]N[/tex] with that "[tex]0\![/tex]" digit deleted: [tex]N^{\prime} :=\overline{(\text{A})\cdots (\text{B}) \cdots (\text{C})}[/tex].

The digits of [tex]N^{\prime}[/tex] would still add up to [tex]2021[/tex]:

[tex]\begin{aligned}& \text{A} + \cdots + \text{B} + \cdots + \text{C} \\ &= \text{A} + \cdots + 0 + \text{B} + \cdots + \text{C} \\ &= \text{A} + \cdots + \text{P} + \text{B} + \cdots + \text{C} \\ &= 2021\end{aligned}[/tex].

However, with one fewer digit, [tex]N^{\prime} < N[/tex]. This observation would contradict the assumption that [tex]N\![/tex] is the smallest positive integer whose digits add up to [tex]2021\![/tex].

On the other hand, if [tex]\text{P}[/tex], the digit in front of [tex]\text{B}[/tex], is not "[tex]0[/tex]", then [tex](\text{P} - 1)[/tex] would still be a digit.

Since [tex]\text{B}[/tex] is not the digit [tex]9[/tex], [tex](\text{B} + 1)[/tex] would also be a digit.

let [tex]N^{\prime}[/tex] be [tex]N[/tex] with digit [tex]\text{P}[/tex] replaced with [tex](\text{P} - 1)[/tex], and [tex]\text{B}[/tex] replaced with [tex](\text{B} + 1)[/tex]: [tex]N^{\prime} :=\overline{(\text{A})\cdots (\text{P}-1) \, (\text{B} + 1) \cdots (\text{C})}[/tex].

The digits of [tex]N^{\prime}[/tex] would still add up to [tex]2021[/tex]:

[tex]\begin{aligned}& \text{A} + \cdots + (\text{P} - 1) + (\text{B} + 1) + \cdots + \text{C} \\ &= \text{A} + \cdots + \text{P} + \text{B} + \cdots + \text{C} \\ &= 2021\end{aligned}[/tex].

However, with a smaller digit in place of [tex]\text{P}[/tex], [tex]N^{\prime} < N[/tex]. This observation would also contradict the assumption that [tex]N\![/tex] is the smallest positive integer whose digits add up to [tex]2021\![/tex].

Either way, there would be a contradiction. Hence, the claim is verified: all digits of this [tex]N[/tex] other than the first digit must be "[tex]9[/tex]".

Therefore, [tex]N[/tex] would be in the form: [tex]N = \overline{\text{A} \, \underbrace{9 \cdots 9}_{\text{many digits}}}[/tex], where [tex]\text{A}[/tex], the leading digit, could also be [tex]9[/tex].

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