Someone PLEASE HELP ME. The diagram above shows a plan for a park.
ABCD is a rectangle.
APB and DQC are semicircles centred at X and Y.
Given AB = 7 cm and AC = 25 cm.
Calculate the perimeter of the park in cm.

Answer:

A. [tex](-1,-2)[/tex]

Step-by-step explanation:

Hope this helps you.

( -4, 1 ) and ( 2 , -5 )

Now,

mid point = ( 2 - 4 )/2 , ( -5 + 1 )/2

= ( -2 /2 ) , ( -4 /2)

= ( - 1, - 2 )

A ( - 1, - 2 )

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Answer:

x = 3.8

Step-by-step explanation:

take 53 degree as reference angle

using cos rule

cos 53 = adjacent/hypotenuse

0.60 = x /6.3

0.60*6.3 = x

3.78 = x

3.8 = x ( after converting the answer to nearest tenth)

Answer:

☆ y=kx

Example: if we have x= 3 and y= 15

Find y?

y= kx

*We know that y= 15 and x= 3

So,

15=k(3)

15=3k

*divide 3 from both sides

K=5

y=5x

y=5(5)=25

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Answer:

8 : 27

Step-by-step explanation:

The ratio of the volumes is the ratio of the scale factor cubed

2^3 : 3^3

8 : 27

Answer:

8 : 27

Step-by-step explanation:

Given 2 similar cylinders with height ratio = a : b , then

ratio of volumes = a³ : b³

Here height ratio = 2 : 3

ratio of volumes = 2³ : 3³ = 8 : 27

Answer:

D. 12m^3n^5

Step-by-step explanation:

Answer:

12m³n⁵

Step-by-step explanation:

3 · 4 = 12

m² · m = m³

n³ · n² = n⁵

Therefore, 3m²n³ · 4mn² = 12m³m⁵

Answer:

93.4 cm²

Step-by-step explanation:

Area of the shaded region = area of the square - area of half of the circle

Area of the shaded region = s² + ½(πr²)

Where,

r = 6.2 cm

s = length of square = diameter of circle = 2*r = 2*6.2

s = 12.4 cm

Plug in the values

Area of the shaded region = 12.4² - ½(π × 6.2²)

= 153.76 - 60.381411

= 93.378589

≈ 93.4 cm² (nearest tenth)

Answer:

5r³ - 34r² + 44r - 16

Step-by-step explanation:

[tex] \small \sf \: (5r − 4)(r² − 6r + 4)[/tex]

use the distributive property

5r × (r² − 6r + 4) - 4× (r² − 6r + 4)

5r³ - 30r² + 20r - 4r² + 24r - 16

combine like terms

5r³ - 30r² - 4r² + 20r + 24r - 16

5r³ - 34r² + 44r - 16

The product of the expressions is 5r^3 - 34r^2 + 44r - 16

The product of two expression is done by multiplying the expressions

The product expression is given as:

[tex](5r - 4)(r^2 - 6r + 4)[/tex]

Expand the expression

[tex]5r^3 - 30r^2 + 20r - 4r^2 + 24r - 16[/tex]

Collect like terms

[tex]5r^3 - 30r^2 - 4r^2 + 20r + 24r - 16[/tex]

Evaluate the like terms

[tex]5r^3 - 34r^2 + 44r - 16[/tex]

Hence, the product of the expressions is 5r^3 - 34r^2 + 44r - 16

Read more about product at:

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Answer:

Ty

Step-by-step explanation:

Answer:

cos2x=sinx

<=> 1-2sin^{2}x =sinx

solve and we have x=3pie/2, x=pie/6,x= 5pie/6

Step-by-step explanation:

Answer:

6+2x=16-x.

Step-by-step explanation:

X will represent the missing number. Sum means 6, twice that number means multiply it by two, equal represents =, minus represents this, therefor the equation 6+2x=16-x represents the correct answer.

Answer:

11:30 A.M.

Step-by-step explanation:

Answer:

11:30

Step-by-step explanation:

12.05- 35 min and its 11:30

hope that helps bby<3

Answer:

degrees of 5 or greater

Step-by-step explanation:

peaks counted are 5

Answer:

The passenger's luggage has an excess weight of 2 kg, which is 10% of the maximum weight.

Step-by-step explanation:

First, we need to find the weight (W) of the 4 bags:

[tex] W = 3.5 kg + 15 kg + 2 kg + 1.5 kg = 22 kg [/tex]

Now, knowing that the maximum allowed (M) is 20 kg the excess weight of the luggage is:

[tex] W_{e} = W - M = 22 kg - 20 kg = 2 kg [/tex]

We can express the excess weight in percentage as follows:

[tex] \% W_{e} = \frac{W_{e}}{M} \times 100 = \frac{2 kg}{20 kg}\times 100 = 10 \% [/tex]  

Therefore, the passenger's luggage has an excess weight of 2 kg, which is 10% of the maximum weight.          

I hope it helps you!                      

Answer:

angle IGH = 50 degree

Step-by-step explanation:

triangle GHI is an isosceles triangle because it's two sides are equal.

if angle I is 50 degree then angle G is also 50 degree becasue in isosceles triangle the base angles are equal.

[tex] \huge\boxed{\mathfrak{Answer}}[/tex]

=> Factor.

When an algebraic expression can be written as the product of two or more expressions, then each of these expressions is called a factor of the given expression.

[tex] \sf \: It's \: called \: a \: \boxed{\underline{\bf \: factor}}[/tex]

When an algebraic expression can be written as the product of two or more expressions, then each of these expressions is called a [tex]\boxed{\underline{\bf \: factor}}[/tex]of the given expression.

Answer:

Option (1)

Step-by-step explanation:

Equation of the given wave function,

f(x) = acos(bx)

Here, a = amplitude of the wave

Period of the wave = [tex]\frac{2\pi }{B}[/tex]

From the graph attached,

Amplitude = [tex]\frac{4-(-4)}{2}[/tex]

                 = [tex]\frac{4+4}{2}[/tex]

                 = 4

Period of the wave = π - 0

                                = π

From the formula of the period,

Period = [tex]\frac{2\pi }{b}[/tex]

[tex]\pi =\frac{2\pi }{b}[/tex]

b = 2

Therefore, a = 4 and b = 2.

Option (1) will be the answer.

Answer:

1/2 or 0.5 hours

Step-by-step explanation:

r = time for repairman to fix one pair of shoes.

a = time for assistant to fix one pair of shoes.

a = r×1.5

x×r + y×a = 6

x = number of pairs of shoes repaired by repairman.

y = number of pairs of shoes repaired by assistant.

x+y = 10

y = 10-x

x = y×1.5 (based on the a/r ratio : as the assistant needs 1.5 times longer, the repairman will have repaired 1.5 times more pair of shoes in the same time)

y = 10 - y×1.5

y + y×1.5 = 10

2.5×y = 10

y = 4

=> x = 6

6×r + 4×r×1.5 = 6

6×r + 6×r = 6

12×r = 6

r = 6/12 = 1/2 or 0.5 hours

Answer:

you nepali me nepali all are nepalese nepalese are only unintelligent

Answer:

[tex] x = \dfrac{-\log 7}{\log 7 - \log 2} [/tex]

Step-by-step explanation:

[tex] 2^x = 7^{x + 1} [/tex]

Take the log of both sides.

[tex] \log 2^x = \log 7^{x + 1} [/tex]

Use properties of log.

[tex] x \log 2 = (x + 1) \log 7 [/tex]

[tex] x \log 2 = x \log 7 + \log 7 [/tex]

[tex] x \log 2 - x \log 7 = \log 7 [/tex]

[tex] x(\log 2 - \log 7) = \log 7 [/tex]

[tex] x = \dfrac{\log 7}{\log 2 - \log 7} [/tex]

[tex] x = \dfrac{\log 7}{-(\log 7 - \log 2)} [/tex]

[tex] x = \dfrac{-\log 7}{\log 7 - \log 2} [/tex]

Answer:

cos(2π/35)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Pre-Calculus

Step-by-step explanation:

Step 1: Define

Identify

cos(π/5)cos(π/7) + sin(π/5)sin(π/7)

Step 2: Simplify

Answer:

??????

Step-by-step explanation:

Answer:

The radius of the circle is 2 units.

Step-by-step explanation:

The radius is half the diameter, therefor you must divide the diameter (4) by 2, and you get 2 units.

Answer: one solution.

Step-by-step explanation:

[tex]\dfrac{2}{3} x-4=12-2x\\\\\dfrac{2}{3} x+2x=12+4\\\\2\dfrac{2}{3} x=16\\\\\dfrac{8}{3} x=16\\\\8x=16 \cdot 3\\\\8x=48\\\\x=\dfrac{48}{8} =6[/tex]

This equation has one solution:  x = 6.

Answer : B

Step-by-step explanation:

Ape

The statement which is true is  KM = 2 .JM, the correct option is C.

A right-angle triangle is a triangle that has a side opposite to the right angle the largest side and is referred to as the hypotenuse. The angle of a right angle is always 90 degrees.

We are given that;

AJKL is an equilateral triangle

Now,

Using these properties, we can eliminate some of the options.

Option A is false because JK and KM are not equal. JK is half of JL, which is one side of the equilateral triangle AJKL, while KM is a perpendicular bisector of JL.

Option B is false because AJKM is not a right triangle. The angle JAK is 60 degrees, not 90 degrees.

Option D is false because AJKM is not a right triangle. The angle JAK is 60 degrees, not 45 degrees.

Option C must be true because KM bisects JL into two equal parts JM and ML. Since JL is one side of the equilateral triangle AJKL, we have JL = AK = AL. Therefore, JM = ML = JL/2 = AK/2 = AL/2. By Pythagoras’ theorem, we have:

KM^2 = AK^2 - AM^2

KM^2 = (AK/2)^2 - (AL/4)^2

KM^2 = (AK/4)^2 + (AL/4)^2

KM^2 = ((AK + AL)/4)^2

Since AK + AL = 2 * JL,

KM^2 = (JL/4)^2 * 4

KM^2 = (JL/4)^2 * 4

KM = JL/4 * 2

KM = JL/2

Therefore, the answer of the triangle will be KM = 2 * JM.

Learn more about a right triangle;

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Answer:

(a) [tex]\frac{1}{7}[/tex]

(b) [tex]\frac{4}{7}[/tex]

(c) [tex]\frac{5}{7}[/tex]

Step-by-step explanation:

Probability (P) of an event is the likelihood that the event will occur. It is given by;

P = number of favourable outcomes ÷ total number of events in the sample space.

Given letters of cards:

A B C D E F G H J

∴ Total number of events in sample space is actually the number of cards which is 7

If a card is picked at random;

(a) the probability P(F), that it is labelled F is given by;

P(F) = number of favourable outcomes ÷ total number of events in the sample space.

The number of favourable outcomes for picking an F = 1 since there is only one card labelled with F.

∴ P(F) = 1 ÷ 7

=> P(F) = [tex]\frac{1}{7}[/tex]

(b) the probability P(N), that it is labelled with a letter in her name JADE is given by;

P(N) = P(J) + P(A) + P(D) + P(E)

Where;

P(J) = Probability that it is labelled J

P(A) = Probability that it is labelled A

P(D) = Probability that it is labelled D

P(E) = Probability that it is labelled E

P(J) = [tex]\frac{1}{7}[/tex]

P(A) = [tex]\frac{1}{7}[/tex]

P(D) = [tex]\frac{1}{7}[/tex]

P(E) = [tex]\frac{1}{7}[/tex]

∴ P(N) = [tex]\frac{1}{7}[/tex] + [tex]\frac{1}{7}[/tex] + [tex]\frac{1}{7}[/tex] + [tex]\frac{1}{7}[/tex]

∴ P(N) = [tex]\frac{4}{7}[/tex]

(c) the probability P(S), that it is labelled with a letter that has at least one line of symmetry is;

P(S) = P(A) + P(B) + P(C) + P(D) + P(E) + P(H)

Where;

P(A) = Probability that it is labelled A

P(B) = Probability that it is labelled B

P(C) = Probability that it is labelled C

P(D) = Probability that it is labelled D

P(E) = Probability that it is labelled E

P(H) = Probability that it is labelled H

Cards with letters A, B, C, D, E and H are selected because these letters have at least one line of symmetry. A line of symmetry is a line that cuts an object into two identical halves. Letters A, B, C, D, E and H can each be cut into two identical halves.

P(A) = [tex]\frac{1}{7}[/tex]

P(B) = [tex]\frac{1}{7}[/tex]

P(C) = [tex]\frac{1}{7}[/tex]

P(D) = [tex]\frac{1}{7}[/tex]

P(E) = [tex]\frac{1}{7}[/tex]

P(H) = [tex]\frac{1}{7}[/tex]

∴ P(S) = [tex]\frac{1}{7}[/tex] + [tex]\frac{1}{7}[/tex] + [tex]\frac{1}{7}[/tex] + [tex]\frac{1}{7}[/tex] + [tex]\frac{1}{7}[/tex]

∴ P(S) = [tex]\frac{5}{7}[/tex]

Answer:

4th option

Step-by-step explanation:

in geometric sequences the number is multiplied or divided by same number continuously

in the 4th option we can see that the number 1 is multiplied by 4 continuously so the correct answer would be that.

Answer:

82.9+38.6=121.5 miles far away.